Two ways water and ice are the same

Answer:

Reactions are given below.

Explanation:

Chemical equation:

CuCl₂ + NaOH     →    Cu(OH)₂ + NaCl

Balanced Chemical equation:

CuCl₂(aq) + 2NaOH(aq)     →    Cu(OH)₂(s) + 2NaCl(aq)

Ionic equation:

Cu²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + 2OH⁻(aq) →  Cu(OH)₂(s) + 2Na⁺(aq) + 2Cl⁻ (aq)

Net ionic equation:

H⁺(aq) + OH⁻(aq) → H₂O(l)  

The Cl⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The Cu(OH)₂ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

Ethyne gas undergo combustion reaction to give two moles of carbon dioxide and water as per the balanced equation written below:

\(\rm C_{2} H_{2} + \frac{5}{2} O_{2} \rightarrow 2CO_{2} + H_{2}O\)

Combustion is a type of reaction in which a gas burns in oxygen to give water and carbon dioxide. Hydrocarbons alkanes, alkenes or alkynes easily undergo combustion reaction and they can be used as fuels.

C₂H₂ is an alkyne names ethyne and it is an unsaturated hydrocarbon with triple bond between two carbon atoms. Ethyne gas reacts with oxygen to give two moles of carbon dioxide and one mole of water.

To balance the number of carbons the right side carbon dioxide is multiplied by 2 and the number of oxygens is balanced accordingly to get the balanced equation as follows:

\(\rm C_{2} H_{2} + \frac{5}{2} O_{2} \rightarrow 2CO_{2} + H_{2}O\)

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Answer:

answer is

chromosomes are made of

The solid and the liquid coexist at the melting point, which is the point where the temperature remains constant during the phase transition.

In the given cooling curve, the melting point is at 50°C, indicated by the flat region on the curve between points C and D. At this point, the energy being released during cooling is used to overcome the energy required for the substance to transition from a liquid to a solid state.

Once all of the substance has solidified, the temperature begins to decrease again.

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Answer: all points on the curve between Q and S

Explanation: Where the graph looks like <-------->horizontal.

Answer:

Partial pressure is proportional to the number of moles so: partial pressure = total pressure x mole fraction. Let's calculate total pressure first. We know the volume in liters and the temperature. We can also find the number of moles of each gas by conversion.Mar 25, 2019

Answer: 3 empirical and structural

Explanation:

Just guessed on same question got it right

Answer: the new temperature of the sample of gas is 361 K

Explanation:

The question requires us to determine the new temperature of a sample of gas, knowing that its pressure was increased and volume decreased.

The following information was provided by the question:

initial volume = V1 = 450 mL

initial pressure = P1 = 167 kPa

initial temperature = T1 = 295 K

final volume = V2 = 400 mL

final pressure = P2 = 230 kPa

Assuming that this gas behaves as an ideal gas, we can apply the equation of ideal gases:

where P corresponds to the pressure of the gas, V is the volume of the gas, n corresponds to the number of moles of gas, R is the gas constant and T is the temperature of the gas.

Note that, even though the pressure, volume and temperature of a sample of gas changes, the number of moles of gas contained in this sample (n) does not change. Thus, with the information of initial volume, pressure and temperature, we can find an expression for the number of moles of gas and then use it to calculate the final temperature of the gas.

In summary, we'll follow these steps:

1) rearrange the equation of ideal gases to determine n;

2) use the values provided by the question to find a mathematical expression for n;

3) rearrange the equation of ideal gases to determine T;

4) use the values of final pressure and volume, provided by the question, and the expression of n determined in the previous step to calculate the new temperature of the gas.

First, let's rewrite the equation of gas in a way we can calculate the number of moles:

Next, let's use the values of initial pressure (P1), initial volume (V1) and initial temperature (T1) to write a mathematical expression for n:

(note that the gas constant, R, as well as the units were kept in the expression - that is because we~ll replace the entire expression into the equation to calculate the temperature).

Next, we'll need to rearrange the equation of ideal gases in order to find an expression to calculate the temperature:

And at last, we'll use the values of final pressure (P2) and final volume (V2) provided by the question, as well as the expression for n determined above, to calculate the final temperature of the sample of gas:

Therefore, the new temperature of the sample of gas is 361 K.

The limiting and excess reactant can be obtained as follow:

2Mg + O₂ -> 2MgO

From the balanced equation above,

48 g of Mg reacted with 32 g of O₂

Therefore,

62.1 g of Mg will react with = (62.1 × 32) / 48 = 41.4 g of O₂

We can see from the above that only 41.4 g of O₂ is required to react completely with 62.1 g of Mg.

Thus, the limiting reactant is magnesium, Mg and the excess reactant is oxygen, O₂

The mass of the excess reactant remaining can be obtained as shown below:

Mass of excess reactant remaining = Mass given - mass reacted

Mass of excess reactant remaining = 100 - 41.4

Mass of excess reactant remaining = 58.6 g

The mass of H₂SO₄ produced can be obtained as illustrated below:

Mg + O₂ -> 2MgO

From the balanced equation above,

48 g of Mg reacted to produce 80 g of MgO

Therefore,

62.1 g of Mg will react to produce = (62.1 × 80) / 48 = 103.5 g of MgO

Thus, the mass of product, MgO produced is 103.5 g

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Complete question:

If 62.1 grams of magnesium react with 100.0 grams of oxygen, how many grams of product are produced?

Which is the Limiting reactant?

Which is the Excess reactant?

How many grams of excess reactant remain?

Approximately 766.08 grams of oxygen are required to completely react with 240g of C₂H₆.

To determine the amount of oxygen required to completely react with 240g of C₂H₆ (ethane), we need to set up a balanced chemical equation for the combustion of ethane.

The balanced equation for the combustion of ethane is as follows:

C₂H₆ + O₂ → CO₂ + H₂O

From the balanced equation, we can see that the stoichiometric ratio between C₂H₆ and O₂ is 1:3. This means that for every one mole of C₂H₆, three moles of O₂ are required for complete combustion.

To calculate the amount of oxygen required, we need to convert the given mass of C₂H₆ to moles using its molar mass, and then use the stoichiometric ratio to determine the moles of O₂ required. Finally, we can convert the moles of O₂ back to grams using the molar mass of oxygen.

The molar mass of C₂H₆ is calculated as follows:

(2 x atomic mass of carbon) + (6 x atomic mass of hydrogen)

(2 x 12.01 g/mol) + (6 x 1.01 g/mol) = 30.07 g/mol

Now, we can proceed with the calculation:

Calculate the moles of C₂H₆:

moles of C₂H₆ = mass of C₂H₆ / molar mass of C₂H₆

moles of C₂H₆ = 240 g / 30.07 g/mol ≈ 7.98 mol

Determine the moles of O₂ using the stoichiometric ratio:

moles of O₂ = moles of C₂H₆ x (3 moles of O₂ / 1 mole of C₂H₆)

moles of O₂ = 7.98 mol x 3 ≈ 23.94 mol

Convert moles of O₂ to grams:

mass of O₂ = moles of O₂ x molar mass of O₂

mass of O₂ = 23.94 mol x 32.00 g/mol = 766.08 g

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Balance the following chemical equations:

1. N2 + 3 H2 → 2 NH3

Ex: Synthesis reaction

2. 2 KClO3 → 2 KCl + 3 O2

Single Replacement reaction

3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl

Decomposition reaction

4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2

Double Replacement reaction

5. 2 H2 + O2 → 2 H2O

Combustion reaction

6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2

Synthesis reaction

7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2

Decomposition reaction

8. C3H8 + 5 O2 → 3 CO2 + 4 H2O

Combustion reaction

9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O

Double Replacement reaction

10. 4 P + 5 O2 → 2 P2O5

Synthesis reaction

11. 2 Na + 2 H2O → 2 NaOH + H2

Single Replacement reaction

12. 2 Ag2O → 4 Ag + O2

Decomposition reaction

13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O

Combustion reaction

14. 2 KBr + MgCl2 → 2 KCl + MgBr2

Double Replacement reaction

15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O

Double Replacement reaction

16. C5H12 + 8 O2 → 5 CO2 + 6 H2O

Combustion reaction

17. 4 Al + 3 O2 → 2 Al2O3

Synthesis reaction

18. Fe2O3 + 2 Al → 2 Fe + Al2O3

Single Replacement reaction

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Answer:

Nearly all of the hydrogen consumed in the United States is used by industry for refining petroleum, treating metals, producing fertilizer, and processing foods. U.S. petroleum refineries use hydrogen to lower the sulfur content of fuels.

Explanation:

Hope it helped brainlist plz:)

The final mass concentration of salt in the solution in g/l is 36.06 g/L.

The mass concentration of the mixture of the two salt solutions is calculated as follows:

Concentration of solution 1 = 15 g/l

mass of salt in the 250 mL solution = 15 g/l * 250 mL * 1 L/1000 mL

mass of salt in the 250 mL solution = 3.75 g

Concentration of solution = 6% (m/v)

This means that in 100 mL solution, 6 g of salt in present.

In 1000 mL or 1 L solution, 60 g of salt will be present.

Hence, the concentration of solution = 60 g/L

mass of salt in the 220 mL solution = 60 g/l * 220 mL * 1 L/1000 mL

mass of salt in the 220 mL solution = 13.2 g

Total mass of salt in the mixture = 16.95 g

Total volume of solution = 470 mL

Final mass concentration of solution = 16.95 g / 470 mL * 1000 mL/L

Final mass concentration of solution = 36.06 g/L

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Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  value is   \(K_b  =   1.89 *10^{-6}\)

Explanation:

From the question we are told that

   The  voltage of the cell is  \(V = 0.731 \ V\)

Generally \(K_b\) is mathematically represented as  

           \(K_b  =  \frac{K_w }{ K_a }\)

Where  \(K_w\)  is the equilibrium constant for this auto-ionization of water with a value  \(K_w  =  1.0 *10^{-14}\)

Generally the \(E_{cell}\) is mathematically represented as

       \(E_{cell} =  V  -  E_{SCE}\)

=>     \(E_{cell} =  0.731 - 0.241 \)

=>       \(E_{cell} =   0.49 V  \)

This  \(E_{cell}\) is mathematically represented as

             \(E_{cell} =  \frac{0.0592}{n} *  log K_a \)

Where n is the number of moles which in this question is  n = 1

         So  

         \(0.490 =  \frac{0.0592}{1}  *  log K_a\)

=>      \(K_a  =  5.30*10^{-9}\)

So  

     \(K_b  =  \frac{ K_w}{ K_a}\)

=>   \(K_b  =  \frac{1.0 *10^{-14}}{ 5.30*10^{-9}}\)

=>    \(K_b  =   1.89 *10^{-6}\)

Answer:

25gc6h1206

Explanation:

Answer:

welcome to mobile legends

Explanation:

ml ka muna maya kana mag module

Answer:

The molecules in a gas have more freedom of movement than molecules in a liquid. Molecules in gas are free to move away from each other, so gas can expand to fill its container.

Explanation:

Water turns from a liquid into a gas known as water vapor. Compared to molecules in a liquid, gas molecules are more flexible.

The gaseous phase of water is known as water vapor, water vapor, or aqueous vapor. Within the hydrosphere, it is one type of water state. Water vapor can be created by the boiling or evaporation of liquid water, as well as by the sublimation of ice. Like the majority of other atmospheric elements, water vapor is transparent.

As a result of the water molecules' vibrations caused by heat, some of the water's molecules escape into the atmosphere and turn into water vapor, or the gaseous state of water. We call it evaporation for this reason. Water turns into a gas known as vapor.

Thus, water turns from a liquid into a gas known as water vapor. Compared to molecules in a liquid, gas molecules are more flexible.

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Answer:

i When sodium carbonate (Na2CO3) is mixed with an aqueous solution of copper(II) sulfate (CuSO4), the student can expect to see several evidence of a chemical reaction:

Formation of a solid precipitate: When these two solutions are mixed, a solid precipitate of copper(II) carbonate (CuCO3) will form. This is a sign that a chemical reaction has occurred.

Change in color: The reaction between sodium carbonate and copper(II) sulfate will also result in a change in color. The solution may turn a blue or green color, indicating the presence of copper(II) ions.

Release of gases: The reaction between sodium carbonate and copper(II) sulfate may also produce gases, such as carbon dioxide (CO2).

ii The balanced chemical equation for the reaction between sodium carbonate and copper(II) sulfate is:

2Na2CO3(aq) + CuSO4(aq) → 2Na2SO4(aq) + CuCO3(s)

iii This is a double displacement reaction, also known as a metathesis reaction. In this type of reaction, the cations (positively charged ions) and anions (negatively charged ions) of the reactant compounds exchange places to form the products. In this case, the sodium ions (Na+) and the copper ions (Cu2+) exchange places to form sodium sulfate (Na2SO4) and copper carbonate (CuCO3).

Answer:

The enzyme urease catalyzes the hydrolysis of urea into ammonia and carbon dioxide. If urease is added to any compound which has no urea, it will not catalyze any reaction because if there is no urea, urease will not bind to any substance.

30 g of pure sulfuric acid (H2SO4) is required to make 150 g of 20% solution of H2SO4.

To find the mass of pure sulfuric acid (H2SO4) required to make a 20% and 150g of solution of H2SO4, you first need to understand the concept of concentration.The concentration of a solution is the amount of solute dissolved in a given volume or mass of solvent. It is expressed as a percentage or as the number of moles per liter of solution.20% solution means that 20 grams of solute is present in 100 grams of solution or 20 grams of solute is dissolved in 80 grams of solvent (water in this case).So, for 150 g of solution, the mass of solute (H2SO4) can be calculated as follows:20% solution means 20 g H2SO4 in 100 g solution.So, in 1 g solution, the mass of H2SO4 is:20 g / 100 g = 0.2 g/g solution.So, in 150 g of solution, the mass of H2SO4 is:0.2 g/g solution x 150 g = 30 g.So, 30 g of H2SO4 is required to make 20% and 150g of solution of H2SO4.To find the mass of pure sulfuric acid (H2SO4) required to make the solution, you need to consider the molar mass of H2SO4. The molar mass of H2SO4 is:2(1.01 g/mol) + 32.07 g/mol + 4(16.00 g/mol) = 98.08 g/mol.So, to find the mass of pure sulfuric acid (H2SO4) required to make the solution, you need to use the formula:mass = moles x molar mass.To find the moles of H2SO4, you need to use the formula:moles = concentration x volume / molar mass.For the 20% solution, the concentration is 20 g/100 g solution or 0.2 g/g solution.The volume of the solution is not given, so we cannot calculate the number of moles of H2SO4 required.For the 150 g solution, the mass of H2SO4 required is 30 g.

So, the number of moles of H2SO4 required is:moles = mass / molar mass = 30 g / 98.08 g/mol = 0.305 mol.So, the mass of pure sulfuric acid (H2SO4) required to make the solution is : mass = moles x molar mass = 0.305 mol x 98.08 g/mol = 29.93 g.

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Answer:

(a) Rate of formation of NO2 is also 0.066M/s

(b) Rate of reaction of O2 gas is 0.033M/s

Explanation:

(a) in one second, according to the equation,

2 moles of NO combines with 2moles of NO2.

Therefore 0.066M NO will still consume 0.066mole NO2.

(b) According to the equation,

2 moles NO consumes 1 mole O2, 0.0666M will consume 0.0333 mole O2

Answer:

In Thomas Cole's painting "The Oxbow," Thomas Cole, the artist, shows himself sitting in the landscape while painting it.

Explanation:

In the painting called "The Oxbow" by Thomas Cole, the artist actually put himself in the picture. He's sitting right in the middle of the landscape, just like he placed himself in the painting, as if taking a selfie while working on it. It's like he took a snapshot of himself while he was working on the painting. This shows how much he cared about creating the artwork and how he felt a personal connection to the beautiful scenery. It's really fascinating because it gives us a glimpse into how he saw himself as an artist and how he wanted to capture the incredible beauty of nature through his art.

Answer:

Do a quick conversion: 1 moles Aluminium Sulfate = 342.150876 gram using the molecular weight calculator and the molar mass of Al2(SO4)3.

Explanation:

The separation of the dye into its individual components is based on the principle of adsorption chromatography, where the stationary phase is a solid adsorbent that retains the components of the mixture based on their adsorption properties.

Answer all the questions, use the answer grid provided. The branch of chemistry that involves the study of chemical nature of living matter is Biochemistry. Biochemistry is a branch of science that deals with the study of chemical processes within and relating to living organisms. It is an interdisciplinary field that involves the application of chemistry, biology, physics, and mathematics to the study of biological systems. It focuses on the chemical and physical properties of living things and their interaction with the environment.Biochemistry can be divided into two main categories, which are structural biochemistry and functional biochemistry. Structural biochemistry deals with the study of the chemical structure of biological molecules such as proteins, carbohydrates, and lipids. It involves the analysis of the molecular structure and the physical properties of these molecules. Functional biochemistry, on the other hand, focuses on the study of the chemical reactions and processes that occur within living organisms. It involves the study of metabolic pathways, enzymology, and the regulation of cellular processes. 2. The diagram below shows the chromatogram for a dye.Chromatography is a technique used to separate mixtures into their individual components. It works on the principle that different compounds will move at different rates through a stationary phase under the influence of a mobile phase. In this case, the dye is separated into its individual components by passing it through a stationary phase of paper under the influence of a mobile phase of water.As can be seen from the chromatogram, the dye has been separated into three distinct components, which are represented by the three peaks on the graph. The first peak represents the component that moved through the paper at the fastest rate, while the third peak represents the component that moved through the paper at the slowest rate. The second peak represents the component that moved through the paper at an intermediate rate.

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Surface sand: 104°F; Subsurface sand: 44.6°F. These temperatures can impact agriculture and daily activities during the Indian monsoon season.

The Indian rainstorm is an intricate climate peculiarity that influences the South Asian locale consistently. The video examines the effect of storm season on different parts of life in India, like agribusiness, transportation, and day to day exercises. One significant viewpoint Fahrenheit that the video makes reference to is the temperature during the rainstorm season.

The video gives two temperatures in Celsius: surface sand at 40°C and subsurface sand at 7°C (15 centimeters down). To switch these temperatures over completely to Fahrenheit, we can utilize the recipe F = 9/5 C+32. Applying this recipe, we can ascertain that the surface sand temperature is 104°F, and the subsurface sand temperature is 44.6°F.

The surface sand temperature of 104°F is very high and can be awkward for some individuals. This temperature can likewise have critical ramifications for farming, as it can make soil dampness dissipate rapidly, prompting dry spell conditions.

Then again, the subsurface sand temperature of 44.6°F is somewhat low and can influence the development of yields adversely.

By and large, the temperature during the Indian storm season is a fundamental element that can impact different parts of life in South Asia. Understanding the temperature changes during the storm season can help policymakers, ranchers, and residents to plan better for the difficulties and open doors that accompany this yearly climate occasion.

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The smooth ER differs from the rough ER in that the smooth ER produces carbohydrates and lipids, whereas the rough ER produces proteins. (Option B)

The manufacture, folding, quality assurance, and shipment of some proteins take place in the rough ER, which is dotted with millions of membrane-bound ribosomes.

The production of steroid hormones, lipid (fat) synthesis, and metabolism are all heavily correlated with SER. It also serves as a detoxifier. The production of proteins is greatly aided by the rough endoplasmic reticulum.

The fundamental distinction between the rough endoplasmic reticulum and the smooth endoplasmic reticulum is that the RER contains ribosomes, which give it its rough appearance and enable protein synthesis.

Ribosomes cover the rough endoplasmic reticulum, which is important in the synthesis and creation of proteins.

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Answer:

B

Explanation:

Elements in a group are determined by the number of valence electrons

Elements in a period are determined by the number of electrons shell

The electronic configuration of the element is

2,8,8

the number of valence electron is 8 that means it is in Group 8/O

the number of electron shell is 3 that means it is in period (row) 3

Group 8/O elements are called Noble gases

At 25 °C a solution having a pOH of 2.33. The [H₃O⁺] of the solution is 2.08 × 10⁻¹² M, and the solution is basic.

To find the [H₃O⁺] of the solution, we first need to use the relationship between pH and pOH;

pH + pOH = 14

Rearranging the equation, we get;

pH = 14 - pOH

Substituting the given value of pOH into equation, we have;

pH = 14 - 2.33 = 11.67

Next, we use the relationship between pH and [H₃O⁺];

pH = -log[H₃O⁺]

Substituting the value of pH we just calculated, we have;

11.67 = -log[H₃O⁺]

Taking the antilog of both sides, we get;

[H₃O⁺] = 2.08 × 10⁻¹² M

Therefore, the [H₃O⁺] is less than 1 × 10⁻⁷ M, the solution is basic.

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Answer:

167.86 tonnes

Explanation:.

I am assuming the iron oxide is Fe2O3 (Haematite) which is the most common form of iron oxide.

From the atomic masses:

Maximum Mass of iron = 240 *  2*55.845 / (2*55.845 + 3*15.999))

= 240 * 111.69 / (159.687)

= 167.86 tonnes