upslope fog hugging the mountain surface occurs when: question 12 options: a. air warms because of decreasing atmospheric pressure
b. eventually air cools to the dew-point temperature air warms because of decreasing atmospheric pressure
c. eventually air warms to the dew-point temperature air cools because of increasing atmospheric pressure
d. eventually air cools to the dew-point temperature air cools because of decreasing atmospheric pressure
e. eventually air cools to the dew-point temperature

Answer:

Answer

Explanation:

Answer:

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2. Medicine 7. Diet

3. Diseases 8. Treatment

4. Exercises 9. Activities

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A) The electric field at 1.0 cm above the center of the sheet is 2.5 × 10⁵ N/C, B) the electric field 15 m above the center of the sheet is 11 N/C.

Side of the square sheet, l =25 cm = 0.25 m

Uniformly distributed charge, Q = 275 × 10⁻⁹ C

ε₀ = 8.8 × 10⁻¹²

a) When close to the sheet, we assume it as an infinite sheet, So,

E = σ/2ε₀,

σ = Q/l²

E = Q/(2ε₀l²)

E = (275 × 10⁻⁹)/(2×8.8 × 10⁻¹²×0.25²)

E = 2.5 × 10⁵ N/C

B) When far from the sheet, we assume it as a point charge, if R = 15 m

E = Q/(4πε₀R²)

E = (275 × 10⁻⁹)/(4π×8.8 × 10⁻¹²× 15²)

E = 11 N/C

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The electric eel can produce a current of 0.58 A through the water from near its head to near its tail.

To solve this problem, we can use Ohm's Law (V = IR) and the rules for combining resistors in series and parallel.

The total emf of the eel is 140 rows x 5000 cells per row x 0.15 V per cell

= 105,000 V.

The total internal resistance of the eel is 140 rows x 0.25 12 per row

= 35 12.

The total resistance of the water is 840 , which is much larger than the eel's internal resistance, so we can neglect it.

Therefore, the current through the eel is

I = V/R = 105,000 V / 35 12 = 0.58 A.

This means that the eel can produce a significant amount of current, which it uses to navigate, communicate, and stun prey.

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Answer:

Pressure means physical force that is another person or object.

Answer:

D: 4.4m/s

Explanation:

From a known theorem the total work on a body is equal of the variation of kinetic energy:

\(W = \Delta K = K_f-K_i = \frac12 mv_f^2 - \frac12 m v_i^2\)

Taking the first and last step in the chain of equalities and replacing the values we have, we get:

\(5 = \frac12(1)v_f^2 - \frac12(1)(3)^2\\10= v_f^2 -9 \rightarrow v_f^2 = 19 \rightarrow v_f=\sqrt19 \approx 4.4m/s\)

Answer:

0.6amp or I= 0.6

Explanation:

V=IR

12V=I(20)

12/20=I

0.6=I

Answer:

0.6amp

Explanation:

Answer

C) Light refracts and bends as it moves thorugh air at different temperatures, causing a mirage.

Explanation:

This is an effective example of Newton's third law. Because of the upward push of the floor, you jump higher and faster. A force of 2,295.9 N is exerted on an airplane weighing 1,500 N while it is accelerated at 15 m/s2.

As we leap, the chemical energy in our muscles is transformed into kinetic energy, which exerts a force on the ground and, according to Newton's third law, causes a reaction that "pushes" us up—leading to the jump. Mass times leap distance equals the typical force that results. A person's center of mass may experience a force from their legs of 1200 N while moving 0.3 m upward during a jump. Gravity, which pulls everything down and causes the bungee jumper to fall, is the first force that the jumper encounters. Almost perfectly constant throughout the trip is the gravitational pull. The force of air resistance is another factor the bungee jumper encounters throughout the descent.

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Answer: 1*10^3 mm^3

That’s it

The light from the green glow stick held by the Olympic sprinter will appear redshifted.

The phenomenon of redshift occurs when the source of light is moving away from the observer. In this case, as the sprinter is running towards you, the distance between you and the glow stick is decreasing over time. This decrease in distance causes a Doppler shift in the frequency of the light emitted by the glow stick.

Since the light is redshifted, its wavelength increases and the frequency decreases compared to its original emitted frequency. As a result, the light that reaches your eyes appears more towards the red end of the visible spectrum.

It is important to note that the color of the glow stick itself remains the same, but due to the relative motion between the source (the sprinter) and the observer (you), the light undergoes a change in frequency and appears redshifted.

This phenomenon is similar to the redshift observed in cosmology, where the light from distant galaxies appears to be redshifted due to the expansion of the universe.

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The vertical height in which the runner’s center of mass is raised during the jump is 0.43 m.

The vertical height reached by the runner is calculated by applying the third kinematic equation as shown below.

Mathematically, the formula is given as;

v² = u² - 2gh

where;

at maximum height, the final velocity, v = 0

The vertical height reached by the runner is calculated as;

0 =  u² - 2gh

2gh = u²

h = u² / 2g

h = ( 2.9² ) / ( 2 x 9.8 )

h = 0.43 m

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Known :

m = 2.36 × 10⁴ kg

M = 9.4 × 10³ kg

V = 2.7 m/s

Solution :

Using the principle of momentum

m • v = (m + M) • V

(2.36 × 10⁴) • v = (2.36 × 10⁴ + 9.4 × 10³)(2.7)

v = 3.77 m/s

Answer:

250N

Explanation:

w = mg

m=25

g = 10

w=25x10

w=250

If a student is pulling on an object that has a mass of 25 kg across the floor. Assuming gravity to be 10 m/s², then the weight of the object would be 250 N , therefore the correct answer is option C.

It can be defined as the force by which a body attracts another body toward its center as the result of the gravitational pull of one body and another.

As given in the problem, a student is pulling on an object that has a mass of 25 kg across the floor. Assuming gravity to be 10 m/s2,

The weight of the object = 25 × 10

                                          = 250 N

Thus,  the weight of the object would be 250 N , therefore the correct answer is option C.

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The balloon's capacity is fixed at 0.413793. Air pressure outside can be assumed to remain constant.

Volume is used to describe an object's capacity. If a cup can carry 100 ml of water in its brim, for example, it is said to have a 100 ml capacity. Volume can also be used to describe how much space a three-dimensional object occupies.

Market share comes in two flavors: value and volume. The business's overall shares of its total accumulated sector sales serve to define a value market share. On the other hand, a volume market share refers to the precise number of units the company markets in comparison to the total number of units sold in the market.

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Answer:

Force=mass×acceleration.

4:5 for masses , 2:3 for acceleration.

For the first car it will be 4×2=8N

For the second car it will be 5×3=15N

The line charge density on a long wire if the electric field 45 cm from the wire has magnitude 240 kn/c and points toward the wire is  2.08 x 10-7 C/m.

Calculating the line charge density of a long wire is a simple process. To begin, we need to know the magnitude of the electric field at a given distance from the wire. In this case, the electric field 45 cm from the wire has a magnitude of 240 kn/c and points toward the wire.

Using this information, we can calculate the line charge density of the wire using the equation:

Line charge density (λ) = Electric field (E) * Permittivity of free space (ε0) / 2π * distance (r)

Plugging in the values, we get:

λ = 240 kn/c * 8.85 x 10-12 C2/Nm2 / 2π * 0.45m

Solving this equation, we get a line charge density of 2.08 x 10-7 C/m.

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The formula z = v/c represents the redshift of an object, where z is the observed redshift, v is the recessional velocity (speed) of the object, and c is the speed of light. In the context of cosmology, the redshift is used to measure how much the light from distant galaxies has been stretched due to the expansion of the universe.

To determine the recessional velocity of a galaxy using the redshift formula, we can rearrange the equation to solve for v. Multiply both sides of the equation by c to isolate v:

v = z * c

Here, z is a dimensionless quantity representing the redshift. Since the speed of light (c) is a constant, the recessional velocity of the galaxy is directly proportional to the redshift.

Given that z = v/c, we can substitute the value of z into the equation to find the recessional velocity of the galaxy:

v = (v/c) * c = v

This implies that the velocity of the galaxy is equal to the speed of light. Therefore, the correct answer is option b. The recessional velocity of the galaxy is 1.3 times the speed of light.

It's important to note that this result appears to violate the theory of relativity, which states that no object with mass can travel at or faster than the speed of light. However, in the case of the redshift formula, the recessional velocity is a consequence of the expansion of space itself, rather than an object moving through space.

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In order to compare the numbers, let's put all of them into the decimal form:

We can see that the greater one is 26.8 (all other numbers are close to 2, and this one is close to 27).

The numbers in decrescent order are:

26.8, 271%, 2.62, 2 2/5, 2.26.

Answer:

26.8

Explanation:

2.26 < 2.4 < 2.62 < 271/100 = 2.71 < 26.8

Answer:

i don't really know but i think yes sorry if it is wrong

Answer:

2000

Explanation:

well it is just   20 * 100 = 2000 v

The free-body diagram is attached in the image below. The time for the toy car to be in rest position is 0.6 s

From the given information:

A force is regarded as a push that causes an alteration in motion of an object within a specified distance. It is usually expressed by the formula:

∴

Using the first equation of motion for the time to bring the car to rest from it reduced speed of 8 m/s;

since the final speed to bring the car in rest position is (0), then:

0 = 8 -  13.33(t)

13.33(t) = 8

t = 8/13.33

t = 0.6 seconds

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Answer:

a)  ΔV₁ = 21.9 V, b) U₀ = 99.2 10⁻¹² J, c) U_f = 249.9 10⁻¹² J,  d)  W = 150 10⁻¹² J

Explanation:

Let's find the capacitance of the capacitor

         C = \(\epsilon_o \frac{A}{d}\)

         C = 8.85 10⁻¹² (8.00 10⁻⁴) /2.70 10⁻³

         C = 2.62 10⁻¹² F

for the initial data let's look for the accumulated charge on the plates

          C = \(\frac{Q}{\Delta V}\)

          Q₀ = C ΔV

           Q₀ = 2.62 10⁻¹² 8.70

           Q₀ = 22.8 10⁻¹² C

a) we look for the capacity for the new distance

          C₁ = 8.85 10⁻¹² (8.00 10⁻⁴) /6⁴.80 10⁻³

          C₁ = 1.04 10⁻¹² F

          C₁ = Q₀ / ΔV₁

          ΔV₁ = Q₀ / C₁

          ΔV₁ = 22.8 10⁻¹² /1.04 10⁻¹²

          ΔV₁ = 21.9 V

b) initial stored energy

          U₀ = \(\frac{Q_o}{ 2C}\)

          U₀ = (22.8 10⁻¹²)²/(2  2.62 10⁻¹²)

          U₀ = 99.2 10⁻¹² J

c) final stored energy

          U_f = (22.8 10⁻¹²) ² /(2  1.04 10⁻⁻¹²)

          U_f = 249.9 10⁻¹² J

d) the work of separating the plates

as energy is conserved work must be equal to energy change

          W = U_f - U₀

          W = (249.2 - 99.2) 10⁻¹²

          W = 150 10⁻¹² J

note that as the energy increases the work must be supplied to the system

Answer:

Explanation:

The communicator

Answer:

It will apply the greatest pressure of an area of 1.

Explanation:

To find pressure use the formula P = F/A

P = 100/1

P = 100

Answer:

10 N / cm^2

Explanation:

The Formiula is P = F / A

P = presure

F = Force in Newtons

A = area.

The answer is the smaller the area the larger the pressure.

The smallest area you have given us is 10 cm^2

The Pressure = 100N / 10 cm^2

Pressure = 10 N/cm^2  

Note: the units are not exactly standard units, but I've given the answer the way the question offers the units.

Answer:

10096

Explanation:

Please mark me brainlist

Answer: 4.192 years

Explanation:

Answer:

c i think

Explanation: