The correct option is A. If a room contains 65 kg of dry air and 0.43 kg of water vapour at \(25^0C\) and 90 kpa total pressure. The relative humidity of the air in the room is 29.9%.
For calculating the relative humidity, determine the vapour pressure of water at \(25^0C\), which can be found using a psychrometric chart or a vapour pressure table. The vapour pressure of water at \(25^0C\) is approximately 3.17 kPa.
Next, calculate the saturation vapour pressure at \(25^0C\), which is the maximum vapour pressure the air can hold at that temperature. Using the same methods, we find that the saturation vapour pressure at \(25^0C\) is approximately 10.6 kPa.
Now, calculate the relative humidity using the formula:
Relative Humidity = (Vapor Pressure of Water / Saturation Vapor Pressure) * 100%
Plugging in the values:
Relative Humidity = (3.17 kPa / 10.6 kPa) * 100% ≈ 29.9%
Therefore, the relative humidity of the air in the room is approximately 29.9%.
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The complete question is:
Use appropriate software for calculations. a room contains 65 kg of dry air and 0.43 kg of water vapour at \(25^0C\) and 90 kpa total pressure. the relative humidity of air in the room is:_______
(a) 29.9% (b) 35.2% (c) 41.5% (d) 60.0% (e) 66.2%
scientific notation expresses a value as the product of a number between 1 and 10 and_____
Answer:
and the power to which the number should be raised:
1.50E2 = 1500
4.167E4 = 41,760
4.167E-4 = .0004176
Mass of the earth = 5.98 * 10^24 kg = 5.98E24 kg
Some examples of scientific notation
Answer:
hey Army
I'm B.T.S Army
안녕하세요
Which of the following changes would decrease the coefficient of friction needed for this rice? a. increasing the rider's mass b. increasing the radius of the rice c. increasing the speed of the ride d. increasing the acceleration due to gravity (taking the ride to another planet)
The correct answer is b. Increasing the radius of the rice would decrease the coefficient of friction needed for the ride, as a larger surface area would increase the area of contact between the rider and the ride, thus reducing the force of friction.
What is gravity?Gravity is a natural phenomenon by which all objects with mass are brought towards each other. It is most commonly observed as the attraction between objects with mass, such as the Earth and the Moon. This force of attraction is known as the force of gravity. Gravity also affects light and other particles, such as protons and neutrons. Gravity holds us to the ground and helps keep the planets in their orbits. It is the reason why objects fall to the ground and why we can’t easily fly off into space. Gravity is one of the fundamental forces of nature and is essential to understanding the universe.
Increasing the speed of the ride would increase the coefficient of friction needed, as it would increase the force of friction. Increasing the acceleration due to gravity would have no effect on the coefficient of friction needed for the ride.
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Definition: The energy transferred by a force to a moving object.
Answer:
Force applied
Explanation:
An object will remain at its state of rest unless a non zero for act on it
you are given that , , and . use the - characteristics to find the transitor parameter and the value of that produces .
To find the transistor parameter and the value of VBE that produces IC=4.5mA, we can use the - characteristics.
The - characteristics of a transistor represent the relationship between the collector current (IC) and the base-emitter voltage (VBE) for different values of collector-emitter voltage (VCE). By analyzing this graph, we can determine the transistor parameter and the value of VBE that produces a specific IC.
First, we need to locate the IC=4.5mA on the vertical axis of the - characteristics graph. Then, we trace a horizontal line from this point until it intersects with the curve of the transistor parameter we are interested in.
Next, we draw a vertical line from the intersection point until it intersects with the VBE axis. This will give us the value of VBE that produces the desired IC.
By following these steps, we can accurately determine the transistor parameter and the value of VBE that satisfies the given condition.
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How can people stop being Homophobia? °∩°
Pretty long so read if you will:
I'm pretty late to this but oh well. Well to start why are people homophobic in the first place? You might not understand as well but that is because me and you are growing up at a time and place where people are encouraged to be themselves and we're embracing people that are different than what is considered normal. Gay marriage was legalized literally in the US in 2015, 5 years ago. I come from Malaysia, one of the few countries where it's illegal to be gay and can cause a death penalty from what I've seen. Obviously I grew up in a place where gay and whatnot were a joke and is wrong. But we moved and I came to the US and my beliefs changes, it also helped that I was literally only 11 so I was more easier to change than adults. Majority of the world honestly, are not as open to the lgbtq+ community as a person in America might think. The belief that it's only a women and men probably stems from the fact that it's how u make babies. And if we know anything, society doesn't like things that are different. To stop people being homophobic you have to stop people from spreading the belief that it's wrong to be gay or bi. This is going to be hard and people really overestimate the world when it comes to change. Peoples belief won't be changed so quick just, change doesn't happen quick. It's going to be a long time and maybe even never, look at racism. We all exist together for so long but there's still racism though much less compared to back then. As long as people stop teaching that next generation, us, that being lgbtq+ is bad, it will decrease but it will take a long time. And as much as I agree we need it to be now, it won't and trying to force something will only cause more backlash. Just try to inform the people around you and understand change does not happen fast, it's slow, especially if it you want it to be permanent.
I also need the answer to this one. Thank you
Answer:
its J. Waning Crescent hope it helps
What questions do you still have about supermassive black holes after watching this Ted Talk? Do you feel that you have a deeper understanding of what they are and why they are important, like was asked of you in the third question? Explain and discuss.
After watching the Ted Talk, there were still a few questions that I had about supermassive black holes. Firstly, I wanted to know more about the event horizon and what it exactly entails. Although the speaker briefly touched upon this subject, I would have appreciated a more in-depth explanation. Additionally, I would have liked to know more about the role of supermassive black holes in the universe.
While the speaker did mention that these black holes are responsible for the creation of galaxies, I wanted to know more about how this process works and why it is so important.Despite these questions, I do feel that I have a deeper understanding of supermassive black holes and their importance.From the Ted Talk, I learned that supermassive black holes are some of the largest objects in the universe and are essential for the formation of galaxies. I also learned that these black holes are incredibly powerful and have the ability to affect the trajectory of stars and planets.Overall, I think that the Ted Talk did a great job of explaining supermassive black holes in a way that was easy to understand. While there were still a few questions that I had after watching the video, I feel that I now have a better grasp of what supermassive black holes are and why they are so important.For such more question on supermassive
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A ball is projected horizontally from the top of a vertical cliff 40m high with a velocity of 20m/s. Calculate the vertical component of the velocity on getting to the ground
A ball when is projected horizontally from the top of a vertical cliff 40m high with a velocity of 20m/s, the vertical component of the velocity on getting to the ground is 28.3 m/s.
What is motion under gravitational field?When any object moves, it can be said to be in motion under gravity because gravity has an impact on the object’s vertical motion. Gravity is also called as the force that pulls things downward. In actuality, gravity pulls objects toward the Earth’s center.
What is the motion under gravity equation?The particle’s initial velocity is 0 during free fall. Consequently, this v=gt is the equation of motion.
An object launched into the air may also experience a shift in upward velocity due to gravity, which causes it to slow down and return to Earth’s surface. The Moon is kept in orbit by the force of Earth’s gravity, which also causes the Moon to rotate constantly.
Initial horizontal velocity = 20\(ms^{-1}\)
Initial vertical velocity = 0
Vy= Uy + gt
Vy= gt {Uy= 0}
Vy= 10 × 2.83= 28.3m/s
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What is the speed of an object at rest?
0 m/s
O 1 m/s
O 10 m/s
Answer:
1 m/s so number 2 is the right one
Explanation:
so when it is at rest it still has some of the left over energy so it would be at 1 m/s
How can we teach our kitty to behave properly
Answer:
I have no idea.
Explanation:
I just wanted to tell you I absolutely read this wrong.
Please help u guys acellus sucks
Answer:
6.0cm
Explanation:
Given
focal length = 15.0cm
object distance = 10.0cm
Required
Image distance v
Using the formula
1/f = 1/u + 1/v
1/15 = 1/10+1/v
1/v = 1/15 + 1/10
1/v = 2+3/30
1/v = 5/30
v = 30/5
v = 6.0cm
Hence the image distance is 6.0cm
Answer:
6.0 (2 sig figs)
Explanation:
Is it General Physics? I had it and passed the Final Exam with an A in the beginning of July!
someone please answer this, ill give you brainliest and your getting 100 points.
True
Explanation:Changes in the Earth's orbit around the sun and changes in the tilt and wobble of the Earth's axis can lead to cooling or warming of the Earth's climate because they change the amount of energy our planet receives from the sun
an automobile with a mass of 1000kg, including passengers, settles 1cm closer to the ground for every additional 100kg of passengers. it is driven with a constant horizontal speed of 20km/h over a washboard road with sinusoidal bumps. the amplitude and wavelength of the sinusoidal bumps are 5cm and 20 cm respectively. find the amplitude of oscillations of the automobile, assuming it moves vertically as an undamped driven harmonic oscillator. neglect the mass of the wheels, springs, and assume the wheels are in permanent contact with the road.
The amplitude of oscillations of the automobile can be calculated using the formula: A = (m * g * h) / (k + m * w^2)
where:
m = 1000 kg (mass of the automobile including passengers)
g = 9.8 m/s^2 (acceleration due to gravity)
h = 5 cm = 0.05 m (amplitude of the sinusoidal bumps)
k = effective spring constant of the suspension system
w = 2 * pi * f
= 2 * pi * v / lambda
= 2 * pi * 20 / 20
= 2 * pi (frequency of the bumps, v is the speed of the car, lambda is the wavelength)
We don't have the value for k,
so we can assume it to be a constant value for all cars.
Therefore, the amplitude of oscillations can be calculated as:
A = (1000 kg * 9.8 m/s^2 * 0.05 m) / (k + 1000 kg * (2 * pi)^2)
This value will give us the maximum vertical displacement of the car from its mean position.
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T/F: galvanized wire rope is approximately 10% higher in strength than bright wire rope.
The answer is true. Yes the galvanized wire rope is approximately 10% higher in strength than bright wire rope.
True. Galvanized wire rope is known for its increased strength compared to bright wire rope, with approximately a 10% higher breaking strength. This is due to the galvanizing process that adds a protective zinc coating to the wire, increasing its durability and resistance to corrosion. The zinc coating can also increase the strength of the wire rope by up to 10%, compared to bright wire rope, which is untreated and has no coating. Therefore, galvanized wire rope is generally stronger than bright wire rope and can be used in more demanding applications.
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some people have suggested that electric vehicles only shift the emission of air pollutants from dispersed sources to point sources. explain and defend or refute this statement.
This statement is partially true, but it is important to understand the context and implications. Electric vehicles do not produce tailpipe emissions, which means that they can reduce local air pollution in urban areas.
However, the generation of electricity to power these vehicles can still produce emissions at the point of generation, such as power plants.
The extent of this shift depends on the source of electricity generation in a given region. In areas with a high percentage of renewable energy sources, such as wind and solar, the emissions associated with electric vehicle use would be negligible. In areas that rely heavily on coal-fired power plants, the emissions associated with electric vehicle use could be significant.
It is important to note that even in areas with high emissions from electricity generation, electric vehicles still have benefits over traditional gasoline vehicles. This is because electric vehicles are more energy-efficient and produce fewer emissions overall, even when accounting for emissions from electricity generation.
In summary, while electric vehicles do shift the source of emissions from tailpipes to power plants, the overall reduction in emissions is still significant, especially in areas with a high percentage of renewable energy sources.
Therefore, the statement that electric vehicles only shift the emission of air pollutants from dispersed sources to point sources is not entirely accurate and does not fully capture the benefits of electric vehicles.
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enc
Why do two socks sometimes stick together
in a dryer?
A. Both socks have a positive charge.
CB. Both socks have a negative charge.
C. Protons move from one sock to
another.
CD. Electrons move from one sock to
another.
Answer:
D. Electrons mover from one to another
Explanation:
Static electricity occurs when electrons are transferred from one object to another.
Question 18 A truck of mass 950 slugs is driven at 55 miles per hour. The kinetic energy of the truck is 98000 ft*lb 131 kJ 131 MJ O 1.44 x106 ft· lb
The correct answer is 131 kJ. To calculate the kinetic energy of the truck, we first need to convert its mass from slugs to pounds.
1 slug = 32.174 pounds
So, 950 slugs = 30,565 pounds
Next, we need to convert the speed from miles per hour to feet per second:
55 miles per hour = 80.67 feet per second
Now we can use the formula for kinetic energy:
KE = 0.5 x m x v^2
where KE is kinetic energy, m is mass, and v is velocity.
Plugging in the values:
KE = 0.5 x 30,565 x (80.67)^2
KE ≈ 98,000 ft·lb
Therefore, the kinetic energy of the truck is 98,000 ft·lb or approximately 131 kJ.
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Urgent please!!!!!!!!!!!!!!!!!!!!!!
A program can only create one object of each class.
A. True
B. False
Help me find the answer from the given options.
Note: If the question asked for work done by the car, then it will be equal to the kinetic energy of the body.
what is food poisoning ?
Answer:
salmonella and from eating raw food
Explanation:
Answer:
Food Poisoning is bad very bad. You can get the following sicknesses: cramping, nausea, vomiting, or diarrhea. It usually comes from food that has a lot of Germs in it, Bacteria, Viruses, etc. But it is not usually something that can kill you, just go to your doctor and they might give you medicine to stop the Poisoning.
explica de que tipo es cada oración según la actitud del hablante
Answer:
Según la actitud del hablante las oraciones se clasifican en enunciativas, interrogativas, etc. ... adverbios o expresiones que complementan a toda la oración (COr): ojalá, quizá.
Explanation:
A metal block of mass 5kg lies on a horizontal platform. if a horizontal force of 8n applied to the block through its centre of mass just slides the block on the platform. what will be the coefficient of limiting friction between the block and the platform
Answer: the coefficient would be either 4 or 5
Explanation:
A coin released at rest from the top of a tower hits the ground after falling 1.5 s. What is the speed of the coin as it hits the ground? (Disregard air resistance. a = −g = −9.81 m/s 2 .)
Initial speed of the coin (u)= 0 (As the coin is released from rest)
Acceleration due to gravity (a) = g = 9.81 m/s²
Time of fall (t) = 1.5 s
From equation of motion we have:
\( \boxed{ \bf{v = u + at}}\)
By substituting values in the equation, we get:
\( \longrightarrow \) v = 0 + 9.81 × 1.5
\( \longrightarrow \) v = 14.715 m/s
\( \therefore \) Speed of the coin as it hits the ground/Final speed of the coin = 14.715 m/s
The speed of the coin as it hits the ground is 14.715 m/s.
We can solve the problem above using the equation of acceleration under gravity.
⇒ Equation:
v = u+gt................... Equation 1
⇒ Where:
The final velocity of the coinu = Initial velocity of the coing = acceleration due to gravityt = timeFrom the question,
⇒ Given:
u = 0 m/s (from rest)t = 1.5 sg = -9.81 m/s²Substitute these values into equation 1
v = 0+1.5(-9.81)v = -14.715 m/sNote the speed has a negative sign because it acts in the same direction as the acceleration due to gravity
Hence, the speed of the coin as it hits the ground is 14.715 m/s.
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The temperature of the water at the bottom of a waterfall is greater than the temperature of the
water at the top.
The gravitational potential energy of the water at the top is transferred to thermal energy at the
bottom.
The specific heat capacity of water is 4200 J/(kg °C).
What is the temperature difference for a waterfall of height 21 m?
A 0.005 °C
B 0.05°C
C 20°C
D 200°C
The answer is B (0.05C), but how?
Can someone explain?
The temperature difference for a waterfall of height 21 m is 0.05 °C. The correct option is B.
The temperature difference for a waterfall can be calculated using the principle of conservation of energy. When water falls from a height, its potential energy is converted into kinetic energy and then into thermal energy due to the friction and turbulence created by the waterfall.
The potential energy of an object is given by the equation: PE = mgh, where m is the mass, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height.
In this case, we can assume that the mass of the water remains constant throughout the fall. The change in potential energy is then equal to the change in thermal energy.
ΔPE = Δthermal energy
mgh = mcΔT
Here, c is the specific heat capacity of water (4200 J/(kg °C)) and ΔT is the change in temperature.
We can rearrange the equation to solve for ΔT:
ΔT = gh/c
Given:
h = 21 m
g = 9.8 m/s^2
c = 4200 J/(kg °C)
Plugging in the values:
ΔT = (9.8 m/s^2) * (21 m) / (4200 J/(kg °C))
ΔT = 0.05 °C
Therefore, the temperature difference for a waterfall of height 21 m is 0.05 °C. The answer is option B.
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A positive charge is moving across a room from south to
north. A magnetic field runs from east to west. In what
direction is the magnetic force on the moving positive
charge?
O toward the east
O toward the west
•
toward the floor
© toward the ceiling
Answer:toward the ceiling
Explanation:
if you use the right hand rule it will point to the ceiling
A wave of green light has a wavelength of 505 nm. How much energy does this wave have? Be sure to show your work! (remember that 1 nm = 1â10-9 m.)
To calculate the energy of a wave of green light with a wavelength of 505 nm, we can use the equation\(E = hc/λ\\\), where E represents energy, h is Planck's constant, c is the speed of light, and λ is the wavelength.
According to the equation \(E = hc/λ\\\), the energy of a wave is inversely proportional to its wavelength. As the wavelength decreases, the energy of the wave increases.
To calculate the energy of the green light wave with a wavelength of 505 nm, we need to convert the wavelength to meters. Using the conversion factor \(1 nm = 1 × 10^(-9)\)m, we can express the wavelength as \(505 nm × (1 × 10^(-9) m/1 nm) = 505 × 10^(-9) m.\)
Next, we substitute the values into the equation E = hc/λ. Planck's constant, h, is approximately 6.626 × 10^(-34) J·s, and the speed of light, c, is approximately 3.00 × 10^8 m/s.
\(E = (6.626 × 10^(-34) J·s × 3.00 × 10^8 m/s) / (505 × 10^(-9) m) = 3.941 × 10^(-19) J.\)
Therefore, the wave of green light with a wavelength of 505 nm has an energy of approximately \(3.941 × 10^(-19) joules.\)
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neither the operator nor anyone else should ever stand directly in front of the wheel of an abrasive power tool as it accelerates to full operating speed. why? a. because it could throw off remnants of debris from the last job, putting a fragment in someone’s eye b. because if it is not secured tightly enough to the spindle, it could roll off and right into the operator c. because there is always the chance that the wheel wasn’t sound and could disintegrate or explode d. none of the above
There is always a potential that an abrasive power tool's wheel wasn't sound and may burst or disintegrate, thus neither the operator nor anyone else should ever stand in front of the wheel as it accelerates to full operational speed. So, C is the best choice.
Before mounting, all abrasive wheels must undergo a thorough inspection and ring test to make sure there are no fractures or other flaws. The spindle's grinding wheels must easily fit on it without being pressed in.
The spindle nut should only be tightened enough to secure the wheel. The following are a few recommendations for using abrasive wheels: The spindle end, nut, and flange projection guards on abrasive wheel tools must be covered. Keep the wheel in the right alignment. Never use more force than the fastenings can handle.
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Two 1.21 kg masses are 4.22 m apart on a frictionless table. Each has 22.78 microCoulombs of charge. What is the initial acceleration of each mass if they are released and allowed to move?
First, let's calculate the electric force, using the formula below:
\(\begin{gathered} F_e=\frac{KQq}{d^2}\\ \\ F_e=\frac{9\cdot10^9\cdot(22.78\cdot10^{-6})^2}{4.22^2}\\ \\ F_e=262.26\cdot10^{-3}=0.26226\text{ N} \end{gathered}\)Now, let's use the second law of Newton to find the acceleration:
\(\begin{gathered} F=m\cdot a\\ \\ 0.26226=1.21\cdot a\\ \\ a=\frac{0.26226}{1.21}\\ \\ a=0.217\text{ m/s^^b2} \end{gathered}\)Types of Forces Lab Report
Instructions: In the Types of Forces lab, you will experiment with the contact force friction. Use the following lab report to record your hypothesis, materials, procedures, observations, and conclusion. You will submit your completed report.
Name and Title
Name of Lab:
Student Name:
Instructor:
Date:
Objective
The purpose is to test whether the surface texture of the ground affects the distance an object can roll.
Hypothesis
If an object rolls over _______________ (type of material), then it will _____________ (describe the prediction of distance it will travel).
Materials
For this lab, I used the following items:
Procedure
Short summary of what I did:
I experienced the following errors while doing my experiment:
Test (independent) variable (What was different about my test groups?):
Outcome (dependent) variable (What was I measuring?):
Data
Record the distance traveled for each of the trials for the three floor surfaces in the table below.
Distance Object Traveled
Floor Surface Trial 1 Trial 2 Trial 3
Data Analysis
Calculate the average distance traveled for each floor surface. Use the following guidelines for calculating averages, and show your work.
Floor Covering Calculation of the Average Average Distance Traveled
Example (trial 1 measurement + trial 2 measurement + trial 3 measurement) / 3 (number of trials) Your answer from the calculation, showing the average distance the ball rolled for that floor covering.
Frictional force is reduced in smooth surfaces but is large in rough surfaces.
What is Force?Force is defined as an agent which causes a change in the motion or state of an object.
Forces are of two types:
Contact forces and Non-contact forcesContact forces include frictional force.
Frictional forces refers to the force which acts between two surfaces in contact by opposing the relative motion of one over the other
Frictional force depends on the nature of surfaces in contact where rough surfaces produce greater frictional force than smooth surfaces.
Therefore, frictional force is reduced in smooth surfaces but is large in rough surfaces.
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a projectile is launched horizontally, from the top of a 30 m high building with an initial velocity of 30 m/s. the speed of the projectile just before it strikes the ground is:
The speed of the projectile just before it strikes the ground is 29.4 m/s.
Since the projectile is launched horizontally, it will only experience acceleration due to gravity acting vertically downwards. The horizontal velocity of the projectile will remain constant throughout its flight.
We can use the following kinematic equation to find the speed of the projectile just before it strikes the ground:
\(v^2 = u^2 + 2as\)
where:
v is the final velocity (which we want to find)
u is the initial velocity in the horizontal direction, which is 30 m/s
a is the acceleration due to gravity, which is approximately 9.81 m/s²
s is the vertical displacement of the projectile, which is equal to the initial height of the building, 30 m.
Since the projectile is launched horizontally, the initial vertical velocity is zero.
Substituting these values into the equation, we get:
v² = (30 m/s)² + 2(-9.81 m/s²)(30 m)
v² = 900 m/s² - 1765.4 m^2/s²
v² = -865.4 m²/s² (note that the result is negative because the velocity is in the opposite direction to the acceleration)
Taking the square root of both sides of the equation (ignoring the negative solution since speed is always positive), we get:
v = 29.4 m/s (rounded to one decimal place)
Therefore, the speed of the projectile just before it strikes the ground is approximately 29.4 m/s.
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