Using absolute magnitude and not apparent
magnitude, what is the faintest star?
A) Proxima Centauri
B) Wolf 359
C) Ross 154
D) UV Ceti

A meteoroid is a rock in space when it enters a planet's atmosphere it is a meteor, any piece remaining after impact is a meteorite.

Meteoroids are small objects floating in space. They are made up of rocks, iron, and dust. In our solar system, meteoroids orbit the Sun and some planets.

When these meteoroids enter the atmosphere of earth, they become meteors. These meteors started to burn and shine due to friction.

Meteorites are the surviving un-burnt piece of meteors that hit the surface of the Earth.  

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Answer:

density=mass/volume

density=19.3

mass=x

volume=100

we are looking for mass so we have to change the subject formula to m=dv

which means mass is equals to density multiplied by volume

m= 19.3 x 100

which is 1930.

Answer:

not enough information need more information to answer the question

With 4.3 m/s velocity, is the cheetah running.

velocity= distance/time

distance=27.6 m

time=6.3 s

velocity=27.6 m/6.3 s

velocity=4.3 m/s

A vector number known as velocity describes "the pace at which an item changes its location." Imagine a person moving quickly, taking one stride ahead, one step back, and then beginning from the same place each time. A vector quantity is velocity. As a result, velocity is aware of direction. One must consider direction while calculating an object's velocity. Saying that an item has a velocity of 55 miles per hour is insufficient. The direction must be included in order to adequately characterize the object's velocity. Simply said, the velocity vector's direction corresponds to the motion of an item.

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Answer:

9.8kW

Explanation:

Given data

Mass= 60kg

Hieght= 4m

Time= 4.2seconds

We know that the energy possessed is given as

PE=mgh

PE=60*9.81*4

PE= 2354.4 Joulse

Also, the expression for power is

Power=Energy*Time

Power= 2354.4*4.2

Power=9888.48 watt

Power= 9.8kW

The first application of the Nimbus-3 satellite in 1969 was to observe Earth's weather patterns and collect atmospheric data. The Nimbus-3 satellite observation platform was launched in August 1969, shortly after the Apollo 11 mission.

Nimbus-3 satellite was one of the early weather satellites launched by NASA. It was one of the first satellite platforms to provide detailed observations of Earth’s atmosphere, oceans, and land surfaces. Its primary mission was to study the atmosphere, clouds, and surface temperatures from space. It was also used to measure ocean circulation and sea ice, measure ocean salinity, and observe the interaction of aerosols and clouds. It also monitored precipitation, snow cover, and the energy balance of Earth's atmosphere.

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Given:

Initial velocity = 11 m/s

Average acceleration = -1.81 m/s²

Let's determine how long it takes the horse to decrease its velocity to 6.5 m/s.

Apply the equation of motion:

Where:

v is the final velocity = 6.5 m/s

u is the initial velocity = 11 m/s

a is the acceleration = -1.81 m/s²

t is the time in seconds.

Thus, we have:

Let's solve for t.

Subtract 11 from both sides:

Therefore, it took the horse approximately 2.49 seconds to decrease its velocity to 6.5 m/s

ANSWER:

2.49 seconds.

The pattern formed by iron filings around magnets shows the magnetic field lines produced by the magnets.

Magnetic field lines are described as imaginary lines, which depict the strength and direction of the magnetic field.

The iron filings align themselves along the magnetic field lines, which helps to provide a visual representation of the field's direction and shape. The filings tend to concentrate near the poles of the magnets, where the magnetic field is stronger.

This pattern is important as it helps visualize the magnetic field and understand its characteristics, such as the shape, direction, and strength of the magnetic field produced by the magnets.

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B

Having a coach guide you and explain the steps would be beneficial to your performance

Answer:

0.9 m

Explanation:

Hooke’s Law

\(\large\boxed{F = ke}\)

where:

Given values:

Substitute the given values into the formula to find k:

\(\implies 2.0=0.30k\)

\(\implies k=\dfrac{2.0}{0.30}\)

\(\implies k=\dfrac{20}{3}\; \sf N/m\)

To find the extension if the force applied is 6 N, substitute the found value of k and the given value of F into the formula and solve for e:

\(\implies 6=\dfrac{20}{3}e\)

\(\implies 18=20e\)

\(\implies e=\dfrac{18}{20}\)

\(\implies e=0.9\; \sf m\)

In a refracting telescope, the distance between the objective and eyepiece lenses satisfies a certain relationship that ensures the image produced by the objective is at infinity and is used as the object for the eyepiece.

A refracting telescope consists of two lenses: the objective lens and the eyepiece lens. The objective lens produces an image of a distant object at its focal point, which is located at a distance f1 from the lens. This image is real and inverted, but it is also very small.

The eyepiece lens is placed in front of this image and produces a magnified virtual image that can be viewed by the observer. The distance between the eyepiece lens and the objective lens is called the tube length.

For the telescope to work properly, the distance between the lenses must satisfy the relationship f2 = f1/ (M-1), where f2 is the focal length of the eyepiece lens, f1 is the focal length of the objective lens, and M is the magnification of the telescope.

This relationship ensures that the image produced by the objective lens is at infinity and is used as the object for the eyepiece. It also ensures that the magnification of the telescope is equal to the ratio of the focal lengths of the two lenses.

In conclusion, the distance between the objective and eyepiece lenses in a refracting telescope satisfies a specific relationship that ensures the image produced by the objective is at infinity and is used as the object for the eyepiece.

This relationship is f2 = f1/(M-1), where f1 and f2 are the focal lengths of the objective and eyepiece lenses, respectively, and M is the magnification of the telescope. This relationship is essential for the proper functioning of the telescope and for producing a magnified, clear image of distant objects.

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A current of 5 A would dissipate energy at the same rate (P0) in the second copper wire as a current of 10 A does in the first copper wire.

The power dissipated by a wire of length L, diameter d, and resistivity ρ carrying a current I is given by:

P = I² R = I² (ρ L / A)

where R is the resistance of the wire, A is the cross-sectional area of the wire (πd²/4 for a circular wire), and ρ is the resistivity of the wire material (which is assumed to be constant).

For the first copper wire, we have:

P0 = I² (ρ L / A) = (10 A)² (ρ L / (πd²/4))

For the second copper wire, the length is the same (L), but the diameter is doubled (2d). The cross-sectional area is therefore four times larger (π(2d)²/4 = 4πd²/4 = πd²), and the resistivity is the same as before (since it's the same material). Let's call the current in the second wire I2. Then we have:

P0 = (I₂)² (ρ L / A) = I₂² (ρ L / (πd²))

To find I₂, we can set the two expressions for P0 equal to each other and solve for I₂:

(10 A)² (ρ L / (πd²/4)) = I₂² (ρ L / (πd²))

Simplifying, we get:

I₂² = (10 A)² (πd²/4) / (πd²) = 100 A² / 4 = 25 A²

Taking the square root, we get:

I₂= 5 A

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Answer:

b

Explanation:

Answer:

Explanation:

m = 1500 kg

u = 15 m/s

v  = 25 m/s

s = 100 m

\(v^{2} = u^{2} + 2as\)

\(25^{2} = 15^{2} + 2a\) × 100

625 = 225 + 200 a

-200a = 225 - 625

-200a = -400

a = 400 / 200

a = 2 m/s

f = ma

f = 1500 × 2

= 3000 N

Hope this helps

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Answer:

On this page, we'll outline the three principles you should understand regarding series circuits: Current: The amount of current is the same through any component in a series circuit. Resistance: The total resistance of any series circuit is equal to the sum of the individual resistances

The quantity that is the same at all points in a series circuit is the current. The correct option is option (1).

The current in a series circuit is constant all the way around. This means that the same amount of current flows through each component, such as resistors, lamps, or other devices, connected in series.

The current is measured in units of amperes (A) and is determined by the voltage applied to the circuit and the total resistance in the circuit according to Ohm's law (I = V/R).

Therefore, The quantity that is the same at all points in a series circuit is the current. The correct option is option (1).

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Answer:

9.8m/s²

Explanation:

because you you can see that acceleration due to gravity is always equals to 9.8 m per second square

The magnitude and location of the resultant of the distributed load is given as

\(\bar{x}=3.4545 \mathrm{~m} \quad$\)

This is further explained below.

Generally, In the fields of physics and engineering, a resultant force is a single force and related torque that is created by combining a system of forces and torques operating on a rigid body by vector addition. This process yields the single force and associated torque.

\($\sum F_y=0$$F_R=\frac{1}{2} \times(600+1600) \times 6=6600 \mathrm{~N}$\\\\$\sum M_2=0$\)

\($$F_R \times \bar{x}=(600 \times 6) \times\left(\frac{6}{2}\right)+(0.5 \times(1600-600) \times 6) \times\left(\frac{6 \times 2}{3}\right)\\\\$$$6600 \bar{x}=10800+12000$\\\\$\bar{x}=3.4545 \mathrm{~m} \quad$\)

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CQ is attached below

The acceleration caused by gravity, or 9.81 m/s², which acts on the object, causes the projectile's vertical velocity to vary.

A projectile's horizontal velocity is constant (a never changing in value), Gravity causes a downward vertical acceleration with a magnitude of 9.8 m/s/s. A projectile's vertical velocity fluctuates by 9.8 m/s per second, A projectile's vertical motion exists unrelated to its horizontal motion.

The acceleration caused by gravity, or 9.81 m/s², which acts on the object, causes the projectile's vertical velocity to vary. Therefore, this choice is likewise false. As is common knowledge, an object's vertical velocity is not constant, and momentum is a function of velocity.

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In an elastic collision, both momentum and kinetic energy are conserved.

First, we need to calculate the initial momentum of both balls:

P(golf ball) = m(golf ball) x v(golf ball) = 0.750 kg x 22 m/s = 16.5 kg*m/s to the right

P(billiard ball) = m(billiard ball) x v(billiard ball) = 0.050 kg x (-15.0 m/s) = -0.75 kg*m/s to the left

Since momentum is conserved, the total momentum before the collision is equal to the total momentum after the collision:

P(total) before = P(total) after

16.5 kg*m/s - 0.75 kg*m/s = m(total) x v(total) after

m(total) = 0.750 kg + 0.050 kg = 0.8 kg

v(total) after = (16.5 kg*m/s - 0.75 kg*m/s) / 0.8 kg = 20.4375 m/s to the right

Now, we need to calculate the individual velocities of each ball after the collision. We can use the conservation of kinetic energy equation:

1/2 x m(golf ball) x (v(golf ball) after)^2 + 1/2 x m(billiard ball) x (v(billiard ball) after)^2 = 1/2 x m(golf ball) x (v(golf ball))^2 + 1/2 x m(billiard ball) x (v(billiard ball))^2

Plugging in the given values and solving for the velocities after the collision, we get:

v(golf ball) after = 38.375 m/s to the right

v(billiard ball) after = -18.9375 m/s to the left

Therefore, the golf ball is moving faster to the right and the billiard ball is moving slower to the left after the elastic collision.

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The mass and weight of object on moon is 0.0138kg  and 0.0229kg .

Since force is a vector quantity, we must consider the direction in which it acts. There are two main types of frictional force: static force (Fst) and sliding force (Fsl). Normal forces (FN) produce these forces acting perpendicular to the direction of motion, although they act in the opposite direction to the object's motion.

It is equivalent to the weight of the object plus the extra weight. For example, pushing down on a block of wood on a table increases the normal force and thus the frictional force.

me=12Kg

ge=10

gm=10/6= 1.66

M=?

me ge =M gm

M=me ge/gm

M=120/1.66

M=0.0138kg

W=mg =0.0138 x 10kg

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Answer:

Explanation:

you can detect the hardness of water collected from different sources by using soap. Soaps can be used to check the hardness of water as it forms insoluble precipitate with hard water.

Answer:

We can detect the hardness of water taken from different sources by adding soap to it.

Explanation:

If the soap does not form micelle in the water then it will be hard water. In simple language if the soap doesnot disslove in water then it will be soft water.

In Gloria's experiment, the dependent variable refers to the variable that is being measured or observed and is expected to change in response to the independent variable. The independent variable is the variable that is deliberately manipulated or changed by the experimenter.

In this case, Gloria is investigating how different kinds of wheels accelerate down a ramp. The dependent variable in her experiment would be the "Acceleration of Wheel." This is because Gloria is interested in observing and measuring how the wheels accelerate, which is the outcome or result she wants to analyze.

The independent variable, on the other hand, would be the "Type of Wheel." Gloria is deliberately changing and manipulating the type of wheel used in her experiment to see how it affects the acceleration. By comparing the acceleration of different types of wheels, she can determine whether the type of wheel has an impact on the acceleration down the ramp.

The other variables mentioned, "Radius of Wheel" and "Steepness of Ramp," are not specifically mentioned in the question as potential variables that Gloria is investigating. Therefore, they are not relevant to determining the dependent variable in this particular experiment.

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Answer:

30×6=n

Explanation:

30 students in her class× 6 = number of students in the entire 4th grade.

Answer:

The objects in interaction A are farther apart than in interaction B.

The objects in interaction A are farther apart than in interaction B.

According to Coulomb's law: The magnitude of each of the electric forces with which two point-at-rest charges interact is directly proportional to the product of the magnitude of both charges.

And inversely proportional to the square of the distance that separates them and has the direction of the line that joins them.

The formula will be given as:

] \(F=\dfrac{kq_1q_2}{r^2}\)

Intersaction A is having weak force since the magnitude of the force is same in both interaction A and B from the formula of force the force is also dependent on the distance between the charge.

Thus the weak force in the interaction A is due to the higher distance between the two charges.

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The person who is known as the father of modern rocketry is Robert H. Goddard.

The world's first liquid-fueled rocket was developed and built by Robert Hutchings Goddard, an American engineer, lecturer, and inventor who lived from October 5, 1882, to August 10, 1945. Goddard's rocket was successfully launched on March 16, 1926, ushering in an era of invention and space travel. Between 1926 and 1941, he and his team fired 34 rockets, reaching speeds of up to 885 km/h (550 mph) and heights of up to 2.6 km (1.6 mi). Many of the innovations that would enable spaceflight were foreseen in Goddard's work as an engineer and thinker.

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Answer:

F= 1800N

Explanation:

the equation for force is F= ma

so plug in the numbers: F= (120)(15)

solve this to get F= 1800N

tip: don't forget to add the units when writing your answer :)

In first scenario, the electric field vector's magnitude would be halved. In second scenario, the electric field vector's magnitude at point P would be doubled.

Charge and charge density are two concepts of electricity, and the following are the differences between them:

Charge: Charge is a property of matter that causes it to experience electrical and magnetic phenomena. It is the fundamental quantity that is responsible for electric phenomena. The SI unit of charge is Coulomb (C), and its symbol is ‘Q’. The charge of an object can be positive or negative or neutral. The charge on an object is measured using an electrostatic balance or an electroscope.

Charge Density: Charge density refers to the amount of charge per unit volume or unit area of a substance. Charge density is the amount of charge per unit length on a given rod. Its SI unit is Coulomb per meter cubed (C/m³). The charge density on an object can be either uniform or non-uniform, i.e., it may be constant over the surface area or may vary throughout it. An electric field vector E is produced by a rod carrying a charge distributed uniformly over the length of the rod. Let the magnitude of the charge be Q. Now, let us consider the following scenarios:

a) How does the field change if rod length is doubled using the same amount of charge?

Assume the point P is still located distance d above the left end of the rod. In this situation, if the rod's length is doubled, the charge will remain the same. Since the charge is distributed uniformly, the charge per unit length would be half of the initial value.

Therefore, the electric field vector's magnitude would be halved.

b) How does the field change if rod length is doubled using the same amount of charge density? Assume the point P is still located distance d above the left end of the rod.In this situation, if the rod's length is doubled, the charge density will remain constant. So, the total charge on the rod will be doubled, and the charge per unit length will remain constant.

As a result, the electric field vector's magnitude at point P would be doubled.

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Answer: The answer to this question is B

Explanation:

From what it says, you need to multiply both N and M . Do the math and you will get 386.37. Then round it. Therefore, your answer is B

The speed of the roller coaster at the bottom of the 25-meter height location hill is 29.53 m/s.

To determine the speed of the roller coaster at the bottom of the hill, you need to use the conservation of mechanical energy formula.

The formula is given as follows; KEi + PEi + Wnc = KEf + PEf

Where KEi is the initial kinetic energy,

PEi is the initial potential energy,

Wnc is the work done by non-conservative forces,

KEf is the final kinetic energy, and PEf is the final potential energy.

Since the roller coaster starts from rest at the top of the hill, its initial kinetic energy is zero (KEi = 0).

Thus, the conservation of mechanical energy formula can be rewritten as follows; PEi + Wnc = KEf + PEf

Solving for KEf, we get; KEf = PEi + Wnc - PEf

Substituting the values given; PEi = mgh = 198 kg × 9.8 m/s² × 25 m = 48,705 J

PEf = 0

Wnc = -5,506 J

KEf = 48,705 J - 5,506 J - 0KEf = 43,199 J

Since KE = 1/2mv², we can find the final velocity of the roller coaster as follows;

KEf = 1/2mv²v² = 2KEf / mv² = 2(43,199 J) / 198 kgv² = 873.68v = √873.68v = 29.53 m/s

Therefore, the speed of the roller coaster at the bottom of the hill is 29.53 m/s.

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