Usted atiende un hotel para mascotas donde recibe gatos y perros. Para alimentarlos usted compro dos sacos para perro y seis para gato y gasto $2100.00, en otra ocasión usted compro cinco sacos de comida para perro y dos sacos de alimento para gato y le cobraron $2000.00. ¿Cuánto cuesta el saco de alimentos para cada uno de los animales?

Answer:

\(3+\sqrt{15} \\3-\sqrt{15}\\\)

Step-by-step explanation:

if ax=6 and a = x-6...

x(x-6) = 6

Completing the square is a process such that \((x^2+2bx)=(x+b)^2-b^2\)

so the idea being, we have a system of equations of two variables and 4 equations, each one rendering a line, for this case these aren't equations per se, they're INEquations, so pretty much the function will be the same for an equation but we'll use > or < instead of =, but fairly the function is basically the same, the behaviour differs a bit.

we have a line passing through (-6,0) and (0,8), side one

we have a line passing through the x-axis and -6, namely (-6,0) and the y-axis and -4, namely (0,-4), side two

we have a line passing through (0,-4) and (6,4), side three

now, side four is simply the line connecting one and three.

the intersection of all four lines looks like the one in the picture below, so what are those lines with their shading producing that quadrilateral?

well, we have two points for all four, and that's all we need to get the equation of a line, once we get the equation, with its shading like that in the picture, we'll make it an inequality.

\((\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{8 -0}{0 +6} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = \cfrac{4}{3} ( x +6) \\\\\\ y=\cfrac{4}{3}x+8\hspace{5em}\stackrel{\textit{side one} }{\boxed{y < \cfrac{4}{3}x+8}}\)

\(\rule{34em}{0.25pt}\\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-4}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{-4 -0}{0 +6} \implies \cfrac{ -4 }{ 6 } \implies - \cfrac{2}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = - \cfrac{2}{3} ( x +6) \\\\\\ y=-\cfrac{2}{3}x-4\hspace{5em}\stackrel{\textit{side two} }{\boxed{y > -\cfrac{2}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\(\stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{(-4)}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{0}}} \implies \cfrac{4 +4}{6 -0} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{0}) \implies y +4 = \cfrac{4}{3} ( x -0) \\\\\\ y=\cfrac{4}{3}x-4\hspace{5em}\stackrel{ \textit{side three} }{\boxed{y > \cfrac{4}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\((\stackrel{x_1}{6}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) ~\hfill~ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{6}}} \implies \cfrac{ 4 }{ -6 } \implies - \cfrac{2}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{6}) \\\\\\ y=-\cfrac{2}{3}x+8\hspace{5em}\stackrel{ \textit{side four} }{\boxed{y < -\cfrac{2}{3}x+8}}\)

now, we can make that quadrilateral a trapezoid by simply moving one point for "side four", say we change the point (0 , 8) and in essence slide it down over the line to  (-3 , 4).  Notice, all we did was slide it down the line of side one, that means the equation for side one never changed and thus its inequality is the same function.

now, with the new points for side for of (-3,4) and (6,4), let's rewrite its inequality

\((\stackrel{x_1}{-3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{(-3)}}} \implies \cfrac{4 -4}{6 +3} \implies \cfrac{ 0 }{ 9 } \implies 0\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{ 0}(x-\stackrel{x_1}{(-3)}) \implies y -4 = 0 ( x +3) \\\\\\ y=4\hspace{5em}\stackrel{ \textit{side four changed} }{\boxed{y < 4}}\)

The equality's transitive property is If a = 7, then a = q, q = s, s = t, and t = 7 .The equality reflex states that if 4x Plus 2=6, then 4x must equal 6.

Two straight lines or rays intersect at a common endpoint to form an angle. The vertex of an angle is the point at which all points meet. Angle is derived from the Latin word angulus, which means "corner." Two rays (half-lines) combined into an angle have a single endpoint. The latter is known as the vertex of the angle, and the rays are known as its sides, occasionally as its legs, and occasionally as its arms. Two lines converge at a common point to form an angle.

given

The equality's transitive property is If a = 7, then a = q, q = s, s = t, and t = 7 .

The equality reflex states that if 4x Plus 2=6, then 4x must equal 6.

The equality's subtraction property states that if 3x = 9 then x = 3.

The premise of angle congruence is Since x = 7 if 7 = x

To know more about angle visit :-

https://brainly.com/question/28451077

#SPJ1

The calculated value of the area of the real room is 10.67 cm²

From the question, we have the following parameters that can be used in our computation:

In the drawing, 3cm represents 4cm

This means that

Scale factor = 4/3

Also, we have the dimension of the scale drawing to be

Dimension = 3cm by 2 cm

So, the area of the bedroom in the scale is

Area = 3cm * 2cm

For the actual room, we have

Area = 3cm * 2cm * (4/3)²

Evaluate the exponent

Area = 3cm * 2cm * (16/9)

Evaluate the products

Area = 10.67 cm²

This means that the real area is 10.67 cm²

Read more about scale factor at

https://brainly.com/question/29229124

#SPJ1

3/4 is 60% of 45.

\( \frac{60}{1} \)

\( \frac{3 \times 60}{4 \times 1 } = \frac{180}{4} \)

\( \frac{180}{4} = 45 \\ \frac{4}{4} = 1\)

\( \frac{45}{1} = 45\)

Answer:

10/8 or 1.25

Step-by-step explanation:

We can write this into an equation to help us understand what we need.

3/4=0.60x

We can make these both into fractions to make it easier.

3/4=6/10x

Divide both sides by 6/10, or multiply both sides by 10/6.

3/4×10/6=30/24=10/8=1.25

10/8=x

Local maximum: (-6, 8)

Local maximum: (6, 3)

Local minimum: (0, -2)

Local minimum: (9, 2)

Increasing from: n ∈ (-∞, -6) ∪ (0, 6) ∪ (9, ∞)

Decreasing from: n ∈ (-6, 0) ∪ (6, 9)

The maximum and minimum of a function, sometimes referred to as the extremum in mathematical analysis, are its biggest and lowest values, respectively, either on the whole domain or within a specified range. A maximum within a constrained domain, particularly a point on a function whose value exceeds the values of every other point in its vicinity. A point on a graph (or its related function) with a value that is lower than all other points close to it.

A real-world problem scenario can be solved by using the local maximum and minimum to get the best equational solution. It is possible to calculate the input values for which these expressions have a maximum or minimum output by using the local maximum and minimum.

Local maximum: (-6, 8)

Local maximum: (6, 3)

Local minimum: (0, -2)

Local minimum: (9, 2)

Increasing from: n ∈ (-∞, -6) ∪ (0, 6) ∪ (9, ∞)

Decreasing from: n ∈ (-6, 0) ∪ (6, 9)

To know more about local maximum refer to:

https://brainly.com/question/29273762

#SPJ1

The expression 48s represents the number of scarves (s) and its per unit  (48).

An expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Given that, Emiko makes shibori scarves and sells them for $48 each on a website for handmade goods.

Here, the expression 48s represents the total price of buying s scarves

We need to tell what 48s mean,

So,

48s here is the total cost for buying s scarves,

That mean, if we buy s scarves we will have to pay $48s

Similarly, if we will buy 4 scarves, we will pay = 48 × 4 = $192

For 10 scarves, we will pay = 48 × 10 = $480

Therefore, we can say $48 is the unit price of the scarf.

Hence, the expression 48s represents the number of scarves (s) and its per unit  (48).

Learn more about expressions, click;

https://brainly.com/question/14083225

#SPJ1

The question was incomplete, so I answered for the question :-

Emiko makes shibori scarves and sells them for 48 each on a website for handmade goods the expression 48s represents the total price of buying scarves what do the parts of the expression 48s represents.

Answer:

Step-by-step explanation:

number of scarves

Price of scarves

Answer:

Shift 3 units to the right.

Reflect over the x-axis

Answer: 2x^2+4x+2

Step-by-step explanation:

Step-by-step explanation:

the probability of A working is 60% or 0.6, so the probability it does not work is 40% or 0.4.

the probability of B working is 90% or 0.9, so the probability it does not work is 10% or 0.1.

plan 1

it is the probabilty that either A works, or (if it is not working) B works.

0.6 + 0.4×0.9 = 0.6 + 0.36 = 0.96

plan 2

either B works, or (if it is not working) A works

0.9 + 0.1×0.6 = 0.9 + 0.06 = 0.96

both plans have the same success probability.

A common denominator is a shared multiple of the denominators of the fractions involved when adding or subtracting fractions. It enables fraction comparison and addition/subtraction.

Simplification is the process of reducing a fraction to its simplest form by dividing the numerator and denominator by their greatest common divisor. This is done to represent fractions in the simplest terms viable.

Conversion: The process of transferring a fraction from one form to another while retaining its equal value is known as conversion. Finding a common denominator or expressing a fraction in terms of a specified unit or fraction may be required.

Fraction Addition/Subtraction: When adding or subtracting fractions, a common denominator is required. This entails determining a common multiple of

To rewrite the expression 3 + 1/5 + 2/3 using fifteenths as the common denominator, we need to find a common denominator for 5 and 3, which is 15 (since 5 and 3 are both factors of 15).

First, let's convert the fractions 1/5 and 2/3 to fifteenths:

\((\frac{1}{5})(\frac{3}{3}) = \frac{3}{15}\)

\((\frac{2}{3})(\frac{5}{5}) = \frac{10}{15}\)

Now we can rewrite the expression using the common denominator:

\(3 + \frac{3}{15}+\frac{10}{15}\)

Answer:

1. The x-intercepts can be determined by taking the opposite of the constants, in this case the x-ints are -6 and +8.

2. (x+6)(x-8)  =  x^2+-2x-48, the y-intercept is -48

Answer:

P ($)=70-5(t)

Where p = price at t days

t = number of days

Step-by-step explanation:

The product price initially = $70

Now, every day , it reduces $5

The rate=$5 per day reduction

The price in the days will be determined by the formula below

P ($)=70-5(t)

Where p = price at t days

t = number of days

So let's assume it's on the second day

The price after the second day

P($) = 70-5(2)

P($) = 70-10

P($)= $60

The price after two days will be reduced to $60

Answer:

undefined

Step-by-step explanation:

division by zero is undefined

Division Property of zero

For any nonzero real number a

The quotient of "a" and 0 is undefined. That is a/0 is undefined

Answer:

The other two angles are 22° , 22°

Step-by-step explanation:

To find the other angles, we can use angle sum property of triangle.

      The given angle 136° cannot be base angles. Let the base angles be x.

x + x + 136 = 180°

   2x + 136 = 180°

Subtract 136 from both sides,

            2x = 180 - 136

            2x = 44°

Divide both sides by 2,

              x = 44 ÷ 2

                \(\sf \boxed{x = 22^\circ}\)

Answer:42

Step-by-step explanation:

Step-by-step explanation:

\(Determine the contents of the accumulator after the completion of each of the following instruction group

MVI A, 4CH

ANI 85H

\)

Answer:

This is not a linear function.

Step-by-step explanation:

It is a quadratic function.  If you were to make a table of the x and y values of the function it would look like this:

x    y

0   -4

1   -1

2    8

Just by looking at these three values, we can see that they do not increase at a consistent rate.  It increases by 3 from 0 to 1, but increase by 9 from 1 to 2.  You can tell if a function is linear by seeing if it increases at a constant rate.  (In this case it does not)

Answer:

SSA the only other right one missing is ASA

The least common denominator needed to solve the equation is given as follows:

D. x(x - 3).

The equation in this problem is given as follows:

1/x + 2/(x - 3) = 5.

The denominators of each expression are given as follows:

x and x - 3 are not factors of each other, hence we multiply them and the least common denominator needed to solve the equation is given as follows:

D. x(x - 3).

More can be learned about least common denominator at https://brainly.com/question/19249494

#SPJ1

Answer: LCM =96

GCF=4

Step-by-step explanation:

Answer:

17.8

Step-by-step explanation:

You have to add 9.2 and 63 and the subtract from 90. Hope this helped! <3

An order-preserving function is a function that preserves the order of its inputs. In other words, if x is less than y, then f(x) will be less than f(y).

The statement "f is order-preserving if x < y implies f(x) < f(y)" means that if x is less than y, then f(x) must be less than f(y). This is a necessary condition for a function to be order-preserving. However, it is not a sufficient condition. For example, the function f(x) = x^2 is not order-preserving, because 2 < 3, but f(2) = 4 > f(3) = 9.

In summary, order-preserving functions are useful in situations where we need to preserve the order of a set of data.

Learn more on functions:https://brainly.com/question/11624077

#SPJ1

Answer:

easygtrderdcgfc

Step-by-step explanation:

drtd

efwhiuhfrie

efijewioafjiewur89308932

1321321

Answer:

What exactly does “ASAP” mean? Ok yes, it means as soon as possible, but in terms of actual time, it means nothing. Th

It depends on the number of variables, if the inequality has one variable, then it is graphed on a number line.

The type of diagram that we need to use depends on the number of variables that we have.

That is the main reason, for example:

x > 2

Is graphed on a number line.

y > 3x + 4

is graphed on a coordinate plane.

learn more about inequalities at:

https://brainly.com/question/24372553

#SPJ1

Answer:

10 lol..................

Answer:

It should be 7.4

Step-by-step explanation:

Answer:

the answer would be 10

Step-by-step explanation: