A vertical demand curve is a type of demand curve that is perfectly inelastic, meaning that the quantity demanded does not change no matter how the price changes. This type of demand curve is also known as a "perfectly inelastic demand curve."
How do demand curves develop?A variety of variables, such as shifts in population, income, pricing of complementary or replacement commodities, and expectations about future circumstances and prices, can vary the demand curve for goods and services, resulting in a different quantity being demanded at any given price.
Why is the demand curve significant?When firms decide how much to charge, the demand curve can be a useful tool. This is so that the demand curve may display the price point at which consumer response declines and the price point that generates the most demand.
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If a truck takes 8 gas tanks to fill up 49%. How much will it take to fill up the truck
Answer:
About 3.9 tanks
Step-by-step explanation:
About 49% of 8 gas tanks is 3.9 tanks.
Can someone help me answer a question anybody I need help ASP
Step-by-step explanation:
yes i ccsan help but i dont know what your question is
the answer is 2.66 (continuous sixes)
is this what the question is?
Gary was looking for a new cell phone plan. Company A is offering $50 for the phone and $.20 per minute for data usage. How much would Company A’s phone plan cost if Gary spends on average 200 minutes for data?
Answer:
$90
Step-by-step explanation:
c = 50 + .2m
c = 50 + .2(200)
c = 50 + 40
c = 90
(L1) Given: CM↔ is a perpendicular bisector of AB¯ at point MProve: AC=BC
CM is the perpendicular bisector of AB at M, it means that CM is perpendicular to AB, and AM=BM. Therefore, we have two right triangles, triangle AMC and triangle BMC, with a shared side CM, and AM=BM.
By the Pythagorean theorem, we know that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Applying this to triangles AMC and BMC, we have:
AC² = AM² + CM²
BC² = BM² + CM²
Since AM=BM, we can substitute AM for BM in the second equation, giving:
BC² = AM² + CM²
Since the left-hand sides of these two equations are equal (by the given that CM is the perpendicular bisector of AB), we can set their right-hand sides equal to each other and simplify:
AC² = BC²
Taking the square root of both sides gives us:
AC = BC
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What is 15/27.5 to the nearest hundredth?
The quotient of 15 and 27.5, rounded to the nearest hundredth, is given as follows:
15/27.5 = 0.55.
How to obtain the quotient of 15 and 27.5?The quotient of two amounts is given by the division of the first amount by the second amount.
The amounts in this problem are given as follows:
15 and 27.5.
Hence the division has the result given as follows:
15/27.5 = 0.545454.
To round to the nearest hundredth, we must look at the third digit. It is 5, hence one must be added to the second digit, and the rounded result is given as follows:
15/27.5 = 0.55.
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At 5 a. M. , the temperature at an airport was −9. 4°F. Six hours later, the temperature was 2. 8°F. Which expression represents the total temperature change over the six hours?
∣∣−9. 4+2. 8∣∣
−9. 4+2. 8
∣∣2. 8−(−9. 4)∣∣
∣∣2. 8+(−9. 4)∣∣
Answer:
Step-by-step explanation:
∣∣2. 8−(−9. 4)∣∣
∣∣2. 8+(−9. 4)∣∣
Where is the removable discontinuity of f(x) located? x = –5 x = 0 x = –2 x = 5
On solving the provided question we can say that - the removable discontinuity of f(x) located is -5
What is discontinuity ?Discontinuous functions in graphs are those that have no connections to one another. Discontinuities come in three different flavors: removable, jump, and infinite.. If the left limit and the right limit of a function, f(x), are both different, then the function has a first-kind discontinuity at x = a. a characteristic that cannot be mathematically continuous. Continuous functions allow you to sketch without having to lift your pen. In such a case, the function is said to as discontinuous.
here,
f(x) = \(\frac{x+5}{x^2+3x-10}\)
\(x^2+3x-10\)
x(x+5) - 2(x+5)
(x+5 )(x-2 )
x = 2, -5
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Hello people please help
Answer:
B
Step-by-step explanation:
angle 1: 50°
angle 2: 65°
All 3 sides of a triangle must add up to 180°
We can create an equation given this information to solve for the third angle, let's call it x
50 + 65 + x = 180
115 + x = 180
-115 -115
x = 65° or B
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Find the reference angle for a rotation of 253º.
Given the angle:
253 degrees
Let's find the reference angle to the given angle for a rotation.
The given angle, 253 degrees, is in quadrant 3.
To find the reference angle of ang angle in quadrant 3, we have:
\(\theta_{ref}=\theta-180\)Hence, we have:
\(\begin{gathered} \theta_{ref}=253-180 \\ \\ \theta_{ref}=73^o \end{gathered}\)Therefore, the reference angle is 73 degrees.
ANSWER:
73°
Raymond earns 1795 each month and pays 53.40 on electricity to nearest 10th of a percent what percent of Raymonds earnings are spent on electricity each month
Radioactive radium has a half-life of approximately 1,599 years. the initial quantity is 13 grams. how much (in grams) remains after 850 years? (round your answer to two decimal places.)
The quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.
The time taken by substance to reduce to its half of its initial concentration is called half life period.
We will use the half- life equation N(t)
N e^{(-0.693t) /t½}
Where,
N is the initial sample
t½ is the half life time period of the substance
t2 is the time in years.
N(t) is the reminder quantity after t years .
Given
N = 13g
t = 350 years
t½ = 1599 years
By substituting all the value, we get
N(t) = 13e^(0.693 × 50) / (1599)
= 13e^(- 0.368386)
= 13 × 0.691
= 8.98
Thus, we calculated that the quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.
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Forty boxes of baseballs weigh a total of 1,200 pounds. How many pounds would 4 boxes of baseballs weigh?How many pounds would 400 boxes of baseball weigh?
Answer: 4 boxes of baseballs weigh 120 pounds and 400 boxes weigh 12,000 pounds.
Step-by-step explanation:
We know that 40 boxes of baseballs weigh a total of 1,200 pounds.
So we can just that the unit rate of this by doing 1,200/40 = 30
After that we get that 1 box of baseballs weigh 30 pounds.
Next to find out how much 4 boxes of baseballs weigh we do 30 * 4 = 120 pound.
Lastly to find out how much 400 boxes of baseballs weigh we do 30 * 400 = 12,000 pounds
find the work done by the force field f(x, y) = xi (y 1)j in moving an object along an arch of the cycloid r(t) = (t − sin(t))i (1 − cos(t))j, 0 ≤ t ≤ 2.
The work done by the force field f(x, y) = xi (y 1)j in moving an object along an arch of the cycloid
r(t) = (t − sin(t))i (1 − cos(t))j, 0 ≤ t ≤ 2 is -4
To find the work done by the force field in moving an object along the arch of the cycloid r(t), we need to compute the line integral of the dot product of the force field with the unit tangent vector of the arch. The cycloid is given by:r(t) = (t - sin(t))i + (1 - cos(t))j, 0 ≤ t ≤ 2.To find the unit tangent vector T(t), we differentiate the cycloid:
r'(t) = (1 - cos(t))i + sin(t)j.
T(t) = r'(t)/|r'(t)|
= (1 - cos(t))/√(2 - 2cos(t)) i + sin(t)/√(2 - 2cos(t)) j. The work done by the force field in moving the object along the arch is given by the line integral:W = ∫C f(r) · T(t) ds,where C is the arch of the cycloid, r is the position vector, T is the unit tangent vector, and ds is the arc length element. We have: f(x, y) = xi(y - 1)j, so f(r(t))
= (t - sin(t))i(1 - cos(t) - 1)j
= (t - sin(t))i(-cos(t))j
= -t cos(t) i + (t sin(t) - t) j.Writing this in terms of the unit tangent vector, we have:f(r) ·
T = (-t cos(t) i + (t sin(t) - t) j) · ((1 - cos(t))/√(2 - 2cos(t)) i + sin(t)/√(2 - 2cos(t)) j)
= -t cos(t) (1 - cos(t))/(2 - 2cos(t)) + (t sin(t) - t) sin(t)/(2 - 2cos(t))
= -t (cos(t) - cos²(t) + sin²(t))/(2 - 2cos(t))
= -t (cos(t) - 1)/(1 - cos(t))
= t (1 - cos(t))/(cos(t) - 1). Therefore, the work done by the force field in moving the object along the arch is:
W = ∫C f(r) · T(t) ds
= ∫0² t(1 - cos(t))/(cos(t) - 1) |r'(t)| dt
= ∫0² t(1 - cos(t))/√(2 - 2cos(t)) dt
= -∫0² t d(cos(t))
= t(cos(t) - 1) |0²
= -4. The work done by the force field in moving the object along the arch of the cycloid is -4.
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a new car is purchased for 18500 dollars. the value of the car depreciates at 8% per year. to the nearest tenth of a year, how long will it be until the value of the car is 9100 dollars?
Answer:
8.5 years
Step-by-step explanation:
You want to know the number of years until 18500 depreciates to 9100 at the rate of 8% per year.
ValueThe depreciation rate given as a percentage of current value tells you the depreciation is exponential. The formula will be ...
value = (initial value) × (1 - (depreciation rate))^t
where the rate is "per year" and t is in years.
Applicationvalue = 18500·(1 -0.08)^t
9100 = 18500·0.92^t . . . . fill in the value of interest
9100/18500 = 0.92^t . . . . divide by 18500
log(91/185) = t·log(0.92) . . . . take logarithms
t = log(91/185)/log(0.92) ≈ -0.3081/-0.03621 ≈ 8.509
It will be about 8.5 years until the value is $9100.
__
Additional comment
The graph shows the solution to ...
18500·0.92^t -9100 = 0
We find it fairly easy to locate an x-intercept, so we wrote the equation in the forms that makes the x-intercept the solution.
debbie owes her brother $25 if she plans to pay him back an equal amount from her savings each day for five day describe the change in her savings each day
Answer:
For 5 days, Debbie will lose 5 dollars from her savings.
Step-by-step explanation:
a stadium can seat 63,026 people. for each game, the amount of money that the organization brings in through ticket sales is a function of the number of people, `n`, in attendance. if each ticket costs $30.00, find the domain and range of this function:
Answer: 63056$
Step-by-step explanation: i learned that in school 2 hours ago
d=√C8-7)° +65--0 OSI='ZN=p
Answer:
3r57i99097654322 that is the answer
You and a friend are walking to school. You start 0.6 miles ahead of your friend, and
walk at a pace of 2.5 miles per hour. Your friend walks at a pace of 4 miles per hour.
Write equations to represent this scenario where x represents hours, and y represents
distance walked.
Your eq'n:
Friend eq'n:
How many minutes
does it take for your
friend to catch up?
How far will your friend have
walked once they catch up?
Include units in your answer.
Answer: 1. It would take your friend 24 minutes to catch up. Your friend would've walked 1.6 miles once they've caught up.
Step-by-step explanation: If you walk 2.5 miles per hour, you would have to divide that by 60 minutes to find out how fast you walk per minute. Which would be 0.04166666667 miles per minute, if you walked for 24 minutes, you would've completed a full mile. Your friend walks 4 miles per hour, you would want to divide that by 60 as well to find out how fast he walks per minute. Which would be 0.06666666667 miles per minute, if he walked for a total of 24 minutes, he would've walked for a total of 1.6 miles. Remember, you started 0.6 miles ahead of him, meaning after a total of 24 minutes, your friend would've caught up to you.
Given h(x) = -x + 2, solve for x when h(x) = -3.
;-;
The value of x when h(x) =-3 is 5.
What is Algebra?A branch of mathematics known as algebra deals with symbols and the mathematical operations performed on them.
Variables are the name given to these symbols because they lack set values.
In order to determine the values, these symbols are also subjected to various addition, subtraction, multiplication, and division arithmetic operations.
Given:
h(x) = -x + 2
Now, we have to find the value of x when h(x)= -3
So, h(x)= -3
-x+ 2= -3
Now, Subtracting 2 from both side
-x+ 2 -2= -3 -2
-x = -5
x= 5
Hence, the value of x is 5.
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In triangle ABC, the measure of angle B is 50 degrees. Select all possible values for the measures of A and C if ABC is an acute triangle. m\angle∠A= 58 degrees; m\angle∠C= 72 degrees m\angle∠A= 100 degrees; m\angle∠C= 30 degrees m\angle∠A= 80 degrees; m\angle∠C= 50 degrees m\angle∠A= 60 degrees; m\angle∠C= 70 degrees m\angle∠A= 90 degrees; m\angle∠C= 40 degrees m\angle∠A= 105 degrees; m\angle∠C= 25 degrees
Answer:
Step-by-step explanation:
Sum of angle in a triangle = 180°
<A+<B+<C = 180
Given <B = 50°
Substituting into the formula
<A+50+<C = 180
<A+<C = 180-50
<A+<C = 130°
Since the ∆ABC is an acute triangle, the angles <A and <C must be angles less than 90° since acute angles are angles less than 90°
The possible values of <A and <C that will be acute and give a sum of 130° are;
∠A= 58° and ∠C= 72°
∠A= 80° and ∠C= 50°
∠A= 60° and ∠C= 70°
You can see that all the Angles are less than 90° and their sum is 130°
I need help please!!
Answer:
14 hrs of babysitting and 6 hrs of tutoring
Find the range of possible values for y.
The range of possible values for y is given as follows:
4.5 < y < 23.5.
What is the law of sines?The law of sines states that the sine of each angle is proportional to the side length opposite the angle.
For this problem, we have that:
A length of 19 is opposite to an angle of 38º.A length of 18 is opposite to an angle of 2y - 9.Due to the smaller side length, the angle measure 2y - 9 has to be less than 38, hence:
2y - 9 < 38
2y < 47
y < 47/2
y < 23.5.
An angle measure has to be greater than 0, thus:
2y - 9 > 0
2y > 9
y > 9/2
y > 4.5.
Hence the range is:
4.5 < y < 23.5.
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Find the percent decrease. Round to the nearest percent. From $8 to $6
Answer:
To find the percent decrease from $8 to $6, we can use the following formula:
Percent Decrease = ((Original Value - New Value) / Original Value) * 100
Plugging in the values:
Percent Decrease = (($8 - $6) / $8) * 100
Percent Decrease = ($2 / $8) * 100
Percent Decrease = 0.25 * 100
Percent Decrease = 25
Therefore, the percent decrease from $8 to $6 is 25%.
Step-by-step explanation:
Answer:
25
Step-by-step explanation:
The decrease in money from 8 to 6 is a total of 8-6=2 dollars. Now, to find the percent decrease, we take 2/8 and write it as a percentage. This is 25%. Therefore, the answer you are looking for is 25.
Feel free to tell me if I did anything wrong! :)
7 x 1/6
Please help if you can
Answer:
7/6
Step-by-step explanation:
U just need to multiply 7 x 1/6 = 7/6 = 1.16
A square has a side length of 2.3cm if the square is dilated by a scale factor of 3 what is the length of the new side
Answer:
\(New\ Side = 6.9cm\)
Step-by-step explanation:
Given
\(Length = 2.3cm\)
\(Scale\ Factor = 3\)
Required
Determine the length of the new side
This is calculated as follows:
\(New\ Side = Length * Scale\ Factor\)
Substitute values for Length and Scale Factor
\(New\ Side = 2.3cm * 3\)
\(New\ Side = 6.9cm\)
Hence, the length of the new side is 6.9cm
can u help me solve this question using radical form
9514 1404 393
Answer:
x = 4√15y = 4√5Step-by-step explanation:
The ratios of side lengths in the given triangle are ...
1 : √3 : 2 = shortest : middle length : longest
We can make the longest side match the given value if we multiply these numbers by 4√5
y : x : 8√5 = 1(4√5) : √3(4√5) : 2(4√5) = 4√5 : 4√15 : 8√5
Then we have ...
x = 4√15
y = 4√5
Please answer this question its easy.
Answer:
ok if its wrong then dont ask on period
Step-by-step explanation:
(Do not use a calculator for this question) Given f(x)-73-12x + 5 answer the following: Is the function increasing or decreasing at x-3? List the interval A=B=where f(x) is decreasing. a F At what X-value does f(x) have a relative maximum?
The function is a set of ordered pairs (x, y), where x is an element of the domain and y is the corresponding element of the range. The notation f(x) is commonly used to denote the output value of the function for a given input value x.
The function is decreasing at x=3. The interval where f(x) is decreasing is (3,∞). The x-value at which f(x) has a relative maximum is x= -4.The derivative of the function f(x) is f'(x)=-12.At x=3, the derivative is negative, f'(3)=-12, so the function is decreasing at x=3.
The function is always decreasing since its derivative is constant and negative. Therefore, the interval where f(x) is decreasing is the entire real line, or (-∞, ∞).
Since the function is always decreasing, it does not have a relative maximum.
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A statistical technique that would allow a researcher to cluster such traits as being talkative, social, and adventurous with extroversion is called:_______
A statistical technique that would allow a researcher to cluster such traits as being talkative, social, and adventurous with extroversion is called factor analysis.
Describe Statistical technique?Statistical techniques are methods and procedures used in the collection, analysis, interpretation, and presentation of data. These techniques involve the use of mathematical and statistical models to draw meaningful insights and conclusions from data.
Some common statistical techniques include:
Descriptive statistics: These techniques are used to summarize and describe the key features of a dataset, such as central tendency, variability, and distribution.
Inferential statistics: These techniques are used to make inferences about a larger population based on a sample of data. This involves using probability theory to estimate population parameters and test hypotheses.
Regression analysis: This technique is used to model the relationship between one or more independent variables and a dependent variable.
Hypothesis testing: This technique is used to test the validity of a hypothesis or claim about a population using sample data.
Time series analysis: This technique is used to analyze data that varies over time, such as stock prices or weather patterns.
Cluster analysis: This technique is used to group similar observations together based on their characteristics.
Data mining: This technique involves the use of automated methods to discover patterns and relationships in large datasets.
Statistical techniques are widely used in many fields, including business, economics, social sciences, medicine, and engineering. They are used to make informed decisions, identify trends and patterns, and to understand complex systems.
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what is balance chemical equations calculator
A balanced chemical equation calculator is an online tool that assists in the balancing of chemical equations by automatically computing the coefficients for each reactant and product to verify that the equation obeys the rule of mass conservation.
According to the law of conservation of mass, matter cannot be generated or destroyed in a chemical process, just rearranged.
A balanced chemical equation includes the chemical formulae for the reactants and products of a chemical reaction, as well as the factors that balance the amount of atoms of each element on both sides of the equation. Balancing a chemical equation is a necessary step in addressing many sorts of chemistry issues, such as forecasting the quantity of product generated or reactant required in a reaction.
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