What is it called when particles in a solid or liquid move slower and closer together?

Answer:

the angle of incident is 40°

Explanation:

NQ is the normal to the mirror, therefore

angle NQA =90°

PQA = 50°

incident angle = NQA - PQA

90°- 50° = 40°

note that the angle of reflection is equal to the angle of incident

Hi there!

1)

Since the charge placed in the middle is positive, we know that the particle is being repelled.

The particle experiences a greater repelling force by the 9μC charge. We can use the equation for electric force:
\(F_E = \frac{kq_1q_2}{r^2}\)

k = Coulomb's Constant

q₁, q₂: Charges (C)
r = distance between charges (m)

This is a VECTOR quantity, so we must subtract the forces since they point in opposite directions.

Force from 9μC particle:
\(F_E = \frac{k(.000005)(.000009)}{2^2} = .101\\\\\)

Force from 4μC particle:
\(F_E = \frac{k(0.000005)(0.000004)}{2^2} = 0.0450\)

Subtract:
\(.101 - 0.0450 = \boxed{0.561 N}\)

2)

We can find a position by setting the two equations equal to one another. (Both repelling forces must be EQUAL for the force = 0 N)

Let the distance between the 9μC and 5μC charge equal 'x', and the distance between the 4μC and 5μC charge equal '4 - x'.

\(\frac{k(0.000009)(0.000005)}{x^2} = \frac{k(0.000004)(0.000005)}{(4 - x)^2}\)

Cancel out 'k' and the 5μC value.

\(\frac{0.000009}{x^2} = \frac{0.000004}{(4 - x)^2}\)

Solve for 'x' using a graphing utility.

\(\boxed{x = 2.4 m}\)

Answer:

a moderate base

Explanation:

Milk of magnesia is popularly known as magnesium hydroxide. Magnesium hydroxide Mg(OH)₂ is used as an anti-acid in toothpaste and medically as a mild laxative.

Its pH values range between 10- 11 on the pH scale.

A solution with pH value of 7 is neutral(i.e. neither acidic nor basic.

A pH value which is less than 7 is acidic while a pH value greater than 7 is basic.

For a pH value between 12 -14 on the pH scale is said to be a strong base.

Since Milk of magnesia Mg(OH)₂ pH values ranges between 10- 11 on the pH scale, it is known to be moderately basic.

To determine the velocity of the system after the catch, we need to consider the concept of momentum conservation. The momentum of an object is the product of its mass and velocity.

Given that the mass of the NFL football is 430 g, we need to convert it to kilograms:

Mass = 430 g = 0.43 kg

Let's assume the football is caught by a receiver who is also moving to the right. Since both the football and the receiver are moving in the same direction, their velocities will have the same sign.

The momentum before the catch is zero since the football is in motion and the receiver is stationary. After the catch, the momentum of the system should still be zero to conserve momentum.

Using the equation for momentum:

Momentum = Mass × Velocity

Since the momentum before the catch is zero, the momentum after the catch should also be zero. Therefore, the product of the mass and velocity of the football and the receiver should sum up to zero.

0 = (Mass of football × Velocity of football) + (Mass of receiver × Velocity of receiver)

Given the mass of the football and assuming the mass of the receiver is unknown, we cannot determine the exact velocity of the system after the catch without additional information.

Therefore, without the mass or velocity of the receiver provided, we cannot calculate the velocity of the system after the catch.

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Answer:

Circuit Breaker - a protective device used to automatically blows and cuts the current when trouble in the circuit such as short circuit or overload occurs

Answer:

1. 4

2.0.625HZ

3.500

4. 428274940000000 or 4.2*10^14

5. 2

Explanation:

omnicalculator.com/physics/wavelength

Answer:

D

Explanation:

im guessing here i hope it is correct and good luck

The dog will not catch the car, as the car is traveling at a faster speed than the dog. The dog may continue to chase after the car, but it will not be able to catch it.

To determine if the dog catches the car, we need to compare their relative speeds. The car is traveling at a constant speed of 5 m/s, while the dog's speed is unknown. We can calculate the dog's speed using the distance it covers in 5 seconds, which is 20 meters.

To calculate the dog's speed, we divide the distance traveled by the time taken:

Speed = Distance / Time

Speed = 20 meters / 5 seconds

Speed = 4 m/s

Now we know that the dog's speed is 4 m/s, which is less than the car's speed of 5 m/s. Therefore, the dog will not be able to catch the car. The dog will keep running after the car but will never catch up to it because the car is traveling faster.

It's worth noting that even if the dog's speed was equal to the car's speed, the dog would still not be able to catch the car. This is because the car is moving away from the dog and the distance between them is constantly increasing.

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Answer:

a is the answer to this problem your welcome

Answer:

Explanation:

The time taken can be found by using the formula

\( t = \frac{d}{v} \\ \)

d is the distance

v is the velocity

From the question we have

\(t = \frac{3.5}{4.8} \\ = 0.72916...\)

We have the final answer as

Hope this helps you

The presence of potential energy  between particles supports the shape of a heating curve.

The existence of potential energy  between particles supports the shape of a heating curve because potential energy causes the heating curve flat as well as in curve form. The heating curves show how the temperature changes as a substance is heated up.

The potential energy of the molecules will increase anytime energy is being supplied to the system but the temperature is not increasing so when the heating curve go flat it means there is potential energy so we can conclude that the existence of potential energy  between particles supports the shape of a heating curve.

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Answer:

The shopping cart has less kinetic energy when it is empty.

Explanation:

When an object of mass \(m\) travels at a speed of \(v\), the kinetic energy of that object would be \((1/2)\, m\, v^{2}\).

In this question, the speed of the shopping cart is fixed (\(v = 2\; {\rm m\cdot s^{-1}}\).) Kinetic energy would be proportional to the mass \(m\) of the shopping cart (including that of its contents.)

The mass of the shopping cart is lower when it is empty on the way back to the store. Therefore, the kinetic energy of the shopping cart would also be lower than when it was full.

Answer:

(Question) A city gets its electricity from a dam, where water is stored in a reservoir. How does the water provide the city with its power?

(Answer) Potential energy in the water becomes kinetic energy as it moves through turbines, which turn kinetic energy into mechanical energy that spins a generator, which changes mechanical energy into electricity.

(Question) An acorn rolls off a roof and falls to the ground. Which statement best describes the change in energy?

(Answer) The acorn’s potential energy decreases as its kinetic energy increases.

(Question) An airplane carries 320 passengers from Phoenix to Los Angeles flying at an average speed of 490 miles per hour. On the return flight, the plane carries 164 passengers and travels at the same average speed. What happens to the plane’s kinetic energy?

(Answer) On the return flight, the plane has less kinetic energy.

(Question) A racehorse is running at 42 miles per hour, equivalent to 18.8 meters per second. The horse and its jockey have a combined mass of 512 kilograms. How much kinetic energy do they have?

(Answer) 90,480.6 J

(Question) Which object has kinetic energy?

(Answer) balloon rising in the sky

(Question) Mr. Starr pushed a cart full of groceries to his car. After emptying the cart, he pushed it back to the store. He pushed the cart at a speed of 2 meters per second each way. Which is the best prediction?

(Answer) When it was empty, the cart had less kinetic energy.

(Question) A student fires a toy rocket into the sky. When does the rocket have the most potential energy?

(Answer) when the rocket reaches its highest point

(Question) What is the best description of one billiard ball hitting a second billiard ball?

(Answer) Most of the kinetic energy in the first ball is transferred to the second ball.

(Question) A roller-coaster car is at the top of a hill. The car and its passengers have a combined mass of 1,088 kilograms. If the hill is 62 meters tall, how much potential energy does the car have?

(Answer) 661,068.8 J

(Question) A roller-coaster is at the top of a 62-meter hill. The car and its passengers have a total mass of 1,088 kilograms. By the time the car reaches the bottom of the hill, its speed is 74 miles per hour (33 meters per second). How much kinetic energy does the car have at the bottom of the hill?

(Answer) 592,416 J

(Question) A diagram is drawn showing a swing set with a swing pulled backward prior to release. The diagram shows how the swing will move forward and then backward after it is initially released. At which point in the diagram is all of the energy gravitational potential energy?

(Answer) when the swing is pulled back prior to release

(Question) essay

(Answer) good luck

(Question) essay

(Answer) good luck

Explanation:

I just completed this assignment UwU

No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.

This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.

i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.

ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.

The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.

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The torque of a lever is equal to the perpendicular force multiplied by the length of the lever arm, which is the distance from the fulcrum of the lever. The total of the individual torques is the net torque.

To calculate the net torque of the origin on the flea, we need to find the torque produced by each force and add them up.

Let's assume that the forces acting on the flea are F1, F2, and F3, and their respective positions are r1, r2, and r3.
The torque produced by each force is given by the cross-product of the force vector and the position vector:
τ = r x F

In unit-vector notation, we can write this as:
τ = (r × F) k
where k is the unit vector in the z-direction (perpendicular to the x-y plane).

So the torque produced by each force can be written as:
τ1 = (r1 × F1) k
τ2 = (r2 × F2) k
τ3 = (r3 × F3) k

To find the net torque, we simply add up these individual torques:
τnet = τ1 + τ2 + τ3

In this case, the position of the flea is given by (0, -1.47 m, 1.89 m), so we can write:
r1 = (0, -1.47, 1.89) m

Similarly, we need to know the force vectors F1, F2, and F3 to calculate their torques. Without this information, we cannot calculate the net torque.

Once we have all the necessary information, we can put in the values and use the cross product to find the individual torques, and then add them up to get the net torque.

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The driving force pulling on this rock is equivalent to a mass of 0.5 Kg.

The driving force pulling on the rock is the component of the rock's weight that is parallel to the slope. This is given by:

Pull Force = mgsinθ

where,

m is the mass of the rock

g is the acceleration due to gravity

θ is the angle of the slope

In the given scenario,

m = 1 kg

g = 9.8 m/s^2

θ = 30°

Hence, the driving force is given by

Driving Force = 1 kg × \(9.8 m/s^2\) × sin  \(30\)°

Driving Force = 0.5 Kg

Therefore, the driving force pulling on this rock is 0.5 Kg.

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To solve this problem, we need to use the formula for calculating the force acting on an object on a slope. The formula is: force = mass x acceleration, where acceleration is the force due to gravity acting on the object down the slope.

We know that the mass of the rock is 1 kg and the angle of the slope is 30 degrees. We can calculate the force due to gravity using the formula: force = mass x gravity x sin(angle). Plugging in the values, we get force = 1 kg x 9.8 m/s^2 x sin(30) = 4.9 N. Now we can subtract the resisting force of 0.87 kg from this value to get the driving force: 4.9 N - 0.87 kg = 4.03 N. Therefore, the answer is e. 0.5 kg, which is the closest to 4.03 N.

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Answer:b

Explanation:

Answer:

B

Explanation:

edg

The load value for interrupts every one milliseconds is

\(\begin{aligned}&\mathrm{val}=1 \times 10^{-3} \times 4.094 \times 10^6 \\&\Rightarrow \mathrm{val}=4094\end{aligned}\)

The load value for interrupts every millisecond is

\(\begin{aligned}&\mathrm{val}=1 \times 10^{-6} \times 4.094 \times 10^6 \\&\Rightarrow \mathrm{val}=4.094\end{aligned}\)

However, we can only load integer values, therefore we apply

\(\Rightarrow v a l \approx 4\)

When the delay is 1 ms, it is accurate, but when the delay is 1 us, it is a little bit less. We are unable to provide an accurate 1 us delay interrupt because this requires a fractional value was calculated.

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The frequency of the displacement with the sinusoidal driving force of the mass-spring-damper system will be equal to the frequency of the driving force, which is 2.2π rad/s.

The equation of motion for a mass-spring-damper system with a sinusoidal driving force is given by:

m d²x/dt² + c dx/dt + kx = F_c sin(ωt)

where m is the mass of the system, c is the damping coefficient, k is the spring constant, F_c is the amplitude of the forcing function, ω is the angular frequency of the forcing function, and x is the displacement of the mass from its equilibrium position.

At steady-state, the displacement x of the mass will also be sinusoidal with the same frequency as the driving force, but with a phase shift that depends on the damping ratio of the system. To find the frequency of x and the phase shift, we can use the complex notation of sinusoidal functions.

Let X be the complex amplitude of x and F be the complex amplitude of the forcing function. Then we can write:

X = A \($e^{j\phi}$\)

F = F_c \($e^{j\omega t}$\)

where A is the amplitude of x, ϕ is the phase angle of x, and j is the imaginary unit.

Substituting these expressions in the equation of motion and solving for X, we get:

X = F / (-k + jωc - mω²)

Taking the absolute value of X, we get:

|X| = |F| / |(-k + jωc - mω²)|

This expression gives us the amplitude of the steady-state response of the system. The frequency of the response is given by the frequency of the driving force, which is ω = 2.2π rad/s in this case.

The phase angle of the response can be found by taking the argument of X:

ϕ = arg(X) = arg(-k + jωc - mω²)

The argument of the denominator can be written as:

arg(-k + jωc - mω²) = arctan((ωc-k)/mω)

This expression gives us the phase shift between the response and the driving force.

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The question is -

A sinusoidal driving force is applied so that the forcing function is now f(t)=F c ​ sin(ωt), where ω=2.2π s rad ​ . At steady-state, what is the frequency of x (displacement) of the mass-spring-damper, and will this frequency be in phase with the sinusoidal driving force? Explain how you arrived at your answer.

ANSWER

(a) 3 N

(b) No, it does not.

EXPLANATION

Parameters given:

Weight of backpack, W = 52N

Spring constant of speing, k = 150 N/m

Extension of spring, x = 2.00 cm = 0.02 m

(a) We want to find the force of friction exerted on the backpack by the table.

Let us consider the forces acting in the horizontal direction. Since the backpack did not move, it means that there is no acceleration by the backpack, hence, the net horizontal force is 0:

There are two forces acting on the backpack when the spring is pulled namely:

-> Force of the pull of the spring, F

-> Force of static friction, Fs

Taking the right hand to be the positive direction, the friction force acts in the positive direction while the pull acts in the negative direction.

Therefore, we have that:

The force of the pull is given by Hooke's law:

Therefore, we have that:

That is the frictional force exerted on the backpack by the table.

(b) In the calculation above, we see that the friction force is not dependent on the mass of the backpack. This implies that if the mass of the backpack is doubled, the friction force does not change.

Hence, the answer is no.

Radio waves traveling through the ionosphere at high latitudes experience quick and unpredictable oscillations, which is known as high-latitude scintillation.

The auroral border, or area of the ionosphere where the aurora borealis (northern lights) appear, is typically connected with scintillation. However, high-latitude scintillation can occasionally be seen equatorward of the auroral boundary depending on the circumstances. The cause of this phenomenon is the presence of ionospheric irregularities that go beyond the auroral oval, such as irregularities in plasma density brought on by equatorial spread F (ESF). ESF can produce significant ionosphere-wide anomalies that lead to scintillation at lower latitudes. This may occur when the sun is active more intensely or when particular ionospheric circumstances favor the production of these anomalies.

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The graph in which the block will travel with the greatest speed is the graph with the greatest displacement at given equal forces.

Based on the principle of work energy theorem, the work done in moving the block against the frictionless floor is equal to the kinetic energy.  

K.E = ¹/₂kx²

K.E = ¹/₂Fd

¹/₂mv² = ¹/₂Fd

mv² = Fd

v² = Fd/m

v = √ (Fd/m)

Thus, the graph in which the block will travel with the greatest speed is the graph with the greatest displacement at given equal forces.

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(a) The velocity of the object at time t is given by finding the derivative of y (t):

y(t) = -2t2 + t + 10dy(t)/dt

= -4t + 1

Therefore, the velocity of the object at time t is -4t + 1.

(b) The acceleration of the object at time t is given by finding the derivative of the velocity function:

dy(t)/dt = -4t + 1d2y(t)/dt2

= -4

Therefore, the acceleration of the object at time t is -4 m/s2.

(c) The ball hits the ground when y(t) = 0, so we can solve for t by setting -2t2 + t + 10 = 0 and using the quadratic formula:

t = (-b ±  (b2 - 4ac)) / (2a), where a = -2, b = 1, and c = 10.

Plugging these values into the formula, we get:

t = (-1 ±  (12 - 4(-2)(10))) / (2(-2)) = (1 ±  81) / 4

We take the negative root because the positive root corresponds to the ball reaching its maximum height before falling back down. Thus,

t = (1 - 81) / 4

= -2/4

= -0.5 s

To find the velocity of the ball at this time, we plug t = -0.5 into the velocity function we found in part

(a):v = -4t + 1

= -4(-0.5) + 1

= 3 m/s

Therefore, the velocity of the ball at the time it hits the ground is 3 m/s.

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The satement is true.

This comes from the fact that, according to Einstein:

and since c² is a very large number then, if we find a way to convert all the mass in energy a small amount will produce a large amount of energy.

The acceleration of a ball falling from a 100-meter cliff is constant at 1 point 9.8 meters per second square.

Gravity causes an object to fall toward the ground more quickly the longer it is in free fall. In reality, an object's velocity increases by 9.8 m/s2, and by the time it starts to fall, it has already reached 9.8 m/s. A ball falls from the top of a structure and accelerates as it goes down. Every second, its speed increases by 10 m/s. For instance, the motion of a ball falling due to gravity is an example of motion with constant acceleration. An object in free fall experiences constant acceleration if air resistance is minimal. G is equal to 9.80 m/s2, or g.

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When final consumers are willing to spend much time and effort comparing quality and style-with brand and price being less important-the product is a heterogeneous shopping product

Define product differentiation strategy

Finding and promoting a product's distinctive attributes while emphasizing the key distinctions between it and its rivals are the key components of a product differentiation strategy. To make a product or service appealing to a target market or audience, product differentiation must go hand in hand with creating a compelling value proposition.

Price will play a significant role in your decision while trying to select a homogeneous product. Because heterogeneous products might differ greatly, there should be other factors taken into account. The quality and features of heterogeneous products are those that buyers perceive to be noticeably different; as a result, pricing is less significant.

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The lowest resonance frequency of the outer ear tube is 1220 Hz.

The lowest resonance frequency of a cylindrical tube, such as the outer ear, can be calculated using the formula:

f = (c/2π) x (1/L)

where:

f is the frequency (in hertz)

c is the speed of sound in air (approximately 343 m/s at room temperature and normal atmospheric pressure)

L is the length of the tube (in meters)

In this case, the length of the outer ear tube is given as 3 cm, or 0.03 meters. The tube is closed at one end and open at the other, so we must take into account that the closed end is a node of the standing wave, and the open end is an antinode.

This means that the lowest resonance frequency, or fundamental frequency, of the tube will be the frequency at which a half-wavelength fits into the length of the tube. Therefore, the wavelength of the sound wave that will resonate in the tube is twice the length of the tube (since it has a closed end), or 0.06 meters.

Using the formula above, we can calculate the fundamental frequency as:

f = (343/2π) x (1/0.03) ≈ 1220 Hz

Therefore, the lowest resonance frequency of the outer ear tube is approximately 1220 Hz.

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Answer:

try the formula v=s/t

v= velocity

s= speed

t=time

Explanation:

Answer:

turtle

Explanation: