what is square root 25/49
A. 25/49
B. 5/9
C. 5/7
D. 5/8

Answer:92

Step-by-step explanation:

\(\frac{64+88+92+89+81+92+x}{7} =85\)

85 x 7 = 595

595 - 64 - 88 - 92 - 89 - 81 - 92 = 92

Answer:

Naomi needs to score a 92 on her seventh test to raise her mean to an 85.

Step-by-step explanation:

Let's call the score Naomi needs to get on her seventh test "x".

To find out what score she needs to raise her mean to 85, we can set up an equation:

(64 + 88 + 92 + 86 + 81 + 92 + x) / 7 = 85

We add up all her scores so far (64 + 88 + 92 + 86 + 81 + 92) and add the score she needs to get on her seventh test (x). We divide the sum by the total number of tests (7) to get the mean score of 85.

Simplifying the equation, we get:

503 + x = 595

Subtracting 503 from both sides, we get:

x = 92

Answer:

C) 4

Step-by-step explanation:

I hope this helps :)

Answer:

y=2(x square)-2x-3

Step-by-step explanation:

Let dy with y varibles in a hand

And dx with x variables on the other hand

dy=(4x-2)dx

Then by integration

y=2(square x)-2x+constant

Then substitute by x=-1 and y=1 to find the value of the constant

1=2(1)-2(-1)+ constant

Then constant=-3

Then the equation is

y=2(x square)-2x-3

Answer:

420

Step-by-step explanation:

231 customer = 55%

100% = ?

100/55 * 231 = 420

You will need to put the number you want on top. In this case 100%.

========================================================

Explanation:

The first term is 4 because of the notation \(a_1 = 4\)

To get the second term, we'll use the recursive equation \(a_n = 5(a_{n-1})-1\) which basically says \(\text{nth term} = 5*(\text{previous term})-1\). To get the second term, we'll multiply the first term by 5, then subtract off 1.

2nd term = 5*(1st term) - 1

2nd term = 5*4 - 1

2nd term = 19

This means \(a_2 = 19\)

We repeat this process again to find the third term \(a_3\)

\(a_n = 5*(a_{n-1})-1\\\\a_3 = 5*(a_{3-1})-1\\\\a_3 = 5*(a_{2})-1\\\\a_3 = 5*(19)-1\\\\a_3 = 95-1\\\\a_3 = \boldsymbol{94}\\\\\)

The third term is 94

The 2972 square feet of surface area that Shane will paint, if he will paint the 4 rectangular sides, 2 triangular pieces and he will not paint the rectangular sections of roof.      

The given is,

Shane wants to paint,

4 rectangular sides

2 triangular sides

From the given diagram,

Total surface area of paint = (4 Rectangular sides surface area ) +(2 triangular sides surface area)....(1)

Surface area of 4 rectangular sides,

For Left side(rectangle) surface area,

A = lb ...........................................................(2)

From the given diagram.

= (45.5 × 20)

= 910 Square feet

Dimensions of left side and right side are equal, so area of right side equal to the left side.

Area of right side = 910 square feet

Area of left and right sides,

= Left side area+ Right side area

= 910 + 910

= 1820 square feet

For front side area,

A= lb ...........................................................(3)

From the given diagram,

= (24 × 20 )

= 480 square feet

Dimensions of front side and back sides are equal, so area of front side equal to the back side.

Area of front side = 480 square feet

Area of front and back sides,

= front side area+ back side area

= 480 + 480

= 960 square feet

Surface area of rectangular sides,

= Area of left and right sides + Area of front and back sides

=  1820 + 960 = 2780 square feet

Surface area of 2 triangular faces,

For area of triangular sides,

\(A= \frac{hb}{2}\) ...............................................(4)

From the given values,

= \(\frac{8 (24)}{2}\)

= \(\frac{192}{2}\)

= 96 square feet

Dimensions of front side triangle and back side triangles are equal, so area of front side triangle equal to the back side triangle.

Area of front side triangle = 96 square meters

Area of front and back side triangles,

= front side triangle area+ back side triangle area

= 96 + 96

= 192 square feet

From the equation (1),

Total surface area of paint = 2780 + 192

Total surface area of paint = 2972 square feet

The 2972 square feet of surface area that Shane will paint, if he will paint the 4 rectangular sides, 2 triangular pieces and he will not paint the rectangular sections of roof.              

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Answer:

The answer is light bulb letter B

Step-by-step explanation:

A = 40

B = 25

C = 60

D = 35

All these are their Unit values.

Let be "x" the length in feet represented by a scale drawing of:

You can write the given fraction as a Decimal number. To do this, you only need to divide the numerator by the denominator. Then:

Based on the information given in the exercise, you can set up the following proportion:

Now you must solve for "x" in order to find its value. This is:

The answer is:

Answer:

the requisite answer for this question is 10 meter.

Step-by-step explanation:

the analysis for this question's answer is as follows:

since, he has a 50 meter long role of cable, correct to the nearest meter,with him and also he uses 10 meter of that role each time during his job to the nearest meter.

therefore, if he does four jobs then the maximum amount of cable that could be left with him would be;

he took (40-m) to finish the entire work,

this simplifies, 50-(10×4) which is equal to 50-40 which in turn is equal to 10

hence, the solution to the afore-mentioned problem is 10 meters.

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Answer:

-48

Step-by-step explanation:

The full sequence until the tenth term is...

-3, -8, -13, -18, -23, -28, -33, -38, -43, -48,

Answer:

-48

Step-by-step explanation: You don't really care about the explanation. You already got the answer. What are you still doing here, reading this?

Answer: 23

Step-by-step explanation: 3 · 32 + 8 ÷ 2 − (4 + 3)  

parentheses first 3 · 32 + 8 ÷ 2 − (7) Then you need to multiply and divide from the left to the right 96 + 4 -7 Then add and subtract 100-7 93

Then simplify

Answer:

\(93\)

Step-by-step explanation:

\(3\times \:32+8\div \:2-\left(4+3\right)\)

Use the PEMDAS order of operations:

⇒ Parentheses

⇒ Exponents

⇒ Multiplication

⇒ Division

⇒ Addition

⇒ Subtraction

______________

Calculate within Parentheses:

\(3\times \:32+8\div \:2-7\)

Multiplication/Division:

\(96+8\div \:2-7\)

\(96+4-7\)

Addition/ Subtraction

_________________

OAmalOHopeO

Answer:

D;the tropical ostrich runs at a speed of about 36 miles per hour

Answer: It is D, The typical ostrich runs at a speed of about 36 miles per hour.

Step-by-step explanation:

I took the quiz on A p e x^^

a. To determine the value of a Call option with a strike price of $30 that expires at time t = 3, we need to calculate the option value at time t = 0 using the binomial model.

At each time period, there are two possible stock price movements: an upward jump and a downward jump. We can construct a binomial tree to represent these possibilities.

Starting at time t = 0, the stock price is $40. In the first time period, the stock can go up to $80 or down to $20. In the second time period, the stock can either go up to $160 or down to $40 (from $80), and down to $10 (from $20). Finally, in the third time period, the stock can reach $320, $80, $20, or $5.

To determine the value of the Call option at time t = 0, we need to calculate the option value at each node of the tree and work backwards. At the final nodes (t = 3), we compare the stock prices with the strike price of $30. If the stock price is higher than the strike price, the option value is the difference between the stock price and the strike price. If the stock price is lower, the option value is zero. We then propagate these option values back up the tree, applying the risk-neutral probability and discounting factors at each node, until we reach the initial node (t = 0).

b. Using the put-call parity, we can determine the value of the Put option at time t = 0 by considering the Call option value, the stock price, the strike price, and the present value of the strike price. The put-call parity relationship is given by:

Put Option Value + Stock Price - Call Option Value = Present Value of Strike Price.

In this case, we are given the Call option value from part (a) as the value at time t = 0. The stock price at time t = 0 is $40, and the strike price is $30. Since the interest rate is zero, the present value of the strike price is equal to the strike price itself.

Rearranging the put-call parity equation, we can solve for the Put option value:

Put Option Value = Call Option Value + Present Value of Strike Price - Stock Price.

Plugging in the known values:

Put Option Value = Call Option Value + $30 - $40.

Substituting the Call option value calculated in part (a), we can find the value of the Put option at time t = 0.

In this problem, we are given a binomial model with three time periods and certain stock price movements. We construct a binomial tree to represent the possible stock price paths and determine the value of the Call option at each node of the tree. By comparing the stock prices with the strike price at the final nodes, we calculate the option values at time t = 3 and propagate them back to time t = 0 using the risk-neutral probabilities and discounting factors.

For the Put option, we use the put-call parity relationship to determine its value at time t = 0. By rearranging the equation and substituting the known values, we can find the value of the Put option using the Call option value obtained in part (a). The put-call parity provides a relationship between the values of Put and Call options, stock price, strike price, and the present value of the strike price.

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Answer:

(0.5,-6)

Step-by-step explanation:

mid point=(x1+x2)/2

 =(-3+4)/2

= 1/2

=0.5

midpoint=(y1+y2)/2

      =(-9+(-3))/2

=(-9-3)/2

=--12/2

=-6

Answer:

D Angle

Step-by-step explanation:

Basically, calculating angle is looking at the degrees of how it tilts. You have to look at the line on the top and see how much it leans to the right. The more it leans, the less the angle is.

Answer:

distance between -5 to 0 = 5 units

(a) To find the critical numbers, we need to take the derivative of the function g(x). The derivative of g(x) is simply 1. To find the critical numbers, we need to set the derivative equal to zero and solve for x.

1 = 0
There is no solution to this equation, which means that there are no critical numbers for the function g(x).

(b) Since there are no critical numbers, we can't use the first derivative test to determine the intervals on which the function is increasing or decreasing. However, we can still look at the graph of the function to determine the intervals of increase and decrease.

The graph of the function g(x) = (x + 3) is a straight line with a slope of 1. This means that the function is increasing for all values of x, since the slope is positive. Therefore, the interval of increase is from negative infinity to positive infinity, and the interval of decrease is NONE.

(c) The graph of the function g(x) = (x + 3) is a straight line passing through the point (-3, 0) with a slope of 1. The graph starts at (-3, 0) and continues to increase indefinitely. The graph is a line that goes through the origin with a slope of 1.

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At 2:20 pm they finish the paint of wall.

Given, Al took 6 hours to paint a wall.

Bob took 4 hours and Chuck took 3 hours for same.

Let the work of painting wall is = LCM(6,4,3) = 12 Units

So in 1 hour Al works = 12/6 = 2 units

In 1 hour Bob works = 12/4 = 3 units

In 1 hour Chuck works = 12/3 = 4 units

In 1 hour, Al and Bob together do = 2+3 = 5 units

In 1 hour, all three together do = 2+3+4 = 9 units

Now from noon i.e. 12 to 1.00 pm Al works alone.

So 2 units of work is done.

From 1 pm to 1.30 pm, Al and Bob work together.

In 30 minutes i.e. ½ hour Al and Bob did = (1/2)*5 = 5/2 units

From 1.30 pm they all three work together.

Now the remaining work is = 12-(2+5/2) = 12-9/2 = 15/2 units

So they complete rest in = (15/2)/9 = 5/6 hours = 50 minutes

Hence the time of finishing the work = 1.30 + 50 minutes = 2.20 pm.

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Answer:

What are the choices?

Step-by-step explanation:

To evaluate the line integral ∫ xy^4 ds, where C is the right half of the circle x^2 + y^2 = 16 oriented counterclockwise, we can parameterize the curve C and then compute the integral along the curve.

The equation of the right half of the circle can be written as x = 4cos(t) and y = 4sin(t), where t ranges from 0 to π.

Now, we need to find the differential ds. The length element ds can be expressed as ds = √(dx^2 + dy^2). Substituting the parametric equations into ds, we get ds = √(16cos^2(t) + 16sin^2(t)) = 4.

Therefore, the line integral becomes ∫ (xy^4) ds = ∫ (4cos(t)(4sin(t))^4)(4) dt.

Simplifying further, we have ∫ 256cos(t)sin^4(t) dt.

To compute this integral, you can apply integration techniques such as u-substitution or trigonometric identities.

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$6,600 was loaned at the rate of 9%.

Here, we have,

Let's denote the amount loaned at 9% as "x" (in dollars).

The amount loaned at 19% can be calculated as the remaining amount, which is the total loan amount ($14,000) minus the amount loaned at 9% (x).

Therefore, the amount loaned at 19% is (14,000 - x).

Now, we can calculate the interest earned from each loan:

Interest from the loan at 9% = x * 0.09 = 0.09x

Interest from the loan at 19% = (14,000 - x) * 0.19 = 2,660 - 0.19x

According to the given information, the total interest earned is $2,000. So, we can set up the equation:

0.09x + (2,660 - 0.19x) = 2,000

Now, let's solve the equation to find the value of x:

0.09x + 2,660 - 0.19x = 2,000

-0.1x = -660

x = -660 / -0.1

x = 6,600

Therefore, $6,600 was loaned at the rate of 9%.

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If the initial population is 3800. The population of cockroaches after 3 years will be 1603.

Consider the function:

y = a(1 ± r)ⁿ

where n is the number of times growth/decay, a = initial amount, and r = fraction by which this growth/decay occurs.

If there is a plus sign, there is exponential growth happening by r fraction or r%.

If there is a minus sign, there is exponential decay happening by r fraction or r%.

If the population is currently 3,800 cockroaches.

The expression is given as

y = 3800(0.75)ⁿ

The population of cockroaches after 3 years will be

y = 3800(0.75)³

y = 3800 x 0.4218

y = 1603.125

y ≅ 1603

Hence, the population of cockroaches after 3 years will be 1603.

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The complete question is:

Colette has an exterminator visit regularly to control an ongoing cockroach problem. it's been working, and the population has declined by 15% every year. if the population is currently 3,800 cockroaches, how many will there be in 3 years? if necessary, round your answer to the nearest whole number.

Answer:

Two angles whose sum in 90 degrees

Step-by-step explanation:

Answer:

Step-by-step explanation:

I think it's B

Answer:250

Step-by-step explanation:

The proportion of the class with a midterm grade less than 75 is approximately 0.3085, or 30.85%. This means that 30.85% of the class is expected to have a midterm grade lower than 75.

We can use the cumulative distribution function (CDF) of the normal distribution to find the proportion of the class with a midterm grade less than 75.

The CDF of a normal distribution with mean μ and standard deviation σ evaluated at a point x is given by the formula:

CDF(x) = 0.5 * [1 + erf((x - μ) / (σ * √2))]

where erf is the error function.

For this problem, μ = 78 and σ = 6, and x = 75, so the CDF can be calculated as follows:

CDF(75) = 0.5 * [1 + erf((75 - 78) / (6 * √2))]

= 0.5 * [1 + erf(-0.3536)]

The value of erf(-0.3536) can be looked up in a table or calculated using a software package. The result is approximately -0.383.

CDF(75) = 0.5 * [1 + -0.383] = 0.5 * [0.617] = 0.3085

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Answer:

$12.50

Step-by-step explanation:

18 - 12 = 6

Brandon bought 6 less than Lance and payed $75 dollars shoes.

That means that 6 shirts cost $75.

We need to divide 6 from 75

75/6 = 12.5

So each shirt costs $12.50.

Hope this helped

Stay curious!

The expression of ln(84) in terms of ln(2), ln (3), and ln(7) is: \(2 ln(2) + ln(3) + ln(7).\)

We need to write ln(84) in terms of ln(2), ln(3), and ln(7).Let us use the prime factorization of 84:

\(84 = 2^2 \cdot 3 \cdot 7\)

Thus, we can write:

\(\ln(84) = \ln(2^2 \cdot 3 \cdot 7)\\\ln(84) = \ln(2^2) + \ln(3) + \ln(7)\\\ln(84) = 2 \ln(2) + \ln(3) + \ln(7)\)

Hence, the expression of ln(84) in terms of ln(2), ln (3), and ln(7) is: \(2 ln(2) + ln(3) + ln(7).\)

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The correct 98% confidence interval for the true proportion of graduates working in the field of study in which they obtained their degree is (0.811, 0.892).

To calculate the confidence interval, we need to use the formula for estimating proportions and the standard error of the proportion. The formula is:

Confidence interval = sample proportion ± z * standard error

Calculate the sample proportion

In this case, the sample proportion is the number of graduates working in their field of study (361) divided by the total number of graduates surveyed (424):

Sample proportion = 361/424 ≈ 0.852

Calculate the standard error

The standard error of the proportion is calculated using the formula:

Standard error = sqrt((sample proportion * (1 - sample proportion)) / sample size)

Using the given values, we have:

Standard error = sqrt((0.852 * (1 - 0.852)) / 424) ≈ 0.014

Determine the confidence interval

To find the z-value for a 98% confidence level, we look up the corresponding value in the z-table. The z-value for a 98% confidence level is approximately 2.33.

Substituting the values into the confidence interval formula, we have:

Confidence interval = 0.852 ± 2.33 * 0.014

Confidence interval ≈ (0.811, 0.892)

Therefore, the correct 98% confidence interval for the true proportion of graduates working in their field of study is (0.811, 0.892).

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