What is the approximate volume of the cylinder use 3.14

Answer:

1,377/2 and 688 1/17

Step-by-step explanation:

Answer:

constant for the first blank

liner equation=y-mx-b form

liner graph blank= straight

i forgot the other ones

Step-by-step explanation:

Answer:

0.25 g/mL

Step-by-step explanation:

d=m/v

6 g / 24 mL

0.25 g/mL

both (g) and mL were only used once so the answer includes both of them

The sample mean of 4.21 cm is significantly different from the specified target mean of 4.00 cm.

Step 1: State the hypotheses.

- Null Hypothesis (H₀): The mean length of the bolts is 4.00 cm (μ = 4.00).

- Alternative Hypothesis (H₁): The mean length of the bolts is not equal to 4.00 cm (μ ≠ 4.00).

Step 2: Compute the value of the test statistic.

To compute the test statistic, we will use the z-test since the population standard deviation (σ) is known, and the sample size (n) is large (n = 121).

The formula for the z-test statistic is:

z = (X- μ) / (σ / √n)

Where:

X is the sample mean (4.21 cm),

μ is the population mean (4.00 cm),

σ is the population standard deviation (0.83 cm), and

n is the sample size (121).

Plugging in the values, we get:

z = (4.21 - 4.00) / (0.83 / √121)

z = 0.21 / (0.83 / 11)

z = 0.21 / 0.0753

z ≈ 2.79 (rounded to two decimal places)

Step 3: Determine the critical value and make a decision.

With a level of significance of 0.02, we perform a two-tailed test. Since we want to determine if the mean length of the bolts is different from 4.00 cm, we will reject the null hypothesis if the test statistic falls in either tail beyond the critical values.

For a significance level of 0.02, the critical value is approximately ±2.58 (obtained from the z-table).

Since the calculated test statistic (2.79) is greater than the critical value (2.58), we reject the null hypothesis.

Conclusion:

Based on the computed test statistic, there is sufficient evidence to show that the manufacturer needs to recalibrate the machines. The sample mean of 4.21 cm is significantly different from the specified target mean of 4.00 cm, indicating that the machine's output is not meeting the desired length. The manufacturer should take action to recalibrate the machines to ensure the bolts meet the required length of 4.00 cm.

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Between the previous balance method and the daily balance method, the method of calculating Yvonne's June finance charge that will result in a greater finance charge is:

Using the previous balance method to compute the finance charge, the beginning balance is added to purchases minus payments.  Then the APR is applied to the sum.

The daily balance method ensures that an average daily balance is computed for the billing cycle and then the APR is applied to the average to compute the finance charge.

Date   Transaction             Amount ($)   Balance     Daily Balance

6/1      Beginning balance    925.43      $925.43  $5,552.58 ($925.43 x 6)

6/7     Payment                       62.74      $862.69     3,450.76 ($862.69 x 4)

6/11    Purchase                      28.27      $890.96     8,909.60 ($890.96 x 10)

6/21   Purchase                      50.00      $940.96    9,409.60 ($940.96 x 10)

Total                                                        $27,322.54

Average daily balance = $910.75 ($27,322.54)

APR = 17.79%

MPR = 1.4825% (17.79%/12)

Previous balance method = $13.95 ($940.96 x 1.4825%)

Average daily balance = $13.50 ($910.75 x 1.4825%)

Difference = $0.45 ($13.95 - $13.50)

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The following table details her credit card transactions in the month of June.

Date   Transaction             Amount ($)

6/1      Beginning balance    925.43

6/7     Payment                       62.74

6/11    Purchase                      28.27

6/21   Purchase                      50.00

Between the previous balance method and the daily balance method, which method of calculating Yvonne's June finance charge will result in a greater finance charge, and how much greater will it be?

a. The daily balance method will have a finance charge $0.21 greater than the previous balance method.

b. The daily balance method will have a finance charge $0.53 greater than the previous balance method.

c. The previous balance method will have a finance charge $0.45 greater than the daily balance method.

d. The previous balance method will have a finance charge $0.40 greater than the daily balance method.

To complete the job in 12 days, they need 100 workers.

We know that 30 workes can complete 1 job in 40 days, then if each worker works at a rate R, then we can write:

30*R*40 days = 1 job

R = (1/1200) job/day

Then if they need to complete the job in 12 days, the number N of workers needed is:

N*(1/1200)*12 = 1

N = (1200/12) = 100

100 workers are needed.

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The probability that neither of them is chosen for inspection is given as follows:

a) 81 %

The mass probability formula, giving the probability of x successes, is of:

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

The parameters are given by:

The parameter values for this problem are given as follows:

n = 2, p = 0.1.

The probability of neither is P(X = 0), hence:

P(X = 0) = (1 - 0.1)² = 0.81.

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Answer:

35 degree angle a cute angle

Answer:

Step-by-step explanation:

A and B are supplementary angles since the lines are parallel

A + B = 180

6x-18 + 14x+38 = 180

Combine like terms

20x +20 = 180

Subtract 20 from each side

20x+20 -20 =180-20

20x = 160

Divide by 20

20x/20 =160/20

x = 8

Answer:

Step-by-step explanation:

Given the rate at which an eucalyptus tree will grow modelled by the equation 0.5+6/(t+4)³ feet per year, where t is the time (in years).

The amount of growth can be gotten by integrating the given rate equation as shown;

\(\int\limits {0.5 + \frac{6}{(t+4)^{3} } } \, dt \\= \int\limits {0.5} \, dt + \int\limits\frac{6}{(t+4)^{3} } } \, dx } \, \\= 0.5t +\int\limits {6u^{-3} } \, du \ where \ u = t+4 \ and\ du = dt\\= 0.5t + 6*\frac{u^{-2} }{-2} + C\\= 0.5t-3u^{-2} +C\\= 0.5t-3(t+4)^{-2} + C\)

a)  The number of feet that the tree will grow in the second year can be gotten by taking the limit of the integral from  t =1 to t = 2

\(\int\limits^2_1 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^2_1\\= [0.5(2)-3(2+4)^{-2}] - [0.5(1)-3(1+4)^{-2}]\\= [1-3(6)^{-2}] - [0.5-3(5)^{-2}]\\ = [1-\frac{1}{12}] - [0.5-\frac{3}{25} ]\\= \frac{11}{12}-\frac{1}{2}+\frac{3}{25}\\ = 0.9167 - 0.5 + 0.12\\= 0.5367feet\)

b)  The number of feet that the tree will grow in the third year can be gotten by taking the limit of the integral from  t =2 to t = 3

\(\int\limits^3_2 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^3_2\\= [0.5(3)-3(3+4)^{-2}] - [0.5(2)-3(2+4)^{-2}]\\= [1.5-3(7)^{-2}] - [1-3(6)^{-2}]\\ = [1.5-\frac{3}{49}] - [1-\frac{1}{12} ]\\ = 1.439 - 0.9167\\= 0.5223feet\)

c) The total number of feet grown during the second year can be gotten by substituting the value of limit from t = 0 to t = 2 into the equation as shown

\(\int\limits^2_0 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^2_0\\= [0.5(2)-3(2+4)^{-2}] - [0.5(0)-3(0+4)^{-2}]\\= [1-3(6)^{-2}] - [0-3(4)^{-2}]\\ = [1-\frac{1}{12}] - [-\frac{3}{16} ]\\= \frac{11}{12}+\frac{3}{16}\\ = 0.9167 - 0.1875\\= 0.7292feet\)

Answer:

0

Step-by-step explanation:

\(2\sqrt[3]{(1-3x)} =6-4=2\\\sqrt[3]{(1-3x)}=\frac{2}{2} =1\\\sqrt[3]{(1-3x)}^{3} =1^{3} \\(1-3x)=1\\-3x=0\\x=0\)

The angle BOC has a measure of 50 degrees

From the question, the given parameters about the angles are:

The above parameters implies that

AOC = AOB + BOC

Next, we substitute the angle measurements in the above equation

So, we have

142 = 9x + 20 + 7x - 6

Evaluate the like terms

So, we have the following equation

142 = 16x + 14

Evaluate the like terms again

So, we have the following equation

16x = 128

Divide both sides by 16

x = 8

Substitute x = 8 in BOC = 7x - 6

BOC = 7 x 8 - 6

Evaluate

BOC = 50

Hence, the measure of the angle is 50 degrees

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The angle BOC has a measure of 50 degrees

An angle is formed when two straight lines or rays meet at a common endpoint

If OA-OB-OC and if AOB = 9x + 20, BOC = 7x - 6 and AOC = 142

We need to find BOC

We have AOC = AOB + BOC

142=9x + 20+7x-6

142=16x+14

Subtract 14 from both sides

142-14=16x

128=16x

Divide both sides by 16.

8=x

Now put x value in BOC = 7x - 6

BOC = 7x - 6

=7(8)-6

=56-6

BOC=50

Hence If OA-OB-OC and if AOB = 9x + 20, BOC = 7x - 6 and AOC = 142 then BOC=50.

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Answer:

$13.50

Step-by-step explanation:

9 9/10 = 9.90

6 3/5 = 6.60

x = 30.00 - 9.90 - 6.60

x = 13.50

Answer:

Step-by-step explanation:

It is possible to solve this problem without using algebra and equations.

One number is 7 more than the other, but they add to 25.

If you subtract the difference of 7 first, you will be left with the sum of two equal numbers.

25

−

7

=

18

18

÷

2

=

9

The one number is 9 and the other is 7 more than 9, so (9+7 = 16)

The numbers are 9 and 16.

Check: 9+16 = 25#

Answer:

The pair of numbers that has a sum of 45 and a difference of 5 is (B) 25 and 20.

Step-by-step explanation:

26 + 19 = 45  and 26 - 19 = 3

25 + 20 = 45 and 25 - 20 = 5

24 + 21 = 45 and 24 - 21 = 3

26 + 21 = 47 and 26 - 21 = 5

Answer: 120 yds

Step-by-step explanation:

48+30+24+18+120 yds

Step-by-step explanation:

Pitchers(p) = 12

Infielders(i) = 5

Others(o) = 8

Total players = 25

Probability(2p and 1i) =

\(( \frac{2}{25} ) \times ( \frac{1}{25} ) = ( \frac{2}{625} )\)

Answer:

2y°+y+10°+50°=180°[by sum of angles of triangle is 180°]

3y + 60°=180°

3y=180°-60°

3y=120°

y=120/3

y=40

option a.

14a. =

15b. 2/3 is less than 0.667

16c. 3 7/8 is greater than 3.375

17d. 3/8 is less than 1/2

Answer:

\(\cos G=\dfrac{2}{3}\)

\(\csc E=\dfrac{3}{2}\)

\(\cot G=\dfrac{2}{\sqrt{5}}\)

Step-by-step explanation:

If the right angle of right triangle EFG is ∠F, then EG is the hypotenuse, and EF and FG are the legs of the triangle. (Refer to attached diagram).

Given ΔEFG is a right triangle, and EG = 6 and FG = 4, we can use Pythagoras Theorem to calculate the length of EF.

\(\begin{aligned}EF^2+FG^2&=EG^2\\EF^2+4^2&=6^2\\EF^2+16&=36\\EF^2&=20\\\sqrt{EF^2}&=\sqrt{20}\\EF&=2\sqrt{5}\end{aligned}\)

Therefore:

\(\hrulefill\)

To find cos G, use the cosine trigonometric ratio:

\(\boxed{\begin{minipage}{9 cm}\underline{Cosine trigonometric ratio} \\\\$\sf \cos(\theta)=\dfrac{A}{H}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)

For angle G, the adjacent side is FG and the hypotenuse is EG.

Therefore:

\(\cos G=\dfrac{FG}{EG}=\dfrac{4}{6}=\dfrac{2}{3}\)

\(\hrulefill\)

To find csc E, use the cosecant trigonometric ratio:

\(\boxed{\begin{minipage}{9 cm}\underline{Cosecant trigonometric ratio} \\\\$\sf \csc(\theta)=\dfrac{H}{O}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)

For angle E, the hypotenuse is EG and the opposite side is FG.

Therefore:

\(\csc E=\dfrac{EG}{FG}=\dfrac{6}{4}=\dfrac{3}{2}\)

\(\hrulefill\)

To find cot G, use the cotangent trigonometric ratio:

\(\boxed{\begin{minipage}{9 cm}\underline{Cotangent trigonometric ratio} \\\\$\sf \cot(\theta)=\dfrac{A}{O}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)

For angle G, the adjacent side is FG and the opposite side is EF.

Therefore:

\(\cot G=\dfrac{FG}{EF}=\dfrac{4}{2\sqrt{5}}=\dfrac{2}{\sqrt{5}}\)

Answer:

Step-by-step explanation‎:

Answer:

10 cases 4 units over

Step-by-step explanation:

Answer:

w<13

Step-by-step explanation:

Works identically to a normal single-variable equation.
Subtract 7 on both sides in order to isolate w--->w+7-7<20-7
The answer (which cannot be simplified any further) is w<13.

Answer:

w < 1`3

Step-by-step explanation:

Isolate the variable w on one side of the inequality sign.

w+7<20

w<20 - 7

w<13.

Answer:

\(x=-3\)

\(y=6\)

Step-by-step explanation:

Elimination method:

\(2x+7y=36\)

\(6x-7y=-60\)

Add these equation to eliminate y:

\(8x=-24\)

Then solve \(8x=-24\) for x:

\(8x=-24\)

\(\frac{8x}{8} =\frac{-24}{8}\)

\(x=-3\)

Add the value of x to solve y:

\(2x+7y=36\)

Substitute \(-3\) for x in \(2x+7y=36\)

\((2)(-3)+7y=36\)

\(7y-6=36\)

\(7y=36+6\)

\(7y=42\)

\(y=42/7\\\)

\(y=6\)

{ \(x=-3\) and \(y=6\) }

hope this helps....

Answer:

(4,6)-(-2,-1)

Step-by-step explanation:

The acute angle the ladder makes with the ground is 69.3 degrees.

The ladder is 5.1 m and it is leaning against a wall.

The wall is perpendicular to the ground.

This means the ground forms 90 degrees with the wall.

This situation forms a right angle triangle.

Therefore, the acute angle the ladder forms with the ground can be found as follows:

Using trigonometric ratios,

cos ∅ = adjacent / hypotenuse

where

∅ = acute angle

Therefore,

adjacent side = 1.8 m

hypotenuse side = 5.1 m

Hence,

cos ∅ = 1.8 / 5.1

∅ = cos⁻¹ 0.35294117647

∅ = 69.3326835065

∅ = 69.3°

Therefore, the acute angle the ladder makes with the ground is 69.3 degrees.

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Answer:

See the answers below. Thanks!

Step-by-step explanation:

(a). Option F is the correct choice. "There are two mutually exclusive outcomes, success or failure."

(b). P(X=15) = 0.1702

(c). P(X<15) = 0.0673

(d). P(X>=15) = 1 - P(X<15) = 0.9327

(e). P(13<=X<=15) = 0.1482

Best Regards!

Answer:

193.08

Step-by-step explanation:

Your Welcome :D

Can i have brainlest

Answer:

193.08

Step-by-step explanation:

Answer: 0.002. 0.127 - 0.125 is 0.002

Answer:

x-intercept= (4.265,0)

y-intercept= (0,-534)

Step-by-step explanation:

Answer:

The width is 18 feet and the length is 42 feet

Step-by-step explanation:

Let x feet be the width of the patio. The length of the patio is 6 feet longer than twice it’s width, then the length of the patio is 2x+6 feet.

Wayne is hanging a string of lights 78 feet long around the three sides of his patio, which is adjacent to his house. The side with length 2x+6 feet is adjacent to the house, so Wayne is hanging a string along three sides with lengths x ft, x ft and 2x+6 ft.

x+x+2x+6=78

4x=78-6

4x=72

divide both sides by 4

x=18 ft

The width  18 ft

2*18+6=36+6=42 ft

The length  42 ft

Answer:

  see attached

Step-by-step explanation:

The equation is in the form ...

  4p(y -k) = (x -h)^2 . . . . . (h, k) is the vertex; p is the focus-vertex distance

Comparing this to your equation, we see ...

  p = 4, (h, k) = (3, 4)

p > 0, so the parabola opens upward. The vertex is on the axis of symmetry. That axis has the equation x=x-coordinate of vertex. This tells you ...

  vertex: (3, 4)

  axis of symmetry: x = 3

  focus: (3, 8) . . . . . 4 units up from vertex

  directrix: y = 0 . . . horizontal line 4 units down from vertex