What is the concentration in molarity of a solution which is 4.61 %m/v
xylene (MM = 106.2 g/mol ) in toluene (MM = 92.30 g/mol)?

Answers

Answer 1

The molarity of the given solution will be 0.434 M  . Since the concentration is given in percentage in mass/volume  form, the molarity of the solution will be calculated as follows:

Here,

Concentration= 4.61% m/v

Molecular mas of xylene= 106.2g/mol

Moecular mass of toulene = 92.30g/mol

Molarity is defined to be as moles of solute present per liter of solution.  Here  we are dealing with two liquids, the one having greater amount will be taken  as the solvent and the one having lower amount will be taken as the solute

4.61% m/v = 4.61 g xylene/100 ml toulene

= 4.61 g xylene/L

Now Converting this to moles / L we will get:

46.1 g xylene  x 1

mol/106.2 g = 0.434 moles xylene per L of toulene

Molarity (M) = No of moles of solute  / Volume of solute( L)

= 0.434 moles / 1 L

= 0.434 M

So, the concentration of the given solution in molarity will be equal 0.434M

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Related Questions

Can you have a pH thats in decimals? For example .3 or .4?

Answers

A pH of 4 is ten times more acidic than a pH of 5.

Yes, pH can have decimal values. In fact, pH values can range from 0 to 14 and can have any value between them including decimals. pH is a measure of the acidity or alkalinity of a solution, and it is determined by the concentration of hydrogen ions (H+) in the solution.A solution with a pH of 7 is neutral, which means that it has an equal concentration of hydrogen ions (H+) and hydroxide ions (OH-). An acidic solution has a pH below 7 and a high concentration of H+ ions. On the other hand, an alkaline solution has a pH above 7 and a low concentration of H+ ions.A pH that is less than 7.0 indicates acidity. pH less than 7.0 is acidic while pH greater than 7.0 is alkaline. Each number on the pH scale represents a ten-fold change in the acidity/alkalinity of the solution. For example, a pH of 5 is 10 times more acidic than a pH of 6, and 100 times more acidic than a pH of 7.A pH of 0 indicates a very strong acidic solution while a pH of 14 indicates a very strong alkaline solution. It's worth noting that pH is a logarithmic scale, meaning that a change of one pH unit corresponds to a ten-fold change in hydrogen ion concentration.

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Write the equation for the equilibrium constant (K) of the reaction studied in this exercise.

2C04 2- (ag) + 2Ht (ag) = CI20, 2- (ag) + H20(1)

Answers

The equation for the equilibrium constant (K) of the reaction studied in this exercise can be written as follows: K = ([\(CI_20\), 2-] * [\(H_20\)(1)]) / ([\(C0_4^ 2\)-] * [Ht])

In this equation, the concentrations of the species involved in the reaction are represented by the square brackets [ ]. The subscripts indicate the stoichiometric coefficients of each species in the balanced chemical equation.

The reaction being studied involves the following species:

\(C0_4^ 2\)- (ag) + 2Ht (ag) = \(CI_20\), 2- (ag) + \(H_20\)(1)

In the equilibrium constant expression, the concentration of \(CI_20\), 2- is multiplied by the concentration of \(H_20\)(1) and divided by the product of the concentrations of \(C0_4^ 2\)- and Ht. The stoichiometric coefficients in the balanced equation are used as exponents for the concentrations of the respective species.

It is important to note that the concentrations used in the equilibrium constant expression should be in molar units (mol/L) or expressed as partial pressures for gases.

Additionally, the equilibrium constant is specific to a given temperature, and its value provides information about the relative amounts of reactants and products at equilibrium.

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PLEASE HELP, IS MY ANSWER CORRECT?
How does the ground temperature in sunlight with CO2 compare with the ground temperature in sunlight without CO2 (part A)? is my answer correct?

Based on the thermometer provided, it is clearly visible that when the simulation is without CO2, the temperature goes higher, however, not as quickly as when CO2 IS present.

Answers

Your answer seems to be partially correct. It is true that the simulation without CO2 shows a rise in temperature, but it's incorrect to say that it goes higher. In fact, the temperature rises more rapidly when CO2 is present. Therefore, the correct answer would be:

Based on the thermometer provided, the ground temperature in sunlight with CO2 rises more rapidly and reaches a higher temperature compared to the ground temperature in sunlight without CO2.

11.9 g Cl2 is reacted with 10.7 g NaOH. How many moles of NaCl are produced?

Answers

Answer:

1. 7.256g of NaCl

2. 47.33g of Cl2

Explanation:

2 moles of Na reacts to produce 2 moles of NaCl

8 moles of Na will still produce 8 moles of NaCl

Mass of NaCl = molar mass of Nacl/moles of Nacl

=58.5/8

=7.256g of NaCl

From the equation, 2 moles of Na reacts with 1 mole of Cl2

3/2 moles of Cl2 will react with 3 moles of Na

Mass of Cl2 = 71/1.5

=47.33g of Cl2

Explanation:

According to the mole concept and stoichiometry, 0.33 50 moles of NaCl are produced when 11.9 g Cl₂ is reacted with 10.7 g NaOH.

What is a mole?

Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.

It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.

It is widely used in chemistry as a suitable way for expressing amounts of reactants and products.For the practical purposes, mass of one mole of compound in grams is approximately equal to mass of one molecule of compound measured in Daltons.

According to chemical reaction between NaOH and HCl 35.5 g of chlorine produces 58.5 g NaCl so 11.9 g will produce, 11.9×58.5/35.5=19.60 g which is equal to 19.60/58.5=0.3350 moles.

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Heredity Lab Report Instructions:
In the Heredity lab, you investigated how hamsters inherit traits from their parents. Record your observations in the lab report below. You will submit your completed report.
Name and Title: Include your name, instructor's name, date, and name of lab.

Objective(s): In your own words, what was the purpose of this lab?

Hypothesis: In this section, please include the if/then statements you developed during your lab activity.

These statements reflect your predicted outcomes for the experiment.

Test One: If I breed a short fur, FF female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Two: If I breed a short fur, Ff female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Three: If I breed a long fur, ff female with a long fur, ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Procedure: The procedures are listed in your virtual lab. You do not need to repeat them here.
Please be sure to identify the test variable (independent variable) and the outcome variable (dependent variable) for this investigation. Remember, the test variable is what is changing in this investigation.
The outcome variable is what you are measuring in this investigation.
Test variable (independent variable): Outcome variable (dependent variable): Data: Record the data from each trial in the data chart below. Be sure to fill in the chart completely. Test One Parent 1: FF Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Two Parent 1: Ff Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Three Parent 1: ff Parent 2: ff Phenotype ratio: ________ : ________ short fur : long fur Conclusion: Your conclusion will include a summary of the lab results and an interpretation of

Answers

For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2

What are the phenotype ratios from the test crosses?

For Test One:

Parent 1: FF (homozygous dominant for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff = 1 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 2 : 0 or 100% short fur

For Test Two:

Parent 1: Ff (heterozygous for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff : ff = 1 : 2 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur

For Test Three:

Parent 1: ff (homozygous recessive for long fur)

Parent 2: ff (homozygous recessive for long fur)

The Punnett square for this cross will give the following genotype ratios:

ff : ff = 1 : 0

And the corresponding phenotype ratios will be:

Short fur : Long fur = 0 : 2 or 100% long fur

For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.

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Question 18 (1 point)
What is the pH of a buffer that is 0.086 M HF and 0.386 M LiF? The K₂ for HF is 3.5
x 10-4.
Your Answer:
Answer

Answers

The pH of a buffer that is 0.086 M HF and 0.386 M LiF when the K₂ for HF is 3.5x 10-4 is 2.802

The pH of a buffer solution is given by Henderson Hasselback equation.

pH=pKa+log[A-]/[HA]

Substituting the values, we get

pH=-log(3.5x10^-4)+log(0.086/0.386)

pH=-log(3.5x10^-4)-0.653

pH=3.455-0.653

pH=2.802

pH is the potenz of hydronium ion.It tells the acidic strength of a compound.Buffer solution resists the change in pH on the addition of weak acid or base and conjugate of weak acid or base.It is used in acid-base chemistry.Buffer solutions are used for keeping the pH at a constant value.

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HQ5.40
Homework Answered Due Today, 11:59 PM
The reaction 3H₂(g) + N₂(g) → 2NH3(g) has an enthalpy of reaction of -92.6 kJ/mol. If 1 g of hydrogen and 2 g of nitrogen are
reacted, how much heat is produced (kJ)?

Answers

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

How do i determine the heat energy produced?

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 3 × 2 = 6 g

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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A sample of gas is put into a rigid (fixed volume) container at 3 oC and a pressure of 38.5 kPa. The container is then placed in an oven at 267 oC.

What pressure would you expect to measure for the gas in the container at this higher temperature?

Answers

We would expect to measure a pressure of approximately 75.25 kPa for the gas in the container at the higher temperature of 267 oC.

To determine the expected pressure of the gas in the container at the higher temperature, we can use the combined gas law, which relates the initial and final conditions of temperature and pressure in a fixed volume system. The combined gas law equation is given as:

(P1 * V1) / T1 = (P2 * V2) / T2

Where:

P1 = Initial pressure

V1 = Initial volume (which is fixed in this case)

T1 = Initial temperature

P2 = Final pressure (to be determined)

V2 = Final volume (which is fixed in this case)

T2 = Final temperature

In this scenario, the initial conditions are given as 3 oC (which is equivalent to 276 K) and 38.5 kPa. The final temperature is 267 oC (which is equivalent to 540 K). Since the volume is fixed, we can substitute the given values into the equation:

(38.5 kPa * V1) / 276 K = (P2 * V1) / 540 K

Simplifying the equation, we can cancel out V1:

38.5 / 276 = P2 / 540

Solving for P2:

P2 = (38.5 / 276) * 540 ≈ 75.25 kPa

Therefore, we would expect to measure a pressure of approximately 75.25 kPa for the gas in the container at the higher temperature of 267 oC.

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How does energy flow through the food chain?
Science Food Chain Concept illustration


eagle, snake, frog, grasshopper, grass

grass, grasshopper, frog, snake, eagle

grasshopper, grass, snake, frog, eagle

grass, grasshopper, frog, eagle, snake

Answers

Answer:

2nd order.

Explanation:

gras, grasshopper, frog, snake, eagle

Pleas mark branliest if you are satisfied with the answer. Thanking you in anticipation.

Answer:

So, energy is really all one big circle. Think of it like this:

When an organism dies, it's body is always inevitably taken back by the earth. For the purpose of the example, we'll use one specific scavenger as the main contributor here. When the body soaks back into the soil, the nutrients act as a fertilizer and aid in the growth of a patch of grass, that grass is eaten by a grasshopper, then, a frog comes along and is eaten by a snake, and eventually, that snake is eaten by an eagle. Let's say that eagle dies of natural causes, and once it passes away, the earth reclaims it's body. Now, we have a whole new fresh patch of grass and the cycle continues on, and on, and on. In this way, all energy is made eternal through the cycle of life and the food chain.

Aluminum undergoes a single-displacement reaction with copper (II) sulfate to form aluminum sulfate and _______________.

Answers

Al + CuSO4- Al2(SO4)3 + Cu

Ans cooper

EX/Cupper(I)Iodide
*What was happen if excess amount of potassium iodide and sodium thiosulfate added?

*How can increase rate of the reaction?

*What is role of the product washing by water, ethanol and ether?​

Answers

Explanation:

Copper sulphate reacts with potassium iodide to form cuprous iodide and iodine.

2CuSO

4

+4KI→Cu

2

I

2

↓+I

2

+2K

2

SO

4

Thus, CuI

2

is not formed in this reaction.

Hence, the option B is incorrect and option A is correct.

The liberated iodine is titrated with sodium thiosulphate to form sodium tetrathionate.

2Na

2

S

2

O

3

+I

2

→Na

2

S

4

O

6

+2NaI

Iodine is reduced and sodium thiosulphate is oxidized.

Kaya is riding her dirt bike eastward on a dirt road. She spots a pothole ahead. Kaya slows from 20.0 m/s to 6 m/s in 6.0 s. What is her acceleration?

Answers

initial velocity=u=20m/sFinal velocity=v=6m/sTime=t=6s

\(\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{6-20}{6}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{-14}{6}\)

\(\\ \sf\longmapsto Acceleration=-2.3m/s^2\)

Convert 12.3 newtons to pounds

Answers

2.7651500001 pound-force

i think thats the answer. Apologies if it isn't :)

The city of Annandale has been directed to upgrade its primary wastewater treatment plant to a secondary treatment plant with sludge recycle that can meet an effluent standard of 11 mg/l BOD5. The following data are available: Flow = 0.15 m3/s, MLSS = 2,000 mg/L. Kinetic parameters: K, = 50 mg/L, Hmax = 3.0 d-, kų = 0.06 d-1, Y = 0.6 Existing plant effluent BOD5 = 84 mg/L. a. Calculate the SRT (Oc) and HRT (0) for the aeration tank. b. Calculate the required volume of the aeration tank. c. Calculate the food to microorganism ratio in the aeration tank. d. Calculate the volumetric loading rate in kg BOD3/m3-d for the aeration tank. e. Calculate the mass and volume of solids wasted each day, when the underflow solids concentration is 12,000 mg/L. 10 A

Answers

Oh that’s hard I can’t figure that out sorry bud:(

Match the following elements with their symbols.

1.mercury Ag
2.silver He
3.gold Al
4.aluminum Fe
5.iron Hg
6.helium Ca
7.calcium Au
8.magnesium Mg
9.nickel Ni

Answers

1: Mercury - Hg
2: Silver - Ag
3: Gold - Au
4. Aluminium - Al
5: Iron - Fe
6: Helium - He
7: Calcium - Ca
8: Magnesium - Mg
9: Nickel - No

Match the following elements with their symbols.

\( \sf 1.\: mercury \: \: \: \: \: \: \: \: \: Ag (2)\\ \sf 2.\: silver \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: He (6) \\ \sf 3.\: gold \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: Al (4) \\ \sf 4.\: aluminum \: \: \: \: \: \: \: Fe (5) \\ \sf 5.\: iron \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: Hg (1)\\ \sf 6.\: helium \: \: \: \: \: \: \: \: \: \: \: \: Ca (7) \\ \sf 7.\: calcium \: \: \: \: \: \: \: \: \: \: Au (3)\\ \sf 8.\: magnesium \: \: \: Mg(8) \\ \sf 9.\: nickel \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: Ni(9) \\ \)

_____________________________

Symbol of Mercury is Hg.Symbol of Silver is Ag.Symbol of gold is Au.Symbol of Aluminium is Al.Symbol of Iron is Fe.Symbol of Helium is He.Symbol of Calcium is Ca.Symbol of Magnesium is Mg.Symbol of Nickel is Ni.

Sam noticed on a climate map that most of the areas with high rainfall and a tropical climate were located in one region. Why are all the rainy, tropical areas found at a similar latitude? Describe the factors that influence the climate in this location.

Answers

Answer:

Okay here's the answer ↓

Step-by-step explanation:

Tropical climate is one of the five major climate groups in the Köppen climate classification. Tropical climates are characterized by monthly average temperatures of 18 ℃ (64.4 ℉) or higher year-round and feature hot temperatures. Annual precipitation is often abundant in tropical climates, and shows a seasonal rhythm to varying degrees. There are normally only two seasons in tropical climates, a wet season and a dry season. The annual temperature range in tropical climates is normally very small. Sunlight is intense because they are receiving direct sunlight.

What is an example of a gas in motion and a fluid in motion?

Answers

Answer:

Gas in motion : Vaporization

Examples of fluid flow :

A river flowing down a mountainAir passing over a bird's wingBlood moving through a circulatory systemFuel moving through an engine.

Explanation:

Silver has a density of 10.5 g/cm³, and gold has a density of 19.3 g/cm³. Which would have a greater mass, 5 cm³ of silver or 5 cm³ of gold?

Answers

Gold have a greater mass

Further explanation  

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

The unit of density can be expressed in g/cm³ or kg/m³  

Density formula:  

\(\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}\)

ρ = density  

m = mass  

v = volume  

mass of Silver :

\(\tt mass=\rho\times V\\\\mass=10.5\times 5=52.5~g\)

mass of Gold :

\(\tt mass=\rho\times V\\\\mass=19.3\times 5=96.5~g\)

Why would you expect the materials used to make pot holders to be poor conductors of heat?

Answers

Answer:

Pot holders are meant to protect your hand from the heat of the pot, and so it would need to be a poor conductor of heat in order to do its job correctly. Silicon dioxide is a solid at room temperature and methanol is a liquid.

The two boron atoms listed in the table are isotopes of the boron. The two carbon atoms and the two oxygen atoms are also called isotopes. Based on the patterns in the particle compositions of these atoms, write a definition for “isotopes”

Answers

Answer:

A type of an atom which has a different number of neutrons but the same atomic number, therefore making it the same element. This atom would still have the same properties as well. (Ex: Vanadium-51 is an isotope of Vanadium that has 51 neutrons but still has 23 protons, as its atomic number is 23.)

Isotopes are variants of an element that have the same number of protons in their atomic nucleus, identifying them as the same chemical element, but differ in the number of neutrons.

The variations in neutron numbers among isotopes lead to differences in their atomic masses, resulting in isotopes having slightly different physical properties while retaining similar chemical behavior.

For example, in the case of boron, the two isotopes listed may have the same number of protons (5), but one has 6 neutrons, and the other has 7 neutrons, leading to slightly different atomic masses.

Similarly, for carbon and oxygen, the isotopes exhibit variations in neutron numbers while maintaining the same number of protons, defining them as isotopes of the respective elements. Isotopes play a crucial role in various scientific fields, including radiometric dating, nuclear energy, and medical imaging.

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The solution in a titration experiment whose concentration is
known is called the
a standard solution
b acid
c indicator
d base

Answers

Answer: It is indeed A.Standard Solution.

Hope this helps you!

A. Standard Solution The standard solution is the solution in a titration whose concentration is known. In the titration described above the base solution is the standard solution.

Enter the complementary strand of this DNA strand. Give your answer as a string.

Enter the complementary strand of this DNA strand. Give your answer as a string.

Answers

Answer:

atagcca

Explanation:

t goes with a, and c goes with g

atagcca matches with

ta tcggt

The nucleus of an atom contains which subatomic partcles?

Answers

Answer:

The nucleus contains two types of subatomic particles, protons and neutrons. The protons have a positive electrical charge and the neutrons have no electrical charge. A third type of subatomic particle, electrons, move around the nucleus. The electrons have a negative electrical charge.

Suppose that the microwave radiation has a wavelength of 12.4 cm . How many photons are required to heat 255 mL of coffee from 25.0 ∘C to 62.0 ∘C

Answers

Answer:

Explanation:

wavelength λ = 12.4 x 10⁻² m .

energy of one photon = h c / λ

= 6.6 x 10⁻³⁴ x 3 x 10⁸ /  12.4 x 10⁻²

= 1.6 x 10⁻²⁴ J .

Let density of coffee be equal to density of water .

mass of coffee = 255 x 1 = 255 g

heat required to heat up coffee = mass x specific heat x rise in temp

= 255 x 4.18 x ( 62-25 )

= 39438.3 J  .

No of photons required = heat energy required / energy of one photon

= 39438.3 / 1.6 x 10⁻²⁴

= 24649 x 10²⁴

= 24.65 x 10²⁷ .

17. According to Newton's first law, an object in motion will stay in what kind of
motion as long as the net forces acting on it are zero?
A. slowing motion in a straight line
B. accelerating motion in a straight line
C. constant motion in a straight line
D. constant motion in an unpredictable direction

Answers

Answer:

C

Explanation:

According to Newton's first law, an object in motion will stay in motion unless acted upon by an unbalanced force. The option which gives the same meaning is :

constant motion in a straight line

According to Newton's first law, an object in motion as long as the net forces acting on it are zero will stay in:

C. constant motion in a straight line

A constant motion in mechanics is a number that remains constant throughout the motion, effectively placing a restriction on the motion.

What is Newton's first law of motion?The foundation of classical mechanics is made up of the three laws of motion that Newton suggested. These three physical laws. In accordance with the three laws of motion, a body's connection to the forces operating on it and the motion that resulted from those forces are both described. As Galileo's law of inertia, Newton's First Law of Motion is also referred to. If a body is not forced by an outside force to change its condition, it will remain in its state of rest or uniform motion in a straight line. As a factor that has the potential to alter an object's condition, the law defines force and mentions it.In this way, Newton uses the inertia of rest, motion, and direction to describe his first law of motion.A body has an attribute called inertia that makes it resist changes to its state. A body's inertia of translational motion is measured by its mass.

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A student examines the effect of the number of D batteries in a closed circuit on the brightness of a light bulb. In the experiment, four circuits were built with 1, 2, 3, and 4 batteries respectively. For each trial, the brightness of the light bulb was measured using a light meter. Which variable should the student keep constant?

Answers

Answer: The type of batteries

Explanation: Your testing the brightness of the bulb nothing has anything to do with the batteries

How did he show that these particles had a charge on them?

Answers

J.J. Thomson discovered electrons and their negative charge through the cathode ray experiment, leading to the development of the plum pudding model of the atom.

J.J. Thomson, a British physicist, was the first to discover electrons in 1897.

He conducted the cathode ray experiment to identify the negatively charged particles.

The cathode ray tube is a vacuum-sealed glass tube with two electrodes at each end: a cathode and an anode.

When a high voltage electrical current is applied to the electrodes, the tube glows, indicating that the cathode rays are being emitted from the cathode and traveling through the tube towards the anode.

The cathode rays were found to have a negative charge, according to Thomson.

These rays were identified as particles by the presence of a magnet, which caused the particles to bend in the direction opposite to the magnet's polarity.

This discovery indicated that the particles had a charge on them because they were deflected by the magnetic field, which is only possible if the particles have an electric charge.

Thomson further concluded that these particles were about 1,000 times smaller than hydrogen atoms because of the degree of deflection they experienced in the magnetic field.

Furthermore, Thomson created the plum pudding model of an atom, in which electrons are dispersed throughout a positively charged matrix, based on his findings.

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pH of a buffer solution prepared from 0.155 mol of phosphoric acid, 0.250 mole of KH2PO4, and enough water to make 0.500 L of solution.

Answers

The pH of the buffer solution would be 7.11.

pH calculation

Phosphoric acid, H3PO4, can donate three protons (H+) in a stepwise manner to form dihydrogen phosphate (H2PO4-) and mono hydrogen phosphate (HPO4^2-) ions. The chemical equation for the reaction is as follows:

H3PO4 + H2O ⇌ H2PO4^- + H3O^+

H2PO4^- + H2O ⇌ HPO4^2- + H3O^+

HPO4^2- + H2O ⇌ PO4^3- + H3O^+

The pKa values for these reactions are 2.15, 7.20, and 12.35, respectively.

To prepare a buffer solution, we need to mix a weak acid and its conjugate base or a weak base and its conjugate acid. In this case, we have a mixture of H3PO4 and KH2PO4, which is a weak acid and its conjugate base, respectively.

The Henderson-Hasselbalch equation for a buffer solution is:

pH = pKa + log([base]/[acid])

where [base] and [acid] are the molar concentrations of the conjugate base and weak acid, respectively.

Using the given values:

[acid] = 0.155 mol / 0.500 L = 0.310 M (molarity of H3PO4)

[base] = 0.250 mol / 0.500 L = 0.500 M (molarity of KH2PO4)

We can calculate the pKa value for the first dissociation of H3PO4 using the given Ka value:

Ka = 10^(-pKa) = 7.52 x 10^(-3)

pKa = -log(Ka) = 2.12

Now, substitute the values into the Henderson-Hasselbalch equation:

pH = 2.12 + log(0.500/0.310)

pH = 7.11

Therefore, the pH of the buffer solution is approximately 7.11.

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Question 8 of 25
Which element is a nonmetal?
A. Li
B. Re
C. Se
D. Sr
SUBMIT

Answers

d. sr explanation i did it on plato

O
Aqueous magnesium nitrate
Mg(NO3)2(aq)
sodium
phosphate
Na3PO4(aq)
Write the balanced molecular equation, including phases, for the reaction of aqueous sodium phosphate with aqueous
magnesium nitrate.

Answers

The balanced molecular equation for the reaction of magnesium nitrate, Mg(NO₃)₂ and sodium phosphate, Na₃PO₄ is:

3Mg(NO₃)₂(aq) + 2Na₃PO₄(aq) → 6NaNO₃(aq) + Mg₃(PO₄)₂(s)

How do i write the balanced equation?

The balanced molecular equation for the reaction of magnesium nitrate, Mg(NO₃)₂ and sodium phosphate, Na₃PO₄ can be written as illustrated below:

Mg(NO₃)₂(aq) + Na₃PO₄(aq) → NaNO₃(aq) + Mg₃(PO₄)₂(s)

There is 1 atom of Mg on the left side and 3 atoms on the right. It can be balanced by writing 3 before Mg(NO₃)₂ as shown below:

3Mg(NO₃)₂(aq) + Na₃PO₄(aq) → NaNO₃(aq) + Mg₃(PO₄)₂(s)

There is 1 atom of P on the left side and 2 atoms on the right. It can be balanced by writing 2 before Na₃PO₄ as shown below:

3Mg(NO₃)₂(aq)  + 2Na₃PO₄(aq) → NaNO₃(aq) + Mg₃(PO₄)₂(s)

There are a total of 6 atom of Na on the left side and 1 atom on the right. It can be balanced by writing 6 before NaNO₃ as shown below:

3Mg(NO₃)₂(aq) + 2Na₃PO₄(aq) → 6NaNO₃(aq) + Mg₃(PO₄)₂(s)

Now, the equation is balanced.

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