What is the equation of this line

The variable "The number of obtained heads when a fair coin is tossed 20 times" is not a continuous variable because it is a discrete variable.

Hence the correct answer is option D.

The variable is a discrete variable and not continuous because it can only take on a finite number of values, namely, integers ranging from 0 to 20. It cannot take on any values in between, and it is not possible to have fractions or decimals of heads obtained in a single coin toss.

In contrast, the other three variables - height of NBA players, time of a flight between Atlanta and Chicago, and average temperature in the month of July in Orlando - are all continuous variables. They can take on any value within a certain range or interval, and can be expressed as a fraction or a decimal value.

The height of NBA players can take on any value between the minimum and maximum height of players in the league, while the flight time and average temperature can vary within a certain range of possible values.

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The weight distribution of newborn African lions may not necessarily follow a normal distribution, and the actual percentages can vary based on the specific data available.

To determine the percentage of newborn African lions that weigh less than 3 pounds and the percentage that weigh more than 3.8 pounds, we would need statistical data on the weight distribution of newborn African lions. Since we don't have that information, we cannot provide the exact percentages.

However, if we assume that the weights of newborn African lions follow a normal distribution, we can use the properties of the standard normal distribution to make an estimation.

For the percentage of newborn African lions weighing less than 3 pounds:

We would need to know the mean and standard deviation of the weight distribution to calculate the Z-score for a weight of 3 pounds and then find the corresponding percentage using a standard normal distribution table. Without this information, we cannot provide an accurate estimation.

For the percentage of newborn African lions weighing more than 3.8 pounds:

Similarly, we would need the mean and standard deviation of the weight distribution to calculate the Z-score for a weight of 3.8 pounds and find the corresponding percentage using a standard normal distribution table. Without the required information, we cannot provide a specific estimation.

Please note that the weight distribution of newborn African lions may not necessarily follow a normal distribution, and the actual percentages can vary based on the specific data available.

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Answer:

20 apples every 1 tree

Step-by-step explanation:

first, we need to find the constant!!

(constant means what you use to multiply in every equation)

so we do  100 apples divided by 5 trees!

the answer will be 20 apples and we know that we need to find how much PER ONE TREE

so, 1 tree = 20 apples !

Answer:

The second blank is 20 apples for every trees

Step-by-step explanation:

Sorry I didn't know the first blank...Hope this helps anyways!

Answer:

|−2x+7|=25 x=-2, 16

3|x+1|−1=11 x=3, -5

Step-by-step explanation:

The linear system shown is "inconsistent" in nature.

A linear equation is an equation that has the variable of the highest power of 1. The standard form of a linear equation is of the form Ax + B = 0.

The given figure is represented linear system represents two parallel lines.

Now, the solution set of the two system of equations could be find by finding their points of intersection.

And when the lines do not intersect then it is said the linear system of the two lines do not have any solution.

Now, we have been given two parallel lines and parallel lines never intersect each other. thus the solution set of both the system of equations represented by these parallel lines is an empty set.

And when the system of linear equation has no solution , then the system is said to be inconsistent.

Hence, The linear system shown is "inconsistent" in nature.

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The complete question is;

The linear system shown is _____.

independent

equivalent

inconsistent

The second deal is better and the unit rate of the better deal is;

⇒ $39 per gram.

What is Division method?

Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications.

For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.

Given that;

The pair of better deal are,

⇒ $224 for 7 g

⇒ $324 for 9 g

Now,

First deal is,

⇒ $224 for 7 g

So, For 1 gram = $224 / 7

                      = $32

And, Second deal is;

⇒ $324 for 9 g

So, For 1 gram = $324 / 7

                      = $39

Thus, The second deal is better and the unit rate of the better deal is;

⇒ $39 per gram.

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The (∃E) rule is used to infer P(0) from ∀xP(x), and this conclusion is supported by the existence of an object that satisfies the predicate.

The rule of natural deduction that justifies P(0) from ∀xP(x) is the existential elimination (∃E) rule. This rule allows us to infer a particular instance of an existential quantification based on the existence of an object that satisfies the predicate. In this case, since we have the universal quantification ∀xP(x), we can use (∃E) to conclude P(0) by substituting 0 for x. By doing so, we have shown that there exists an object, namely 0, that satisfies the predicate P(x). Therefore, (∃E) justifies the statement P(0) from the given universal quantification.

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Answer:

x = 14.97

Step-by-step explanation:

a= 10 c=18

1. plug variables in for pythagorean theorem.

\(a^2+b^2=c^2\)→\(10^2+b^2=18^2\)

2.solve for b from pythagorean theorem.

\(10^2+b^2=18^2\)→\(100+b^2=324\)

                          -100         -100

\(b^2=224\)→\(b=\sqrt{224}\)

b = 14.9666295.....

3. Round variable b to the nearest hundreth assuming they expect that and change the variable to x since we were actually looking for x.

b=14.9666....→ b(estimated)= 14.97

x(estimated)=14.97

Answer:

To find the percent increase between the average low and high temperatures in July, we need to calculate the difference between the average high and low temperatures and then divide that difference by the average low temperature. Finally, we multiply the result by 100 to get the percentage increase.

The difference between the average high and low temperatures is:

90°F - 69°F = 21°F

To find the percentage increase, we need to divide the difference by the average low temperature and multiply by 100:

Percentage increase = (21°F / 69°F) × 100%

≈ 30.4%

Therefore, the percent of increase between the average low and high temperatures in July is approximately 30.4%, rounded to the tenths place.

Answer:

Step-by-step explanation:

you are going to give more info ?????

The term is called an identity element. In multiplication, the identity element is one because any number multiplied by one results in the same number. In addition, the identity element is zero because any number added to zero results in the same number.

The term in mathematics for the operation or number that leaves others unchanged when combined with them is called the identity element.

It is also known by the name of neutral element.

In multiplication, the identity element is one (1) because when you multiply a number by one the result remains the same as the original number. For any number a,

a1=1a=a.

While in addition, the identity element is zero (0) because when you add zero to a number, the result remains the same as the original number. For any number a,

a+0=0+a=a.

There is no identity element for subtraction, and division only has an identity element for certain sets.

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The number of franchises predicted for 15 years from now is 24. To determine the number of franchises predicted for 15 years from now, we need to solve the given differential equation.

The equation dn =\(\frac{9}{t+1}\) dt represents the rate at which the number of franchises (dn) is changing with respect to time (dt). Integrating both sides of the equation gives us the equation n = 9 ln(t+1) + C, where C is the constant of integration.

Given that there is one franchise at present (t = 0), we can substitute n = 1 and solve for C. Plugging in the values, we get 1 = 9 ln(0+1) + C, which simplifies to C = 1 - 9 ln(1) = 1.

Now, to find the number of franchises predicted for 15 years from now (t = 15), we substitute t = 15 into the equation n = 9 ln(t+1) + C. Plugging in the values, we get n = 9 ln(15+1) + 1, which simplifies to n = 24. Therefore, the predicted number of franchises for 15 years from now is 24.

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Answer:

D

Step-by-step explanation:

hope it helps

Answer:

Step-by-step explanation:

Babe u here

Yes, it is greater than the portion of the students who walk to school.

Percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100.

Percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%".

Percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100. It is given by:

Percentage = (value / total value) * 100%

Students who walk = 18%

18% of 50 = (18/100) x 50

Students who walk = 9

While the students who live within the 1/2 mile of the school = 11

We can deduce that 11 is greater than 9.

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The comparison results are as follows -

A function is a relation between a independent variable and a dependent variable such that the value of dependent variable depends upon the independent one. For example -

f(x) = 4x + 5

h(x) = 7x + 9

Given are two functions such f(x) and g(x).

The y - intercept is a point on the y - axis where the graph of the function cuts the y - axis. It can be seen that the y - intercept[c] of f(x) has a positive value as it is above the origin and that of g(x) has a negative value. Therefore, f(x) has greater y - intercept than that of g(x). Mathematically -   c[f(x)] > c[g(x)]

A relative minimum point is a point where the function changes direction from decreasing to increasing. The relative minimum point of f(x) has the coordinates (0.8, - 1.5) and that of g(x) is (-1, -2.25). Therefore, g(x) has lesser relative minimum value as -2.25 < -1.5.

Therefore -

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According to the information we can infer that Dora's conclusion may be incorrect because the information provided only states that the number of people who spent time reading falls within specific ranges (0-2 hours, 2-4 hours, and 2-10 hours), but it does not give a specific count for those who spent at least 4 hours. Therefore, Dora's assumption that "most people spent at least 4 hours a week reading" is not supported by the given data.

The range of the time spent reading cannot be determined from the information provided because the ranges are overlapping. For example, a person who spent exactly 2 hours reading could fall into both the first range (0-2 hours) and the second range (2-4 hours). Without more specific data or non-overlapping ranges, it is not possible to determine the exact range of time spent reading.

To estimate the mean time spent reading by Dora's friends, we can calculate the midpoint of each range and use it as an approximate value. The midpoint for the first range (0-2 hours) is 1 hour, for the second range (2-4 hours) is 3 hours, and for the third range (2-10 hours) is 6 hours. We can then calculate the estimated mean by taking the weighted average of these midpoints using the respective number of people as weights.

Estimated mean = [(4 * 1) + (5 * 3) + (11 * 6)] / (4 + 5 + 11) = 4.53 hours (approximately)

So, an estimate of the mean time spent reading by Dora's friends is approximately 4.53 hours.

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Answer:

Step-by-step explanation:

approximately 7.29

Answer:

\( {x}^{2} + {8.5}^{2} = {11.2}^{2} \)

\( {x}^{2} + 72.25 = 125.44\)

\( {x}^{2} = 53.19 = \frac{5319}{100} \)\( x = \frac{3 \sqrt{591} }{10} = about \: 7.3 \)

A. Inference procedures for paired data are used because the measurements are not independent; each child is measured under both conditions (low GI and high GI), so there is a natural pairing between the two sets of observations.

B. The symbol for the point estimate for the true mean of the differences in calorie intake for the children (high GI - low GI) is x (sample mean), and the value of the point estimate is 63.543 calories.

A. Inference procedures for paired data are necessary because the measurements in this study are not independent of each other. Each child in the sample is subjected to both conditions (low GI and high GI breakfasts), and their calorie intake is measured under each condition.

B. The symbol for the point estimate for the true mean of the differences in calorie intake for the children (high GI - low GI) is x, which represents the sample mean. In this case, the calculated value for x is 63.543 calories. This means that, on average, the calorie intake after a high GI breakfast was 63.543 calories higher than the calorie intake after a low GI breakfast, based on the observed data from the sample.

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Using the critical values of t=+/-2.201 is less likely to lead to rejection of the null hypothesis than using the critical values of +/-2.093.

Critical Value Definition -

Using the critical values of t=±2.201 is more "conservative" than using the critical value of ±2.093 because it is more likely to reject the null hypothesis using the greater value i-e t=±2.201.

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Answer: no

Step-by-step explanation: if we'd substitute the numbers, it'd look like this 10≤-10+7  which isn't true  as "≤" this symbol means more than or equals to but -10 plus 7 is equal to 3 so it doesn't fit the inequality

To find the probability that the difference between the numbers chosen by Jenn and Bela is at least 2, we need to consider the number of possible outcomes and the number of favorable outcomes.

- Jenn can choose any number from 1 to 20, giving us a total of 20 possible choices.
- Bela can choose any number from the remaining 19 numbers, as it needs to be distinct from Jenn's choice. This gives us 19 possible choices for Bela.
- To ensure that the difference between the chosen numbers is at least 2, we need to exclude cases where Bela chooses a number that is adjacent to Jenn's choice. For example, if Jenn chooses 5, Bela cannot choose 4 or 6.

To calculate the number of favorable outcomes, we subtract the number of unfavorable outcomes from the total number of outcomes:
- There are 19 numbers that Bela can choose from (excluding the number chosen by Jenn).
- Out of these 19 choices, there are 2 adjacent numbers to Jenn's choice (the number before and the number after).
- So, the number of unfavorable outcomes is 2.

Therefore, the number of favorable outcomes is 19 - 2 = 17.

The probability that the difference between the numbers chosen by Jenn and Bela is at least 2 is given by the ratio of the number of favorable outcomes to the total number of outcomes.
- The total number of outcomes is 20 * 19 = 380.
- The probability is therefore 17/380.

So, the answer in the form m/n is 17/380.

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Answer:

To solve the inequality |h + 3| < 5, we need to consider two cases, depending on whether the expression inside the absolute value bars is positive or negative:

Case 1: h + 3 >= 0

If h + 3 >= 0, then we can remove the absolute value bars without changing the inequality:

h + 3 < 5

Subtracting 3 from both sides, we get:

h < 2

So the solution for this case is h < 2.

Case 2: h + 3 < 0

If h + 3 < 0, then the inequality becomes:

-(h + 3) < 5

Multiplying both sides by -1 (and reversing the inequality), we get:

h + 3 > -5

Subtracting 3 from both sides, we get:

h > -8

So the solution for this case is h > -8.

Putting these two solutions together, we have:

-8 < h < 2

Therefore, the solution set in set-builder notation is:

{h | -8 < h < 2}

The Laplace transform of the given function is,

L{f(t)} = (8/s) - 4e^{-3s/2}/s - 6e^{-2s}/s

Given function is f(t) = {8 12 1 Jo, 0 ≤ t < 3/2, 3/2 ≤ t < 2, 2 ≤ t < ∞ respectively.

We have to find Laplace transform of the given function.

For first interval 0 ≤ t < 3/2,

f(t) = 8u(t) - 8u(t-3/2)

For second interval 3/2 ≤ t < 2,

f(t) = 12u(t-3/2) - 12u(t-2)

For third interval 2 ≤ t < ∞,

f(t) = Jo(u(t-2))

Hence, we can write the Laplace transform of the given function as,

L{f(t)} = L{8u(t) - 8u(t-3/2)} + L{12u(t-3/2) - 12u(t-2)} + L{Jo(u(t-2))}

Where, L is Laplace transform.

Let's calculate each Laplace transform stepwise,

1. L{8u(t) - 8u(t-3/2)}L{8u(t)} = 8/L{u(t)}L{u(t)}

= 1/sL{u(t-3/2)}

= e^{-3s/2}/s

Therefore,

L{8u(t) - 8u(t-3/2)} = 8[1/s - e^{-3s/2}/s]

2. L{12u(t-3/2) - 12u(t-2)}L{12u(t-3/2)}

= 12e^{-3s/2}/sL{12u(t-2)}

= 12e^{-2s}/s

Therefore,

L{12u(t-3/2) - 12u(t-2)} = 12[e^{-3s/2}/s - e^{-2s}/s]

3. L{Jo(u(t-2))}L{Jo(u(t-2))} = ∫_{0}^{∞}δ(t-2)e^{-st}dtL{Jo(u(t-2))}

= e^{-2s}

Hence, the Laplace transform of the given function is,

L{f(t)} = 8[1/s - e^{-3s/2}/s] + 12[e^{-3s/2}/s - e^{-2s}/s] + e^{-2s}

= (8/s) - 4e^{-3s/2}/s - 6e^{-2s}/s

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Answer:

17260

Step-by-step explanation:

multiply 14400 by 20%

After that add 14400 and 2880together

and you got the answer

Answer:

The original price would be $17,280

Step-by-step explanation:

14,400× 0.2= 2,880

14,400+ 2,880= 17,280

Answer:100

Step-by-step explanation:

Because

The day the two bags will have the same weight is the 24th day.

The linear equation that can be used to determine the pound of dog food left is:

Amount of dog food left = capacity of the bag - (number of days x amount the dog eats per day)

Amount of dog food left = 34 - (1 x p)

Amount of dog food left = 34 - 1p

The linear equation that can be used to determine the pound of cat food left is:

Amount of cat food left = capacity of the bag - (number of days x amount the cat eats per day)

Amount of cat food left = 16 - (1/4 x p)

Amount of cat food left = 16 - 1/4p

On the day the two bags will have the same weight, the two above equations would be equal:

16 - 1/4p = 34 - 1p

p - 1/4p = 34 - 16

3/4p = 18

p = (18 x 4) / 3

p = 24 days

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please give brainliest

Answer:

To shift the graph of the function f(x) = cos(x) downward by 2.5 units, you can subtract 2.5 from the function. The equation of the middle for the shifted function would be:

f(x) = cos(x) - 2.5

Answer:

y=-2.5

Step-by-step explanation:

f(x) =0 -2.5

y=-2.5

Hope this helped buddy

peace ️

The solution to the given first-order linear differential equation is \(y(x) = \frac{1}{x^3+1} \left( x^3 + \frac{3}{10} e^{-x^3} \sin(x) + \frac{7}{10} \cos(x) \right)\).

The first-order linear differential equation \(y'+3x^2y=\sin(x)e^{-x^3}\) with the initial condition \(y(0)=1\), we can use the method of integrating factors. The integrating factor is given by \(I(x)=e^{\int 3x^2 dx}=e^{x^3}\).

Multiplying both sides of the differential equation by the integrating factor, we have \(e^{x^3}y'+3x^2e^{x^3}y=e^{x^3}\sin(x)e^{-x^3}\). Simplifying the equation, we get \((e^{x^3}y)'=\sin(x)\).

Integrating both sides with respect to \(x\), we obtain \(e^{x^3}y=\int \sin(x)dx=-\cos(x)+C\), where \(C\) is the constant of integration.

Dividing both sides by \(e^{x^3}\), we have \(y(x)=\frac{-\cos(x)+C}{e^{x^3}}\).

Using the initial condition \(y(0)=1\), we substitute \(x=0\) and \(y=1\) into the equation to solve for \(C\). This gives us \(C=1\).

Therefore, the solution to the differential equation is \(y(x)=\frac{-\cos(x)+1}{e^{x^3}}\).

Simplifying further, we have \(y(x)=\frac{1}{x^3+1}\left(x^3+\frac{3}{10}e^{-x^3}\sin(x)+\frac{7}{10}\cos(x)\right)\).

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Answer:

These are the answers

Step-by-step explanation:

The orbit of a planet is an ellipse, with the Sun at one of the two foci.

A line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time.

The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit.

Hope it helped !

Answer:

The universal law of gravitation states that every particle attracts every other particle in the universe with a force that is directly proportional to the ...

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