What is the net electric force on the charge located at the lower right-hand corner of the triangle.

To know more about the effects of doubling the radius of a wheel and solve the given problem:

When the radius of a wheel is doubled, the answers to the given questions are affected in the following ways:

The angular speed at 2.00 s is smaller: False. Doubling the radius does not directly affect the angular speed at a specific time. It depends on the angular acceleration and initial conditions.

The angle rotated through from t = 0 to t = 2.00 s is the same: True. The angle rotated depends on the angular speed and time, which are not directly affected by the radius.

The angular speed at t = 2.00 s is greater: False. The angular speed is not affected by doubling the radius, assuming the angular acceleration remains constant.

The angular speed at t = 2.00 s is the same: True. Doubling the radius does not directly impact the angular speed at a specific time, assuming other factors remain constant.

The angle rotated through from t = 0 to t = 2.00 s is greater: False. The angle rotated depends on the angular speed and time, which are not directly influenced by the radius.

The angle rotated through from t = 0 to t = 2.00 s is smaller: False. The angle rotated depends on the angular speed and time, which are not directly affected by the radius.

Now, let's solve the provided problem. We are given that the wheel has a constant angular acceleration of 3.40 rad/s² and an angular speed of 1.70 rad/s at t = 0.

(a) To find the angle rotated between t = 0 and t = 2.00 s, we can use the equation: θ = ω₀t + (1/2)αt², where ω₀ is the initial angular speed, α is the angular acceleration, and t is the time. Substituting the given values, we get θ = (1.70 rad/s)(2.00 s) + (1/2)(3.40 rad/s²)(2.00 s)². Evaluating this expression gives us the angle rotated in radians.

(b) To find the angular speed at t = 2.00 s, we can use the equation: ω = ω₀ + αt. Substituting the given values, we get ω = 1.70 rad/s + (3.40 rad/s²)(2.00 s).

(c) To find the angular displacement in revolutions when the angular speed doubles, we need to find the angular speed when t = 2.00 s and then double that value.

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Answer:

Having begun as a "science of mental life", psychology evolved in the 1920's into the "scientific study of observable behavior". ... Today's science emphasizes the interaction of genes and experiences in specific environment

Answer:

Psychology continues to develop over the years all the way up to today by new and better scientific like science emphasizes. Also new experiences in specifics enviroment.

Explanation:

Hope it helped :)

A neutron star is as dense as The Nucleus of an Atom . Option C is correct.

The collapsing core of a large supergiant star with a total mass of between 10 and 25 solar masses—possibly even more if the star was very metal-rich—is what we refer to as a neutron star. Neutron stars are the tiniest and densest class of stellar objects currently known, with the exception of black holes and other hypothetical phenomena.

When a big star runs out of fuel and collapses, neutron stars are created. The core of the star, which is its most central portion, collapses, fusing every proton and electron into a neutron.

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Answer:

Boiling a kettle is an example of both thermal and kinetic energy. Thermal energy comes from a substance whose molecules and atoms are vibrating faster due to a rise in temperature. Heat energy is another name for thermal energy. Kinetic energy is the energy of a moving object.

it's kinetic!

Explanation:

formation of compounds because the electric forces compel the atoms to attract each other and formed bonds which leads to the formation of chemical compounds. The attractive or repulsive interaction between any two charged bodies is known as an electric force so the attraction between two opposite charged atoms causes the formation of compounds so we can conclude that electric forces are important for the formation of compounds.

Centripetal force on the end of a 66.0 m (radius) wind turbine blade that is rotating is calculated as = 1.23 *10^-4 N.

Centripetal force is the force acting on the object in curvilinear motion directed towards axis of rotation or the center of curvature and the unit of centripetal force is newton. It is directed perpendicular to the direction of the displacement of the object.

Given, radius= 66m mass is 3.4 kg

Given 0.47 rev/s

Angular velocity = 0.47 * 2π / 60

= 0.049 m/s

Centripetal force = mass * velocity²/radius

= 3.4 *  0.049² /66

Centripetal force= 1.23 *10^-4 N

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Answer:

Work Definition in Chemistry

Work Definition . Work is the energy required to move an object against a force. ...

Mechanical Work . Mechanical work is the type of work most commonly dealt with in physicsand chemistry. ...

PV Work . Another common type of work is pressure-volume work. ...

Sign Convention for Work . Work performed by the system on the surroundings has a negativesign. ...

Explanation:

The circumference of the circular path is C = d = (4) = 12.57 feet. To find the distance traveled by the object in 1 hour, multiply the circumference with the number of revolutions per hour to find the distance traveled in miles = 16602.4/5280 = 3.14 miles. The linear velocity of the object is 3.14 miles/hour.

The circumference of the circular path is given by, C = πd = π(4) = 12.57 feet [∵d = 4 feet]To find the distance traveled by the object in 1 hour, we need to multiply the circumference with the number of revolutions per hour. The distance traveled by the object in 1 hour = 12.57 × 1320 = 16602.4 feet [∵the object makes 1,320 revolutions per hour]Now, we need to find the distance traveled by the object in miles. We know that 1 mile = 5,280 feet. So, the distance traveled by the object in miles = 16602.4/5280 = 3.14 miles (approx) The linear velocity of the object in miles per hour = Distance/Time So, we need to find the time taken by the object to cover the distance of 3.14 miles. We know that the time taken is 1 hour. So, the linear velocity of the object = 3.14 miles/hour (approx)Therefore, the linear velocity of the object, in miles per hour, is approximately 3.14 miles/hour.

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Answer:

A

Explanation:

Answer:

If the person rises 12 ft per revolution that person will

rise 18 ft in 1 and 1/2 revolutions

E = m g h = W h          where W is the weight of the person

E = 149 lb * 18 ft = 2682 ft-lbs

The force acting on the body by its weight is 656.6 N. The displacement for him is 2.4 m. Then the work done is 1595.5 J.

Work done is a physical quantity describing the force acted over a displacement. It is the dot product of force and displacement.

Given that, the weight of the person = 149 lb

1 lb = 0.45 kg

149 lb = 149 × 0.45 = 67 kg.

weight in Newton = 67 kg × 9.8 m/s² = 656.6 N

The displacement he made = 12 ft - 4 ft = 8 ft

1 ft = 0.3 m

then 8 ft = 8 × 0.3 = 2.4 m

Now, work done W = f. ds

W = 2.4 m × 656.6 N = 1595.5 J

Therefore, the work done by the person weighing 149 lb walking exactly one and a half revolution(s) up a circular, spiral staircase of radius 4 ft if the person rises 12 ft after one revolution is 1595.5 J.

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Answer:  By multiplying mass by velocity

Explanation:  By multiplying mass by velocity

Answer:

IF SHE BREATHS SHES A T.H.OT

Explanation:

Pls dont hate me its meme k ,_.

Answer:

it have to be a

Explanation:

The type of investigation is she is conducting by determining the period in which it is from is referred to as the geologic age.

This is defined as the time period in which the fossil was present on the earth and can be done using various methods such as radiometric dating methods etc. The age gotten will help scientists to ascertain different information about the organism in this context.

Fossil on the other hand which is the remains of organisms preserved in the earth crust can be studied to find out the differences in the features of organisms and how they were able to adapt to the changing environmental conditions.

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Answer:

Acceleration of one cyclist=\(2.67m/s^2\)

Yes, the acceleration is higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds.

Explanation:

We are given that

Initial velocity of one cyclist, u=0 m/s

Final velocity of one cyclist, v=8m/s

Time, t=3 s

Initial velocity of another cyclist, u'=0

Final velocity of another cyclist, v'=30m/s

Time, t'=8 s

We know that

Acceleration, \(a=\frac{v-u}{t}\)

Using the formula

\(a=\frac{8-0}{3}=\frac{8}{3}=2.67m/s^2\)

Acceleration of one cyclist=\(2.67m/s^2\)

Acceleration of another cyclist, a'=\(\frac{30-0}{8}m/s^2\)

Acceleration of another cyclist, a'=\(3.75m/s^2\)

Yes, the acceleration of another cyclist is higher than the cyclist which accelerates from 0m/s to 8m/s.

Answer:

The mass of object is 300g.

Its weight on earth is W×0.3kg×9.8m/s2=2.94 N

Its weight on moon is A 300 g would be 48 g on the moon

GOOD LUCK!

Answer:

6 seconds?

Explanation:

I'm gonna guess but it might be

0 - 1 and 3 - 4.5

The correct options are:

All cathode-ray particles had the same mass to charge ratio.

The cathode-ray particle behaved identically regardless of the metal used to make it.

The discovery of subatomic particles was a major milestone in the development of modern physics, and the cathode-ray experiments played a significant role in this discovery. The cathode-ray experiments were conducted in the late 19th century by scientists such as J.J. Thomson, who demonstrated that cathode rays were composed of negatively charged particles that were much smaller than atoms. This discovery led to the development of the first subatomic particle model of the atom, in which electrons orbit a positively charged nucleus.

The lines of evidence that supported the hypothesis that the cathode-ray was a subatomic particle were crucial in demonstrating the existence of these tiny particles. The fact that all cathode-ray particles had the same mass-to-charge ratio suggested that they were a fundamental particle rather than a complex mixture of atoms. Similarly, the fact that the cathode-ray particle behaved identically regardless of the metal used to make it supported the hypothesis that the particle was a fundamental constituent of matter.

Overall, the cathode-ray experiments provided important insights into the nature of matter and paved the way for further discoveries in subatomic physics. They demonstrated that the atom was not the smallest particle of matter and helped to establish the idea of subatomic particles as the building blocks of matter.

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Answer:

a

Explanation:

kinematical equations are only valid for motion with constant acceleration (uniformly accelerated motion).

Hopefully this answer helped you!!!

The moment about a of the force exerted by the cable at b if the tension in the cable is 406 Ib is (2400j + 1440k) Ib -ft.

Write the coordinates of each point as follows:

A = (0i,0j,0k)

B= (12i,0j, 0k)

C = (0i, 4.8j,-8k)

Calculate the position vector of B with respect to A.

rAB= B - A

rAB =(12i,0j, 0k ) - ( 0i,0j,0k)

=(12i)ft

Calculate the position vector of cable C with respect to B.

rBC=C - B

rBC = (0i, 4.8j,-8k) - (12i,0j, 0k)

= (-12i+4.8j -8k) ft

Calculate the magnitude of BC.

IBCl = √(-12)^2 + (4.8)^2 +(-8)^2

=15.2 ft

Calculate the unit vector of C with respect to C.

unit vector of C with respect to C (Ucc) = rBC / IBCl

=(-12i+4.8j -8k) / 15.2

Represent the force BC in vector from.

TBC= TBC (Ucc)

TBC= (380 (-12i+4.8j -8k) )/ 15.2 lb

Calculate the moment about A.

MA = rAB x TBC

MA = (12i) x (380 (-12i+4.8j -8k) / 15.2

= (300i) x (-12i + 4.8j - 8k )

= 1440k - (-2400j)

MA= (2400j + 1440k ) lb -ft

Therefore, The moment about a of the force exerted by the cable at b = (2400j + 1440k) Ib -ft.

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Answer:

-10 m/s²

Explanation:

a = Δv / Δt

a = (20 m/s − 50 m/s) / 3 s

a = -10 m/s²

Answer 10 m/s²

Explanation:

a = Δv / Δt

a = (20 m/s − 50 m/s) / 3 s

a = -10 m/s²

Explanation:

The orientation of the compass needle  suggests that the magnetic field lines point away from the north pole of a magnet and toward its south pole.

If you place a compass near the north pole of a magnet, the north pole of the compass needle will be repelled and point away from the magnet.

This is because a compass needle is made of a magnet, and the needle is always pointing to the geographic north of Earth.

So when a compass is brought near a magnet, the needle will be attracted if it is in direct contact with the south pole of the magnet and it will be repelled if it is in direct contact with the north pole of the magnet.

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A client reports general malaise and has a temperature is 103.8°F (39.9°C). What is the rationale for administering a prescribed aspirin, an antipyretic, to this client

step-by-step explanation:

Step 1: A client reports general malaise and has a temperature of 103.8°F (39.9°C).

Step 2: The high temperature is an indication that the body is fighting an infection or inflammation.

Step 3: Antipyretics, such as aspirin, work by blocking the production of certain chemicals in the body that cause fever.

Step 4: Lowering the body temperature can help alleviate the discomfort associated with fever and reduce the risk of complications, such as seizures or dehydration.

Step 5: Aspirin is a commonly prescribed antipyretic that can be effective in reducing fever.

Step 6: The rationale for administering a prescribed aspirin, an antipyretic, to this client is to lower the body temperature and alleviate the discomfort associated with fever.

Step 7: It is important to follow the prescribed dosage and instructions for aspirin to avoid potential side effects or interactions with other medications.

Step 8: If the fever persists or worsens, it is important to seek medical attention to determine the underlying cause and ensure appropriate treatment.

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A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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Answer:

e

Explanation:e

Both of the boys have equal potential energy when they reach the first floor.

The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.

Let, the mass of two boys be m.

Height of the first floor be h.

Then, the potential energy of boy A at first floor: E₁ = mass × acceleration due to gravity × height = mgh.

And the potential energy of boy B at first floor: E₂ = mass × acceleration due to gravity × height = mgh.

Hence,  E₁ = E₂ =  mgh.

So, potential energies of both boy A and boy B are same in magnitude.

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(a) When the current flows horizontally toward the east, the magnitude of the magnetic force is approximately 9078 N, and the direction is upward at 90° from the horizontal. (b) When the current flows horizontally toward the south, the magnitude of the magnetic force is 0 N, and there is no specific direction associated with it.

To find the direction and magnitude of the magnetic force exerted on the wire, we can use the equation:

F = |B| * I * L * sin(θ)

where:

F is the magnetic force,

|B| is the magnitude of the magnetic field,

I is the current,

L is the length of the wire, and

θ is the angle between the current and the magnetic field.

Given:

Current, I = 110 A

Magnitude of the magnetic field, |B| = 0.39 G

Length of the wire, L = 210 m

(a) When the current flows horizontally toward the east:

θ = 90° (since the wire is perpendicular to the magnetic field)

Plugging in the values:

F = (0.39 G) * (110 A) * (210 m) * sin(90°)

F = (0.39 G) * (110 A) * (210 m) * 1

F ≈ 9078 N

The magnitude of the magnetic force is approximately 9078 N.

The direction of the magnetic force is perpendicular to both the current and the magnetic field. Since the wire is horizontal and the magnetic field points north (downward at 72° below horizontal), the magnetic force acts vertically upward.

Therefore, the direction of the magnetic force is upward, and the angle is 90°.

(b) When the current flows horizontally toward the south:

θ = 180° (since the current and the magnetic field are parallel and in opposite directions)

Plugging in the values:

F = (0.39 G) * (110 A) * (210 m) * sin(180°)

F = (0.39 G) * (110 A) * (210 m) * 0

F = 0

The magnitude of the magnetic force is 0 N.

Since the magnetic force is zero, there is no direction associated with it.

Therefore, the magnitude of the magnetic force when the current flows horizontally toward the south is 0 N, and there is no specific direction.

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The dog MUST be SEEN by a vet.

Not on the phone, not from your description. Not a web search, and not asking for advice online.

A qualified veterinarian has to have his hands on the animal, examine the dog, and make some suggestions. It might cost some money.

There's something missing here. A qualified real vet will never just say "I don't know, good bye!".

a) Two other forces that act on thee sled are the weight of the daughter and the drag force

b) The drag force slows down the sled while the weight presses it down.

We know that motion is the result of the action of unbalanced forces. From the Newton's third law, we know that if the forces that are acting on an object are balanced that the object is not going to move from its state of rest.

In this case, we are told that a  father pushes his daughter and son on a sled down a hill. The fact that the led is moving is due to the fact that there are forces that are acting on the sled.

The forces that are acting on the sled apart  from the force that was applied in pushing the sled is the drag force and the weight of the son.

The drag force would determine how fast that the sled would move because it acts in opposition to the forward force and tries to slow down the sled as it is moving. The weight of the son does press the sled downwards.

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