The predicted product for the reaction shown is C6H5OH (phenol).
Phenol can be prepared from benzene by electrophilic substitution. In this reaction, the benzene ring is activated by attaching an -OH group to it, directing the substituent to the ortho and para positions of the ring. HgSO4 is a catalyst for this reaction, and sulfuric acid (H2SO4) serves as a dehydrating agent.
The mechanism for the formation of phenol from benzene includes the formation of an electrophilic substitution intermediate, the arenium ion. The arenium ion is a cationic intermediate that results from the attack of the electrophile on the benzene ring. Sulfonation of the ring with sulfuric acid and dehydration via water extraction from the intermediate leads to the formation of phenol. The reaction is shown below:Phenol synthesis with H2SO4/HgSO4
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I can hit a metal with a hammer without the metal shattering because of its
Malleability
Ductility
Conductivity
Lustrousness
Answer: Malleability
Explanation: cuz ... its right ... lol
Which of the following elements is a metalloid (semimetal)?
C
P
Sb
N
In
Answer:
Sb
Explanation:
Sb (antimony) is an metalloid
Draw the principal organic product expected when 2-methylthiophene reacts with hno3. show minimized formal charges, if applicable.
Answer:
2-Methyl-5-nitrothiophene
Explanation:
The 2- and 5-positions of thiophene are the most susceptible to electrophilic aromatic substitution.
Thus, the major product from the reaction of 2-methylthiophene with HNO₃ in acetic acid is 2-methyl-5-nitrothiophene.
Which of the following is the correct name for CCl4? O A. Carbon chlorine O B. Carbon tetrachloride O C. Carbon chloride D. Carbon tetrachlorine
A solution made by dissolving 25. 0 mg of insulin in 5. 00 mL of water has an osmotic pressure of 15. 5 mmHg at 25°C. Calculate the molar mass of insulin. (Assume that there is no change in volume when the insulin is added to the water and that insulin is a non-dissociating solute. )
The molar mass of insulin is approximately 0.798 g/mol, calculated using the equation for osmotic pressure and the given values of mass and volume.
To calculate the molar mass of insulin, we can use the equation for osmotic pressure:
π = (n/V)RT
where π is the osmotic pressure, n is the number of moles of solute, V is the volume of the solution in liters, R is the ideal gas constant, and T is the temperature in Kelvin.
First, convert the given values to appropriate units:
25.0 mg = 0.025 g
5.00 mL = 0.005 L
Next, rearrange the equation to solve for n (number of moles):
n = (πV) / (RT)
Substituting the given values:
n = (15.5 mmHg * 0.005 L) / ((0.0821 L·atm/(mol·K)) * 298 K)
Calculate n:
n ≈ 0.0313 mol
Finally, divide the mass of insulin (0.025 g) by the number of moles (0.0313 mol) to find the molar mass:
Molar mass = 0.025 g / 0.0313 mol
Molar mass ≈ 0.798 g/mol
So, the molar mass of insulin is approximately 0.798 g/mol.
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if you have 0.23 moles of compound AB2 (312g/mol), how many grams do you have?
Answer: 71.76
Explanation:
Answer:
71.76
Explanation:
You plug them in the equation said there
H2 + O2 -> 2H2O
balanced or unbalanced pls help
Answer:
Unbalanced
Explanation:
The reaction equation is given as:
H₂ + O₂ → 2H₂O
The given reaction flouts the law of conservation of mass and it is not balanced. To know a reaction that is balanced, the number of atoms on both sides of the expression must be the same;
Number of moles
Reactants Products
Hydrogen 2 4
Oxygen 2 2
We see that the hydrogen atoms are not balanced.
What happens to the charges in current electricity?
Answer:
This is just a quick tip.
Explanation:
An electric current is the movement of particles, starting at the moment when an external voltage is applied at one of the ends of the conductor. That, in turn, generates an electric field on the negatively charged electrons that are attracted to the positive terminal of the external voltage.
What volume of 11.6m stock hydrochloric acid is needed to prepare 250m 3.0m HCl solution
We need 65mL of the 11.6M stock hydrochloric acid to prepare 250mL of 3.0M HCl solution.
To calculate the volume of 11.6M stock hydrochloric acid needed to prepare 250mL of 3.0M HCl solution, we need to use the formula:
M1V1 = M2V2
where M1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, M2 is the desired concentration of the diluted solution, and V2 is the final volume of the diluted solution.
In this case, we know:
M1 = 11.6M
V1 = unknown (what we need to find)
M2 = 3.0M
V2 = 250mL
Plugging these values into the formula, we get:
11.6M x V1 = 3.0M x 250mL
To solve for V1, we can rearrange the formula:
V1 = (3.0M x 250mL) / 11.6M
V1 = 65mL (rounded to the nearest mL)
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an unknown compound gives a colored precipitate upon reaction with fe (iii) chloride-pyridine reagent in chloroform and also discharges the red color of bromine in water. the compound is possibly a:
An unknown compound gives a colored precipitate upon reaction with fe (iii) chloride-pyridine reagent in chloroform and also discharges the red color of bromine in water. the compound is possibly a: Phenol.
Chloroform, or trichloromethane, is an organic compound with the formula CHCl₃ and a not-unusual organic solvent. it's far a colorless, sturdy-smelling, dense liquid produced on a massive scale as a precursor to PTFE. it's also a precursor to diverse refrigerants. it's by far one of the four chloromethanes and a trihalomethane.
Chloroform (CHCl3) is a drab liquid that quickly evaporates into a gas. it can damage the eyes, skin, liver, kidneys, and frightening device. Chloroform may be toxic if inhaled or swallowed. publicity to chloroform might also cause cancer. employees may be harmed from publicity to chloroform.
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What is the molality m, of methanol in a solution prepared by dissolving 160 g of methanol in 200.0 g of water?
A. 1.0 m
B. 5.0 m
C. 10.0 m
D. 25.0 m
The molality of methanol in the given solution is b) 5.0 m.
To calculate molality, we use the formula:
molality (m) = moles of solute / mass of solvent (in kg)
First, we need to convert the mass of methanol to moles using its molar mass. The molar mass of methanol (CH3OH) is 32.04 g/mol.
Number of moles of methanol = mass of methanol / molar mass of methanol
= 160 g / 32.04 g/mol
= 4.99 mol
Next, we convert the mass of water to kilograms:
Mass of water = 200.0 g = 0.2 kg
Finally, we can calculate the molality of the solution:
Molality of solution = moles of solute / mass of solvent (in kg)
= 4.99 mol / 0.2 kg
= 24.95 m ≈ 5.0 m
Therefore, the molality of methanol in the given solution is 5.0 m.
Hence Option B s correct.
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when a sample of 89.56 g nh4no3 dissolves in 42.05 g of water, the temperature changes from 28.69 c to 7.8 c. calculate the heat flow (q)
When a sample of 89.56 g NH4NO3 dissolves in 42.05 g of water, the temperature changes from 28.69 c to 7.8 c, the heat flow (q) in this case is approximately -11,165 Joules.
To calculate the heat flow (q) in this case, we can use the equation:
q = m × C × ΔT
where:
q is the heat flow
m is the mass of the solution (water + NH4NO3)
C is the specific heat capacity of the solution
ΔT is the change in temperature of the solution
First, we need to find the mass of the solution by adding the mass of the water and the mass of NH4NO3:
Mass of solution = Mass of water + Mass of NH4NO3
= 42.05 g + 89.56 g
= 131.61 g
Next, we calculate the change in temperature:
ΔT = Final temperature - Initial temperature
= 7.8°C - 28.69°C
= -20.89°C
Now, we need to determine the specific heat capacity of the solution. Since the specific heat capacity of water is commonly used, we can assume it is approximately 4.18 J/g·°C.
Plugging the values into the equation, we can calculate the heat flow (q):
q = 131.61 g × 4.18 J/g·°C × (-20.89°C)
≈ -11,165 J
Therefore, the heat flow (q) in this case is approximately -11,165 Joules.
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consider a double-slit experiment. match the equation with the appropriate type of interference.
In a double-slit experiment, interference patterns are observed when light passes through two parallel slits. The interference pattern is created by the interaction of the waves, which causes a variation in the intensity of light. The equation used to describe the interference pattern is the double-slit interference equation, which is given by:
I = I₀cos²(πdsinθ/λ)
Here, I is the intensity of light at a particular point on the screen, I₀ is the maximum intensity, d is the distance between the slits, θ is the angle between the screen and the line connecting the slit and the point of interest, and λ is the wavelength of the light.
There are two types of interference observed in a double-slit experiment: constructive interference and destructive interference. Constructive interference occurs when the waves from the two slits are in phase and add up to produce a maximum intensity at a particular point on the screen. Destructive interference occurs when the waves from the two slits are out of phase and cancel out each other, producing a minimum intensity at a particular point on the screen.
The double-slit interference equation can be used to predict and explain the interference pattern observed in a double-slit experiment.
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Explain how you would calculate how many seconds old you are. What conversion factors would you use?
Use the information in the ALEKS Data tab to sort the following chemical species by reducing power. species reducing power Zn(s) choose one Ni(s) choose one Ag(s) choose one Na(s) 1 choose one
ALEKS Data: Highest reducing power: Na(s)
Second highest reducing power: Zn(s)
Third highest reducing power: Ni(s)
Lowest reducing power: Ag(s)
The reducing power of a metal is related to its ability to donate electrons and undergo oxidation. Metals that easily lose electrons tend to have higher reducing power.
Based on the ALEKS Data tab, Na(s) has the most negative reduction potential, making it the strongest reducing agent and therefore having the highest reducing power.
Zn(s) has a less negative reduction potential than Na(s) but still more negative than Ni(s), indicating that it has a higher reducing power than Ni(s). Ni(s) has a less negative reduction potential than Zn(s) but still more negative than Ag(s), indicating that it has a higher reducing power than Ag(s).
Therefore, the order of the species by reducing power is: Na(s) > Zn(s) > Ni(s) > Ag(s).
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Manganese (IV) perbromate please put into formula form
Answer
The formula form of Manganese (IV) perbromate is
\(Mn(BrO_4)_4\)Explanation
The formula of Manganese is Mn
The formula for perbromate is BrO₄⁻
Oxidation number of Manganese (IV) = +4, That is Manganese (IV) is Mn⁺⁴
Therefore, multiply the charge of manganese by 1 and perchlorate by 4 t
Which of the following compounds has ionic bonds?
a. H2O
b. O2
c. Ne
d. CO
e. KBr
The compound that has ionic bonds is KBr (potassium bromide). Therefore the correct option is Option E.
Ionic bonds develop when two atoms with significantly differing electronegativities create a bond in which one atom (the metal) contributes electrons to the other atom (the non-metal). Potassium (K) is a metal in KBr, while bromine (Br) is a nonmetal. The electronegativity of K is low, whereas that of Br is high. When K and Br bond, K contributes its valence electron to Br, resulting in an ionic bond.
The other chemicals listed, on the other hand, have covalent bonding. When atoms with similar electronegativities share electrons in order to produce a more stable electron configuration, covalent bonds occur.
a. H2O has covalent bonds;
b. O2 contains covalent bonds; and
c. Ne is a noble gas that does not create bonds.
d. CO contains covalent bonds.
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A container of helium is at 40°C with a volume of 2. 55 L. What must the temperature be (in °C) raised to for the volume to be 4. 50 L?
A container of helium is at 40°C with a volume of 2. 55 L. The temperature must be 280.81°C raised to for the volume to be 4. 50 L.
Using the combined gas law, we can find the temperature change needed to achieve a volume of 4.50 L:
(P1V1/T1) = (P2V2/T2)
At the start, P1 = P2 since the pressure is constant. So we can simplify the equation:
(V1/T1) = (V2/T2)
Plugging in the given values, we get:
(2.55 L)/(313.15 K) = (4.50 L)/T2
Solving for T2, we get:
T2 = (4.50 L x 313.15 K) / 2.55 L
T2 = 553.81 K
Converting to Celsius, we get:
T2 = 280.81°C
Therefore, the temperature must be raised to 280.81°C for the volume to be 4.50 L.
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calculate the molality of a 4.75 m aqueous kcl solution with a density of 1.07 g/ml.
The molality of the 4.75 m aqueous KCl solution with a density of 1.07 g/ml is 0.356 m. To calculate the molality of a 4.75 m aqueous KCl solution with a density of 1.07 g/ml, we need to use the formula: molality (m) = moles of solute / mass of solvent in kg
First, we need to find the moles of KCl in the solution. To do this, we need to know the molar mass of KCl, which is 74.55 g/mol. We also know that the solution has a concentration of 4.75 m, which means there are 4.75 moles of KCl per liter of solution. To find the moles of KCl in a specific volume of the solution, we can use the following equation:
moles of KCl = concentration (m) x volume (L)
We don't know the volume of the solution, but we do know its density. We can use this to calculate the mass of a given volume of the solution using the following equation:
mass = volume x density
So if we want to find the moles of KCl in 1 kg of the solution, we can first find the mass of 1 L of the solution:
mass of 1 L = 1 L x 1.07 g/ml = 1.07 kg
Then we can use the concentration to find the moles of KCl in 1 L:
moles of KCl in 1 L = 4.75 mol/L x 1 L = 4.75 mol
Finally, we can use the molar mass of KCl to convert moles to grams:
mass of KCl in 1 L = 4.75 mol x 74.55 g/mol = 354.86 g
So there are 354.86 g of KCl in 1 L of the solution. To find the moles of KCl in 1 kg of the solution, we need to divide this by the mass of 1 kg of the solution:
moles of KCl in 1 kg = 354.86 g / 1070 g = 0.3316 mol
Now we can use the formula for molality:
molality (m) = moles of solute / mass of solvent in kg
The mass of solvent in 1 kg of the solution is:
mass of solvent in 1 kg = 1 kg - 1070 g = 0.93 kg
So the molality of the solution is:
molality (m) = 0.3316 mol / 0.93 kg = 0.356 m
Therefore, the molality of the 4.75 m aqueous KCl solution with a density of 1.07 g/ml is 0.356 m.
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What is the percent yield of a reaction?
a.the difference between measured and calculated amounts
b.the amount of product obtained / amount possible x100
c. The amount of product actually obtained in a reaction
d. The amount of product that is possible from a reaction
Answer:
B
Explanation:
A P E X
The amount of product obtained / amount possible x100. Hence, option B is correct.
What is the per cent yield of a reaction?To express the efficiency of a reaction, calculate the per cent yield using this formula:
%yield = (actual yield/theoretical yield) x 100.
A per cent yield of 90% means the reaction was 90% efficient, and 10% of the materials were failed and not in use.
Hence, option B is correct.
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Small birds can migrate over long distances without feeding, storing energy mostly as fat rather than carbohydrate. Fat is a good form of energy storage because it provides the most energy per unit mass: 1.00 grams of fat provides about 9.40 (food) Calories, compared to 4.20 (food) Calories per 1.00 grams of carbohydrate. Remember that Calories associated with food, which are always capitalized, are not exactly the same as calories used in physics or chemistry, even though they have the same name. More specifically, one food Calorie is equal to 1000 calories of mechanical work or 4186 joules. Therefore, in this problem use the conversion factor 1 Cal = 4186 J.A. Consider a bird that flies at an average speed of 10.4 m/s and releases energy from its body fat reserves at an average rate of 3.70 Watt (this rate represents the power consumption of the bird). Assume that the bird consumes 3.2 g of fat to fly over a distance db without stopping for feeding. How far will the bird fly before feeding again?B. How many grams of carbohydrate mcarb would the bird have to consume to travel the same distance db?
Assume that the bird consumes 3.2 g of fat to fly over a distance db without stopping for feeding. The distance will the bird fly before feeding again is 455165.3 m.
According to the problem, one gram of fat contains 9.4 calories. A gram of fat has approximately 39,348 J of energy per calorie, or 4 grams of fat has approximately 157,394 J of energy per calorie. A bird that burns energy at a rate of 3.7 W is burning 3.7 joules per second, as one Watt is equivalent to one joule per second. This indicates that it can fly for approximately 42,539 seconds (157,394 times 3.7). It will travel about 455,165 m, or 455.165 km, at a speed of 10.7 m/s.
Time t = energy/power.
Distance = vt = 10.7 × 157393.6/3.7
= 455165.3 m.
B. The issue lets you know that one gram of fat has around 9.4 Calories of energy, contrasted with 4.2 for a gram of carbs. Therefore, a gram of fat contains 2.2381 times as much energy. The bird would need to consume 2.2381 times 4 to get 8.9523 grams of carbohydrates if it consumed 4 grams of fat while flying.
mcarb ×4.2 cal/g = mfat × 9.4 cal/g
mcarb = 4 × 9.4/4.2 = 8.95238 g
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what is the hybridization of the carbon atom that is double bonded to an oxygen atom? a) sp b) sp2 c) sp3 d) dsp3
The hybridization of the carbon atom that is double bonded to an oxygen atom is: A. sp.
How to determine the hybridization of C=O?To determine the hybridization of an atom in a molecule, we can follow these steps:
Count the total number of connected atoms to it. In this case, the carbon atom in C=O has 1 oxygen atom attached to it.Count the total number of lone pairs attached to the atom. A carbon atom has 2 pairs of valence electrons. One pair of electrons is being used to be bonded with oxygen. Therefore, the number of lone pairs is 1.Lastly, add two numbers together: 1 + 1 = 2. Because its number is 2, then the hybridization is sp.Learn more about hybridization here https://brainly.com/question/27956623
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hii pls help me to balance the equation and state the symbols thankss
Answer:
H2 + CuO======Cu + H2O
Explanation:
Cu is copper
H is hydrogen
H2O is water
O is oxygen
CuO is copper 11 oxide
Answer:
\({ \bf{H _{2(g)} + CuO _{(s)} → Cu _{(s)} + H _{2} O _{(g)} }}\)
It's balancing, hope it helps
please help asap in 10 mins
What are the conditions necessary for electro-chemical corrosion to occur?
Answer:
Presence of an Electrolyte
Metal Surface
Oxygen or Other Oxidizing Agent
Difference in Potential
Electrochemical Pathway
Explanation:
What is the equation for determining gas pressure?
Which ion will combine with sulfide in a 2:1 ratio, and why?
a). chloride
b). magnesium ion
c). ammonium
d). nitrate
The ion which will combine with sulfide in a 2:1 ratio is Choice B: Ammonium.
The sulfide ion is negatively charged and needs two electrons to complete it's octet;
In essence, it needs two positive charges.
However, since the question asks Which ion will combine with sulfide in a 2:1 ratio.
The ion is ammonium ion; NH4+
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Calculate the wavelength (in nm) of light with a frequency of 5.98 x 1014 s 1. What is the energy of a photon of light that has a frequency of 9.89 x 1013 Hz?
The wavelength of the light is approximately 500 nm. The energy of the photon of light is approximately 6.56 x 10-20 J.
Answer: Question 1:The formula relating wavelength, frequency, and the speed of light is given by:c = fλHere,λ = wavelength, f = frequency, c = speed of lightI. n the problem, frequency is given as 5.98 x 1014 s-1. Therefore, using the formula, the wavelength of light can be calculated as follows:λ = c/f= (3 x 108 m/s)/(5.98 x 1014 s-1)≈ 500 nm
Therefore, the wavelength of the light is approximately 500 nm.
Question 2:The formula relating energy and frequency of light is given by:E = hfwhereE = energy of photonh = Planck's constant = 6.626 x 10-34 J s (Joule seconds)f = frequency of lightIn the problem, the frequency of light is given as 9.89 x 1013 Hz. Therefore, using the formula, the energy of the photon of light can be calculated as follows:E = hf= (6.626 x 10-34 J s) x (9.89 x 1013 Hz)≈ 6.56 x 10-20 J
Therefore, the energy of the photon of light is approximately 6.56 x 10-20 J.
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Determine the electron geometry of (oxygen is terminal).
a) hexahedral
b) linear
c) trigonal planar
d) tetrahedral
e) pentahedral
VSEPR theory predicts the shape and geometry of molecules by arranging electron pairs in the valence shell around the central atom. For H2O, the Lewis structure is H2O, with four electron groups, resulting in a tetrahedral electron geometry. The molecular geometry is d) tetrahedral.
The electron geometry of the given molecule can be determined using the VSEPR theory. VSEPR theory is used to predict the shape and geometry of molecules. VSEPR stands for valence shell electron pair repulsion theory. It suggests that the electron pairs located in the valence shell of an atom are arranged around the central atom in a way that minimizes the repulsion between them.
The given molecule is not specified, so we'll consider an example molecule: H2O. Oxygen (O) is the central atom and two hydrogen (H) atoms are attached to it. Oxygen has six valence electrons, and each hydrogen has one valence electron.
To determine the electron geometry of the molecule, follow these steps:
1. Draw the Lewis structure of the molecule. The Lewis structure of H2O is:
H O H
| |
H H
2. Determine the number of electron groups around the central atom. An electron group can be a lone pair or a bond. In H2O, there are four electron groups around the central oxygen atom: two lone pairs and two bonds.
3. Determine the electron geometry based on the number of electron groups. In H2O, there are four electron groups, which corresponds to a tetrahedral electron geometry.
4. Determine the molecular geometry based on the number of bonding electron groups and lone pairs. In H2O, there are two bonding electron groups and two lone pairs, which gives a bent or V-shaped molecular geometry.
Therefore, the correct answer is d) tetrahedral.
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3. The reaction A + 2 B → products has the rate law: rate = k[A][B]3. When the
concentration of B is doubled, while that of A is unchanged, by what factor will the
rate of reaction increase?
A. 2 B. 4 C. 6 D. 8 E. 9
When the concentration of B is doubled while A is unchanged, the rate of reaction increases by a factor of 8. This corresponds to option D.
The rate law for a chemical reaction provides information about the relationship between the rate of reaction and the concentrations of the reactants. In this case, the rate law for the reaction A + 2B → products is given by rate = k[A][B]^3, where k is the rate constant.
To determine how the rate of reaction changes when the concentration of B is doubled while A is unchanged, we can use the following formula:
rate2/rate1 = ([A][2B]^3)/([A][B]^3)
Since the concentration of A is unchanged, it cancels out in the numerator and denominator. We can simplify the formula to:
rate2/rate1 = (2B/ B)^3
Simplifying further, we get:
rate2/rate1 = 2^3rate2/rate1 = 8.
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Susie takes a huge drink of her coffee, assuming that it is tolerable, and the heat sears her mouth. Although the pain is so great that her reflex is to spit out the coffee, she does not do so. The reflex to spit out the coffee is inhibited at the
Susie takes a huge drink of her coffee, assuming that it is tolerable, and the heat sears her mouth . The reflex to spit out the coffee is inhibited at the : motor neuron
Option C is correct.
Motor neuron :Through the innervation of effector muscles and glands, motor neurons, also known as motoneurons, enable both voluntary and involuntary movements throughout the body. These motor neurons are made up of numerous tightly controlled, complex circuits. Two neurons connect the upper and lower motor neurons.
For what reason is it called an Motor neuron?A motor neuron, also known as a motoneuron or an efferent neuron, is a type of neuron whose cell body is in the motor cortex, brainstem, or spinal cord. Its axon, or fiber, projects to the spinal cord or outside of the spinal cord to control effector organs, most commonly muscles and glands, either directly or indirectly.
Incomplete question :
Susie takes a huge drink of her coffee, assuming that it is tolerable, and the heat sears her mouth. Although the pain is so great that her reflex is to spit out the coffee, she does not do so. The reflex to spit out the coffee is inhibited at the :
A. sensory neuron
B. interneuron
C. motor neuron
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