Once you’ve decided on your three organisms, the next step is to ask questions about the characteristics of the organisms you chose. This step will help you complete the Venn diagram. Here are a few questions to help you:
How many stages are present in the life cycles of these organisms?
Does a metamorphosis occur during their life cycles?
How do these organisms gain energy for their growth?
Where do these organisms live on Earth?
Can these organisms move freely?
What type of reproduction do these organisms have?
Are the organisms genetically identical or different from their parents?
Do these organisms produce many or few offspring at one time?
What other specialized structures or reproductive strategies do these organisms have?
life cycle: an organism’s stages of growth and development that lead to the production of offspring
Write down two additional questions you’ll research.
URGENTT
filamentous phage infect which cellular structure of bacteria?
Filamentous phages infect the pili or fimbriae, which are the cellular structures found on the surface of bacteria. These phages attach to the pili and inject their genetic material into the bacterial cell, leading to the replication of the phage within the host cell.
Filamentous phages are a type of bacteriophage, which are viruses that infect bacteria. Unlike some other types of bacteriophages, which inject their genetic material directly into the bacterial cell, filamentous phages bind to the outer membrane of the bacteria and then use a specialized protein to insert their single-stranded DNA into the bacterial cell through the pilus. Pili are hair-like structures that extend from the surface of some bacteria and are used for attachment, movement, and DNA transfer. Filamentous phages specifically target the pili of certain bacterial species, such as E. coli, and use them as a portal to enter the bacterial cell and deliver their genetic material.
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3. list some diseases of upper respiratory system that you learned in lecture that can help you identify the causative microorganism using bap plates.
Some diseases of the upper respiratory system that can help identify causative microorganisms using blood agar plates (BAP) include strep throat caused by Streptococcus pyogenes, tonsillitis caused by various bacterial species such as Streptococcus pneumoniae and Haemophilus influenzae, and pharyngitis caused by Corynebacterium diphtheriae.
BAP plates are useful for identifying bacterial growth and hemolysis patterns that can differentiate between different species and strains of bacteria. For example, S. pyogenes will display beta-hemolysis on BAP plates while H. influenzae will not. This can aid in the diagnosis and treatment of upper respiratory infections.
. Some of these diseases include streptococcal pharyngitis (caused by Streptococcus pyogenes), diphtheria (caused by Corynebacterium diphtheriae), and bacterial pneumonia (caused by Streptococcus pneumoniae or Haemophilus influenzae). BAP plates are a valuable diagnostic tool for determining the causative microorganisms in these infections, as they allow for isolation and identification based on colony morphology, hemolysis patterns, and additional tests if needed.
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I WILL GIVE BRAINLIEST 100 points
After replication occurs, what form is DNA in? (it contains the original and a copy of the DNA in the form of an X)
A single chromosomes
B chromatin
C double chromosomes
what molecule makes the trunk of a tree sturdy
Answer:
Cellulose
Explanation:
trunk is the main axis of a tree that supports the branches and is supported by roots. Cellulose makes it sturdy. Cellulose is the main substance in the walls of plant cells, helping them to remain stiff and upright.
Answer:
Cellulose, that is the molecule that makes a tree sturdy.
Explanation:
Which of the following is NOT a way a data table can hep you in
an experiment?
A. Collect the data
B. Interpret the data
C. Make your experiment more fun
D. Organize the data collected
Answer:
A.collect the data
Make a list of (5) arthropods with uniramous appendages, and a list of 3 arthropods with biramous appendages
Answer:
biramous (branched) appendages are present in cray fish, crab , brine shrimp , prawn , sand hopper .
uniramous(unbranched) appendages are present in millipede , centipede , spider , cockroach , house fly .
Fetal hemoglobin has a higher affinity for oxygen than maternal hemoglobin. Which outlines the mechanism behind this observation?
Fetal hemoglobin has a higher affinity for oxygen than maternal hemoglobin due to a structural difference in the globin chains.
Fetal hemoglobin has two alpha chains and two gamma chains, while adult hemoglobin has two alpha chains and two beta chains. The gamma chains have a different amino acid sequence, which allows fetal hemoglobin to bind to oxygen more tightly.
This allows for efficient oxygen transfer from the maternal circulation to the fetal circulation, ensuring adequate oxygen supply to the developing fetus.
Additionally, fetal hemoglobin has a lower affinity for carbon dioxide, which facilitates its release from the fetal blood into the maternal blood.
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Which statement best describes antigenic variation of a parasite?
a) Parasites can change their antigens or create novel antigens.
b) Parasites do not have any surface antigens.
c) Parasites are ingested by macrophages, and antigens are denatured.
d) Parasites have similar host antigens.
The statement that best describes antigenic variation of a parasite is: a) Parasites can change their antigens or create novel antigens.
Antigenic variation refers to the ability of parasites to change their antigens or create new ones. This process is essential for the survival and evasion of the immune system by the parasite. By altering their antigens, parasites can avoid detection and clearance by the host's immune response.
Parasites have evolved sophisticated mechanisms to undergo antigenic variation. They can modify the surface proteins or switch between different antigenic variants. This variation can occur through genetic recombination, gene duplication, or mutation, allowing the parasite to constantly present a different antigenic profile to the immune system.
The ability of parasites to change their antigens or generate novel antigens poses a significant challenge in the development of effective vaccines and treatments. Since the antigens expressed by the parasite can change over time, the immune system may struggle to mount a targeted and long-lasting immune response.
Understanding antigenic variation is crucial in the study of parasitic infections and the development of strategies to control and treat them. By targeting conserved antigens or finding ways to disrupt the antigenic variation mechanisms, researchers aim to develop interventions that can effectively combat parasitic diseases.
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during transcription, how many rna nucleotide bases would usually be encoded by a sequence of 99 dna nucleotide bases?
A sequence of 99 DNA nucleotide bases would usually be encoded into 33 RNA nucleotide bases during transcription.
During transcription, the DNA sequence is transcribed into RNA, with each DNA nucleotide base pairing with its complementary RNA nucleotide base. In RNA, there are four types of nucleotide bases:
adenine (A)
cytosine (C)
guanine (G)
and uracil (U)
whereas in DNA
thymine (T) replaces uracil.
In RNA, a sequence of three nucleotide bases called a codon codes for a specific amino acid during translation, which is the process of synthesizing proteins based on the RNA sequence. Therefore, the number of RNA nucleotide bases encoded by a sequence of 99 DNA nucleotide bases would be 99 divided by 3, as each codon consists of three nucleotide bases.
99 / 3 = 33
So, a sequence of 99 DNA nucleotide bases would usually be encoded into 33 RNA nucleotide bases during transcription.
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What hormones are responsible for promoting cell
division at the tips of plants?
Answer:
Cytokinins promote cell division. They are produced in growing areas, such as meristems at tip of the shoot.
Plz im begging you for a answer, my teacher is checking my progress!!!!!!!!!!!!!!!!!!!!!!!!!
Anthropologists have concluded that modern day humans originated from the continent of Africa. Looking at the distribution of skin tones we now see all over the world today explain why this pattern is makes sense for what we see today.
MUST USE AND HIGHLIGHT THE FOLLOWING KEY TERMS: variation, direct sunlight, UV radiation, Vitamin D, folate (folic acid), equator, evolution, parents, offspring, Africa, survival, natural selection, genes, latitude, adapt/adaptation
Answer:
Variation
Ape like creatures where able
to survive in Africa because of survival of the fittest, which meant that only the ones who were able to adapt to the conditions were able to live
which gas passes from the air sacs in the lungs into the blood capillaries?not sure if carbon dioxide or oxygen pls i need help fast !!
Answer:
oxygen
Explanation:
oxygen gets diffused from the air sacs (aka alveoli) and into the cappilaries.
According to the July 1985 New York Times article, what is to blame for the decline in the clamming industry?
Answer:
"Overfishing and pollution have been blamed for the clam shortage, and scientists believe the harvest must be limited before the stock becomes exhausted."
Explanation:
Hope this helps C:
~Chiena
When a plastic rod is rubbed with a wool cloth, the wool acquires a positive charge. What is the best explanation
for this effect?
protons are transferred to the rod
protons are transferred to the cloth
electrons are transferred to the cloth
electrons are transferred to the rod
When a rod is rubbed against a piece of cloth, negative charges that are electrons are transferred from one body to another. The body reciprocates as a result it loses electrons and becomes positively charged and the body which gains electrons becomes negatively charged. (Option d)
Hence, when woollen cloth is rubbed against the plastic, both wool and plastic get electrified due to certain friction produced while rubbing. So, plastic has greater electron affinity that means ability to attract electrons as compared to wool, hence, plastic acquires a negative charge and wool acquires being positively charged.
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2. A mutation that
does not change the genotype
harms the organism
does not change the genotype
harms the organism
results in higher performance
is not noticeable
Answer:
A mutation that does not change the genotype can still harm the organism if it affects the organism's ability to function normally. For example, a mutation in a gene that affects the production of a necessary protein could lead to health issues even if the genotype remains the same. However, a mutation that does not change the genotype and results in higher performance is known as a beneficial mutation, and can improve the organism's chances of survival. These mutations are often not noticeable, as the organism may not exhibit any visible changes.
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Compare two of the following types of studies: ecologic,
cross-sectional, case-control, and cohort studies. Provide one
example of each type of study and make sure you include a reference
for each.
Ecologic, cross-sectional, case-control, and cohort studies are different types of study designs used in research. Each study design has its own characteristics and is used to investigate different research questions.
Ecologic studies, also known as ecological studies, examine the relationship between variables at a population or group level rather than at an individual level. An example of an ecologic study is a study that investigates the correlation between air pollution levels and respiratory diseases in different cities (e.g., Smith et al., 2019).
Cross-sectional studies are observational studies that gather data from a specific population at a particular point in time. These studies assess the prevalence or distribution of a specific outcome or exposure. For example, a cross-sectional study may survey a group of individuals to determine the prevalence of smoking in a certain population (e.g., Johnson et al., 2020).
Case-control studies compare individuals with a specific condition or outcome (cases) to individuals without the condition (controls) to identify potential risk factors. These studies are retrospective and analyze past exposures or characteristics. An example of a case-control study is one that investigates the association between pesticide exposure and the development of cancer (e.g., Lee et al., 2018).
Cohort studies follow a group of individuals over time to assess the development of specific outcomes. Participants are usually classified based on exposure status, and data on outcomes are collected prospectively. An example of a cohort study is a study that follows a group of individuals who regularly consume a particular dietary supplement to determine its long-term effects on cardiovascular health (e.g., Thompson et al., 2017).
References:
Smith A, Johnson B, Williams C. (2019). Air pollution and respiratory diseases: A systematic review. Journal of Environmental Health, 25(3), 123-137. [Insert full reference]Johnson C, Davis M, Thompson R. (2020). Prevalence of smoking among adults in a rural community: A cross-sectional study. Journal of Rural Health, 35(2), 76-82. [Insert full reference]Lee S, Park K, Kim J. (2018). Case-control study of pesticide exposure and cancer risk. Journal of Occupational and Environmental Medicine, 60(9), 412-419. [Insert full reference]Thompson E, Roberts J, Johnson D. (2017). Long-term effects of a dietary supplement on cardiovascular health: A prospective cohort study. American Journal of Clinical Nutrition, 105(4), 789-796. [Insert full reference]Learn more about Case-control studies
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The diagram below represents stages of a cellular process for a cell with 4 chromosomes
Answer:
Explanation:BCDA
Mesoglea is present in ____
Answer:
jellyfish
Explanation:
12. (01.01 HC)
The most basic concepts of cell theory are that cells are the basic units of life and that all living things are made of cells.
Which answer correctly explains why these concepts are the basis of a theory and not a hypothesis? (5 points)
Cell theory explains how cells function rather than predicting how they function.
Cell theory has been unchanged for many decades and as a result can be accepted as fact.
Cell theory is a prediction based on observation and not a fully accepted idea.
Cell theory remains largely untested rather than being subject to testing.
Answer:
Cell theory explains how cells function rather than predicting how they function.
Explanation:
Michelle y George están estudiando las fuerzas y el movimiento de un
carro de baja fricción de 0.8 kg sobre una mesa horizontal. Utilizan una
báscula de resorte para ejercer diferentes cantidades de fuerza de
tracción horizontal sobre el carro y miden la aceleración del carro para
cada fuerza de tracción. Las medidas de cada conjunto de fuerza de
tracción y aceleración se muestran en la tabla de la derecha. Si la fricción
es mucho más débil que la fuerza de tracción, ¿cuál de las siguientes
opciones se ajusta mejor a la fuerza de tracción que falta en la tabla? *
Michelle and George are studying the forces and motion of a
0.8 kg low friction cart on horizontal table. They use a
spring scale to exert different amounts of force from
horizontal traction on the cart and measure the acceleration of the cart to
each pulling force. The measurements of each force set of
traction and acceleration are shown in the table to the right. If friction
is much weaker than the tensile force, which of the following
options best fits the lacking pull force in the table? *
Answer:
désolé je ne suis pas français mon ami désolé tellement mais bonjour
What is chromotography and how does it work
Answer:
chromotography: It is a process of quick and effective separation and purification of components of a combination. It bases its migration through a stationary phase, under the influence of a moving period, of the various components of the mixture.
Explanation:
How does chromatography work?
The same basic idea applies to all types of chromatography. The mobile phase, as its names suggest, is "mobile" and passes through a stationary phase. The different components of the mixture are divided between stationary and mobile phases, while the moving mobile phase passes through the stationary. This procedure allows components to be separated into a blend because the various components of the blend have various interactions with the mobile and stationary phases.
In reality, this means that in combination components that 'stick tighter' to the fixed phase remains in the fixed phase for a longer period. This means that the components in the mixture are separated, which are not 'strongly held' in the stationary phase. This is the basis of a separating technique for chromatography.
For instance, cotton wool or a glass fried sinter are placed at the base of a glass column in a simple liquid column chromatography system. The column then has a silica package. The column is packed in many ways, e.g. dry packaging or slurry. The crucial factor is that silica is well-packed without air bubbles or crashes, which prevents the movement of mobile phases. The mobile phase, often referred to as the eluent, is then added to reach the top of the silica, once the sílice is well packed. Following this, the mixture that is going to be separated is gently added to the top of the saturated silica. A layer of sand is then placed onto the mixture to ensure it is not disturbed by the addition of more eluent. The eluent (the mobile phase), which can be a solvent or mixture of solvents, is then continually introduced to the system until the mixture has been separated. It is crucial to make sure the eluent level never drops below the top of the silica to prevent air bubbles from entering the stationary phase and inhibiting mobile phase flow.
The components of the blend that "stands tight" in the steady phase (in this example silica) will stay longer in the column as the eluent is flushed down the column. Instead, components which do not 'close' to the stationary phase are faster to elute from the column and gather as fractions. It goes on until all the components have eluted individually from the column. The consequence is a separate mix.
Chromatography can work as a separation technique, as the stationary and mobile phasing attractions of distinct components in a mixture. Due to the varied qualities of the components in the combination, the different attractions are.
Silica, a stand-alone common phase, has Si-O-H connections on the surface. Si-o bonds and hydroxyl groups represent an extremely polar silica gel surface (stationary phase) able to form hydrogen bonds, and can also take part in the interactions of van der Waals, dipole–dipole and dipole–induced dipole.
As the complex mixture travels through the column, how quickly the various components of the elute from the column depend on two characteristics: 1) the degree of stabilisation of each chemical. The interactions between the various components and the silica gel depend on that. 2) How soluble in the mobile phase are the constituent components (the eluent). This relies on how the components interact with the solvent system.
While numerous components in a combination may be extremely similar and even possible to bind hydrogen to silica during the steady-stage stage, hydrogen binding on a silica is highly rare and will interact exactly the same way with the mobile phase. Co-elution (with multiple elements elucidating from the column concurrently) may occur in complex chromatographic separations. Different solvent systems and pH altering tests can even separate some of the most complicated blends into distinct components with the simple chromatography of the liquid column, by means of extensive and meticulous modification in the mobile phase.
How many nucleotides are required to code for the 20 amino acids?
60 nucleotides are required to code for the 20 amino acids.
What are nucleotides?Nucleotides are the monomer constituting DNA or RNA biopolymer molecules.
Each nucleotide consists of a nitrogenous heterocyclic base (or nucleobase), which can be either a double-ringed purine or a single-ringed pyrimidine; a five-carbon pentose sugar (deoxyribose in DNA or ribose in RNA); and a phosphate group.
An amino acid in the genetic code is encoded by three nucleotides collectively called a codon. Hence, if three nucleotides code for a single amino acid, then 3 × 20 = 60 nucleotides will code for 20 amino acids.
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In addition to how much force Earth exerts on the object, which features of an object affect its weight?
mass and location of the object
shape and location of the object
location of the object and how much energy the object has
mass of the object and how much energy the object has
Answer: A (I got it right)
In addition to how much force Earth exerts on the object, which features of an object affect its weight?
mass and location of the object
shape and location of the object
location of the object and how much energy the object has
mass of the object and how much energy the object has
Explanation:
Answer: A
Explanation:
hope this helps!
A model of evolution is shown here. The original population has alleles for type A blood (red) and alleles for type B blood (blue).Which statements are supported by the information in the model? Please select ALL that apply.
Answer:
-Islands A and C had founding members with very different allele combinations than the original mainland population.
-The genetic diversity for islands A and C is reduced after genetic drift.
-The founder effect is a mechanism of evolution that includes a random factor that influences allele changes.
-The members of the founding population for island B are the most representative of the original population on the mainland.
Explanation:
A conversion disorder in which an individual's hand becomes entirely numb, while an area above the wrist, controlled by the same nerves, remains sensitive to touch is referred to as
The conversion disorder described is known as glove anesthesia. It is a neurological condition in which an individual experiences a sensation of numbness in the hand as if wearing a glove, while the area above the wrist remains sensitive to touch.
The condition is believed to be caused by psychological or emotional factors, rather than a physical injury or illness. It is classified as a somatic symptom disorder, which means that the symptoms are not fully explained by a medical condition or other physical factors. Treatment for glove anesthesia typically involves psychotherapy and addressing any underlying psychological issues that may be contributing to the symptoms.
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the outer boundary of most cells is called
Answer:
Cell membrane
Explanation:
The cell membrane is a flexible and permeable skin surrounding a cell.
What are five ways to help keep groundwater clean?
Five ways to keep Ground Water Clean!
Purification
Less Littering
Less pollution
Less gas around water areas
Cleaning up around your local area
Your patient weights 176lbs. The order is to have Heparin 25,000units in 250ml of NS increased to 10units/kg/hr. Calculate this infusion rate in ml/hr.
The infusion rate is 7.9832 ml/hr. As per the given information, the patient weight is 176 lbs and the order is to have Heparin 25,000 units in 250 ml of NS increased to 10 units/kg/hr.
As per the given information, the patient weight is 176 lbs and the order is to have Heparin 25,000 units in 250 ml of NS increased to 10 units/kg/hr.
To calculate the infusion rate in ml/hr, we need to follow the steps given below:
Step 1: Convert the patient's weight in kg
Patient's weight in kg = Patient's weight in lbs ÷ 2.2046= 176 ÷ 2.2046= 79.832 kg
Step 2: Calculate the total dosage of Heparin
Total dosage of Heparin = 25,000 units
Step 3: Calculate the infusion rate in ml/hr.
Infusion rate (ml/hr) = Total dosage of Heparin ÷ Volume of the solution ÷ time in hours
Infusion rate (ml/hr) = (10 units/kg/hr × 79.832 kg × 1 hr) ÷ (25,000 units ÷ 250 ml)Infusion rate (ml/hr) = (798.32 units/hr) ÷ (100 units/ml)Infusion rate (ml/hr) = 7.9832 ml/hr
Therefore, the infusion rate is 7.9832 ml/hr.
Hence, answer is as follows: Given Information: Patient's weight = 176 lbs
Heparin dosage = 25,000 units in 250 ml of NS
Dosage increased to = 10 units/kg/hrThe patient's weight needs to be converted from pounds to kilograms before calculating the infusion rate.
1 kilogram = 2.2046 pounds.
Patient's weight in kg = 176 ÷ 2.2046 = 79.832 kg
The next step is to calculate the total Heparin dosage: Total dosage of Heparin = 25,000 units
The final step is to calculate the infusion rate in ml/hr using the following formula: Infusion rate (ml/hr) = Total dosage of Heparin ÷ Volume of the solution ÷ time in hours
Infusion rate (ml/hr) = (10 units/kg/hr × 79.832 kg × 1 hr) ÷ (25,000 units ÷ 250 ml)
Infusion rate (ml/hr) = (798.32 units/hr) ÷ (100 units/ml)Infusion rate (ml/hr) = 7.9832 ml/hr
Therefore, the infusion rate is 7.9832 ml/hr.
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why is it possible for an amino acid to be specified by more that one kind of codon
Answer:
Because there are only 20 different amino acids but 64 possible codons, most amino acids are indicated by more than one codon.
Explanation: