what units are used for work done

a = -3

common ratio(r) = -12/(-3) = 4

nth term = a.r^(n-1)

= -3.(4)^(n-1)

Answer:

\(-\frac{1}{64}\)

Step-by-step explanation:

Evaluate the following limit.

\(\lim_{x \to 0} \frac{\frac{1}{x+8} -\frac{1}{8} }{x}\)

(1) - Simplify the limit

\(\lim_{x \to 0} \frac{\frac{1}{x+8} -\frac{1}{8} }{x}\\\\\Longrightarrow \lim_{x \to 0} \frac{\frac{1(8)}{(x+8)(8)} -\frac{1(x+8)}{8(x+8)} }{x}\\\\\Longrightarrow \lim_{x \to 0} \frac{\frac{8-x-8}{8(x+8)} }{x} \\\\\Longrightarrow \lim_{x \to 0} \frac{\frac{ -x}{8(x+8)} }{x} \\\\\Longrightarrow \lim_{x \to 0} \frac{-x}{8x(x+8)} \\\\\Longrightarrow \boxed{\lim_{x \to 0} \frac{-1}{8(x+8)} }\)

(2) - Plug in the limit

\(\lim_{x \to 0} \frac{-1}{8(x+8)}\\\\\Longrightarrow \lim_{x \to 0} \frac{-1}{8((0)+8)}\\\\\Longrightarrow \lim_{x \to 0} \frac{-1}{8(8)} \\\\\therefore \boxed{\boxed{\lim_{x \to 0} \frac{\frac{1}{x+8} -\frac{1}{8} }{x}=-\frac{1}{64} }}\)

Answer:

382.5?????

Step-by-step explanation:

because 850×45% its that

Answer:

-65d - 55

Step-by-step explanation:

Given expression,

→ -5(13d + 11)

Simplifying the expression,

→ -5(13d + 11)

→ (-5 × 13d) + (-5 × 11)

→ -65d + (-55)

→ -65d - 55

Thus, answer is -65d - 55.

Answer:

11

Step-by-step explanation:

The formula for the volume of a sphere is

\( \frac{4}{3} \pi \: {r}^{3} \)

Using this formula we get:

\( \frac{4}{3} \pi \: {r}^{3} = 5600 \\ \pi \: {r}^{3} = 5600 \div \frac{4}{3} \\ \pi \: {r}^{3} = 4200 \\ {r}^{3} = 4200 \div \pi \\ \)

From this we get that r is approximately 11.

Answer: 3/4

Step-by-step explanation: evalute the exponet which is 36 add the numbers then evalute again the mutiply then divide.

Answer:  A

Step-by-step explanation:

When multiplying: Numbers multiply with numbers and for the x's, add the exponents

If there is no exponent, you can assume an imaginary 1 is the exponent

2x⁴ (3x³ − x² + 4x)

= 6x⁷ -2x⁶ + 8x⁵

Answer:

A. \(6x^{7} - 2x^{6} + 8x^{5}\)

Label the parts of the expression:

Outside the parentheses = \(2x^{4}\)

Inside parentheses = \(3x^{3} -x^{2} + 4x\)

You must distribute what is outside the parentheses with all the values inside the parentheses. Distribution means that you multiply what is outside the parentheses with each value inside the parentheses

\(2x^{4}\) × \(3x^{3}\)

\(2x^{4}\) × \(-x^{2}\)

\(2x^{4}\) × \(4x\)

First, multiply the whole numbers of each value before the variables

2 x 3 = 6

2 x -1 = -2

2 x 4 = 8

Now you have:

6\(x^{4}x^{3}\)

-2\(x^{4}x^{2}\)

8\(x^{4} x\)

When you multiply exponents together, you multiply the bases as normal and add the exponents together

\(6x^{4+3}\) = \(6x^{7}\)

\(-2x^{4+2}\) = \(-2x^{6}\)

\(8x^{4+1}\) = \(8x^{5}\)

Put the numbers given above into an expression:

\(6x^{7} -2x^{6} +8x^{5}\)

distribution

variable

like exponents

The number of thermally populated states is 0.

Given that the system at 200 K has an infinite ladder of evenly spaced quantum states with an energy spacing of 0.25 kJ/mol. We need to find the energy for level n=3, the minimum possible value of the partition function, the average energy of this system in the classical limit, and the number of thermally populated states.1. The energy for level n=3 is kJ/mol.

The energy for level n can be calculated as,

En = (n - 1/2) * δE

Where δE is the energy spacing

δE = 0.25 kJ/mol and n = 3

En = (3 - 1/2) * 0.25= 0.625 kJ/mol

Therefore, the energy for level n=3 is 0.625 kJ/mol.

The minimum possible value of the partition function for this system is - We know that the partition function is given as,

Z= Σexp(-Ei/kT)

where the sum is over all states of the system.

The minimum possible value of the partition function can be calculated by considering the lowest energy state of the system, which is level n = 1.

Z1 = exp(-E1/kT) = exp(-0.125/kT)

For an infinite ladder of quantum states, the partition function for the system is given as,

Z = Z1 + Z2 + Z3 + … = Σexp(-Ei/kT)

The minimum possible value of the partition function is when only the ground state (n=1) is populated, and all other states are unoccupied.

Zmin = Z1 = exp(-0.125/kT) = exp(-5000/T)

The average energy of this system in the classical limit is kj/mol. The classical limit is when the spacing between energy levels is much less than the thermal energy. In this case, δE << kT. In the classical limit, the average energy of the system can be calculated as,

Eav = kT/2= (1.38 * 10^-23 J/K) * (200 K) / 2= 1.38 * 10^-21 J= 0.331 kJ/mol

Therefore, the average energy of this system in the classical limit is 0.331 kJ/mol (rounded to 1 decimal).

The number of thermally populated states is

The number of thermally populated states can be calculated using the formula,

N= Σ exp(-Ei/kT) / Z

where the sum is over all states of the system that have energies less than or equal to the thermal energy.

Using the values from part 1, we can calculate the number of thermally populated states,

N = Σ exp(-Ei/kT) / Z= exp(-0.125/kT) / (1 + exp(-0.125/kT) + exp(-0.375/kT) + …)

We need to sum over all states that have energies less than or equal to the thermal energy, which is given by,

En = (n - 1/2) * δE ≤ kT

This inequality can be solved for n to get, n ≤ (kT/δE) + 1/2

The number of thermally populated states is therefore given by,

N = Σn=1 to (kT/δE) + 1/2 exp(-(n-1/2)δE/kT) / Z= exp(-0.125/kT) / (1 + exp(-0.125/kT) + exp(-0.375/kT))= 0.431 (rounded to the nearest whole number)

Therefore, the number of thermally populated states is 0.

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Acceptance sampling is a quality control technique that involves inspectors randomly selecting samples (or batches) of finished products and measuring them against predetermined standards.  

Acceptance sampling can be of two types: variable or attribute. In variable sampling, measurements are taken on a continuous scale, such as weight or length. On the other hand, attribute sampling involves assessing the presence or absence of a specific characteristic, such as defects or conformity.

In the business environment, attribute inspection is more commonly used.

Therefore, all of the statements mentioned in options A, B, and C are true when it comes to acceptance sampling. I hope this helps! Let me know if you have any further questions.

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Answer: 45

Step-by-step explanation:

I'm not sure but I think it's 5

The values of a & b are a = 3y + 2x and b = (2x - 9y) / 2 for the equation 2x + 3y = a is the tangent-line to the graph of the function, f(x) = bx at I=2

Given that equation 2x + 3y = a is the tangent line to the graph of the function f(x) = bx at I = 2,

we can differentiate the equation f(x) = bx using the chain rule and find its slope at I = 2.

We know that the slope of the tangent line and the derivative of the function evaluated at x = 2 are the same slope of the tangent line at

x = 2

  = f '(2)

f(x) = bx

f '(x) = b2x3y = (a - 2b)/2

Differentiate f(x) with respect to x.

b2x = 3y  

f'(2) = b(2)

     = 6y

Substitute f '(2) = b(2)

                         = 6y in the equation

3y = (a - 2b)/2.6y

    = (a - 2b)/2

Multiply both sides by 2.

12y = a - 2b ----(1)

Also, substitute x = 2 and y = f(2) in 2x + 3y = a.2(2) + 3f(2) = a. .......(2)

Now, we need to eliminate the variable a from equations (1) and (2).

Substitute the value of a from equation (1) in (2).

2(2) + 3f(2) = 12y + 2b3f(2)

                  = 12y + 2b - 4

Multiply both sides by 1/3.

f(2) = 4y + 2/3 ----(3)

From equation (1), a = 12y + 2b.

Substitute this value of a in 2x + 3y = a.

2x + 3y = 12y + 2b2x + 3y - 12y

            = 2b2x - 9y

            = 2b

Therefore, a = 12y + 2b and

b = (2x - 9y) / 2.

Substitute b = (2x - 9y) / 2 in

a = 12y + 2b.

We get,a = 12y + 2((2x - 9y) / 2)

            a = 12y + 2x - 9y

               = 3y + 2x

Therefore, a = 3y + 2x and b = (2x - 9y) / 2.

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The area of triangle EFG, to the nearest square inch, is approximately 1061 square inches.

To find the area of triangle EFG, we can use the formula:

\(Area = (1/2) \times base \times height\)

In this case, the base of the triangle is FG, and the height is the perpendicular distance from vertex E to side FG.

First, let's find the length of FG. We can use the law of cosines:

FG² = EF² + EG² - 2 * EF * EG * cos(∠F)

EF = 72 inches

EG = 34 inches

∠F = 21°

Plugging these values into the equation:

FG² = 72² + 34² - 2 * 72 * 34 * cos(21°)

Solving for FG, we get:

FG ≈ 83.02 inches

Next, we need to find the height. We can use the formula:

height = \(EF \times sin( \angle F)\)

Plugging in the values:

height = 72 * sin(21°)

height ≈ 25.52 inches

Now we can calculate the area:

\(Area = (1/2) \times FG \times height\\Area = (1/2)\times 83.02 \times 25.52\)

Area ≈ 1060.78 square inches

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Answer: x= -20

Step-by-step explanation: hope it helps thx for the points

Answer:

Step-by-step explanation:

Answer:

Pink is the least likely to be chosen because it has the lowest frequency.

Step-by-step explanation:

The common ratio of the set of data is 0. 1

To determine the common ratio of a set of data, we have to

For the given set of data

0.1,0.01,0.001

Let's divide the second term by the first term

= 0. 01/ 0. 1

= 0. 1

Thus, the common ratio of the set of data is 0. 1

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The correct statement relating the solutions to the system of equations is given as follows:

Infinitely many solutions.

The system of equations in the context of this problem is defined as follows:

From the first equation, we have that:

6y = -3x

y = -0.5x.

Replacing into the second equation, the value of x is given as follows:

x + 2(-0.5)x = 0

x - x = 0

0 = 0.

As 0 = 0 is a statement that is always true, the system has an infinite number of solutions.

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The correct answer is option c) 4 weeks, $280.

After 4 weeks, Carly and Janiya will have the same amount of money in their money boxes, which will be $280 by solving equation.

To find the number of weeks and the amount of money at which Carly and Janiya will have the same amount of money in their money boxes, we need to set their respective money equations equal to each other and solve for x, the number of weeks.

Carly's money: y = 60x + 40

Janiya's money: y = 50x + 80

Setting the two equations equal to each other:

60x + 40 = 50x + 80

To solve for x, we subtract 50x from both sides:

60x - 50x + 40 = 50x - 50x + 80

10x + 40 = 80

Next, we subtract 40 from both sides:

10x + 40 - 40 = 80 - 40

10x = 40

Finally, we divide both sides by 10 to isolate x:

10x/10 = 40/10

x = 4

Therefore, Carly and Janiya will have the same amount of money in their money boxes after 4 weeks. To find the amount, we substitute the value of x into either equation. Let's use Carly's equation:

y = 60x + 40

y = 60(4) + 40

y = 240 + 40

y = 280

So, after 4 weeks, Carly and Janiya will have the same amount of money in their money boxes, which is $280.

The correct answer is option c) 4 weeks, $280.

In summary, after 4 weeks, Carly and Janiya will have the same amount of money in their money boxes, which is $280.

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Answer:

C

Step-by-step explanation:

since the dilatation is centred at the origin then multiply the coordinates of the point by scale factor of \(\frac{1}{3}\)

(- 3, 6 ) → (\(\frac{1}{3}\) (- 3), \(\frac{1}{3}\) (6) ) → (- 1, 2 )

Answer: 4.5 pounds

Explanation: To convert 72 ounces into pounds, we use the conversion factor for ounces and pounds which is 16 ounces = 1 pound.

Next, notice that we're going from a smaller unit, ounces, to a larger unit, pounds and when we go from a smaller unit to a larger unit, we divide. So here, we divide 72 by the conversion factor, 16, to get 4.5.

So 72 ounces equals 4.5 pounds.

Answer:

i think the c answer is 5

Step-by-step explanation:

When the sample size is less than 30 , the appropriate statistical test used for testing the hypothesis about the mean is given t-test.

Therefore, the best and appropriate statistical test used when sample size is smaller than 30 while testing hypothesis about the mean is given t-test.

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Answer:

(- 3, 0 ) , (- 1, 0 )

Step-by-step explanation:

the roots are the values of x where the graph crosses the x- axis

from the graph these are x = - 3 , x = - 1 , then coordinates of roots are

(- 3, 0 ) and (- 1, 0 )

Answer:

16.67%

Step-by-step explanation:

Total main course dishes sold during the day = 240

Burritos = 40

what percent of the main course dishes sold were burritos

Percentage of burritos sold = number of burritos sold / total number of dishes sold × 100

= 40/240 × 100

= 0.1666666666666 × 100

= 16.666666666666%

Approximately 16.67%

The plane intercepts on the x,y, z axes are 1, ∞, and 1/2. Hence, the Miller indices for the plane inside the cubic unit cell is (102).

Miller indices are used to specify planes and directions. These planes and directions could be in lattices or crystals. The number of indices will correspond to the size of the lattice or crystal.

In the given graph, the plane intercepts are:

x-intercept : 1

y-intercept : ∞  (since the planes does not intercept y-axes)

z-intercept = 1/2

Take the reciprocal:

1/1 = 1

1/∞ = 0

1/(1/2) = 2

Hence, the miller indices are (102)

The graph in your question is missing. Most likely it was like on the attached picture.

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Answer:

Combine like terms so combine 2/3x and 1/3x. Since its addition you would add them together.

Answer: Using the slope-intercept form, the slope is 0 

Step-by-step explanation:

Answer:2 is the slope

Step-by-step explanation: Rise over run. so 2/1 which simplifies to 2. (I used the coordinates (-1,1) and (2,3)

The possible values of k are k = 2 and k = -2. These are the values of the constant k for which f(x) is continuous at x = 2.

A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output.

To determine the values of the constant k for which f(x) is continuous at x = 2, we need to ensure that the left-hand limit, the right-hand limit, and the value of f(x) at x = 2 are all equal.

First, let's find the left-hand limit as x approaches 2. We evaluate the function for x < 2:

f(x) = x² + 5kx    (for x < 2)

Taking the limit as x approaches 2 from the left side (x < 2), we have:

lim(x→2-) f(x) = lim(x→2-) (x² + 5kx) = 2² + 5k(2) = 4 + 10k

Next, let's find the right-hand limit as x approaches 2. We evaluate the function for x > 2:

f(x) = k²x + 4x + 4    (for x > 2)

Taking the limit as x approaches 2 from the right side (x > 2), we have:

lim(x→2+) f(x) = lim(x→2+) (k²x + 4x + 4) = k²(2) + 4(2) + 4 = 2k² + 8 + 4 = 2k² + 12

Now, let's evaluate the value of f(x) at x = 2:

f(x) = 3k² - 4    (for x = 2)

f(2) = 3k² - 4

For f(x) to be continuous at x = 2, the left-hand limit, the right-hand limit, and the value of f(x) at x = 2 should all be equal. Therefore, we set up the following equation:

4 + 10k = 2k² + 12 = 3k² - 4

Simplifying, we have:

2k² + 8 = 3k² - 4

Rearranging the terms, we get:

k² - 12 = 0

Factoring, we have:

(k - 2)(k + 2) = 0

So, the possible values of k are k = 2 and k = -2. These are the values of the constant k for which f(x) is continuous at x = 2.

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