The volume of NaOH needed to reach the equivalence point if the concentration of the added base were 0.160 M is 31.25 mL.
The pH titration curve of 50 mL of 0.100 M solution of HCl.
The strong base react with HCl gives:
NaOH + HCl -----> NaCl + H₂O
it is clear fron the above equation that 1 mole of HCl react with 1 mole of NaOH
number of mole of NaOH = number of mole of HCl
number of moles of HCl = volume in L × Molarity
= 0.050 × 0.100
= 0.005 moles
Therefore, moles of NaOH = 0.005 moles
volume of NaOH = moles / molarity
= 0.005 / 0.160
= 0.03125 L = 31.25 mL
Thus, The volume of NaOH needed to reach the equivalence point if the concentration of the added base were 0.160 M is 31.25 mL.
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what type of reaction is performed with the elephant toothpaste demonstration?
The reaction performed with the elephant toothpaste demonstration is known as a decomposition reaction.
Decomposition Reaction:The process of breaking down a chemical compound into smaller molecules, atoms, or ions is known as a decomposition reaction. It is also known as analysis or disintegration. A reaction in which a single substance is broken down into two or more simpler substances is known as a decomposition reaction. The elephant toothpaste demonstration is a simple chemical reaction in which hydrogen peroxide breaks down into oxygen gas and water in a matter of seconds.
The formula for hydrogen peroxide is H₂O₂. It is a pale blue liquid that contains hydrogen, oxygen, and water. When you add yeast, soap, and food coloring, the reaction is more exciting. The yeast acts as a catalyst, breaking down hydrogen peroxide into water and oxygen gas. The oxygen gas created causes the soap to foam up, creating the "elephant toothpaste" effect. The chemical reaction that takes place during the elephant toothpaste demonstration can be written as follows:
2H₂O₂(liquid) → 2H₂O (liquid) + O₂ (gas)
This reaction is an example of a decomposition reaction.
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Read the chemical equation.
2H2 + O2 → 2H2O
Which of the following statements would be correct if one mole of H2 was used in this reaction?
One mole of oxygen was used in this reaction.
Two moles of oxygen were used in this reaction.
One mole of water was produced from this reaction.
Two moles of water were produced from this reaction.
WILL MARK BRAINLIST
Answer:
One mole of water was produced from this reaction.
Explanation:
According to this question, the following equation is given as follows:
2H2 + O2 → 2H2O
Two (2) moles of hydrogen gas produces two (2) moles of water in this balanced chemical equation.
If 1 mole of hydrogen gas was used, then:
1 × 2/2 moles of water would be produced
1 mole of water would be produced.
Answer:
One mole of water was produced from this reaction.
Explanation:
Guy above me is right
what is chemistry? please tell me
Chemistry is the scientific discipline involved with elements and compounds composed of atoms, molecules and ions: their composition, structure, properties, behavior and the changes they undergo during a reaction with other substances.
What is formed when a base dissociates in water, according to the Bronsted-Lowry definition?
O a salt
•
a stronger acid
O a conjugate acid
O a conjugate base
When a base dissociates in water, it forms a conjugate acid and a conjugate base, according to the Bronsted-Lowry definition.
The Bronsted-Lowry definition of acids and bases states that an acid is a substance that donates a proton (H+) and a base is a substance that accepts a proton. When a base is added to water, it accepts a proton from a water molecule and forms a conjugate acid and a hydroxide ion (OH-), which is the conjugate base. For example, when ammonia (NH3) is added to water, it accepts a proton from a water molecule to form ammonium ion (NH4+) and hydroxide ion (OH-).
The conjugate acid is formed when a base accepts a proton and has one more H+ than the original base. On the other hand, the conjugate base is formed when an acid donates a proton and has one less H+ than the original acid. Understanding the concept of conjugate acid and conjugate base is important in acid-base chemistry as they are essential in acid-base reactions.
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In science class, the students planned and conducted an investigation to learn about the density of fresh and salty water. They used two beakers and placed an egg in each. Use the findings to explain how density depends on salinity and apply this idea to elaborate on what type of water rises above the other when a river meets the ocean.
The egg would be found to float on the sea water which is denser but would tend to sink in the fresh water which is less dense.
What is salinity?The term salinity has to do with the amount of salt that is present. A solution is very saline if there is a high concentration of salt in the solution. We know that sea water has a greater density than water. The reason why the density of the sea water is greater than the density of the pure water is that the sea water contains dissolved salts.
Now, we know that given the fact that the sea water is denser than the fresh water, it is easier for an object to sink in the fresh water than it does in the sea water which is denser. This is even observed in ships as there is a greater tendency to remain afloat in sea water than in salt water.
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If the same large amount of heat is added to a 250 g piece of aluminum and a 150 g piece of aluminum, what will happen?
What does the internal temperature of chicken need to be?.
The internal temperature of chicken needs to be 165°F (74°C) in order to be safe for consumption.
Internal temperature is critical when it comes to cooking meat or poultry, and it is important to ensure that meat is cooked to the correct temperature to eliminate harmful bacteria. When it comes to chicken, the internal temperature should reach 165°F (74°C) throughout the chicken in order to kill bacteria that may cause illness.Using a meat thermometer to check the internal temperature of chicken is the most reliable way to ensure that it has been cooked to the correct temperature.
Insert the thermometer into the thickest part of the chicken, being careful not to touch bone or the bottom of the pan. Let the temperature stabilize for a few seconds before reading it. If the internal temperature of the chicken is not 165°F (74°C), continue cooking until it reaches that temperature.
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How many grams of NaN3 are required to produce 283 L of nitrogen gas about the size of an automotive air bag, if the gas has a density of 1.25 g/L? Please answer ASAP
3.300
bc im right fgdfgdffffffffg
which of the following is an oxyanion?
Answer:
please give the answer choice.
Help Please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
All substances taking part in a certain interaction are shown below: (5 points)
Calcium Carbonate is written after that an equal to sign is shown followed by Calcium Oxide followed by an addition sign followed by Carbon dioxide. Just below Calcium Oxide 112 grams is written and just below Carbon dioxide 88 grams is written
Which of the following is the correct estimate of the amount of calcium carbonate used in the interaction?
Sum of 112 g and 88 g
Difference between 112 g and 88 g
Twice the sum of 112 g and 88 g
Twice the difference between 112 g and 88 g
Answer:
Hey there!
The correct answer is "sum of 112+88 g"...
The calcium carbonate has 88g in a fine manor which goes along with 1128.
Hope this helps! Happy Holidays and stay safe!
Explanation:
Answer:
answer is "sum of 112+88 g"...
Explanation:
The calcium carbonate has 88g in a fine manor which goes along with 1128.
hope this helps and ill get brainliest im trying to rank up so i can help more people
For a CSTR you have the following data, X = 0.5, molar flow rate of A (n) = 4 0.2 min¹¹. Assume liquid phase reaction and first order mol/min., Caº kinetics. no = 1 mol/l, k = a). Calculate the Volume for the CSTR
For a CSTR you have the following data, X = 0.5, molar flow rate of A (n) = 4 0.2 min¹¹. The volume of the CSTR is approximately 12.5 liters.
The volume of a CSTR can be determined based on the molar flow rate of the reactant and the rate of reaction. In this case, we are given the conversion, molar flow rate of component A, initial concentration of A, and the rate constant for the first-order reaction. By applying the appropriate equations, we can calculate the volume of the CSTR.
First, we calculate the rate of reaction (-rA) using the rate constant 'a' and the concentration of A. Then, we determine the concentration of A at the given conversion using the initial concentration and the molar flow rate. With the values of n and (-rA), we can substitute them into the volume equation V = n / (-rA).
The resulting volume will be the solution to the problem, indicating the required volume for the CSTR.
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If 2.2 moles of calcium oxide are decomposed, how many moles of oxygen are produced?
2CaO --> 2Ca + O2
Answer: Since the reaction is 2Ca(NO3)2 = 2CaO + 4NO2 + O2
1) - given the stoichiometric coefficients, we know that 2 moles of Ca(NO3)2 will produce 4 moles of NO2, hence, 1 mole will produce 2 moles of NO2
2) - 328 g produces 22.4 L, since One mole of any gas at S.T.P. occupies the same volume which is 22.4 L.
Hence, 65.6 g produces (65.6*22.4)/328 = 4.48 L
3) - 328 g produces 112 g CaO. Therefore, 65.6 g produces = (65.6*112)/328 = 22.4 g CaO.
4) - Given the stoichiometric coefficients, we know 5 moles of gaseous products are already being produces ( 4+1) by 2 moles of reactant.
5) - 44.8 L at STP = 2 moles of NO2, since One mole of any gas at S.T.P. occupies the same volume which is 22.4 L.
Hence, to produce 2 moles of NO2, we need 1 mole of reactant = 164 g
Hope this helps :)
Explanation:
Plz helpppp^^^^^^^^^^
A spectrophotometric method for the analysis of iron has a linear calibration curve for standards of 0. 00, 5. 00, 10. 00, 15. 00, and 20. 00 ppm. An iron ore sample with an expected iron content of 40–60% w/w is to be analyzed by this method. An approximately 0. 5 g sample is taken, dissolved in a minimum of concentrated HCl, and diluted to 1 L in a volumetric flask using distilled water. A 5. 00-mL aliquot is removed with a pipet. To what volume (10, 25, 50, 100, 250, 500, or 1000 mL) should it be diluted to minimize the uncertainty in the analysis? Explain
To calculate the concentration of the iron sample by using a spectrophotometric method, it is necessary to dilute the sample. The volume to which the sample should be diluted is a crucial question in achieving the most accurate result.
The process involves diluting the sample, and the concentration must be calculated to determine the precise result of the dilution. This question can be answered by calculating the uncertainty and identifying the value of the uncertainty. The value with the lowest uncertainty will be the best value to choose. The volume with the lowest uncertainty will be the ideal volume to dilute the 5 ml aliquot of the iron sample to achieve a result with the minimum level of uncertainty.
To determine the optimal volume for dilution, the uncertainty should be calculated.
This can be done by using the equation for propagation of uncertainty, which states that the uncertainty of the result is equal to the square root of the sum of the squares of the uncertainties of the individual components. When calculating the uncertainty of the diluted sample, the uncertainty of the initial sample and the uncertainty of the diluent must be considered. The uncertainty of the initial sample can be calculated using the calibration curve. As the expected iron content is 40-60%, the concentration of the sample is expected to be 8-12 ppm. The uncertainty of the calibration curve is given by the standard deviation of the calibration standards.
The diluent has a negligible uncertainty. The uncertainty of the diluted sample will be lower if a larger volume is used for dilution because the relative contribution of the uncertainty of the initial sample will decrease. However, the uncertainty of the measurement will increase if the sample is diluted too much because the concentration of the analyte will be too low to be detected accurately. A 100 mL volume is a good choice because it balances the need for sufficient dilution to reduce the uncertainty of the initial sample with the need for sufficient concentration to allow for accurate detection of the analyte.
The volume of the sample that should be diluted is 5 ml. The minimum level of uncertainty is obtained at a dilution of 100 ml. When the volume of the diluent is greater than 100 ml, the uncertainty of the measurement increases, and when the volume of the diluent is less than 100 ml, the uncertainty of the measurement also increases. Thus, a 100 ml volume of diluent is the ideal volume to minimize the uncertainty in the analysis of iron.
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Name 10 radioactive substances. HELP ASAP I AM BOMBARDED WITH HOMEWORK TODAY!! GIVING BRAINLIEST! NO SPAM
NO ROBOTS !
Answer: alpha radiation, uranium, radium, radon, polonium,
Explanation:
10 radioactive substances are:
UraniumRadiumPoloniumRadonPlutoniumProtactinium StrontiumNobeliumThoriumActiniumto a first approximation the ionization constant of h2s is
The ionization constant of H₂S is approximately 1.0 x 10⁻⁷.
The ionization constant, also known as the acid dissociation constant (Ka), is a measure of the extent to which an acid dissociates in water. It indicates the degree of ionization of an acid and is typically expressed as the equilibrium constant for the reaction between the acid and water.
In the case of H₂S (hydrogen sulfide), it is a weak acid that can partially dissociate in water to produce hydrogen ions (H⁺) and sulfide ions (HS⁻). The ionization reaction can be represented as follows:
H₂S ⇌ H⁺ + HS⁻
The ionization constant (Ka) represents the equilibrium expression for this reaction. The value of Ka determines the relative strength of the acid. For H₂S, the ionization constant is approximately 1.0 x 10⁻⁷, indicating that it is a weak acid.
This value indicates that H₂S only partially ionizes in water, with a small fraction of H₂S molecules dissociating into H⁺ and HS⁻ ions. The majority of H₂S remains in its molecular form.
It is important to note that the ionization constant can vary depending on factors such as temperature and concentration. The given approximation is a typical value at standard conditions.
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what fraction of all electrochemical reactions are electrolytic?
It is likely that only a small fraction of all electrochemical reactions are electrolytic.
It is difficult to give an exact fraction of all electrochemical reactions that are electrolytic, as the classification of a reaction as electrolytic depends on various factors such as the direction of the current flow, the nature of the electrodes and the electrolyte, and the specific conditions of the reaction.
However, electrolytic reactions are typically defined as those that require an external electrical source to drive the non-spontaneous reaction in the opposite direction to the natural flow of electrons.
In general, electrolytic reactions are less common than spontaneous reactions, which occur without the need for an external electrical source. Therefore, it is likely that only a small fraction of all electrochemical reactions are electrolytic.
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Help I need them fast pls
Answer:
I don't have a paper right now so I am attaching images for b(i), (ii) and c(i)
Explanation:
c) Ionic bond is the result of strong electrostatic force of attraction between positively charged metal ion and negatively charged metal ion.
A science teacher asked students to calculate the density of a toy block. The mass of the block was 110 grams and the volume of the block was 8 cubic centimeters. What was the density of the toy block in cubic centimeters?
Answer:
13.75
Explanation:
Density is equal to mass divided by volume. 110/8 = 13.75
an unknown compound gives a colored precipitate upon reaction with fe (iii) chloride-pyridine reagent in chloroform and also discharges the red color of bromine in water. the compound is possibly a:
An unknown compound gives a colored precipitate upon reaction with fe (iii) chloride-pyridine reagent in chloroform and also discharges the red color of bromine in water. the compound is possibly a: Phenol.
Chloroform, or trichloromethane, is an organic compound with the formula CHCl₃ and a not-unusual organic solvent. it's far a colorless, sturdy-smelling, dense liquid produced on a massive scale as a precursor to PTFE. it's also a precursor to diverse refrigerants. it's by far one of the four chloromethanes and a trihalomethane.
Chloroform (CHCl3) is a drab liquid that quickly evaporates into a gas. it can damage the eyes, skin, liver, kidneys, and frightening device. Chloroform may be toxic if inhaled or swallowed. publicity to chloroform might also cause cancer. employees may be harmed from publicity to chloroform.
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HELP ME IS IMPORTANT I WILL GIVE REWARDS OR ANYTHING U WANT
The height of a horse is traditionally measured in “hands” where a hand is 4.00 inches. What is the height of a horse, in meters, that is 14.0 hands tall?
Balance the following equations:C(s) +CO2(g)- CO(g)
Answer:
C(s)+CO₂(g)→2CO(g)
Explanation:
Basically you’re adding the compounds until they’re equal on both sides
Please help me with these questions!!
Large particles usually get smaller as a result of surface reactions. Both heating and freezing effects of tiny particles on the climate are seen.
Weathering can be classified as either physical or chemical. There is a wide variety in soil particle size due to variations in weathering processes.The overall surface area increases when the size is reduced more. This is significant since most chemical changes start at an object's surface.
The Earth's materials are the four major elements that make up the earth's crust. The earth is made up of minerals, rocks, soil, and water. Earth materials include the necessary building components for life, agriculture, and industry.
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Consider the following: Li(s) + ½ I₂(g) --> LiI(s) ΔH = –292 kJ. LiI(s) has a lattice energy of –753 kJ/mol. The ionization energy of Li(g) is 520 kJ/mol, the bond energy of I₂(g) is 151 kJ/mol, and the electron affinity of I(g) is –295 kJ/mol. Use these data to determine the heat of sublimation of Li(s).
Answer:
Heat of sublimation of Li(s) = 160.5 kJ/mol
Explanation:
Given that:
\(\mathtt{2Li(s) + \dfrac{1}{2} I_2(g) \to 2LiI(s)}\)
ΔH = –292 kJ
The heat of formation for the above reaction = –292 kJ × 2 = -584 kJ/mol
\(\mathtt{Li^+_{(g)} + I^-_{(g)} \to LiI_{(s)}}\)
The lattice energy of LiI(s) = -753 kJ/mol
\(\mathtt{Li(g)\to Li^+(g) + e^- }\)
The ionization energy of LiI(s) = +520 kJ/mol
\(\mathtt{I_2_{(g)} \to 2I_{(g)} }\)
The Bond Energy of I₂(g) = 151 kJ/mol
\(\mathtt{I_{(g)} + e^- \to I^-_{(g)}}\)
The electron affinity of I(g) = -295 kJ/mol
Heat of sublimation: Sublimation is the process of changing of a solid matter into gas without passing through the liquid stage, Now, the molar heat of sublimation is the amount of energy that must be added to a mole of solid to turn it directly into a gas without any interference through the liquid phase provided the pressure is constant.
From the above reactions: The heat of sublimation of Li(s) can be calculated by the sum total of the following.
\(\mathtt{Li_{(s)} + \dfrac{1}{2} I_2_{(g)} \to LiI_{(s)} \ \ -292 kJ/mol} \\ \\\mathtt{I_{(g)} \to \dfrac{1}{2} I2(g) \ \ -75.5 kJ/mol} \\ \\ \mathtt{I^-(g) \to I(g) + e^- \ \ +295 kJ/mol} \\ \\ \mathtt{LiI(s) \to Li^+_{(g)} + I^-_{(g)} \ \ +753 kJ/mol} \\ \\ \mathtt{Li^+_{(g)} + e^- \to Li(s) \ \ -520 kJ/mol} \\ \\\)
\(\mathtt{Li(s) \to Li(g)}\) = (-292 +(-75.5)+295+753+(-520)) kJ/mol
\(\mathtt{Li(s) \to Li(g)}\) = 160.5 kJ/mol
Heat of sublimation of Li(s) = 160.5 kJ/mol
What is the difference between Eukaryote and Prokaryote cells?
Hydrogen gas was cooled from 373 K to 283 K. Its new volume is 750.0 mL. What was the original volume?
This is an exercise in Charles's Law which states that, at constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature. This means that when the temperature of a gas increases, its volume also increases, and vice versa, as long as the pressure remains constant.
Charles' law can be expressed by the formula:V₁/T₁ = V₂/T₂
Where V₁ is the initial volume of the gas, T₁ is the initial temperature, V₂ is the final volume of the gas, and T₂ is the final temperature.
This law is one of the fundamental laws of thermodynamics and applies to any ideal or real gas. It is important to note that Charles's law only applies to situations where the pressure is held constant. If the pressure changes, other laws, such as Boyle's law or Gay-Lussac's law, must be used.
Charles' law has many practical applications, including measuring temperature using gas thermometers, determining the thermal expansion of materials, and understanding the behavior of gases under different conditions of temperature and pressure.
We know that the formula is:
V₁/T₁ = V₂/T₂
It tells us that it cooled hydrogen from T1 = 373 K to T2 = 283 K. Since its new volume is 750.0 mL.
They ask us, what was the original volume? , Here we are asked to calculate the initial volume.But before calculating the initial volume, we solve the formula, then:
V₁ = (V₂T₁)/T₂
Now that we have our formula cleared, we plug in the data and solve:
V₁ = (V₂T₁)/T₂
V₁ = (750.0 mL × 373 K)/(283 K)
V₁ = 988.52 mL
The original volume was 988.52 mL.
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Which of the following features arise when depicting and populating an orbital energy diagram for a many-electron atom? Select all that apply.
-There is a limit is on the number of electrons in an orbital.
-A spin quantum number is assigned to each electron.
-Principal energy levels are split into sublevels.
The correct features that arise when depicting and populating an orbital energy diagram for a many-electron atom are:
- A spin quantum number is assigned to each electron.
- Principal energy levels are split into sublevels.
1. The limit on the number of electrons in an orbital is a concept related to the Pauli exclusion principle, which states that each orbital can accommodate a maximum of two electrons with opposite spins. However, it is not directly associated with orbital energy diagrams.
2. The spin quantum number is assigned to each electron to describe its spin orientation. The possible values for the spin quantum number are +1/2 (representing "spin-up") and -1/2 (representing "spin-down").
3. Principal energy levels are split into sublevels based on their different orbital shapes and orientations. These sublevels are represented by letters such as s, p, d, and f, which correspond to different angular momentum quantum numbers.
In summary, when depicting and populating an orbital energy diagram for a many-electron atom, the features that arise include assigning a spin quantum number to each electron and splitting the principal energy levels into sublevels.
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What is the weighted average of lemonas if 80% are the GX model (4,000 lbs) and 20% are
the GXL model (5,000 lbs)?
Answer:
4200
Explanation:
4,000 * .8 + 5,000 * .2
The weighted average of lemonas with 80% GX model and 20 % GXL model is calculated using their mass percent and it is 4200.
What is weighted average?
The weighted average is different from the normal average we use in maths. Let's X and Y be two number and their average be x+ y/2. That is the arithmetic mean.
The weighted average of lemonas is similar to the atomic weight of an element calculated from ist two isotopes where, the percentage abundance in earth and the mass of isotopes if given the weighted average is calculated as follows:
weighted average = % abundance / 100 × mass of isotope 1 + % abundance / 100 × mass of isotope 2
In a similar way, the weighted average of lemonas of GX and GXL model is calculated as follows:
weighted average = ( 4000 lbs ×80/100 ) + ( 5000 lbs ×20/100)
= 4200 lbs.
Hence, the weighted average of lemonas if 80% are the GX model (4,000 lbs) and 20% are the GXL model is 4200 lbs.
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Indicate which Haworth projection corresponds to the beta-pyranose form of the Fischer projection below. Compound A Compound B Compound C Compound D Compound E Compound A Compound B Compound C Compound D Compound E
Compound B will indicate the Haworth projection which corresponds to the beta-pyranose form of the Fischer projection.
The Haworth projection is a convenient notation for showing the structure of sugars. Because each substituent points either straight up or straight down, it is much easier to discern conformational differences between sugars in the Haworth conformation than in the chair conformation. The Fisher projection is his way of representing a 3D molecule in his 2D. By following certain rules for drawing these projections, complex carbohydrates such as glucose and fructose can be represented in a way that conveys structural information. To turn a Fisher projection into a connecting line, draw a zigzag with the appropriate number of carbons, add groups, and randomly assign cuneiform and dash notation.
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