What would be the total magnification if the ocular were 20X and the objective were 100X (oil immersion)

Depending on how the changed amino acid functions. A protein's function may be affected replacement of one amino acid but not by the replacement of another, which could result in a complete loss of function.

Alanine, arginine, aspartic acid, aspartic acid, cysteine, glutamic acid, glutamine, glycine, proline, serine, and tyr are the non-essential amino acids. Conditional amino acids are a few non-essential acids. They are thus only regarded as necessary when you're ill or even under stress.

Proteins are comprised of substances called amino acids. Proteins and amino acids are the components of life. Amino acids are the byproducts of the digestion or breakdown of proteins. Organic molecules are being used by the body to create proteins that aid inside the digestion of meals.

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A system's equilibrium will move to the right, or toward the side of the products, in accordance with Le Chatelier's principle, if more reactants are added. ... The equilibrium will move to the left if we add more product to a system, producing more reactants.

Solution: By increasing the number of reactants, the equilibrium moves to the right and in the direction of the products.

Thus, if a reactant is added, equilibrium shifts to the right, away from the reactant. Equilibrium shifts to the left, away from the product, when a product is added. If we take away the product, equilibrium returns and produces the product. Reactant is created if reactant is removed, breaking the equilibrium.

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Answer:

Option b (V1/T1 = V2/T2) is the right alternative or the new volume will be "0.048 L".

Explanation:

The given values are:

Temperature,

T₁ = 25°C

or,

   = 298.15 K

T₂ = 50°C

or,

    = 323.15 K

Volume,

V₁ = 45 mL

or,

    = 0.045 L

V₂ = ?

As we know,

⇒  \(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)

Or,

⇒  \(V_2=\frac{V_1\times T_2}{T_1}\)

On substituting the values, we get

⇒       \(=\frac{0.045\times 323.15}{298.15}\)

⇒       \(=\frac{14.541}{298.15}\)

⇒       \(=0.048 \ L\)

Answer:

Explained below

Explanation:

Formula for Ammonia is NH3

Now, Nitrogen has 5 electrons in it's outermost shell while hydrogen has only 1 electron.

Thus means that nitrogen needs three more electrons to add to it's five to complete it's octet shell.

Whereas each hydrogen atom will need one extra electron to complete 2 electrons in it's outermost shell.

As depicted in the image attached, Each atom will now have a complete valence shell since the three

Hydrogen(H) atoms share their electrons thereby forming covalent bonds with one Nitrogen(N) atom.

Therefore, the mass of silver sulfide formed when 9.48 g of hydrosulfuric acid is reacted with 6.35 g of silver nitrate is 2.238 g.

When 9.48 g of hydrosulfuric acid is reacted with 6.35 g of silver nitrate, the reaction forms solid silver sulfide. The equation for this reaction is:

H₂S + 2 AgNO₃ → Ag₂S + 2 HNO₃.

To calculate the mass of silver sulfide formed, we need to use the mole ratio of the two reactants. We know that the molecular weight of silver nitrate is 169.88 g/mol and the molecular weight of hydrosulfuric acid is 34.08 g/mol.

Using the mole ratio, we can find the moles of each reactant:

9.48 g/34.08 g/mol = 0.2786 moles of H₂S and 6.35 g/169.88 g/mol = 0.0373 moles of AgNO₃.

Since the reaction forms 1 mole of Ag₂S for every 2 moles of AgNO3, we can calculate the moles of Ag₂S formed: (0.0373 moles of AgNO₃ x 1 mole of Ag₂S)/2 moles of AgNO₃ = 0.01865 moles of AgS.

Now, using the molecular weight of silver sulfide (119.97 g/mol), we can calculate the mass of silver sulfide formed: 0.01865 moles of Ag₂S x 119.97 g/mol = 2.238 g of Ag₂S.

Therefore, the mass of silver sulfide formed when 9.48 g of hydrosulfuric acid is reacted with 6.35 g of silver nitrate is 2.238 g.

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Answer: C

Explanation:

The option that best explains why conservation of mass should be studied in a closed system is to prevent the release of any gases produced.

The law of conservation of mass states that mass can neither be created nor destroyed in a reaction, but can be converted from one form to another during the course of the reaction.

A closed system is one that cannot exchange matter with its surrounding while an open system is free to exchange both matter and energy with its surrounding.

When a system is opened, gaseous reactants of products may be lost to the surroundings and the mass will not be conserved as a result.

However, in a closed system, gaseous reactants or products remain within the system and the mass of the system before and after the reaction remains constant.

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The name of the process by which glucose is regenerated from lactate is called Cori cycle.

Cori cycle is the metabolic pathway in which lactate produced by anaerobic glycolysis in the muscles moves to the liver and is converted to glucose, which then returns to the muscles and is metabolized back to lactate.

This process was named after its discoverers as follows; Carl Ferdinand Cori and Gerty Cori.

The Cori cycle is a way to bring energy to the muscles during intense workouts and other times of lower oxygen levels in the body.

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Answer:

Potential energy is something "about" to happen, it hasnt had movement but had the POTENTIAL to. Kinetic is in movement, it is moving.

Answer:

The difference between the Potential and Kinetic are

Potential energy is the energy in a body due to its position. While kinetic energy is the energy in a body due to its motion.

Hope that helps

Answer:

it's thermal energy

Explanation:

There are five types of kinetic energy: radiant, thermal, sound, electrical and mechanical.

#carry on learning

Hope it helps

In this exercise we have to use the knowledge of kinetic energy and we can also describe it as a thermal energy.

Kinetic energy is a type of energy that is related to the movement of bodies. The result of kinetic energy is intrinsically linked to the value of the object's mass and its speed of movement.

Kinetic energy does not depend exclusively on the speed of a body but also on its mass. Any type of body in motion is endowed with this type of energy: translation, rotation, vibration and others.

With these definitions we can write that it will be the same as saying that kinetic energy can be transformed into thermal energy.

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Answer:

the answer is A, they are measured in kilograms

Answer:

Quantitative data refers to any information that can be quantified, counted or measured, and given a numerical value. Qualitative data is descriptive in nature, expressed in terms of language rather than numerical values

Explanation:

:)

Answer:.

Explanation:

In 183 kg of semiconductor with a dopant concentration of 2.00 ppm by mass, there is 0.366 g of dopant present.

To find the amount of dopant present, we can use the formula:

Dopant mass = (Dopant concentration × Total mass of semiconductor) / 1,000,000

Plugging in the given values:

Dopant mass = (2.00 ppm × 183 kg) / 1,000,000

Dopant mass = 0.366 g

Therefore, there is 0.366 g of dopant present in 183 kg of semiconductor with a dopant concentration of 2.00 ppm by mass.

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Dihydroxyacetone is a ketose, while glyceraldehyde is an aldose.

Aldoses are carbohydrates that contain an aldehyde group (carbonyl group on a terminal carbon atom). This means that, of the two, glyceraldehyde is the aldose (more precisely, an aldotriose, because it has 3 carbon atoms) as glyceraldehyde molecule has an aldehyde group.

On the other hand, ketoses are carbohydrates that contain a keto group (carbonyl group that is not located on a terminal carbon atom). This means that dihydroxyacetone is the ketose (more precisely, a ketotriose, because it also has 3 carbon atoms), as the acetone molecule has a keto group.

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The molecule that is expected to exhibit resonance is the nitrate ion (NO₃⁻).

The nitrate ion (NO₃⁻) has a trigonal planar structure with one central nitrogen atom (N) bonded to three oxygen atoms (O). The nitrogen atom has a formal charge of +1, and each oxygen atom has a formal charge of -1. The overall charge of the nitrate ion is -1.

In the resonance structures of the nitrate ion, the double bond can be delocalized or spread out over the three oxygen atoms. This occurs because the oxygen atoms can share the electrons in the double bond with the nitrogen atom through the process of resonance.

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The arrangement of electron pairs around n in nh3 and around c in ch4 are: In ammonia, there is 3 bond pair of electrons and one lone pair of electrons and in methane, there is 4 bond pair of electrons.

Electron is a loose and open-source software framework evolved and maintained by GitHub. The framework is designed to create desktop programs with the usage of net technology which can be rendered using a flavor of the Chromium browser engine, and a backend the use of the Node.js runtime environment.

An electron is a negatively charged subatomic particle that can be both sure to an atom or loose (not bound). An electron is sure to an atom is one of the 3 primary types of debris inside the atom -- the alternatives is protons and neutrons.

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Answer:

High pressure.

Explanation:

The weather should have clear skies, if it is a Large "L" it would be could be stormy.

Hope this helps! have a great day!

Most Cl- and SO42- salts are soluble in water, meaning they dissolve and form a solution.

The solubility of salts in water is influenced by several factors, including the charge and size of the ions, temperature, and pressure. In general, most Cl- (chloride) and SO42- (sulfate) salts are highly soluble in water, meaning they dissolve and form a solution.

This is because Cl- and SO42- ions have a relatively low charge density and are small in size, allowing them to easily interact with water molecules and dissolve.

Most Cl- and SO42- salts are soluble in water, meaning they dissolve and form a solution.

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The \(p^{H}\) change is -0.092.

To measure the acidity or alkalinity of a sample, we use the \(p^{H}\) scale.

⇒                     \(H^{+} + NO_{2}\)     ⇄     \(HNO_{2}\)  

when we add \(Hcl_{4}\), then the following takes place

                   \(NO^{-} _{2}\)     +     \(H ^{+}\)  from  \(Hcl_{4}\)   →   \(HNO_{2}\)

⇒   Moles of  \(HNO_{2}\)    =    0.435 - 0.071

                                     =    0.364 mole

⇒   Moles of  \(NO^{-} _{2}\)      =    0.283 - 0.071                                      

                                    =    0.212 mole  

⇒         \(P^{ka}\)   +     \(HNO_{2}\)     =    3.15 ( from the table )

⇒  \(P^{H}\)  after addition

\(P^{H}\)    =    \(P^{ka}\)    +    log( salt / acid )

        =     \(P^{ka}\)   +    log(  \(NO^{-} _{2}\)  / \(HNO_{2}\) )

        =     3.15   +   log(  0.212 / 0.364 )

        =     3.15   +   log( 0.582 )

        =     3.15   +   ( -0.235 )

\(P^{H}\)    =     2.915    

⇒  \(P^{H}\) after deletion

\(P^{H}\)    =    \(P^{ka}\)    +    log( salt / acid )

        =     \(P^{ka}\)   +    log(  \(NO^{-} _{2}\)  / \(HNO_{2}\) )

        =     3.15   +   log(  0.283 / 0.435 )

        =     3.15   +   log( 0.718 )

        =     3.15   +   ( -0.143 )

\(P^{H}\)    =     3.007  

\(P^{H}\)  change    Δ \(P^{H}\)   =   \(P^{H}\)  after addition - \(P^{H}\) after deletion

                                   =   2.915 - 3.007

                     Δ \(P^{H}\)     =  -0.092

Therefore, Δ \(P^{H}\)  is  -0.092 when 0.071 mol hclo4 is added to 1.00 l of a buffer solution that is 0.435 m in hno2 and 0.283 m in no2-.

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Answer:

A because even if its a minor cut, it's always a better choice to inform someone.

Answer:

The correct answer is 5.08 atm

Explanation:

This question tests our knowledge of the Dalton's law of partial pressures which is stated in the question; that the pressure of a mixture of non-reacting gases in a single container is the sum of all the pressures of the individual gases.

It can hence be represented mathematically as Ptotal = Pa + Pb + ...

Ptotal = pressure of methane + pressure of ethane

Ptotal = 3.4 atm + 1.68 atm

Ptotal = 5.08 atm

Answer:

Explanation:

The way you can find this out is first doing 60 seconds times 60 minutes (1 min times 60/ an hour), then you do that answer (3600) times 48 (2 days) and get that answer (172,800) and put that aside. Then do Step 1 again, but do 3600 times 12 this time (half a day) and then add the two answers together (172,800 + 43,200) and you will get 216,000.

Hope this helps!

Answer:

1. D 2.. A 3. C 4. B

Explanation:

just took the quiz

We can classify each rock as intrusive or extrusive and basaltic or granitic as follows; Rock A - Extrusive, Basaltic, Rock B - Intrusive, Granitic, Rock C - Extrusive, Basaltic, and Rock D - Extrusive, Basaltic.

Rock A - Extrusive, Basaltic

Rock A is described as having dark-colored large grains, which indicates a fine-grained texture, typical of extrusive rocks. The presence of dark-colored large grains suggests a basaltic composition.

Rock B - Intrusive, Granitic

Rock B is described as having large crystals and a high percentage of silica, which suggests a coarse-grained texture, typical of intrusive rocks. The high silica content and large crystals indicate a granitic composition.

Rock C - Extrusive, Basaltic

Rock C is described as having a fine-grained texture and being light-colored, which are characteristic features of extrusive rocks. The fine-grained texture suggests a rapid cooling, typical of extrusive rocks, and the light color is indicative of a basaltic composition.

Rock D - Extrusive, Basaltic

Rock D is described as being from the Hawaiian volcano area and having no visible crystals. This indicates a glassy texture, typical of rapidly cooled extrusive rocks. The origin from a volcanic area and glassy texture suggest a basaltic composition.

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Answer:

\(\Delta H=-92.7kJ\)

Explanation:

Hello there!

In this case, according to the given information, we can infer that 890 kJ of energy are released when 1 mole of methane is burned; however, to find the total heat when 1.67 grams are burned, we first need to calculate the moles in this mass of methane:

\(1.67gCH_4*\frac{1molCH_4}{16.04gCH_4}=0.104molCH_4\)

And thus, for calculating the resulting ∆H, we proceed as follows:

\(\Delta H=-890kJ/mol*0.104mol\\\\\Delta H=-92.7kJ\)

Regards!

Answer:  Both A and C

Explanation:

It is a combustion reaction that is exothermic.  It is a chemical reaction.  Choices A and C are both correct, so I'm not certain what criteria are most important in answering.

The concentration of hydronium ion [H3O⁺]  for a solution with a pH of 8.75 is approximately 1.78 x 10⁻⁹ M.

The pH of a solution is defined as the negative logarithm (base 10) of the hydrogen ion concentration ([H3O⁺] ). In this case, the pH is given as 8.75. To find the [H3O⁺]  concentration, we can use the reverse process and take the antilogarithm of the negative pH value.

[H3O⁺] = 10^(-pH)

[H3O⁺] = 10^(-8.75)

Calculating this value, we find:

[H3O⁺]  ≈ 1.78 x 10⁻⁹ M.

Therefore, the concentration of [H3O⁺] in the solution is approximately 1.78 x 10⁻⁹ M.

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Answer:

315.51g/mol

Explanation:

137(33 + (16.00 + 1.01) 2 + 8 [1.01 (2) + 16.00] = 315.51g/mol