When the air resistance can be ignored the velocity of an object dropped initially from rest is given by the following equation where g is free-fall acceleration

A. g*t^2/2
B. g*t
C. g*t/2
D. g

The motion of a spring represents a longitudinal wave.

Option d is correct.

Because the medium's vibrations run parallel to the direction the sound wave travels, sound waves in air (and any other fluid media) are longitudinal waves.

Sound waves are the right response. In longitudinal waves, the particle's medium vibrates in a direction parallel to the wave's propagation. By vibrating in the wave's line of transmission, particles in longitudinal waves move energy from one location to another.

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Answer:

I KNOW THE ANSWER IT WILL COST 30$

Explanation:

The arcsine of 1 is 90 degrees, the critical angle is 90 degrees.the minimum depth (measured to the top of the Batbox) is equal to the height of the Batbox.

To determine the minimum depth of the Batbox below the surface of the water for Batman to remain hidden from the Joker, we need to consider the principle of total internal reflection. When light travels from a medium with a higher refractive index to a medium with a lower refractive index, it can undergo total internal reflection if the angle of incidence exceeds the critical angle. In this case, the light traveling from water (refractive index nw = 1.333) to the Batplastic (refractive index np = 1.333) can undergo total internal reflection at the interface between the two.

To calculate the minimum depth, we need to find the critical angle. The critical angle can be determined using the formula:

Critical angle = arcsin(np/nw)

Given:

Refractive index of water, nw = 1.333

Refractive index of Batplastic, np = 1.333

Calculating the critical angle:

Critical angle = arcsin(1.333/1.333)

Critical angle = arcsin(1)

Since the arcsine of 1 is 90 degrees, the critical angle is 90 degrees.

To ensure that Batman remains hidden, the Batbox should be placed at a depth below the surface of the water such that the light undergoes total internal reflection. In this case, the minimum depth is determined by the height of the Batbox. Therefore, the minimum depth (measured to the top of the Batbox) is equal to the height of the Batbox. However, the specific height of the Batbox is not provided in the question, so it cannot be determined without additional information.

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Assuming standard atmospheric conditions, the air pressure at sea level is approximately 1013.25 hectopascals (hPa) or 1 atmosphere (atm). The air pressure decreases with altitude following the barometric formula, which states that pressure decreases by about 1 hPa for every 8 meters of ascent.

Using this formula, we can estimate the air pressure at 1200 meters above sea level as follows:

1200 m / 8 m per hPa = 150 hPa

Therefore, the hiker on a mountain ridge 1200 meters above sea level would experience an air pressure of approximately 863.25 hPa (1013.25 hPa - 150 hPa) or about 0.85 atm.

Answer:

The entry level is the basic part of any text or power point which needs to be pushed to the higher levels for reading the entire content

The given statement about “Nuclear energy is a clean energy source with virtually no greenhouse gas emissions.” is true, because Nuclear is a zero-emission clean energy source.

Fission is the process by which atoms of uranium are separated to release energy, and this is how nuclear power plants produce electricity. Electricity is produced without the emission of hazardous pollutants often associated with the combustion of fossil fuels by using the heat released by fission to create steam that turns a turbine. The Nuclear Energy Institute (NEI) estimates that in 2020 the United States will have prevented the release of about 471 million metric tons of carbon dioxide. That's more than all other forms of clean energy put together, and it's the same as taking 100 million cars off the road. In addition to preventing acid rain, pollution, lung cancer, and cardiovascular illness, it also cleans the air by thousands of tons annually.

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Answer:

14.68m/s

Explanation:

As per the question, the data provided is as follows

Mass = M = 0.148 kg

Height = h = 11 m

Initial velocity = U = 0 m/s

Final velocity = V

Gravitational force = F

Mass = M

Based on the above information, the speed that hit to the ground is

As we know that

Work to be done = Change in kinetic energy

\(F ( S) = (\frac{1}{2} ) M ( V^2 - U^2 )\)

\(M g h = (\frac{1}{2} ) M ( V^2 - U^2 )\)

\(g h = (\frac{1}{2} ) ( V^2 - U^2 )\)

\(V^2 - U^2 = 2gh\)

\(V^2 - 0 = 2gh\)

\(V = \sqrt{2 g h}\)

\(= \sqrt{2\times9.8\times11}\)

= 14.68m/s

Stopping a 1000 kg car moving at a speed of 174 km/h will be more difficult than stopping an identical car moving at 100 km/h.

This can be explained by using Newton's second law of motion which says that the rate of change of momentum of a body is equal to the force applied.

Therefore, the car moving at 174 km/h has higher momentum and from Newton's second law of motion, a higher force would be required to stop this car.

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Answer:

In picture one because string telephones are best heard when there is more tension on the string

Explanation:

Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

The acceleration due to gravity on the asteroid, given that it has a mass of 1.00×10⁴ kg and a radius of 20.0 m is 1.67×10¯⁹ m/s²

Acceleration due to gravity of planets can be obtained by using the following formula:

g = GM / R²

Where

Now, we shall apply the above formula, to determine the acceleration due to gravity on the asteroid. Details below                                                                                  

g = GM / R²

g = (6.67×10¯¹¹ × 1.00×10⁴) / (20)²

g = 6.67×10¯⁷ / 400

g = 1.67×10¯⁹ m/s²

Thus, we can conclude that the acceleration due to gravity on the asteroid is 1.67×10¯⁹ m/s²

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Answer:

5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.

Explanation:

We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.

Plugging in the values:

(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)

Simplifying:

24 kg m/s = 2 kg v1f + 6 kg v2f

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Plugging in the values:

(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2

Simplifying:

144 J = 1 kg v1f^2 + 3 kg v2f^2

Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:

v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f

Plugging this into the second equation:

144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2

Simplifying and solving for v2f:

144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2

144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2

6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0

Dividing by 6 kg:

v2f^2 - 12 kg m/s v2f + 24 J/kg = 0

Using the quadratic formula:

v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)

v2f = [12 kg m/s ± sqrt(96) m/s]/2

v2f = 6 kg m/s ± 2sqrt(6) m/s

v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s

Plugging these values into the equation we found for v1f:

v1f = 12 m/s - 3v2f

v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s

Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:

v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s

The Title of the interviews Questionnaire is : Community Members' Right to Safe and Healthy Living Questionnaire. The Questionnaire is attached.

A tool for research known as a questionnaire comprises a series of questions formulated to extract data from individuals or a collective of individuals. A systematic approach in acquiring data, which permits researchers to obtain uniform feedback and perspectives from respondents, is termed as structured data collection.

Questionnaires have multiple applications such as conducting surveys, holding interviews, performing assessments, and carrying out evaluations.

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If a plane is moving in a straight line down the tarmac after landing, its displacement will depend on its starting and ending points, its velocity depends on displacement and acceleration depends on velocity.

Assuming the plane is moving in a straight line down the tarmac:

Displacement: The displacement of the plane will depend on the starting point and the end point of its motion. If we take the starting point as the point of touchdown, then the displacement will be the distance between the touchdown point and the current position of the plane on the tarmac.

Velocity: The velocity of the plane can be calculated by dividing the displacement of the plane by the time taken to travel that distance. If we assume that the plane is traveling at a constant speed, then its velocity will be constant as well. If the speed is not constant, then the velocity will be changing over time.

Acceleration: If the plane is slowing down as it travels down the tarmac, then it is experiencing negative acceleration (deceleration). If the plane is speeding up, then it is experiencing positive acceleration. The magnitude of the acceleration can be calculated as the change in velocity over time. If the plane is traveling at a constant velocity, then its acceleration will be zero.

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The parameter that dictates whether a particular solar eclipse appears as a total or an annular eclipse to an observer is the distance between the Moon and the Earth.

A solar eclipse is a celestial event that occurs when the Moon passes between the Sun and the Earth, blocking some or all of the Sun's light from reaching the Earth. Solar eclipses can only occur during a new moon, when the Moon is at its closest point to the Earth (perigee) and aligned with the Sun and Earth. There are three types of solar eclipses: total, partial, and annular. In a total solar eclipse, the Moon completely blocks the Sun's disk, causing the sky to darken and revealing the Sun's outer atmosphere, or corona. This is the most dramatic and rare type of solar eclipse, and it can only be seen from a narrow path on the Earth's surface. In a partial solar eclipse, the Moon only partially covers the Sun's disk, creating a crescent shape. This type of eclipse can be seen from a wider area on the Earth's surface.

Here,

During a total solar eclipse, the Moon passes directly between the Sun and the Earth, blocking the Sun's entire disk and causing the sky to darken. This occurs when the Moon is at a point in its orbit where it is relatively close to the Earth, and its apparent size is larger than the Sun's.

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Answer:

3.88 × 10^-4 m

Explanation:

Given that a  person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?

The total weight = 614 + 85

The total weight = 699N

Let the total area of contact = A

Pressure = Force / A

Substitute all the parameters into the formula

900000 = 699 /A

A = 699 / 900000

A = 7.77 × 10^-4 m

The area of contact between each tire and the ground will be = A/2

That is, 7.77 / 2 = 3.88 × 10^-4 m

Therefore, the area of contact between each tire and the ground is 3.88 × 10^-4 m approximately.

The buoyant force acting on the cylinder is, \(Fb = \rho Ahg\). Here A is the cross-sectional area of the cylinder, h is the height of the cylinder, ρ is the density of the cylinder, and g is the acceleration due to gravity.

This buoyant force is also equal to the volume of the fluid displaced. \(Fb = \sigma h(A-x)g\). Here σ is the density of the fluid.

Equate the above two equations and solve for x.

\(\rho Ahg = \sigma A(h-x)g\\\rho h = \sigma h - \sigma x\\x = \frac{(\sigma - \rho)h}{\sigma}\)

So, the distance x depends on the density of the fluid, density of the cylinder and the height of the cylinder.

1. The density of the cylinder is same and distance x is independent of the diameter of the cylinder. Therefor, there will be no change in the distance x. Hence, the correct answer is No change.

2. Now the height is changing keeping the density same. As the distance x is directly proportional to the height, the distance x will increase.

3. The density of the added liquid is greater than of the water and it does not mix with the water. So, the liquid will settle down and there will be no change in the distance x.

4. The density of the added liquid is less than that of the water and it does not mix with the water. So, the liquid will not settle down and the distance x will change. The change in distance x can be determined as follow:

\(\rho Agh = \sigma' Axg + \sigma A(h-x)g\\\rho h=\sigma' x + \sigma h - \sigma x\\x=(\frac{\sigma - \rho}{\sigma - \sigma'})h\)

Here, σ' is the density of the added liquid.

From the above relation it is clear, that on adding the liquid of the density less than that of water, the denominator term become small ando so the value of x will increase.  

5. On removing some of the water inside the glass, the height of the water column will decrease, but the value of x does not depend on the height of the water column. So, there will be no change in the distance x.

6. The density of the new cylinder is smaller than that of the earlier one. So, the numerator term will increase. Therefore, the value of x will increase.

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Average speed is the ratio of the total distance to total time. The average velocity is the rate at which position changes. That is average velocity is the ratio of total displacement to the total time.

The speed is a scalar quantity and the velocity is a vector quantity.

The distance is the total length of the path of the object, whereas the displacement is the straight or the minimum distance between the initial and the final position of the object.

Therefore when an object completes its motion, the distance traveled by the object can be larger than the displacement.

Thus, an object can have a high average speed but a small average velocity.

Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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Answer:

a) The work done on the gas during an isothermal expansion is given by:

W = nRT ln(V2/V1)

where n is the number of moles of gas, R is the gas constant, T is the temperature, V1 is the initial volume, and V2 is the final volume.

Since the gas is monatomic, we can use the ideal gas law to find the number of moles:

PV = nRT

n = PV/RT

Substituting this expression for n into the equation for work, we get:

W = PV ln(V2/V1)

where we have cancelled out the R and T terms.

Substituting the given values, we get:

W = (1.20e5 Pa)(0.540 m^3) ln(1.25/0.540) = 1.38e4 J

b) The thermal energy transfer Q during an isothermal process is equal to the work done on the gas. Therefore, Q = 1.38e4 J.

c) The change in internal energy ΔU of a gas during an isothermal process is zero, since the temperature of the gas does not change. Therefore, ΔU = 0.

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer:

The speed of the resistive force is 42.426 m/s

Explanation:

Given;

mass of skydiver, m = 75 kg

terminal velocity, \(V_T = 60 \ m/s\)

The resistive force on the skydiver is known as drag force.

Drag force is directly proportional to square of terminal velocity.

\(F_D = kV_T^2\)

Where;

k is a constant

\(k = \frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2}\)

When the new drag force is half of the original drag force;

\(F_D_2 = \frac{F_D_1}{2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_1}{2V_{T2}^2} \\\\\frac{1}{V_{T1}^2} = \frac{1}{2V_{T2}^2}\\\\2V_{T2}^2 = V_{T1}^2\\\\V_{T2}^2= \frac{V_{T1}^2}{2} \\\\V_{T2}= \sqrt{\frac{V_{T1}^2}{2} } \\\\V_{T2}= \frac{V_{T1}}{\sqrt{2} } \\\\V_{T2}= 0.7071(V_{T1})\\\\V_{T2}= 0.7071(60 \ m/s)\\\\V_{T2}= 42.426 \ m/s\)

Therefore, the speed of the resistive force is 42.426 m/s

At terminal speed, the speed of the resistive force will be:

"42.426 m/s".

According to the question,

Skydriver's mass, m = 75 kg

Terminal velocity, \(V_T\) = 60 m/s

Constant = k

We know the relation,

→ \(F_D\) = k\(V_T^2\)

here, k = \(\frac{F_D_1}{V_T_1^2} = \frac{F_D_2}{V_T_2^2}\)

Now,

  \(F_D_2\) = \(\frac{F_D_1}{2}\)

  \(\frac{F_D_1}{V_T_1^2}= \frac{F_D_2}{V_T_2^2}\)

   \(\frac{1}{V_T_1^2} = \frac{1}{2V_T_2^2}\)

By applying cross-multiplication,

  \(V_T_2^2 = \sqrt{\frac{V_T_1^2}{2} }\)

By substituting the above values,

  \(V_T_2\) = 0.7071 (\(V_T_1\))

        = 0.7071 × 60

        = 42.426 m/s

Thus the above response is correct.

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As you pass over the top of the bump, the apparent weight of a 67 kg person in a car is therefore -17.80N.

Constant motion is a sort of motion that takes place when either the object's speed varies by the same amount every second or its distance travelled is the same every second. A car that goes continuously for 5 seconds in a straight line at 20 metres per second is said to be in motion. An object is considered to be moving at a constant speed when it covers the same distance in the same amount of time. When moving at a constant pace, an object covers a certain distance in a fixed amount of time. S = d t is a formula that can be used to express the speed.

The body is said to be moving at a uniform speed if it travels the same distance in the same amount of time. If the body goes in a straight line without changing its direction, the velocity is said to be constant. In all scenarios, there is no acceleration. Recall that the uniform velocity is a constant velocity as well.

-mg+N = -mass (v2/r) -(67(9.8) +N

= -(67(9.30/35) +N

=-17.80N

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The total system momentum would remain the same before and after the collision. Option D

The law of conservation of momentum, which states that when no external forces are exerted on a system of objects, the system's overall momentum will remain constant, is a fundamental principle of physics.

The momenta of all the objects added together in the system prior to an event or interaction are equal to the momenta of the objects added together after the event or interaction.

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Answer: Distance traveled in time t is s

Explanation: Self Explanatory

From the information given,

radius = 6

frequency = 50

a) Period, T is the reciprocal of frequency. This means that

T = 1/frequency

Thus,

T = 1/50 = 0.02

Period = 0.02 s

b) The formula for calculating velocity for an object in circular motion, V is expressed as

V = 2pi x radius/T

By substituting pi = 3.14, radius = 6 and T = 0.02 into the formula,

V = 2 x 3.14 x 6/0.02

V = 1884

Velocity is 1884 rad/s

c) The formula for calculating centripetal acceleration is expressed as

A = V^2/radius

Substituting V = 1884 and radius = 6 into the formula,

A = 1884^2/6 = 591576

Acceleration = 591576 rad/s^2

Answer:

OD and E are the answers because in fourth quadrant X is positive and Y is negative

Explanation:

if u want to know which quadrant has what pairs i have given below

In Quadrant I both x and y are positive,

in Quadrant II x is negative y is positive,

in Quadrant III both x and y are negative, and.

in Quadrant IV x is positive , and y is negative

The speed of the microwaves is 3 × 10^10 meters per second. This result indicates that microwaves, like all electromagnetic waves, travel at the speed of light in a vacuum.

The speed of a wave can be calculated using the formula: speed = frequency × wavelength. In this case, the frequency of the microwaves is given as 10,000 million Hz, which is equivalent to 10,000 × 10^6 Hz or 10^10 Hz. The wavelength is given as 0.03 m.

Plugging these values into the formula, we have:

Speed = (10^10 Hz) × (0.03 m)

Simplifying the calculation, we find:

Speed = 3 × 10^10 m/s

Therefore, the speed of the microwaves is 3 × 10^10 meters per second. This result indicates that microwaves, like all electromagnetic waves, travel at the speed of light in a vacuum. The speed of light is approximately 3 × 10^8 meters per second, so microwaves have a slightly higher speed due to their longer wavelength. It's important to note that the speed of light is a fundamental constant of nature and does not depend on the properties of the specific electromagnetic wave being considered.

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