Which absolute value functions will be narrower than the parent function?

According to the 1991 census, there are about 43406932 people in our country who speak Urdu. Which of the following is the closest approximation of this number?

A 4 lakhs

B 43 lakhs

C 4 crores

D 43 crores

→ C 4 crores

Explaination :

2 - Unit place

3-tens place

9- hundred place

6 - thousand place

0- ten thousand place

4 - lakh place

3 - ten lakh place

4 - crore place

hence , closest approximation of this number is 4 crores.

Approximation of number is 4 crores.

Anything that is similar to something else but not exactly equal to it is an approximation. By rounding, a number can be approximated. By rounding the values contained within a calculation prior to performing the operations, it can be approximated.

Given census of a country is 43406932

Adjusting numbers to the closest 10, 100, 1,000

To rough to the closest ten, check out at the digit during the tens section.

Look at the digit in the hundreds column to approximate to the nearest hundred. Take a look at the digit in the thousands column to determine the nearest thousand.

so the number to the closest is crore

Hence the closest approximation of this number is 4 crores.

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a)  The electrical potential V (center) at the center C of the circle due to the charges Q1 and Q2 is -2.30 V.

b) The total electrical potential at the point P due to charge Q1 and Q2 , located at a distance of 6.71 cm is -1.78V.

Given that:

Radius of the circle, r = 8.20cm

Charge distributed along one-quarter of the circumference of the circle,

Q1 = +4.20pC

Charge distributed along 3/4th of the circumference of the circle,

Q2 = 25.20pC

Distance of the point from the center, d = 6.71cm

The electric potential at infinity is. V = 0

Using the concept of potential at a point on a thin rod, we can obtain the individual potential due to each charge. The sum of these values ​​can now be used to obtain the desired potential value at the center and at the point, taking into account the distance to the point.

Formula:

The potential due to a point charge at a distance r from the point charge is determined by the equation V = \(\frac{1}{4\pi E_0} * \frac{q}{r}\)        ---------------- (1)

The potential due to the collection of point charges is determined by formula:

V = ∑\(\frac{1}{4\pi E_0} * \frac{q}{r}\)                 -------------------- (2)

(a) The potential VQ1 at the center C of the circle due to the charge Q1 is determined using equation (i) as:

\(V_Q_1 = \frac{1}{4\pi E_0} * \frac{Q_1}{R}\)              --------------------- (3)

Here, R is the radius of circle

The potential VQ1 at the center C of the circle due to the charge Q1 is determined using equation (i) as:

\(V_Q_1 = \frac{1}{4\pi E_0} * \frac{Q_2}{R}\)                 ----------------------- (4)

Now the potential V(center) at the center C of the circle due to charges Q1 and Q2 is the sum of the potential due to charge Q1 and the potential due to charge Q2. This is given using equations (a) and (b) in equation (ii) as:

    \(V_Center = \frac{1}{4\pi E_0} * \frac{Q_1}{R} + \frac{1}{4\pi E_0} * \frac{Q_2}{R}\)

⇒ \(V_Center = \frac{1}{4\pi E_0} *( \frac{Q_1}{R} + \frac{Q_2}{R})\)

⇒ 9.0 × 10⁹Nm²/C₂ (\(\frac{4.20*10^-12 C}{0.082m} +\frac{-25.2*10^-12C}{0.082m}\))

⇒ -2.30V

The electrical potential V (center) at the center C of the circle due to the charges Q1 and Q2 is -2.30 V.

(b) From the above figure the r between each charged particle and the point P is given as:

\(r = \sqrt{R^{2}+D^{2} }\)                    

In the figure above, r between each charged particle and point P is defined as: ="1662703245948 "

\(V_Q_1 = \frac{1}{4\pi E_0} * \frac{Q_1}{\sqrt{R^{2} + D^{2} } }\)                  ------------------ (5)

Again, the electric potential at point P due to charge Q2 is given using equation (i) as follows:
\(V_Q_1 = \frac{1}{4\pi E_0} * \frac{Q_2}{\sqrt{R^{2} + D^{2} } }\)                   -------------------- (6)

A The potential at point P due to charge Q2 is determined using equation (i): The potential of charge Q1 and the potential of charge Q2. This is given using equations (c) and (d) in equation (ii) as:

\(V_P = 9.0 * 10^9Nm^2/C^2 (\frac{4.20*10^-12C-6(4.20*10^-12C)}{\sqrt{(0.082m)^{2} + (0.082m)^{2} } })\)

= -1.78V

The total electrical potential at the point P due to charge Q1 and Q2 , located at a distance of 6.71 cm is -1.78V.

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The domain of the given function is (-1, ∞), the vertical asymptote is x = -1, and the x-intercept is (-1/2, 0).

The given function is y = 1 + log₂(x + 1).Domain: Let's find out the domain of the given function . y = 1 + log₂(x + 1)The logarithmic function is defined only for positive values of x. Thus, the argument (x + 1) in the given function should be greater than 0.(x + 1) > 0x > -1 .

Therefore, the domain of the given function is (-1, ∞).Vertical asymptote: The vertical asymptote of a logarithmic function can be found at the point where the denominator of the function becomes zero. x + 1 = 0x = -1 .

Therefore, the vertical asymptote of the given function is x = -1.x-intercept: The x-intercept of a function is the point at which the graph of the function intersects the x-axis. This point can be found by setting y = 0.0 = 1 + log₂(x + 1)log₂(x + 1) = -1(x + 1) = 2⁻¹x + 1 = 1/2x = -1/2Therefore, the x-intercept of the given function is (-1/2, 0).Thus, the domain of the given function is (-1, ∞), the vertical asymptote is x = -1, and the x-intercept is (-1/2, 0).

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The probability that a randomly selected car had automatic transmission or air conditioning or both is 0.92517.

Total number of cars sold, n = 147

Let A denotes the car is air conditioning.

And B denotes the car is automatic message transmission.

A = 81

B = 82

Number of cars that neither of these extras = 11

Only A = 54

Only B = 55

Now,

P(A ∩ B') = A/n

P(A ∩ B') = 81/147

P(A ∩ B') = 0.551

P(A' ∩ B') = 11/147

P(A' ∩ B') = 0.07483

The probability that a randomly selected car had automatic transmission or air conditioning or both is:

P(A ∪ B) = 1 - P(A' ∩ B')

P(A ∪ B) = 1 - 0.07483

P(A ∪ B) = 0.92517

The likelihood that an automobile chosen at random has either an automatic gearbox, air conditioning, or both is 0.92517.

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When we divide the 464 by 60 we get the following remainder in our answer that is 44.

The Remainder is the name for the value that is left behind after division. If an amount (reward) cannot be divided completely with another number, we are left with only a meaning (divisor). The remaining is the name for this amount. For instance, 10 is not precisely divisible by 3. We can calculate 3 x 3 = 9 because that is the closest value.

7.733333333333333

=7 44/60 ⇔ 7 R 44

464 divided by 60

=7 with a remainder of 44

Here, we provide you the outcome of the dividing with remainder, often known as the Euclidean division, along with a brief explanation of the following terms:

464 divide by 60 yields a quotient and residual of 7 R 44.

464 is the dividend & 60 is the divisor; the division (numeric division) of 464/60 is 7; the remainder ("left over") is 44.

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Net present value is a measure of profitability. The NPV of an investment is the net cash inflow received over the project's life, less the initial cash outflow, adjusted for the time value of money.

A higher NPV means the project is more lucrative. The profitability index measures the benefit-cost ratio of a project and is calculated by dividing the present value of future cash flows by the initial cash outflow. A profitability index greater than one indicates that the project will be profitable, whereas a profitability index less than one indicates that the project will not be profitable.

Calculation of Net Present Value (NPV) of Project AInitial Outlay = $454,000Net annual cash flows = $68,000Discount Rate = 9%Use the PV of an annuity of $1 table to determine the PV of net cash flows.Using the formula for NPV,NPV of Project A = PV of net cash flows – Initial OutlayNPV of Project A = 68,000 × 7.63930 – 454,000NPV of Project A = $56,201.85Calculation of Profitability Index of Project AProfitability Index of Project A = Present value of future cash flows / Initial OutlayProfitability Index of Project A = 68,000 × 7.63930 / 454,000Profitability Index of Project A = 1.14

Calculation of Net Present Value (NPV) of Project BInitial Outlay = $300,000Net annual cash flows = $47,000Discount Rate = 9%Use the PV of an annuity of $1 table to determine the PV of net cash flows.Using the formula for NPV,NPV of Project B = PV of net cash flows – Initial OutlayNPV of Project B = 47,000 × 6.10338 – 300,000NPV of Project B = $37,100.86Calculation of Profitability Index of Project BProfitability Index of Project B = Present value of future cash flows / Initial OutlayProfitability Index of Project B = 47,000 × 6.10338 / 300,000Profitability Index of Project B = 0.96

The NPV and profitability index calculations show that project A is the better investment since it has a higher NPV and profitability index than project B.

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Answer:

3 1/9

Step-by-step explanation:

6 feet 7 inches

1 feet = 12 inches

6 feet = 6(12) = 72 inches

6 feet 7 inches = 72 + 7 = 79 inches

Answer:

79 inches

The original equation and the orthogonal equation are the same, we can conclude that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves.

To show that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves, we need to take the derivative of the equation and set it equal to -1/b^2, the slope of the orthogonal line.

First, we take the derivative of the equation with respect to x:

2x/a^2 = -2y/b^2 * dy/dx

Simplifying, we get:

dy/dx = -b^2*x/a^2*y

Now, we set this equal to -1/b^2:

-b^2*x/a^2*y = -1/b^2

Cross-multiplying and simplifying, we get:

x/a^2*y = 1/b^2

Finally, we can rearrange this equation to get:

y = b^2*x/a^2

This equation represents the orthogonal family of curves to the original family of conics. Since the original equation and the orthogonal equation are the same, we can conclude that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves.

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Therefore, the vector form of the equation y = x² - 8x + 15 is y = (x - 4)² + 14. The vertex of the parabola is at the point (4, 14).

To convert the quadratic equation y = x² - 8x + 15 from standard form to vertex form, we need to complete the square by adding and subtracting a constant term. Here's the step-by-step explanation:

Factor the coefficient of x²: The coefficient of x² is 1, so we don't need to factor it.

Group the x terms: Rewrite the quadratic equation as y = (x² - 8x) + 15.

Complete the square: To complete the square, we need to add and subtract a constant term that will make the expression inside the parentheses a perfect square trinomial. The constant we need to add is half of the coefficient of x, squared: (8/2)² = 16.

y = (x² - 8x + 16 - 16) + 15 // add and subtract 16

y = (x - 4)² - 1 + 15 // factor and simplify

Simplify: Now we can simplify the expression by combining the constants -1 and 15 to get 14.

y = (x - 4)² + 14

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Answer:

(3y+z)/20

Step-by-step explanation:

Begin by moving 3y to the right side of your equation:

20x=3y+z

Then divide both sides by 20 isolating x on one side of your equation:

x=(3y+z)/20

The required solution of the following equation 20x - 3y = z is

x=(3y+z)/20

An equation is a mathematical statement that is made up of two expressions connected by an equal sign. Equation, statement of equality between two expressions consisting of variables and/or numbers.

Given:

The following equation is

20x - 3y = z

According to given question we have

The equation is

20x - 3y = z

By simplifying we have to solve in terms of x

By move 3y to the right side of your equation:

20x=3y+z

Then divide both sides by 20 isolating x on one side of your equation:

x=(3y+z)/20

Therefore, the required solution of the following equation 20x - 3y = z is

x=(3y+z)/20

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For greatest integer function,

domain :  set of all real numbers (ℝ)

range : set of all integers (ℤ)

We know that the greatest integer function of any real number n is the integer which is less than or equal to the given number n.

The mathematical definition of greatest integer function is :

f(x) = minimum { p ∈ Z ; p ≤ x }

where Z is the set of integers.

A greatest integer function is also known as the floor function.

The symbol to represent greatest integer function is  ⌊ ⌋.

We can write greatest integer function for x as ⌊x⌋

The for x = 1.98,

⌊1.58⌋ = 1

From above definition of floor function, we can say that the domain of greatest integer function is the set of all real numbers (R) whereas the range of  is the set of all integers (Z).

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The distance from the moon to Jakarta is 240,127.83 miles

To get the distance from moon to Jarkata, we will use the intersecting chord theorem;

According to the theorem,

251,308* (238,857) = 249,978 * x

x is the distance from the moon to Jakarta

60,026,674,956 =  249,978 * x

x = 60,026,674,956/249,978

x = 240,127.83

Hence the distance from the moon to Jakarta is 240,127.83 miles

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Answer:

240,127.83

Step-by-step explanation:

The value of the probability represented by P(Take the bus | Sophomore) is 0.83

Conditional probabilities are probabilities that only occurred because an event has already occurred i.e. they are dependent on the initial event

From the table of values in the question, we have the following parameters:

The required probability represented by P(Take the bus | Sophomore ) = [?] is then calculated as:

P(Take the bus | Sophomore) = Number of students that (Take the bus and Sophomore) divided by Number of students that are (Sophomore)

Substitute the known values in the above equation

P(Take the bus | Sophomore) = 25/(2 + 25 + 3)

Evaluate the sum in the denominator

P(Take the bus | Sophomore) = 25/30

Evaluate the above quotient

P(Take the bus | Sophomore) = 0.83

Hence, the value of the probability represented by P(Take the bus | Sophomore) is 0.83

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Answer:

206.25

Step-by-step explanation:

825/2=412.5

412.5/2=206.25

∠CFA ≅ ∠EDA (By Transitive Property of Congruence).

Given:

Three lines AD, CF, and BE are intersecting each other at the midpoint O.

To prove:

∠CFA ≅ ∠EDA

Proof:

Given that AD, CF, and BE intersect at the midpoint O.

By definition of a midpoint, OA ≅ OD, OB ≅ OE.

OA = OD and OB = OE.

Triangle OAD ≅ Triangle OBE (By Side-Side-Side congruence).

∠OAD ≅ ∠OBE (By Corresponding Parts of Congruent Triangles are Congruent).

∠CFA and ∠EDA are vertical angles.

∠OAD ≅ ∠CFA and ∠OBE ≅ ∠EDA (By Vertical Angles are Congruent).

Therefore, ∠CFA ≅ ∠EDA (By Transitive Property of Congruence).

Hence, it is proven that ∠CFA ≅ ∠EDA.

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The population as an exponential function of time t is given by \(n(t) = 2,000,000 * e^(0.022t)\) when the initial value is 2 million.

The population has a yearly per capita growth rate of 2.2% and the initial value is 2 million, we can express the population as an exponential function using the formula:

\(n(t) = a * e^(rt)\)

In this formula, n(t) represents the population as a function of time t, a is the initial value, e is Euler's number (approximately 2.71828), and r is the annual growth rate expressed as a decimal.

The exponential function for the population with an initial value of 2 million and an annual growth rate of 2.2%, we substitute the given values into the formula:

\(n(t) = 2 * e^(0.022t)\)

To simplify the equation, we can multiply both sides by 1,000,000:

\(n(t) = 2,000,000 * e^(0.022t)\)

Therefore, the population as an exponential function of time t is given by \(n(t) = 2,000,000 * e^(0.022t)\) when the initial value is 2 million.

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Answer: 7z+6

Step-by-step explanation:

Question 1: The sum of the angles in the garden is 540 degrees. Without knowing the number of sides of the garden, we cannot determine the measure of each individual angle.

Question 2:  angle DAB is 90 degrees.

Question 3:  the diagonals of a rhombus are perpendicular and bisect each other, we can check whether the diagonals of ABCD satisfy these properties. The midpoint of BD is (0, 4), which is the same as the midpoint of AC. Therefore, the diagonals bisect each other.

Question 1:

To find the angle measures of each vertex of the garden, we need to use the fact that the sum of the angles in any polygon is (n-2) x 180 degrees, where n is the number of sides of the polygon. Since we do not know the number of sides, we can divide the garden into triangles and find the sum of the angles in each triangle.

Let's call the angles of the first triangle a, b, and c. Since the triangle has three sides, we know that a + b + c = 180. Let's call the angles of the second triangle d, e, and f, and the angles of the third triangle g, h, and i. Then we have:

a + b + c = 180

d + e + f = 180

g + h + i = 180

We can solve this system of equations by substituting known values. We are given that:

b + d + f + h = 360

Substituting b + d + f for 180 - a and f + h + i for 180 - g, we get:

(180 - a) + (180 - c) + (180 - g) = 360

Simplifying and solving for a + c + g, we get:

a + c + g = 540

Question 2:

We are given that diagonals AC and BD of parallelogram ABCD intersect at point A. We need to find the measure of angle DAB, which is denoted by x in the diagram.

Since ABCD is a parallelogram, we know that opposite angles are congruent. Therefore, angle ABC is also equal to 45 degrees. We can use the fact that opposite angles of a parallelogram are congruent to find the measure of angle BCD, which is also equal to 45 degrees.

Now we have a triangle ABD, and we can use the fact that the sum of the angles in a triangle is 180 degrees to find x:

x + 45 + 45 = 180

Simplifying, we get:

x = 90 degrees

Question 3:

To determine whether quadrilateral ABCD is a rectangle, rhombus, or square, we need to examine the properties of the diagonals.

First, we need to find the coordinates of the midpoint of diagonal AC. Using the midpoint formula, we get:

Midpoint of AC = ((-2 + 2)/2, (6 + 2)/2) = (0, 4)

Next, we need to find the slope of diagonal AC. Using the slope formula, we get:

Slope of AC = (6 - 2)/(-2 - 2) = -1

Now we can find the equation of line AC using the point-slope formula:

y - 4 = -1(x - 0)

y = -x + 4

Similarly, we can find the equation of line BD:

y - 2 = 1(x + 2)

y = x

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(x, y) is an element of the set c × d, since x is an element of c and y is an element of d.

Since (x, y) was an arbitrary element in a × b, we can conclude that every element in a × b is also in c × d. Thus, we have shown that if a ⊆ c and b ⊆ d, then a × b ⊆ c × d.

To show that if a ⊆ c and b ⊆ d, then a × b ⊆ c × d, follow these steps:

Step 1: Understand the notation.
a ⊆ c means that every element in set a is also in set c.
b ⊆ d means that every element in set b is also in set d.

Step 2: Consider the Cartesian products.
a × b is the set of all ordered pairs (x, y) where x ∈ a and y ∈ b.
c × d is the set of all ordered pairs (x, y) where x ∈ c and y ∈ d.

Step 3: Show that a × b ⊆ c × d.
To prove this, we need to show that any ordered pair (x, y) in a × b is also in c × d.

Let (x, y) be an arbitrary ordered pair in a × b. This means that x ∈ a and y ∈ b.

Since a ⊆ c, we know that x ∈ c because every element in set a is also in set c.
Similarly, since b ⊆ d, we know that y ∈ d because every element in set b is also in set d.

Now, we have x ∈ c and y ∈ d, so the ordered pair (x, y) belongs to c × d.

Step 4: Conclusion
Since any arbitrary ordered pair (x, y) in a × b also belongs to c × d, we can conclude that a × b ⊆ c × d.

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Answer:

The question is not clearly stated, but I can correctly infer that you wanted to ask the question below:

Out of 150 members, 120 took part, what is the percentage of the total that took part:

Answer:

80%

Step-by-step explanation:

The question is asking us to find what percentage of 150 is 120

Let the percentage of 150 that is 120 be x

x % of 150 = 120

x/100 × 150 = 120

0.01x × 150 = 120

0.01x = 120 ÷ 150 = 0.8

x = 0.8 ÷ 0.01 = 80

∴ 120 = 80% of 150

The margin of error at a 99% confidence level is 8.36.

The margin of error at a 99% confidence level based on a larger sample of 275 observations is 4.14.

a. Yes, the condition that X−X− is normally distributed is satisfied for a sample size of 69 by the central limit theorem.

b. The margin of error at a 99% confidence level can be computed using the formula:

Margin of error = z* (sigma / sqrt(n))

where z* is the z-score corresponding to a 99% confidence level, sigma is the known standard deviation, and n is the sample size.

The z-score for a 99% confidence level is 2.576 (from the z table).

Substituting the given values, we get:

Margin of error = 2.576 * (27.5 / sqrt(69)) = 8.36

c. The margin of error at a 99% confidence level based on a larger sample of 275 observations can be computed using the same formula:

Margin of error = z* (sigma / sqrt(n))

where z* is the z-score corresponding to a 99% confidence level, sigma is the known standard deviation, and n is the sample size.

The z-score for a 99% confidence level is still 2.576 (from the z table).

Substituting the given values, we get:

Margin of error = 2.576 * (27.5 / sqrt(275)) = 4.14

d. The margin of error is inversely proportional to the square root of the sample size. As the sample size increases, the margin of error decreases. Therefore, the margin of error with n = 275 will be smaller than the margin of error with n = 69, leading to a narrower confidence interval.

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The probability that x is less than or equal to 38 is 0.9861.

For a normally distributed set of data, given the mean and standard deviation, the probability can be determined by solving the z-score and using the z-table.

First, solve for the z-score using the formula below.

z-score = (x – μ) / σ

where x = individual data value = 38

μ = mean = 5

σ = standard deviation = 15

z-score = (38 - 5) / 15

z-score = 33 / 15

z-score = 2.2

Find the probability that corresponds to the z-score in the z-table. (see attached images)

z-score =  2.2

probability = 0.9861

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A customer would  be charged $ 52 for an international phone call that started at 9:35 p.m. and ended at 11:15 p.m. the same day.

Charge for first 5 charged = $ 4.50

Charge for additional time = $ 0.50 per minute

Starting time = 9:35 p.m.

End time = 11:15 p.m.

Total minutes = 100 minutes

Total charge = 4.50 + (95 x 0.50)

                  = 4.50 + 47.50

                  = 52.00

Hence, a customer would  be charged $ 52 for an international phone call that started at 9:35 p.m. and ended at 11:15 p.m. the same day i.e. for 100 minutes.

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The theoretical domain is all real numbers greater than or equal to one and less than or equal to two. Then the correct option is C.

Inequality is simply a type of equation that does not have an equal sign in it. Inequality is defined as a statement about the relative size as well as is used to compare two statements.

Kellen runs for at least 1 hour but for no more than 2 hours. He runs at an average rate of 6.6 kilometers per hour. The equation that models the distance he runs for t hours is d = 6.6t

Then the domain of the function d will be a real number.

But in the problem, the value of t is more than or equal to one but less than or equal to two.

1 ≤ t ≤ 2

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Answer:

B

Step-by-step explanation:

(To save time, I'm going to use x instead of θ)

So we have the expression:

\((\sin(x)-\cos(x))^2+(\sin(x)+\cos(x))^2\)

First, expand these binomials:

\(=(\sin^2(x)-2\sin(x)\cos(x)+\cos^2(x))+(\sin^2(x)+2\sin(x)\cos(x)+\cos^2(x))\)

Combine like terms:

\(=\sin^2(x)+\sin^2(x)+\cos^2(x)+\cos^2(x)-2\sin(x)\cos(x)+2\sin(x)\cos(x)\\=2\sin^2(x)+2\cos^2(x)\)

Factor out a 2:

\(=2(\sin^2(x)+\cos^2(x))\)

The expression inside the parentheses is the Pythagorean Identity:

\(\sin^2(x)+\cos^2(x)=1\)

Substitute:

\(=2(1)\\=2\)

The answer is B.