Answer:
F= 45 N
Explanation:
Choose the measure that cannot be found using a box-and-whisker plot.
A. mean
B. first quartile
C. range
D.median
how much time after the stage-two firing will it take for the rocket to fall back to the launch pad?
After 30.15 sec the stage-two firing will it take for the rocket to fall back to the launch pad.
What is projectile motion?
When a particle is thrown obliquely close to the Earth's surface, it travels along a curved path while experiencing constant acceleration. Always pointing in the direction of the Earth's center is this curving path. Such a particle's motion is referred to as projectile motion, and its trajectory is known as the projectile's trajectory.
In the first stage of a two-stage rocket, the rocket is fired from the launch pad starting from rest but with a constant acceleration of 3.50 m/s² upward. At 25.0 s after launch, the second stage fires for 10.0 s, which boosts the velocity of the rocket to 132.5 m/s upward at 35.0 s after launch.
The formula is
s = ut + 1/2at²
In the initial stage, the velocity is zero, acceleration is a = 3.50 m/s², t = 25 sec.
s = 0 ×25+ 1/2× 3.50 × 25²
s = 1,093.75 m
In the next stage, the initial velocity is 132.5 m/s and at the highest point the velocity is 0 m/s and acceleration is a = -9.8 m/s
v² - u² =2as
0² - 132.5² = 2 × (-9.8) × s
s = 895.73
The maximum height of the rocket is 1,093.75 + 895.73 = 1989.48 m
When the rocket is fall the initial velocity is u = 0 m/s, acceleration a = -9.8 m/s, s = 1989.48 m
s = ut + 1/2at²
1989.48 = 0× t + 1/2 ×9.8× t²
t² = 406.01
t = 20.15 s
The total time is 10 + 20.15 s =30.15 s
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Complete question:
In the first stage of a two-stage rocket, the rocket is fired from the launch pad starting from rest but with a constant acceleration of 3.50 m/s2 upward. At 25.0 s after launch, the second stage fires for 10.0 s, which boosts the rocket's velocity to 132.5 m/s upward at 35.0 s after launch. This firing uses up all the fuel, however, so after the second stage has finished firing, the only force acting on the rocket is gravity. Air resistance can be neglected.
How much time after the stage-two firing will it take for the rocket to fall back to the launch pad?
130 An object, initially at rest, is dropped from a height of 12.0m. The change in gravitational potential
energy when it falls to the ground is 565J.
The frictional forces are negligible
mgh
What is its speed when it hits the ground?
A
4.71 m/s
B
15.5m/s
C 47.1 m/s
D 240 m/s
The speed when it hits the ground is option (B) 15.5 m/s.
To determine the speed of the object when it hits the ground, we can use the principle of conservation of energy. The initial potential energy of the object is converted into kinetic energy as it falls.
The change in gravitational potential energy is given as ΔPE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.
We know that ΔPE = 565 J, and the height h = 12.0 m.
Since the object is initially at rest, its initial kinetic energy is zero.
The total mechanical energy (sum of potential and kinetic energy) is conserved, so:
ΔPE = ΔKE
mgh = (1/2)mv^2
Here, m cancels out, giving:
gh = (1/2)v^2
Substituting the known values:
(9.8 m/s^2)(12.0 m) = (1/2)v^2
117.6 = (1/2)v^2
Dividing both sides by (1/2):
235.2 = v^2
Taking the square root of both sides:
v ≈ 15.33 m/s
Therefore, the speed of the object when it hits the ground is approximately 15.33 m/s.
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A water hose 2.50 cm in diameter is used by a gardener to fill a 30.0 L bucket. The gardener notes that it takes 1.00 min to fill the bucket. A nozzle with an opening of cross-sectional
The speed of the water flowing through the hose is approximately 0.50 m/s.
How do we calculate the speed of the water flowing through the hose?To calculate the speed of the water flowing through the hose, we can use the equation v = Q/A, where v represents the velocity, Q is the volume flow rate, and A is the cross-sectional area of the hose's opening.
First, we need to find the volume flow rate Q, which is the amount of water passing through the hose per unit time. In this case, the gardener fills a 30.0 L (or 0.03 m³) bucket in 1.00 minute. Therefore, the volume flow rate is Q = 0.03 m³ / 1.00 min = 0.03 m³/min.
Next, we need to determine the cross-sectional area A of the hose's opening. The diameter of the hose is given as 2.50 cm, so the radius (r) is half of that, or 1.25 cm (0.0125 m). The cross-sectional area can be calculated as A = πr² = π(0.0125 m)².
Now, we can substitute the values into the equation v = Q/A to find the velocity: v = (0.03 m³/min) / (π(0.0125 m)²) ≈ 0.50 m/s.
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an archer shot a 0.06 kg arrow at a target. The arrow accelerated at 5,000 m/s2 to reach a speed of 50.0 m/s2 as it left the bow. During this acceleration what was the net force on the arrow to the nearest newton?
Answer:
300
Explanation:
i answered it and got it right
if rain drops of equal size fall with terminal velocity of 0.50m/s. what will be the terminal velocity if the drops collaspe to form a big drop?
Answer:
0.25m/s
Explanation:
m1v1 =m2 v2. law of conservation the of momentum. since they smash together to form a big drop M2 =2m1
m1*0.50m/s=2m1*v2
V2= m1*0.50m/s÷2m1
V2= 0.25m/s
4. A meteorite travels at 15 km/s before reaching Earth's
atmosphere. Calculate how far it travels in 12 s. (Distance)
Answer:
180 km
Explanation:
velocity (v) = distance (s) / time (t)
From there we get that the distance is: s=v*t
s = 15 km/s * 12 s
s =180 km
V = ?
d= 15 m left
t = 5 s
What is the velocity?
Answer:
Velocity= 3\(ms^{-1}\)
Explanation:
Formula to find velocity = Displacement/time taken
therefore, velocity= 15/5 ➤ Velocity = 3 \(ms^{-1}\)
as part of a lab experiment, allison uses an air-track cart of mass to compress a spring of constant by an amount from its equilibrium length. the air track has negligible friction. when allison lets go, the spring launches the cart. what cart velocity should she expect after it is launched by the spring?
Cart velocity should she expect after it launched by the spring is: 0.63 m/s.
When Allison compresses the spring of constant k by an amount x from its equilibrium length, she should expect the cart to be launched with a velocity given by the equation v = (kx)1/2. In other words, the cart velocity is determined by the spring constant and the amount the spring is compressed from equilibrium.
To calculate the expected cart velocity, multiply the spring constant k by the amount the spring is compressed from equilibrium x, then take the square root of the result. For example, if Allison compresses the spring by 0.2 m from its equilibrium length, and the spring constant is 10 N/m, the cart velocity should be (10 * 0.2)1/2, or approximately 0.63 m/s.
It's important to note that the air track has negligible friction, so all of the energy initially stored in the compressed spring is transferred to the cart, giving it a certain velocity. With this in mind, Allison should expect the cart velocity to be determined solely by the spring constant and the amount the spring is compressed from equilibrium.
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Which location, 23 degrees or 48 degrees would experience the same earthquake at stronger intensity?Explain why.
Answer:
48 degress
Explanation:
An earthquake causes many different intensities of shaking in the area of the epicenter where it occurs. So the intensity of an earthquake will vary depending on where you are. Sometimes earthquakes are referred to by the maximum intensity they produce. In the United States, we use the Modified Mercalli Scale. Earthquake intensity is a ranking based on the observed effects of an earthquake in each particular place. Therefore, each earthquake produces a range of intensity values, ranging from highest in the epicenter area to zero at a distance from the epicenter.
A 5kg traveling at 4 m/s slams into a 1kg object and sticks to it. What will the final velocity of the two objects be?
Answer:
Below
Explanation:
Using conservation of momentum
mv = mv
5(4) + 1(0) = (4+1) v
( this assumes the 1 kg mass was not moving before being struck)
20 = 5 v
v = 4 m/s
A gun is fired with muzzle velocity 1099 feet per second at a target 4750 feet away. Find the minimum angle of elevation necessary to hit the target. Assume the initial height of the bullet is 0 feet, neglect air resistance, and give your answer in degrees.
A gun is fired with muzzle velocity 1099 feet per second at a target 4750 feet away. The minimum angle of elevation necessary to hit the target is approximately 15.2 degrees.
To find the minimum angle of elevation, we can use the equation for the horizontal range of a projectile. The horizontal range is the distance traveled by the bullet in the horizontal direction, which in this case is 4750 feet. The equation for the horizontal range is: R = (v^2 * sin(2θ)) / g
where R is the range, v is the muzzle velocity, θ is the angle of elevation, and g is the acceleration due to gravity.
Rearranging the equation to solve for θ, we have: θ = 0.5 * arcsin((R * g) / v^2). Plugging in the given values, we have: θ = 0.5 * arcsin((4750 * 32.2) / (1099^2))
Evaluating this expression, we find that the minimum angle of elevation necessary to hit the target is approximately 15.2 degrees. This means that the gun should be elevated at an angle of approximately 15.2 degrees above the horizontal in order to hit the target 4750 feet away.
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With all of the electric wires and current running through your house, what direction would a compass point if you were standing in the middle of your room? Why is this? What property of magnetic fields does this demonstrate, and how would the magnetic field lines look in this region?
1) The direction it points depends on the direction of the electric current in the wires.
2) The magnetic field lines in the region would form circles around each individual wire carrying current.
3) This is because of the right-hand rule
Where does the current point?The magnetic field produced by the electric current forms a circular magnetic field around the wire in accordance with the right-hand rule, which is applicable to conventional current flow.
The current's flow direction determines the direction of the magnetic field lines. The curled fingers of your right hand, which is holding the wire with your thumb pointing in the direction of the current flow, would point in the direction of the magnetic field.
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What acceleration would be achieved by a 5N thrust motor in a 0.30kg
Answer:
F=ma
5N=0.3a
a=5/0.3=16.66m/s²
PLEASE GIVE BRAINLIEST
Answer:
16.7
Explanation:
acceleration=force/mass
What is the formula for acceleration? ( PLEASE HELP! ALSO IF YOU GET B IT'S WRONG BECAUSE I ALREADY PUT THAT AND IT WAS WRONG sorry caps)
A: Final speed-initial speed ________________________ time
B: Net force = Mass x acceleration
C: Mass x Velocity
D: Force a 5N Force B 10N Net force of forces A and B 15N
Answer:
option A is correct
Explanation:
acceleration the time rate of change of velocity or speed so
a=Δv/t
Δv=vf-vi
Δv= final speed-initial speed
now a=final speed-initial speed/time
The seismogram shows P-wave and S-wave arrival times at a seismic station following an earthquake. The distance from this seismic station to the epicenter of the earthquake is approximately
answer choices
O 1,600 km
O 3,200 km
O 4,400 km
O 5,600 km
Based on the time difference between the P-wave and S-wave arrivals on the seismogram, the approximate distance from the seismic station to the earthquake epicenter is calculated to be 70 kilometers. However, the given answer choices do not match this distance.
To calculate the distance to the earthquake epicenter using the given seismogram, we need to determine the time difference between the P-wave and S-wave arrivals. Let's assume we have the following information:
P-wave arrival time: tP
S-wave arrival time: tS
Calculate the time difference between the P-wave and S-wave arrivals:
Time Difference = tS - tP
Determine the average wave velocity for P-waves and S-waves in the specific geological region. Let's assume the velocities are:
P-wave velocity: VP
S-wave velocity: VS
Calculate the distance to the epicenter using the formula:
Distance = (Time Difference) * (P-wave velocity)
Note: Since S-waves travel slower than P-waves, we use the P-wave velocity to calculate the distance.
Let's assume the given seismogram provides the following values:
P-wave arrival time: tP = 10 seconds
S-wave arrival time: tS = 30 seconds
P-wave velocity: VP = 5 km/s
Calculate the time difference:
Time Difference = tS - tP
= 30 s - 10 s
= 20 seconds
Assume the P-wave velocity:
P-wave velocity: VP = 5 km/s
Calculate the distance to the epicenter:
Distance = (Time Difference) * (P-wave velocity)
= 20 s * 5 km/s
= 100 km
Therefore, based on the given information, the approximate distance from the seismic station to the earthquake epicenter is 100 kilometers.
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LaCie kicks a football from the ground level at a velocity of 13.9 m/s and at angle of 25 degrees to the ground. You have determined that the football would travel 15.1 m before landing. How would this value change if the football was kicked at an angle of 35 degrees? Complete all equations without rounding and then round to the nearest tenth at the end
The ball will travel more distance when projected or kicked at an angle of 35 degrees.
What is the range of projectile?
The range of the projectile or the horizontal distance traveled by the ball is calculated by applying the following kinematic equation as shown below.
R = ( u² sin (2θ ) ) / g
where;
u is the initial velocity of the ballg is the acceleration due to gravityThe horizontal distance traveled by the ball when projected at 35 degrees is calculated as;
R = ( 13.9² x sin ( 2 x 35 ) ) / ( 9.8 )
R = 18.53 m
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what are two properties that lead to electromagnetic interactions? pls help I'm so confused and cant find the answer anywhere!!
Answer:
Electric charge. A fundamental property that leads to the electromagnetic interactions among particles that make up matter.
Summarize your findings by describing the result of adding various combinations of red, green, and blue primary light colors in equal intensities And explain the result of adding these primary colors in unequal intensities.
White color is the result of adding various combinations of red, green, and blue primary light colors in equal intensities.
What are primary colors?The three primary colors are Red, green, and blue. This implies that by additively combining the colors red, green, and blue in varied proportions the different color is obtained.
Practically all other colors may be made, and when the three primaries are mixed together in equal amounts, white is produced.
Hence white color is the result of adding various combinations of red, green, and blue primary light colors in equal intensities.
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Erector Spinae:
Origin: __ surface of the __, __ __, __ process of the __ __ and last two __ __.
The erector spinae muscles are a group of muscles that extend along the back of the spine. The origin of the erector spinae muscle group is complex, and it varies depending on the specific muscle within the group.
What is Erector Spinae?
The erector spinae muscles are responsible for extending the spine, or bending the spine backwards, as well as for helping to maintain proper posture and balance. They also play a role in lateral flexion and rotation of the spine. These muscles are important for many everyday activities, such as standing, walking, lifting, and bendin
The erector spinae muscles are important for maintaining proper posture, supporting the spine, and allowing movement of the back. They are also involved in activities that require bending, twisting, and lifting.
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which method is commonly used for improving cattle breeds and why?
Answer: Cross-breeding method is commonly used for improving cattle breeds. Cross-breeding between two good varieties of cattle will produce a new improved variety. Cross breeding is defined as the process or the act of producing offspring particularly through mating two pure bred individuals but come from different breeds, varieties, or even species. Crossbreeding is undertaken to: Utilise the desired attributes of two or more breeds. Produce progeny better suited to target markets while maintaining environmental adaption. Improve productivity quicker in traits which are slow to change within a breed i.e. environmental adaption, fertility and carcass traits.
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An iron is supplied with a current of 3 A from the mains. The resistance of the iron is 1000
Calculate the power of the iron.
Answer:
1.6 An iron is supplied with a current of 3 A from the mains. The resistance of the iron is 100 Ω. Calculate the power of the iron. [2
1) Calculate the ideal efficiency of a heat engine that takes in energy at 800 K and expels heat to a
reservoir at 300K ?
Answer:
Could you explain that more better?
Explanation:
In an insulated cup of negligible heat capacity, 50. G of water at 40. °c is mixed with 30. G of water at 20. °c. The final temperature of the mixture is closest to.
The final temperature of the mixture is closest to 32.5 °C
Data obtained from the questionMass of warm water (Mᵥᵥ) = 50 gTemperature warm water (Tᵥᵥ) = 40 °CMass of cold water (M꜀) = 30 gTemperature of cold water (T꜀) = 20 °C Specific heat capacity of the water = 4.184 J/gºC Equilibrium temperature (Tₑ) =? How to determine the equilibrium temperatureHeat loss = Heat gain
MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – M꜀)
50 × 4.184 (40 – Tₑ) = 30 × 4.184(Tₑ – 20)
209.2(40 – Tₑ) = 125.52(Tₑ – 20)
Clear bracket
8368 – 209.2Tₑ = 125.52Tₑ – 2510.4
Collect like terms
8368 + 2510.4 = 125.52Tₑ + 209.2Tₑ
10878.4 = 334.72Tₑ
Divide both side by 334.72
Tₑ = 10878.4 / 334.72
Tₑ = 32.5 °C
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Taylor rides her bicycle 5km north from her house to the park, turns around, and then rides the bicycle 3 km back towards her house
Taylor decides to go for a bike ride to the park. Taylor turns around and rides her bicycle back to her home three kilometres away.
The choice is made by Taylor to ride her bicycle to the park. She travels five kilometres on her bicycle north from her home before arriving at the park. After spending some time at the park, she returns home on her bicycle after travelling three kilometres.
This shows that Taylor has pedalled 8 km in total. Both to and from her home, she commutes by bicycle, covering a different distance in each direction. She completes her ride, and it seems that she enjoyed being outside.
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Express 48 m/s in terms of
1.km/h
2.m/min
3.km/s
4.km/minutes
48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.
To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.
1 km (kilometer) = 1000 meter
1 h (hour) = 3600 seconds
1 minutes = 60 seconds
To convert m/s into km/h,
48 m/s * 3600/1000 = 172.8 km/h
To convert m/s into m/min,
48 m/s * 60 = 2880 m/min
To convert m/s into km/s,
48 m/s ÷ 1000 = 0.048 km/s
To convert m/s into km/minutes,
48 m/s * 60 / 1000 = 2.88 km/min
Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.
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48 m/s is equivalent to 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.
To express 48 m/s in different units of velocity:
km/h (kilometers per hour):
To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.
48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h
Therefore, 48 m/s is equivalent to 172.8 km/h.
m/min (meters per minute):
To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.
48 m/s * (60 m/min / 1 s) = 2880 m/min
Therefore, 48 m/s is equivalent to 2880 m/min.
km/s (kilometers per second):
Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.
48 m/s / 1000 = 0.048 km/s
Therefore, 48 m/s is equivalent to 0.048 km/s.
km/minute (kilometers per minute):
To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.
0.048 km/s * 60 = 2.88 km/minute
So, 48 m/s is equivalent to 2.88 km/minute.
Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.
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Why do space probes continuously move in outer space?
Answer:
It is because of the gravity. Gravity pulls things down to an planet/star, but a space probe is far enough from the Earth, so it is pulled into the Earth's orbit.
An 18.0-Newton wooden block slides across a horizontal wooden floor at constant velocity.
Calculate the magnitude of the force of kinetic friction between the block and the floor.
[Show all work, including the equation and substitution with units.]
Answer:
Hi Emily, I know you from school.
Explanation:
You're in my class. 2024 am i right
This is not meant to be a long, mathematically-intensive problem. If you find yourself going down that road, you might want to rethink your approach.
Answer:
rethink your approach to what?
Explanation:
What formula is used for the questions two forces of magnitude 5 Newton and 4 Newton act on a body of mass 4.0 kg at a right angle to each other determine the magnitude of the acceleration of the body
The magnitude of the acceleration of the body is approximately 1.802 m/s^2 when forces of magnitude 5 Newton and 4 Newton act on a body of mass 4.0 kg at a right angle to each other.
To determine the magnitude of the acceleration of a body when two forces act on it at a right angle, we can use the Pythagorean theorem and Newton's second law of motion.Newton's second law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force is the vector sum of the two forces acting on the body.Using the Pythagorean theorem, we can find the magnitude of the net force. Let's call the force with magnitude 5 Newton as F1 and the force with magnitude 4 Newton as F2. The net force (Fnet) can be calculated as the square root of the sum of the squares of the individual forces: Fnet = sqrt(F1^2 + F2^2).Now we can substitute the net force into Newton's second law to find the acceleration (a). Rearranging the formula, we have a = Fnet / m.Plugging in the values, Fnet = sqrt(5^2 + 4^2) = sqrt(25 + 16) = sqrt(41) Newtons. The mass (m) is given as 4.0 kg.
Finally, the magnitude of the acceleration of the body is calculated as a = Fnet / m = sqrt(41) / 4.0 ≈ 1.802 m/s^2.
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