Which is more important distance or charge in determining strength

Answer:

\(a=6\ m/s^2\)

Explanation:

Initial speed of a cat, u = 2m/s

It takes the cat 3 s to reach a top speed of 20 m/s.

We need to find the cat's rate of acceleration during this time. Acceleration is equal to the rate of change of velocity. So,

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{20-2}{3}\\\\a=6\ m/s^2\)

So, the acceleration of the cat is \(6\ m/s^2\).

The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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In a series combination of capacitors, the largest potential difference does not appear across the smallest capacitor. This statement is false.

What is a capacitor?

What is potential difference?

Therefore, in a series combination of capacitors, the potential difference across each capacitor is the same. Because the capacitors are connected in series, the charge on each plate is the same, but the voltage across each capacitor is different. The capacitor with the largest capacitance will have the smallest voltage, whereas the capacitor with the smallest capacitance will have the largest voltage.

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Answer:

Analytical

Explanation:

When a diffraction grating having a specified number of slits per unit length is illuminated by a beam of light, a pattern of bright spots or dark lines is produced on a screen placed perpendicular to the beam. Therefore, the wavelength of the light diffracted by the grating is 0.00072516 mm.

A pattern of this kind is called a diffraction pattern. A diffraction grating is a device that divides light into its component colors and produces diffraction patterns. It is used for analyzing light and determining the wavelengths of the different colors that make up the light.

The equation used to find the wavelength of light diffracted by a grating is

`d*sin(theta) = n*lambda`.

Here, d is the distance between two successive slits on the grating, theta is the angle of diffraction, n is the order of the diffraction, and lambda is the wavelength of the light. To determine the wavelength of the light in this case, we will use the given data and the above equation. The first-order diffraction angle is 34° and the diffraction grating has 750 slits/mm. Therefore, the distance between two successive slits on the grating is d = 1/750 mm = 0.001333 mm. The order of diffraction is 1.Using the above equation, we have`0.001333*sin(34) = 1*lambda`

Simplifying, we get `lambda = 0.00072516 mm`

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Answer:

One force acts on the object

A situation is impossible in such a circumstance - one force acts on the object. Because when the object is moving at constant velocity it means net force is zero. If one force acts on the object, net force is always not a zero. All the other combinations (no forces, two forces, three forces … )could give a resultant force equal zero

Answer:

it begins to move to the right! :)

Answer:

I believe it's True!    Brainliest??

Explanation: Hope you have a great day :)

The two astronauts are about 20.77 meters apart when the lighter astronaut has moved 15 meters.

By use conservation of momentum to solve this problem. According to Newton's third law of motion, when the astronauts push each other, they will experience equal and opposite forces, and their momentum will be conserved.

Therefore, the product of their masses and velocities before and after the push should be equal:

(m₁)(v₁) + (m₂)(v₂) = (m₁)(v₁') + (m₂)(v₂')

where m₁ and m₂ are the masses of the astronauts, v₁ and v₂ are their velocities before the push (which are both zero), and v₁' and v₂' are their velocities after the push. We can solve for v₁' and v₂':

v₁' = (m₁/m₂)(-v₂)

v₂' = (m₂/m₁)(-v₁)

where the negative signs indicate that the astronauts are moving in opposite directions.

Let's plug in the values we know:

m₁ = 65 kg

m₂ = 86 kg

v₁ = 0 m/s

v₂ = 0 m/s

v₁' = ?

v₂' = ?

Using the equations above, we get:

v₁' = (65/86)(-0 m/s) = 0 m/s

v₂' = (86/65)(-0 m/s) = 0 m/s

This tells us that the astronauts will move away from each other with equal and opposite velocities. Let's call the distance between them x, and let's assume that the lighter astronaut (m1) moves 15 m. Then we can set up an equation based on the fact that the total distance they move apart is x:

x = 15 m + (86/65)(-15 m)

Simplifying this equation, we get:

x = 15 m - 20.77 m

x = -5.77 m

This negative value for x means that the lighter astronaut has moved 15 m to the left, while the heavier astronaut has moved 5.77 m to the right. The distance between them is therefore the sum of these distances:

distance = 15 m + 5.77 m

distance = 20.77 m

So the two astronauts will be about 20.77 meters apart when the lighter astronaut has moved 15 meters.

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Answer:

by charging the coil

Explanation:

do you know how a magnet grabs another magnetic material and move it closer, an electric current passes through the coil making it act like a magnet by charging the coil called electromagnetism

your question seems incomplete, I think you are asking the question which is given below.

Question: As the frequency of electromagnetic waves increases, what happens to the wavelength?

when the frequency of an electromagnetic wave increases, its wavelength would decrease, according to eq (i).

speed of light = frequency X wavelength ............(i)

as the speed of light is constant in the same medium.

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Answer:

4.71m/s

Explanation:

Average speed = Total distance travelled ÷ Total time taken.

80/17=4.71

4.71m/s

Answer:

In this question,

                                                = 80m.

                                     = 17s

So, Average speed would be 80 ÷ 17

= \(\frac{80}{17}\)

 = 4.71 m/s. or 4.71 meter per second.

Answer:

50 kmph

Explanation:

300 / 6 = 50

The maximum voltage that can be applied across the whole network is 1.28 V.

To calculate the maximum voltage that can be applied across the whole network, you need to apply Ohm's Law and power formula.

The equation for power is P = V²/R,

where P is power, V is voltage, and R is resistance.

Therefore, V = sqrt(P * R).

Given that each resistor is rated at 0.50 W, the power of the network is 2 x 0.50 W = 1 W.

Since the resistors are in parallel, the equivalent resistance can be calculated as follows:

1/R = 1/R1 + 1/R2 + 1/R3 + 1/R4 + 1/R5R = 1/(1/3 + 1/3 + 1/6 + 1/8 + 1/16)R = 1.6375 Ω

Therefore, the maximum voltage that can be applied across the whole network is V = sqrt(P * R) = sqrt(1 * 1.6375) = 1.28 V (approx).

Therefore, the maximum voltage that can be applied across the whole network is 1.28 V.

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A mother notices that the prescription for her child's contact lenses is 2.00 d. The child's near point is 16.7 cm away from the lens, or approximately 17 cm.

The near point is related to the power of the eye in diopters (D) by the formula:

P = 1/f

Assuming that the contact lens is designed to enable the child to see objects 25.0 cm away clearly, the power of the contact lens can be calculated as follows:

\(P_{lens} = 1/f_{lens}\\P_{lens} = -2.00 D = -2.00 m^({-1}\)

We can use the thin lens equation to relate the focal length of the lens to the distance of the object from the lens and the distance of the image from the lens:

\(1/f_lens} = 1/d_o + 1/d_i\)

where d_o is the distance of the object from the lens (25.0 cm), and d_i is the distance of the image from the lens (which we will assume is the near point).

Solving for d_i, we get:

\(1/d_i = 1/f_{lens} - 1/d_o\\1/d_i = -2.00 m^{-1} - 1/0.25 m\\1/d_i = -2.00 m^{-1} - 4.00 m^{-1}\\1/d_i = -6.00 m^{-1}\\d_i = -0.167 m = -16.7 cm\)

Contact lenses are thin, curved lenses placed on the surface of the eye to correct vision problems or enhance cosmetic appearance. They are made of various materials, including silicone hydrogel, and are available in different designs, such as spherical, toric, and multifocal.

Contact lenses are a popular alternative to traditional eyeglasses because they provide clear, unobstructed vision without the bulk or inconvenience of frames. They are also useful for individuals who participate in sports or have jobs that require clear vision without the risk of glasses falling off or getting in the way. Contact lenses require proper care and maintenance to avoid infections or damage to the eyes. This includes cleaning and disinfecting them regularly, as well as following proper hygiene practices when handling them.

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Answer:

200

Explanation:

Given parameters:

Number of turns in primary coil  = 1000 turns

Primary voltage  = 230V

Secondary voltage  = 46V

Unknown:

Number of turns in secondary coil = ?

Solution:

To solve this problem, we have to use the expression for solving problems related with transformers;

        \(\frac{Vs}{Ns}\)   = \(\frac{Vp}{Np}\)  

Vs is the secondary voltage

Ns is the number of secondary turns

Vp is the primary voltage

Np is the number of primary turns

 Now insert the parameters and solve;

         \(\frac{46}{Ns}\)   = \(\frac{230}{1000}\)

          46 x 1000 = 230Ns

             Ns = 200

Answer:

Explanatin

its not 50 points it's 25!

Answer:

it is still 25 points

Explanation:

Answer: Water vapors are the gaseous form of water when liquid water is exposed to heat or boiling temperature it vaporizes.

Explanation:

Humidity is the total concentration of water in the atmosphere or air. Dew point can be defined as the temperature at which the air get saturated into vapors. Clouds are the mass of water vapors enters into higher atmosphere due to evaporation these water vapors when condense they result in precipitation in the form of rain, hail, and others. The water cycle is the circulation of water in the form of vapors and liquid in the atmosphere, hydrosphere, and earth.

Using a cable with a tension of 1350 N , a tow truck pulls a car 5.00 km alone a horizontal roadway. Therefore,

(a) Cable work: 6,750,000 J horizontally.

(b) Cable work: 6,308,250 J at 35.0° above horizontal.

(c) No work by gravity.

To calculate the work done by the cable in each scenario, we need to consider the angle between the direction of the force applied and the displacement.

(a) If the cable pulls horizontally (0° above the horizontal):

In this case, the angle between the force and the displacement is 0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(0°)

Work = 1350 N * 5000 m * 1

Work = 6,750,000 J

The cable does 6,750,000 Joules of work on the car when it pulls horizontally.

(b) If the cable pulls at 35.0 degrees above the horizontal:

In this case, the angle between the force and the displacement is 35.0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(35.0°)

Work = 1350 N * 5000 m * 0.819

Work = 6,308,250 J

The cable does approximately 6,308,250 Joules of work on the car when it pulls at 35.0 degrees above the horizontal.

(c) The work done by gravity on the car is zero because gravity acts vertically downward, perpendicular to the displacement along the horizontal roadway. Therefore, the gravitational force does not contribute to the work done on the car in this scenario.

In both cases (a) and (b), the cable does the same amount of work on the tow truck as on the car since they are connected by the cable. So the work done by the cable on the tow truck would be equal to the values calculated above: 6,750,000 J in case (a) and 6,308,250 J in case (b).

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Answer:

a = 0.41 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force [N]

m = mass = 87 [kg]

a = acceleration [m/s²]

The frictional force will be taken as negative, since it opposes the movement of the block.

\(43-7.3 = 87*a\\35.7 = 87*a\\a=0.41[m/s^{2} ]\)

Answer:

It has to be important to you.

-It has to be something that you are in control of.

-It has to be attainable, or able to be achieved.

-It has to be clear and specific.

-It has to have a plan.

Wellness

Wellness refers to a healthy state of being in body, mind, and emotion.

Body wellness

means eating right, exercising, and keeping your bodily systems in good health.

Mental wellness

means feeling safe and secure in your environment and at peace with your decisions and actions.

Emotional wellness

means feeling your best and having the ability to deal with many different situations.

Wellness: Setting Goals

The first step to setting a goal is defining it. Keep in mind that not everything you wish for can be a goal. When it comes to physical activity, diet, and exercise, you may wish to run a marathon before the end of the school year. However, this goal could be difficult to achieve if school ends in just a few months and you are not already training. A more reasonable goal might be to be able to run a mile in the amount of time considered healthy for your age group.

Importance of Physical Education

Physical education explores the methods, types, and benefits of physical activity for the body. In addition to staying active, making healthy choices about diet and exercise is important to overall personal and long-term health. Long-term health passed down through generations can also promote healthy family lifestyles.

Fitness

is the ability of the body to function effectively and efficiently during physical activity and is the ability to move joints through an entire range of motion.

Physical exercise

is the act of improving one's body through specific intentional movements.

differences between exercise and fitness

while anyone can exercise, only someone who exercises regularly can be fit.

Why is it important to make healthy choices about your diet and exercise?

Choosing healthy behaviors when it comes to diet and exercise is important to personal health, long-term health, and promoting healthy family lifestyles.

five components of physical education:

-Cardiorespiratory endurance

-Muscular strength

-Muscular endurance

-Flexibility

-Body composition

Explanation:

Life is WORTH LIVING

Answer: I didn’t make my schedule with a support system in mind. But, I can build a support system by finding people who can keep me on track. On the weekends, my friends can be my support system. During the week, it’s not that easy because my friends and family are so busy. I know that my mom goes for a 20-minute walk in the morning before work. Maybe I could walk with her and then work out on my own for 40 minutes afterward.

Explanation: Plato

Answer:

The spring constant is approximately 46.382 newtons per meter.

Explanation:

From Physics, the period (\(T\)), measured in seconds, experimented by an object under Simple Harmonic Motion:

\(T = 2\pi\cdot \sqrt{\frac{W}{g\cdot k} }\) (1)

Where:

\(W\) - Weight, measured in newtons.

\(g\) - Gravitational acceleration, measured in meters per square second.

\(k\) - Spring constant, measured in newtons per meter.

If we know that \(W = 127\,N\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(T = 3.32\,s\), then the spring constant of the system is:

\(\frac{T^{2}}{4\cdot \pi^{2}} = \frac{W}{g\cdot k}\)

\(k = \frac{4\cdot \pi^{2}\cdot W}{g\cdot T^{2}}\)

\(k \approx 46.382\,\frac{N}{m}\)

The spring constant is approximately 46.382 newtons per meter.

By 0.27m, the kitchen is farther than the hallway. Because Kim's home's hallway is 4.63 metres long. The distance of her kitchen is 0.0049 kilometres. The distance is same in any velocity.

Distance is measured numerically or sporadically qualitatively. far apart certain things or points are. Distance in physics or common language can refer to a physical length or an assumption based on other factors. Purposes In disciplines that study human behaviour, such the social sciences, qualitative measurements are frequently used. The rate of change in an object's position relative to a frame of reference is called velocity, and it depends on time.

4.9m is equal to 0.0049 km;

the difference is equal to 4.9 - 4.63;

and the difference is equal to 0.27.

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The lower energy level in system of N similar but distinct particles is non-degenerate, meaning that it has only one available state. On other hand, upper energy level has degeneracy, indicating that it has multiple available states.

There are several types of energy level in different contexts. In the field of atomic physics, energy levels refer to the discrete states that electrons can occupy within an atom. These levels are often represented by electron shells or orbitals. In quantum mechanics, energy levels are quantized and determined by the system's potential energy. Additionally, in the context of molecular spectroscopy, energy levels can represent the rotational, vibrational, and electronic states of molecules. Each of these energy levels corresponds to specific energy values and associated properties of the system.

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A pendulum clock on the surface of the earth has a period of 1.00 s. On a distant planet, the length of the pendulum must be shortened slightly to have a period of 1.00 s true about the acceleration due to gravity on the distant planet  option B: The gravitational acceleration on the planet is slightly less than g.

Any object within the gravitational field of the earth feels a tug. The acceleration that an object experiences due to the force of gravity acting on it is known as gravitational acceleration. Its symbol is "g," and its unit is "m/s2." The amount and direction of gravitational acceleration are both vector quantities. In physics, the term "gravitational acceleration" (symbolised "g") is used to describe the strength of a gravitational field. It is measured in m/s2, or metres per second squared. At the earth's surface, 1 g is equivalent to 9.8 m/s 2.

Einstein's concept of equivalence, which served as a cornerstone in the creation of the general theory of relativity, is the source of the term acceleration's application in relation to gravity.

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Complete Question is :

A frictionless pendulum clock on the surface of the earth has a period of 1.00 s. On a distant planet,

the length of the pendulum must be shortened slightly to have a period of 1.00 s. What is true

about the acceleration due to gravity on the distant planet?

A) The gravitational acceleration on the planet is slightly greater than g.

B) The gravitational acceleration on the planet is slightly less than g.

C) We cannot tell because we do not know the mass of the pendulum.

D) The gravitational acceleration on the planet is equal to g.

"An advantage of subsurface (underground) coal mining is that it employs more people than surface mining techniques and thus creates more jobs." So, the correct option is A.

Subsurface mining techniques are used when material ores are too deep to reach using surface mining techniques. Subsurface mining has the benefit of causing much less ground disturbance than surface mining. In actuality, it disturbs less ground than a tenth of what surface mining does.

When the ore body is too deep to be mined effectively by open pit, subsurface mining has advantages. The orebody's grades or quality are high enough to pay expenses. Compared to open pit mining, underground mining has a smaller environmental impact.

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