Answer:
The atomic mass is the number of grams of an element that is numerically equal to the
mass in amu.
Explanation:
The equation for photon energy, E, is E=hcλ where h = 6.626×10−34 J⋅s (Planck's constant) and c = 2.99×108 m/s (the speed of light). What is the wavelength, λ, of a photon that has an energy of E = 4.61×10−19 J ?
Answer:
9.133×10^-6 m
Explanation:
A photon is the smallest discrete amount or quantum of electromagnetic radiation. It is the basic unit of all light. Photons are always in motion and, in a vacuum, travel at a constant speed to all observers of 3 x 10^8 m/s.
From the question, the following details were supplied;
Energy of the photon (E) = 4.61×10^−19 J
Speed of light (c) = 2.99×10^8 m/s
Plank's constant (h) = 6.626×10^−34 J⋅s
Wavelength of the photon (λ)= ??? The unknown
From
E=hc/λ
λ= hc/E
Substituting values
λ= 6.626×10^−34 × 2.99×10^8/ 4.61×10^−19
λ= 91.33×10^-7 m
λ= 9.133×10^-6 m
How many grams of water should be added to 4.00 g NaOH to create 2.00% by mass NaOH solution?
Answer:
196 grams
because ^^^ was wrong and person in comments said it was 196 and it was right
When NaOH of 4.00 g is being added with water, the mass of water required to create 2.00% of NaOH solution by mass is 196 g.
What is mass percent of solute?It means that the particular amount of solute in terms of percentage is present in the solute.
Given the mass of the solute, NaOH is 4.00g
Suppose the mass of water required to add is x in g.
The mass percent of the solute is
\(\dfrac{2}{100} =\dfrac{4.00}{4.00 +x }\)
x =196 g
Therefore, mass of water required to create 2.00% of NaOH solution by mass is 196 g.
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The arrangement of particles is most ordered in a sample of
1.
NaCl(aq)
2.
NaCl(l)
3.
NaCl(g)
4.
NaCl(s)
PLEASE HELP
We have that the arrangement of particles of NaCl is most ordered in a sample of
NaCl(s)
i.e solid NaCl
From the question we are told
The arrangement of particles is most ordered in a sample of
1. NaCl(aq)
2. NaCl(l)
3. NaCl(g)
4. NaCl(s)
NaCl Generally known as sodium chloride or salt exist in four main states as shown
1. NaCl(aq)
2. NaCl(l)
3. NaCl(g)
4. NaCl(s)
Mow in a subject of its arrangement of particles we can see that as its state changes from gaseous through to solid it gains in form and arrangement of particles
Therefore
The arrangement of particles of NaCl is most ordered in a sample of
NaCl(s)
i.e solid NaCl
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calculate the molar solubility of pbbr2 in a 0.2740 m lead(ii) nitrate, pb(no3)2 solution.
The molar solubility of PbBr₂ in a 0.2740 M Pb(NO₃)₂ solution is 0.0547 M.
The molar solubility of PbBr₂ in a 0.2740 M lead(II) nitrate, Pb(NO₃)₂, solution can be calculated using the common ion effect. Write the balanced equation for the dissolution of PbBr₂ in water:
PbBr₂(s) ⇌ Pb²⁺(aq) + 2Br⁻(aq)
Write the expression for the solubility product constant (Ksp) of PbBr₂:
Ksp = [Pb²⁺][Br⁻]²
Calculate the initial concentration of Pb²⁺ in the solution:
[Pb²⁺] = 0.2740 M
Use the common ion effect to calculate the equilibrium concentration of Br⁻ ions:
Ksp = [Pb²⁺][Br⁻]²
[Br⁻]² = Ksp / [Pb²⁺] = (6.60 × 10⁻⁶) / (0.2740) = 2.41 × 10⁻⁵
[Br⁻] = √(2.41 × 10⁻⁵) = 0.00491 M
Calculate the molar solubility of PbBr₂ using the equilibrium concentration of Br⁻ ions:
PbBr₂(s) ⇌ Pb²⁺(aq) + 2Br⁻(aq)
[PbBr₂] = Ksp / ([Pb²⁺][Br⁻]²) = (6.60 × 10⁻⁶) / (0.2740 × (0.00491)²) = 0.0547 M
Therefore, PbBr₂ has a molar solubility of 0.0547 M in a 0.2740 M Pb(NO₃)₂ solution. This calculation shows how the presence of a common ion (in this case, Pb²⁺) can affect the solubility of a slightly soluble salt (in this case, PbBr₂) through the common ion effect.
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Generally, what determines the number and kinds of chemical bonds an element can make and the chemical reactivity of an element?
Valence stability determines the chemical reactivity of an element. Generally, an atom with 8 valence electrons is most stable. For example, metals with 1 valence electron will readily give up that electron to another atom in need of it. An atom with 7 valence electrons will be able to take the electron of another atom. The ions created will allow bonds to be formed: covalent bonds, ionic bonds, polar bonds, and probably others as well. The type of element, its electronegativity, and valence level are only a few factors of the number of bonds certain elements can form.
Generally, valence electrons determines the number and kinds of chemical bonds an element can make and the chemical reactivity of an element.
The valence stability of an element controls its chemical reactivity. A stable atom typically has 8 valence electrons. For instance, an atom in need of an electron will gladly accept it from a metal with one valence electron. If an atom has seven valence electrons, it can absorb one electron from another atom. Covalent bonds, ionic bonds, polar bonds, and possibly additional bonds can all be established thanks to the ions that are produced. The number of bonds that a particular element can make depends on a variety of characteristics, including the element's kind, electronegativity, and valence level.
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The first part of the strontium test removes any residual barium. Do you have to be careful adding too much additional chromate? What might happen to the strontium ?
Yes, it is necessary to be careful when adding too much additional chromate during the strontium test. Excessive amounts of chromate can form a precipitate with strontium ions, leading to the formation of strontium chromate.
This can interfere with the accurate detection and measurement of strontium. Strontium chromate is a yellow solid that can precipitate out of the solution, making it difficult to distinguish and quantify the presence of strontium. This interferes with the accuracy and reliability of the strontium test. Therefore, it is important to use the appropriate amount of chromate in the test to ensure that the reaction specifically targets the barium ions without affecting the strontium ions.
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explain why the ph at the half-titration point is equal to the pka in your experiment
In an experiment, the pH at the half-titration point is equal to the pKa because the half-titration point is the point at which exactly half of the acid or base has been neutralized by the titrant.
At this point, the concentration of the acid and the conjugate base are equal, and they are in the process of forming equal amounts of H+ and A-.The pKa is defined as the negative logarithm of the acid dissociation constant (Ka), which is a measure of the strength of the acid. It represents the pH at which half of the acid is dissociated and half is undissociated. Therefore, at the half-titration point, the concentration of the acid and its conjugate base are equal, and the pH is equal to the pKa of the acid. For example, if the pKa of the acid being titrated is 4.5, then the pH at the half-titration point would be 4.5.
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How many carbon atoms are represented by the model below?
A. 12
B. 5
C. 4
D. 6
Answer:
D. 6
Explanation:
Each pointy end represents 1 carbon. So in total we have six carbons.
The name of this organic compound is hexane.
A sample of gas has a volume of 526 mL at 346 mmHg and 35.0°C. Determine the moles of gas.
Answer:
The moles of gas is 0.009474 moles.
Explanation:
Given that,
Volume = 526 mL
Pressure = 346 mmHg
Temperature = 35.0°C
We need to calculate the moles of gas
Using formula of ideal gas
\(n=\dfrac{PV}{RT}\)
Where, P = pressure
V = volume
R = gas constant
T = temperature
Put the value into the formula
\(n=\dfrac{\dfrac{346}{760}\times0.526}{0.08206\times(35+273)}\)
\(n=0.009474\ moles\)
Hence, The moles of gas is 0.009474 moles.
A chemical process used to produce ethanol as a fuel additive was expected to produce 5,000 kilograms of ethanol based on the amounts of starting materials used, but only 4,760 kilograms were produced. What was the percent yield for ethanol in this process?
A)1.09
B)4.80
C)95.2
D)105
Answer:
C)95.2
Explanation:
Given parameters:
Expected yield = 5000kg
Experimental yield = 4760kg
Unknown:
Percentage yield = ?
Solution:
The percentage yield of the substance is determined by find the ratio of the true experimental yield to the expect yield and multiply by 100;
Percentage yield = \(\frac{4760}{5000}\) x 100 = 95.2%
Deposits of gold can be found in the deep ocean. true?
Answer:
yes that should be true
Answer:
true
Explanation:
One study found there is only about one gram of gold for every 100 million metric tons of ocean water in the Atlantic and north Pacific
What the concentration of oxygen
Answer:
19.5%
Explanation:
the air required for human breathing is 19.5 percent.
A photon of light possesses 5 x 10^-19 J of energy. Calculate its frequency
Answer:
The frequency of photon is 0.75×10¹⁵ s⁻¹.
Explanation:
Given data:
Energy of photon = 5×10⁻¹⁹ J
Frequency of photon = ?
Solution:
Formula;
E = hf
h = planck's constant = 6.63×10⁻³⁴ Js
5×10⁻¹⁹ J = 6.63×10⁻³⁴ Js ×f
f = 5×10⁻¹⁹ J / 6.63×10⁻³⁴ Js
f = 0.75×10¹⁵ s⁻¹
The frequency of photon is 0.75×10¹⁵ s⁻¹.
PLEASE HELP DUE TOMORROW!!!
1. The new volume of the gas will be 58 L
2. The new volume will be 105.65 mL
3. The new temperature will be -15.49 °C
4. The final pressure will be 28.48 KPa
1. How do I determine the new volume of the gas?The new volume of the gas can be obtained by using Charles' law equation as follow:
Initial temperature (T₁) = 265 KInitial volume (V₁) = 24 LNew temperature (T₂) = 642 KPressure = ConstantNew volume (V₂) =?V₁ / T₁ = V₂ / T₂
24 / 265 = V₂ / 642
Cross multiply
265 × V₂ = 24 × 642
Divide both side by 265
V₂ = (24 × 642) / 265
New volume (V₂) = 58 L
2. How do I determine the new volume of the gas?The following data were obtained from the question
Initial volume (V₁) = 250 mLInitial pressure (P₁) = 0.5 atmInitial temperature (T₁) = 50 °C = 50 + 273 = 323 KNew temperature (T₂) = 0 °C = 0 + 273 = 273 KNew pressure (P₂) = 1 atmNew volume (V₂) = ?The new volume can be obtained by using the combined gas equation as follow:
P₁V₁ / T₁ = P₂V₂ / T₂
(0.5 × 250) / 323 = (1 × V₂) / 273
Cross multiply
323 × V₂ = 0.5 × 250 × 273
Divide both side by 323
V₂ = (0.5 × 250 × 273) / 323
New volume = 105.65 mL
3. How do i determine the new temperature?The new temperature can be obtained by using the combined gas equation as follow:
Initial Volume (V₁) = 2.52 LInitial temperature (T₁) = 37 °C = 37 + 273 = 310 KInitial pressure (P₁) = 450 torr New pressure (P₂) = 600 mmHg = 600 torrNew volume (V₂) = 1.57 LNew temperature (T₂) =?P₁V₁ / T₁ = P₂V₂ / T₂
(450 × 2.52) / 310 = (600 × 1.57) / T₂
Cross multiply
450 × 2.52 × T₂ = 310 × 600 × 1.57
Divide both side by (450 × 2.52)
T₂ = (310 × 600 × 1.57) / (450 × 2.52)
T₂ = 257.51 K
Subtract 273 to obtain answer in °C
T₂ = 257.51 - 273 K
New temperature = -15.49 °C
4. How do i determine the final pressure?Initial volume (V₁) = 0.450 LInitial temperature (T₁) = 25 °C = 25 + 273 = 298 KInitial pressure (P₁) = 47.81 KPaFinal volume (V₂) = 825 mL = 825 / 1000 = 0.825 LFinal temperature (T₂) = 52.5 °C = 52.5 + 273 = 325.5 KFinal pressure (P₂) = ?The combined gas equation is given as follow:
P₁V₁ / T₁ = P₂V₂ / T₂
Inputting the given parameters, we obtained:
(47.81 × 0.45) / 298 = (P₂ × 0.825) / 325.5
Cross multiply
298 × 0.825 × P₂ = 47.81 × 0.45 × 325.5
Divide both sides by (345 × 150)
P₂ = (47.81 × 0.45 × 325.5) / (298 × 0.825)
Final pressure = 28.48 KPa
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how many carbon atoms are represented in the formula (ch3)3c(ch2)2cho
The formula (CH3)3C(CH2)2CHO represents 13 carbon atoms.
To calculate it:Firstly, we need to expand the formula by multiplying the subscript outside the parentheses by all the atoms inside the parentheses to get the following:CH3CH3CH3CCCH2CH2CHOThen we count all the carbon atoms, which are 13 in total.
The C atoms are represented in the structure as follows:Three carbon atoms are present in the (CH3)3C group, which is a tertiary carbon atom.
There are two carbon atoms in the (CH2)2 chain.
Finally, there is one carbon atom in the CHO functional group.
As a result, the formula (CH3)3C(CH2)2CHO contains 13 carbon atoms.
The molecular weight of the compound can be determined using the Avogadro number, which is 6.02 x 10^23 atoms per mole.
We can also use the periodic table's atomic weights to estimate the molecular weight.
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calculate the work (kj) done during a reaction in which the internal volume expands from to against an outside pressure of group of answer choices 0 kj; no work is done. -7.3 kj 7.3 kj -17 kj 17 kj
The work done during this reaction is -0.1013 kJ. Therefore, the correct option is 2) -7.3 kJ.
According to the question, the work done during a reaction in which the internal volume expands from 0.75 L to 1.25 L against an external pressure of 2 atm has been asked to calculate. The formula for work done by a system can be given as: Work = -PΔV Where P is the external pressure and ΔV is the change in volume of the system. The pressure is given as 2 atm, the change in volume can be calculated as:
ΔV = Vf - ViΔV
= 1.25 L - 0.75 L
= 0.5 L
Now, putting the given values into the formula of work, we get:Work = -PΔVWork = -(2 atm)(0.5 L)Work = -1 atm L The units of atm L are not in standard units of Joules, but we can convert them using the conversion factor 1 atm L = 101.3 J Therefore, Work = -1 atm L × 101.3 J/atm L Work = -101.3 J = -0.1013 kJ.
Thus, the work done during this reaction is -0.1013 kJ. Therefore, the correct option is 2) -7.3 kJ.
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will give BRAINLIST !!
(QUESTION 3 IS THE IMAGE)
From question 3,
you calculated the theoretical yield of CO2 in liters use that value to calculate the percent yield of 250L of CO2 are collected for the actual yield percent yield?
Percent Yield = actual yield/ theoretical yield x 100%
A) 72%
B) 25%
C) 79%
D) 35%
Answer:
To calculate the percent yield, we need to divide the actual yield (250 L) by the theoretical yield (in liters) and then multiply by 100%.
Percent Yield = (actual yield / theoretical yield) x 100%
So, if we know the theoretical yield of CO2 in liters and we want to calculate the percent yield of 250L of CO2 collected as the actual yield, we need to insert the theoretical yield in the equation.
For example, let's assume that the theoretical yield of CO2 is 350L.
Percent Yield = (250 L / 350 L) x 100% = 71.42%
This is close to option A) 72%. So, The percent yield of 250L of CO2 collected for the actual yield is 72%
Keep in mind that this is a theoretical example and the actual yield percentage will vary depending on the reaction and the experimental conditions.
Explanation:
I need help with question 2 please help quickly this is due in 3 hours! For this activity,
you need to find reliable Internet or library sources about energy resources. You will
research their advantages and disadvantages. Advantages are positive impacts, or
benefits. Disadvantages are negative impacts. Resources include coal, oil, natural gas,
nuclear power, biomass, wind, hydropower, geothermal energy, and solar energy. Their
positive and negative effects can depend on how they are obtained and the pollution they
cause when used. Their effects may also depend on how much the resource we use.
How much we use a resource can be described by its per capita consumption.
I
Part 1: Identifying Sources (5 points)
2. Identify three websites you will use to start your research. If you use other websites to
complete the research questions in Part 2, add them to this list. Cross out any websites
that don't end up helping you complete the activity. (3 points)
Coal is abundant and cost-effective, providing stable energy.
Coal extraction damages the environment, and burning it releases high levels of CO2 and air pollutants. Oil has high energy density and infrastructure, but its combustion contributes to climate change and spills cause environmental harm.
Natural gas emits less CO2, is versatile, and is abundant, but extraction techniques like fracking can harm ecosystems and water resources. Nuclear power produces large amounts of electricity without CO2 emissions but faces concerns about radioactive waste disposal and safety risks. Biomass is renewable but competes with food production and can release emissions.
Wind, solar, hydro, and geothermal offer renewable sources, but their scalability, intermittency, and land use impacts vary. Per capita, consumption affects the magnitude of their environmental effects.
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You will be marked as brainlest if you are able to solve this question
Answer:
See Explanation
Explanation:
1) According to the question, the reactivity of a metal is measured by the temperature of the solution after reaction. The higher the temperature of the solution, the greater the reactivity of the metal. Based on this criterion, the metals can be arranged in an order of reactivity as follows;
Mg> Zn > Fe.
2) The equation of the reaction is;
Mg(s) + 2H^+(aq) ------>Mg^2+(aq) + H2(g)
If we consider the changes in oxidation number from left to right;
The oxidation number of Mg changed from zero to +2
The oxidation number of H changed from +1 to zero
Recall that a redox reaction is a reaction in which the oxidation number of species changes from left to right in the reaction. Hence this reaction is a redox reaction.
The reducing agent experiences an increase in oxidation number. In this case, Mg is the reducing agent.
The oxidation half equation is;
Mg(s) ------> Mg^2+(aq) + 2e
The reduction half equation is;
2H^+(aq) + 2e ------> H2(g)
pls help asap you can!
The frequency of the color light, given that it has a wavelength of 5.0×10⁻⁷ m is 6.0×10¹⁴ Hertz (last option)
How do i determine the frequency of the color light?First, we shall list out the given parameters from the question. This is shown below:
Wavelength of color light (λ) = 5.0×10⁻⁷ mSpeed of color light (v) = 3×10⁸ m/sFrequency of color light (f) =?Speed, wavelength and frequency of wave are related by the following formula:
Velocity (v) = wavelength (λ) × frequency (f)
Inputting the given parameters, we can obtain the frequency as shown below:
3×10⁸ = 5.0×10⁻⁷ × frequency
Divide both sides by 5.0×10⁻⁷
Frequency = 3×10⁸ / 5.0×10⁻⁷
= 6.0×10¹⁴ Hertz
Thus, we can conclude that the frequency of the color light is 6.0×10¹⁴ Hertz (last option)
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ASAP PLEASE! Mostly just need the data and conclusion answers please!!!
Electromagnetic Spectrum Lab Report
Instructions: In this virtual lab, you will use a virtual spectrometer to analyze astronomical bodies in space. Record your hypothesis and spectrometric results in the lab report below. You will submit your completed report to your instructor.
Name and Title:
Include your name, instructor's name, date, and name of lab.
Objectives(s):
In your own words, what is the purpose of this lab?
Hypothesis:
In this section, please include the predictions you developed during your lab activity. These statements reflect your predicted outcomes for the experiment.
Procedure:
The materials and procedures are listed in your virtual lab. You do not need to repeat them here. However, you should note if you experienced any errors or other factors that might affect your outcome. Using your summary questions at the end of your virtual lab activity, please clearly define the dependent and independent variables of the experiment.
Data:
Record the elements present in each unknown astronomical object. Be sure to indicate “yes” or “no” for each element.
Hydrogen Helium Lithium Sodium Carbon Nitrogen
Moon One
Moon Two
Planet One
Planet Two
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.
Using two to three sentences, summarize what you investigated and observed in this lab.
Astronomers use a wide variety of technology to explore space and the electromagnetic spectrum; why do you believe it is essential to use many types of equipment when studying space?
If carbon was the most common element found in the moons and planets, what element is missing that would make them similar to Earth? Explain why. (Hint: Think about the carbon cycle.)
We know that the electromagnetic spectrum uses wavelengths and frequencies to determine a lot about outer space. How does it help us find out the make-up of stars?
Why might it be useful to determine the elements that a planet or moon is made up of?
Answer: This lab's goal is to investigate the absorbance patterns created by recently discovered moons and planets.
The first moon consists of Lithium and carbon, the second moon consists of sodium and nitrogen. Moving onto the planets, the first planet consists of hydrogen and carbon, and lastly, the second planet is consistent with helium and carbon.
How to explain the lab report
The theory was right; there have been no flaws in the outcome. The astronomical item observed by the spectrometer is the independent variable. The spectrum of any astronomical object is the dependent variable.
Space consists of bodies with different types of the electromagnetic spectrum. This includes high-energy bodies emitting radiation in short wavelengths and extremely short wavelengths such as in UV spectrum, X rays, and gamma rays. Conversely, other bodies might be emitting radiations in the longer wavelengths such as Microwaves and Radio waves.
The element missing from the moons and the planets would be Oxygen. It is to be remembered that Oxygen forms the base of the sustenance of life forms on Earth and forms an indispensable part of the carbon cycle. In the absence of oxygen, these planets and moons remain lifeless.
Stars emit heat and light. Along with the heat and light, radiations are emitted by the star. These radiations travel outward from stars and work as the signature of the stars. By analyzing the radiations from the stars, scientists back on Earth could deduce the physical conditions in the heart of a star including its constitution, temperature, and surface conditions.
The knowledge of the constitution of the elements making up the moon or planet is necessary to ascertain the life-sustaining capability of the same.
Answer: This lab's goal is to investigate the absorbance patterns created by recently discovered moons and planets.
The first moon consists of Lithium and carbon, the second moon consists of sodium and nitrogen. Moving onto the planets, the first planet consists of hydrogen and carbon, and lastly, the second planet is consistent with helium and carbon.
How to explain the lab report
The theory was right; there have been no flaws in the outcome. The astronomical item observed by the spectrometer is the independent variable. The spectrum of any astronomical object is the dependent variable.
Space consists of bodies with different types of the electromagnetic spectrum. This includes high-energy bodies emitting radiation in short wavelengths and extremely short wavelengths such as in UV spectrum, X rays, and gamma rays. Conversely, other bodies might be emitting radiations in the longer wavelengths such as Microwaves and Radio waves.
The element missing from the moons and the planets would be Oxygen. It is to be remembered that Oxygen forms the base of the sustenance of life forms on Earth and forms an indispensable part of the carbon cycle. In the absence of oxygen, these planets and moons remain lifeless.
Stars emit heat and light. Along with the heat and light, radiations are emitted by the star. These radiations travel outward from stars and work as the signature of the stars. By analyzing the radiations from the stars, scientists back on Earth could deduce the physical conditions in the heart of a star including its constitution, temperature, and surface conditions.
The knowledge of the constitution of the elements making up the moon or planet is necessary to ascertain the life-sustaining capability of the same.
If the laser were replaced with a green laser with a shorter wavelength (532 nm), which would best describe the resulting pattern? a. Pattern would not change b. Pattern gets wider, dark spots move apart C. Pattern gets narrower, dark spots move closer together d. Pattern would be completely bright with no dark spots e. None of those
The correct answer would be: e. None of those. The pattern observed in the double-slit interference experiment is determined by the wavelength of the light used. When a laser with a shorter wavelength (such as a green laser at 532 nm) is used instead of a longer wavelength, the resulting interference pattern will be different.
The interference pattern in the double-slit experiment depends on the relationship between the wavelength of light, the distance between the slits, and the distance from the slits to the screen. A shorter wavelength of light will lead to narrower bright fringes and a narrower overall pattern. The dark spots (where destructive interference occurs) will also be narrower, but they will not move closer together or farther apart.
Therefore, the most accurate answer is that the pattern would change, but it cannot be determined precisely without additional information about the experimental setup.
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What is the molarity of a solution that has 2.87 moles of NaCl in 5020 mL of solution?
For a science experiment, Matt places a flashlight on the table on the east side of a potted plant. He covers the plant and flashlight with a darkened box. Matt waits several days, then checks to see how the plant is growing. Which of the following results is an example of phototropism? Question 9 options: The plant grows toward the west. The plant continues to grow upward. The plant grows toward the south. D. The plant grows toward the east.
The correct answer is (d) The plant grows toward the east. Phototropism is the growth of a plant in response to a light stimulus. In this case, the plant is growing toward the east because that is the direction of the light source.
The plant's cells on the side facing the light will produce more auxin, a plant hormone that promotes growth. This will cause the cells on that side to grow longer, bending the plant toward the light. The other options are not examples of phototropism. The plant continuing to grow upward is an example of geotropism, or the growth of a plant in response to gravity. The plant growing toward the west or south is not an example of any type of tropism.
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2. write a conclusion statement that will address the following:
write in complete sentences.
is your hypothesis supported or not? explain using your data/calculations for support.
the accuracy & precision of your data.
possible further experimentation.
possible sources of error
.
(the hypothesis is : if the density of the object is 19.32 g/ml then the object is gold)
Based on the data and calculations obtained, it can be concluded that the hypothesis stating, "If the density of the object is 19.32 g/ml, then the object is gold" is not supported.
To support this conclusion, the data and calculations regarding the density of the object should be analyzed. If the calculated density of the object differs significantly from the expected value of 19.32 g/ml, it indicates that the object is not gold.
The accuracy and precision of the data can be assessed by comparing the calculated density with the expected density value. If the calculated density is close to the expected value, it suggests high accuracy. Additionally, if multiple measurements of density yield consistent results, it indicates high precision.
Further experimentation could involve additional tests to determine the identity of the object. These tests could include assessing other physical or chemical properties such as melting point, electrical conductivity, or reactivity with certain substances.
Possible sources of error in the experiment could include instrumental errors in measuring the mass or volume of the object, contamination of the object, or inaccuracies in the known density of gold used for comparison. These factors could contribute to deviations between the calculated and expected densities.
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What are examples of alloys?
Answer:
steel solder brass Peter duralumin bronze and amalgams
Answer:
Examples of alloys are steel, solder, brass, pewter, duralumin, bronze and amalgams.I hope it help you,
God blessed youPlease help with this question!
Answer:
The answer is 1:1
Explanation:
Which of the following is likely to be affected by a growing human population?
Question 5 options:
Amount of land for farming
Amount of air pollution
Amount of clean water
All of the above
None of the above
Answer:
D.) All of the above
is the correct answer
By a growing human population, amount of land for farming, amount of air pollution and clean water is likely to be affected.
What is population?Population tells about the relative numbers of people present in particular area.
When there is a increase in the population of people then there is decrease in the amount of land for farming because more people want more land and this results in lack of land for individual. The affect of increased population results in the increase of air pollution, noise pollution, land pollution as well as water pollution.
Hence, option (d) is correct i.e. all of the above.
To know more about pollution, visit the below link:
https://brainly.com/question/24704410
How many grams of lithium chloride are in a 3.0 Molarity solution of 0.5 L?
Explanation:
LiCl2 3 M =
in sol. 1 L there is LiCl2 3 mol
if sol. 0.5 L there is LiCl2 0.5×3 = 1.5 mol
LiCl2 = 6.9 + 35.5(2)
= 6.9 + 71
= 77.9 g
Answer:
63.52g of LiCl are in a 3.0 molarity solution of 0.5L
Explanation:
Moles = Molarity x Volume
Molarity = 3.0 mol/L
Volume = 0.5L
Moles = (3.0) x (0.5)
Moles = 1.5
In order to find the grams dissolved in the solution, we must first find the molar mass of Lithium Chloride (LiCl).
Molar mass of LiCl = (6.9) + (35.45) = 42.35g/mol
Now we multiply the moles by the molar mass of LiCl to get the grams of LiCL dissolved in the solution.
1.5 * 42.35 = 63.52g of LiCl
5)
What is the mass in grams of carbon dioxide, CO₂,
produced if 12.0 mol of iron are also produced?
Rxn A: 2Fe₂O3 + 3C → 4Fe + 3CO₂
Given:
Unknown:
To determine the mass of carbon dioxide produced in the reaction, we need to use the balanced chemical equation. The balanced equation for reaction A is:
2 Fe2O3 + 3 C -> 4 Fe + 3 CO2
The reaction tells us that for every 2 moles of Fe2O3, 3 moles of CO2 are produced. We are given the amount of Fe produced, which is 12 moles, so we can use that to determine the amount of Fe2O3 consumed and, therefore, the amount of CO2 produced.
First, let's calculate the amount of Fe2O3 consumed:
12 moles Fe / (4 moles Fe / 2 moles Fe2O3) = 6 moles Fe2O3
Next, we can use the ratio of Fe2O3 to CO2 from the balanced equation to calculate the amount of CO2 produced:
6 moles Fe2O3 * (3 moles CO2 / 2 moles Fe2O3) = 9 moles CO2
Finally, to convert moles to grams, we use the molar mass of CO2, which is 44.01 g/mol:
9 moles CO2 * 44.01 g/mol = 396.09 g CO2