Which of the following monoalkylbenzenes undergo nitration in HNO3/H2SO4 to yield a product mixture with the highest ortho : para ratio?ethylbenzenepropylbenzenetert-butylbenzenetoluene

Answer:

7

Explanation:

The amount of sodium azide required will be 123.72 grams

From the equation of the reaction below:

\(2NaN_3 --- > 2Na + 3N_2\)

The mole ratio of sodium azide to nitrogen gas is 2:3

Mole of 80.0 g nitrogen = 80/28.02 = 2.855 moles

Equivalent mole of sodium azide = 2/3 x 2.855 = 1.903 moles

Mass of 1.903 moles sodium azide = 1.903 x 65 = 123.72 grams

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Answer:

45N, and B

Explanation:

Answer:

an object will continue in its state of motion unless an unbalanced force is acting on it. If forces are balanced, then the net force equals 0. This means that there is no acceleration.

Explanation:

Based on the given reactions, the compounds are as follows:

A: The specific product formed from the reaction between prop-1-yne and either 2HBr or H2O2.

B: The product formed when compound A reacts with 2H2O.

C: The product formed when compound B reacts with K2CO3(aq).

D: The product formed from the heat-induced reaction of compound C.

E: The product formed when compound D reacts with HBr.

Based on the given reactions, let's analyze the compounds involved:

Reaction 1: prop-1-yne + 2HBr/H2O2 = A

The reactant prop-1-yne reacts with either 2HBr or H2O2 to form compound A. The specific product formed will depend on the reaction conditions.

Reaction 2: A + 2H2O = B

Compound A reacts with 2H2O (water) to form compound B.

Reaction 3: B + K2CO3(aq) = C

Compound B reacts with K2CO3(aq) (potassium carbonate dissolved in water) to form compound C.

Reaction 4: C + heat = D

Compound C undergoes a heat-induced reaction to form compound D.

Reaction 5: D + HBr = E

Compound D reacts with HBr (hydrobromic acid) to form compound E.

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Answer:

answer A is the answer suii

Answer:

A

Explanation:

u put it down and let them pick it up themselves so if anything happens u are not to be blamed

Answer:

I really don't know if this is right but i did the math and there would have to be one cent leftover , but you would have to buy 8 sodas and 5 bag of chips .

Explanation:

Answer:

Numbers 4,3

Explanation:

Ionic bond is between nonmental and metals

Answer:

53.5gram.

Explanation

Explanation: number of moles = number of molecule ÷ avogadro's number. => moles = 6.022 × 10²³ ÷ 6.022 × 10²³ = 1 mole. mass of 1 mole of NH4Cl = 1 × molar mass.

In an ecosystem, the  impact of soil Science to the development of Ghana's agriculture is that it provides suitable conditions for root germination and growth.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

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​

Answer:

C

Explanation:

Option C points to Sr which is the element Strontium

D) Whorl

Explanation:

whorls always have 2 deltas while loops only have one. Have fun in forensics!

Answer: 0.0827

Hope This Will Help You And This Should Be The Correct One.

Answer:c

Explanation:c

Answer:

I had this question on a test a long time ago and i believe it is

16- or 32-

Explanation:

The normal boiling point of the unknown liquid is 57.4°C.

The normal boiling point occurs when the vapor pressure of the liquid is equal to the atmospheric pressure. At normal boiling point, the temperature of the liquid is called the boiling point.

Using the Clausius-Clapeyron equation:

ln(P₂/P₁) = -(ΔHvap/R) * (1/T₂ - 1/T₁)

where P₁ is the vapor pressure at the given temperature T₁, P₂ is the vapor pressure at the boiling point temperature T₂, ΔHvap is the heat of vaporization, R is the gas constant.

At -170°C, the vapor pressure of the liquid is given as P₁ = 117 torr. At normal boiling point, the vapor pressure of the liquid is P₂ = 760 torr.

Converting all units to SI units, we have:

P₁ = 15.47 Pa

P₂ = 101325 Pa

ΔHvap = 5480 J/mol

R = 8.314 J/(mol*K)

Plugging in the values, we get:

㏑(101325/15.47) = -(5480/8.314) * (1/T₂ - 1/103.15)

Solving for T₂, the boiling point is found to be:

T₂ = 57.4°C

As a result, the unknown liquid's usual boiling point is 57.4°C.

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The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.

The combined gas law equation is:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.

Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.

To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.

Now we can solve for T₂:

(T₂ * V₁) / T₁ = V₂

T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL

Simplifying the equation, we find:

T₂ ≈ 143.27 K

Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

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The statement(s) that correctly compare the masses of protons, neutrons, and electrons are options A and F.

Subatomic particles are any of many units of matter smaller than an atom. They are three in number and are as follows;

Protons are positively charged subatomic particles forming part of the nucleus of an atom. Electrons are negatively charged particles while neutrons are neutrally charged i.e. 0.

Based on the above explanation, it can be said that:

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The molar mass of MgCrO4 is approximately 140.30 g/mol.

To determine the molar mass of MgCrO4 (magnesium chromate), we need to calculate the sum of the atomic masses of each individual element in the compound.

The chemical formula MgCrO4 indicates that the compound consists of one magnesium atom (Mg), one chromium atom (Cr), and four oxygen atoms (O).

The atomic masses of the elements can be found on the periodic table:

Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol.

Chromium (Cr) has an atomic mass of around 51.99 g/mol.

Oxygen (O) has an atomic mass of about 16.00 g/mol.

Now, we can calculate the molar mass of MgCrO4 by summing up the atomic masses of each element, considering the respective subscripts:

Molar mass = (Atomic mass of Mg) + (Atomic mass of Cr) + 4 × (Atomic mass of O)

Molar mass = (24.31 g/mol) + (51.99 g/mol) + 4 × (16.00 g/mol)

Molar mass = 24.31 g/mol + 51.99 g/mol + 64.00 g/mol

Molar mass ≈ 140.30 g/mol

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Answer:

Oxygen exits the leaf.

Answer:

453 or 453.592

Explanation:

400 jellybeans are about a pound and a pound is 453.592 grams

We need collisonal section area

\(\\ \sf\longmapsto \sigma=2d\)

\(\\ \sf\longmapsto \sigma=2(0.20nm)\)

\(\\ \sf\longmapsto \sigma=0.4nm\)

Answer: No, two atoms belonging to the same chemical element are not necessarily identical.

Explanation:

I hope that was helpful

The molar mass of the gas is 3.58 g/mol.

We can use the ideal gas law equation:

\(PV = nRT\)

Where

We can rearrange the equation to solve for n:

\(n = PV/RT\)

We know the following values:

P = 918 torr

V = 222 mL

R = 62.36 L torr/mol K

T = 57°C + 273 = 330 K

To solve for n, we can enter these numbers into the equation:

n = (918 torr)(222 mL)/(62.36 L torr/mol K)(330 K) = 0.0108 mol

Now, we can use the definition of molar mass to find the molar mass of the gas:

molar mass = mass/number of moles

We know the following values:

mass = 38.6 mg = 0.0386 g

n = 0.0108 mol

We can plug these values into the equation to solve for the molar mass

molar mass = 0.0386 g/0.0108 mol = 3.58 g/mol

Therefore, the molar mass of the gas is 3.58 g/mol.

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Answer:

C. electricity conductive

Answer:

The pH at the midpoint in the titration of an acid with a base is

A) equal to the pK of the corresponding base.

B) equal to the pK of the corresponding acid.

C) equal to 14 minus the pK of the corresponding acid.

D) equal to 14 plus the pK of the corresponding base.

E) none of the above

Explanation:

When a weak acid is titrated with a strong base, then a buffer solution is formed.

pH of a buffer solution can be calculated by using the formula:

\(pH=pKa+log\frac{[salt]}{[acid]}\)

Exactly at the mid point,

[conjugate base of the salt]=[acid]

So, log [salt]/[acid] =0

Hence, pH of the solution will be equal to pKa of the weak acid.

Answer is option B.

Answer: 20.9 billion years.

Explanation: To estimate the age of the rock, we can use the fact that the half-life of uranium-238 is 4.47 billion years. This means that half of the uranium-238 in the rock would have decayed into lead-206 after 4.47 billion years, and half of what remains would decay in the next 4.47 billion years, and so on.

If 20% of the uranium-238 in the rock has decayed into lead-206, then 80% of the original uranium-238 is still present in the rock. This means that the rock has gone through one half-life of uranium-238 decay, and we can estimate its age by using the graph on page 253.

According to the graph, the ratio of lead-206 to uranium-238 after one half-life is approximately 0.027. This means that the rock contains 0.027 times as much uranium-238 as it did originally, and the remaining 80% of the uranium-238 corresponds to 0.8 times the original amount.

Therefore, we can estimate the original amount of uranium-238 in the rock as follows:

Original amount of uranium-238 = (0.8) / 0.027 = 29.63 times the current amount

Next, we can use the fact that each half-life corresponds to a reduction in the amount of uranium-238 by a factor of 2, to estimate the number of half-lives that have passed since the rock formed:

Number of half-lives = log2(29.63) = 4.88

Finally, we can estimate the age of the rock as follows:

Age of the rock = (4.88) x (4.47 billion years per half-life) = 20.9 billion years

Therefore, we can estimate that the age of the rock is approximately 20.9 billion years.

Answer:

4 millllllermeeters jb

Answer:

A logic bomb and a time bomb are both types of malicious software or code that are designed to cause harm to a computer system or network. Here's a brief explanation of each:

Logic Bomb:

A logic bomb is a piece of code or software that is intentionally inserted into a system to execute a malicious action when specific conditions are met. It remains dormant until triggered by a predefined event or circumstance, such as a specific date, time, or user action. Once triggered, the logic bomb may perform various harmful actions, such as deleting files, corrupting data, or disrupting system functionality. The purpose of a logic bomb is often to cause damage or to gain unauthorized access to a system.

Time Bomb:

A time bomb is similar to a logic bomb, but it is specifically designed to activate or execute its malicious payload at a certain date or time. It is usually programmed to remain undetected until the predetermined time arrives. The time bomb can be set to trigger after a specific time period or on a particular date, at which point it may carry out destructive actions. Time bombs can be used by attackers to target specific events or to coordinate an attack to occur simultaneously across multiple systems.

Both logic bombs and time bombs are considered forms of malicious code or malware and are used with malicious intent to disrupt, damage, or compromise computer systems or networks. They can be extremely harmful, and it is important to have strong security measures, such as antivirus software and regular system updates, to protect against such threats.

Explanation: