Which series reveals the source of energy for coal?

coal chemicals sun
coal plants chemicals
coal animals sun
coal plants sun

The gland that can be precisely controlled, and its amount of secretion and the area of the body involved can be varied independently is the **sweat gland**.

Sweat glands are distributed all over the body and are controlled by the autonomic nervous system. The amount of sweat secreted and the area of the body involved can be regulated by the sympathetic nervous system, which is responsible for the "fight or flight" response. This means that the body can vary the amount of sweat produced in different areas of the body depending on the situation, such as in response to exercise or heat. The secretion of sweat is also under hormonal control, with hormones such as adrenaline and cortisol increasing sweat production. Overall, sweat glands play an important role in regulating body temperature and maintaining homeostasis.

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Answer: A stopwatch

Explanation:

You don’t needed

A student requires all of them except a balance. The correct option is A.

Students calculate the volume of various rods that have the same mass using the water displacement method. Each rod's density is calculated, and the distinctive densities of each material are used to distinguish the five rods.

Then, to explain why various rods have varied densities, students think about the connection between the mass, size, and arrangement of atoms. The periodic table will be briefly introduced to the class.

The volume displacement method is often used to determine the volume of an object with an irregular shape. This technique involves submerging an object into a known amount of water; as a result, the water level will rise.

Therefore, A student requires all of them except a balance. The correct option is A.

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Option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

The long-run equilibrium condition for perfect competition is that price (P) is equal to average total cost (ATC), which is also equal to marginal cost (MC), and marginal revenue (MR).

Option (d), P=ATC=MR=MC, best represents the long-run equilibrium condition for perfect competition. In perfect competition, firms operate at the minimum point of their average total cost curve, where price equals both average total cost and marginal cost. This condition ensures that firms are earning zero economic profit and are producing at an efficient level.

In the long run, if firms are earning economic profit, new firms will enter the market, increasing competition and driving prices down. Conversely, if firms are experiencing losses, some firms may exit the market, reducing competition and causing prices to rise. This process continues until firms reach a state where price equals average total cost, marginal cost, and marginal revenue, ensuring a long-run equilibrium.

Therefore, option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

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moles = mass / molar mass We know the moles of oxytocin acetate recovered (2.2 x 10^-6 moles) and its molar mass (1067 g/mol). We need to find the mass of the oxytocin acetate in the solution, and from there we can determine the volume of the solution.

mass = moles x molar mass
mass = 2.2 x 10^-6 moles x 1067 g/mol
mass = 2.3454 x 10^-3 g

Now, we need to take into account the 10 mM Zn2+ additive. We don't know the exact concentration of the oxytocin solution, but we can assume that the 10 mM Zn2+ additive does not significantly change the volume of the solution. Therefore, we can calculate the volume of the solution using the mass of oxytocin acetate and its concentration in the original sample.Let's assume that the original sample had a concentration of 1 mM (this is just an example, the actual concentration could be different). This means that there was 1 mmol of oxytocin acetate per liter of solution. To find the volume of the solution that was analyzed, we can use the following formula:
volume = mass / (concentration x molar mass)
volume = 2.3454 x 10^-3 g / (1 x 10^-3 mol/L x 1067 g/mol)
volume = 2.3454 x 10^-6 L or 2.3454 µL
Therefore, the approximate volume of the oxytocin solution with the 10 mM Zn2+ additive that was analyzed is 2.3454 µL.

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The approximate volume of the oxytocin solution with the 10 mM Zn²⁺ additive that was analyzed is 2.3454 µL.

moles = mass / molar mass

We know the moles of oxytocin acetate recovered (2.2 x 10⁻⁶ moles) and its molar mass (1067 g/mol).

mass = moles x molar mass

mass = 2.2 x 10⁻⁶ moles x 1067 g/mol

mass = 2.3454 x 10⁻³ g

Utilizing the mass of oxytocin acetate and its concentration in the first sample, we can determine the volume of the solution. Assume for the sake of argument that the first sample had a concentration of 1 mM (the real concentration may have been different).

This indicates that each litre of solution contained 1 mmol of oxytocin acetate. Using the following formula, we can get the volume of the solution that was examined:

volume = mass / (concentration x molar mass)

volume = 2.3454 x 10⁻³ g / (1 x 10⁻³ mol/L x 1067 g/mol)

volume = 2.3454 x 10⁻⁶ L or 2.3454 µL

Therefore, the approximate volume of the oxytocin solution with the 10 mM Zn²⁺ additive that was analyzed is 2.3454 µL.

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Answer:  Most elements don't have formulas.  

Explanation:  They exist as single atoms, witn no bonds to another atom.  A few element do exist as molecules, such as )2 and N2, but they are bonded to the same atom.  There are no different elements.

Answer: 4 pretty sure :)

There are two non-bonding electron pairs are on the central atom in SF₅

A Sulfur atom (S) in the middle of the SF₅ Lewis structure is surrounded by five Fluorine atoms (F). Between each Fluorine atom and the Sulfur atom (S), there are 5 single bonds (F). All of the fluorine atoms (F) have 3 lone pairs, and the Sulfur atom has 1 lone pair (S).

So, as shown in the following picture, the central atom has two free electrons or a pair of non-bonding electrons.

Since it has five bond pairs and one lone pair. As a result, its molecules have a square pyramidal shape.

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The formulas of the compounds that were shown are;

CaCl2

K2S

AlBr3

BeF2

MgS

Ionic compounds are a type of chemical compound made up of ions, which are atoms or molecules that have a positive or negative charge due to the gain or loss of electrons. In ionic compounds, positive ions (cations) are typically metal atoms, while negative ions (anions) are typically non-metal atoms. These ions are held together in a crystal lattice structure by strong electrostatic forces, forming a solid, crystalline substance.

Ionic compounds typically have high melting and boiling points, and they are often soluble in water. They are also typically poor conductors of electricity in the solid state, but good conductors in the melted or dissolved state due to the movement of ions.

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CO2, water, and ATP are the final products. In chemical processes, glucose can be rearranged due to its higher number of chemical bonds.

The risk of some chronic problems can be reduced by identifying hyperglycemia with the aid of random blood glucose tests.

All of the body's cells use glycolysis to produce energy. Pyruvate in aerobic environments and lactate in anaerobic environments are the end products of glycolysis. For additional energy production, pyruvate enters the Krebs cycle.

The major sugar present in your blood is known as blood sugar or glucose. It comes from the food you eat and is the primary energy source for your body. Glucose is delivered by your blood to all of your  body cell to use energy.

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Answer:

yes because wet is water

Answer: Being a liquid, water is not itself wet, but can make other solid materials wet. Wetness is the ability of a liquid to adhere to the surface of a solid, so when we say that something is wet, we mean that the liquid is sticking to the surface of a material.

The volume of hydrogen gas at 45.0°C and 699 torr that can be produced by the reaction of 5.66g of zinc with excess sulfuric acid is A. 2.84 L.

To determine the volume of hydrogen gas produced, we will use the ideal gas law (PV=nRT) and stoichiometry. First, let's convert the given mass of zinc (5.66 g) to moles using its molar mass (65.38 g/mol):

5.66 g Zn × (1 mol Zn / 65.38 g Zn) = 0.0866 mol Zn

The balanced equation for the reaction is:

Zn + H₂SO₄ → ZnSO4 + H₂

From the stoichiometry, 1 mol of Zn produces 1 mol of H₂. Therefore, 0.0866 mol Zn produces 0.0866 mol H₂.

Now, let's convert the temperature to Kelvin and the pressure to atm:

T = 45.0°C + 273.15 = 318.15 K
P = 699 torr × (1 atm / 760 torr) = 0.9197 atm

We can now use the ideal gas law:

PV = nRT
V = nRT / P
V = (0.0866 mol H2)(0.0821 L·atm/mol·K)(318.15 K) / 0.9197 atm

V ≈ 2.84 L

So, the volume of hydrogen gas produced is approximately 2.84 L (option A).

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Answer:

Option A

Explanation:

The atomic number is the number of protons in the nucleus of an atom.

Molar concentration of Sodium chloride (NaCl) means the number of moles of sodium chloride present in 1L of water.

Molar mass of NaCl = Molar mass of Na + Molar mass of Cl

Molar mass of NaCl = 23 + 35.5

Molar mass of NaCl = 58.5g

∴ 1L of water contains 55.55 moles of water. Hence,

Mass of ocean water = 55.55 × 18 = 999.9g

Since, 1L of ocean water has a mass of 999.9g of which 3.5% is the salt.

hence, (999.9) (0.035) = 34.99g

So, No. of moles of NaCl = Mass of NaCl / 58g NaCl per mol

No. of moles of NaCl = 34.99/58.5

No. of moles of NaCl = 0.59 moles

So, Molar concentration or Molarity would be 0.59 moles present in 1L of solution.

Hence, Molarity or Molar Concentration = Moles of NaCl/ Volume of solution (in L)

Molarity = 0.59/1L

⇒ Molarity = 0.59M

Hence, the molarity is 0.59M

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In the high-spin state of Cr²⁺ in a tetrahedral field, there are 4 unpaired electrons.

Step-by-step explanation:

1. Determine the electron configuration of Cr²⁺: Chromium (Cr) has an atomic number of 24, so its ground-state electron configuration is [Ar] 3d⁵ 4s¹. When it loses 2 electrons to form Cr²⁺, the electron configuration becomes [Ar] 3d⁴.

2. Consider the tetrahedral field: In a tetrahedral field, the d-orbitals split into two energy levels: e (double-degenerate) and t2 (triple-degenerate). The e orbitals are lower in energy than the t2 orbitals.

3. Distribute the electrons in the high-spin state: In a high-spin state, electrons will fill the available orbitals with parallel spins before pairing up. In the case of Cr²⁺ with 4 d-electrons, two electrons will occupy the e orbitals, and the other two will occupy the t2 orbitals.

4. Count the unpaired electrons: Since all the electrons have parallel spins and occupy different orbitals in the high-spin state, there are 4 unpaired electrons in the Cr²⁺ ion within a tetrahedral field.

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Answer:

A₃B₈ + 5C₂ –> 3AC₂ + 4B₂C

Explanation:

A₃B₈ + C₂ –> AC₂ + B₂C

The equation can be balance as illustrated below:

A₃B₈ + C₂ –> AC₂ + B₂C

There are 3 atoms of A on the left side and 1 atom on the right side. It can be balance by writing 3 before AC₂ as shown below:

A₃B₈ + C₂ –> 3AC₂ + B₂C

There are 8 atoms of B on the left side and 2 atoms on the right side. It can be balance by writing 4 before B₂C as shown below:

A₃B₈ + C₂ –> 3AC₂ + 4B₂C

There are 2 atoms of C on the left side and a total of 10 atoms on the right side. It can be balance by writing 5 before C₂ as shown below:

A₃B₈ + 5C₂ –> 3AC₂ + 4B₂C

Now, the equation is balanced.

Based on the future value analysis, the Gold Oxide Drill should be selected for drilling wells.

To determine the type of drill that should be used based on future value analysis, we need to calculate the future value (total cost) for each drill type and select the one with the lowest future value.

The future value (FV) can be calculated using the formula:

FV = P * \((1 + r)^n\)

Where:

P = Monthly operation cost

r = Monthly interest rate (annual interest rate / 12)

n = Useful life in months

Let's calculate the future values for each drill type:

High-Speed Stainless Steel Drill:

P = $2,000

r = 0.12/12 = 0.01

n = 3 months

FV₁ = $2,000 * (1 + 0.01)³

     = $2,060.20

Gold Oxide Drill:

P = $1,500

r = 0.12/12 = 0.01

n = 6 months

FV₂ = $1,500 * (1 + 0.01)⁶

      = $1,556.52

Titanium Nitrite Drill:

P = $1,200

r = 0.12/12 = 0.01

n = 6 months

FV₃ = $1,200 * (1 + 0.01)⁶

       = $1,241.63

Now we compare the future values and select the drill with the lowest future value. In this case, the Gold Oxide Drill has the lowest future value, which means it would be the most cost-effective choice based on the future value analysis.

Therefore, based on the future value analysis, the Gold Oxide Drill should be selected for drilling wells.

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Answer:

0.833 moles of Phosphorus

Explanation:

100 g C * \(\frac{1 mol C}{12g C}\) * \(\frac{1 mol P}{10 mol C}\) = 0.833 mol P

Answer:

24.58 ml

Explanation:

d=m/v ---> v=m/d

v=160.8788 g/6.544 g/ml

v= 24.58 ml

To increase the yield of a reaction sometimes excess reagents maybe helpful. Certain cases it can cause negative effects also in the outcome of a reaction.

Assume a student using acetone as a solvent. Adding two-fold excess of acetone. It probably not have a significant effect on the outcome of the reaction.

Acetone is a common organic solvent. It is often used in reactions as a reaction medium or as a solvent to dissolve the starting materials.

But if the student is adding a two-fold excess of acetone as a reactant, it can lead to chemical reaction. it can lead to the formation of unwanted byproducts. Also interfere with the desired reaction.

Information of specific reaction is not given. So it is not possible to determine what product they are likely to isolate.

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Answer:

La masa molar de la sustancia disuelta es de aproximadamente 138,473 g/mol

Explanation:

Los parámetros dados son;

La masa de benceno en el recipiente = 100 gramos

La masa de benceno que se evapora del benceno puro = 1.273 gramos

La masa del soluto no volátil disuelto en 100 gramos de benceno = 10 gramos

La masa de benceno que se evapora de la mezcla = 1.205 gramos

Según la ley de Raoult, tenemos;

\(P_ {solucion} = P_ {solvente} \times X _ {solvente}\)

Dónde;

\(P_ {solucion}\) = La presión de vapor de la solución.

\(P_ {solvente}\) = La presión de vapor del solvente

\(X_ {solvente}\) = La fracción molar del solvente

Por lo tanto;

\(X_ {solvente} = \dfrac {P_ {solucion}} {P_ {solvente}}\)

Según la ley de los gases ideales, tenemos;

\(P \times V = n \times R \times T = \dfrac{m}{M} \times R \times T\)

Dónde;

P = La presión del gas

V = El volumen ocupado por el gas

m = La masa del gas

M = La masa molar del gas

R = La constante universal de los gases

T = La temperatura del gas

n = El número de moles del gas

Por lo tanto;

\(P = \dfrac{m \times R \times T}{M \times V}\)

Donde R, T, M y V son constantes, tenemos P ∝ m

\(\therefore X_ {solvente} = \dfrac {P_ {solucion}} {P_ {solvente}} = \dfrac {Masa \ evaporada \ de \ solucion} {Masa \ evaporada \ de \ solvente} = \dfrac {1.205 \ g} {1.273 \ g} \approx 0.9466\)

\(X_ {solvente}\) ≈ 0.9466

\(X_ {solvente} = \dfrac {El \ numero \ de \ moles \ del \ solvente} {El \ total \ numero \ de \ moles \ de \ la \ solucion}\)

El número de moles del solvente, C₆H₆ = (Masa de C₆H₆) / (La masa molar de C₆H₆) = 100 g / (78.11 g.mol) ≈ 1.28025 moles

El número de moles del solvente, C₆H₆ ≈ 1.28025 moles

El número total de moles = El número de moles del solvente, C₆H₆ + El número de moles del soluto no volátil, \(n_ {soluto}\)

\(\therefore X_ {solvente} = 0.9466 = \dfrac {1.28025 \ moles} {1.28025 \ moles + n_ {soluto}}\)

0.9466 × (1.28025 moles + \(n_ {soluto}\)) = 1.28025 moles

1.21189 moles + 0.9466 × \(n_ {soluto}\) = 1.28025 moles

\(n_ {soluto}\) = (1.28025 - 1.21189)/0.9466 moles ≈ 0.07221635 moles

\(\therefore \dfrac {Masa \ de \ soluto} {Molar \ masa \ de \ soluto} = \dfrac {10 \ g} {Molar \ masa \ de \ soluto} \approx 0.07221635 \ moles\)

\(\ Masa \ molar \ de \ soluto = \dfrac {10 \ g} {0.07221635 \ moles} \approx 138.473 \ g / moles\)

La masa molar de la sustancia disuelta (el soluto) ≈ 138,473 g/mol

The statement is FALSE. Non-ferrous metals can be hardened by heat treatment, although the mechanisms and processes involved may differ from ferrous metals.

Heat treatment techniques such as precipitation hardening can be used to increase the strength of non-ferrous metals. Non-ferrous metals are metals or alloys that do not include iron (or iron allotropes, such as ferrite, etc.) in significant quantities. Non-ferrous metals are employed because they have desired qualities like reduced weight (for example, aluminium), greater conductivity (for example, copper), non-magnetic characteristics, or corrosion resistance (for example, zinc), even though they are often more expensive than ferrous metals. In the iron and steel sectors, several non-ferrous materials are also employed. Bauxite, for instance, is used as a flux in blast furnaces, whereas wolframite, pyrolusite, and chromite are utilised to create ferrous alloys.

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The molecular mass of the substance is 181 g/mol if 22. 5 g dissolved in 250 g of water produces a solution whose freezing point is -0. 930°C.

To determine the molecular mass of the substance, we can use the freezing point depression formula:

ΔTf = Kf·m

Where ΔTf is the freezing point depression, Kf is the freezing point depression constant of water (1.86°C·kg/mol), and m is the molality of the solution, which is the number of moles of solute per kilogram of solvent.

We can start by calculating the molality of the solution:

molality = moles of solute/mass of solvent (in kg)

Since we know that 22.5 g of the substance is dissolved in 250 g of water, we can calculate the mass of the solvent as:

mass of solvent = 250 g / 1000 = 0.250 kg

The mass of the solute can be calculated as:

mass of solute = 22.5 g / 1000 = 0.0225 kg

Now we can calculate the molality of the solution:

molality = 0.0225 kg / 0.250 kg = 0.09 mol/kg

Next, we can use the freezing point depression formula to calculate the molecular mass of the substance:

ΔTf = Kf·m

-0.930°C = 1.86°C·kg/mol x 0.09 mol/kg

Solving for the molecular mass (M):

M = (Kf x m) / ΔTf = (1.86°C·kg/mol x 0.09 mol/kg) / 0.930°C

M = 0.181 kg/mol = 181 g/mol

Therefore, the molecular mass of the substance is 181 g/mol.

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Answer:

the answer base on my test is H3O4P1

Dow Chemical would be best described as a multinational corporation in this scenario.

This is the type of corporation which are involved in controlling production of goods and services in at least one country different from that of residence.

Dow chemical is known to have a plant in Germany and Russia thereby making it a multinational corporation.

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The crash where the cone experience a stronger force is option D because: Crash 1: the force on the black hockey puck was stronger in this crash, so the force on the cone was also stronger.

The ball is drawn back to Earth by gravitational force. The ball returns to Earth as a result of friction. The ball is forced back toward Earth by magnetic force.

A puck's velocity changes when a player makes contact with it when it is still. He causes the puck to speed up, in other terms. The hockey stick's force, which causes the acceleration, is responsible. The velocity grows as long as this force is in motion.

Therefore, the force applied to an object must be larger than what is required for a progressive slowing down if the object must be slowed down quickly. For instance, a bicycle's brakes will slow or stop it more quickly the more force is given to it.

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See full question below

After hockey practice, Carissa and Keenan were playing a game where they were pushing some objects to get them to crash. They were using a cone and two different pucks—a black one with more mass for Crash 1 and a blue one with less mass for Crash 2. They want to know what happened to the cone.

Use the information from the diagram to answer.

In which crash did the cone experience a stronger force? How do you know?

answer choices

There was no force on the cone. In both crashes, only the hockey puck experienced a force.

The diagram doesn’t tell you anything about the force on the cone. It only gives information about the force on the pucks.

It was the same force in both crashes; the hockey puck changed speed by the same amount in each crash, so the force on the cone was the same each time.

Crash 1; the force on the black hockey puck was stronger in this crash, so the force on the cone was also stronger.

The solution pH for 50mL of O.1M HCL after titration with 50ml 0.15M NaOH is 7 (neutral).

Titration is strong acid vs strong base. HCl and NaOH react in a 1:1 mole ratio.

pH= -log[H₃O⁺]

Number of solutes in H₃O⁺] = 0.1 molL⁻¹ × 50 × 10⁻³ L

Number of solutes in H₃O⁺] = 0.005 moles

Number of moles in NaOH = 0.1 molL⁻¹ × 50 × 10⁻³ L

Number of moles in NaOH = 0.005 moles

Since the difference in the number of moles between acid and base is zero which says that the solution is neutral it only contains water and aqueous sodium chloride.

Since the pH of the solution = -log (1×10-7) = 7

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Four reasonable resonance structures for the \(PO_3F^2^-\) are:

Structure 1:
O- P(=O)-O- F

Structure 2:
O- P(-O•)-O•- F

Structure 3:
O•- P(-O)-O- F,

Structure 4:
O•- P(-O•)-O•- F

The \(PO_3F^2^-\) ion has four reasonable resonance structures, which are shown below:

Structure 1:
O- P(=O)-O- F, with formal charges of +1 on the P atom, -1 on the F atom, and -1 on each of the two terminal O atoms.

Structure 2:
O- P(-O•)-O•- F, with formal charges of 0 on the P atom, -1 on the F atom, and -1 on each of the two terminal O atoms.

Structure 3:
O•- P(-O)-O- F, with formal charges of -1 on the P atom, -1 on the F atom, and 0 on each of the two terminal O atoms.

Structure 4:
O•- P(-O•)-O•- F, with formal charges of -2 on the P atom, -1 on the F atom, and 0 on each of the two terminal O atoms.

To draw four reasonable resonance structures for the \(PO_3F^2^-\) ion, consider that the central phosphorus (P) atom is bonded to the three oxygen (O) atoms and to the fluorine (F) atom. Here are the four resonance structures with formal charges:

1. P is double bonded to one O, single bonded to the other two O atoms, and single bonded to F. The O atom with a double bond has a formal charge of 0, the other two O atoms have a formal charge of -1 each, P has a formal charge of +1, and F has a formal charge of 0.

2. P is double bonded to the second O, single bonded to the other two O atoms, and single bonded to F. The O atom with a double bond has a formal charge of 0, the other two O atoms have a formal charge of -1 each, P has a formal charge of +1, and F has a formal charge of 0.

3. P is double bonded to the third O, single bonded to the other two O atoms, and single bonded to F. The O atom with a double bond has a formal charge of 0, the other two O atoms have a formal charge of -1 each, P has a formal charge of +1, and F has a formal charge of 0.

4. P is single bonded to all three O atoms and single bonded to F. One O atom has a formal charge of 0, the other two O atoms have a formal charge of -1 each, P has a formal charge of +1, and F has a formal charge of -1.

These four resonance structures show the distribution of electrons and formal charges for the \(PO_3F^2^-\) ion, illustrating its resonance stabilization.

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Answer:

I believe it's either D or A I did it in my math

Explanation:

Compound: a substance that is made up of more than 1 type of atom bonded together Example: H2O

Mixture: combination of two or more elements or compounds not chemicaly bonded together. example: Sugar and salt in one container

elements pure substance of an atom. Example: hydrogen