The statement "The game scores of season 2006 have a greater spread than the game scores of season 2005" must be true.
To determine which statement must be true, we need to compare the spreads of game scores between different seasons. The spread refers to the range or variability of the scores.
The statement "The game scores of season 2006 have a greater spread than the game scores of season 2005" is true because it implies that the range of game scores in 2006 is larger than the range of game scores in 2005. This means that the game scores in 2006 are more spread out or have more variability compared to the game scores in 2005.
The other statements are not necessarily true based on the information provided. We don't have any information about the game scores of season 2008 or season 2007 in relation to other seasons. Therefore, we cannot make conclusions about the spreads of game scores in those specific years.
In summary, the statement "The game scores of season 2006 have a greater spread than the game scores of season 2005" is the only statement that can be confirmed as true based on the given information.
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| Question 10 Solve each one of the following linear systems. When taking the augmented matrix, use the order: in first place, y in second, z in third, and w in fourh. -x-5 y-5 z+3 w = -7 5x + 24 y + 20 z-15 w = 22 -5 x 30 y - 51 z + 15 w = [Select] -103 5 x + 20 y + 5z - 15 w x-5 y 3z-5 w = = -15 -3 : [Select] -5 x + 24 y + 15z + 30 w = 32 -5 x + 20 y + 15z +51 w 103 -85 = 5 x 20 y 15 z- 45 w = -x-5 y + 15 z-5 w = -7 -5 x 24 y + 72 z 30 w = -52 . [Select] = 117 5x+ 20 y 5 x + 20 y = 105 = 7 - 60 z +49 w 60 z + 45 w x + 5y + 5z - 15 w -5 x 24 y-30 z +72 w 5x+20 y + 51 z - 60 w -5 x 30 y-5 z+90 w -x-5 y + 5 z - 15 w -5 x 24 y + 30 z 90 w [Select] = -52 = 123 = 35 = 23 128 [Select] 5 x + 30 y + z-3 w = -47 5x + 30 y + 5 z-15 w = -35 Choose the options according to the following solutions. (In the options, let C be the free variable.) 1. < 2, 0, -2, 3 > + c <3,1,0,0 > 2. < 2, 2, 0,3 + c <3,0,1,0 > 3. < 2, 4. <2, -2, 3,0 > + c 2, 3,0 > + c < 0, 0, 3, 1 > <3,0,0,1> 5. < 2, 2, 0, 3 > + c < 0, 3, 1,0 > 6. < 2, -2, 3,0> + c <0,3,0,1 > : 10 pts
The linear system is inconsistent for every value of x.
solve the given linear system, let's write the augmented matrix and perform row operations to reduce it to row-echelon form:
[ -1 -5 1 3 | -7 ]
[ 5 24 20 -15 | 22 ]
[ -5 30 -51 15 | [Select] ]
[ 5 20 5 -15 | [Select] ]
Performing row operations:
Row 2 = Row 2 + Row 1:
[ -1 -5 1 3 | -7 ]
[ 4 19 21 -12 | 15 ]
[ -5 30 -51 15 | [Select] ]
[ 5 20 5 -15 | [Select] ]
Row 3 = Row 3 + Row 1:
[ -1 -5 1 3 | -7 ]
[ 4 19 21 -12 | 15 ]
[ -6 25 -50 18 | [Select] ]
[ 5 20 5 -15 | [Select] ]
Row 4 = Row 4 + Row 1:
[ -1 -5 1 3 | -7 ]
[ 4 19 21 -12 | 15 ]
[ -6 25 -50 18 | [Select] ]
[ 4 15 6 -22 | [Select] ]
Row 3 = Row 3 + Row 2:
[ -1 -5 1 3 | -7 ]
[ 4 19 21 -12 | 15 ]
[ -2 44 -29 6 | [Select] ]
[ 4 15 6 -22 | [Select] ]
Row 4 = Row 4 + Row 2:
[ -1 -5 1 3 | -7 ]
[ 4 19 21 -12 | 15 ]
[ -2 44 -29 6 | [Select] ]
[ 0 1 27 -34 | [Select] ]
Row 3 = Row 3 + 2 * Row 4:
[ -1 -5 1 3 | -7 ]
[ 4 19 21 -12 | 15 ]
[ -2 46 -7 -62 | [Select] ]
[ 0 1 27 -34 | [Select] ]
Row 3 = Row 3 + Row 2:
[ -1 -5 1 3 | -7 ]
[ 4 19 21 -12 | 15 ]
[ -2 65 20 -96 | [Select] ]
[ 0 1 27 -34 | [Select] ]
Row 2 = Row 2 - 4 * Row 1:
[ -1 -5 1 3 | -7 ]
[ 0 39 17 -24 | 43 ]
[ -2 65 20 -96 | [Select] ]
[ 0 1 27 -34 | [Select] ]
Row 3 = Row 3 + 2 * Row 1:
[ -1 -5 1 3 | -7 ]
[ 0 39 17 -24 | 43 ]
[ 0 55 22 -90 | [Select] ]
[ 0 1 27 -34 | [Select] ]
Row 3 = Row 3 - 55 * Row 2:
[ -1 -5 1 3 | -7 ]
[ 0 39 17 -24 | 43 ]
[ 0 0 -3 90 | [Select] ]
[ 0 1 27 -34 | [Select] ]
Row 4 = Row 4 - Row 2:
[ -1 -5 1 3 | -7 ]
[ 0 39 17 -24 | 43 ]
[ 0 0 -3 90 | [Select] ]
[ 0 0 10 10 | [Select] ]
Row 4 = (1/10) * Row 4:
[ -1 -5 1 3 | -7 ]
[ 0 39 17 -24 | 43 ]
[ 0 0 -3 90 | [Select] ]
[ 0 0 1 1 | [Select] ]
Row 3 = (-1/3) * Row 3:
[ -1 -5 1 3 | -7 ]
[ 0 39 17 -24 | 43 ]
[ 0 0 1 -30 | [Select] ]
[ 0 0 1 1 | [Select] ]
Row 2 = Row 2 - 17 * Row 3:
[ -1 -5 1 3 | -7 ]
[ 0 39 0 517 | [Select] ]
[ 0 0 1 -30 | [Select] ]
[ 0 0 1 1 | [Select] ]
Row 1 = Row 1 - Row 3:
[ -1 -5 0 33 | [Select] ]
[ 0 39 0 517 | [Select] ]
[ 0 0 1 -30 | [Select] ]
[ 0 0 1 1 | [Select] ]
Row 1 = Row 1 + 5 * Row 2:
[ -1 0 0 53 | [Select] ]
[ 0 39 0 517 | [Select] ]
[ 0 0 1 -30 | [Select] ]
[ 0 0 1 1 | [Select] ]
Row 1 = (-1) * Row 1:
[ 1 0 0 -53 | [Select] ]
[ 0 39 0 517 | [Select] ]
[ 0 0 1 -30 | [Select] ]
[ 0 0 1 1 | [Select] ]
Row 4 = Row 4 - Row 3:
[ 1 0 0 -53 | [Select] ]
[ 0 39 0 517 | [Select] ]
[ 0 0 1 -30 | [Select] ]
[ 0 0 0 31 | [Select] ]
Row 2 = (1/39) * Row 2:
[ 1 0 0 -53 | [Select] ]
[ 0 1 0 13 | [Select] ]
[ 0 0 1 -30 | [Select] ]
[ 0 0 0 31 | [Select] ]
Row 1 = Row 1 + 53 * Row 4:
[ 1 0 0 0 | [Select] ]
[ 0 1 0 13 | [Select] ]
[ 0 0 1 -30 | [Select] ]
[ 0 0 0 31 | [Select] ]
Now, we have the row-echelon form of the augmented matrix. To find the solutions, we'll back-substitute:
From the last row, we have 0x + 0y + 0z + 31w = [Select], which implies 31w = [Select]. Since 31w can't be equal to [Select] (because it is a constant term), there is no solution to the system.
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Honestly don't understand this
pleaae help me solve this 61/2×(8/9÷13/18)+(3/4) of 31/5
Answer:
\(10 \frac{2}{5}\)
Step-by-step explanation:
Using BODMAS
\(6\frac{1}{2} \times (\frac{8}{9} \div\frac{13}{18}) + ( \frac{3}{4} )\ of \ 3\frac{1}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ solving \ expression \ inside \ bracket \ ]\\\\\frac{13}{2} \times (\frac{8}{9} \times \frac{18}{13}) + (\frac{3}{4}) \ of \ \frac{16}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ \frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c} \ ]\\\\\frac{13}{2} \times (\frac{16}{13}) + (\frac{3}{4}) \ of \frac{16}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ solving \ of \ ] \\\\\)
\(\frac{13}{2} \times (\frac{16}{13} ) + (\frac{3}{4} \times \frac{16}{5} )\\\\\frac{13}{2} \times (\frac{16}{13} ) + \frac{12}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [\ solving \ \times \ expressions \ ] \\\\(\frac{13}{2} \times \frac{16}{13}) + \frac{12}{5}\\\\8 + \frac{12}{5}\\\\\frac{40 + 12}{5}\\\\\frac{52}{5}\\\\10\frac{2}{5}\)
Amad was curious if triangles \triangle ABC△ABCtriangle, A, B, C, and \triangle EDF△EDFtriangle, E, D, F were congruent. He was able to map one figure onto the other using a reflection and a rotation. Amad concluded: "I was able to map \triangle ABC△ABCtriangle, A, B, C onto \triangle EDF△EDFtriangle, E, D, F using a sequence of rigid transformations, so the figures are congruent."
Answer:
There is no error, Amad is correct.
Step-by-step explanation:
Khan Academy Checked.
Amad had done no error. His conclusion is true.
What is Congruency?Two triangles are said to be congruent if their sides are equal in length, the angles are of equal measure, and they can be superimposed on each other.
For example,
In the figure given above, Δ ABC and Δ PQR are congruent triangles. This means that the corresponding angles and corresponding sides in both the triangles are equal.
Sides: AB = PQ, BC = QR and AC = PR;
Angles: ∠A = ∠P, ∠B = ∠Q, and ∠C = ∠R.
Therefore, Δ ABC ≅ Δ PQR
The following are the congruence theorems or the triangle congruence criteria that help to prove the congruence of triangles.
SSS (Side, Side, Side)SAS (side, angle, side)ASA (angle, side, angle)AAS (angle, angle, side)RHS (Right angle-Hypotenuse-Side or the Hypotenuse Leg theorem)As, from the given cases the prediction of congruency of two triangles is correct. There is no error he made.
Hence, Amad had not made any error.
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For right triangle trig ratios, the hypotenuse will _________ be in the denominator
A) Sometimes
B) Never
C) Always
Three triangles are shown on the centimetre grid. A, B, C. A\ Which triangle has the largest area? B\ Work out the area of this triangle. Give your answer a.S a decimal.
Answer:
A) The three triangles have the same area
B) 10 square units
Step-by-step explanation:
In the figure attached, the triangles are shown.
A) The three triangles have the same area because all have the same base and height (see figure)
B) Area of a triangle = (1/2)*base*height
Area of a triangle = (1/2)*4*5 = 10 square units
Answer:
A) = C
B) = 4.5 cm^2
Evaluate the given integral by changing to polar coordinates. ∬ D
cos( x 2
+y 2
)dA, where D is the disk with center the origin and radius 9
To evaluate the given integral ∬D cos(x^2 + y^2) dA using polar coordinates, we convert the double integral into polar coordinates and integrate over the corresponding region in the polar plane. The region D is a disk with center at the origin and radius 9.
In polar coordinates, the variables x and y are expressed as x = r cosθ and y = r sinθ, where r represents the radial distance and θ represents the angle.
To convert the integral, we need to determine the limits of integration for r and θ. Since D is a disk with radius 9, the limits for r are from 0 to 9. The limits for θ will cover the full range from 0 to 2π since we want to cover the entire disk.
The differential area element dA in polar coordinates is given by dA = r dr dθ.
Substituting the variables and the differential area element into the integral, we have:
∬D cos(x^2 + y^2) dA = ∫(θ=0 to 2π) ∫(r=0 to 9) cos(r^2) r dr dθ.
We can then evaluate this double integral using the limits of integration and the appropriate integration techniques to find the result.
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help me please ill give brainly :D please dont answer for my points :(
Answer:
15 days
Step-by-step explanation:
5 people * 16 days * 6 hrs= 480 hours
8 people * x days * 4 hours= 32x hours
32x=480x= 480/32x= 15 daysFind the value of p if (3, 2) is a solution of px – 5y + p2 = 0.
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Substitute the x and y values in:
p^2 + 3p - 5(2) = 0
p^2 + 3p - 10 = 0
Factorise this:
(p - 2)(p + 5)
p = 2
p = -5
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GM Geometry BCR-imagine Ed
Ox-1)² + (y + 2)² =25
Ox+2)+(y-1)²=5
O(x + 2)² + (y-1)²=25
O(x-1)² + (y + 2)²=5
7
Which equation represents a circle that contains the point (-5,-3) and has a center at (-2, 1)?
Distance formula: √(x₂-x)² + (xx-13²
45:1
(-2, 1) is (x + 2)² + (y - 1)² = 25 is the equation for the circle whose centre is at (-2, 1) and contains the point (-5, -3).
To find the equation of a circle with a center at (-2, 1) that contains the point (-5, -3), we can use the distance formula. The distance between the center (-2, 1) and any point (x, y) on the circle should be equal to the radius.
Let's calculate the distance between the center and the given point:
Distance = √[(x₂ - x)² + (y₂ - y)²]
Plugging in the values:
Distance = √[(-5 - (-2))² + (-3 - 1)²]
Distance = √[(-5 + 2)² + (-3 - 1)²]
Distance = √[(-3)² + (-4)²]
Distance = √[9 + 16]
Distance = √25
Distance = 5
The distance between the center and the given point is 5 units. Consequently, the circle's radius is 5.
Using the general equation for a circle, which is (x - h)² + (y - k)² = r², where (h, k) stands for the centre and r for the radius, is now possible.
Plugging in the given values:
(x - (-2))² + (y - 1)² = 5²
(x + 2)² + (y - 1)² = 25
As a result, (-2, 1) is (x + 2)² + (y - 1)² = 25 is the equation for the circle whose centre is at (-2, 1) and contains the point (-5, -3).
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Given (x – 7)2 = 36, select the values of x. x = 13 x = 1 x = –29 x = 42
After solving the given expression the values for x will be equal to x = 1 and x = 13.
What is an expression?Mathematical actions are called expressions if they have at least two terms that are related by an operator and include either numbers, variables, or both. Adding, subtraction, multiplying, and division are all reflection coefficient operations. A mathematical operation such as reduction, addition, multiplication, or division is used to integrate terms into an expression.
As per the given information in the question,
The given equation is,
(x - 7)² = 36
x - 7 = √36
x = ±6
Then the values for x will be,
x1 = 6 + 7 = 17
x2 = -6 + 7 = -1
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Factor the Polynomial
5x2 + 45x
Answer:
55x
Step-by-step explanation:
5x*2+45x=
10x + 45x= 55x
Find y as a function of x if y(4)−12ym+36y′′=0 y(0)=19,u′(0)=2,u′′(0)=36,u′′(0)=0
The final solution of y as a function of x if y(4)−12ym+36y′′=0 y(0)=19,u′(0)=2,u′′(0)=36,u′′(0)=0
is given by: y(x) = 1\(8 + c2 e^x + c3 e^(7x/2) + 8e^(7x/2) + 92x - (123/2).\)
Given the data: \(y(4)−12ym+36y′′=0 and y(0)=19,u′(0)=2,u′′(0)=36,u′′(0)=0\)
Now, we need to find y as a function of x. Here is the solution for it.
We know that the solution of y(4)−12ym+36y′′=0 is given by the characteristic equation as:
r(r-1)(r-2)(r-3) - 12r^2(r-1) + 36r(r-1) = 0
Simplifying, we get:
\(r(r-1)(r-2)(r-3) - 12r^3(r-1) + 36r(r-1) = 0\)
\(r(r-1){(r-2)(r-3) - 12r(r-1) + 36} = 0\)
\(r(r-1)(r^2 - 5r + 6 - 12r^2 + 12r + 36) = 0\)
\(r(r-1)(-12r^2 - 5r + 42) = 0\)
\(r1 = 0, r2 = 1, r3 = 7/2\)
Therefore, the complementary function is given by yh(x) = c1 + c2 e^x + c3 e^(7x/2)
Also, given that y(0) = 19, we have: yh(0) + yp(0) = 19 ....(i)
Now, we need to find yp(x). We have: y(4)−12ym+36y′′=0 ....(ii)
Using the operator method, we have: D^2(D-1)(D-2)(D-3)y = 0
D^2(D-1)(D-2)(D-3)[yp] = 0 ....(iii)
Applying D-2 on both sides of equation (iii), we get: D^2(D-1)(D-2)[yp] = 0
On differentiating both sides w.r.t x, we get:
D^3(D-1)(D-2)[yp]' + D^2(D-1)(D-2)yp'' = 0
Again, applying D-2, we get:
D^3(D-1)[yp]''' + 2D^2(D-1)(D-2)[yp]'' + D(D-2)(D-1)yp''' = 0
[D-2]y'' = [D-2]yp'' + [D-2]yh''
Using the above equations, we get:
[D-2]yp'' = -[D-2]yh'' = -7c3e^(7x/2)/4
[D-2]yp'' = -7c3e^(7x/2)/4 ....(iv)
Integrating both sides of equation (iv) w.r.t x, we get: yp'' = (7/4) c3e^(7x/2) + c4
On differentiating w.r.t x, we get: yp' =
(7/8) c3e^(7x/2) + c4x + c5
Using the condition u'(0) = 2, we get:
yp'(0) = (7/8) c3 + c5 = 2
Using the condition u''(0) = 36, we get:
yp''(0) = (7/4) c3 + c4 = 36
Also, we have u''(0) = 0, which implies:
y(0) + 2y'(0) + 36y''(0) = 19 + 2(c4 + c5) = 0 or c4 + c5 = -19/2
Solving the above equations, we get:
c3 = 8, c4 = 92, c5 = -123/2
Therefore, the particular solution is given by:
yp(x) = 8e^(7x/2) + 92x - (123/2)
Therefore, the general solution is given by: y(x) = yh(x) + yp(x)
y(x) = c1 + c2 e^x + c3 e^(7x/2) + 8e^(7x/2) + 92x - (123/2)
Putting x = 0 in the above equation, we get:
c1 + c2 + c3 + 19 - (123/2) = 0 or c1 + c2 + c3 = 25.5
Using this in equation (i), we get:
25.5 + 8 + 92 - (123/2) = 19 + c1 or c1 = 18
Therefore, the final solution is given by: y(x) =
18 + c2 e^x + c3 e^(7x/2) + 8e^(7x/2) + 92x - (123/2).
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Find a 95% confidence interval for the slope of the model below with n = 30 Coefficients: Estimate Std.Error t value Pr(>[t]) (Intercept) 7.453 1.194 6.24 0.000 Dose -0.5485 0.3099 -1.77 0.087 Round your answers to three decimal places. Attempts: 0 of 4 used Save for Later Submit Answer
The estimated slope of the model is -0.5485, with a standard error of 0.3099. The t-value for the slope is -1.77, and the p-value is 0.087. We need to calculate a 95% confidence interval for the slope.
To calculate the confidence interval for the slope, we can use the formula: estimate ± (t-value) * (standard error). Given the estimate of -0.5485 and the standard error of 0.3099, we need to find the t-value corresponding to a 95% confidence level with n-2 degrees of freedom (n = 30 in this case). Checking the t-distribution table, the critical value for a two-tailed test is approximately 2.045. Thus, the margin of error is 2.045 * 0.3099.
Calculating the confidence interval:
Lower bound = -0.5485 - (2.045 * 0.3099)
Upper bound = -0.5485 + (2.045 * 0.3099)
Evaluating the above expressions, we find:
Lower bound ≈ -0.638
Upper bound ≈ -0.459
Therefore, the 95% confidence interval for the slope is approximately (-0.638, -0.459). This means we are 95% confident that the true slope falls within this range, based on the given data.
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What value of c makes the equation true? assume x greater-than 0 and y greater-than 0 rootindex 3 startroot startfraction x cubed over c y superscript 4 baseline endfraction endroot = startfraction x over 4 y (rootindex 3 startroot y endroot) endfraction
The value of c = 64 makes the equation true.
What is an Equation ?An equation is defined as the mathematical statement formed when two algebraic expression are equated by an equal sign.
It is given in the question that
x> 0 and y>0
\(\rm \sqrt[3]{\dfrac{x^3}{cy^4} }= \dfrac{x}{4y\sqrt[3]{y}}\\\\\\{\dfrac{x^3}{cy^4} = \dfrac{x^3}{64y^3 \times y} \\\\\\\\\\\therefore\; from \;this \\\\c= 64\\\)
The value of c = 64 makes the equation true.
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Which expression is equivalent to x2(3x3−2x)−(−7x3+2) ?
Answer:
R27.
Step-by-step explanation:
what is 67-u=182 i got 249 and ik it is wrong
Answer:
Step-by-step explanation:
67 - u = 182
67 - 182 = u
-115 = u
Unit 6 Sample Work: Do all questions. Show your work!
Sketch a graph of the quadratic function with the given vertex and through the given point. Then write the
equation of the parabola in vertex form and describe how the function was transformed from the parent
function y = ².
1. vertex (0, 0), point (-2.3)
The graph of the quadratic function y = 0.75x² is given by the image at the end of the answer.
The notation y = 0.75x² is already in vertex form, meaning that the function was vertically compressed by a factor of 3/4 from the original graph.
How to define the quadratic equation?The definition of a quadratic equation with vertex (h,k) is given as follows:
y = a(x - h)² + k.
In which a represents the leading coefficient of the quadratic function.
In this problem the coordinates of the vertex are:
(0,0).
Hence the parameters are:
h = 0, k = 0.
Thus the equation is:
y = ax².
When x = -2, y = 3, hence the leading coefficient is given as follows:
3 = a(-2)²
4a = 3
a = 3/4
a = 0.75.
Hence the equation is:
y = 0.75x².
The multiplication by 0.75 means that the parent function y = x² is vertically compressed by a factor of 0.75.
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how to graph in standard form
Answer:If the equation of a line is in standard form, the easiest method to graph the line is by finding intercepts. Remember that at the y-intercept, the x coordinate is equal to 0, and that at the x-intercept, the y coordinate is equal to 0. To find the y-intercept, set x equal to 0 and solve for y.
Step-by-step explanation: hope this helps you
What is the equation of this line? Graph of a line passing through the origin and the point begin ordered pair 4 comma negative 1 end ordered pair
Answer:
y = - \(\frac{1}{4}\) x
Step-by-step explanation:
the equation of a line passing through the origin is
y = mx ( m is the slope )
calculate m using the slope formula
m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (4, - 1) ← 2 points on the line
m = \(\frac{-1-0}{4-0}\) = \(\frac{-1}{4}\) = - \(\frac{1}{4}\)
y = - \(\frac{1}{4}\) x ← equation of line
the picture shows a man next to a tree the man has a height of 1.8m the man and the tree are drawn tO the same scale work out an estimate for height in metres of the tree
The height of the tree is 5.4 meters.
What is multiplication?Multiplication is a mathematical arithmetic operation. It is also a process of adding the same types of expression for some number of times.
Example - 2 × 3 means 2 is added three times, or 3 is added 2 times.
Given:
The picture shows a man next to a tree.
The man has a height of 1.8 meters.
The man and the tree are drawn to the same scale.
The height of the tree = 1.8 x 3 = 5.4 meters
Therefore, the height is 5.4 meters.
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Answer:7.2
Step-by-step explanation: as the man is 1.8 you can see that if you add on top of him 4 more in total that would be the height of the tree so the calculation would be 1.8x4 which would be 7.2
What is the slope of the line in this graph?
Answer:
it is b 5/7
Step-by-step explanation:
bc you rise 5 and run 7
hope this helps
Please mark me brainlest
PLEASE HELP- URGENT!
Step-by-step explanation and Answer:
i) 48-(10-3+(\(4^{2}\)))+2 x (4)
=33
ii)7 x (2) + 3 x (5)-(2)-1)³
=2
iii) (3 x 10)+9 x (3)-3
=54
iv)135÷ (1+\(2^{2}\)) -(8)-5)x 4
=15
Find missing length.
One diagonal of a kite is twice as long as the other diagonal. If the area of the kite is 240 square inches, what are the lengths of the diagonals?
If one diagonal of a kite is twice as long as the other diagonal and the area of the kite is 240 square inches, then the length of the shorter diagonal is 4√15 inches and the length of the longer diagonal is 8√15 inches.
To find the length of the diagonals, follow these steps:
Let the length of the shorter diagonal = x. So, the length of the longer diagonal = 2x.Area of the kite = (1/2)×product of diagonals= (1/2)×x×2x= x² square inchesSince the area of the kite is 240 square inches, then x² = 240 ⇒x = √240 ⇒x = 4√15 unitsTherefore, the length of the shorter diagonal is x = 4√15 inches and the length of the longer diagonal is 2x = 8√15 inches.Learn more about kite:
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Write an inequality if correct you will get a brainlest
No boat may be rented for more than t 7.5.
Which 5 forms of inequality math are there?The larger than symbol (>), just under symbol (), more than or equal to symbol (), less than or similar to symbol (), but not equal to symbol () are the four inequality symbols in mathematics.
What does GCSE math inequality mean?Relationships among two expressions that aren't equivalent to one another are known as inequalities.The symbols, >,, and, are used to denote inequalities. translates form right to left as "7 is larger than" or "is less than 7."
The phrase "at most" means "less than or equivalent to." Hence, the lesser than or equivalent to sign will be used to represent the disparity. The hourly rate for the boat is $6, which is equivalent to:
6t
A discount coupon means subtracting $4 from the 7t:
\(6t-3\)
When these are placed with the inequality:
6t - 3 ≤ 45
Solving this inequality means isolating the variable. To do this, adding 4 to both sides will be the first step.
6t ≤ 45
Finally, dividing both sides by 6 will get the final answer of 7.5, meaning the possible number of hours they could rent the boat is no more than 7.5.
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PLS HELP WILL MARK BRAINLIEST TO THE BEST ANSWER !
Answer:
13mn
Step-by-step explanation:
(10mn-5m+3n)+(mn-5m-3n)+(mn+9m+4n)
8mn+(-8mn)+13mn
=13mn
that's the answer I think
y/-7 = 1/14
y = ?
pls answer as a reduced fraction.
Answer:
y = -1/2
Step-by-step explanation:
−7⋅
Answer:
y=-1/2Step-by-step explanation:
y/-7=1/14
use cross multiplication
ie,14×y=1×-7 14y= -7 y= -7/14 y= -1/2Hope it helps
What is the vertex of g(x) = -6.3|x|
Help please !!!!!!!!!!
Answer:
D
Step-by-step explanation:
A function means that each input value (in this case, x) has only one output value (y). The vertical line test states that if a vertical line intersects with the relation more than once, it is not a function. Therefore, as a vertical line at x=0 intersects with the graph twice, the graph fails the vertical line test
How much do you save using the better buy? 432 for 6 or 364 for 7