While two leaders may have identical expectations, the way they reach their goals is always dependent on the unique arrangement of their strengths. True or False Quizlet

In the case above,  poor connection at the pressure cycling switch  and also a faulty A/C clutch coil could be the cause.

The cause that hinders the A/C Compressor from engaging are:

Note that the pressure switches is known to be one that control the on/off function of any kind of AC compressor and as such, if there is switch failure, it can hinder the AC compressor from functioning at all.

Therefore, technician A and B are correct.

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Answer:

mechanical engineer is the best answer

Economic activities can occur during and between different stages of various processes.

Here are some examples:

Production Stage: During the production stage, economic activities can include the purchase of raw materials, labor costs, and the use of machinery and equipment.

Distribution Stage: During the distribution stage, economic activities can include transportation costs, warehousing costs, and marketing costs.

Consumption Stage: During the consumption stage, economic activities can include the purchase of goods and services by consumers.

Recycling Stage: During the recycling stage, economic activities can include the collection and processing of waste materials, the production of recycled materials, and the sale of these materials to manufacturers.

Innovation Stage: Economic activities during the innovation stage can include research and development expenses, patents, and intellectual property rights.

Service Stage: During the service stage, economic activities can include the provision of services to customers, such as consulting, repair, and maintenance services.

Investment Stage: During the investment stage, economic activities can include the purchase of securities, property, and other assets.

Overall, economic activities occur throughout various stages of a process, from the production of goods and services to their consumption and beyond.

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I'm sorry, but I cannot provide a screenshot without further context. However, I can explain the general concept of what happens in an antenna.

The basic idea behind an antenna is that it converts electrical signals into electromagnetic waves that can be transmitted through the air, and it can also convert incoming electromagnetic waves into electrical signals that can be interpreted by an electronic device.

The antenna works by using the movement of electrons in a conductive material to generate the electromagnetic waves. When a current flows through a wire or other conductor, it creates a magnetic field around the wire.

If the current is changing, the magnetic field will also change, and this change in the magnetic field will create an electric field that will propagate through space as an electromagnetic wave.

When an electromagnetic wave reaches an antenna, the electric field of the wave will cause the electrons in the antenna to move back and forth. This motion of the electrons generates a current in the antenna that can be used to drive an electronic circuit or to generate a signal that can be sent to another antenna.

the electrons in the receiving antenna do move in response to incoming electromagnetic waves.

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Answer:

- the mass flow rate of air is 7.53 kg/s

- the exit area is 0.108 m²

Explanation:

Given the data in the question;

lets take a look at the steady state energy equation;

m" = W"\(_{cv\) / [ (h₁ - h₂ ) -\(\frac{V_2^2}{2}\) ]

Now at;

T₁ = 900K, h₁ = 932.93 k³/kg

T₂ = 500 K, h₂ = 503.02 k³/kg

so we substitute, in our given values

m" = [ 3200 kW × \(\frac{1\frac{k^3}{s} }{1kW}\) ] / [ (932.93 - 503.02  )k³/kg  -\(\frac{100^2\frac{m^2}{s^2} }{2}\)|\(\frac{ln}{kg\frac{m}{s^2} }\)||\(\frac{1kJ}{10^3N-m}\)| ]

m" = 7.53 kg/s

Therefore, the mass flow rate of air is 7.53 kg/s

now, Exit area A₂ = v₂m" / V₂

we know that; pv = RT

so

A₂ = RT₂m" / P₂V₂

so we substitute

A₂ = {[ \((\frac{8.314}{28.97}\frac{k^3}{kg.K})\)×\(500 K\)×\((7.54 kg/s)\) ] / [(1 bar)(100 m/s )]} |\(\frac{1 bar}{10N/m^2}\)||\(10^3N.m/1k^3\)

A₂ = 0.108 m²

Therefore, the exit area is 0.108 m²

Answer:

ABS: Antilock Braking System – Prevents the wheels from locking during emergency braking.

ACC: Adaptive Cruise Control – Monitors traffic ahead and reduces or increases the car's speed based on the flow of traffic.

AEB: ...

AWD: ...

BHP: ...

CVT: ...

DDI: ...

DFI:

Explanation:

hope it helpssss

Answer:

ABS: Antilock Braking System – Prevents the wheels from locking during emergency braking.

ACC: Adaptive Cruise Control – Monitors traffic ahead and reduces or increases the car's speed based on the flow of traffic.

AEB: ...

AWD: ...

BHP: ...

CVT: ...

DDI: ...

DFI:

The thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.

The thickness of the aluminum can be determined using from distance of closest approach of the particle.

\(K.E = \frac{2KZe^2}{r}\)

where;

\(r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (1.6\times 10^{-19})^2}{2.5 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m\)

Since the magnitude of charge of electron and proton is the same, at equal kinetic energy, the thickness will be same. r = 1.5 x 10⁻¹⁴ m.

Charge of alpah particle = 2e

\(r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (2 \times 1.6\times 10^{-19})^2}{10 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m\)

Thus, the thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.

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Answer:

b remains the same

Explanation:

voltage and amps have no connection

the electricity used to rin your clothes dryer is normally 220V 18-24A

the voltage in your car's battery is usually 12V 20-30A

see they are approximately the same amperage but very different voltage

Note that the standard state values are ΔG = -2.63 kJ/mol, ΔH = 75.0 kJ/mol, and ΔS = -0.215 J/mol/K.

To calculate the standard state ΔG, ΔH, and ΔS of the assembly process, we need to use the following equations:

ΔG = ΔH - TΔS

ΔS = ΔS_sys + ΔS_surr

ΔS_sys = R ln (W_f / W_i)

ΔS_surr = -ΔH / T

where R is the gas constant (8.314 J/mol/K), T is the temperature in Kelvin, W_f and W_i are the final and initial states' probabilities, respectively.

a) The initial state has 4 peptides in free form with 3 conformations each. Thus, W_i = 3^32^4. The final state has a single sheet with W_f = 1. Therefore, ΔS_sys = R ln (1 / (3^32^4)) = -36.732 J/mol/K.

b) The enthalpy change ΔH is given as -25 h-bonds * (-3.00 kJ/mol/h-bond) = 75.0 kJ/mol.

c) For each of the 84=32 residues, there are 30% hydrophobic, which is 9.6 HP residues. Each HP residue has 3 water molecules, so there are 39.6=28.8 water molecules released. The water configuration increases by a factor of 4 when moving from HP residue to bulk water, so ΔS_sys = R ln (4^28.8) = 283.295 J/mol/K.

Using the values of ΔH and ΔS_sys, we can now calculate the standard state ΔG as:

ΔG = ΔH - TΔS

= 75.0 kJ/mol - (300 K * 283.295 J/mol/K)

= -2.63 kJ/mol

Therefore, the standard state values are ΔG = -2.63 kJ/mol, ΔH = 75.0 kJ/mol, and ΔS = -0.215 J/mol/K.

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The decoration on the top story of a building can vary depending on the architectural style and design.

In some cases, it may consist of a combination of different elements, including corinthian pilasters, doric pilasters, corinthian columns, and ionic columns. Each of these elements has a distinct style and design that can add a unique and elegant touch to the overall aesthetic of the building. Corinthian pilasters are characterized by their ornate and elaborate design, while doric pilasters are simpler and more restrained. Corinthian columns are known for their intricate details and decorative flourishes, while ionic columns are more slender and feature volutes or scrolls at the top. The specific combination of these elements can create a beautiful and distinctive look for any building.

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According to the claim, a house inspection consists of checking submersible pumps.

Pumpset. Pumpset is an assembly that includes a pumped, a driver, a coupling, and auxiliary parts on a common mounting base with an integrated or standalone fire pump regulator. Document currency is not guaranteed when printed. downloaded the RMIT Local Library on 24 Jul 2015.

All pipes rely on the natural forces of nature to move a liquid. As the moving pump gear (impeller, rotary, piston outer layer, etc.) begins to move, air is pushed aside. A cold air partial vacuum created by air movement might be filled with some more air.

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The value of floor(lg(n)) for n = 63 is found to be 5.

To determine the value of floor(lg(n)) for n = 63, we can calculate the base-2 logarithm of 63 and round down to the nearest integer.

The base-2 logarithm, denoted as lg(n), represents the exponent to which 2 must be raised to obtain the value of n. In this case, lg(63) is approximately 5.977, but since we need to round down, the result is 5.

Therefore, the value of floor(lg(n)) for n = 63 is 5.

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The material used in the rollover protection structures must have the capability to perform at 0 degrees Fahrenheit is, True.

The material used in rollover protection structures, such as roll cages or roll bars in vehicles, must indeed have the capability to perform at 0 degrees Fahrenheit. This requirement is crucial to ensure the structural integrity and safety of the vehicle in cold weather conditions.

The material used should be able to withstand the low temperatures without compromising its strength and durability. By selecting materials that can perform at 0 degrees Fahrenheit, the rollover protection structures can effectively provide the necessary safety measures even in freezing temperatures.

It is true that the material used in rollover protection structures must have the capability to perform at 0 degrees Fahrenheit. This ensures that the structures maintain their strength and integrity in cold weather conditions, providing the necessary protection for occupants in the event of a rollover accident. The selection of suitable materials is essential to meet safety requirements and ensure the reliability of the rollover protection structures.

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Answer:

Diameter of pipe is 0.535 ft

Explanation:

see attachment, its works out 1st half

Answer:

try b

Explanation:

Answer:

Subsystem denotes to the installation of some subassemblies, which can be very small or gigantic in size, that serve this subsystem and the overall system. ... In addition, availability importance measures are employed to rank various subsystems with regards to their impact on the overall system availability.

Explanation:

Subsystem refers to the installation of a few subassemblies that support this subsystem and the entire system.

An assembly is a template for a corridor's cross section at a certain station.

A set of interconnected subassemblies that are each connected to a center point or to other subassemblies makes up an assembly. An assortment of shapes, linkages, and points make up a subassembly.

The installation of a few subassemblies that support this subsystem and the overall system is referred to as a subsystem.

These subassemblies can range in size from little to huge. In addition, subsystems are ranked according to their impact on the overall system's availability using availability importance criteria.

The primary memory, the input/output subsystem, and the central processor unit (CPU) are the three basic categories or subsystems that make up a computer. Data processes are carried out by the central processing unit (CPU).

A subassembly could be:

Thus, these are important subassemblies and subsystems.

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Answer:

See explanation.

Explanation:

Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.

If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,

P=2×pi×N×T/60 or T=60×p/2×pi×N

Where P=power transmitted by the shaft=50×10³W

N=rotation speed of the shaft in rpm=730rpm

Pi=3.142

T is the twisting moment

By substituting the values for pi, N and P, we get

T=654Nm or 654×10³Nmm

Also, T=pi×rho×d³/16 or rho=16×T/pi×d³

Where rho=maximum shear stress

T = twisting moment=654×10³Nmm

d= diameter of shaft= 40mm

By substituting T, pi and d

Rho=52Mpa

b. For a hollow shaft, the value for rho is unknown

T=pi×rho(do⁴-di⁴/do)/16

Rho=T×16×do/pi×(do⁴-di⁴)

Where

T= twisting moment=654×10³Nmm gotten above

do=outside shaft diawter=40mm

di= inside shaft diameter =30mm

Pi=3.142

Substituting values for pi, do, di and T.

Rho=76Mpa

Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

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When air undergoes adiabatic expansion, the process is governed by the equation PV^γ = constant, where γ is the ratio of specific heats. In this case, the value of γ for air is 1.4. We are given that one pound of air undergoes an adiabatic expansion from 200 psia to 50 psia, with an initial volume of 4 ft3/lbm and PV^1.4 = constant.

Let's calculate the final volume of the air using the initial and final pressures and the initial volume. Using the formula P1V1^γ = P2V2^γ and substituting the given values, we have: 200(4)^1.4 = 50(V2)^1.4V2 = (200(4)^1.4 / 50)^(1/1.4)V2 = 11.14 ft^3/lbmThe work done by the air is given by the equation W = ∆E + Q, where ∆E is the change in internal energy and Q is the heat added to or removed from the system. Since the process is adiabatic (Q = 0), the work done is equal to the change in internal energy. Let's calculate the work done:W = ∆E = C_v (T2 - T1)where C_v is the specific heat at constant volume, and T1 and T2 are the initial and final temperatures, respectively. The specific heat at constant volume for air is 0.1715 Btu/lbm·R. Let's calculate the final temperature of the air using the initial and final pressures and volumes and the equation P1V1^γ/T1 = P2V2^γ/T2.200(4)^1.4/T1 = 50(11.14)^1.4/T2T2 = T1 * (P2V2^γ / P1V1^γ)T2 = 1183.3 RLet's substitute the values into the equation for work done to get:W = C_v (T2 - T1)W = 0.1715 Btu/lbm·R (1183.3 R - 527.7 R)W = 0.1715 Btu/lbm·R (655.6 R)W = 112.3 Btu/lbmThe change in internal energy is also 112.3 Btu/lbm, since Q = 0. The change in temperature is T2 - T1 = 1183.3 R - 527.7 R = 655.6 R.Answer: The work done by the air is 112.3 Btu/lbm, and the change in internal energy and temperature of the gas are also 112.3 Btu/lbm and 655.6 R, respectively.

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When you notice another vehicle that is preparing to enter one of your space areas, this area should be identified as a potential conflict zone.

when you notice another vehicle that is preparing to enter one of your space areas, this area should be identified as: 100 words

When you notice another vehicle that is preparing to enter one of your space areas, it is important to identify the area as a potential conflict zone. A conflict zone is an area where there is a risk of a collision occurring between two or more vehicles. It is important to maintain awareness of your surroundings and to anticipate the actions of other drivers. By identifying potential conflict zones, you can take proactive measures to avoid collisions, such as adjusting your speed, changing lanes, or signaling your intentions to other drivers. Proper identification of potential conflict zones is a key component of defensive driving and can help you to stay safe while on the road.

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Answer:

car a is moving faster than the car b

Answer:

B: Car A and car B are moving in opposite directions.

C: Car A is moving faster than car B.

E: Car A and car B are moving toward each other until they cross over.

Explanation:

I just did the assignment on EDGE2020 and it's 200% correct!  

Also, heart and rate if you found this answer helpful!! :) (P.S It makes me feel good to know I helped someone today!!)  :)  

Answer:

a) \(h_c = 0.1599 W/m^2-K\)

b) \(H_{loss} = 5.02 W\)

c) \(T_s = 302 K\)

d) \(\dot{Q} = 25.125 W\)

Explanation:

Non horizontal pipe diameter, d = 25 cm = 0.25 m

Radius, r = 0.25/2 = 0.125 m

Entry temperature, T₁ = 304 + 273 = 577 K

Exit temperature, T₂ = 284 + 273 = 557 K

Ambient temperature, \(T_a = 25^0 C = 298 K\)

Pipe length, L = 10 m

Area, A = 2πrL

A = 2π * 0.125 * 10

A = 7.855 m²

Mass flow rate,

\(\dot{ m} = 4.5 tons/hr\\\dot{m} = \frac{4.5*1000}{3600} = 1.25 kg/sec\)

Rate of heat transfer,

\(\dot{Q} = \dot{m} c_p ( T_1 - T_2)\\\dot{Q} = 1.25 * 1.005 * (577 - 557)\\\dot{Q} = 25.125 W\)

a) To calculate the convection coefficient relationship for heat transfer by convection:

\(\dot{Q} = h_c A (T_1 - T_2)\\25.125 = h_c * 7.855 * (577 - 557)\\h_c = 0.1599 W/m^2 - K\)

Note that we cannot calculate the heat loss by the pipe to the environment without first calculating the surface temperature of the pipe.

c) The surface temperature of the pipe:

Smear coefficient of the pipe, \(k_c = 0.8\)

\(\dot{Q} = k_c A (T_s - T_a)\\25.125 = 0.8 * 7.855 * (T_s - 298)\\T_s = 302 K\)

b) Heat loss from the pipe to the environment:

\(H_{loss} = h_c A(T_s - T_a)\\H_{loss} = 0.1599 * 7.855( 302 - 298)\\H_{loss} = 5.02 W\)

d) The required fan control power is 25.125 W as calculated earlier above

The sql statement to display the warehouseid and the sum of quantityon-hand grouped are

SELECT WarehouseId, SUM(QuantityOnHand) AS TotalItemsOnHand

FROM Inventory

GROUP BY WarehouseId

ORDER BY TotalItemsOnHand DESC;

Screenshot of the above query:

![alt text][1]

What is sql?

SQL (Structured Query Language) is a special-purpose programming language used to manage and query data stored in relational databases. It is designed to manipulate and retrieve data in a structured way, allowing users to perform complex queries and analyze data easily. SQL is used in almost all relational database management systems, including Oracle, Microsoft SQL Server, IBM DB2, MySQL, PostgreSQL, and Microsoft Access. SQL is a powerful language that enables users to access and manipulate data in a database, including creating and deleting tables, inserting and modifying data, and creating views and stored procedures. SQL also provides a platform for users to write queries, set up access control mechanisms, and create triggers.

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Answer:

a.) Time = 17.13 seconds

b.) 31.88 m

c.) V = 11.18 m/s

d.) V = 7.1 m/s

Explanation:

The initial velocity U of the automobile is 15.65 m/s.

 At the instant that the two vehicles are abreast of each other, the police car starts to pursue the automobile with initial velocity U = 0 at a constant acceleration of 1.96 m/s². Because the police is starting from rest.

For the automobile, let us use first equation of motion

V = U - at.

Acceleration a is negative since it is decelerating with a = 3.05 m/s² . And

V = 0.

Substitute U and a into the formula

0 = 15.65 - 3.05t

15.65 = 3.05t

t = 15.65/3.05

t = 5.13 seconds

But the motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s².

The total time required for the police car to overtake the automobile will be

12 + 5.13 = 17.13 seconds.

b.) Using the third equation of motion formula for the police car at V = 11.18 m/s and a = 1.96 m/s²

V^2 = U^2 + 2aS

Where S = distance travelled.

Substitute V and a into the formula

11.18^2 = 0 + 2 × 1.96 ×S

124.99 = 3.92S

S = 124.99/3.92

S = 31.88 m

c.) The speed of the police car at the time it overtakes the automobile will be in line with the speed zone which is 11.18 m/s

d.) That will be the final velocity V of the automobile car.

We will use third equation of motion to solve that.

V^2 = U^2 + 2as

V^2 = 15.65^2 - 2 × 3.05 × 31.88

V^2 = 244.9225 - 194.468

V = sqrt( 50.4545)

V = 7.1 m/s

Answer:

Option B (Cold working) would be the correct alternative.

Explanation:

The other possibility isn't linked to the given scenario. Therefore the alternative above is the right one.

Answer:

A) ΔL = 0.544 mm

B) Δd = -0.0168 mm

Explanation:

We are given;

Elastic modulus; E = 67.1 GPa = 67.1 × 10^(9) Pa

Force; F = 46400 N

Diameter; d = 17.8 mm = 17.8 × 10^(-3) m

Radius; r = d/2 = 17.8/2 = 8.9 mm = 8.9 × 10^(-3) m

Length; L = 196 mm = 0.196 m

Poisson ratio; ν = 0.34

A) We know that formula for elastic modulus is;

E = σ/ε

Where;

σ = F/A

ε = ΔL/L

Thus;

E = (FL/ΔL•A)

ΔL is change in length. Making it the subject of the formula, we have;

ΔL = FL/AE

Now, A = πr²

A = π × (8.9 × 10^(-3))²

ΔL = [(0.196 × 46400)/(π × (8.9 × 10^(-3))² × 67.1 × 10^(9)]

ΔL = 0.544 × 10^(-3) m

ΔL = 0.544 mm

B) formula for Poisson ratio is given as;

ν = -ε_x/ε_z

Where;

ε_x is transverse strain = Δd/d

ε_z is longitudinal strain = ΔL/L

Thus;

ν = -Δd•L/d•ΔL

Making Δd the subject, we have;

Δd = -νdΔL/L

Δd = -(0.34 × 17.8 × 10^(-3) × 0.544 × 10^(-3))/0.196

Δd = -0.0168 × 10^(-3) m = -0.0168 mm

Answer:

A

Explanation:

the type of work they do

Hotel Fire Safety Directors are not authorized to order a full building evacuation of guests. Therefore, option (C) is correct.

Hotel Fire Safety Directors are individuals who are responsible for ensuring the safety of guests and employees in the event of a fire emergency in a hotel or other hospitality establishment.

They are typically appointed by the hotel management and must have knowledge of fire safety regulations and protocols, as well as the ability to lead and manage a team during an emergency.

Hotel Fire Safety Directors are responsible for implementing and maintaining the Fire Safety Plan, which includes conducting fire drills, training and supervising the Fire Brigade, and distributing applicable parts of the Fire Safety Plan to all employees. They must also work closely with the local fire department to ensure compliance with local fire safety regulations and protocols.

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how am I going to do this, I have a friend that might be able to help I will check

The components or elements of a work of art that can be isolated and defined are known as the elements of art.They serve as the foundation upon which an artistic creation is built.

Students will be better able to comprehend an artist's decisions if they can recognize the components of a work of art and assess how they contribute to its composition.

Equal visual weight on the two sides of a visual area is necessary for our eyes to function properly.

For instance, we anticipate that the left and right portions of a screen will have equal visual weight.We perceive that a picture is incorrect if it is unbalanced when it is displayed on a screen.

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The complete question will be:

Art Text Questions

Question one: There were seven elements of the design listed in the unit. Please name five of them, and give a short description of each.

Answer: line, shape, space, value, form, texture, and color.

Line: I thin or thick drawn/made considered a moving point in space, It is one-dimensional and can vary in width, direction, and length.

Shape: a two-dimensional form tends to be colored or circled/lined

Space: the feeling of depth or three dimensions there’s a positive and negative space, Positive space is filled in or used to be a part of the drawing, the negative can be the empty space in the painting

Value: it sometimes light and dark colors it is used a scale at times and used to make high or low contrast

Form: has a physical being and the other could be like a message from an image,

Textures: surface quality, there are real and actual textures, some textures aren't as they seem or made something created to look like something it is not

Color: the element of art

Question two: There were also seven principles of the design listed in the unit. List five of the principles of design and explain what each means.

Answer: Emphasis, contrast, balance, pattern, and rhythm.

Emphasis: The principle of art that helps the audience put the story of a painting together in their own minds. Any object or area of emphasis is called a focal point.

Contrast: The arrangement of opposite elements and effects. For example, light and dark colors, smooth and rough textures, large and small shapes.

Balance: The distribution of the visual weight of objects, colors, texture, and space.

Pattern: A design in which lines, shapes, forms, or colors are repeated.

Rhythm: The principle of design that suggests movement or action.

Question three: There are three different ways that balance is used. Please list the three different ways and explain what each means.

Answer: Symmetrical, asymmetrical, and radial

Balance is the principle of design that teaches the work of art should be in harmony, and that its sides “weigh” the same so that it doesn’t look uneven. The three types of balance are symmetrical, asymmetrical, and radial.

Symmetrical balance means the two parts of the art are identical. If we were to separate the picture or art piece in the middle, the two sides would be equal, presenting the same elements and weighing the same.

An asymmetrical balance occurs when the two parts of the painting or work of art are not the same, yet they weigh the same. They are in harmony, but they have different components. For example, maybe one side presents larger elements, but the other side has brighter colors, so there is no tension, and the observer sees composure on the piece.

Radial balance is presented as elements gathered around the joined center. They can go towards it, or from it, but they seem as if to radiate from the same point.

Question four: In the unit, elements of content were discussed. There were four elements of content listed; please name all four and write one sentence explaining each?

Answer: line, shape, form, and texture

Line: Lines, a line is the starting point of every artist's artwork, the line could either be broken, jagged, vertical, horizontal, or diagonal, so basically, a line is the start of the art.

Shape: A shape is anything with edges or is surrounded by an outline, a shape can be anything, but it just has to all end and connect at a certain point to make it a certain shape you want, or you can make your own shape!

A device that can connect many computers and sends packets out of every port is known as Hub.

The name of the device that usually connects many computers is known as a hub. It typically connects multiple computer networking devices together. It also acts as a repeater in that it amplifies signals that worsen after traveling long distances over connecting cables.

According to the context of this question, a hub usually connects multiple computers together in a Local Area Network (LAN). All types of information are generally processed or sent to the hub is then sent through each port to every device in the network. It is noted that all types of devices are definitely connected to a network hub and share all available bandwidth equally.

Therefore, a device that can connect many computers and sends packets out of every port is known as Hub.

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