While you stand on the floor you are pulled downward by gravity and supported upward by the floor. Gravity pulling down and the support force pushing up
answer choicesa. make an action-reaction pair of forces.
b. do not make an action-reaction pair of forces.
c. need more information

Answer:

1, 2, 3, 4

Explanation:

Just did it on Edge

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Answer:

1234 is correct

Explanation:

Answer:

C. 199.9 s

Explanation:

3 minutes = 3×60 = 180 seconds.

the turtle moves in that time 180×10 = 1800 cm.

in other words the rabbit gave it that much head-start (it does not matter if that was at the begin of in the middle of the race).

the rabbit moves with 10×10cm/s = 100cm/s.

the rabbit needs therefore 1800/100 = 18 seconds for the

1800 cm.

at that time the turtle has added another 18×10 = 180 cm.

for which the rabbit needs 180/100 = 1.8 seconds.

during that time the turtle has added 1.8×10 = 18 cm.

and so on.

in formal mathematics this looks like this :

1800 + 10x = 100x

after x seconds of the rabbit running both will have run the same distance, and it is a tie.

1800 = 90x

x = 20 seconds

so, at that point, the rabbit was actively running for 20 seconds and raced 20×100 = 2000 cm

and the turtle was actively running for 180 + 20 = 200 seconds, and also covered 200×10 = 2000 cm.

but our question tells us that the turtle won by 10 cm.

so, the race was over a little bit before these 200 seconds (for a tie).

this means, the rabbit could not run the last 10 cm for the tie (because the race was over and the turtle had won).

the rabbit would have needed 10/100 seconds for these 10 cm.

as speed = distance/time

we need to divide distance by speed

distance/1 / distance/time

to get time.

so,

10cm/1 / 100cm/s = 10s/100 = 1/10 s

so, we need to deduct this 1/10 s from the 200 seconds of the turtle (and also from the 20 seconds for the rabbit).

the race lasted of course the whole time the turtle was running (while the rabbit was resting, officially still participating in the race with speed 0 for 3 minutes).

and so, the race was 199.9 s long.

The strength of the electric field will be 0.75 NC⁻¹.

The strength of the electric field is the ratio of electric force per unit charge. Its unit is NC⁻¹.

The given data in the problem is;

q is the positive charge = 6.0 × 10-4 C

F is the electric force of 4.5 × 10-4 N

E is the electric field intensity=?

The electric force is given by;

\(\rm F= q \times E \\\\ \rm E= \frac{F}{q} \\\\ \rm E= \frac{4.5 \times 10^4}{6 \times 10^{-4}} \\\\ \rm E=0.75 \ NC^{-1}\)

Hence the strength of the electric field will be 0.75 NC⁻¹.

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Answer:

7m/s^2

Explanation:

using v=u+at

since the car started from rest, u=0 , v=14m/s t=2s

a =acceleration.

14=0+a×2

14=0+2a

14=2a

a= 14/2 =7

a=7m/s^2

A transformer with a turns ratio of sqrt(5000), or approximately 70.7. This will step up the impedance seen by the filter to 35.4 ohms, which can be further stepped down to 10 ohms with a load resistor.

fc = 1 / (2 * pi * R * C)

fc = 1 / (2 * pi * R * C)

For a cutoff frequency of 10 kHz, we can choose a capacitor value of 10 nF. To ensure that the second stage does not load the first stage, we can choose a resistor value of at least 10 ohms.

A transformer is a type of neural network architecture that was introduced in a 2017 paper by Vaswani et al. It revolutionized natural language processing (NLP) by introducing a new way of processing sequences of data, such as text. Unlike traditional recurrent neural networks (RNNs) that process sequences one element at a time, transformers process the entire sequence all at once.

Transformers use a mechanism called "self-attention" to weigh the importance of each element in the sequence when computing representations of the sequence. This allows them to capture long-range dependencies and better understand the context in which each element appears.

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The centripetal force is directly determined by measuring the tension force in the string of the rotating object.

In any apparatus that involves rotating objects, the centripetal force is the force required to keep the object moving in a circular path. This force is directed towards the center of the circle and is equal to the product of the mass of the object, the square of its velocity, and the reciprocal of the radius of the circle. In order to directly determine the centripetal force, one must measure the tension force in the string of the rotating object. This can be done by using a tension meter or by measuring the change in length of the string under load. Once the tension force is known, the centripetal force can be calculated using the equation for centripetal force.

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Breathing exercises  , Self - hypnosis , Enough sleep and meditation practice can counteracts the relaxation pressures and promotes the steady blood pressure

Their are several techniques which counteracts the relaxation pressures and promotes the steady blood pressure , that are

1) Breathing exercises

For this , one can focus on taking slow, deep breaths which is also called diaphragmatic breathing

2) Self - hypnosis

In this , one can learn to produce the relaxation response when prompted by a phrase

3) Enough sleep and meditation practice

The less you sleep, the higher your blood pressure may go. People who sleep six hours or less may have steeper increases in blood pressure.

The relaxation response (from meditation) helps decrease metabolism, lowers blood pressure, and improves heart rate, breathing, and brain waves," Benson says. Tension and tightness seep from muscles as the body receives a quiet message to relax.

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Answer:

well that means they are driving 100 mph

so it will take them less than an hour and a half

The slope of the graph of the equation at the point (20, 2) is 1/8.

To find the slope of the graph of the equation at the given point (20, 2), we need to find the derivative of the equation with respect to x and evaluate it at x = 20. Let's differentiate the equation implicitly:

xy - 9y^2 = 4

To differentiate implicitly, we treat y as a function of x and apply the chain rule. Differentiating both sides of the equation with respect to x:

1 * y + x * dy/dx - 9 * 2y * dy/dx = 0

Simplifying this equation:

y + x * dy/dx - 18y * dy/dx = 0

Grouping the terms with dy/dx:

dy/dx * (x - 18y) = -y

Now, let's solve for dy/dx by dividing both sides by (x - 18y):

dy/dx = -y / (x - 18y)

Substituting the given point (20, 2) into the equation:

dy/dx = -2 / (20 - 18(2))

         = -2 / (20 - 36)

         = -2 / (-16)

         = 1/8

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Imagine standing at the edge of a calm ocean, holding a buoyant ball in your hand. You toss the ball into the water, and it begins to float away from you. As the ball moves away, you notice that it bobs up and down with the waves, but it does not move in the same direction as the waves.

This scenario demonstrates that waves carry energy, not matter. The ball is made up of matter, and it floats on the surface of the water. However, the waves that pass through the water are made up of energy, not matter. When the waves encounter the ball, they transfer some of their energy to the ball, causing it to bob up and down.

The ball itself is not being carried along by the waves, but is instead being influenced by the energy of the waves as they pass through the water. This is why waves are often described as a disturbance that travels through a medium, rather than as a physical object that moves through space.

In summary, the scenario of a buoyant force ball floating on the surface of the ocean and being influenced by passing waves is a clear example of how waves carry energy, not matter.

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In a low-pressure chiller, air and other non-condensable gases can collect in the upper portion of the chiller, typically in the condenser.

Non-condensable gases are gases that are not able to be condensed into a liquid state under normal operating conditions. These non-condensable gases can have a negative impact on the performance of the chiller. They can reduce the cooling capacity of the chiller, increase energy consumption, and cause corrosion in the system.

Therefore, it is important to regularly remove non-condensable gases from the chiller to maintain optimal performance and prevent damage to the system. This is typically done through a process called purging, which involves removing the non-condensable gases from the chiller and replacing them with the proper refrigerant.

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Answer:

Approximately \(0.3\; {\rm m}\). (Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

In this question, the ball initially possesses gravitational potential energy \(\rm GPE}\) and kinetic energy \({\rm KE}\). That energy was converted into the elastic potential energy \({\rm EPE}\) of the compressed spring.

Let \(m\) denote the mass of the ball. When the height of the ball changes by \(\Delta h\), the change in the \({\rm GPE}\) of the ball would be \({\rm GPE} = m\, g\, \Delta h\).

Let \(v\) denote the initial speed of the ball. The initial kinetic energy of the ball would be \({\rm KE} = (1/2)\, m\, v^{2}\).

Assume that the height of the cliff far exceeds the height of the spring. Thus, the change in the height of the ball would be approximately the same as the height of the cliff: \(\Delta h \approx 5\; {\rm m}\). The \({\rm GPE}\) of the ball would be:

\(\begin{aligned}{\rm GPE} &= m\, g\, \Delta h \\ &\approx (10)\, (9.81)\, (5)\; {\rm J} \\ &= 490.5\; {\rm J} \end{aligned}\).

With a speed of \(v = 2\; {\rm m\cdot s^{-1}}\), the initial \({\rm KE}\) of the ball would be:

\(\begin{aligned}{\rm KE} &= \frac{1}{2}\, m\, v^{2} \\ &= \frac{1}{2}\, (10)\, (2)^{2}\; {\rm J} \\ &= 20\; {\rm J}\end{aligned}\).

Let \(k\) denote the spring constant of the spring. With a displacement of \(x\), the \({\rm EPE}\) in the spring would be \({\rm EPE} = (1/2)\, k\, x^{2}\).

All that \({\rm GPE} + {\rm KE} \approx (490.5 + 20)\; {\rm J} = 510.5\; {\rm J}\) of energy would have been converted into the \({\rm EPE}\) of the spring.

It is given that \(k = 10000\; {\rm N\cdot m^{-1}}\). In other words, when \(x\) is in meters:

\((1/2)\, (10000)\, x^{2} = {\rm EPE} \approx 510.5\).

Solve for the displacement of the spring, \(x\):

\(\begin{aligned} x &\approx \sqrt{\frac{510.5}{(1/2)\, (10000)}} \approx 0.3\; {\rm m}\end{aligned}\).

Like classical novae , X-ray bursters suddenly brighten when accreted material hits the surface of the compact object and undergoes runaway nuclear fusion.

A Nova is a transient astronomical event that causes the sudden appearance of a bright, apparently "new" star (hence the name "Nova", which is a Latin word means "new") that slowly fades over weeks or months. Classical nova eruptions are the most common type. They are likely created in a close binary star system. Classical novae are the result of a hydrogen, thermonuclear runaway on top of an accreting white dwarf, in a close binary system (cataclysmic variable). Classical nova explosion are the 3rd most violent explosions than can occur in a galaxy.

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Despite their darkness, their lustrous dark fur coat can make them difficult, if not impossible, to spot. Panthers have small heads, powerful jaws, and emerald green eyes. Their hind legs are often larger and slightly longer than their front legs.

The ability to remain undetected is one of the main ways that panthers differ from other big cats. Panthers hunt at night since they are nocturnal.

Therefore, They can blend in with their surroundings thanks to their dark fur, and their keen eyesight and nose make it easier for them to find their prey.

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Answer:

Metallic bonding is the bond that exist between the atoms. The electrons do not only flow at its respective atoms but instead, contribute to a sea of delocalised electrons. As a result, metals can conduct electricity as the delocalised electrons are able to carry charges.

Explanation:

The volume flux inside the rectangular duct is 0.028 m³/s.

Volume flux, also known as volumetric flow rate, is a measure of the volume of fluid passing through a given area per unit time. It is commonly expressed in cubic meters per second (m³/s). To calculate the volume flux in the given scenario, we can use the formula:

Volume Flux = (Air flow rate) / (Cross-sectional area)

First, we need to calculate the cross-sectional area of the rectangular duct. The area can be determined by multiplying the length and width of the duct:

Area = (138 mm) * (346 mm)

To maintain consistent units, we convert the dimensions to meters:

Area = (138 mm * 10⁻³ m/mm) * (346 mm * 10⁻³ m/mm)

Next, we can calculate the air flow rate using the given information. The air flow rate is given as 17 N/s, which represents the mass flow rate. We can convert the mass flow rate to volume flow rate using the ideal gas law:

Volume Flow Rate = (Mass Flow Rate) / (Density)

The density of air can be determined using the ideal gas law:

Density = (Pressure) / (Gas constant * Temperature)

where the gas constant (R) is given as 28.5 m/K, the pressure is 112 kPa, and the temperature is 20 degrees Celsius.

With the density calculated, we can now determine the volume flow rate. Finally, we can divide the volume flow rate by the cross-sectional area to obtain the volume flux.

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Answer:

a moderate base

Explanation:

Milk of magnesia is popularly known as magnesium hydroxide. Magnesium hydroxide Mg(OH)₂ is used as an anti-acid in toothpaste and medically as a mild laxative.

Its pH values range between 10- 11 on the pH scale.

A solution with pH value of 7 is neutral(i.e. neither acidic nor basic.

A pH value which is less than 7 is acidic while a pH value greater than 7 is basic.

For a pH value between 12 -14 on the pH scale is said to be a strong base.

Since Milk of magnesia Mg(OH)₂ pH values ranges between 10- 11 on the pH scale, it is known to be moderately basic.

The time it takes for the helicopter to reach the ground is approximately 5.26 seconds, using the equation of motion for vertical motion.

To calculate the time, we can use the equation of motion for vertical motion: s = ut + (1/2)gt², where s is the displacement (120 m), u is the initial velocity (5.20 m/s), g is the acceleration due to gravity (approximately 9.8 m/s²), and t is the time.

Rearranging the equation to solve for t, we have t = √((2s) / g), t = √((2 × 120 m) / 9.8 m/s²) ≈ 5.26 seconds.

During the ascent of the helicopter, the package was at rest relative to the helicopter, so it shares the same vertical motion.

Therefore, the time it takes for the helicopter to reach the ground is the same as the time it takes for the package to fall to the ground.

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Answer:

a = 5 m / s²   and    x = 562.5 m

Explanation:

Let's apply the kinematics relations

          v = v₀ + at

          v² = v₀² + 2a x

In this case, as the car stops, its final speed is zero (v = 0) and the acceleration must be opposite to the speed, that is, negative

           0 = v₀ - a t

           a = v₀ / t

let's calculate

           a = 75/15

           a = 5 m / s²

let's look for the distance

           0 = v₀² - 2a x

           x = v₀² / 2a

let's calculate

           x = \(\frac{75^2}{2 \ 5 }\)

           x = 562.5 m

Answer:

We conclude that the required momentum is 80 kgm/s.

Explanation:

Given

To determine

The momentum p = ?

Important Tip:

We can determine the momentum using the formula

\(p = mv\)

where

now substituting m = 20 and v = 4 using the equation

\(p = mv\)

\(p = (20) (4)\)

\(p = 80\) kg m/s

Therefore, we conclude that the required momentum is 80 kgm/s.

The momentum of the moving cart is 80kgm/s.

HOW TO CALCULATE MOMENTUM:

Momentum (p) = mass (m) × velocity (v)

Momentum (p) = 20kg × 4m/s

Momentum (p) = 80kg*m/s.

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Answer:

A is true ,b is true

Explanation:

Evaluating this expression, we can find the length of the wire, which is equal to the circumference of the coil.

To find the length of the wire from which the coil is made, we can use the formula for torque experienced by a coil in a magnetic field:

τ = BIA,

where τ is the torque, B is the magnetic field strength, I is the current, and A is the area of the coil.

In this case, the torque (τ) is given as 12×10^(-3) N⋅m, the magnetic field (B) is 1.0 T, and the current (I) is 3.2 A. We are looking for the length of the wire, which is related to the area (A) of the coil.

The area of a circular coil with only one turn can be calculated using the formula:

A = πr^2,

Since the coil consists of only one turn, the circumference of the coil is equal to the length of the wire. The circumference can be calculated as:

C = 2πr.

We can rearrange the equation to solve for r:

r = C / (2π).

Substituting this value of r into the formula for the area, we get:

A = π(C / (2π))^2.

12×10^(-3) N⋅m = (1.0 T)(3.2 A)(π(C / (2π))^2).

Simplifying the equation, we find:

12×10^(-3) N⋅m = (1.0 T)(3.2 A)(C / (2π))^2.

Solving for C, we can rewrite the equation as:

C = √[(12×10^(-3) N⋅m) / ((1.0 T)(3.2 A))].

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Answer:

It is based on weight and height. Weight (in kilograms) is divided by height (in meters squared)

The magnitude of the total force of the stone on the man's hand is 1.43N

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics.

The direction of the net force acting on an object determines the direction of its acceleration.

Newton's Second Law's Second Law of Acceleration describes the magnitude of an object's acceleration.

Nis normal force exerted by stone on hand.

According to Newton's third law stone also exerted the same force.

⇒ N-mg= ma

⇒ N=1.3(9.8+1.2)

⇒ N=1.43newton

The magnitude of the total force of the stone on the man's hand is 1.43N

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The distance from the starting point is same as the hypotenuse of the right angle triangle and the length is 3.606 blocks

This is a rule applied in mathematics that states that the sum of both the square of the opposite and the square of adjacent is equals to the square if the hypotenuse. The rule holds true for a right angled triangle.

the part described forms a right angle triangle so the opposite three blocks while the adjacent is two blocks and the hypotenuse will be solved as follows:  

Hypotenuse^2 = opposite^2 + adjacent^2

= 3^2 + 2^2

=9 + 4

= 13

Hypotenuse = sqrt(13)

Hypotenuse = 3.606 blocks

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Answer:Friction is a force that opposes the motion of objects; friction can cause objects to slow down. Air resistance is a type of friction. Air resistance causes moving objects to slow down. Different physical properties, such as the shape of an object, affect the air resistance on an object.

Explanation:

To solve this problem, we can use the continuity equation,

which states that the mass flow rate (the rate at which mass flows through a point in a system) must be constant throughout the system.

In other words, the mass flow rate at point 1 must equal the mass flow rate at point 2.

The mass flow rate is equal to the density of the fluid times the flow rate (also known as the volume flow rate). The flow rate is equal to the crosssectional area of the tube times the velocity of the fluid. Therefore, we can write the continuity equation as:

\(density ${ }^*($ cross-sectional area $*$ velocity $)=$ constant\)

We can rearrange this equation to solve for the velocity at each point:

\(velocity = constant (density* cross-sectional area)\)

At point 1 , the velocity can be calculated as follows:

\(V1 = constant $/\left(\right.$ density $*$ A1) $=$ constant $/\left(\right.$ density $\left.* 1.00 \mathrm{~cm}^{\wedge} 2\right)$\)

At point 2 , the velocity can be calculated as follows:

\($$\text { V2 = constant } /(\text { density } * A 2)=\text { constant } /\left(\text { density } * 4.00 \mathrm{~cm}^{\wedge} 2\right)$$\)

We can find the value of the constant by using the pressure difference between the two points and the ideal gas law:

\($$P 1-P 2=\left(\text { density } * \text { velocity }{ }^{\wedge} 2\right) / 2$$\)

Substituting the known values, we have:

\($$9.45 \mathrm{kPa}=\left(\text { density }{ }^* \mathrm{~V} 1^{\wedge} 2\right) / 2$$\)

Solving for \($\mathrm{V} 1$\), we find that the velocity at point 1 is:

V1 = sqrt(2 * 9.45 kPa / density)

Similarly, we can solve for V2:

V2 = sqrt(2 * 9.45 kPa / density) / 2 = V1 / 2

Note that the density of glycerin is not given, so we cannot calculate the exact values of V1 and V2. However, we can still determine the relationships between the velocities at the two points. Specifically, we can see that the velocity at point 2 is half the velocity at point 1.

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