By considering the cases of including and excluding the 'n-th' element, we obtain the recurrence relation is C(n) = C(n-1) + C(n-1).
The first term, C(n-1), represents the number of subsets that exclude the 'n-th' element. Since we exclude this element, we are essentially counting the subsets of a set with 'n-1' elements.
The second term, C(n-1), represents the number of subsets that include the 'n-th' element. Since we include this element, we need to count the subsets of a set with 'n-1' elements as well.
By adding these two terms, we obtain the total number of subsets for a set with 'n' elements.
To use the recurrence relation, we need to establish initial conditions or base cases. These are specific values of C(n) that we know beforehand.
For the subsets of a set with 0 elements, there is only one possible subset: the empty set {}. Therefore, we have:
C(0) = 1
With this initial condition, we can start using the recurrence relation to calculate the number of subsets for sets with larger numbers of elements.
To use the recurrence relation, we start with the initial condition C(0) = 1. Then, we can iteratively calculate C(n) for larger values of 'n' using the recurrence relation:
C(1) = C(0) + C(0) = 1 + 1 = 2
C(2) = C(1) + C(1) = 2 + 2 = 4
C(3) = C(2) + C(2) = 4 + 4 = 8
And so on.
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Trying find out which is true
Answer:
Step-by-step explanation:
y>x+1
how many different three-digit numbers can be formed using the digits 0,1,2,3,4,5,6,7,8, and 9 if the first digit cannot be 0 or 1
There are 800 different three-digit numbers that can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9, with the restriction that the first digit cannot be 0 or 1.
If the first digit cannot be 0 or 1, we have 8 options for the first digit (2, 3, 4, 5, 6, 7, 8, 9). For the second and third digits, we have all 10 digits available (0-9) since there are no restrictions on them.
Therefore, the total number of different three-digit numbers that can be formed is:
= 8 options for the first digit × 10 options for the second digit ×10 options for the third digit
= 8 × 10 × 10
= 800
So, there are 800 different three-digit numbers that can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9, with the restriction that the first digit cannot be 0 or 1.
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Find The area of the figure below
Answer:
wow asphalt theme I have that too in my quizziz
In one hour, Frank earns the money shown below. How much does he earn in 7 weeks if he works 3 hours each week?
↓↓
$12
↑↑
ITS DUE TODAY HELP PLEASE
Answer:
$252
Step-by-step explanation:
If Frank earns $12 an hour and works 3 hours a week, he makes $36 a week. So for 7 weeks, he earns $252 because $36x7 weeks= $252 in 7 weeks
If the relation is a function, list the domain and range. If the relation is not a function, choose "not a function". C = {(9, 1) (8, -3) (7, 5) (-5, 3)} A: Domain: {9, 8, 7, -5} Range: {1, -3, 5, 3} B: Domain: {1, -3, 5, 3} Range: {9, 8, 7, -5} not a function
Answer:
A: Domain: {9, 8, 7, -5} Range: {1, -3, 5, 3}
Step-by-step explanation:
C = {(9, 1) (8, -3) (7, 5) (-5, 3)}
The domain is the inputs
Domain: { -5,7,8,9}
The range is the output
Range{ -3,1,3,5}
This is a functions since there is no input that goes to multiple outputs
A gallon of milk costs an unknown amount,Jason wishes to purchase Two gallons write an equation
The equation 2C is a simple algebraic expression that represents the relationship between the cost of one gallon and the cost of two gallons of milk.
Let's assume the unknown cost of a gallon of milk is represented by the variable "C" (for cost).
To write an equation representing the cost of purchasing two gallons of milk, we can multiply the cost of one gallon (C) by the quantity of gallons, which is 2:
2C
This equation states that the cost of purchasing two gallons of milk (2C) is equal to twice the cost of one gallon (C).
For example, if the cost of one gallon of milk is $3, the equation would be:
2 * $3 = $6
So, purchasing two gallons of milk would cost $6.
It is important to note that the equation assumes a linear relationship between the quantity of milk and its cost. In reality, the cost of two gallons of milk may not be exactly twice the cost of one gallon due to factors such as bulk discounts, promotions, or varying prices.
The equation provides a simplified representation and is based on the assumption that the cost per gallon remains constant.
By using this equation, Jason can determine the total cost of purchasing two gallons of milk based on the actual cost per gallon.
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Cost of the student ticket to the school play is $7. Write an equation that correctly relates the total cost, c,
Complete question :
The cost of a student ticket to the school play is $7. Write an equation that correctly relates the total cost, c, for a particular number, s, of student tickets purchased. Identify the independent and dependent variable.
Answer:
Dependent variable = Total cost
Independent variable = number of students
Step-by-step explanation:
The total cost equation is :
Total cost, c = cost per ticket * number of tickets
c = 7 * s
c = 7s
The Independent variable also called the predictor variable is the number of students in the scenario described above as it is the variable upon which the total cost relies. It dictates the value of the output or dependent variable. As we vary the value of the Independent variable, number of students, the total cost which is the dependent variable also varies. The dependent variable on the other hand is the predicted value or variable which is controlled by the independent variable. The dependent variable in this case is the total cost, c
What happens when a triangle is dilated using one of the vertices as the center of the dilation? Complete
the explanation.
The sides of the triangles adjacent to the center of dilation will be collinear. The third sides of the pre-
image and image will be ?
The vertex used as the center of dilation will be in
Answer:
The sides of the triangles adjacent to the center of dilation will be collinear. The third sides of the pre-
image and image will be “parallel”
The vertex used as the center of dilation will be in “the same location in both triangles”
1. Differentiate the function f(x) = ln (81 sin^2 (x)) f’(x) 2. Differentiate the function P(t) = in ( √t2 + 9) p' (t) 3. if x2 + y2 + z2 = 9, dx/dt = B, and dy/dt = 4, find dz/dt when (x,y,z) = (2,2,1)
dz/dt =
First you will get 4dz
Fill in the missing numbers to complete the linear equation that gives the rules for this tablex: 4, 5, 6, 7y: 56, 70, 84, 98y = ?x + ?
the two points are
A(4,56) and B(5,70)
so, the linear equation is
\(y-70=\frac{70-56}{5-4}(x-5)\)\(\begin{gathered} y-70=\frac{14}{1}(x-5)_{} \\ y-70=14x-70 \end{gathered}\)\(y=14x\)thus, the equation is
y = 14x + 0
so we can put 14 in first place and 0 in second
In a game, the probability that a spinner will land on blue is 1/4. How many times would you expect to land on blue if you spin the spinner 8 times?
Answer:
2 times
Step-by-step explanation:
Find the slope and the y-intercept of this table. X 0 3 6 9 and y 4 6 8 10
Answer:
Step-by-step explanation:
y = 2/3x+4
2/3 is your slope, if you do y2-y1/x2-x1. 6-4/3-0. 2/3
your y intercept is what y is when x is 0. so 4
What happens to the value of the expression \dfrac{10}{d} d 10 start fraction, 10, divided by, d, end fraction as ddd increases from a small positive number to a large positive number?
Answer:
The quotient decreases
Step-by-step explanation:
Give the expression :
10 / d
What happens to the expression as d increases. from small positive to large positive ;
d in the expression is the denominator ;the value obtained by dividing the numerator by the denominator is the quotient.
Since the value of the numerator is constant ;
As the value of d increases, the quotient obtained becomes smaller `
For instance,
Let
d = 2;
10 /2 = 5
d = 3
10 / 3 = 3.333
d = 4
10 / 4 = 2.5
And the trend continues
Answer:
2.5 on khan
Step-by-step explanation:
Look at this square. Find the value of
S.
S
Perimeter = 16 miles
S =
miles
The value of S, which represents the length of each side of the square, is 4 miles.
To find the value of S, we need to determine the length of each side of the square. Given that the perimeter of the square is 16 miles, we can use the formula for the perimeter of a square, which is 4 times the length of a side.
Perimeter = 4 × S
Given that the perimeter is 16 miles, we can substitute this value into the equation:
16 = 4 × S
To solve for S, we divide both sides of the equation by 4:
16 ÷ 4 = S
4 = S
Therefore, S, which stands for the square's side lengths, has a value of 4 miles.
So, S = 4 miles.
This means that each side of the square measures 4 miles, and the square has equal sides and right angles at each corner.
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What additional information do you need to prove AABC AADC by the SAS Postulate?A)
Answer:
A. ∠ACB ≅ ∠ACD.
Explanation:
To prove that ∆ABC is congruent to ∆ADC by the SAS postulate:
Side: AC is congruent to AC
Angle: Angle ACB is congruent to angle ACD
Side: BC is congruent to DC
That is, the angle between the two congruent sides must be the same.
Thus, the additional information needed is that ∠ACB ≅ ∠ACD.
A is the correct choice.
Pls help me!! Show all work! I will mark brianliest!!
3.Solve this system of equations (X and Y) using ELIMINATION.
4x-3y=22
x-5y =14
Step-by-step explanation:
make eqn for both
4x-3y=22 epuation first
x-5y=15
use elimating method
4x-3y=22
4x-20y=56
from here the value of y will come -1.39
put the value of y in epn 2
the ans if x is -7.04
A chemical company makes two brand of antifreeze. The first brand is 70 % pure antifreeze, and the second brand is 95% pure antifreeze. In order to obtain 110 gallons of a mixture that contains 85% pure antifreeze, how many gallons of each brand of antifreeze must be used?first brand:_____gallonssecond brand:_____gallons
Since the 1st brand is 70% pure antifreeze
Since the 2nd brand is 95% pure antifreeze
Since we need to obtain 110 g of a mixture that contains 85% pure antifreeze
Let the quantity of the first is x and the second is y
Then
\(\frac{70}{100}x+\frac{95}{100}y=\frac{85}{100}(110)\)\(0.7x+0.95y=93.5\text{ (1)}\)\(x+y=110\text{ (2)}\)Now let us solve the two equations to find x and y
Multiply equation (2) by -0.7
\(\begin{gathered} (-0.7)x+(-0.7)y=(-0.7)110 \\ -0.7x-0.7y=-77\text{ (3)} \end{gathered}\)Add equations (1) and (3)
\(\begin{gathered} (0.7x-0.7x)+(0.95y-0.7y)=(93.5-77) \\ 0+0.25y=16.5 \\ 0.25y=16.5 \end{gathered}\)Divide both sides by 0.25
\(\begin{gathered} \frac{0.25y}{0.25}=\frac{16.25}{0.25} \\ y=66 \end{gathered}\)Substitute the value of y in equation (2) to find x
\(x+66=110\)Subtract 66 from both sides
\(\begin{gathered} x+66-66=110-66 \\ x+0=44 \\ x=44 \end{gathered}\)First brand: 44 gallons
Second brand: 66 gallons
is the function y=0.5x linear?
Answer:
Yes, it is linear.
Step-by-step explanation:
There is a constant change in the slope. Basically, if it is in y=mx+b form then it is linear. But if the slope is squared then it is not linear.
(I'll take that brainliest now)
3.02 x 10-1 =
A = 30.2
Answer:
3.02
x 10
-------
000
+302x
______
30.20
Find an ordered pair (x,y) that is a solution to the equation. 3x-y=9
Answer:
3x-y=9
(3,-9)
Step-by-step explanation:
How do you put fractions in order from least to greatest?
To put fractions in order from least to greatest, you need to compare their values by finding the common denominator.
Here are the steps to follow:Step 1: Find a common denominator for all the fractions.
Step 2: Convert each fraction to an equivalent fraction with the common denominator.
Step 3: Compare the numerators of the equivalent fractions. The fraction with the smallest numerator is the smallest fraction, and the fraction with the largest numerator is the largest fraction.
Step 4: If two or more fractions have the same numerator, compare their denominators. The fraction with the smallest denominator is the smallest fraction, and the fraction with the largest denominator is the largest fraction.
Step 5: Write the fractions in order from least to greatest.
For example, let's say you need to put the fractions 1/3, 2/5, and 3/8 in order from least to greatest.
Step 1: The common denominator for 3, 5, and 8 is 120.
Step 2: Convert each fraction to an equivalent fraction with a denominator of 120.
1/3 = 40/120
2/5 = 48/120
3/8 = 45/120
Step 3: Compare the numerators of the equivalent fractions: 40 < 45 < 48
Step 4: Since 40 is not equal to 45 or 48, we don't need to compare the denominators.
Step 5: Write the fractions in order from least to greatest: 1/3 < 3/8 < 2/5.
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two cheeseburgers and one small order of fries contain a total of 1350 calories. three cheeseburgers and two small orders of fries contain a total of 2140 calories. find the caloric content of each item.
Two cheeseburgers contain a total of 1120 calories (2 x 560) and one small order of fries contains 230 calories. And three cheeseburgers contain a total of 1680 calories (3 x 560) and two small orders of fries contain a total of 460 calories (2 x 230).
Let's use a system of equations to solve for the caloric content of each item.
Let x be the number of calories in one cheeseburger and y be the number of calories in one small order of fries.
From the first statement, we know that:
2x + y = 1350
From the second statement, we know that:
3x + 2y = 2140
We can use these two equations to solve for x and y. First, we'll solve for y in terms of x by rearranging the first equation:
y = 1350 - 2x
Now we can substitute thisn expression for y into the second equation:
3x + 2(1350 - 2x) = 2140
Simplifying this equation, we get:
3x + 2700 - 4x = 2140
-x = -560
x = 560
So one cheeseburger contains 560 calories. We can plug this value back into either of the original equations to solve for y:
2(560) + y = 1350
y = 230
So one small order of fries contains 230 calories.
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Urgent please help!!
Answer:
i think it would be B because if AC= 80 and thats like the distane between then abc would be 80 if im thinking right
Step-by-step explanation:
but hey if im wrong ill have my friend punch me in the arm to make it even
please help!! ABCD is a square. If AC = 26, Find BC
a. 7
b. 26
c. 12
d. 18.4
\( \\ \\ \)
To find:-BC\( \\ \\ \)
Solution:-Let AC = x.
\( \\ \)
As given figureis square, therefore all sides are equal :-
AB = xAD = xDC = x\( \\ \)
So now instead of square focus on triangle ABC.
where :-
\( \small \rm \angle B = 90 \degree\)
\( \\ \)
Equation formed:-
\( \\ \\ \)
\( \rm \dashrightarrow AC {}^{2} = AB {}^{2} + BC {}^{2} \)
\( \\ \)
\( \rm \dashrightarrow 26 {}^{2} = x{}^{2} + x {}^{2} \)
\( \\ \)
\( \rm \dashrightarrow 26 {}^{2} =2x {}^{2} \)
\( \\ \)
\( \rm \dashrightarrow 26 \times 26 =2x {}^{2} \)
\( \\ \)
\( \rm \dashrightarrow2x {}^{2} = 26 \times 26 \)
\( \\ \\ \)
\( \rm \dashrightarrow x {}^{2}=\dfrac{ 26 \times 26 }{2}\)
\( \\ \\ \)
\( \rm \dashrightarrow x {}^{2}=\dfrac{ 26 \times \cancel{26 }}{\cancel{2}}\)
\( \\ \\ \)
\( \rm \dashrightarrow x {}^{2}=\dfrac{ 26 \times 13}{1}\)
\( \\ \\ \)
\( \rm \dashrightarrow x {}^{2}=26 \times 13\)
\( \\ \)
\( \rm \dashrightarrow x = \sqrt{26 \times 13} \)
\( \\ \)
\( \rm \dashrightarrow x = \sqrt{338} \)
\( \\ \)
\( \bf \dashrightarrow x = 18.38\)
\(\\ \\ \)
Formula used:-
\( \bigstar \boxed{\tt Hypotenuse^2 = Base^2+Perpendicular^2}\)
\(\\ \\ \)
Therefore BC is equal to 18.38 cm.
____________________⭑Related Concept⭑
Property of square:-
All sides of square are equal.All angles of square are equal.All angles of square are in 90°.The diagonals of a square bisect each other and meet at 90°.There are four sides and four angles in square.Opposite sides of a square are parallel to each other.Pallette Manufacturing received an invoice dated October 5 with terms 4/10, n/30. The amount stated on the invoice was $3584.00. (a) What is the last day for taking the cash discount? (b) What is the amount due if the invoice is paid on the last day for taking the discount? (a) The last day to take the cash discount is (b) The amount due is $ (Round to the nearest cent as needed.)
(a) The last day for taking the cash discount is October 15.
(b) The amount due if the invoice is paid on the last day for taking the discount is $3440.64.
(a) To determine the last day for taking the cash discount, we need to consider the terms mentioned: 4/10, n/30.
The first number, 4, represents the discount percentage, and the second number, 10, represents the number of days within which the discount can be taken. The "n" represents the net amount due, and the third number, 30, represents the total credit period available.
To calculate the last day for taking the cash discount, we need to add the discount period (10 days) to the invoice date (October 5).
Invoice date: October 5
Discount period: 10 days
Adding 10 days to October 5, we get:
October 5 + 10 days = October 15
Therefore, the last day for taking the cash discount is October 15.
(b) To calculate the amount due if the invoice is paid on the last day for taking the discount, we subtract the discount from the total amount stated on the invoice.
Invoice amount: $3584.00
Discount percentage: 4%
To calculate the discount amount, we multiply the invoice amount by the discount percentage:
Discount amount = $3584.00 × 0.04 = $143.36
Subtracting the discount amount from the invoice amount gives us the amount due:
Amount due = $3584.00 - $143.36 = $3440.64
Therefore, the amount due if the invoice is paid on the last day for taking the discount is $3440.64.
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Are u confused, depressed, and need help with homework?
Too bad, so am i
it's ok.
Answer:
true, i feel ya.
Add
3/5+7/8+3/10
Enter your answer in the box as a mixed number in simplest form.
Let C=D={-3, -2, -1, 1, 2, 3} and define a relation S from C to D as follows: For all
( x , y ) \in C \times D
(x,y)∈C×D
.
( x , y ) \in S
(x,y)∈S
means that
\frac { 1 } { x } - \frac { 1 } { y }
x
1
−
y
1
is an integer. a. Is 2 S 2? Is -1S-1? Is (3, 3)
\in S ?
∈S?
Is (3, -3)
\in S ?
∈S?
b. Write S as a set of ordered pairs. c. Write the domain and co-domain of S. d. Draw an arrow diagram for S.
Answer:
Step-by-step explanation:
I'm pretty
a. Let's check whether the given pairs are in the relation S or not.
Is 2 S 2?
To check if (2, 2) is in S, we need to evaluate the expression:
(1/2) - (1/2) = 1/2 - 1/2 = 0
Since 0 is an integer, (2, 2) is in S.
Is -1 S -1?
To check if (-1, -1) is in S, we need to evaluate the expression:
(1/-1) - (1/-1) = -1 - (-1) = 0
Since 0 is an integer, (-1, -1) is in S.
Is (3, 3) ∈ S?
To check if (3, 3) is in S, we need to evaluate the expression:
(1/3) - (1/3) = 1/3 - 1/3 = 0
Since 0 is an integer, (3, 3) is in S.
Is (3, -3) ∈ S?
To check if (3, -3) is in S, we need to evaluate the expression:
(1/3) - (1/-3) = 1/3 + 1/3 = 2/3
2/3 is not an integer, so (3, -3) is not in S.
b. Set of ordered pairs S:
S = {(x, y) | (1/x) - (1/y) is an integer}
S = {(2, 2), (-1, -1), (3, 3)}
c. Domain and Co-domain of S:
Domain of S: The set of all first components (x-values) of the ordered pairs in S.
Domain of S = {-3, -2, -1, 1, 2, 3}
Co-domain of S: The set of all second components (y-values) of the ordered pairs in S.
Co-domain of S = {-3, -2, -1, 1, 2, 3}
d. Arrow diagram for S:
Domain (C): {-3, -2, -1, 1, 2, 3}
Co-domain (D): {-3, -2, -1, 1, 2, 3}
(2, 2) -----> (0) // 0 represents an integer
(-1, -1) -----> (0)
(3, 3) -----> (0)
(3, -3) -----> (2/3) // 2/3 is not an integer
Note: The arrow diagram helps visualize the mapping of elements from the domain to the co-domain based on the relation S. Arrows point from the element in the domain to the result of the expression (integer or not integer) in the co-domain.
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What value of x is in the solution set of the inequality 4x – 12 ≤ 16 + 8x?
–10
–9
–8
–7
Answer:
-7
Step-by-step explanation:
\(4x-12 \leq 16+8x \\ \\ -12 \leq 16+4x \\ \\ -28 \leq 4x \\ \\ 4x \geq -28 \\ \\ x \geq -7\)
Add these fractions, giving your answer
in its simplest form.
6/12 + 2/13 =?
Answer: 0.6 espero haberte ayuado
Step-by-step explanation: