If you double the lenght of a wire, how does the resistance of the wire change?
and
If you make a wire twice as thick, how does the resistance of the wire change?
Answer:
If the length of a wire is doubled the resistance is shortened if it is thicker is is more durable due to the electrons having more room to spread out and flow through the wire
I hope this will help you
need some help with just one question please help.What is the pH of a 9.7 x 10-5 M NaOH solution? (2 formulas)
51.86% of all the isotopes of an element have a mass of 106.82 amu and 48.14% have a mass of 109.03 amu.
What is the average mass of this element?
Answer:
Average Mass = 107.88 amu
Explanation:
We can calculate the average mass of an element by mutlpying the mass of its isotopes by their respective relative abundance and then making a total sum. Meaning that for this case:
Average Mass = 106.82 amu * 51.86/100 + 109.03 amu * 48.14/100Average Mass = 107.88 amuWhat is the specific heat of a substance if 690 J of heat are required to raise the temperature of a 100 g
sample by 15°C? You must show your work
Answer:
hi
Explanation:
______. What is the mass in grams of 5.90 mol C6 H14?
a. 389 g
b.104g
c. 613.6g
d.0567g
C6H14 has a molecular weight of 86.18 g/mol (612.01 + 141.01) g/mol.
How much is the weight?Weight is a measurement of the force of gravity acting on an object. It is inversely related to the mass and gravitational acceleration of an object. Despite the fact that the terms weight and mass are frequently used interchangeably in ordinary conversation, it is crucial to understand the difference between the two. Weight is a measurement of the force of gravity acting on an object, whereas mass was an indication of the quantity of matter that makes up that object.
Describe a force?A physical quantity called force defines the interaction of two systems or objects. It has both size (size) and direction because it is a form of vector quantity.
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Word Bank please help will give brainlist :)
Answer:
Erosion: The process of eroding or being eroded by wind, water, or other natural agents.
Abrasion: The process of scraping or wearing something away.
Water: A type of liquid that fills our ocean, lakes, rivers etc.
Glaciers: A slowly moving mass or river of ice formed by the accumulation and compaction of snow on mountains or near the poles.
Deflation: The action or process of deflating or being deflated.
Plucking: Take hold of something and quickly remove it from its place.
Deposition: The action of deposing someone, especially a monarch.
Gravity: The force that attracts a body toward the center of the earth, or toward any other physical body having mass.
Weathering: The process of wearing or being worn by long exposure to the atmosphere.
Moraines: A mass of rocks and sediment carried down and deposited by a glacier, typically as ridges at its edges or extremity.
Mass Movements: Processes of erosion, transport and accumulation of material that occur on both gentle and steep slopes mainly owing to gravitational forces
Wind: The perceptible natural movement of the air, especially in the form of a current of air blowing from a particular direction.
Explanation:
I hope this is the answers you want (also sorry for being so late)
HELP PLEASE FAST 100 POINTS
In any chemical reaction, the mass of the products must equal the mass of the reactants. The mass of product B is the same as the combined mass of Reactant A and H₂O.
Answer:
sh5barch shougi
Explanation:
HELP ASAPPPPPPPPPPPPPPPP PLEASEEEEE
Answer choices
Na2SO4
Al2(SO4)3
BaCl2
NaOH
Na2CrO4
Ba(NO3)2
1. The volume of a given mass of gas is 720 ml at 15°C. Assuming
constant pressure, at what temperature will its volume be 960 ml?
2. A sample of gas is found to occupy a volume of 900 cm3 at 270
°C. Calculate the temperature at which it will occupy a volume of
300 cm3, provided the pressure is kept constant.
please mark my answer brainliest...
condition...pressure remains constant.
for 720 ml temp is 15°...so for 960ml temp will be 15/720×960=20°...(.answer for 1st part...)for 900cmcube temp is 270°C...so for300cmcube temp will be 270/900×300=90°....(answer for 2nd part)...I hope it helps the dear students...and if it is then let me know through ur comments...and please mark my answer as brainliest...plz...1. The temperature at which the volume of gas has been 960 ml is \(\rm \bold{19.99\;^\circ C}\).
2. The temperature at which the volume of gas has been \(\rm 300\;cm^3\) is \(\rm \bold{90^\circ C}\).
1. The gas has been assumed to be an ideal gas. For an ideal gas, the relationship between temperature and volume at constant pressure has been given as:
\(\dfrac{V1}{T1}=\dfrac{V2}{T2}\)
Where, the initial volume, \(V1=720\;\text {ml}\)
The final volume, \(V2=960\;\text {ml}\)
The initial temperature, \(T1=15\;^\circ \text C\)
Substituting the values, the final temperature, T2 can be given as:
\(\rm \dfrac{720\;ml}{15\;^\circ C}=\dfrac{960\;ml}{\textit{T}2} \\\textit T2=\dfrac{15\;^\circ C}{720\;ml}\;\times\;960\;ml\\\textit T2=19.99\;^\circ C\)
The temperature at which the volume of gas has been 960 ml is \(\rm \bold{19.99\;^\circ C}\).
2. The temperature for gas to occupy \(\rm 300\;cm^3\) has been given as:
Where, the initial volume, \(V1=900\;\rm{cm^3}\)
The final volume, \(V2=300\;\rm {cm^3}\)
The initial temperature, \(T1=270\;^\circ \text C\)
Substituting the values, the final temperature, T2 can be given as:
\(\rm \dfrac{900\;cm^3}{270\;^\circ C}=\dfrac{300\;cm^3}{\textit{T}2} \\\textit T2=\dfrac{270\;^\circ C}{900\;cm^3}\;\times\;300\;cm^3\\\textit T2=90\;^\circ C\)
The temperature at which the volume of gas has been \(\rm 300\;cm^3\) is \(\rm \bold{90^\circ C}\).
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1- Draw the potential energy for system of two atoms versus the internuclear separation distance for these two atoms U(r) 2- Bohr's model of the hydrogen atom
1- U(r) has a repulsive region at small r due to electron-electron repulsion, followed by an attractive region at intermediate r due to electron-nucleus attraction, and a negligible potential at large r.
The potential energy, U(r), for a system of two atoms can be represented graphically as a function of the internuclear separation distance, r. At small values of r, the atoms experience repulsion due to the electron-electron interactions, resulting in a steep increase in potential energy. This repulsive region prevents the atoms from getting too close to each other.
As the internuclear separation distance increases, the attractive force between the electrons and the nuclei becomes dominant, leading to a decrease in potential energy. This attractive region is typically characterized by a shallow potential well. At intermediate values of r, the potential energy reaches a minimum, indicating a stable configuration where the atoms are bonded.
2- Bohr's model describes the hydrogen atom as a nucleus with an electron orbiting it in quantized energy levels. Electrons can transition between levels by absorbing/emitting photons with energy given by ΔE = hf. The model has limitations but introduced the concept of discrete energy states in atoms.
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As the reaction in a galvanic cell proceeds towards products, which of the following are true?
A) ΔG starts at 0, stays same
B) ΔG starts < 0, becomes more negative
C) ΔG starts < 0, stays same
D) ΔG starts < 0, becomes more positive
E) ΔG starts > 0, stays same
In a galvanic cell, the reaction proceeds towards the production of products. ΔG starts < 0, becomes more negative
Option B is correct .
As the reaction proceeds, the Gibbs free energy (ΔG) reduces, and the following are true: ΔG starts < 0, becomes more negative.
When the reaction in a galvanic cell proceeds towards the production of products, the Gibbs free energy starts with a negative value, and it becomes even more negative.
The Gibbs free energy (ΔG) is a measure of the available energy in a system that can be used to do work. It measures the difference between the free energy of the final state and the initial state.The Gibbs free energy change of a system is dependent on the enthalpy and entropy change. If the enthalpy change is negative (exothermic), and the entropy change is positive (disorderly), the Gibbs free energy change is negative, and the reaction is spontaneous.
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Which response contains all the salts whose aqueous solutions are acidic, and no other salts?
I. NH4NO3
II. NaCN
III. KCl
IV. NH4Br
V. LiCl
VI. CaCl2
VII. CH3NH3Cl
VIII. KNO2
IX. NH4CH3COO
a. II, III, V, VI, and VIII
b. I, IV, and VII
c. II, VIII, and IX
d. I, IV, VII, and IX
e. II and VIII
The salts whose aqueous solutions are acidic are those that contain the conjugate acid of a weak base. This means that when dissolved in water, they donate protons (H+) to the solution, leading to an increase in the concentration of hydrogen ions and a decrease in pH.
From the given options, the response that contains all the salts whose aqueous solutions are acidic and no other salts is option (b) I, IV, and VII.
Salt I is ammonium chloride (NH4Cl), which is formed from the reaction between ammonia (a weak base) and hydrochloric acid. It ionizes in water to give ammonium ions (NH4+) and chloride ions (Cl-), and since ammonium ion is the conjugate acid of the weak base ammonia, its aqueous solution is acidic.
Salt IV is sodium bisulfate (NaHSO4), which is formed from the reaction between sulfuric acid and sodium hydroxide. It ionizes in water to give hydrogen ions (H+) and bisulfate ions (HSO4-), and since hydrogen ion is acidic, its aqueous solution is also acidic.
Salt VII is potassium hydrogen phthalate (KHC8H4O4), which is a weak acid. It ionizes in water to give hydrogen ions (H+) and phthalate ions (C8H4O42-), and since it is a weak acid, its aqueous solution is acidic.
Therefore, the response that contains all the salts whose aqueous solutions are acidic and no other salts is option (b) I, IV, and VII.
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Plastic is used to cover the copper wire in the power codes of appliances because plastic differs from copper in _________
Answer:
in copper from different plastics because appliances of codes to power day in wire copper the cover to use to plastic
below what pressure will solid sulfur sublime
In terms of the above, Solid sulfur sublimes below the pressure of 0.027mmHg.
What is sublimation?This refers to the process by which substances change directly from the solid phase to the gas phase without passing through the intermediate liquid phase.
Sulfur that has been sublimed is created through a time-honored natural chemical process. This sublimation, which takes place in high-temperature furnaces, enables the product to reach 99.99% particle single purity
Therefore, one can say that sublimation is an endothermic phase transition( phase change that absorbs heat from the surrounding environment) that takes place at temperatures and pressures below the triple point of a chemical in the phase diagram.
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calculate ∆g at 298 k for a mixture of 1.0 atm n2, 3.0 atm h2, and 0.50 atm nh3 being used in the equation below:
The Haber process's value of ∆G at 298 K is -73.2 kJ/mol. The reaction occurs spontaneously in the forward direction because ∆G is negative.
To calculate ∆G for this reaction at 298 K, we can use the equation:
∆G = ∆G° + RTln(Q)
where ∆G° is the standard free energy change, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.
First, we need to determine the value of Q. For this, we use the partial pressures of the gases at equilibrium:
Q = (P(NH₃))² / (P(N₂) * P(H₂)³)
Substituting the values, we get:
\(Q = \frac{{(0.50 \, \text{{atm}})^2}}{{(1.0 \, \text{{atm}}) \cdot (3.0 \, \text{{atm}})^3}}\)
Q = 1.85 x 10^-5
Next, we need to determine ∆G°. For this, we can use tabulated standard free energy of formation values to calculate the change in free energy for the reaction.
The standard free energy of formation values for N₂, H₂, and NH₃ are 0 kJ/mol, 0 kJ/mol, and -16.5 kJ/mol, respectively.
\(\Delta G^{\circ} = (2 \cdot \Delta G^{\circ}_f(NH_3)) - (\Delta G^{\circ}_f(N_2) + 3 \cdot \Delta G^{\circ}_f(H_2))\)
\(\Delta G^{\circ} = (2 \times (-16.5 \, \text{kJ/mol})) - (0 \, \text{kJ/mol} + 3 \times 0 \, \text{kJ/mol})\)
∆G° = -33.0 kJ/mol
Substituting the values in the first equation, we get:
\(\Delta G = -33.0 \, \text{kJ/mol} + (8.314 \, \text{J/mol}\cdot \text{K}) \times (298 \, \text{K}) \times \ln(1.85 \times 10^{-5})\)
∆G = -33.0 kJ/mol - 40.2 kJ/mol
∆G = -73.2 kJ/mol
Therefore, the value of ∆G at 298 K for the Haber process is -73.2 kJ/mol. Since ∆G is negative, the reaction is spontaneous in the forward direction.
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Complete question :
Calculate ∆G at 298 K for a mixture of 1.0 atm N₂, 3.0 atm H₂, and 0.50 atm NH₃ being used in the Haber process: N₂(g) + 3H₂(g) ⇌ 2NH₃(g)
0.22g of carbon dioxide are dissolved in 400 cm3 of pure water.
Calculate the concentration in mol/dm3 of the
solution produced.
Answer:
0.0125mol/dm³
Explanation:
Given parameters:
Mass of carbon dioxide = 0.22g
Volume of water = 400cm³
Unknown:
Concentration in mol/dm³ = ?
Solution:
Concentration is the amount of solute dissolved in a solvent.
The formula is expressed as;
Concentration = \(\frac{number of moles}{volume}\)
Number of moles = \(\frac{mass}{molar mass}\)
Molar mass of CO₂ = 12 + 3(16) = 44g/mol
Number of moles = \(\frac{0.22}{44}\) = 0.0005mol
Now,
1000cm³ = 1dm³
400cm³ = \(\frac{400}{1000}\) = 0.4dm³
Insert the parameters and solve;
Concentration = \(\frac{0.005}{0.4}\) = 0.0125mol/dm³
What was the significance of Daniel Burham’s Plan of Chicago?
What is the reaction ship between cells and tissues
Answer:
A. Tissues are made up of cells
Explanation:
I just googled it :3
What are the elements in group two called
Answer: Alkaline-earth metal, any of the six chemical elements that comprise Group 2 (IIa) of the periodic table. The elements are beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra). Hopefully i helped
Explanation:
Answer: Alkaline-earth metal
Explanation:
what frequency does television channel 7 broadcast at?
Answer:
Channel 7's frequency is 117.5 MHz
Answer:
174 MHz - 180 MHz w/ center frequency of 177 MHz
Explanation:
216 - 174 = 42
42/7 = 6
6 + 174 = 180 - 7 - 177 MHz
180 + 6 = 186 - 8 - 183 MHz
186 + 6 = 192 - 9 - 189 MHz
192 + 6 = 198 - 10 - 195 MHz
198 + 6 = 204 - 11 - 201 MHz
204 + 6 = 210 - 12 - 207 MHz
210 + 6 = 216 - 13 - 213 MHz
What results when two waves that are completely out of phase meet?
Answer:
Explanation:Destructive interference occurs when the maxima of two waves are 180 degrees out of phase: a positive displacement of one wave is cancelled exactly by a negative displacement of the other wave. The amplitude of the resulting wave is zero.
If two waves that are completely out phase if meet they results in destructive interference. Hence, their intensities decreases for the resultant wave.
What is interference ?A wave of greater, lower, or the same amplitude is created when two waves merge through interference by combining their displacements at all points in space and time.
The interaction of waves that are coherent or correlated with one another, either because they originate from the same source or because their frequencies are similar or almost identical, leads to both constructive and destructive interference.
All sorts of waves, including light, radio, acoustic, surface water waves, gravity waves, and matter waves, can exhibit interference effects. In constructive interference, the waves are in single phase forms a resultant wave with higher amplitude.
When waves from out of phase meets, the resultant wave will have an amplitude less than the individual amplitudes.
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We wish to determine how many grams
of solid silver chromate will precipitate
when 150. mL of 0.500 M silver nitrate
solution is added to excess potassium
chromate.
2AgNO3(aq)
How many moles of AgNO3 are present
in 150. mL of 0.500 M AgNO3?
+ K₂ CrO4 (aq) → Ag₂ CrO4(s) + 2KNO3(aq)
Approximately 12.45 grams of solid silver chromate will precipitate when 150 mL of 0.500 M silver nitrate solution is added to excess potassium chromate.
To determine the number of moles of AgNO3 present in 150 mL of a 0.500 M AgNO3 solution, we can use the formula:
moles = concentration × volume
Given:
Concentration of AgNO3 solution = 0.500 M
Volume of AgNO3 solution = 150 mL
First, we need to convert the volume from milliliters (mL) to liters (L) since the concentration is given in moles per liter (M).
1 L = 1000 mL
Therefore, the volume of the AgNO3 solution in liters is:
150 mL × (1 L / 1000 mL) = 0.150 L
Now we can calculate the moles of AgNO3 using the formula:
moles = concentration × volume
moles = 0.500 M × 0.150 L
moles = 0.075 mol
So, there are 0.075 moles of AgNO3 present in 150 mL of the 0.500 M AgNO3 solution.
Now, let's proceed to determine how many grams of solid silver chromate (Ag2CrO4) will precipitate when the AgNO3 solution reacts with excess potassium chromate (K2CrO4).
From the balanced chemical equation:
2AgNO3(aq) + K2CrO4(aq) → Ag2CrO4(s) + 2KNO3(aq)
We can see that the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Therefore, for every 2 moles of AgNO3, we will form 1 mole of Ag2CrO4.
Since we have 0.075 moles of AgNO3, we can calculate the moles of Ag2CrO4 formed:
moles of Ag2CrO4 = 0.075 mol / 2 = 0.0375 mol
To determine the mass of Ag2CrO4, we need to multiply the moles by its molar mass. The molar mass of Ag2CrO4 is calculated by summing the atomic masses of each element in the compound:
Ag2CrO4 = 2(Ag) + 1(Cr) + 4(O) = 2(107.87 g/mol) + 1(52.00 g/mol) + 4(16.00 g/mol) = 331.87 g/mol
mass of Ag2CrO4 = moles of Ag2CrO4 × molar mass of Ag2CrO4
mass of Ag2CrO4 = 0.0375 mol × 331.87 g/mol = 12.45 g
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Tarnish on silver is the compound Ag2O. A tarnished silver spoon is placed in an aluminum pan of boiling water. When enough salt is added so that the solution conducts electricity, the tarnish disappears.
Imagine that the two halves of this redox reaction were separated and connected with a wire and a salt bridge.
Calculate the standard cell potential given the following standard reduction potentials:
Al3+ + 3e- ---> Al Eo = -1.66 V
Ag+ + e- ---> Ag Eo = +0.799 V
Tthe standard cell potential of the redox reaction is 2.459 V.
To calculate the standard cell potential (E°cell), we subtract the reduction potential of the anode from the reduction potential of the cathode. The cathode is where reduction occurs, so we use the reduction potential of Ag, which is +0.799 V.
The anode is where oxidation occurs, so we use the reduction potential of Al and reverse the sign since it is an oxidation reaction, resulting in -1.66 V.
E°cell = E°cathode - E°anode
E°cell = +0.799 V - (-1.66 V)
E°cell = +0.799 V + 1.66 V
E°cell = 2.459 V
Therefore, the standard cell potential of the redox reaction is 2.459 V.
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the group numbers for carbon oxygen, nitrogen and sulpher.
Answer:
Carbon: 14
Oxygen: 16
Nitrogen: 15
Sulpher: 16
does a reaction occur when aqueous solutions of potassium nitrate and copper(ii) sulfate are combined?
Yes, the reaction between aqueous solutions of potassium nitrate and copper(ii) sulfate happens when they are combined giving products by a reaction called double displacement reaction.
What is double displacement reaction?
Double displacement reaction is also called as double displacement exchange. This happens when some parts of 2 ionic compounds which are reacting are exchanged between them, making 2 new compounds. The positive and negative ions swap their places between the reactants in this reaction.
The reaction between aqueous solutions of potassium nitrate and copper(ii) sulfate give 2 products that is copper nitrate and potassium sulfate. This reaction is known as double displacement reaction.
Balanced chemical equation:
2KNO3 + CuSO4 ----> Cu(NO3)2 + K2SO4
Therefore, the reaction between aqueous solutions of potassium nitrate and copper(ii) sulfate is possible and it gives products like copper nitrate and potassium sulfate making it a double displacement reaction.
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Three elements in the same period are listed in order of decreasing atomic radius. Which of the following is an appropriate explanation for the non-metal in the list having the smallest atomic radius
The appropriate explanation for the non-metal is that the higher effective nuclear charge less will be the atomic radius.
Atomic radius typically decreases during a period from left to right. There are a few little outliers, such how the oxygen radius is a tiny bit bigger than the nitrogen radius. Protons are gradually added to the nucleus at the same time that electrons are gradually added to the main energy level. The enhanced positive charge of the nucleus gradually attracts these electrons closer to it. The size of the atoms shrinks as the strength of attraction between nuclei and electrons grows. Due to electron-electron repulsions that would otherwise result in the atom's size expanding, the effect becomes less pronounced as one proceeds further to the right in a period.
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An advantage of cooking in steam is .
A. it is faster than boiling when pressure is added
B. foods are more flavorful
C. foods are more nutritious
D. All of the above.
Answer:
The answe is all of the above
14. A force acts for 0.2 second on a body of mass 80 kg at rest and produces a velocity of 10 ms¹.Find the magnitude of the force.
The magnitude of the force acting on the body is 4000 Newtons.
To find the magnitude of the force, we can use Newton's second law of motion, which states that the force applied to an object is equal to the product of its mass and acceleration.
The given information includes the mass of the body (80 kg) and the resulting velocity (10 m/s). However, since the time duration (0.2 seconds) is also provided, we can use it to calculate the acceleration of the body.
The formula to calculate acceleration is:
Acceleration = Change in Velocity / Time
The change in velocity can be calculated by subtracting the initial velocity (which is 0 m/s as the body is at rest) from the final velocity:
Change in Velocity = Final Velocity - Initial Velocity
Change in Velocity = 10 m/s - 0 m/s
Change in Velocity = 10 m/s
Now, we can calculate the acceleration:
Acceleration = Change in Velocity / Time
Acceleration = 10 m/s / 0.2 s
Acceleration = 50 m/s²
Finally, we can calculate the magnitude of the force using Newton's second law:
Force = Mass x Acceleration
Force = 80 kg x 50 m/s²
Force = 4000 N
Therefore, the magnitude of the force acting on the body is 4000 Newtons.
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The enthalpy change when 1 mole of gaseous atoms is formed from elements in its standard state____Enthalpy change of atomisation (ÎHat)
The enthalpy change when 1 mole of gaseous atoms is formed from elements in its standard state is called the enthalpy change of atomization.
It is defined as the enthalpy change that occurs when one mole of a substance in its standard state is converted into gaseous atoms at the same temperature and pressure. This process requires the input of energy, which is typically provided by heat. The enthalpy change of atomization is usually expressed in units of kilojoules per mole (kJ/mol).
For example, the enthalpy change of atomization for chlorine gas is +121 kJ/mol. This means that it takes 121 kilojoules of energy to convert one mole of chlorine gas into gaseous chlorine atoms at standard temperature and pressure.
This process involves breaking the bonds between the atoms in the elements and forming new bonds between the individual atoms to create the gaseous atoms. The enthalpy change associated with this process is a measure of the energy required to break the bonds and the energy released when the new bonds are formed.
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A compound conducts electricity in the solid state and does not dissolve in water. It isshiny and malleable. What type of bonding does it likely have?b. Ionicc. metallica.Covalent
Metallic solids,
the atoms within such a metallic solid are held together by a unique force known as metallic bonding that gives rise to many useful and varied bulk properties. All exhibit high thermal and electrical conductivity, metallic luster, and malleability.
Answer: c. metallic