write the equilibrium-constant expression for the given reaction. c(s) 2h2(g)↽−−⇀ch4(g)
by placing the correct species in the appropriate locations.

Vapor density is defined as the amount of weight of a gas or vapor in comparison to air.

The relative weight of a gas or vapor in comparison to air, which has an arbitrary value of one, is defined as vapor density. If a gas's vapor density is less than one, it will rise in air. When the vapor density exceeds one, the gas will normally sink in air.

Vapor density is only a broad concept used to estimate where vapors might be discovered when released. This physical parameter, however, is not absolute and can be influenced by:

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Answer:

Iron: Fe

Co: cobalt

Na: sodium

Tin: sn

P: phosphorus

F: fluorine

Sb: Antimony

Magnesium: mg

Titanium: Ti

Ca: calcium

Carbon: C

Lead: PB

Ag: silver 

Zn: zinc 

Ni: Nickle

Explanation:

the one above me had a few open spots so a patched them

NO₂ is the reactant in excess, and 4.4 moles of NO₂ remain after the reaction has completed.

To determine which reactant is in excess, we need to compare the stoichiometric ratios of the reactants. According to the balanced equation, the ratio between NO₂ and H₂O is 3:1.

To determine the limiting reactant, we can calculate the moles of each reactant required for the reaction. Since the ratio is 3:1, we need 3 times more moles of NO₂ than H₂O.

Moles of NO₂ required = 3 * 0.20 mol = 0.60 mol

Comparing this with the actual amount of NO₂ provided (5.0 mol), we see that there is an excess of NO₂.

Therefore, NO₂ is the reactant in excess.

To find the number of moles of the excess reactant remaining after the reaction has completed, we can subtract the moles of the limiting reactant used from the initial moles of the excess reactant.

Moles of excess reactant remaining = Moles of excess reactant initially - Moles of excess reactant used

Moles of excess reactant remaining = 5.0 mol - 0.60 mol

Moles of excess reactant remaining = 4.4 mol

After the reaction has completed, there are 4.4 moles of NO₂ remaining as the excess reactant.

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Answer:

n₂ =  6.8 mol

Explanation:

Given data:

Initial number of moles = 3.4 mol

Initial volume = 25 L

Number of moles = ?

Final volume = 50 L

Solution:

According to Avogadro law,

V₁/n₁  = V₂/n₂

Now we will put the values in formula.

25 L/3.4 mol = 50 L/ n₂

n₂ = 50 L× 3.4 mol/25 L

n₂ = 170 L.mol/25 L

n₂ =  6.8 mol

The learner can identify which sample, P or Q, has a larger concentration of sulfuric acid based on the volumes of NaOH needed.

The learner can utilise titrations to determine whether sample, P or Q, is more concentrated. Here is a procedure the student can follow in detail:

Create a standard sodium hydroxide (NaOH) solution with a given concentration.

Samples P and Q are divided into equal volumes and transferred into two separate flasks.

To each flask, add a few drops of an indicator, such as phenolphthalein. The indicator's colour will change when the titration has reached its conclusion.

Stirring continuously, gradually add the standard NaOH solution to one flask until the indicator's colour permanently changes.

Utilising the same quantity of the regular NaOH solution, repeat the procedure for the second flask.

Each flask's NaOH solution volume should be noted.

The amounts of NaOH used for samples P and Q should be compared. The sample with a higher percentage of sulfuric acid required more NaOH to get to the endpoint.

To make sure the titration is accurate and consistent, repeat it several times.

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Step 1

The reaction involved here:

3 FeO + 2 Al => 3 Fe + AI2O3 (Don't forget to completed it and balance it)

---------------

Step 2

Data provided:

125 grams of FeO react with 25.0 grams of AI

--

Data needed:

The molar masses of:

FeO) 71.8 g/mol

Al) 27.0 g/mol

Fe) 55.8 g/mol

---------------

Step 3

The limiting reactant:

By stoichiometry,

3 FeO + 2 Al => 3 Fe + AI2O3

3 x 71.8 g FeO ----- 2 x 27.0 g Al

125 g FeO ----- X

X = 125 g FeO x 2 x 27.0 g Al/3 x 71.8 g FeO

X = 31.3 g Al

For 125 g of FeO, 31.3 g of Al is needed, but there is 25.0 g of Al, so the limiting reactant is Al.

-------------

Step 4

The amount of Fe produced:

By stoichiometry,

3 FeO + 2 Al => 3 Fe + AI2O3

2 x 27.0 g Al ---- 3 x 55.8 g Fe

25.0 g Al --- X = 77.5 g Fe

Answer: 77.6 g Fe (the closest value)

Answer:

Center of gravity.

Explanation:

Answer:

No, Lithium is the softest alkai metal

Explanation:

hope this helps :)

The pH of 7.67 in the patient's blood, which is more basic than the normal range, suggests a potential health concern and warrants further evaluation.

There is cause for concern. A pH of 7.67 indicates that the blood is more basic than the normal range for human blood, which suggests a higher hydroxide ion concentration. While the given pH value does not provide the exact hydroxide ion concentration, it is clear that the patient's blood pH is outside the normal range. This abnormal pH level can be indicative of an underlying health issue, especially in the case of diabetics who are known to experience fluctuations in blood pH due to metabolic imbalances.

A pH level outside the normal range may indicate a condition called metabolic alkalosis, which can be caused by various factors such as excessive vomiting, certain medications, or underlying health conditions. It is important for the patient to consult a healthcare professional to determine the cause of the abnormal pH and to assess their overall health. Regular monitoring and proper management of blood pH levels are crucial for maintaining homeostasis and ensuring optimal health.

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Answer:

all metals have low melting point

Answer:

1;1, 2;1, 3;1, 1;2, 1;1, 3;2, 1;3, 2;3, 1;1.

I hope this will help.

Answer:

This is what the answer looks like

Explanation:

Answer:

Your Answer is Option A that is Gas.

Answer:

nNaOH = 0,2 mol

Trong hỗn hợp các chất đề bài cho chỉ có phenol tác dụng với NaOH

C6H5OH + NaOH → C6H5ONa + H2O

   0,2  ←     0,2 (mol)

⟹ mphenol = 0,2.94 = 18,8 gam

⟹  

%mC6H5OH=18,8/28,9 x100%= 65,05%

Explanation:

The welding electrodes are commonly classified by the coating type, welding position, preferred current and polarity, and the tensile strength of the deposited weld metal.

The classification of welding electrodes takes into account factors such as the electrode metal, flux coating, current utilized, welding position, performance traits, chemistry, and mechanical properties of the weld metal, among others. The usefulness, the makeup of the deposited weld metal, and the electrode specification are all dependent on the composition of the welding electrode coating.

The creation of welding electrode coatings is based on well-known metallurgical, chemical, and physical concepts. Once the molten metal is exposed to the environment, oxygen and nitrogen are absorbed, which have negative effects and make the metal brittle. To protect from the atmosphere, molten/solidifying weld metal would need to be covered in as blanket; electrode coating serves as this shield.

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Answer:

The correct answer is 1) 257 and 2) 135

Explanation:

Answer:

The movement of materials based on differences in temperature and density, I believe

Explanation:

a- Aluminium bromide has the following formula: AlBr₃, so the unbalanced equation is:

As we can see, for now the aluminium atoms are balanced, but the bromine is not. To balance the bromine, we can put 3 in front of Br₂ and 2 in front of AlBr₃. That way, we will have a total of 6 bromine atoms in each side:

But now the Al is unbalaced, so to fix it we can add a 2 in front of Al to get the balanced equation:

b- The aluminium are the lone atoms, so, counting them, we see that there are 8 atoms initially.

c- Each pair of empty circles represent a molecule of Br₂, counting them we have 6 molecules initially.

d- The proportion of Al to AlBr₃ is 2:2, that is, 1:1, so if all Al reacts, we would produce the same amount of AlBr₃ as Al, which would be 8 molecules.

The proportion of Br₂ to AlBr₃ is 3:2, so is all Br₂ reacts we will get 2/3 of that as AlBr₃, which would be 6*2/3 = 4 molecules.

This shows that there is not enough Br₂ to react with all 8 atoms of Al, meaning only 4 molecules of AlBr₃ will be produced.

e- Since there is not enough Br₂ to react with all Al present, the limiting reactant is the bromine.

f- The excess reactant is the other one, so if bromine is the limiting, the aluminium is the excess reactant.

g- Since only 4 molecules of AlBr₃ will be formed with all the bromine present, since the proportion of Al to AlBr₃ is 1:1, we wil need only 4 atoms of Al to produce them, which meand that, from the total 8 atoms, we will get

4 atoms of Al as excess reactant after the reaction is complete.

Answer:

Elements on the left side of a row always have higher atomic mass than elements on the right side of that row.

Explanation:

the answer I have above should be correct because it’s false so it’s the right answer.

The fact that coal releases more heat than charcoal means that the chemical potential energy is lower in charcoal than in coal.

When the substance is burnt in oxygen, the chemical potential energy stored in the substance is converted into heat energy. The substance that has the most chemical potential energy releases the most energy when burnt.

In burning coal and charcoal, you notice that coal releases more heat energy than charcoal. This means that the chemical potential energy is lower in charcoal than in coal.

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While visiting his uncle's farm, Derek learned that horses and donkeys are two different species. Based on this information, Derek can infer that horses and donkeys are members of different populations.


Since horses and donkeys are different species, they belong to different populations. A population refers to a group of individuals of the same species that live in the same area and can interbreed. While horses and donkeys can mate, their offspring, known as mules, are usually infertile.

This means that mules cannot produce offspring of their own, which indicates that horses and donkeys are not members of the same population. In contrast, if they were members of the same population, they would be able to produce fertile offspring. Therefore, Derek can infer that horses and donkeys are members of different populations.

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Answer:

~2.054M

Explanation:

In this question ,I am going to assume that the acid is monoprotic acid(contains only one hydrogen) which I'll represent by HA.

Chemical equation:

NaOH(aq) + HA(aq)----->NaA(aq) + H2O(l)

The mole ratio of NaOH:HA is 1:1

1.25M NaOH=1.25 Moles/L or 1.25 moles /1000ml of NaOH

(1.25 moles /1000ml) x (24.65ml)=0.0308125 moles NaOH

Mole ratio is 1:1

So, moles of HA are also 0.0308125 moles

volume of HA  =15ml

To find molarity of HA:

=(0.0308125 moles x 1000ml)/(15ml)

~2.054M of HA

~Hope it helps:)

We need to understand that reactions can happen at different speeds depending on the conditions to develop methods for production improvement.

The rate of any chemical reaction depends upon the nature of the reacting substances.  Under the same conditions , reactions that appear similar have different rates of reaction. Chemical reaction proceeds in different speeds, depend on the various factors such as type of chemical transformation , temperature and other factors. the information about the speed of reaction is useful in large scale production.

Thus, We need to understand that reactions can happen at different speeds depending on the conditions to develop methods for production improvement.

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Option C, a more saturated fat is the product(s) for the hydrogenation of corn oil.

Organic molecules are frequently reduced or saturated by the process of hydrogenation, which is a chemical reaction between hydrogen (H2) and another substance or element. The process of incorporating hydrogen molecules into the various carbon-carbon bonds is known as hydrogenation. Saturated fats emerge from this process. Double bonds change into single bonds throughout this Saturated fats, and the melting point steadily increases.

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The StartBracket upper O upper H superscript minus EndBracket equals StartFraction equation [OH-] = 1.0 x \(10^_-14\)/ [H+] is used to calculate [OH-] from [H+]. It is derived from the ion product constant for water.

The condition that accurately demonstrates the way that you could work out [OH-] from [H+] is:

[Goodness ] = 1.0 x \(10^_-14\)/[H+]

This condition is gotten from the particle item consistent for water, which is:

Kw = [H+][OH-] = 1.0 x \(10^_-14\)

At 25°C, the convergence of H+ and Gracious in unadulterated water are equivalent and each is equivalent to 1.0 x\(10^_-7\) mol/L. In this way, the pH of unadulterated water is 7.

On the off chance that the grouping of H+ in an answer is known, the centralization of Goodness can be determined involving the particle item consistent for water and reworking the condition to settle for [OH-]. This is on the grounds that the convergence of H+ and Goodness are conversely relative to one another.

Assuming the pH of the arrangement is known, the grouping of H+ can be determined utilizing the condition:

pH = - log[H+]

and afterward subbed into the situation to ascertain [OH-].

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The compound C7H14O8 does fit the formal definition of a carbohydrate.

Carbohydrates are organic compounds consisting of carbon, hydrogen, and oxygen atoms. They are characterized by their ratio of hydrogen and oxygen atoms, which is typically 2:1, similar to water (H2O). The general formula for carbohydrates is (CH2O)n, where "n" represents the number of carbon atoms.

In the given compound, C7H14O8, we can see that it contains carbon, hydrogen, and oxygen atoms. The ratio of hydrogen to oxygen atoms is close to 2:1, which is consistent with the general definition of carbohydrates. The presence of carbon and oxygen atoms further supports its classification as a carbohydrate.

However, to definitively confirm if C7H14O8 is a carbohydrate, additional information is needed, such as the arrangement and bonding of its atoms. Carbohydrates can have different structures, including monosaccharides (simple sugars), disaccharides (two sugar units), and polysaccharides (multiple sugar units). Without knowing the specific structure of the compound, it is challenging to determine its exact classification within the carbohydrate family.
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Answer:

Moon

Explanation:

The material is approximately 119 months old. This is based on the fact that the half-life of a radioactive material is the time taken for the quantity of the material to decrease to half of its original amount. In this case, 6.25% of the original radioactive atoms were present, which means that the material has decreased to half its initial amount after 35 months.  Therefore, it can be concluded that the material is approximately 119 months old (35 months * 3.4 = 119 months).

CLAIM: The material is approximately 105 months (8.75 years) old.

EVIDENCE: The material contains 6.25% of the original radioactive atoms.

REASONING: We can use the formula for radioactive decay to calculate the age of the material. The formula is:

\(N = N0 x (1/2)^(^t^/^T^)\)

where N is the final amount of radioactive atoms, N0 is the initial amount of radioactive atoms, t is the time that has passed, and T is the half-life of the material.

We know that N = 0.0625 N0, since only 6.25% of the original radioactive atoms are present. We also know that T = 35 months, the given half-life. Substituting these values into the formula, we get:

\(0.0625 N0 = N0 x (1/2)^(^t^/^3^5^)\))

Dividing both sides by N0, we get:

\(0.0625 = (1/2)^(^t^/^3^5^)\)

Taking the logarithm of both sides, we get:

\(log 0.0625 = (t/35) log (1/2)\)

Solving for t, we get:

\(t = -35 x (log 0.0625) / (log 1/2)\)

Using a calculator, we can evaluate the right-hand side of this equation to be approximately 105 months (8.75 years).

CONCLUSION: The material is approximately 105 months (8.75 years) old based on the evidence and reasoning presented above.