Explanation:
Let's use Zach's weight F = ma
F = 80 (9.81) = 785 N
at constant speed descending a = 9.81 and Zach's weight is still 785 N
As the elevator is slowing to a stop, Zach's apparent weight will increase
a = change in velocity / change in time = 10 m/s / 3s = 3.33 m/s^2
Zach's APPARENT weight will be F = ma where a = 9.81 + 3.33 m/s^2
F = 80 ( 9.81+3.33) = 1051 N
The arc definition of the Degree of Curve (D) is defined as the a) Central angle subtended by 100 ft of are b) Central angle subtended by 100 ft of chord c) Central angle subtended by 50 ft of chord d) Total arc length of the curve in stations divided by the total central angle of degrees
The main answer to your question is that the arc definition of the Degree of Curve (D) is defined as the central angle subtended by 100 ft of arc.
This means that as a train travels along a curved track, the degree of curve is based on the angle formed by the 100-foot arc length of the curve. To provide further explanation, the degree of curve is a measurement used in railroad engineering to determine the amount of curvature in a section of track. It is important because it affects train speeds, lateral forces on the rails, and overall safety. The central angle subtended by 100 ft of arc is used as a standard measurement for the degree of curve because it allows for consistent and accurate calculations across different curves. The other answer options (central angle subtended by 100 ft of chord, central angle subtended by 50 ft of chord, total arc length of the curve in stations divided by the total central angle of degrees) are not correct definitions of the degree of curve and may lead to incorrect calculations.
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Convert 1.5 days to s
Convert 5.2 ft to m
Convert 3600 s to hr
Convert 10.2 m to ft
Convert 305 g to kg
Convert 180 pm to m
Convert 73 kg to g
Convert 1,366 s to min
Convert 86,000 m to km
Please answer these and SHOW ALL WORK, please please please show ALL WORK. Need this done right now please help! Thank you so much!
One minute has 60 seconds, One hour has 60 minutes and one day has 24 hours. Thus, 80 x 60 x 24 = 86,400 seconds in a day.
What is the formula for days to seconds?The information about how many seconds there are in a minute, how many minutes there are in an hour, and how many hours there are in a day can be used to quickly and efficiently answer this question. The next step is to convert 90 minutes into hours and minutes because there are only 60 minutes in an hour: 90 60 = 1.5 hours. A minute has 60 seconds, thus an hour (60 mins) has 3,600 seconds (60 x 60), and if you multiply that number by three hours, you get 10,800 seconds. Assuming that each month has 30 days, a whole year has 360 days. A different European approach (30E+/360) Date A will be modified if it coincides with the 31st of a given month.To learn more about days to seconds refer to:
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An object in circular motion moves along____________path
Answer:
Circular path
Explanation:
hope it helps you...
a herd of deer would be]
Community
Ecosystem
Individual
Population
A herd of deer would be a population (in this case, the individual is the deer).
What is a population?A population is a group of individuals of the same species living in a particular geographic region.
Moreover, a community is a group of populations living together in a particular ecosystem.
In conclusion, a herd of deer would be a population (in this case, the individual is the deer).
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Marine magnetic anomalies result when sea-floor spreading occurs at the same time as ___
Marine magnetic anomalies result when sea-floor spreading occurs at the same time as the Earth's magnetic field reverses polarity.
Marine magnetic anomalies result when sea-floor spreading occurs at the same time as the Earth's magnetic field reverses polarity. The marine magnetic anomalies are created by basaltic rocks being magnetized in the direction of the Earth's magnetic field as they cool and solidify. As new sea floor is created at the mid-ocean ridge, it records the polarity of the geomagnetic field at the time of its formation and preserves it in the rocks as a stripe of either normal or reversed polarity. By measuring the magnetic intensity of the rocks at various locations on either side of a mid-ocean ridge, it is possible to map out the pattern of magnetic stripes and, hence, the history of magnetic reversals.
Marine magnetic anomalies result when sea-floor spreading occurs at the same time as the Earth's magnetic field reverses polarity. Marine magnetic anomalies result from the changes in the earth's magnetic field's polarity, as new rocks are formed at the mid-ocean ridge. As the rocks cool, they become magnetized and record the polarity of the magnetic field at the time of their formation.
The Earth's magnetic field can have either a normal or reversed polarity, which is frequently reversed. When sea-floor spreading occurs, and the rocks cool and become magnetized, this produces marine magnetic anomalies. The resulting marine magnetic anomalies are a result of the Earth's magnetic field reversing polarity while sea-floor spreading is happening. The creation of new rocks at the mid-ocean ridge is responsible for the polarity of the geomagnetic field at the time of its formation being recorded and preserved. The pattern of magnetic stripes can be used to map out the history of magnetic reversals by measuring the magnetic intensity of the rocks on either side of the mid-ocean ridge. Therefore, marine magnetic anomalies result when sea-floor spreading occurs at the same time as the Earth's magnetic field reverses polarity.
Marine magnetic anomalies result when sea-floor spreading occurs at the same time as the Earth's magnetic field reverses polarity. Marine magnetic anomalies are a result of the Earth's magnetic field's polarity reversing, which occurs when rocks are formed at the mid-ocean ridge. The polarity of the geomagnetic field at the time of its formation is recorded and preserved in the rocks as new sea floor is created at the mid-ocean ridge. Mapping out the history of magnetic reversals is possible by measuring the magnetic intensity of the rocks on either side of the mid-ocean ridge.
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the vertical distance between atc and avc reflects:
c) average fixed cost.This implies that in the case of ATC and AVC first both the cost decreases reaches the lowest point and then increases. AFC (average fixed cost) curve is always decreasing, because the average cost remains constant.
Why does the vertical gap shrink as output rises between ATC and AVC?
As output rises, the separation between the AC and AVC curves tends to decrease. This is due to the fact that as output rises, the AC's AVC component tends to grow while its AFC component tends to shrink.
What does the vertical distance between ATC and AVC curve represent?
AFC = ATC - AVC where AFC = Average fixed cost, ATC = Average total cost and AVC = Average variable cost. Therefore, the vertical distance between ATC and AVC is the AFC.
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What is the proper unit for gravitational potential energy?Question 16 options:gravitonsjoulesnewtonsmeters
Answer:
Joules
Explanation:
The unit for Energy is Joules, which is equal to kg m²/s².
The gravitational potential energy is calculated as:
\(Ep=\text{mgh}\)Where m is mass (kg), g is gravity (m/s²) and h is the height (m). So, the unit of the potential energy is:
\(kg\cdot\frac{m}{s^2}\cdot m=kg\cdot\frac{m^2}{s^2}=\text{Joules}\)Therefore, the answer is joules.
A 5.5 Kg rock falling in air experience a force due to air resistance of 50N. What is the acceleration
Answer:
F1 = ma = 5.5 kg * 10 m/s² = 55 N (force acts downwards)
F2 = - 50 N (force acts upwards)
net force = 5 N (downwards)
F = ma
a = F/m
a = 5 / 5.5
a = 0.91 m/s²
Explanation:
Since the object is falling downwards, the air resistance acts upwards. We also have a force acting downwards since the rock experiences gravitational acceleration (the value of g above is 10 m/s² for the sake of easier calculation but you can also set it to be 9.81 m/s² which is the more accurate value). Since the air resistance and force due to gravity are acting in opposite directions and force is a vector, we have to put a minus in front of F1 or F2 (it doesn't matter which direction you chose to be the positive one) . Then we calculate the net force, aka the difference between F1 and F2. Finally, knowing the force and the mass, we can calculate the acceleration.
Explain how pushing a box can be both applied force and normal force
Answer:
pushing a box can be both of them because u have to put force into pushing it and also the normal force punches up on the system to support its weight
Two spheres A and B are placed in the arrangement shown below.
(a) If mA = 2m and mB = 7m, where on the dashed line should a third sphere C of mass 7m be placed so that the net force on it is zero? (Select 1)
-between A and B, closer to B
-at the midpoint between A and B
-to the left of B
-to the right of A
-between A and B, closer to A
(b) If the distance between the two spheres A and B is 500 cm, find the location for the third sphere C so that the net force on it is zero.
a. The third sphere must be placed between A and B, closer to A.
b. the third sphere must be placed at 175 cm from the first sphere.
a. If mA = 2m and mB = 7m, where on the dashed line should a third sphere C of mass 7m be placed so that the net force on it is zero?
Since
mA = 2 kg,mB = 7 kg and mC = 7kg,Using Newton's law of universal gravitation, the net force on the first sphere on the third sphere is F = mAmC/x² where x = distance between sphere C and A
Also, the Force of attraction between there second sphere and the third sphere is F' = mBmC/(R - x)² where R = distance between mA and mB and x = distance between mA and mC.
Since the net force must be zero, then
F = F'
mAmC/x² = mBmC/(R - x)²
So, (R - x)²/x² = mB/mC/mAmC
(R - x)²/x² = mB/mA
Substituting the values of mA and mB into the equation, we have
(R - x)²/x² = 7/2
(R - x)²/x² = 3.5
(R - x)/x = √3.5
(R - x)/x = 1.87
R - x = 1.87x
R = x + 1.87x
R = 2.87x
x = R/2.87
x = 0.35R
Since x = 0.35R, the third sphere must be placed between A and B, closer to A.
b. If the distance between the two spheres A and B is 500 cm, find the location for the third sphere C so that the net force on it is zero.Since the position of the third sphere is
x = 0.35R and R = 500 cmSo, x = 0.35 × 500 cm
x = 175 cm
So, the third sphere must be placed at 175 cm from the first sphere.
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As global population ______
a.) increases b.) decreases
food production must _____
a.) increase b.) decrease
Answer:
As global population a.) increases food production must a.) increase.
Example:
More people means more food must be produced.
According to these data, which type of animal is most likely to hear
sounds with frequencies of 10 hertz?
A Bat
B Dog
C Grasshopper D Human
C
becuz grasshopper can hear between 12-20kHz
Classify each planet as an inner planet or an outer planet.
Planet A has 67 moons, and
major parts of its atmosphere
are hydrogen and helium.
Planet B has rings but
not much atmosphere.
Planet C has no moons but
has high volcanic activity
Known as the red planet, planet
D has high amounts of carbon
dioxide in its atmosphere and
has two moons.
Planet E has a thin layer of
atmosphere but no moons due
to the effects of the Sun’s gravity.
Planet F has 27 moons, and its
atmosphere is mostly composed
of hydrogen, helium, and methane.
Planets A, B and F are the outer planets.
Planets C, D and E are the inner planets .
What are outer and inner planets ?
Outer planets: These are four in number which are Jupiter, Saturn, Uranus and Neptune. The atmosphere of these planets are mainly made up from hydrogen and helium. These planets have many number of moons around them and they all have ring systems.
Inner planets: These are four in number which are Mercury, Venus, Earth and Mars. The atmosphere of these planets are made up from mixture of gases. Main gases are nitrogen and carbon dioxide. These planets have maximum moons of 2 around them and they does not have ring systems.
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Select the correct answer.
A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom
of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Glven: g=-9.81 meters/second?
A.22.5 meters
B.50.7 meters
C.100 meters
D.110 meters
E.152.45 meters
Answer:
A
Explanation:
Givens
d = 100 meters plus the depth of the well
d = 100 + x where x is the depth of the well.
vi = 0 m/s The object is dropped. It was not thrown.
t = 5 seconds
a = 9.81 m/s^2
formula
d = vi*t + 1/2 a t^2
solution
100 + x = 0 + 1/2 * 9.81 * 5^2
100 + x = 122.625 Subtract 100 from both sides
x = 122.625 - 100
x = 22.6 m
The well is 22.6 meters deep.
If a car moving at a steady speed rounds a corner at 60 km/h, does it maintain a constant speed? Maintain a constant velocity? Defend your answers. Match the words in the left column to the appropriate blanks in the sentences on the right 1. The ______ is constant and the ______ changes 2. Thus, the car ______ a constant speed and it a ______ a constant velocity - does not maintain - distance - instantaneous speed
- maintains - direction of motion
The speed is constant and the direction of motion changes.
Thus, the car maintains a constant speed and it does not maintain a constant velocity - the instantaneous speed varies as it goes around the corner due to the change in direction of motion.
What happens to the car's velocity when it rounds a corner?When a car rounds a corner at a steady speed, it changes its direction of motion, and therefore, its velocity changes as well. Velocity is a vector quantity that takes into account both the speed and direction of an object's motion. Since the direction changes, the velocity changes as well. However, if the car maintains the same speed throughout the turn, then the speed remains constant. Speed is a scalar quantity that only takes into account the magnitude of an object's motion, and it is measured as the distance traveled per unit of time.
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(b)Paulina and Mary walking starting at the door of their classroom, they walk 3meters South. They make a right-hand tumn and walk 17meters West. They turn right and again walk 24meters north. They turn left and walk 38meters. What is the magnitude of their overall displacement?
The magnitude of their overall displacement is approximately 29.7 meters.
To find the magnitude of their overall displacement, we need to find the net displacement, which is the straight-line distance from their starting point to their final point.
We can use the Pythagorean theorem to find the net displacement. Let's break down their movements in terms of their x and y components:
Moving 3 meters South gives us a displacement of -3 meters in the y direction.
Turning right and walking 17 meters West gives us a displacement of -17 meters in the x direction.
Turning right again and walking 24 meters North gives us a displacement of +24 meters in the y direction.
Turning left and walking 38 meters East gives us a displacement of +38 meters in the x direction.
To find the net displacement, we can add up the x and y components separately:
Net x displacement = -17m + 38m = 21m to the right (east)
Net y displacement = -3m + 24m = 21m to the north
Using the Pythagorean theorem, we can find the magnitude of the net displacement:
Magnitude of net displacement = sqrt(21² + 21²) = sqrt(882) ≈ 29.7 meters
Therefore, the magnitude of their overall displacement is approximately 29.7 meters.
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the liquid pressure varies with depth why
Explanation:
Hey, there!
The liquid pressure varies with depth because liquid pressure is directly proportional to the depth of liquid from the free surface of the liquid. so, more the depth more the pressure and less the depth less the pressure.
Hope it helps...
The answer is -7m, but I don’t know how that’s the answer. Can anyone explain?
Explanation:
At first it is in 14m position but position doesn't matter in displacement, similar case for time taken.
So at first it travels 6m in positive direction.
So displacement= 6m
Then it travels 13 in opposite or negative direction.
So displacement = 6 -13 m = -7 m
Hope it helps ya
You're standing in the lobby of a huge building.
You go up 6 floors.
You stop and catch your breath.
You go down 13 floors.
Where do you end up ?
choose the correct realistic problem for which this is the correct equation. choose the correct realistic problem for which this is the correct equation. at what distance along the axis of a charged disk is the electric field strength double its value at the center of the disk? give your answer in terms of the disk's radius r . at what distance along the axis of a charged disk is the electric field strength half its value at the center of the disk? give your answer in terms of the disk's radius r . at what distance along the axis of a charged square is the electric field strength double its value at the center of the square? give your answer in terms of the square's side r . at what distance along the axis of a charged square is the electric field strength half its value at the center of the square? give your answer in terms of the square's side r .
The correct realistic problem for the given equation is problem 1 in which the electric field strength of the disc is half its value at the center of the disk.
We know that,
Electric field of a charged disc at a distance along its axis is given by,
E = σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) )
Electric field at the centre of a charged disc is given by,
\(E_{c}\) = σ / 2 ε ( Since at centre, x = 0 )
Distance along the axis of a charged disk, where electric field strength's value is half its value at the center of the disk.
\(E_{x}\) = \(E_{c}\) / 2
σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) ) = ( σ / 2 ε ) / 2
x / √ ( \(x^{2}\) + \(r^{2}\) ) = 1 / 2
4 \(x^{2}\) = \(x^{2}\) + \(r^{2}\)
3 \(x^{2}\) = \(r^{2}\)
x = r / √ 3 ,which is the correct distance, when magnitude is half its value from centre.
Electric field is a field that surrounds electrically charged particles that exerts force on other charged particles in the field.
Therefore, the given equation is suitable for Electric field of a charged disc at a distance along its axis where electric field strength's value is half its value at the center of the disk.
The given question is incomplete. The completed question is
You are given the following equation to solve a problem:
σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) ) = \(E_{c}\) = σ / 2 ε
Choose the most realistic problem for which this could be the correct equation.
1 ) At what distance along the axis of a charged disk is the electric field strength half its value at the center of the disk? Give your answer in terms of the disk's radius R.
2 ) At what distance along the axis of a charged disk is the electric field strength double its value at the center of the disk? Give your answer in terms of the disk's radius R.
3 ) At what distance along the axis of a charged square is the electric field strength double its value at the center of the square? Give your answer in terms of the square's side R.
4 ) At what distance along the axis of a charged square is the electric field strength half its value at the center of the square? Give your answer in terms of the square's side R.
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23. Describe the objects or materials that
vibrated to produce three of the sounds
10 you've heard today
Answer: 1. flushing the toilet,
2. oil popping in a pan,
3. the clicking of a mouse on a computer,
Explanation: Lu-.v u
A soil with modest CEC of 15 cmol(+)/kg soil has a pH of 6.0. If you took 100 pounds of soil and mixed it with 100 pounds of KCl, the resulting soil would: have a pH near 7.0 have a pH less than 6 have a pH remaining at 6.0 be a moderately alkaline soil (pH 7.5 to 8.5) be calcareous
When you mix 100 pounds of soil with 100 pounds of KCl, the resulting soil would have a pH near 7.0.
This is because KCl is a neutral salt and does not affect the pH of the soil. The modest CEC of the soil means that it has a relatively low capacity to retain positively charged ions such as K+. Therefore, adding KCl would not significantly affect the pH of the soil. The resulting soil would have a similar pH to the original soil, but it may have a slightly higher pH due to the dilution effect of adding more material. However, the pH increase would be minimal and would not make the soil moderately alkaline (pH 7.5 to 8.5) or calcareous.
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Why does earth have so little carbon dioxide in its atmosphere compared to venus?.
Compared to Venus, Earth's volcanoes produced significantly less carbon dioxide gas. Carbon dioxide was originally abundant on Earth, but it was lost to space during the violent bombardment that occurred early in the history of our solar system.
Everything boils down to water. Although there are large oceans of liquid water on Earth, Venus and Mars' atmospheres are predicted to be dominated by carbon dioxide. Since carbon dioxide is easily dissolved in water, our oceans absorbed a large portion of the atmospheric CO2, leaving an ammonia-dominated environment. Evidently, Venus is close enough to the Sun that the small amount of carbon dioxide in its early atmosphere, which was similar to Earth's, led the surface to warm and release additional carbon dioxide into the atmosphere.
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Calculate the frequency of an X-ray with a wavelength of 5.5•10-11 meters
Answer:
55
Explanation:
because the formula of frequency=wavelength × distance
Big sound is heard in bathroom than in a living room
Answer
That doesn't make any sense.
Explanation:
What is molasses?
dye
sugar
brown candy
brown syrup
I need help fast please I will give you extra points
Answer: Brown syrup
Explanation:
Answer:
syrup
Explanation:
Answer all these and i'll mark brainliest.
State the basic assumptions of kinetic theory
I SWEAR IF ANOTHER BOT SENDS ME A "LiNk To ThE aNsWeR" I WILL COMMIT ARSON ON BRAINLY
Answer:
i got you there
Explanation:
the kinetic theory is that what ever that is in motion stays in motion
A pressure of 7x10^5N/m is applied to all surfaces of a copper cube (of sides 25 cm) what is the fractional change in volume of a cube? ( for copper B= 14x10^10N/m)
Answer:
The correct solution is "\(5\times 10^{-4}\) %".
Explanation:
The given values are:
Pressure,
\(\Delta P=7\times 10^5 \ N/m\)
for copper,
\(B=14\times 10^{10} \ N/m\)
As we know,
The Bulk Modulus (B) = \(\frac{\Delta P}{-\frac{\Delta V}{V} }\)
or,
The decrease in volume will be:
= \((\frac{\Delta V}{V})\times 100 \ percent\)
then,
= \(\frac{\Delta P}{B}\times 100 \ percent\)
On putting the values, we get
= \(\frac{7\times 10^5}{14\times 10^{10}}\times 100 \ percent\)
= \(5\times 10^{-4} \ percent\)
a spoon can appear broken in a glass of water due to the wave interaction known as
The wave interaction that can cause a spoon to appear broken in a glass of water is called refraction.
Refraction occurs when a wave, such as light, passes from one medium to another with a different density or refractive index. When light waves travel from air into water, for example, they undergo a change in direction due to the change in speed caused by the difference in optical properties between the two mediums.
In the case of the spoon in a glass of water, the light waves coming from the spoon encounter the air-water interface. As they pass from air into water, they undergo refraction, causing a change in their direction. This change in direction can create an optical illusion where the spoon appears to be bent or broken at the water's surface.
This phenomenon is a result of the bending of light rays as they pass through different mediums with different refractive indices, and it is a common example of how refraction can distort the perception of objects when viewed through different mediums.
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b. The silica cylinder of a radiant wall heater is 0.6 m long
and has a radius 6 mm. If it is rated at 1.5 kw estimate
its temperature when operating. [The Stefan constant,
6=6 x 10-8 wm-2-4)
Ans: 1025 K
So, If the silica cyliner of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K
To estimate the operating temperature of the radiant wall heater, we need to use the equation for power radiated by the radiant wall heater.
Power radiated by the radiant wall heaterThe power radiated by the radiant wall heater is given by P = εσAT⁴ where
ε = emissivity = 1 (since we are not given), σ = Stefan-Boltzmann constant = 6 × 10⁻⁸ W/m²-K⁴, A = surface area of cylindrical wall heater = 2πrh where r = radius of wall heater = 6 mm = 6 × 10⁻³ m and h = length of heater = 0.6 m, and T = temperature of heaterSince P = εσAT⁴
P = εσ(2πrh)T⁴
Making T subject of the formula, we have
Temperature of heaterT = ⁴√[P/εσ(2πrh)]
Since P = 1.5 kW = 1.5 × 10³ W
Substituting the values of the variables into the equation, we have
T = ⁴√[P/εσ(2πrh)]
T = ⁴√[1.5 × 10³ W/(1 × 6 × 10⁻⁸ W/m²-K⁴ × 2π × 6 × 10⁻³ m × 0.6 m)]
T = ⁴√[1.5 × 10³ W/(43.2π × 10⁻¹¹ W/K⁴)]
T = ⁴√[1.5 × 10³ W/135.72 × 10⁻¹¹ W/K⁴)]
T = ⁴√[0.01105 × 10¹⁴ K⁴)]
T = ⁴√[1.105 × 10¹² K⁴)]
T = 1.0253 × 10³ K
T = 1025.3 K
So, If the silica cylinder of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K
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