1) What is the distance between (4.3)
and (3,-2)?

The minimum profit occurs at L = 0, where Q = 0.

To find the value of L that maximizes the profit Q = L²\(e^{(0.01L)\).

We need to differentiate Q with respect to L and find the critical points where the derivative equals zero.

Then we can determine whether each critical point is a maximum or a minimum by examining the second derivative.

Testing for critical points:Q = L²\(e^{(0.01L)\)

Q' = \(2Le^{(0.01L)\) + \(0.01 L^2e^{(0.01L)\)

= 0(2L + 0.01L²) \(e^{(0.01L)\)

= 0L (critical point) or 200 \(e^{(0.01L)\)

= 0 (extraneous, ignore)

2L + 0.01L² = 0L(2 + 0.01L) = 0L = 0 or L = -200 (extraneous, ignore)

The only critical point is at L = 0.

Testing for maximum or minimum:Q'' = \(2e^{(0.01L)\) + 0.02Le^(0.01L) + 0.0001L²\(e^{(0.01L)Q''(0)\)

= \(2e^{(0)\) = 2Since Q''(0) > 0,

The critical point at L = 0 is a minimum.

Therefore, there is no value of L that maximizes the profit.

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The values of L that will maximize the profit are 0 and -200

From the question, we have the following parameters that can be used in our computation:

\(Q = L\²e^{0.01L\)

Differentiate the function

So, we have

\(Q' = \frac{L \cdot (L + 200) \cdot e^{0.01L}}{100}\)

Set the equation to 0

\(\frac{L \cdot (L + 200) \cdot e^{0.01L}}{100} = 0\)

Cross multiply

\(L \cdot (L + 200) \cdot e^{0.01L} =0\)

When expanded, we have

L = 0, L + 200 = 0 and \(e^{0.01L} =0\)

When solved for L, we have

L = 0 and L = -200

Hence, the values of L are 0 and -200

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Answer: 3/4

Step-by-step explanation:

There are 4 suits (Clubs, Hearts, Diamonds, and Spades) and there are 13 cards in each suit. This means, there are 13 possible club cards to pick from the 52 card deck.

But it is asking for, "not a club".

Which means, we have to find out the probability of Roger not picking the club card.

So we have to find out the possible cards to pick which are not club.

We can simply do :

52-13 = 39

Now there are 39 cards which are not a club, so there are 39 different possibilities.

We can simply make it a fraction =

39/52 .

Now that we have made it a fraction, we can simplify it.

Which makes it :

3/4

So the answer is 3/4.

Answer:

b. no autocorrelation.

Step-by-step explanation:

The Durbin-Watson test assumes that

H0:ρ=0

HA:ρ≠0

p=0 is a statement for the null hypothesis that assumes that the error term in one period is not correlated to the error term in the previous period.

The Durbin-Watson test is used in regression analysis to test for autocorrelation. The results from the test would always range from 0 to 4. A value of less than 2.0 indicates positive autocorrelation. A value of 2.0 indicates no autocorrelation, and a value of 2.0 to 4.0 indicates negative autocorrelation.

The average rate of change of the function over the interval is 4

From the question, we have the following parameters that can be used in our computation:

y = 4x + 1

The interval is given as

[-1, 1)

The function is a linear function

This means that it has a constant average rate of change

From y = 4x + 1, we have

Rate = 4

Hence, the rate is 4

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Answer:

I think it would be 70mi/h if u need explanation tell me

The item most likely to weigh 2 kilograms is a roast chicken.

The size, breed, and any other ingredients or stuffing used can all affect the weight of a roast chicken. Weights of roast chickens can range from petite ones weighing less than 1 kilogram to larger ones weighing more than 2 kilograms.

The other things that we have there would either weigh less than 2 Kg such as a tea bag or much more than 2 Kg such as a horse. The egg and the tea a very light and would be less than 2 Kg in weight while the bag and the horse would be above 2 Kg in weight.

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Answer:

Answer:

it's 600

Step-by-step explanation:

that's not an option there but...

10% of 800 is 80

5% of 800 is 40

80 × 7 = 560

560 + 40 = 600

Answer:

sadddddddddddddddddd

Step-by-step explanation:

jugkhvvvvvvvvvvebannabadjguy8uegksmbn iyah

Answer:

Assuming both people are pulling in the same direction, the net force on the car is, according to Newton's second law,

600 N + 800 N - 1200 N = (2250 kg) a

Solve for the acceleration a :

200 N = (2250 kg) a

a = (200 N) / (2250 kg)

a ≈ 0.0889 m/s/s

Step-by-step explanation: I hope this helps!

Answer:

10x

Step-by-step explanation:

Answer:

10 x

Step-by-step explanation:

I think it's the answer

Answer:

B

Step-by-step explanation:

Y=mx=b

m= slope

b= y- intercept

x&y are variables

Case 1: a = 0; b = 0 --> Real Number

Case 2: a = 0; b ≠ 0 --> Non-Real Complex Number

Case 3: a ≠ 0; b = 0 --> Real Number

Case 4: a ≠ 0; b ≠ 0 --> Non-Real Complex Number

For each case, we can determine whether the expression a + bi represents a real number or a non-real complex number based on the values of a and b.

Case 1: a = 0; b = 0

In this case, both a and b are zero. The expression a + bi simplifies to 0 + 0i, which is equal to 0. Therefore, the expression represents a real number.

Case 2: a = 0; b ≠ 0

Here, a is zero, but b is nonzero. The expression a + bi becomes 0 + bi, where b is a nonzero real number multiplied by the imaginary unit i. Since the expression contains a nonzero imaginary part, it represents a non-real complex number.

Case 3: a ≠ 0; b = 0

In this case, a is nonzero, but b is zero. The expression a + bi simplifies to a + 0i, which is equal to a. As there is no imaginary part in the expression, it represents a real number.

Case 4: a ≠ 0; b ≠ 0

Here, both a and b are nonzero. The expression a + bi contains both a real part (a) and an imaginary part (bi). Thus, it represents a non-real complex number.

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Null hypothesis: The mean number of points scored by the taller team is not significantly different from the population mean of 72.

Alternative hypothesis: The mean number of points scored by the taller team is significantly greater than the population mean of 72.

Since the population variance is unknown, we will use a t-test. The degrees of freedom for this test will be 9 (n-1), where n is the sample size of the taller team (10).

Using an alpha level of 0.05 and 9 degrees of freedom, the critical t-value is 1.833.

To calculate the test statistic, we first need to find the sample mean and standard deviation of the taller team's scores. The sample mean is 82, and the sample standard deviation is 9.89. Using these values, we can calculate the t-value:

t = (82-72) / (9.89 / sqrt(10)) = 3.19

Since the calculated t-value (3.19) is greater than the critical t-value (1.833), we reject the null hypothesis and conclude that there is a significant difference between the mean number of points scored by the taller team and the population mean of 72. The coach can therefore conclude that having a taller team does result in a greater number of points scored.

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Answer:

no

Step-by-step explanation:

its just set up different

Answer:

No

Step-by-step explanation:

Commutative property of addition

Answer:

D

Step-by-step explanation:

3 | 1   5   - 8   6

   ↓   3    24   48

   ----------------------

    1   8   16    54 ← Remainder

Answer:

the equation y=mx+b

The y intercept is the point on a line that passes through the y line.

To solve the y intercept, solve y=mx+b.

m being slope

y being a y point

x being a x point

and b being y intercept.

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

Answer:

c) f(x) = (4ln(x²))/(e ²)

   g(x) = e ^ ((e ² * x)/8)

Step-by-step explanation:

Part to part ratio

For 2 oranges and five bananas

2oranges:5bananas(2:5)

Part to whole ratio

2oranges:7pieces of fruit(2:7)

5bananas:7pieces of fruit (5:7)

All the best!

Answer:

  a)  a = 5500

  b)  r = 0.92

  c)  63.2%

Step-by-step explanation:

You want various values related to the exponential decrease in the number of living trees from 5500 to 5060 between 2018 and 2019, and you want the percentage decrease to 2030 at the same rate.

The function ...

  N = a·r^t

has an initial value of 'a' when t=0. The problem statement tells you that is 5500.

  a = 5500

The value of r is the ratio of the values of N for t=1 and t=0:

  r = (a·r^1)/(a·r^0) = 5060/5500 = 23/25

  r = 0.92

The fraction still alive after 12 years is predicted to be ...

  0.92^12 ≈ 0.3677

So, the percentage decrease is ...

  (1 -0.3677) × 100% ≈ 63.2%

The predicted percentage decrease in living trees is 63.2% by 2030.

Answer: Half of them are even and half of them are odd.

Step-by-step explanation:

The even numbers are 6, 12, 18, 24, and 30. An even number is defined as a number that is divisible by 2, meaning it has no remainder when divided by 2. For example, 6 divided by 2 equals 3 with no remainder, so 6 is even.

The odd numbers are 3, 9, 15, 21, and 27. An odd number is defined as a number that is not divisible by 2, meaning it has a remainder of 1 when divided by 2. For example, 9 divided by 2 equals 4 with a remainder of 1, so 9 is odd.

Therefore, out of the given numbers, half of them are even and half of them are odd.

________________________________________________________

Answer:

43

133

Step-by-step explanation:

Complementary means that the two angles added together equal 90

90 - 47 = 43

Supplement means that the two angels added together equal 180

180 -47 = 133

Answer:

169

Step-by-step explanation:

Perimeter of a rectangle= 2(length+breath)

2(18 + 8)

2(26)

52.

A square has four equal sides.

The length will be determined by dividing 52 by 4

\(52 \div 4 = 13\)

The length is 13.

Since the area of a square is

\( {l}^{2} = {13}^{2} \)

L is length.

The answer is

\( {169}^{2} \)

After 18 years, the investment compounded periodically (quarterly) will be worth $1,230.23 more than the investment compounded annually.

Compounded interest refers to the interest system that charges interest on both principal and accumulated interest.

The period of compounding in a year determines the worth of the future value.

The future value can be ascertained using an online finance calculator as follows:

Interest periods: = 4 times yearly (Quarterly)

Principal = $5,000

Annual interest rate = 9%

Number of years: 18

N (# of periods) = 72 quarters (18 years x 4)

I/Y (Interest per year) = 9%

PV (Present Value) = $5,000

PMT (Periodic Payment) = $0

Results:

Future Value (FV) = $24,815.83

Total Interest = $19,815.83

Interest periods: = Annually

N (# of periods) = 18 years

I/Y (Interest per year) = 9%

PV (Present Value) = $5,000

PMT (Periodic Payment) = $0

Results:

Future Value (FV) = $23,585.60

Total Interest = $18,585.60

Difference in Future Values $1,230.23 ($24,815.83 - $23,585.60)

Thus, an investment compounded periodically earns more than an investment compounded annually.

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STEP - BY - STEP EXPLANATION

What to find?

The rate of commission.

Given:

To solve, we will follow the steps below:

Step 1

Define the formula that can be use in solving the given problem.

From the question;

amount earned = $6300 and total amount = $210000

Step 2

Substitute the values into the formula and simplify.

ANSWER

The rate of commission is 3 %

Answer:

Step-by-step explanation:

To find the equation for the nth term in the sequence, we need to determine the pattern or rule that generates the sequence.

From the given information, we can see that the sequence is not arithmetic because the differences between consecutive terms are not constant. Instead, the sequence appears to be quadratic because the second difference between consecutive terms is constant.

Using the given values of a₁, a₃, and a₅, we can find the first few differences:

a₃ - a₁ = 4 - (-6) = 10

a₅ - a₃ = 14 - 4 = 10

So, the first difference is 10, which indicates a linear term in the equation for an. We can now use the given value of a₁ and the first difference to find the constant term in the quadratic equation. Let d be the common difference, then we have:

a₂ = a₁ + d = -6 + 10 = 4

a₄ = a₃ + d = 4 + 10 = 14

a₆ = a₅ + d = 14 + 10 = 24 - 1

a₇ = a₆ + d = 24 - 1 + 10 = 33

Now, we can find the second difference between consecutive terms:

a₄ - 2a₃ + a₂ = 14 - 2(4) + (-6) = 0

a₆ - 2a₅ + a₄ = 19 - 2(14) + 4 = -5

a₇ - 2a₆ + a₅ = 33 - 2(19) + 14 = 9

Since the second difference is constant (-5), this confirms that the sequence has a quadratic term in its equation. Let's assume the equation for the nth term is:

an = an² + bn + c

Substituting the values we know, we get three equations:

a₁ = a₁² + b₁ + c --> -6 = c

a₃ = a₃² + b₃ + c --> 4 = 9a + b + c

a₅ = a₅² + b₅ + c --> 14 = 25a + 5b + c

Solving this system of equations, we get:

a = 1/2, b = 19/2, and c = -6

Therefore, the equation for the nth term in the sequence is:

an = (1/2)n² + (19/2)n - 6.