2
.
What is the resulting combination
when h(x) is subtracted from klx) if
h(x)= -X+6 and k(x)=2x-5 ?
1

Answers

Answer 1

Answer:

3x - 11

Step-by-step explanation:

k(x) - h(x)

2x - 5 - (- x + 6) ← distribute parenthesis by - 1

= 2x - 5 + x - 6 ← collect like terms

= 3x - 11


Related Questions

In the number 73.6592104, which digit is in the thousandths place?

Answers

Answer:

In the number 73.6592104,  the 9 is in the thousandths place.

Let me know if this helps!

The population of a town is decreasing at a rate of 3.2% per year. In 2015, there were 14,250 people. What is the first year that the population will be less than 10,000?
А
2026
B
2020
С
2016
D
2025

Answers

The answer is D
you would set up an equation like this
14,250 x .032
this will give you how much the population is decreasing per year. Which is 456 people per year.
You then take 2015 and find the difference between that number and 2025 and do it with all of the other years too.
For example 2025-2015 is 10 years
You then take 10 x 456 to tell you how much the of population you lost in those 10 years. You will then take that number which is 4,560 and do 14,250-4,560 to get 9,650.

A straight line, L, has equation 3y = 5x - 6. Find the gradient of L,​

Answers

Answer:

5/3

Step-by-step explanation:

3y = 5x - 6

y = 5/3x - g

using y = mx + b

gradient = m

gradient = 5/3

Suppose we have a group of 4 girls and 3 boys and we wish to seat them in a row of 7 chairs. In how many ways can the students be seated

Answers

Answer:

5,040 ways

Step-by-step explanation:

Here, we want to find the number of ways they can sit

The total

number here is 3 + 4 = 7

The first person has 7 choices, next has 6 choices and so on

So the total

number of ways will

be :

7! = 5,040 ways

3. describe the pattern of learning math concepts according to siegler.

Answers

According to Siegler, the pattern of learning math concepts involves a gradual development and refinement of strategies. Siegler's theory, known as the overlapping waves model, suggests that learners use multiple strategies simultaneously and gradually shift towards more efficient ones over time. This process allows for a better understanding and application of math concepts, ultimately leading to improved problem-solving skills.

According to Siegler, the pattern of learning math concepts involves a gradual progression from using counting strategies to more efficient and accurate strategies. Children initially rely on counting strategies to solve math problems, such as counting fingers or objects. As they progress, they begin to use more advanced strategies, such as decomposition or mental math, which allow them to solve problems more quickly and accurately. Siegler also emphasizes the importance of practice and repetition in developing math skills and the role of feedback and instruction in promoting learning. Overall, Siegler's theory suggests that children's math skills develop through a combination of innate abilities and environmental factors, including exposure to math concepts and opportunities for practice and instruction in time.

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(H1.01 MC) What is the remainder of 5x³ + 7x +57 over x+2 Show all necessary steps.​

Answers

The remainder of 5x³ + 7x +57 over x+2  is 3.

What is expression?

In mathematics, an expression that incorporates variables, constants, and algebraic operations is known as an algebraic expression (addition, subtraction, etc.). Terms comprise expressions.

Given expressions are 5x³ + 7x +57 and x+2.

Remainder theorem: According to the remainder theorem, the remainder equals f(a) when a polynomial, p(x), is divided by (x - a).

Assume that P(x) = 5x³ + 7x +57.

Equate x + 2 to zero and find the value of x:

x + 2 = 0

x = -2

Putting x = -2 in the polynomial P(x) = 5x³ + 7x +57:

P(-2) = 5(-2)³ + 7(-2) +57

P(-2) = 5(-8) + 7(-2) +57

P(-2) = -40 - 14 +57

P(-2) = 3

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are these two lines parallel , explain or show your reasoning ?

are these two lines parallel , explain or show your reasoning ?

Answers

yes they are parallel lines because they do not meet. they are straight lines

yes, they arent intersecting and they have the same slope

you have one type of chocolate that sells for $1.70/lb and another type of chocolate that sells for $5.40/lb. you would like to have 7.4 lbs of a chocolate mixture that sells for $4.10/lb. how much of each chocolate will you need to obtain the desired mixture?

Answers

You will need approximately 2.66 lbs of the $1.70/lb chocolate and 4.74 lbs of the $5.40/lb chocolate to obtain the desired mixture.

Let x be the number of pounds of the $1.70/lb chocolate and y be the number of pounds of the $5.40/lb chocolate.

Since you want a mixture of 7.4 lbs that sells for $4.10/lb, you can set up the following system of equations:

Equation 1: x + y = 7.4 (to represent the total weight of the mixture)


Equation 2: (1.70x + 5.40y) / 7.4 = 4.10 (to represent the average price per pound)

Now, we can solve this system of equations to find the values of x and y.

First, let's rewrite Equation 2 to eliminate the fraction:

1.70x + 5.40y = 4.10 * 7.4

Next, we can solve the system using any method, such as substitution or elimination. Let's use the elimination method to eliminate the variable x:

Multiply Equation 1 by 1.70 to make the coefficients of x in both equations equal:

1.70 * (x + y) = 1.70 * 7.4
1.70x + 1.70y = 12.58

Now, subtract Equation 2 from the modified Equation 1 to eliminate x:

(1.70x + 1.70y) - (1.70x + 5.40y) = 12.58 - (4.10 * 7.4)
1.70x - 1.70x + 1.70y - 5.40y = 12.58 - 30.14
-3.70y = -17.56

Divide both sides of the equation by -3.70 to solve for y:

y = -17.56 / -3.70
y ≈ 4.74

Now, substitute the value of y back into Equation 1 to solve for x:

x + 4.74 = 7.4
x ≈ 7.4 - 4.74
x ≈ 2.66

Therefore, you will need approximately 2.66 lbs of the $1.70/lb chocolate and 4.74 lbs of the $5.40/lb chocolate to obtain the desired mixture.

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Halp me plass me halp

Halp me plass me halp

Answers

Answer:

\( \sqrt{( - 5 - 10) ^{2} + (3 - ( - 5)) ^{2} } \)

Step-by-step explanation:

I don't know what is the difference between B and D.

But remember the formula of distance:

If M(x1, y1); N(x2, y2),

the distance=

\( \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } \)

I do not get this question: 6b-5b+(-8b)=?

Answers

Answer:

-7b

Step-by-step explanation:

Ok soo you have add the terms.

1b+(-8b)=-7b

Have a good!!

Answer:

-9b

Step-by-step explanation:

i'm assuming this is just combining like terms so if you ignore the (b) you will have

6-5+(-8)

-1+(-8)

-9

then you put back the variable and you get -9b

SOLVE USING ELIMINATION *20 POINTS*


1. 3x - y = 28

3x - y = 14


a. (8,-4)

b. (-7,7)

c. (7,-7)

d. (-4,8)


2. x+ 4y 13

2x + 3y 6


a. (3,5)

b. (-3,4)

C. (4,5)

d. (4,4)


3. 12r-9y 30
6x + 15y = 54


A. x = 4 and y 2

B. x = 2 and y = 4

C. x = 14 and y 2

D. x = 37/7 and y =26/7







4. x + 3/2 y = -3




6/7x + 7y = -8


A. (27/8, -1/4)

B. (9/2, -5)

C. (-3/11, -10/11)

D. (-63 / 40, -19/20)

Answers

1. No answer ( may be due to incorrect question)

2. x = -3

y = 4

3. x= 4

y = 2

4.x = -63/40

y= -19/20

Step 1

Multiply equation 1 by the coefficient of x in equation 2

Multiply equation 2 by the coefficient of x I'm equation 1

(after completing this step you will derive equation 3 and 4 )

Step 2

Subtract equation 4 from equation 3

Step 3

Divide both sides of the equation by the coefficient of y

Step 4

substitute your value for y in equation 1 or 2

(after this you will derive the values of x)

Note : This method is for the Elimination of x

I hope it helps

SOLVE USING ELIMINATION *20 POINTS*1. 3x - y = 28 3x - y = 14a. (8,-4) b. (-7,7)c. (7,-7)d. (-4,8)2.
SOLVE USING ELIMINATION *20 POINTS*1. 3x - y = 28 3x - y = 14a. (8,-4) b. (-7,7)c. (7,-7)d. (-4,8)2.

Answer: A.  X = 11

Step-by-step explanation:

x - 7 = 4

11 - 7 = 4

Divide 8 by 4 and then add 2.
Add 5 and 3 together.
Multiply the two results.

Answers

Answer:

32

Step-by-step explanation:

8 ÷ 4 = 2

2 + 2 = 4

5 + 3 = 8

4 × 8 = 32

Answer:

8 divdie 4 = 2 + 2 = 4

5 + 3 =8

4 x 8 = 32

Step-by-step explanation:

Hope this helped

Which theorem has two sides and a non-included angle?

Answers

Angle-Angle-Side (AAS) Theorem has two sides and a non-included angle.

What is Angle-Angle-Side (AAS) Theorem?The triangles are congruent if two angles and a non-included side in one triangle are congruent with two angles and the corresponding non-included side in another triangle, according to the Angle-Angle-Side (AAS) Congruence Theorem.The side-angle-side (SAS) theorem is the first such theorem. The triangles are congruent if two sides and the included angle of one triangle are equivalent to two sides and the included angle of another triangle.When two angles and an unincluded side of one triangle are equal to two angles and the corresponding unincluded side of the other triangle, two triangles are said to be congruent (AAS=AAS).

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what are the zeros of this function. f(x)=x^2+3x-40

Answers

By solving the given equation f(x) = \(x^{2} +3x-40\), the zeroes are -3 and 5.

To solve the given equation we have to do the factorization.

What is factorization: Factorization is the method of writing numbers as the product of their factors or divisors.  In other words, we can say finding what to multiply together to get an expression.

To do the factorization, we have to follow the steps as shown below:

 \(x^{2} +3x-40\) \(= 0\)

\(-40 = 8 * -5\\\)                        [ multiplication of 8 and -5 is -40]

\(x^{2}+8x-5x -40\) \(= 0\)

\(x(x+8) -5(x+8)\) \(= 0\)

\((x-5)(x+8)\) \(= 0\)

\(x = 5\)   and  \(x = -8\)              [ The roots or zeroes]

From the above solution, we can conclude that the zeros of the given function \(x^{2} +3x-40\) are 5 and -8.

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Write an equation for a function that has the graph with the shape of y=x^2, but upside-down and shifted left 8 units.

Answers

This equation takes the standard form of the quadratic equation (y = ax^2 + bx + c) where a is negative (-1), indicating that the graph will be upside-down. The term (x + 8) indicates a horizontal shift to the left by 8 units, and squaring this expression gives us the familiar parabolic shape of y = x^2. Finally, the negative sign in front of the parentheses flips the graph over the x-axis.

To clarify, the standard form of a quadratic equation is y = ax^2 + bx + c, where a, b, and c are constants. The quadratic equation typically represents a parabola, which can have different orientations (upward or downward) depending on the coefficient of the x^2 term (a).

In the case of the equation you mentioned, x^2 + 2x - 1 = |x + 2| + 2, it is not a simple quadratic equation. The absolute value function, represented by |x + 2|, introduces a piecewise behavior to the equation. Depending on the value of (x + 2), the expression inside the absolute value function, the equation may have different forms.

To analyze and solve this equation, we need to consider the two cases: when (x + 2) is positive and when it is negative.

When (x + 2) ≥ 0 (or x ≥ -2):

In this case, the absolute value function simplifies to (x + 2), and the equation becomes:

x^2 + 2x - 1 = x + 2 + 2

When (x + 2) < 0 (or x < -2):

In this case, the absolute value function simplifies to -(x + 2), and the equation becomes:

x^2 + 2x - 1 = -(x + 2) + 2

By solving these two cases separately, we can find the possible solutions to the equation.

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123 students each gave 2 cupid to each student in school there's 6 council how many cupid did they evenly make for the 123 student

Answers

Answer:

each made 20.5

Step-by-step explanation:

123/6 = 20.5

steve can paint his greenhouse in four hours working alone; his ten-year-old son can paint the greenhouse alone in nine hours. working together, how long, to the nearest minute, would it take them?

Answers

Working together will take them 2 hours and 46 minutes which is 166 minutes.

What do we mean by equation?A mathematical statement made up of two phrases joined by an equal sign is known as an equation. 3x - 5 = 16 is an example of an equation. We get the value of the variable x as x = 7 after solving this equation.

So,

Consider these work rates in terms of "greenhouses per hour," rather than "hours per greenhouse." Steve's work rate is one-fourth of a greenhouse per hour, while his son is one-ninth of a greenhouse per hour. Now, multiply each rate by the time t to obtain the percentage of the greenhouse that each paints, and add the products to obtain one greenhouse.

The work equation is now:

\(\begin{aligned}&\frac{1}{4} t+\frac{1}{9} t=1 \\&\frac{9}{36} t+\frac{4}{36} t=1 \\&\frac{13}{36} t=1\end{aligned}\\\frac{36}{13} \cdot \frac{13}{36} t=\frac{36}{13} \cdot 1\\t=\frac{36}{13} \mathrm{hrs}\\\frac{36}{13} \cdot 60 \approx 166 \min\)

Therefore, working together will take them 2 hours and 46 minutes which is 166 minutes.

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3. Kwame travelled from Accra to Kumasi. He travelled from 1/3 of the journey by Lorry, 2/5 of the journey by taxi and the rest by train ​

Answers

The fraction of the Journey that Kwame travelled by the train is found to be 4/15.

Let's start by finding the fraction of the journey that Kwame travelled by Lorry and taxi combined,

1/3 + 2/5 = 5/15 + 6/15 = 11/15

This means that Kwame travelled 11/15 of the journey by Lorry and taxi, and the remaining fraction of the journey by train. To find the fraction of the journey that Kwame travelled by train, we can subtract the fraction he travelled by Lorry and taxi combined from 1,

1 - 11/15 = 15/15 - 11/15 = 4/15

Therefore, Kwame travelled 4/15 of the journey by train.

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Complete question - Kwame travelled from Accra to Kumasi. He travelled from 1/3 of the journey by Lorry, 2/5 of the journey by taxi and the rest by train . what fraction of the journey did he travel by train.

A typical person begins to lose consciousness if subjected to accelerations greater than about 5 g(49.0 m/s^2) for more than a few seconds. Suppose a 3.00×10^4−kg manned spaceship's engine has an exhaust speed of 2.50×10^3 m/s. What maximum burn rate ∣ΔM/Δt∣ could the engine reach before the ship's acceleration exceeded 5 g and its human occupants began to lose consciousness?

Answers

The maximum burn rate ∣ΔM/Δt∣ that the engine could reach before the ship's acceleration exceeded 5 g and its human occupants began to lose consciousness is approximately 51.0 kg/s.

Acceleration is directly proportional to the force acting on an object. In simple terms, if the force on an object is greater, then it will undergo more acceleration. However, there are limitations to the acceleration that can be tolerated by the human body. At about 5 g (49.0 m/s2) for more than a few seconds, an average person starts to lose consciousness. Let's use this information to answer the given question.

Let the maximum burn rate |ΔM/Δt| that the engine could reach before the ship's acceleration exceeded 5 g be x.

Let the mass of the spaceship be m and the exhaust speed of the engine be v.

Using the formula for the thrust of a rocket,

T = (mv)e

After substituting the given values into the formula for thrust, we get:

T = (3.00 × 104)(2.50 × 103) = 7.50 × 107 N

Therefore, the acceleration produced by the engine, a is given by the formula below:

F = ma

Therefore,

a = F/m= 7.50 × 107/3.00 × 104= 2.50 × 103 m/s²

The maximum burn rate that the engine could reach before the ship's acceleration exceeded 5 g is equal to the acceleration that would be produced by a maximum burn rate. Therefore,

x = a/5g= 2.50 × 103/(5 × 9.8)≈ 51.0 kg/s

Therefore, the maximum burn rate ∣ΔM/Δt∣ that the engine could reach before the ship's acceleration exceeded 5 g and its human occupants began to lose consciousness is approximately 51.0 kg/s.

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Help ! It's A Math Problem I don't know What to do I am confused

Help ! It's A Math Problem I don't know What to do I am confused

Answers

Answer:

The answer would be the first option or the last option: x + 5 or x - 3

Step-by-step explanation:

Simplify:

             x2 - 25  

Trying to factor by splitting the middle term

1.1     Factoring  x2 - 8x + 15

The first term is,  x2  its coefficient is  1 .

The middle term is,  -8x  its coefficient is  -8 .

The last term, "the constant", is  +15

Step-1 : Multiply the coefficient of the first term by the constant   1 • 15 = 15

Step-2 : Find two factors of  15  whose sum equals the coefficient of the middle term, which is   -8 .

     -15    +    -1    =    -16

     -5    +    -3    =    -8    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -5  and  -3

                    x2 - 5x - 3x - 15

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (x-5)

             Add up the last 2 terms, pulling out common factors :

                   3 • (x-5)

Step-5 : Add up the four terms of step 4 :

                   (x-3)  •  (x-5)

            Which is the desired factorization

Trying to factor as a Difference of Squares:

1.2      Factoring:  x2-25

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 25 is the square of 5

Check :  x2  is the square of  x1

Factorization is :       (x + 5)  •  (x - 5)

Canceling Out :

1.3    Cancel out  (x - 5)  which appears on both sides of the fraction line.

Final result :

 x - 3 /  x + 5

HOPE THIS HELPS! HAVE A WONDERFUL DAY!!! :)

The common factor would be -5
The factors for x^2 - 25 are -5 and 5 (they add up to zero and multiply to -25)
The factors for x^2 - 8x -15 are 3 and -5 (add up to -8 and multiply to -15)

If f(x) and its inverse function, f superscript negative 1 baseline (x), are both plotted on the same coordinate plane, where is their point of intersection? (0, 6) (1, 4) (2, 2) (3, 0)

Answers

The point of intersection for the function is  (2, 2)

Considering to the line passing through the points (0,6) and (3,0)  to be f(x).Therefore the slope intercept of the function is

m = 0-6/3-0 = -2

So, the functions F(x) in the slope-intercept form f(x)= -2x+6  ......1

interchanging the variable x to y and y to  x

=> x =-2y + 6

=> 2y = -x + 6

=> y= -0.5x + 3

let  f⁻¹(x)= y

f⁻¹(x) =-0.5x+3   ......2

Solving the equation  1 and 2, we get

=> -0.5x + 3 = -2x + 6

=> 2x - 0.5x = 6 - 3

=> 1.5x = 3

=> x = 2

Substituting the values of x in the function  we get,

f( x) = -2(2) + 6 = 2

Thus, the outcome is (2,2)

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HELP ME! I WILL MARK U AS THE BRAINLIEST!

HELP ME! I WILL MARK U AS THE BRAINLIEST!

Answers

The area of the quarter circle is 38.4895 cm²

How to find the area of a figure?

The figure above is quarter of a circle. The area of the square can be found as follows:

Therefore,

area of the quarter of the circle = 1 / 4 πr²

where

r = radius

Therefore,

r = 7 cm

area of the quarter of the circle = 1 / 4 × 3.142 × 7²

area of the quarter of the circle = 1 / 4 × 3.142 × 49

area of the quarter of the circle = 1 / 4 × 153.958

area of the quarter of the circle = 153.958 / 4

area of the quarter of the circle = 38.4895

Therefore,

area of quarter of the circle = 38.4895 cm²

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please help I am brianab9968 If u r there babe

please help I am brianab9968 If u r there babe

Answers

Answer:

After simplifying ur ans comes out to be option a

__________ LANs are usually arranged in a star topology with computers wired to central switching circuitry that is incorporated in modern routers.​
a) Mobile
b) Internet
c) ​Ethernet
d) Wireless

Answers

Ethernet LANs are usually arranged in a star topology with computers wired to central switching circuitry that is incorporated in modern routers.

Ethernet is a family of computer networking technologies that is used in LAN, metropolitan area networks (MAN), and wide area networks (WAN). It was first introduced in 1980 by Xerox Corporation, and later standardized by the Institute of Electrical and Electronics Engineers (IEEE) as IEEE 802.3.

Ethernet networks can be implemented in different topologies, such as a bus, star, or mesh topology. However, the most common topology for Ethernet LANs is a star topology, in which computers are wired to a central switching circuitry that is incorporated in modern routers. This allows for efficient communication between the computers on the network.In addition to LANs, Ethernet is also used for other networking applications such as Internet access, wireless networking, and broadband access. Overall, Ethernet is a widely used technology that has become an important component of modern computer networking.

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determine whether the lines shown are interior or exterior tangents

determine whether the lines shown are interior or exterior tangents

Answers

A tangent of two circles is a common internal tangent if the intersection of the tangent and the line segment joining the centers is not empty.

In this case, the lines represent interior tangents

A bag contains twelve marbles, which includes seven red marbles and five blue marbles. Roja reaches into the bag and pulls out four marbles. a) How many different sets of four marbles can be pulled from this bag? b) How many of these sets contain two red marbles and two blue marbles? c) How many of these sets contain all red marbles? d) How many of these sets contain all red marbles or all blue marbles?

Answers

Answer:

a) 495

b) 210

c) 35

d) 40

Step-by-step explanation:

Given a total of 12 marbles.

n = 12

Number of red marbles = 7

Number of blue marbles = 5

a) Number of different sets of 4 marbles that can be made from this bag ?

This is a simple combination problem.

where n = 12 and r = 4.

So, answer will be:

\(_{12}C_4\)

Formula:

\(_{n}C_r = \dfrac{n!}{(n-r)!r!}\)

\(_{12}C_4 = \dfrac{12!}{(8)!4!} = \dfrac{12\times 11\times 10\times 9}{4 \times 3\times 2} =\bold{495}\)

b) Two red and two blue marbles:

The answer will be:

\(_{7}C_2 \times _{5}C_2 = \dfrac{7\times 6}{2} \times \dfrac{5\times 4}{2} =\bold{210}\)

c) all red marbles.(4 chosen out of 7 red and 0 chosen out of 5 blue marbles)

\(_{7}C_4 \times _{5}C_0 = \dfrac{7\times 6\times 5\times 4}{4\times 3\times 2} =\bold{35}\)

d) all red or all blue.(all red marbles plus all blue marbles)

All red marbles:

\(_{7}C_4 \times _{5}C_0 = \dfrac{7\times 6\times 5\times 4}{4\times 3\times 2} \times 1=\bold{35}\)

All blue marbles:

\(_{7}C_0 \times _{5}C_4 = 1 \times \dfrac{5\times 4\times 3\times 2}{4\times 3\times 2} =\bold{5}\)

So, answer is 40.

Determine the maximum average shear stress in pin A of the truss. A horizontal force of P = 40 kN is applied to joint C. Each pin has a diameter of 25 mm and is subjected to double shear. A - C = 1.5 m and A - B = 2 m

Answers

The maximum average shear stress in pin A of the truss is 42.2 MPa.

How to calculate maximum average shear stress

A horizontal force of P = 40 kN is applied to joint C. diameter of each pin, d = 25 mm double shear.

A - C = 1.5 mA - B = 2 mAs the horizontal force of P = 40 kN is applied to joint C, the maximum average shear stress in pin A of the truss is to be determined.

Shear force in AB = Shear force in AC = P/2 = 40/2 = 20 kN

Shear force in AD = 0

Resolving forces horizontally:

RA + RB = 20 ..................... (1)

Resolving forces vertically:

RC = RD = 20 .............................. (2)

Taking moments about joint A:

2RA + 1.5RC = 20 × 1.5 ........... (3)

Substituting values from equations (1) and (2) in equation (3), we get,

RA = 7.5 kN

RB = 12.5 kN

RC = RD = 20 kN

As the pin is subjected to double shear, the maximum average shear stress can be given byτ = 4V/πd²

From the figure, Shear force in AB = Shear force in AC = P/2 = 20 kN

Shear force in AD = 0Maximum shear force in the truss = P = 40 kN∴

Maximum average shear stress in the truss

τ = 4 × 40 × 10³ / π (0.025)²= 80/π MPa= 25.46 MPa

But, the pin is subjected to double shear.

Hence, the maximum average shear stress in pin A of the truss isτ = 2 × 25.46= 42.2 MPa.

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Find the length of segment XY.




a.28



b.21



c.29

d



7

Find the length of segment XY.a.28b.21c.29d7

Answers

Answer:

7

Step-by-step explanation:

Because the parts of the circle are congruent, the segments are as well, we can use that to make an equation then solve it like normal

9x-34=4x+1

-1 on both sides

9x-35=4x

-9x on both sides

-35=-5x

x=7

Given the following proposition:
[(X ⊃ A) • (B ⊃ ∼ Y)] ⊃ [(B ∨ Y) • (A ⊃ X)]

Given that A and B are true and X and Y are false, determine the truth value of Proposition 2A.

a.
True.

b.
False.

Answers

Therefore, the truth value of Proposition 2A is False.

To determine the truth value of Proposition 2A, let's substitute the given truth values for the variables:

A = True

B = True

X = False

Y = False

Now let's evaluate the truth value of each component of the proposition:

(X ⊃ A) • (B ⊃ ∼ Y):

(False ⊃ True) • (True ⊃ ∼ False)

(True ⊃ True) • (True ⊃ True)

True • True

True

(B ∨ Y) • (A ⊃ X):

(True ∨ False) • (True ⊃ False)

True • False

False

[(X ⊃ A) • (B ⊃ ∼ Y)] ⊃ [(B ∨ Y) • (A ⊃ X)]:

True ⊃ False

False

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I need the answer since I’m plain dumb. Ty

I need the answer since Im plain dumb. Ty

Answers

Answer:

A and B

Step-by-step explanation:

The "zeros" of the quadratic equation simply refers to what x equals when q(x) = 0.

Set the equation equal to zero as so: 0 = x^2 - 9, and solve!

9 = x^2

+/- 3 = x, when q(x) = 0.

This means that the two points you are trying to find are (-3, 0) and (3, 0)!

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