4. How do these measurements compare? 2500 meters and 200 grams *

The wavelength of the light is approximately 500 nm. The energy of the photon of light is approximately 6.56 x 10-20 J.

Answer: Question 1:The formula relating wavelength, frequency, and the speed of light is given by:c = fλHere,λ = wavelength, f = frequency, c = speed of lightI. n the problem, frequency is given as 5.98 x 1014 s-1. Therefore, using the formula, the wavelength of light can be calculated as follows:λ = c/f= (3 x 108 m/s)/(5.98 x 1014 s-1)≈ 500 nm

Therefore, the wavelength of the light is approximately 500 nm.

Question 2:The formula relating energy and frequency of light is given by:E = hfwhereE = energy of photonh = Planck's constant = 6.626 x 10-34 J s (Joule seconds)f = frequency of lightIn the problem, the frequency of light is given as 9.89 x 1013 Hz. Therefore, using the formula, the energy of the photon of light can be calculated as follows:E = hf= (6.626 x 10-34 J s) x (9.89 x 1013 Hz)≈ 6.56 x 10-20 J

Therefore, the energy of the photon of light is approximately 6.56 x 10-20 J.

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Answer:

Lichens can be used as air pollution indicators, especially of the concentration of sulphur dioxide in the atmosphere. Lichens are organisms that grow in exposed places such as rocks or tree bark. They need to be very efficient at absorbing water and nutrients to grow there.

Answer:

OCEANOGRAPHY

The two panels initially charged with identifying ocean metrics (physical/chemical and biological) worked together to develop a single table covering physical, chemical, and biological processes. This integration recognizes that the fluid dynamics of the ocean underlie its chemistry and biology and that the three cannot be considered in isolation.

The panels focused on climate metrics that are highly integrated with the impacts of climate change (Table 3-1). For example, the panels proposed a metric for the health of fisheries, which depends in part on the primary productivity of the ocean. In contrast, the GCOS equivalent focuses on ocean productivity as a fundamental indicator.

The panels gave higher priority to metrics that either integrate human impacts (e.g., fisheries) or could have significant impacts on the ecosystem services that provide value to society (e.g., the impacts of harmful algal blooms). Therefore, the ocean metrics are strongly weighted toward the human dimension of ocean processes, not simply the fundamental processes of climate change. The panels then further refined the metrics toward those for which there is significant potential for risk and vulnerability. For example, the panels considered the impacts of climate change (i.e., rising sea level) on the infrastructures of ports and harbors, which are crucial to global trade, but not on coastal recreation.

Many of the proposed indicators focus on emerging issues, as well as on new management and development strategies. In other words, they do not simply recapitulate ongoing indicators. For example, new approaches to management, such as of marine protected areas, should be studied now in order to assess their effectiveness as well as their impacts on ocean ecosystems.

Finally, the ocean panels recognized that many of their metrics are “process based” rather than “place based.” For example, because the location and intensity of fisheries shift over time, we cannot define a set of key places to monitor. Rather, we must ensure that there is ongoing feedback between the systems being observed and the systems observing them. Thus, the ocean indicators are often iterative in nature and should be refined as knowledge improves.

The panels relied on the six criteria to prioritize the metrics. It became clear that metrics could be distinguished based on the strength of their connection to climate processes and to environmental sustainability. As a result, the panels identified three priority levels: (1) high climate, high environmental sustainability; (2) low climate, high environmental sustainability; and (3) low climate, moderate environmental sustainability. The panels chose to not include metrics that have high climate, low environmental sustainability because the special emphasis of the report is on the environmental sustainability connection. As noted earlier, many other reports have addressed traditional climate change indicators.

Two examples will highlight this process. Sea level rise has a direct link to the climate system, and it is significant, dominant, measurable, historical, and well documented. Therefore, it was placed in the high climate, high environmental sustainability category. In comparison, fisheries health is significant, measurable (with varying quality), historical, and well documented, but climate change is not the only (or

The panels considered the following two metrics to be important, but not correlated strongly enough at this time with climate change and environmental sustainability to warrant inclusion in the table: (1) location and extent of offshore energy production and supply including onshore infrastructure, and (2) location and extent of desalination facilities in coastal zones.

The location and extent of offshore energy production and supply could be measured by ocean productivity, high-resolution imagery of energy production infrastructure, seafloor morphology, and habitat imagery of the coastal zone and shoreline. Areas where it would be useful to apply this metric are those that are expected see increased development in the next 5- to 10 years, such as Denmark, the Gulf Coast, and France. Although offshore energy development may not have a strong connection to environmental sustainability and climate change at this time, it may become important in the future as sources of energy that do not depend on fossil fuel are developed. Many of these new sources will likely be located in coastal oceans and may impact ocean ecosystems.

Explanation:

The temperature needs to be raised by about 28.15°C to make the catalyzed reaction 100 times faster.

To calculate the temperature increase required to make the catalyzed reaction 100 times faster, we can apply the Arrhenius equation.

The rate constants at temperatures T1 and T2 are denoted by k1 and k2 respectively, while Ea is the activation energy (98.4 kJ mol-1) and R is the gas constant (8.314 J K-1 mol-1).

Since we want the reaction rate to increase by a factor of 100, we can write the ratio of rate constants as k2/k1 = 100. Rearranging the equation and solving for T2, we get:

\(T_2 = (Ea / R)*{ln(k_2/k_1)}^-^1 + T_1\)

Assuming the room temperature T1 is 298 K, we can plug in the values:

\(T_2 = (98.4 * 10^3 J mol^-^1 / 8.314 J K^-^1 mol^-^1) * {ln(100)}^-^1 + 298 K\\T_2 = 326.3 K\)

To convert T2 to degrees Celsius, we subtract 273.15:

T2 = 326.3 - 273.15 ≈ 53.15°C

Therefore, the temperature needs to be raised by about 28.15°C to make the catalyzed reaction 100 times faster.

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The formal charge on the C in  is 0.

In order to determine the formal charge on the carbon atom in , we need to consider the arrangement of electrons and bonds in the molecule. The Lewis structure for  is one carbon atom (C) bonded to two oxygen atoms (O). In the structure, there is a double bond between the carbon atom and one oxygen atom, while the other oxygen atom is bonded to the carbon atom by a single bond.

To calculate the formal charge on an atom, we use the formula: Formal Charge = Valence Electrons - Lone Pair Electrons - 0.5 * Bonding Electrons.

The carbon atom in  has four valence electrons. In the Lewis structure, the carbon atom is involved in two bonds and has no lone pair electrons. The carbon-oxygen double bond consists of four electrons (two bonding electrons and two lone pair electrons on the oxygen atom). The carbon-oxygen single bond consists of two electrons.

Plugging these values into the formula, we get: Formal Charge = 4 - 0 - 0.5 * (4 + 2) = 4 - 0 - 3 = 1.

Therefore, the formal charge on the carbon atom (C) in  is +1.

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Answer:

.5 moles of glucose are produced

Answer:

2.5 atm

Explanation:

To find the original pressure of the gas, you need to use the Combined Gas Law. The corresponding equation is:

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)

In this equation, "P₁", "V₁", and "T₁" represent the original pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the new pressure, volume, and temperature.

Before you can plug the given values into the equation and solve for "P₁", you need to convert the temperatures from Celsius to Kelvin (°C + 273 = K).

The final answer should have 2 sig figs like the least accurate given value.

P₁ = ? atm                                          P₂ = 2.0 atm

V₁ = 28 L                                           V₂ = 34 L

T₁ = 45°C + 273 = 318 K                   T₂ = 35°C + 273 = 308 K

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)                                            <----- Combined Gas Law

\(\frac{P_1(28L)}{318K}=\frac{(2.0 atm)(34L)}{308K}\)                            <----- Insert values

\(\frac{P_1(28L)}{318K}=0.2208\frac{atm*L}{K}\)                            <----- Simplify right side

\({P_1(28L)}=70.21atm*L\)                         <----- Multiply both sides by 318 K

\(P_1=2.5atm\)                                           <----- Divide both sides by 28 L

Answer:

False. Humans are the only reason the earth is polluted

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Answer:3,4,1,2

Explanation:

hope this helped

Answer:

number of protons

Explanation:

The number of protons determines an element's atomic number and is used to distinguish one element from another. 

The phrase “the danger is in the dose” means that sometimes it contains toxic chemicals too.

The inorganic chemicals most commonly responsible for poisonings in the United States are cyanide, mercury, arsenic, and lead. While the last three often appear in chemical forms that are quite harmless, it is the soluble salts of the substances that are poisons. Cyanide is a dangerous substance in any form. Overdoses can happen at many opioid dose levels. For example, for instance if a patient drinks alcohol while on the medications, loses track of when they last took a dose, or takes more than the prescribed dose to handle a flare-up of pain.

Thus, we can say overdose can be the danger in the dose.

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Answer: a) No, both are different.

b) Ramesh- 9.9%

  Sarika - 10%

Explanation:

According to the solution prepared by Ramesh,

Mass of sugar he took (Solute) = 10 g

Mass of water he took (Solvent) = 100 g

Thus Mass % of the solution =

According to the solution prepared by Sarika,

Mass of sugar she took (Solute) = 10 g

Mass of Solution she took  = 100 g

Thus Mass % of the solution =

Explanation:

Answer:

Explanation:

In a hot gas, the molecules move faster than in a cold gas; the mass remains the same, but the kinetic energy, and hence the temperature, is greater because of the increased velocity of the molecules. ... We can sense that one gas is hotter than another gas and therefore has a higher temperature.

Phenol and bromomethane are the major products obtained upon treatment of methyl phenyl ether with excess HBr.

What do you mean by Phenol and Bromomethane?

Phenols  are a class of chemical compounds which consist of a hydroxyl group (—OH) bonded directly to an aromatic hydrocarbon group. The simplest of the class is phenol, C6H5OH. Friedlieb Ferdinand Runge discovered Phenol in the year 1834. It was extracted from coal tar.

Bromomethane, commonly known as methyl bromide, is an organobromine compound with formula CH3Br. It is a colorless, odorless, nonflammable gas which is produced both industrially and biologically.  It consist of a  a tetrahedral shape and is  recognized as a ozone-depleting chemical.

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Approximately 597.726 grams of magnesium will react with 16,400 mL (STP) of ammonia. To determine the number of grams of magnesium required to react with 16,400 mL of ammonia, we need to convert the volume of ammonia to the number of moles and then use the balanced chemical equation to calculate the corresponding moles of magnesium.

First, let's convert the volume of ammonia to moles. We'll assume STP (Standard Temperature and Pressure) conditions, where 1 mole of any gas occupies 22.4 liters.

Volume of ammonia (NH3) = 16,400 mL

Temperature and pressure are not specified, so we assume STP.

1 liter = 1000 mL

16,400 mL = 16,400 mL / 1000 mL/L = 16.4 L

Now we can calculate the number of moles of ammonia:

Moles of NH3 = Volume (L) at STP

Moles of NH3 = 16.4 L

Next, let's use the balanced chemical equation to determine the mole ratio between magnesium (Mg) and ammonia (NH3):

3 Mg + 2 NH3 → Mg3N2 + 3 H2

According to the equation, 3 moles of magnesium react with 2 moles of ammonia.

Now we can set up a proportion to find the moles of magnesium:

3 moles of Mg / 2 moles of NH3 = x moles of Mg / 16.4 moles of NH3

Simplifying the proportion:

3/2 = x/16.4

Cross-multiplying:

2x = 3 * 16.4

2x = 49.2

Dividing by 2:

x = 24.6 moles of Mg

Finally, we can calculate the mass of magnesium using its molar mass, which is approximately 24.31 g/mol:

Mass of Mg = Moles of Mg × Molar mass of Mg

Mass of Mg = 24.6 moles × 24.31 g/mol

Mass of Mg ≈ 597.726 g

Therefore, approximately 597.726 grams of magnesium will react with 16,400 mL (STP) of ammonia.

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The final molarity is 74.03 mM.

What is molarity?
Molar concentration, also known as molarity, amount concentration, or substance concentration, is a unit used to describe the amount of a substance in a solution expressed as a percentage of its volume. The number of moles per litre, denoted by the unit symbol mol/L as well as mol/dm3 in SI units, is the most widely used unit for molarity in chemistry. One mol/L of a solution's concentration is referred to as one molar, or 1 M.

Molar mass of KBr = 119.00 g/mol
Mass of KBr = 1.76 g
Moles of KBr = 1.76 g / 119.00 g/mol = 0.0148 mol
Initial molarity of AgNO3 = 74.0 mM
Molarity of AgNO3 = 74.0 mM = 74.0 mol/L
Volume of AgNO3 = 350 mL = 0.35 L
Moles of AgNO3 = 74.0 mol/L x 0.35 L = 25.9 mol
Total moles in solution = 0.0148 mol KBr + 25.9 mol AgNO3 = 25.91 mol
Total volume of solution = 0.35 L
Final molarity of KBr = 25.91 mol KBr / 0.35 L = 74.03 mM

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The percentages of carbon and hydrogen 84.37%  and 15.693% respectively.

The mass of a certain chemical element or chemical compound (g) divided by the amount of material is known as the molar mass (mol). By multiplying the standard atomic masses (in g/mol) of the component atoms, one may get the molar mass of a compound.

Molar mass of the compound is the mass of 1 mole of compound which is the sum of masses of each element.

\(C_9H_{20.\)

Mass of 1 mole of compound= mass of carbon + mass of hydrogen+ = 9(12) + 20(1)= 128 g.

Percentage by mass of carbon = \(\frac{mass \ of \ the \ carbon}{mass \ of \ the\ molecule }\)%

= 108/128 * 100

= 84.37 %

Percentage by mass of carbon = \(\frac{mass \ of \ the \ H}{mass \ of \ the\ molecule }\) %

=20/128 *100 =15.63 %

The percentages of carbon and hydrogen 84.37%  and 15.693% respectively.

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The balanced chemical equations for each of the given reactions are a. KOH(aq) + H3PO4(aq) = K3PO4(aq) + H2O(l), b. AgNO3(aq) + NaCl(s) = AgCl(s) + NaNO3(aq), c. Ca(OH)2(aq) + H3PO4(aq) = Ca3(PO4)2(aq) + H2O(l), and d. FeS(s) + 2HCl(aq) = FeCl2(aq) + H2S(g).

To write a balanced equation for each reaction, the reactants and the products on both sides of the equation must match. This means the number of atoms of each element should be equal on both sides. Let's start with:

These are the balanced chemical reactions corresponding to each equation. Remember to always check to make sure that the number of atoms of each element are balanced on both sides of the equation.

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Answer:

they are bacteria

Explanation:

Answer:

Good bacteria keeps you healthy by supporting your immune function and controlling inflammation. Certain types of good bacteria can also: Help your body digest food. Keep bad bacteria from getting out of control and making you sick.

Explanation:

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Answer:

Calcium nitride (Ca3N2)

148.25 g/mol is the molar mass

Pbcl2 precipitate when 275 ml of a 0.134 m solution of pb(no3)2 is added to 125 ml of 0.0339 m solution of nacl? the ksp of pbcl2 is 1.17e-5.

Given that,

The volume of NaCl = 125 ml

Concentration of NaCl = 0.0339 m

The volume of Pb(NO3)2 = 275 ml

Concentration of Pb(NO3)2 = 0.134 m

K(eq) = 1.17 × 10(-5) --------(1)

Total volume = 275 + 125 = 400 ml

Pb(NO3)2 ------- Pb(+2) + 2 NO3(-)

at t = 0 0.134 0 0

at t = t 0 0.134 0.134

NaCl -------- Na(+) + Cl(+)

at t = 0 0. 0339 0 0

at t = t 0 0.0339 0.0339

PbCl2 ---------- Pb(+2) + 2Cl(-)

Q(sp) = [Pb+2] [ Cl-]^2

By substituting the values of conc. of all the ions, we get Pbcl2 precipitate when 275 ml of a 0.134 m solution of pb(no3)2 is added to 125 ml of 0.0339 m solution of nacl? the ksp of pbcl2 is 1.17e-5.

= (275 × 0.134/ 400) (125 × 0.0339/400)^2

= 9.8 × 10(-6)

As we noticed that, Ksp > Qsp

Therefore, PbCl2 will not precipitate.

Thus, we concluded that the Pbcl2 precipitate when 275 ml of a 0.134 m solution of pb(no3)2 is added to 125 ml of 0.0339 m solution of nacl? the ksp of pbcl2 is 1.17e-5.

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Answer:

Residuals Requires 5,000 times greater

Answer:

The answer is: Species A is more primitive than species B.

Explanation:

Species A has worse genetics than all the other fishes.

According to the ideal gas law, the reaction can make 47 liters of water.

What is the ideal gas law?

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