A fisherman is holding a fishing rod with a large fish hanging from thee line. Identify the forces acting on the rod and describe the interaction partner of each.

Answers

Answer 1

In summary, when a fisherman is holding a fishing rod with a large fish hanging from the line, there are multiple forces acting on the rod. The external forces are the weight of the fish and the force of air resistance, while the internal forces are the tension in the fishing line and the force that the fisherman is exerting on the rod. The interaction partners of these forces are the fishing line, the rod, the fish, and the fisherman's hand.

When a fisherman is holding a fishing rod with a large fish hanging from the line, the following forces act on the rod:

- Tension force: This is the force that is pulling on the line that is attached to the fish. The line is creating a tension force in the rod as it tries to pull the rod downwards.
- Weight force: This is the force that is acting on the rod and the fish due to gravity. The weight force is directed downwards towards the earth.
- Normal force: This is the force that is exerted by the fisherman on the rod. The normal force acts perpendicular to the surface of the rod and prevents the rod from falling down.

The interaction partner of each force acting on the rod is as follows:

- Tension force: The interaction partner of the tension force is the fish. The line is pulling on the fish and the fish is exerting a force back on the line that is equal in magnitude and opposite in direction. This is the principle of Newton's third law of motion.
- Weight force: The interaction partner of the weight force is the earth. The earth is exerting a force back on the rod and the fish that is equal in magnitude and opposite in direction. This is also the principle of Newton's third law of motion.
- Normal force: The interaction partner of the normal force is the fisherman. The fisherman is holding the rod and is exerting a force on the rod that is perpendicular to its surface. This force prevents the rod from falling down and is equal in magnitude and opposite in direction to the weight force acting on the rod.

In summary, the forces acting on the rod when a fisherman is holding a fishing rod with a large fish hanging from the line are tension force, weight force, and normal force. The interaction partners of these forces are the fish, the earth, and the fisherman, respectively.

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Related Questions

The free-body diagram of a crate is shown. A free body diagram with 4 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline = negative 440 N. The second vector is pointing right, labeled F Subscript p Baseline = 176 N. The third vector is pointing upward, labeled F Subscript N Baseline = 440 N. The fourth vector is pointing left, labeled F Subscript f Baseline = negative 352 N. The up and down vectors are the same length. The right vector is shorter than the left vector. What is the net force acting on the crate? 352 N to the left 176 N to the left 528 N to the right 440 N to the right

Answers

The net force acting on the crate is determined as 176 N to the left.

Net force acting on the crate

The net force acting on the crate is calculated as follows;

∑F = F1 + F2 + F3 + F4

F(net) = -440y + 176x + 440y - 352x

F(net) = -176 x

The resultant force is pointing in negative x direction.

Thus, the net force acting on the crate is determined as 176 N to the left.

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PLEASE HELP ME I AM TIMED!

PLEASE HELP ME I AM TIMED!

Answers

Answer:

they all need a source of oxygen

Answer:

B

Explanation:

jeff 60 kg and julia 45 kg are in two separate bumper cars 130 each. jeff was moving at 4 m/s north while julie was going 6 m/s west. julia bounces off going 2 m/s at an angle of 15 s of w. what is the final velocity and direction of jeff car

Answers

Final velocity of Jeff's car is 7.133 m/s south. The direction is 59.3° south of east.

In this issue, we can utilize preservation of energy to track down the last speed and course of Jeff's crash mobile after the impact with Julia's. Before the impact, the energy in the x-heading is zero, and in the y-course, it is 60 kg × 4 m/s = 240 kg⋅m/s north. Julia's force is 45 kg × 6 m/s = 270 kg⋅m/s west.After the crash, the energy in the x-course is rationed. The absolute energy in the x-course is as yet zero, as Julia's force that way is likewise zero. In the y-heading, the absolute force after the crash is 60 kg × vj + 45 kg × 2 m/s sin 15°, where vj is Jeff's last speed in the y-course.Utilizing protection of energy, we can compare the force when the crash in the y-heading:

60 kg × 4 m/s + 45 kg × 6 m/s = 60 kg × vj + 45 kg × 2 m/s sin 15°

Working on this situation, we get:

240 kg⋅m/s + 270 kg⋅m/s = 60 kg × vj + 12.19 kg⋅m/s

Addressing for vj, we get:

vj = (240 kg⋅m/s + 270 kg⋅m/s - 12.19 kg⋅m/s)/60 kg

vj = 7.133 m/s south

Consequently, Jeff's last speed is 7.133 m/s south. To find the course, we can utilize geometry. The point of Jeff's last speed concerning the x-pivot is given by:

θ = tan^-1(vj/4 m/s)

θ = 59.3° south of east

Accordingly, the last speed and heading of Jeff's amusement cart are 7.133 m/s at a point of 59.3° south of east.

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answer this question ​

answer this question

Answers

Answer:

That's ezy

Explanation:

so you add sponge and Bob so then. you go to earth to get milk because your dad didn't came back you you add Spider-Man so you can get taco bell but that's when you don't find the earth but SpongeBob can drink water

so that how I got 25

rotational kinematics with constant angular acceleration: a 1.15-kg grinding wheel 22.0 cm in diameter is spinning counterclockwise at a rate of 20.0 revolutions per second. when the power to the grinder is turned off, the grinding wheel slows with constant angular acceleration and takes 50.0 s to come to a rest. (a) what was the angular acceleration (in rad/s2) of the grinding wheel as it came to rest if we take a counterclockwise rotation as positive? (b) how many revolutions did the wheel make during the time it was coming to rest?

Answers

(a) The angular acceleration of the grinding wheel as it came to rest is approximately -0.008 rad/s² (clockwise).

(b) The wheel made approximately 1000 revolutions during the time it was coming to rest.

(a) We can use the formula of rotational kinematics:

ω = ω₀ + αt

where ω is the final angular velocity, ω₀ is the initial angular velocity, α is the angular acceleration, and t is the time.

Given:

ω = 0 rad/s (final angular velocity)

ω₀ = 20.0 revolutions per second = 20.0 * 2π rad/s (initial angular velocity)

t = 50.0 s

Substituting the values into the formula, we have:

0 = 20.0 * 2π + α * 50.0

Solving for α, we get:

α ≈ -0.008 rad/s² (clockwise)

(b) To find the number of revolutions the wheel made during the time it was coming to rest, we can use the formula:

θ = ω₀t + 0.5αt²

where θ is the angular displacement.

Given:

ω₀ = 20.0 revolutions per second = 20.0 * 2π rad/s (initial angular velocity)

t = 50.0 s

α ≈ -0.008 rad/s² (clockwise)

Substituting the values into the formula, we have:

θ = (20.0 * 2π) * 50.0 + 0.5 * (-0.008) * (50.0)²

Simplifying the equation, we find:

θ ≈ 1000 revolutions

Therefore, the wheel made approximately 1000 revolutions during the time it was coming to rest.

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4. As a 500 N woman sits on the floor, the floor exerts a force on her of
ext
a) 1000 N.
b) 500 N.
c) 250 N.
d) 50 N.
e) 5 N.

Answers

Answer: 1000

Explanation:

Its double her weight

When a ball rolls along carpet, it slows down faster than when it is rolled on the floor. What transfer of energy explains this observation?
Select one:

A carpet transfers more energy to potential energy than the floor.

A carpet transfers less energy to heat than the floor.

A carpet transfers more energy to heat than the floor.

A carpet transfers less energy to potential energy than the floor.

Answers

Answer:

A carpet transfers more energy to heat than the floor, I believe.

Explanation:

There is more friction on the carpet creating more heat and energy loss. Potential energy is gained from being at a higher elevation.

a 1.0 kg mass is attached to the end of a vertical end of a vertical ideal spring with a spring constant of 400 n/m. the mass is set into simple harmonic motion with amplitude 10 cm. the speed of the 1.0. kg mass at the equilibrium position is

Answers

The speed of the 1.0. kg mass at the equilibrium position is 2 m/s.

What in physics is a simple harmonic motion?

In physics, simple harmonic motion is the repeated back-and-forth movement through an equilibrium, or center, position so that the maximum displacement on one side of this position is equal to the maximum displacement on the other. Each whole vibration occurs at the same time interval.

Calculation:

A point mass performing a straightforward harmonic movement has an instantaneous velocity given by:

v(t) = ω × A × cos(ωt + Ф)

ω = Angular frequency

A = Amplitude

Ф = Initial phase

Express the amplitude in meters:

10cm × 1m / 100cm = 0.1 m

The following equation can be used to get the angular frequency:

ω = √k/m

ω = √1/400

ω = 20

At the equilibrium position:

Ф = 0

v = (20) × (0.1) cos (20 × 0 + 0)

v = 2 × 1 m/s

v = 2m/s

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5. On a hot summer day the grass feels cooler than the sidewalk, because
O
O
the grass has a higher specific heat
the grass has a smaller surface area
the sidewalk is at a higher temperature

Answers

Answer:

because the side walk is at high temperature

a 1.30-μf capacitor is charging through a 14.0-ω resistor using a 12.0-v battery. What will be the current when the capacitor has acquired 1/4 of its maximum charge?

Answers

So, the current when the capacitor has acquired 1/4 of its maximum charge is approximately 0.171 A.

To find the current when the capacitor has acquired 1/4 of its maximum charge, we can use the equation for the current in an RC circuit, which is:

I(t) = V/R * e^(-t/RC)

Here,
I(t) is the current at time t,
V is the battery voltage (12.0 V),
R is the resistor value (14.0 Ω),
C is the capacitor value (1.30 µF),
t is the time when the capacitor has acquired 1/4 of its maximum charge, and
e is Euler's number (approximately 2.718).

First, we need to find the time t when the capacitor has 1/4 of its maximum charge. We can use the equation for the voltage across a charging capacitor:

V(t) = V * (1 - e^(-t/RC))

We know that at 1/4 of its maximum charge, the voltage across the capacitor will be 1/4 of the battery voltage:

V(t) = 0.25 * V = 0.25 * 12 = 3.0 V

Now, we can solve for t:

3.0 V = 12 V * (1 - e^(-t/(14 Ω * 1.30 µF)))

0.25 = 1 - e^(-t/(14 Ω * 1.30 µF))

0.75 = e^(-t/(14 Ω * 1.30 µF))

Now, take the natural logarithm of both sides:

ln(0.75) = -t/(14 Ω * 1.30 µF)

Now, solve for t:

t ≈ 3.14 * 10^(-6) s

Now, we can plug the value of t back into the current equation:

I(t) = 12 V / 14 Ω * e^(-3.14 * 10^(-6) s / (14 Ω * 1.30 µF))

I(t) ≈ 0.857 A * e^(-1.614)

I(t) ≈ 0.857 A * 0.199

I(t) ≈ 0.171 A

So, the current when the capacitor has acquired 1/4 of its maximum charge is approximately 0.171 A.

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In an inverse relationship which one variable increases the other?

Answers

Answer:

as A increases, B decreases, and as B increases, A increases. Hope this helps!

Explanation:

The figure below shows a ball on a curved surface. The ball is released at point A. At which point does the ball have maximum gravitational potential energy?

The figure below shows a ball on a curved surface. The ball is released at point A. At which point does

Answers

Answer:

Point A

Explanation:

Because it reaches maximum height

A ball with an initial speed of 4.0 m/s undergoes constant acceleration at 3.0 m/s² for 5.0 s. What is the total distance traveled by the ball during this 5.0-s period?
A 38 m
B 58 m
C 75 m
D 95 m

Answers

To solve this problem, we can use the kinematic equation that relates the initial velocity, acceleration, time, and distance:

d = v₀t + 1/2at²

where d is the total distance traveled, v₀ is the initial velocity, a is the acceleration, and t is the time.

Substituting the given values into the equation, we get:

d = (4.0 m/s)(5.0 s) + 1/2(3.0 m/s²)(5.0 s)²

Simplifying and solving for d, we get:

d = 20.0 m + 37.5 m

d = 57.5 m

Therefore, the total distance traveled by the ball during the 5.0-s period is 57.5 meters.

B 58 m (rounded)

a child sleds down a steep, snow-covered hill with an acceleration of 2.82m/s squared. if her initial speed is 0.0 m/s and her final speed is 15.5 m/s, how long does it take her to travel from the top of the hill to the bottom?

Answers

A child sleds down a steep, snow-covered hill with an acceleration of 2.82m/s squared. if her initial speed is 0.0 m/s and her final speed is 15.5 m/s, It takes the child 5.50 seconds to travel from the top of the hill to the bottom.

We can use the following kinematic equation to solve this problem:

v^2 = u^2 + 2as

Where:

v is the final speed

u is the initial speed

a is the acceleration

s is the distance traveled

We are given u = 0.0 m/s, a = 2.82 m/s^2, and v = 15.5 m/s. We need to find s.

Rearranging the equation gives:

s = (v^2 - u^2) / (2a)

Substituting the values gives:

s = (15.5^2 - 0.0^2) / (2 x 2.82) = 74.47 m

Now, we can use another kinematic equation to find the time taken:

v = u + at

Where t is the time taken.

Substituting the values gives:

15.5 = 0.0 + 2.82t

Solving for t gives:

t = 15.5 / 2.82 = 5.50 seconds

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Just like Coke is a type of soda, __________ is a type of ___________.
A.concentration,.equilibrium
B..equilibrium, concentration
C.diffusion, osmosis
D.osmosis. diffusion​

Answers

Answer:

osmosis diffusion

Explanation:

ok it's correct

A wave has a frequency of 6 Hz, how long is the period?

A 6

B 12

C .17

D 36

Answers

Answer:

C.

Explanation:

part 1 of 2
A neutron in a reactor makes an elastic
head-on collision with the nucleus of an atom
initially at rest.
Assume: The mass of the atomic nucleus is
about 11.1 the mass of the neutron.
What fraction of the neutron's kinetic en-
ergy is transferred to the atomic nucleus?

part 2 of 2
In the initial kinetic energy of the neutron
is 1.77 x 10^-13 J. find its final kinetic energy.
Answer in units of J.



Answers

Answer:

for part 1 the answer is 0.303

Explanation:

1. A kangaroo hops 84 m to the east in 7 seconds.
o What is the kangaroo's speed? 12 m/s
o What is the kangaroo's velocity?

Answers

Explanation:

Given parameters:

Distance hopped  = 84m

Displacement  = 84m due east

Time  = 7s

Unknown:

Speed of kangaroo  = ?

Velocity of kangaroo  = ?

Solution:

To solve this problem,

    Speed  = \(\frac{distance}{time }\)   = \(\frac{84}{7}\)  = 12m/s

  Velocity  = \(\frac{displacement}{time}\)   = \(\frac{84}{7}\)   = 12m/s due east

In what way is a screw similar to an inclined plane?

-A screw and an inclined plane both have threads.

-A screw is put in place with a screwdriver, which is a wedge.

-A screw is an inclined plane wrapped around a cylinder.

Answers

Answer:

-A screw is an inclined plane wrapped around a cylinder.

Explanation:

Answer:

b

Explanation:

A micrometer is used to measure the diameter of a length of copper wire. The zero error and scale reading are as shown.
A - what is the zero error of the micrometer?
B - what is the correct diameter wire?

A micrometer is used to measure the diameter of a length of copper wire. The zero error and scale reading

Answers

The answer should be b

A micrometer is used to measure the diameter of a length of copper wire. The zero error and scale reading are as shown.The correct answer should be the micrometer.

What is micrometer?

The micrometer is an instrument that is capable of measuring the component of an object to very high precision. It is used to obtain accurate measurements in engineering.

In the case of the copper wire, the diameter of 0.3 mm was an approximation and a more accurate measure of the diameter would be obtained by using the micrometer.A micrometer is used to measure the diameter of a length of copper wire. The zero error and scale reading are as shown.The correct answer should be the micrometer.

Therefore, A micrometer is used to measure the diameter of a length of copper wire. The zero error and scale reading are as shown.The correct answer should be the micrometer.

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true or false: for problems involving rockets, the equation f = ddtddt(mv) can be used with the assumption that the mass m is constant.

Answers

False. The equation you provided, f = ddtddt(mv), is the correct equation for the force acting on an object (such as a rocket) with varying mass.

However, the assumption of constant mass (dm/dt = 0) cannot be applied to rockets as they experience mass change due to fuel consumption. In the case of a rocket, as it expels its exhaust gases, its mass decreases over time.

Therefore, the mass term (m) in the equation f = ddtddt(mv) is not constant and should be taken into account when calculating the force and acceleration of the rocket. This is typically done using the rocket equation, which incorporates the concept of mass change and the specific impulse of the rocket's engine.

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how come if you jump in a train you will land in the same spot but if you jump on top of the train you won't? i tried to make it make sense.

Answers

Answer:

Well, it has to do something with the force of the train. It's pulling you, a force of gravity

However jumping off results in a different sort of energy, the train know is moving farther away as you jump down. So you end up in a different place

Explanation:

Junita lifts a round box & a square box to a shelf. The GPE for the round box increases by 50 J. The GPE for the square box increases by 100 J. On which box did Junita do more work

Answers

Junita will do more work on the square box. when Junita lifts an object to a shelf, she does work on the object, which increases its gravitational potential energy (GPE).

The amount of work done on an object is equal to the increase in its GPE.

Junita lifted a round box and a square box to a shelf. She did work on the boxes, increasing their GPE. The round box's GPE increased by 50 J, meaning Junita exerted 50 J of work.

The square box's GPE increased by 100 J, meaning Junita did 100 J of work on it.

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8. A satellite weighs 200 newtons on the surface of

Earth. What is its weight at a distance of one Earth

radius above the surface of Earth?

1) 800 N

3) 100 N

2) 400 N

4) 50 N

Answers

The weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.

The given parameters:

Weight of the satellite, F = 200 NOne Earth radius above the surface of Earth = 2R

The gravitational force on the satellite is calculated by applying Newton's law of universal gravitation is calculated as;

\(F = \frac{Gm_1m_2}{R^2} \\\\F_1 R_1^2 = F_2R_2^2\\\\F_2 = \frac{F_1 R_1^2 }{R_2^2} \\\\F_2 =\frac{200 \times R_1^2}{(2R_1)^2} \\\\F_2 = \frac{200 \times R_1^2 }{4R_1} \\\\F_2 = 40 \ N\)

Thus, the weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.

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What happens to our temperature when
the heat photons stay in our
atmosphere ?

Answers

Answer:

the temperature would go up

Explanation:

It doesn't matter about what the temperature is, when the heat photons stay in the atmosphere they collect heat and build up the atoms. Then the Photons heat up and the temperature goes up.

If you thought this was good, can I have a brainesit plz.

If you didn't don't worry about it, have a good day!

Thanks,

:)

what is the drift velocity of electrons in a wire of diameter 2.7mm that carries a current of 3 a

Answers

The drift velocity of electrons in the wire is \(6.5 x 10^{-5} m/s.\) It can be calculated by using drift velocity formula.

The drift velocity of electrons in a wire of diameter 2.7mm that carries a current of 3 A can be calculated using the formula:

Drift velocity = I/(n.A.e)

Where I is the current, n is the number of charge carriers per unit volume, A is the cross-sectional area of the wire, and e is the charge of an electron. Given that the diameter of the wire is 2.7mm, we can calculate the cross-sectional area as:

A =\(\pi r^2 = \pi (1.35mm)^2 = 5.73mm^2\)

Now, we can plug in the given values into the formula:

Drift velocity = \(3 A/(n . 5.73mm^2 . 1.6 . 10^{-19} C)\)

Assuming that the number of charge carriers per unit volume is 8.5 × 10^28 m^-3, we can calculate the drift velocity as:

Drift velocity = \(3 A/(8.5 . 10^{28} m^{-3} . 5.73 . 10^{-6} m^2 . 1.6 . 10^{-19} C) = 6.5 . 10^{-5} m/s\)

Therefore, the drift velocity of electrons in the wire is \(6.5 x 10^{-5} m/s.\)

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sam says that beta particles are not used to irradiate food because they make it radioactive. Jo says that the reason is that beta particles would not be able to penetrate all the way through think packages of food. Who is correct, Sam or Jo?

Answers

Answer:

Jo

Explanation:

irradiating food doesn't make it radioactive (that's contamination) and beta particles are stopped by aluminium foil or thin metals, so it may not pass through thick packaging (usually gamma is used to irradiate foods as it can pass through the packaging)


1. What are the different types of waves? Give examples of each type.
2.When light travels from air to glass, the light bends at the interface. What
is the reason for this phenomenon of bending of light at the interface of the
two media?

Answers

Answer:

See explanation

Explanation:

1) There are two main types of waves;

Mechanical waves and electromagnetic waves.

Mechanical waves usually require a medium for propagation, e.g sound, waves on a spiral spring, etc

Electromagnetic waves do not require a medium for propagation e.g microwaves, x-rays etc

2) The phenomenon is known as refraction. Refraction occurs at the boundary between two media because of the change in the speed of a wave as it moves from one medium to another.

How do u find the number of electronic

Answers

Count.................

Se coloca una tuerca con una llave, como muestra la figura, si el brazo r= 30 cm y el torque de apriete recomendado para la fuerza es de 30 Nxm, Cuàl debe ser el valor de la fuerza F aplicada?

Answers

Answer:

F = 100 N

Explanation:

The torque is given by the expression

      τ = F x r

where bold letters indicate vectors, the magnitude of this expression is

     τ = F r sin θ

In general, when tightening a nut, the force is applied perpendicular to the arm, therefore  θ = 90 and sin 90 = 1

      τ = F r

      F = τ / r

calculate

      F = 30 / 0.30

      F = 100 N

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