4 indentical charges each of value 2 mc are placed at the four corners of square 2 meters. What is the electric potential at the centre of the square​​​

Answers

Answer 1

\({\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\\)

\(\:\:\:\:\bullet\:\:\:\sf{ 4 \: identical \: charges = 2 \mu \: C \:\:\:(each)} \\\\ \)

\(\:\:\:\:\bullet\:\:\:\sf{Side \: of \: square = 2 \: m }\)

\(\\\)

\({\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\\)

\(\:\:\:\:\bullet\:\:\:\sf{ Electric \: potential \: at \: centre\:( V_{c})}\)

\(\\\)

\({\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}} \\ \\\)

According to the given data,

\(\\\)

\(\:\:\:\:\bullet\:\:\:\sf{Length \: of \: diagonal= \sqrt{2} a } \\\\\)

\(\:\:\:\:\bullet\:\:\:\sf{ Length \:of \: half \: diagonal = \sqrt{2}}\)

\(\\\)

As we know that,

\(\\\)

\(\dashrightarrow\:\: \sf{V_{c} = V_{1} + V_{2} + V_{3} + V_{4} }\)

\(\\\)

\( \sf{(V_{1} = V_{ 2} = V_{3} = V_{4}) }\)

\(\\\)

\(\dashrightarrow\:\: \sf{V_{c} = 4 V_{1} }\)

\(\\\)

\(\dashrightarrow\:\: \sf{ V_{c} = 4 \times \dfrac{k q_{1}}{ r_{1}}}\)

\(\\\)

\(\dashrightarrow\:\: \sf{V_{c} = 4 \times \dfrac{9 \times {10}^{9} \times 2 \times {10}^{ - 6} }{\sqrt{2}} }\)

\(\\\)

\(\dashrightarrow\:\: \sf{V_{c} =4 \times 9 \times \sqrt{2} \times {10}^{9 - 6} }\)

\(\\\)

\(\dashrightarrow\:\: \sf{V_{c} =36\sqrt{2} \times {10}^{3} }\)

\(\\\)

\(\dashrightarrow\:\: \underline{\boxed{\sf{V_{c} =3.6\sqrt{2} \times {10}^{4} \: J /c }}}\)

\(\\\)

★ The electric potential at center of square is 3.6\(\sqrt{2}\) × 10⁴ J/c


Related Questions

35 milliseconds?! that is crazy fast. Another
way to write that is 0.035 seconds. If the
airbag has to inflate 1 meters. How fast does
this airbagtravel? (remember velocity =
distance/time)

Answers

Answer:

28 m/s

Explanation:

1m / 0,035 s

v = 28.57 m/s

if you want km/h, multiply witz 3,6

102,85 km/h = 28,57 m/s

What is the answer please help

What is the answer please help

Answers

Answer:

I think c

Explanation:

cold air pushes warm air up and then the air mixes(im not sure)

Fossil fuels like gasoline or coal are examples of

Answers

Answer:

Nonrenewable Resources

Answer:

fossil fuels

Explanation:

Convert 13.1 miles to feet. Using one step conversion

Answers

Answer:

69,168 ft

Explanation:

When a mass of 3.0-kg is hung on a vertical spring, it stretches by 0.085 m. Determine
the period of oscillation of a 4.0-kg object suspended from this spring.

Answers

Answer:

the period of oscillation of the given object is 0.14 s

Explanation:

Given;

mass of the object, m = 3 kg

extension of the spring, x = 0.085 m

The spring constant is calculated as follows;

\(F = mg = \frac{1}{2} ke^2\\\\2mg = ke^2\\\\k = \frac{2mg}{e^2} \\\\k = \frac{2\times 3 \times 9.8}{(0.085)^2} \\\\k = 8,138.41 \ N/m\)

The angular speed of a 4 kg object is calculated as follows;

\(\omega = \sqrt{\frac{k}{m} } \\\\\frac{2\pi }{T} = \sqrt{\frac{k}{m} } \\\\T= 2\pi \sqrt{\frac{m}{k} } \\\\T = 2\pi \sqrt{\frac{4}{8138.41} }\\\\T = 0.14 \ s\)

Therefore, the period of oscillation of the given object is 0.14 s

2. An object’s velocity is measured to be v (t) = αt−βt2, where α = 4.00 m/s2 and β = 2.00 m/s3. Calculate the average acceleration of the object from t = 0.0 s to t = 3.0 s

Answers

Hi there!

Given the values for α and β, we can plug these into the given equation:

\(v(t) = 4t - 2t^2\)

Begin by solving for the velocity at t = 0 and t = 3:

At t = 0:
\(v(0) = 4(0) - 2(0^2) = 0 \frac{m}{s}\)

At t = 3:
\(v(3) = 4(3) - 2(3^2) = 12 - 18 = -6 \frac{m}{s}\)

Acceleration is the SLOPE of the velocity graph (its derivative), so we can use the kinematic equation:

\(a = \frac{v_f - v_i}{\Delta t}\)

Plug in the knowns:

\(a = \frac{-6-0}{3 - 0} = \boxed{-2 \frac{m}{s^2}}\)

A cleaner pushes a laundry 4.50 kg cart in such a way that the net external force on it 60.0 N. Calculate the magnitude of its acceration

Answers

Answer: 13.33

Explanation:

F=ma

m= 4.5 kg

F= 60 N

60 N/4.5 kg =13.33 m/s

9. What's the process that a spark represents?
A. A body with a strong positive charge is placed near a body with a neutral charge and the electrons jump between the two bodies
B. A body with a strong positive charge is placed near a body with a strong negative charge and the electrons jump between the two
C. A body with a neutral charge is placed near a body with a strong negative charge and the electrons jump between the two bodies
D. A body with a strong positive charge is placed near a body with a strong positive charge and the electrons jump hatupon the. The answer

Answers

Answer:

Sparks often indicate the presence of a high voltage, or "potential field". The higher the voltage; the farther a spark can jump across a gap, and with enough energy supplied can lead to greater discharges such as a glow or an arc.

Explanation:

Find the unit vector of the vector F=(9.00i-8.00j)N

Answers

9\(\^{i}\)+8\(\^{j}\)/\(\sqrt{136}\)

F=(9.00i-8.00j)N

we are now to find the unit vector

according to formula

unit vector = \(\frac{vector of F}{Magnitude of F}\)

Now :

vector form of F = 9\(\^{i}\)+8\(\^{j}\)

magnitude of F =\(\sqrt{9^2+8^2}\)

magnitude of F=\(\sqrt{136}\)

now put that in formual

unit vector = 9\(\^{i}\)+8\(\^{j}\)/\(\sqrt{136}\)

When a normal vector's magnitude is one, or unit, it is said to be a unit normal vector.Normal vectors, often known as perpendicular to surfaces, are vectors that, at the provided coordinates, are normal to surfaces. The normal pointing inside and the normal pointing outside the surface are often identified when perpendiculars are obtained on closed surfaces.Normal vectors are often denoted by the letters "N" or "n," and occasionally with a cap to specifically denote the unit normal vector.

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Select the correct answer. Which segment of this graph shows a decreasing velocity? Graph representing Time in seconds on the x-axis and position in miles on the y-axis. The line starts at point A (0, 20), and passes points B (20, 20), C (40, 40), D (60, 60), E (80, 60), and F (100, 80) A. A to B B. B to C C. C to D D. D to E E. E to F

Answers

The portion that shows a decreasing velocity is  D to E.

What is a position - time graph?

The position time graph is used to describe the motion of a body. We know that the slope of a velocity time graph is the velocity of the graph.

If we look at the graph as shown in the image attached to the answer, we can see that the portion that shows a decreasing velocity is  D to E.

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Select the correct answer. Which segment of this graph shows a decreasing velocity? Graph representing

Answer:

D - E

Explanation:

hope this help


\(2.25 \times 30\)

Answers

67.5 is the answer i believe!!
67.5
I hope this helped <33

Trently limited
Spiderman's cell phone falls from his pocket while he is surveying the city. His spider senses have
failed him. It takes the phone 3.6s to crash into the pavement below. How high up was Spiderman?

Answers

Answer:

h= 63.5 m

Explanation:

Assuming that air resistance is neglectable, and that the phone drops from Spiderman's pocket, we can use the following kinematic equation for the vertical displacement:

       \(\Delta h = \frac{1}2} * g* t^{2} = \frac{1}{2} *(-9.8 m/s2)*(3.6s)^{2} = -63.5 m\)

\(\Delta h = y - y{o} = -63.5 m\)Taking as zero level reference the ground level, we get:

        y₀ = h = 63.5 m

earth energy budget is the relationship between how much energy the earth _______ and energy the earth _________

Answers

earth energy budget is the relationship between how much energy the earth receive from the sun and energy the earth radiates out.

What is energy?

Energy is described as the quantitative property that is displaced to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.

The term earth's energy budget is also described as the  balance between of the amount of energy, that gets to the earth. from the Sun and the energy that leaves Earth and returns to the universe.

The earth's energy budget was mainly three types as shown:

shortwave radiation, longwave radiation, and internal heat sources.

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report of "fan made of plastic bottle" with string

Answers

Fan made of plastic bottle is an innovative way to reuse plastic bottles and can be easily made at home. This can be done by following simple steps, and a few materials are required to make it. The fan can be created by using a plastic bottle, scissors, string, a ruler, and a marker.

First, the bottle needs to be cut into half, and the upper part needs to be cut into three equal sections, then fold each section to make a blade. With the help of a ruler and marker, make a mark on each section, then make a hole in the center of each blade. Insert a string through the holes and tie the ends of the strings. The fan is ready to use by holding the string and swinging it back and forth.

The use of plastic bottle fans can significantly reduce the number of plastic waste and provide a practical solution to avoid environmental pollution. Besides, it is easy to make, and the materials are readily available, which can be used for various occasions, such as picnics, camping, or any outdoor activities.

In conclusion, the creation of a fan made of plastic bottle with string is an excellent way to reuse plastic bottles and can be made with simple steps. This project encourages everyone to contribute to environmental protection by utilizing what is available at home and reducing the number of plastic wastes.

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A particle is projected at an angle 60 degrees to the horizontal with a speed of 20m/s. (i) calculate total time of flight of the particle. (i) speed of the particle at its maximum height

Answers

Answer:

Time of flight=3.5 seconds

Speed at maximum height is 0

Explanation:

Φ=60°

initial velocity=u=20m/s

Acceleration due to gravity=g=9.8 m/s^2

Total time of flight=T

Final speed=v

question 1:

T=(2 x u x sinΦ)/g

T=(2 x 20 x sin60)/9.8

T=(2 x 20 x 0.8660)/9.8

T=34.64/9.8

T=3.5 seconds

Question 2

Speed at maximum height is 0

1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.

2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.

1. A ball is at rest on the top of a hill (see the figure).At the top of the hill, the ball will have

Answers

1. At the top of the hill, the ball will have the maximum value of its gravitational potential energy and the minimum value of its kinetic energy. As the ball rolls down the hill, its gravitational potential energy is converted to kinetic energy when it gets to the ground.

2. When dropping the object, you should drop it so its top part is initially at the height h. The initial speed of the ball will be zero since it starts from rest. To measure the time it takes for the ball to hit the ground, you should start the stopwatch when the ball leaves your hand and stop it when the ball hits the ground for the first time. It is recommended to perform multiple trials and calculate the average time to minimize errors.

What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m

Answers

The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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A flat loop of wire consisting of a single turn of cross-sectional area 8.60 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 2.40 T in 1.02 s. What is the resulting induced current if the loop has a resistance of 2.80

Answers

Answer:

The  induced current is \(I = 5.72*10^{-4 } \ A\)

Explanation:

From the question we are told that

     The cross-sectional area is  \(A = 8.60 \ cm^2 = \frac{8.60 }{10000} = 8.60 *10^{-4} \ m\)

     The initial value of magnetic field is  \(B_1 = 0.500 \ T\)

     The  value of magnetic field  at  time  t     is  \(B_f = 2.40 \ T\)

     The number of turns  is  N  =  1  

     The  time taken is   \(dt\)=  1.02 \ s  

       The resistance of the loop is  \(R = 2.80\ \Omega\)

Generally the induced emf is mathematically represented as

         \(e = - \frac{d \phi}{dt }\)

Where  \(d \phi\) is the change n the magnetic flux which is mathematically represented as

          \(d \phi = N *A * d B\)

Where \(dB\) is the change in magnetic field which is mathematically represented as  

          \(d B = B_f - B_i\)

substituting values  

         \(d B = 2.40 - 0.500\)

         \(d B = 1.9 \ T\)

So  

        \(d \phi = 1 * 1.9 * 8.60 *10^{-4}\)

       \(d \phi = 1.63*10^{-3} \ T\)

So  

      \(e = - \frac{1.63 *10^{-3}}{ 1.02 }\)

      \(e = - 1.60*10^{-3} \ V\)

     Here the negative only indicates that the emf is acting in opposite direction of the motion producing it so the magnitude of the emf is  

       \(e = 1.60*10^{-3} \ V\)

Now the induced current is evaluated as follows

       \(I = \frac{e}{R }\)

substituting values  

      \(I = \frac{1.60 *10^{-3}}{2.80 }\)

      \(I = 5.72*10^{-4 } \ A\)

An AC voltage source is connected to a resistor R = 1.90 102 Ω. The output from an AC voltage source is given by the expression V = (2.20 102 V) sin 2ft. (a) What is the rms voltage across the resistor? V (b) What is the rms current flowing through the resistor? A

Answers

Answer:

(a) The rms voltage across the resistor is given by V = (2.20 102 V) sin 2ft.

V = (2.20 102 V) sin 2ft

V = (2.20 102 V) (0.707)

V = 1.56 102 V

(b) The rms current flowing through the resistor is given by I = V/R.

I = V/R

I = (1.56 102 V)/(1.90 102 Ω)

I = 8.21 A

Review procedures and confirm results to avoid possible errors.

Explanation:

g Drop the object again and carefully observe its motion after it hits the ground (it should bounce). (Consider only the first bounce and do NOT assume the total energy is the same as the total energy of the object before it hits the ground.) a. List the quantities that you need to know to determine the total energy of the object after it hits the ground. b. Record your measurements and describe how you measured them. c. Calculate the total energy of the object after it hit the ground. Your final answer: ______________ d. Determine whether or not the object’s energy was conserved when it hit the ground. If it was not conserved, explain where the energy went.

Answers

Answer:

a) quantity to be measured is the height to which the body rises

b) weighing the body , rule or fixed tape measure

c)   Em₁ = m g h

d) deformation of the body or it is transformed into heat during the crash

Explanation:

In this exercise of falling and rebounding a body, we must know the speed of the body when it reaches the ground, which can be calculated using the conservation of energy, since the height where it was released is known.

a) What quantities must you know to calculate the energy after the bounce?

The quantity to be measured is the height to which the body rises, we assume negligible air resistance.

So let's use the conservation of energy

starting point. Soil

          Em₀ = K = ½ m v²

final point. Higher

          Em_f = U = mg h

         Em₀ = Em_f

         Em₀ = m g h₀

b) to have the measurements, we begin by weighing the body and calculating its mass, the height was measured with a rule or fixed tape measure and seeing how far the body rises.

c) We use conservation of energy

starting point. Soil

          Em₁ = K = ½ m v²

final point. Higher

          Em_f = U = mg h

         Em₁ = Em_f

         Em₁ = m g h

d) to determine if the energy is conserved, the arrival energy and the output energy must be compared.

There are two possibilities.

* that have been equal therefore energy is conserved

* that have been different (most likely) therefore the energy of the rebound is less than the initial energy, it cannot be stored in the possible deformation of the body or it is transformed into heat during the crash

All types of mass movement are caused by the force of

Answers

Answer:

Mass and Acceleration

Explanation:

The typical Force equation is:

F = ma

where m = mass, and a=acceleration.

Answer:

Gravity is the main force responsible for mass movements. Gravity is a force that acts everywhere on the Earth's surface, pulling everything in a direction toward the center of the Earth

Explanation:

People who do very detailed work close up, such as jewellers, often can see objects clearly at much closer distance than the normal 25 cm. a. What is the power in D of the eyes of a woman who can see an object clearly at a distance of only 8.5 cm

Answers

This question is incomplete, the complete question is;

People who do very detailed work close up, such as jewelers, often can see objects clearly at much closer distance than the normal 25 cm.

a) What is the power in D of the eyes of a woman who can see an object clearly at a distance of only 8.50 cm? (Assume the lens-to-retina distance is 2.00 cm.)

b) What is the size in mm of an image of a 8.00 mm object, such as lettering inside a ring, held at this distance? (Include the sign of the value in your answer.)  __ mm

Answer:

1) the power in D of the eyes of a woman is 61.7647 D

2) the size in mm of an image of a 8.00 mm object is -1.882 mm

Explanation:

Given the data in the question;

a) power in D of the eyes of woman who can see an object clearly at a distance of only 8.5 cm and the lens-to-retina distance is 2.00 cm,

so

u = 8.5 cm = ( 8.5 / 100 )m = 0.085 m

v = 2.00 cm = ( 2 / 100 )m =  0.02 m

Now, we know that power of lens p = 1 / u + 1 / v

so we substitute

p = ( 1 / 0.085 ) + ( 1 / 0.02 )

p = 11.7647 + 50

p = 61.7647 D

Therefore,  the power in D of the eyes of a woman is 61.7647 D

b) What is the size in mm of an image of a 8.00 mm object, such as lettering inside a ring, held at this distance? (Include the sign of the value in your answer.)

we know that;

m = -v / u

we substitute

m = -0.02 / 0.085

m = -0.2353

since H₀ = 8.0 mm

H\(_i\) = m × H₀

H\(_i\) = -0.2353 × 8.0

H\(_i\) = -1.882 mm

the size in mm of an image of a 8.00 mm object is -1.882 mm

An artist working on a piece of metal in his forging studio plunges the hot metal into oil in order to harden it. The metal piece has a mass of 60 kg and its specific heat is 0.1027 kcal/(kg · °C). He uses 810 kg of oil at 35°C. The specific heat of oil is 0.7167 kcal/(kg · °C). Once the metal is immersed in the oil, the temperature reaches an equilibrium value of 39°C. How hot was the forged metal piece just before he plunged it into the oil?

Answers

Answer:

The temperature of the metal is  \(T_m = 376.8 ^o C\)

Explanation:

From the question we are told that

     The mass of the metal is  \(M = 60 \ kg\)

     The specific heat of the metal is  \(c_p = 0.1027 kcal/(kg \cdot ^oC)\)

       The mass of the oil is \(M_o = 810 \ kg\)

       The temperature of the oil is  \(T_o = 35^oC\)

       The specific heat of oil is  \(c_o = 0.7167 kcal/(kg \cdot ^oC )\)

       The equilibrium temperature is \(T_e = 39 ^oC\)

According to the law of energy conservation

     Heat lost by metal  =  heat gained by the oil

So  

   The quantity  of heat lost by the metal is mathematically represented as

               \(Q = - Mc_p \Delta T\)

=>            \(Q = -Mc_p (T_m - T_c)\)

Where \(T_ m\)  the temperature of metal before immersion

The negative sign show heat lost

The quantity  of gained t by the metal is mathematically represented as      

           \(Q = M_o c_o \Delta T\)

=>        \(Q = M_o c_o (T_c - T_o)\)

So  

         \(Mc_p (T_m - T_c) = M_o c_o (T_c - T_o)\)

substituting values

          \(- 60 * 0.1027 (T_m - 39) = 810 * 0.7167 * (39 - 35)\)

=>       \(T_m = 376.8 ^o C\)

         

Question 3: Chapter 3, Problem 42 from Serway. This also appears on your written homework. What does it mean for an object to move upstream? What about downstream? You need to be sure you understand these before you can work this problem. It will definitely help to draw diagrams for this problem.

A river has a steady speed of vs. A student swims upstream a distance d (measured along the bank of the river) and back to their starting point. (a) If the student can swim at a speed of v in still water, how much time, tup, does it take the student to swim upstream a distance d? Express the answer in terms of d, v, and vs. (b) Using the same variables (v, vs, and d), how much time, tdown, does it take to swim back downstream to the starting point? (c) Sum the answers found in parts (a) and (b) and show that the total time, ta, required for the whole trip can be written as


(d) How much time, tb, does the trip take in still water? (e) Which is larger, ta or tb ? Is it always larger? Justify your answer algebraically.

Answers

I believe the answer is A for this answer

Samir is waiting for a slow reaction to finish. What is the best way to make the reaction go faster?

Question 12 options:

Put it in the fridge where it is cold


Cover it with a blanket so it's dark


Warm it up on the stove


There is nothing you can do to change the speed of the reaction

Answers

In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.

Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct

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Solve this question please A.S.A.P ⁉️
No spamming ❗​

Solve this question please A.S.A.P No spamming

Answers

Answer:

Here given is :-

Velocity (u) = 10m/sGravity (g) = 10 m/s²Height (h) = ?

Explanation:

v² - u² = 2gh

0² - 10² = 2 × (-10) × h

-100 = -20 h

\(h = \frac{ - 100}{ - 20} = 5m\)V = u + gt0 = 10 - 10t10t = 10\(t = \frac{10}{10} = 1 \: sec\)Total time = 2 sec

Answer:

See below

Explanation:

vf = vo + at        when it reaches top vf = 0    vo = 10m/s      a = -9.81 m/s^2

0 =   10  + (-9.81) t  

t = 1.02 seconds to reach max

time up = time down   so    roundtrip =  2.04 seconds

HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?

Answers

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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We know the mass and luminosity of the star. We also know the mass of the spacecraft and the area of its stellar sail. We must find the net force exerted on the spacecraft, as well as the direction of its acceleration. We are asked to find both the net force exerted on the spacecraft and the direction of the acceleration. Which principle is best used to find the direction of the acceleration once the net force has been found

Answers

Answer:

Newton's principle of force, the variation of the momentum and the acceleration have the same direction

Explanation:

To find the force exerted by the star on the sail of the ship, the expression of the momentum of the radiation is used, which in the case of a total reflection

            p = \(\frac{2U}{c}\)

where p is the momentum and U the incident energy and c the speed of light.

The strength I could get from

            F = \(\frac{dp}{dt}\)

the direction of the acceleration is the direction of the momentum, therefore the principle to find the acceleration of is Newton's principle of force, the variation of the momentum and the acceleration have the same direction.

. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification

Answers

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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In the following circuit, find the potential difference (magnitude) between points A and B.

In the following circuit, find the potential difference (magnitude) between points A and B.

Answers

The potential difference between points A and B in the circuit is 12 V.

How to determine potential difference?

To find the potential difference between points A and B in the given circuit, determine the total voltage across the circuit.

From the information provided, there are four resistors labeled as 12 Ω each. Assuming these resistors are connected in series, the total resistance in the circuit is 12 Ω + 12 Ω + 12 Ω + 12 Ω = 48 Ω.

Next, determine the current flowing through the circuit. The voltage is given as 24 V.

Using Ohm's Law (V = IR), calculate the current:

I = V / R

I = 24 V / 48 Ω

I = 0.5 A

Since the resistors are connected in series, the current remains the same throughout the circuit.

Finally, to find the potential difference between points A and B, multiply the current by the resistance between those points:

V_AB = I × R_AB

V_AB = 0.5 A * 24 Ω

V_AB = 12 V

Therefore, the potential difference between points A and B in the circuit is 12 V.

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