6th grade math help me pleaseeee

Answer:

r= 15 yd means that if they give you an equation in that question with r you plug in 15 for r.

Answer:

Third choice: \( y \le \dfrac{2}{3}x + \dfrac{1}{5} \)

Step-by-step explanation:

First, we find the equation of the line.

y = mx + b

b = y-intercept = 0.2 = 1/5

y = mx + 1/5

m = rise/run = 2/3

y = 2/3 x + 1/5

The line is solid, and the shading is below the line, so the inequality is

\( y \le \dfrac{2}{3}x + \dfrac{1}{5} \)

Answer:

C. y = 2/3x + 1/5

Step-by-step explanation:

Well lets look at the features,

Solid line and shaded down meaning it is y ≤.

So we can cross out choices A. B. D.

Do the answer is C. because it’s the only one that starts with y≤.

The limit of the given expression as x approaches 1 is 0.

To evaluate the limit of the given expression as x approaches 1, we can use L'Hopital's rule, which states that if the limit of a quotient of functions is of the form 0/0 or ±∞/±∞, then the limit can be found by taking the derivative of the numerator and denominator and evaluating the new quotient at the same point.

Using L'Hopital's rule on the given expression, we get:

lim x→1 [5x/(x-1) - 5/x] = lim x→1 [(5x^2 - 10x + 5)/(x^2 - x)]

Plugging in x = 1 directly to this expression, we get:

lim x→1 [(5x^2 - 10x + 5)/(x^2 - x)] = (5 - 10 + 5)/(1 - 1) = 0/0

Since the limit is still in an indeterminate form, we can apply L'Hopital's rule once again:

lim x→1 [(5x^2 - 10x + 5)/(x^2 - x)] = lim x→1 [(10x - 10)/(2x - 1)] = 0

Therefore, the limit of the given expression as x approaches 1 is 0.

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Answer: t=2

Step-by-step explanation:

\(1=t+\sqrt{2t} -3\\1-1=t+\sqrt{2t}-3-1\\0= t+\sqrt{2t} -4\\Thus,\\t+\sqrt{2t} -4=0\\Let`s\ \sqrt{t} =x\geq 0\\\Rightarrow\ x^2+\sqrt{2} x-4=0\\x^2-\sqrt{2} x+2\sqrt{2}x-4=0\\ x(x-\sqrt{2})+2\sqrt{2} ( x-\sqrt{2})=0\\ (x-\sqrt{2})(x+2\sqrt{2})=0\\\\x-\sqrt{2} =0\\ x-\sqrt{2}+\sqrt{2}=0+\sqrt{2} \\ x=\sqrt{2}\\ \Rightarrow\ t=(\sqrt{2})^2\\ t=2\\\\x+2\sqrt{2} =0\\x+2\sqrt{2} -2\sqrt{2} =0-2\sqrt{2} \\x=-2\sqrt{2} \notin(x\geq 0)\)

Answer:

6/13

Step-by-step explanation:

Of the 13 students who do not own a graphing calculator, 6 are girls.  The probability is 6/13.

Answer:

THIS MAKES NO SENSE WHATS SO EVER

Step-by-step explanation:

For the whole numbers:

24

26

23

25

21

46

63

57

75

91

1. 24 and 23.8

2. 26 and 25.7

3. 23 and 22.8

4. 25 and 24.8

5. 21 and 20.9

6. 46 and 46.3

7. 64 and 63.7

8. 56 and 56.5

9. 75 and 74.6

10. 91 and 90.7

When rounding, whether it's a whole number or a decimal, you would round up if the number next to it is 5 and up. You wouldn't change the number next to it if it's below 5.

If you have any further question, please reach out to me :)

Answer:

\(\huge\boxed{\cot\theta=\dfrac{1}{xy}}\)

Step-by-step explanation:

\(\bold{METHOD\ 1}\)

\(\sin\theta=x\\\\\sec\theta=y\\\\\cot\theta=?\\\\\text{We know:}\\\\\sec x=\dfrac{1}{\cos x};\ \cot x=\dfrac{\cos x}{\sin x}\\\\\sec\theta=y\to\dfrac{1}{\cos \theta}=y\to\dfrac{\cos\theta}{1}=\dfrac{1}{y}\to\cos\theta=\dfrac{1}{y}\\\\\cot \theta=\dfrac{\frac{1}{y}}{x}=\dfrac{1}{xy}\)

\(\bold{METHOD\ 2}\)

\(\text{We know}\\\\\tan x=\dfrac{\sin x}{\cos x}\\\\\cot x=\dfrac{\cos x}{\sin x}=\dfrac{1}{\tan x}\\\\\sec x=\dfrac{1}{\cos x}\\\\\text{therefore}\\\\(sin x)(\sec x)=(\sin x)\left(\dfrac{1}{\cos x}\right)=\dfrac{\sin x}{\cos x}=\tan x\\\\\dfrac{1}{(\sin x)(\sec x)}=\dfrac{1}{\tan x}=\cot x\)

\(\\\sin \theta=x;\ \sec\theta=y\\\\\text{substitute}\\\\\cot\theta=\dfrac{1}{xy}\)

(a) The probability that there are no calls within a 30-minute interval is approximately 0.3680. (b) 0.4689. (c) 0.2160. (d)47.60 minutes.

(a) To find the probability that there are no calls within a 30-minute interval, we can use the exponential distribution. The parameter λ (lambda) for the exponential distribution is equal to 1/mean.

Given that the mean time between calls is 16 minutes, we can calculate λ as:

λ = 1/16

Now, let's calculate the probability using the exponential distribution formula:

P(no calls within 30 minutes) = e^(-λt)

P(no calls within 30 minutes) = e^(-(1/16) * 30)

P(no calls within 30 minutes) ≈ 0.3680

So, the probability that there are no calls within a 30-minute interval is approximately 0.3680.

(b) To find the probability that at least one call arrives within a 10-minute interval, we can use the complementary probability. The complementary probability is 1 minus the probability of no calls within the interval.

P(at least one call within 10 minutes) = 1 - P(no calls within 10 minutes)

P(at least one call within 10 minutes) = 1 - e^(-λt)

P(at least one call within 10 minutes) = 1 - e^(-(1/16) * 10)

P(at least one call within 10 minutes) ≈ 0.4689

So, the probability that at least one call arrives within a 10-minute interval is approximately 0.4689.

(c) To find the probability that the first call arrives within 5 and 10 minutes after opening, we can subtract the probability of no calls within 10 minutes from the probability of no calls within 5 minutes.

P(first call within 5-10 minutes) = P(no calls within 10 minutes) - P(no calls within 5 minutes)

P(first call within 5-10 minutes) = e^(-λ*10) - e^(-λ*5)

P(first call within 5-10 minutes) ≈ 0.2160

So, the probability that the first call arrives within 5 and 10 minutes after opening is approximately 0.2160.

(d) To determine the length of an interval of time such that the probability of at least one call in the interval is 0.90, we need to find the value of t that satisfies the equation:

P(at least one call within t minutes) = 0.90

Using the exponential distribution formula:

1 - e^(-λt) = 0.90

e^(-λt) = 1 - 0.90

e^(-λt) = 0.10

Taking the natural logarithm of both sides:

-λt = ln(0.10)

t = ln(0.10) / -λ

Substituting λ = 1/16:

t ≈ 47.5957 minutes

So, the length of the interval of time such that the probability of at least one call is 0.90 is approximately 47.60 minutes.

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Answer:

x=17/1/7, y=8/4/7

Step-by-step explanation:

x:

30/30+x=14/22

420+14x=660

14x+240

x=17/1/7

y:

14/22=15/15+y

210+14y=330

14y=120

y=8/4/7

Answer:

x = \(17\frac{1}{7}\)

y = \(8\frac{4}{7}\)

Step-by-step explanation:

1. Lines DE and AC are parallel.

Therefore, by the Triangle Proportionality Theorem:

\(\frac{SideBD}{SideAD} = \frac{SideBE}{SideEC}\)
= \(\frac{30}{x} = \frac{15}{y}\)

Rearranging:

\(\frac{30}{15} = \frac{x}{y}\)

\(2 = \frac{x}{y}\)

Cross-multiplication is applied:

\((x)(1) = (2)(y)\)

\(x = 2y\) —-(equation i)

2. ΔBDE and ΔBAC are similar triangles

Which means:

\(\frac{SideBD}{SideDE} = \frac{SideBA}{SideAC}\)

\(\frac{30}{14} = \frac{30 + x}{22}\)

Cross-multiplication is applied

\((14)(30 + x) = (30)(22)\)

\(420 + 14x= 660\)

\(14x = 660 - 420\)

\(14x = 240\)

\(x = \frac{240}{14}\)

Reduce the numerator and denominator by the Highest Common Factor (2):

∴x = \(\frac{120}{7}\)

     =\(17\frac{1}{7}\)

Substitute the value of x in (equation i) to solve for y:

\(\frac{120}{7} = 2y\)

\(y = \frac{120}{7(2)}\)

∴y = \(\frac{60}{7}\)

    = \(8\frac{4}{7}\)

Marcus needs to combine the like terms that have the same variable and exponent in order to finish rewriting the polynomial.

When rewriting a polynomial by combining like terms, Marcus needs to look for terms that have the same variable and exponent. Like terms are terms that can be added or subtracted because they share these common characteristics. For example, in the polynomial\(3x^2\)- 4x - 7, Marcus would need to combine the terms \(3x^2\) and \(5x^2\) since they have the same variable (x) and exponent (2). After combining these terms, the polynomial can be rewritten as (\(3x^2+5x^2\) + (2x - 4x) - 7.

Marcus would still need to combine the terms \(3x^2\\\)and \(5x^2\), as well as the terms 2x and -4x. By adding or subtracting these like terms, Marcus will be able to simplify the polynomial further. Once all the like terms are combined, the polynomial will be fully rewritten in a simplified form, with no more terms that can be combined.

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Answer:

0.05 metrs = 5 cetimeters

Step-by-step explanation:

1 meter = 100 centimeters

0.05 meters = 0.05 * 100 = 5 centimeters

In ANOVA with 4 groups and a total sample size of 44, the computed F statistic is 2.33 and the p-value is d. cannot tell - it depends on what the SSE is. Therefore, the correct option is option d.

In an ANOVA with 4 groups and a total sample size of 44, with a computed F statistic of 2.33, to determine the p-value, we need to consider the degrees of freedom for both the numerator (between groups) and the denominator (within groups).

Step 1: Calculate the degrees of freedom.
Degrees of freedom between groups (DFb) = Number of groups - 1 = 4 - 1 = 3
Degrees of freedom within groups (DFw) = Total sample size - Number of groups = 44 - 4 = 40

Step 2: Use an F-distribution table or an F-distribution calculator to determine the p-value.
With DFb = 3 and DFw = 40, you can look up the critical F value in an F-distribution table or use an online F-distribution calculator.

Based on the provided information, we cannot directly tell the p-value without consulting an F-distribution table or calculator. However, you can follow these steps to determine the p-value for the given F statistic of 2.33.

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The sequences of transformations could be applied is

A point, line, or geometric figure can be transformed in one of four ways, each of which affects the shape and/or location of the object. Pre-Image refers to the object's initial shape, and Image, after transformation, refers to the object's ultimate shape and location.

From the picture we have, g(x) = -3x - 1

Parent function: f(x) = x

1)  Reflect over the y-axis gives g(x) = -x

Vertically stretch by a factor of 3 gives g(x) = -3x

Shift down 1 unit gives g(x) = -3x - 1

2) Shift left 2 units: g(x) = x+2

Reflect over x-axis: g(x) = -x-2

Vertically stretch by a factor of 3 gives g(x) = -3x -6

3) Shift right 1 unit: g(x) = x-1

Reflect over the y-axis: g(x) = -x-1

Vertically stretch by a factor of 3: g(x) = -3x -3

4) Shift right 1 unit: g(x) = x-1

Reflect over the x-axis: g(x) = -x+1

Vertically stretch by a factor of 3: g(x) = -3x +3

5) Reflect over the x-axis: g(x) = -x

Vertically stretch by a factor of 3: g(x) = -3x

Shift down 1 unit: g(x) = -3x - 1

6) Shift down 1 unit: g(x) = x - 1

Reflect over the x-axis: g(x) = -x + 1

Vertically stretch by a factor of 3: g(x) = -3x + 3

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Answer:

40.8

Step-by-step explanation:

60% = 60/100

60/100 * 68

4080/100

40.8

Answer:

40.8

Step-by-step explanation:

d/68=60/100

60×68=4080

d×100=100d

4080=100d

4080÷100=40.8

100d÷100=d

d=40.8

hope this helps

Answer: 770

Step-by-step explanation:

It would= 10 x 77 and 77 x 10 it=770 because you always add a zero like this.

7 x 10=70

70 x 10=700

700 x 10=7,000

7,000 x 10=70,000

Or another example take 8

8 x 10=80

8 x 100=800

8 x 1,000=8,000

8 x 10,000=80,000

Hope it helps have a great day:)

The size of the set |E ∩ B| is 2, and the size of the set |B| is 3.

There are six possible outcomes when two dice are thrown:
{(1,1), (1,2), (1,3), (2,1), (2,2), (2,3), (3,1), (3,2), (3,3), (4,1), (4,2), (4,3), (5,1), (5,2), (5,3), (6,1), (6,2), (6,3)}.

Out of these 18 outcomes, the following three satisfy the event E (both dice are odd): (1,3), (3,1), and (3,3).
The following outcomes satisfy event B (the blue die is odd): (1,1), (1,3), (2,1), (2,3), (3,1), and (3,3).

Therefore, the size of the set |E ∩ B| is 2 (the two outcomes that satisfy both events are (1,3) and (3,1)), and the size of the set |B| is 3 (three outcomes satisfy the event B).

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Answer:

W = 7

Step-by-step explanation:

From the two column proof concept we can say that:

1) It is one way to organize a proof in geometry.

2) The statements are on the first column

3) Statement 2: ∠MOK ≅ ∠TOK

Reason 2: Definition of Angle Bisector

Statement 3: OK ≅ OK

Reason 3: Reflexive Property of Congruency

Statement 4: OM ≅ OT

Reason 4: Given

1) A two column proof is the most common formal proof in elementary geometry courses, where the known or derived statements are written in the left column, and the reasons why each statement is known or valid are in the right column next to it. is written.

Thus, it is one way to organize a proof in geometry.

2) The statements are on the first column while the reasons are on the second column

3) Statement 2: ∠MOK ≅ ∠TOK

Reason 2: Definition of Angle Bisector

Statement 3: OK ≅ OK

Reason 3: Reflexive Property of Congruency

Statement 4: OM ≅ OT

Reason 4: Given

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Answer:

Perimeter is 30 and area is 32

Step-by-step explanation:

7+8+7+8= 30 and A= BH so 8 x 4 = 32

For a two-tailed test, the p-value is the probability of obtaining a value for the test statistic at least as unlikely as or more unlikely than that provided by the sample.

What is two tailed test ?

In statistics, a two-tailed test is a procedure that determines whether a sample is greater than or less than a specific range of values by using the critical area of a distribution that is two-sided.

Main body:

Hence the p-value is the probability of obtaining a value for the test statistic at least as unlikely as or more unlikely than that provided by the sample.

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Answer:

Volume = 261.8 cm³

Surface area = 254.2 cm²

Step-by-step explanation:

To calculate the volume of the cone, we have to use the following formula:

\(\boxed{V = \frac{1}{3} \pi r^2 h}\),

where:

V ⇒ volume

r ⇒ radius = 5 cm

h ⇒ height = 10 cm

Using the above formula and the provided measures, we get:

V = \(\frac{1}{3}\) × π × (5)² × 10

    = \(\frac{1}{3}\) × π × 25 × 10

      = 261.8 cm³

In order to calculate the surface area of the cone, we have to use the following formula:

\(\boxed{SA = \pi r^2 + \pi r l}\)

where:

SA ⇒ surface area

r ⇒ radius = 5 cm

l ⇒ slant length = \(\sqrt{r^2+h^2}\) = \(\sqrt{5^2+10^2}\) = 5√5 cm

Using the formula,

SA = π × (5)² + π × 5 × 5√5

     = π × 25 + π × 25√5

     = 254.2 cm²

The statement "A histogram with the hills to the far left means the image is overexposed" is not accurate. In fact, a histogram with the hills to the far left indicates that the image is underexposed, not overexposed.

A histogram is a graphical representation of the distribution of pixel values in an image. It displays the frequency of occurrence of different tonal values. The horizontal axis represents the tonal values, while the vertical axis represents the frequency or number of pixels.

When the hills of the histogram are concentrated towards the left side, it means that a significant portion of the image has darker or lower tonal values. This indicates an underexposed image, where the exposure settings were insufficient to capture enough light, resulting in a darker overall appearance.

Conversely, an overexposed image would have the hills of the histogram concentrated towards the right side, indicating that a significant portion of the image has brighter or higher tonal values.

Therefore, the correct interpretation is that a histogram with the hills to the far left means the image is underexposed, not overexposed.

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Answer:

y + 4t + 5y + 3 (3t + 9y) = 13t + 33y

9 (y + 4y + 5)​ = 45y + 45

Answer:

s=5

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

s=5

Answer:

s = 5

Step-by-step explanation:

1.52(s + 3) − 2.61 = 9.55

solve the brackets first

1.52s + 4.56 − 2.61 = 9.55

1.52s + 1.95 = 9.55

1.52s = 9.55 -  1.95

1.52s = 7.6

s = 7.6 / 1.52

s = 5

Let's Cross-Check

1.52 (5 + 3) − 2.61

7.6 + 4.56  − 2.61

7.6  + 1.95

= 9.55

CROSS-CHECKED

Answer:

they are good I think I don't see why they wouldn't be

Expanding the matrix multiplication, we have k + 1 + 0 = 0, k + 2 = 2, 3 = -3, and k + 5 = 0. However, the equation 3 = -3 has no solution.

Let's calculate the matrix multiplication on the left-hand side of the equation. Expanding the multiplication, we obtain:

[k + 1 + 0] [k + 0 + 2] [1] = [0 2 -3]

[1 + 0 + 2] [k + 1 + 4] [1]

Simplifying, we have:

[k + 1] [k + 2] [1] = [0 2 -3]

[3] [k + 5] [1]

To determine if there are values of k that satisfy the equation, we compare the corresponding entries on both sides. From the first row, we have k + 1 = 0 and k + 2 = 2. Solving these equations gives k = -1 and k = 0, respectively.

However, when we consider the second row, we have 3 = -3, which has no solution. Therefore, there are no values of k that satisfy the given equation. This means that the equation [1 1 0] [k] [k 1 1] [1 0 2] [1] = 0 [0 2 -3] [1] has no solution.

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