7. Two campers dock a canoe. One camper steps onto the dock. This camper has a mass of 80 kg and moves forward at 4.0 m/s. With what speed and direction do the canoe and the other camper move if their combined mass is 110 kg?

Distance traveled in a given amount of time is equal to the average speed. utilizing the formula s=ut+21at2s=510+212102s=50+100=150m.

By understanding how far an object is from us, we may calculate its actual size. It is possible to calculate the space that an object takes up in the sky. The actual size of an object can then be determined by taking into account its distance. The further away something is, the smaller it appears.

A common metric length from around three feet, 3 inches is called a metre. This proves that in the metric system, a meter is a measuring unit. Objects up to one meter in length include yardsticks, baseball bats, and guitars. Distances in sporting events like run and swimming are also measured in meters.

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Answer:

i would want to be a dog or a cat

Explanation:

there just funny

According to this equation, so f = 3.29 x 1014 Hz. The light therefore has a frequency of 3.29 x 1014 Hz. The wavelength range of visible light is roughly 400–700 nm, and its frequency range is roughly 400–800 tHz.

The frequencies used by white LED lighting devices are a combination of 474 terahertz, 535 terahertz, and 638 terahertz. White LED technology has made it possible to create inexpensive, energy-efficient lighting that may be utilised in a range of applications, from desk lamps to street lamps.

The capacity to render different kinds of light visible for human sight makes light energy a type of kinetic energy. Light is referred to as an electromagnetic radiation that is produced by hot objects like the sun, lasers, and lightbulbs. Photons, which are tiny energy packets, are present in light.

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The factor that has the greatest effect on a community's stores of fresh water can vary depending on the specific circumstances and location. However, some common factors that can significantly impact fresh water availability include:

Climate and Precipitation: The amount and pattern of rainfall or snowfall in a region greatly affect the replenishment of fresh water sources such as rivers, lakes, and groundwater. Geography and Topography: The presence of mountains, hills, or other physical features can affect the availability and distribution of fresh water resources within a community. Population and Water Demand: The size of the population and the demand for water within a community can put stress on available freshwater supplies. Water Management and Infrastructure: The efficiency of water management practices, including storage, distribution, and treatment systems, can greatly impact the availability and access to fresh water. Regarding submersible vehicles exploring and studying the deep ocean zone, the hazard they must overcome is extreme pressure. As they descend into the deep ocean, the pressure increases significantly due to the weight of the water above. Submersible vehicles must be designed and constructed to withstand these high pressures to ensure the safety of the occupants and the integrity of the vehicle's structure.

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The speed of the first car is 52 mph.

The speed of the second car is 40 mph.

Let's use "x" mph to represent the second car's speed. We can express the first car's speed as "x + 12" mph because it is 12 mph faster. According to our knowledge, the first car travelled 234 miles, while the second car covered 180 miles.

The relationship between speed and distance travelled is inversely proportional. As a result, the proportion of distances covered by the two vehicles will match the proportion of their speeds:

234 / 180 = (x + 12) / x

To solve this equation, we can cross-multiply:

234x = 180(x + 12)

Expanding the equation:

234x = 180x + 2160

Rearranging terms:

234x - 180x = 2160

54x = 2160

Dividing both sides by 54:

x = 40

Therefore, the speed of the second car is 40 mph.

To find the speed of the first car, we can substitute the value of x back into the expression "x + 12":

x + 12 = 40 + 12 = 52

Hence, the speed of the first car is 52 mph.

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Answer: v = 43.98 m/s

Explanation: 22 + 15.7x1.4 = 43.98.

Hope this helps!

Answer:

mass- the amount of matter in an object

balance- tool used to measure mass

scale- a tool used to measure weight

weight- the downward pull on an object due to gravity

Answer:

The mass of a single paper  is approximately 0.047 lb/paper which in SI Units is approximately 21.77  g/paper

Explanation:

The given information on the size and the weight of paper are;

The mass of a box of 500 sheets of paper = 24 lb

The number of sheets in the paper = 500 sheets

The dimensions of the paper = 17 in. × 22 in., which is equivalent to  43.18 cm × 55.88 cm

The mass of a single paper = The mass of the box of paper/(The number of sheets of paper present in the box)

The mass of a single paper = 24 lb/500 = 0.047 lb/paper

Given that 1 lb = 453.6 g, we have;

0.047 lb/paper = 0.047 lb/paper×453.6 g/(lb) = 21.77  g/paper

The mass of a single paper  = 0.047 lb/paper = 21.77  g/paper.

Answer:

5.349g

Explanation:

The other post forgot about the differing answer. They wanted the answer for 21.59cm*27.94cm. when they get that 0.047=43.18cm*55.88cm we can set a ratio;

0.047/43.18*55.88=X/21.59*27.94=0.01179

then we do the same;

0.01179lb(453.6g/1lb)=5.349

(*the number is bigger but we have 4 sig figs*)

Answer:

Relative to the ground, the velocity of the aircraft is 240 km/hr

Explanation:

Relative velocity is different from normal velocity;

When 2 objects are moving in opposite directions towards each other, they will appear to be faster than they actually are;

This is known as the relative velocity;

The information tells us we have the aircraft moving 320 km/hr northwards relative to the wind;

The wind is in the opposite direction at 80 km/hr;

R = relative velocity of the aircraft

v = actual velocity of the aircraft

w = velocity of the wind

R = v + w

Note: if the wind was moving in the same direction, the formula would be R = v - w

320 = v + 80

v = 320 - 80

v = 240

The velocity relative to the ground is simply the actual velocity as the ground doesn't move;

So, relative to the ground, the velocity of the aircraft is simply 240 km/hr

The work done in pulling the crate 1000 m at constant velocity is 300000 Joules.

Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.

The friction force prevents any two surfaces of objects from easily sliding over each other or slipping across one another. It depends upon the force applied to the object.

As given in the problem a 6000 N crate is pulled across an icy surface. the coefficient of kinetic friction is 0.05.

The frictional force responsible for the work don

Frictional force = μMg

                         =0.05× 6000

                         = 300 N

Work done = force  × displacement

                  = 300 ×1000

                  = 300000 Joules

Thus, the work done in pulling the crate 1000 m at constant velocity would be 300000 Joules.

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Answer:

your answer would be c !

Explanation:

Answer:

1.0x10^7 Pa or 1,460 psi.

Explanation:

2000N is applied to an area of (0.02m)*(0.01m).  Pressure is in units of N/m^2.  1 N/m^2 is 1 Pascal (Pa).

 (2000N)/(0.002 m^2) = 1.0x10^7 Pa

This is equal to 1,460 psi

The Rayleigh length and Rayleigh range \(Z_{R}\) are calculated: Here is the light's λ wavelength, and n is really the refraction index. This same width w of the beam is 1.414 larger at a distance from the waist equitable.

To the Rayleigh range \(Z_{R}\) that it is at the focus in W = \(W_{0}\) which, this same beam waist. A laser beam's Rayleigh length (and otherwise Rayleigh range) is the distance out from the beam waist (within the propagation path) where the wave radius is elevated by the squared of 2.

This means that the toggle area of a circular beam is doubled at this point. The Rayleigh beam concept takes into account rotational inertia effects that the Euler-Bernoulli beam theory does not.

As a result, the model is applied to a greater range of regimes. Waves in well before Rayleigh beams on elastomer fundaments are given special consideration.

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Answer:

A

Explanation:

A has the longest wavelength

If the hole is smaller than the wavelength, then the wavefronts coming out of the hole will be circular. Therefore, longer wavelengths diffract more than shorter wavelengths. The higher the diffraction, the easier you could see

Answer:

A student is running at her top speed of 5. 4m/s to catch a bus.

Explanation:

Thats to fast

Answer:

When a proton is placed directly in the path of the proton cannon, it will experience a strong electromagnetic force. The proton cannon emits a beam of protons at high energy and velocity. When the proton in the path of the cannon interacts with the beam, there will be a collision between the two protons.

During the collision, the protons may undergo a process called scattering, where they change direction and momentum. The exact outcome of the collision depends on the energy and angle of the incoming proton, as well as the properties of the target proton. It is possible that the protons may scatter off each other, transferring energy and momentum in the process.

In some cases, the collision may result in the absorption of the incoming proton by the target proton. This can lead to the formation of a more massive particle or the emission of other particles. The specifics of the interaction will depend on the energy and conditions of the proton cannon and the characteristics of the protons involved.

Overall, placing a proton directly in the path of a proton cannon will result in a collision and potential scattering or absorption of the protons, causing changes in their momentum and possibly leading to the creation of other particles.

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The energy change caused by an endothermic chemical reaction is the absorption of thermal energy. So, option B.

Endothermic reactions are defined as, those reactions in which the reactants take in heat energy from the environment to create products.

Here,

The endothermic reactions lower the temperature of their surrounding area, thereby creating a cooling effect.

When bonds in the reactants are broken, more energy is absorbed than is released when new bonds are generated in the products. This is known as an endothermic reaction.

A drop in the temperature of the reaction mixture is a characteristic of endothermic reactions.

In endothermic reactions, the enthalpy of the products of the reaction is greater than that of the reactants. Energy is absorbed from the surroundings.

Hence,

The energy change caused by an endothermic chemical reaction is the absorption of thermal energy.

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The displacement of the student is `√34`, and the angle between the displacement vector and the eastward direction is approximately 53.1°.

A vector quantity that describes the distance and direction between two points is known as displacement. The starting point and the final point are both considered in this measurement. Displacement is different from distance since it not only tells us how far two points are from one another, but also the direction in which they are located.

First, let's take a look at the student's eastward travel. Since the student walked three blocks east, the eastward vector component will have a magnitude of 3 and will be directed to the right.Next, let's take a look at the student's northward travel. Since the student walked 4 blocks north, the northward vector component will have a magnitude of 4 and will be directed upward.Finally, we'll look at the student's westward travel.

Since the student walked three blocks west, the westward vector component will have a magnitude of 3 and will be directed to the left.Combining the eastward, northward, and westward components, we get a net displacement vector. We may use the Pythagorean Theorem to calculate the magnitude of this vector, as well as the tangent function to determine its direction.

The Pythagorean Theorem states that: `c² = a² + b²`, where `c` is the hypotenuse of a right triangle, and `a` and `b` are the other two sides. The magnitude of the displacement vector is equivalent to the length of the hypotenuse of a right triangle formed by the eastward, northward, and westward vector components. Therefore, the magnitude of the displacement vector is: `√(3² + 4² + 3²) = √34`

The inverse tangent function (`tan⁻¹`) must now be used to calculate the angle between the displacement vector and the eastward direction. In general, if a vector is aimed in the first quadrant, the angle between the vector and the positive x-axis (eastward direction) is the inverse tangent of the vector's y-component divided by its x-component. We have to use the other three quadrants and make adjustments for negative values when the vector is aimed in the other quadrants.

However, in this case, we can see that the displacement vector is directed to the north, west, and south. We can picture it as moving three blocks eastward, then moving four blocks northward, and finally moving three blocks westward. This forms a parallelogram in which the displacement vector represents the diagonal that bisects the parallelogram's opposite corners.

Since this diagonal is split into two triangles by its perpendicular bisector (the eastward direction, in this case), we can use the triangle formed by the vector's eastward and northward components to calculate the displacement vector's angle with the eastward direction. We have a right triangle with opposite and adjacent sides of length 4 and 3, respectively, in this triangle. The inverse tangent of the ratio of the opposite side to the adjacent side is the angle we want. We get: `θ = tan⁻¹(4/3) ≈ 53.1°`.

Therefore, the displacement of the student is `√34`, and the angle between the displacement vector and the eastward direction is approximately 53.1°.

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The same-side exterior angles are not congruent, they are supplementary. The same side exterior angles are formed and they have a sum of 180 degrees.

Congruent refers to having the same precise size and shape. Even if we flip, turn, or rotate the forms, their shape and size need to remain constant. If it is possible to superimpose one geometric figure onto the other such that they correspond throughout, then the two are said to be congruent, or to be in the relation of congruence.

In general relativity, a congruence (more precisely, a congruence of curves) is the collection of integral curves of a (never vanishing) vector field in a four-dimensional Lorentzian manifold that is used to physically represent spacetime.

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Answer:

v = 31.32 [m/s]  

Explanation:

To solve this problem we must use the principle of energy conservation, which tells us that potential energy is converted into kinetic energy or vice versa. The potential energy can be calculated by the product of mass by gravity by height.

\(E_{pot}=m*g*h\)

where:

Epot = potential energy [J]

m = mass = 25 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 50 [m]

Now replacing:

\(E_{pot}=25*9.81*50\\E_{pot}= 12262.5[J]\)

When the rock falls the potential energy is converted into kinetic energy.

\(E_{pot}=E_{k}\\E_{k}=\frac{1}{2}*m*v^{2}\)

where:

Ek = kinetic energy [J]

v = velocity [m/s]

Now clearing v:

\(v^{2} =\frac{E_{k}*2}{m}\\v=\sqrt{(2*12262)/25}\\v = 31.32 [m/s]\)

Answer:

what is the question ? That is only a statement

To determine the corresponding values of the mean velocity (um) and mean temperature (tm), we first need to measure the velocity and temperature at different points in the fluid. We can then calculate the mean velocity and temperature using these measurements.



The mean velocity (um) is the average velocity of the fluid over a given area. It is calculated by dividing the total volume flow rate by the cross-sectional area of the flow. The mean temperature (tm) is the average temperature of the fluid over a given area. It is calculated by taking the average of the temperature measurements at different points in the fluid.

To plot the velocity and temperature distributions, we need to measure the velocity and temperature at different points in the fluid and plot them on a graph. We can then connect the data points to get a visual representation of the distribution.

Whether or not the values of um and tm appear reasonable will depend on the specific system being studied. We would need to compare our results to previous studies or theoretical models to determine if our values are reasonable.

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Using the theories of light year, we got that 57.0 trillion km is  'Barnard's star' away from earth.

Light is the fastest-moving stuff in the our universe. It actually travels at 186,000 miles per second (300,000 km/sec). And thus a light-year is about 5.88 trillion miles (9.46 trillion kilometers).

We know very well that ,

1 light year=9.5 trillion km

Therefore,6 light year=6×9.5 trillion km

               =>6 light year=57.0 trillion km.

Hence, if a light year is approximately 9. 5 trillion km long, 'Barnard's star' is 6 light years away from earth which is equivalent to 57 trillion of kilometres

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The speed of the moving train is approximately 33.5 m/s.

The beat frequency is given by the difference in frequency between the two horns, which is equal to the Doppler shift in frequency due to the motion of the moving train. Using the formula for the Doppler effect, we can solve for the speed of the train:

\(f_b = f_s\dfrac{(v + v_o)}{(v + v_s)}\)

where \(f_b\) is the beat frequency, \(f_s\) is the horn frequency, v is the speed of sound, \(v_o\) is the observer's speed, and \(v_s\) is the speed of the source.

We know that \(f_s\) = 410 Hz and \(f_b\) = 35 Hz. The speed of sound in air at standard temperature and pressure is approximately 343 m/s. Since the observer is stationary, \(v_o\) = 0.

Solving for \(v_s\), we get:

\(v_s = \dfrac{(f_s + f_b)}{f_s - 1} \times v\)

\(v_s\) = ((410 Hz + 35 Hz) / 410 Hz - 1) * 343 m/s

\(v_s\) = 33.5 m/s

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The statement that is most likely true about the locations is that location A is farther from the equator than location B ( A )

The average temperature throughout the year is higher in location B then that of location A. The temperature is typically warmer near the equator and is typically cooler near the polar regions.

But some factors such as elevation, precipitation and ocean currents might affect the climate pattern. This change in temperature between equator and polar regions is due to the fact that equatorial regions receive more light and energy from the Sun than the polar regions.

Therefore, the statement that is most likely true about the locations is that location A is farther from the equator than location B ( A )

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(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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The average force the wall exerts on the ball is 180.4 N

From the question given above, the following data were obtained:

We'll begin by calculating the impulse. This can be obtained as follow:

I = m(v + u)

I = 0.055 (19 + 22)

I = 0.055 × 41

I = 2.255 Ns

I = Ft

2.255 = F × 0.0125

Divide both side by 0.0125

F = 2.255 / 0.0125

F = 180.4 N

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