A 10 ft chain weighs 25 lb and hangs from a ceiling find the work done in lifting the lower end of t
Answers
The work done in lifting the lower end of the 10-ft chain to the ceiling so that it is level with the upper end is 257 ft-lb.
Determine the work done?To calculate the work done, we need to consider the weight of the chain. The weight of the chain can be expressed as force times distance. In this case, the weight is given as 25 lb and the distance is 10 ft.
Therefore, the work done is 25 lb * 10 ft = 250 ft-lb.
However, this calculation only accounts for the work done to lift the chain vertically. Since the chain needs to be lifted to the ceiling and brought to the same level as the upper end, we need to consider the additional work done to raise the chain horizontally.
As the chain is being lifted, its length increases, and this additional length contributes to the horizontal displacement. The increase in length is equal to the hypotenuse of a right triangle, where one side is the initial length of the chain (10 ft) and the other side is the vertical distance the lower end needs to be lifted (10 ft).
Using the Pythagorean theorem, the hypotenuse is √(10 ft)^2 + (10 ft)^2 = √200 ft ≈ 14.14 ft.
Therefore, the total work done is the sum of the work done vertically (250 ft-lb) and the work done horizontally (√200 ft * 25 lb = 5√2 ft-lb). Adding these two values, we get 250 ft-lb + 5√2 ft-lb ≈ 250 ft-lb + 5 * 1.41 ft-lb ≈ 250 ft-lb + 7.07 ft-lb = 257.07 ft-lb.
Rounding to the nearest whole number, the work done is approximately 257 ft-lb.
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Complete question here:
A 10-ft chain weighs 25 lb and hangs from a ceiling. Find the work done (in ft-lb) in lifting the lower end of the chain to the ceiling so that it is level with the upper end.
Related Questions
Please help I'm so lost.
Erbium-165 has a half-life of 10.4 hours. If you start with 1,000 grams of erbium-165, how much time will it take to have 125 grams of erbium-165 left in the sample?
A. 41.6 hours
B. 31.2 hours
C. 10.4 hours
D. 20.8 hours
Answers
If you start with 1,000 grams of erbium-165, the time it will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.
option D is the correct answer.
What is half life?Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.
If you start with 1,000 grams of erbium-165, the time it will take to have 125 grams of erbium-165 left in the sample is calculated as follows;
1,000 ---------- 0 time
500 ----------- 10.4 hours
125 ------------- 20.8 hours
Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.
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A 12 kg object has 500 j of kinetic energy. What is it's speed?
Answers
Answer: 9.13 m/s
Explanation:
Hi there,
The equation for kinetic energy is
\(KE=\frac{1}{2} mv^2\)
With m representing mass and v representing velocity. Before you start a problem, it is very important to check what units you are working with. Mass should always be in kg and velocity in m/s, so it looks like you are all set.
Start by plugging in the given numbers to their respective spots:
\(500.0=\frac{1}{2} (12.0)v^2\)
From there, you can just solve for velocity. It should be 9.13 m/s. Remember to round to your significant figures and keep units consistent.
Hope this helps!
a 0.11 kg tin can is resting on top of a 1.7 m high fence post. a 0.0020 kg bullet is fired horizontally at the can. it strikes the can with a speed of 900 m/s, passes through it, and emerges with a speed of 720 m/s. when the can hits the ground, how far is it from the fence post? disregard friction while the can is in contact with the post.
Answers
A mass of can 0.11 kg rests on a fence post 1.7 m high. a 0.0020 kg bullet is fired horizontally at a can. it hits the can at 900 m/s, passes through it, and emerges at 720 m/s.
when the can hits the ground, it is 1.93 m away from the fence post.
for vertical fall,
d = 0.5*g*t^2
1.7 = 0.5*9.8*t^2
t = 0.589 s
use conservation of momentum to calculate the initial horizontal velocity to tin
mb*vbi = mb*vbf + mt*vt
2*10^-3*900 = 2*10^-3*720 + 0.11*vt
vt = 3.273 m/s
horizontal distance = vt*time
= 3.273 m/s * 0.589 s
= 1.93 m
Answer= 1.93 m
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In your own words, describe how an object's potential energy can be affected by its position.
Answers
Answer:
Explanation:
The higher the object is relative to some defined baseline (like the ground), the greater the potential energy.
Potential Energy = U = mgh
U is directly proportional to h (height of the object), so the greater the h the greater the U.
a simple pendulum consisting of a bob of mass m attached to a string of length l swings with a period t.
Answers
The new period of oscillation if the mass of the bob is reduced by half is \(\frac{T}{\sqrt{2}}\) or T/√2.
Look at the attachment for a complete question. The period of oscillation of the simple pendulum
\(T \:=\: 2 \pi \sqrt{\frac{m}{k}}\)\(T \:=\: 2 \pi \sqrt{\frac{L}{g}}\)where
π = 3.14m = the mass of the bob (kg)k = the rope constant (N/m)L = the length of the swing (m)g = the acceleration due to gravity (m/s²)If we change the mass of the bob and didn't change the rope, the period also will change but the rope constant will not. The ratio of the period between the two condition
m₁ = mT₁ = Tm₂ = 0.50 mT² = 4π²m/k
T₁²: T₂² = m₁ : m₂
T²: T₂² = m : 0.50 m
T²: T₂² = 1 : 0.5
T₂² = 0.5T²
\(T_2 \:=\: \sqrt{0.5T}\)
\(T_2 \:=\: \sqrt{\frac{T}{2}}\)
T₂ = T/√2
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What do psychologists used to assist them in diagnosing abnormal behavior?
Answers
Ok so it usually includes the evaluation of symptom and disorder severity, patterns of symptoms over time number, frequency, and duration of episodes, and the patient's strengths and weaknesses.
consider the titration of 100.0 ml of 0.200 m acetic acid (ka by 0.100 m koh. calculate the ph of the result- ing solution after the following volumes of koh have been added.
Answers
Answer: The pH of the solution after 50.5 mL of 0.100 M KOH has been added is 16.85.
The reaction between acetic acid and potassium hydroxide (KOH) is given by the equation:
CH3COOH + KOH → CH3COOK + H2O.
It can be observed that for every mole of KOH added, one mole of H+ from CH3COOH reacts with one mole of OH- from KOH to produce one mole of H2O. Therefore, after the addition of n moles of KOH, the number of moles of H+ remaining is (0.200 - n) moles (since 0.200 M is the initial concentration of acetic acid). On the other hand, the number of moles of CH3COOK produced is also n moles; thus the final concentration of CH3COOK is n/V (where V is the total volume of the solution).
The reaction produces a salt (CH3COOK), which is neutral. Therefore, the final pH is given by: pH = pKa + log([A-]/[HA]) where A- is CH3COOK and HA is CH3COOH.
To find the pH of the resulting solution after the following volumes of KOH have been added, we need to calculate the number of moles of KOH added, the number of moles of CH3COOK produced, the number of moles of CH3COOH remaining, and the total volume of the solution. Then we can use the Henderson-Hasselbalch equation above to find the pH.
Here are the calculations: Initial number of moles of CH3COOH = M × V = 0.200 × 0.100 = 0.020 moles. For each mole of KOH added, one mole of CH3COOH reacts with one mole of KOH to produce one mole of CH3COOK.Number of moles of KOH added Volume of KOH added (mL)Moles of KOH added0.02 0.00 (initial) 0.000.02 10.10 0.010.02 20.20 0.020.02 30.30 0.030.02 40.40 0.040.02 50.50 0.05Number of moles of CH3COOK produced = number of moles of KOH added = n moles. Concentration of CH3COOK produced = n/V = n/(Vinitial + V added) = n/(0.100 L + V added)
Number of moles of CH3COOH remaining = initial number of moles - number of moles of KOH added = 0.020 - n moles. Total volume of the solution after the addition of KOH = V initial + V added = 0.100 L + V added. We can then use the Henderson-Hasselbalch equation to find the pH: pH = pKa + log([A-]/[HA])where A- is CH3COOK and HA is CH3COOH.pKa of acetic acid = 4.76
Let's tabulate the values of n, [A-], [HA], and pH for each volume of KOH added: Number of moles of KOH added n (moles)Concentration of CH3COOK produced [A-] (M)
Number of moles of CH3COOH remaining [HA] (M)pH0.000.000.020.76 (initial)0.010.010.019.84 0.020.020.018.98 0.030.030.018.20 0.040.040.017.49 0.050.050.016.85.
The pH of the solution after 50.5 mL of 0.100 M KOH has been added is 16.85.
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Một nguồn O phát sóng cơ dao động theo phương trình u = 4cos(4pi t - pi/4). Tốc độ truyền sóng là 1m/s.
1. Tìm số điểm dao động cùng pha, ngược pha, vuông pha, lệch pha pi/3 với nguồn O trên đoạn MN
Answers
Answer:
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tkrjthr74uu3jt
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y
Explanation:
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If a player through a basketball to the target with an initial velocity of 17 m/s making an angle of 30 degrees with the horizontal, calculate the final position made with the vertical (Yf) after 1.3 seconds.
Answers
Answer:
The final position made with the vertical is 2.77 m.
Explanation:
Given;
initial velocity of the ball, V = 17 m/s
angle of projection, θ = 30⁰
time of motion, t = 1.3 s
The vertical component of the velocity is calculated as;
\(V_y = Vsin \theta\\\\V_y = 17 \times sin(30)\\\\V_y = 8.5 \ m/s\)
The final position made with the vertical (Yf) after 1.3 seconds is calculated as;
\(Y_f = V_yt - \frac{1}{2}g t^2\\\\Y_f = (8.5 \times 1.3 ) - (\frac{1}{2} \times 9.8 \times 1.3^2)\\\\Y_f = 11.05 \ - \ 8.281\\\\Y_f = 2.77 \ m\)
Therefore, the final position made with the vertical is 2.77 m.
how long (in s) does it take a child on a swing to complete one swing if her center of gravity is 3.57 m below the pivot?
Answers
If the child's center of gravity is 3.57 m below the pivot, it would take approximately 3.791 seconds for the child to complete one swing.
The time it takes for a child on a swing to complete one swing depends on several factors, including the length of the swing's arm, the angle at which the swing is released, and the force exerted by the child to keep swinging. However, if we assume a simple idealized case, we can use a formula to estimate the time period of a pendulum.
The formula for the time period of a simple pendulum (which can be approximated to a swing) is:
T = 2π√(L/g)
Where:
T = Time period (in seconds)
π ≈ 3.14159 (pi)
L = Length of the pendulum arm (from pivot to center of gravity)
g = Acceleration due to gravity (approximately 9.8 m/s²)
In this case, you mentioned that the child's center of gravity is 3.57 m below the pivot. Assuming this refers to the length of the pendulum arm (L), we can use this value in the formula. Therefore:
L = 3.57 m
g = 9.8 m/s²
Plugging in these values, we can calculate the time period:
T = 2π√(3.57/9.8)
T = 2π√(0.364)
T = 2π * 0.603
T = 3.791 seconds
Therefore, if the child's center of gravity is 3.57 m below the pivot, it would take approximately 3.791 seconds for the child to complete one swing.
The question is '' How long does it take a child on a swing to complete one swing if her center of gravity is 3.57 m below the pivot''.
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Two upwards forces act: one of 34N which is 3.5m to the left of the axle, the other is 25N and is 2.6m to the right of the axle. There is also a 10N force to the left which is 0.80m below the axle.
Answers
Answer:
See explanation below
Explanation:
In this case, you want to know if you put an object between these forces, which direction would go.
To know this, we need to calculate the moment of an object, which is defined as the product of a force and it's distance. In other words:
M = F * d (1)
And, in order to reach equilibrium the force will exert a direction in clockwise or anticlosewise, and these moments, should be even:
anticlockwise moment = clockwise moment.
The clockwise would be the forces to the right, and anticlock would the only force to the left of the axle.
Clockwise moment = (10 * 0.8) + (25 * 2.6) = 73 Ns
Anticlockwise moment = 34 * 3.5 = 119 Ns.
As we can see, the moment in the anticlockwise is higher than the actual clockwise moment, therefore, we can assume that the object will move anticlockwise, or simply move to the left.
Hope this helps
What is the momentum of a 10 kg dog running at a speed of 13m/s?
Answers
Answer:
P = mv
Explanation:
P = Momentum
m = mass
v = velocity
Therefore, P = 10 x 13 = 130 kg • m/s
Those under probation following a DUI conviction may not be able to enter a business that...
A. sells automobiles.
B. issues driver licenses.
C. serves alcohol.
Answers
Those under probation following a DUI conviction may not be able to enter a business that C. serves alcohol.
What is DUI?Driving while intoxicated (DUI) is the crime of operating a vehicle while under the influence of alcohol or other substances (including prescription medications and recreational drugs) to the point where it is unsafe for the driver to do so. The offence goes under many different names in different jurisdictions.
Even if the person accused is not actually driving the car, the criminal violation may generally include being physically "in control" of a car while under the influence of alcohol.
For instance, DUI charges may be brought against those who are discovered holding the car keys while intoxicated in the driver's seat of a parked vehicle.
What are the DUI probation conditions?DUI probationary criteria can vary based on the situation, but frequently include things like:
Avoiding alcohol and drugs, and abiding by the law, completion of a substance abuse assessment and suggestions for treatment.
Regular drug and alcohol testing, attendance at AA meetings, and using an ignition interlock device (IID) in your car are all required.
The judge may also order ongoing drug and alcohol monitoring utilising tools like SCRAM (secure continuous remote alcohol monitoring) bracelets or drug patches to make sure the offender doesn't use drugs or alcohol while on DUI probation.
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A hammer drives a nail into a piece of wood. Identify an action-reaction pair.Group of answer choicesThe hammer exerts a force on the nail; the wood exerts a force on the nail.The hammer exerts a force on the nail; the hammer exerts a force on the wood.The nail exerts a force on the hammer; the hammer exerts a force on the wood.The hammer exerts a force on the nail; the nail exerts a force on the hammer.
Answers
Newton's third law states that if an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.
Let:
A = Hammer
B = Nail
so:
\(F_{AB}=-F_{BA}\)Therefore:
The hammer exerts a force on the nail; the nail exerts a force on the hammer.
What would be the diameter of the earth if it had the density of a neutron star
Answers
Answer:
At neutron star density, the Earth's whole mass would fit inside a 305-meter-diameter sphere.
Explanation:
7 6 points For an object at infinity (soo), say a near-sighted person has an image form 2 cm behind their eye's lens, but the problem is that this is 0.5 cm short of their screen (retina). What is the focal length f (in cm) of a corrective lens that makes the image appear perfectly 2.5 cm behind the lens? (Treat the problem as the ideal case of two thin lenses right next to each other. Hint: It is kind of a bad name for it, but "focal length f" can be positive or negative, and the sign matters.) 6 points Same as the previous problem (lens to retina 2.5 cm, object at s=oo), except for a far-sighted person where the uncorrected image forms 0.5 cm behind their screen (retina). Now what is the focal length f (in cm) of a corrective lens that makes the image form perfectly on the retina 2.5 cm behind the lens?
Answers
The focal length (f) of the corrective lens should be 8 cm.
The term nearsightedness, or myopia, refers to a condition where a person can see nearby objects clearly, but distant objects appear blurry. This occurs because the lens of a nearsighted person focuses light in front of the retina instead of on it. On the other hand, farsightedness, or hyperopia, refers to a condition where a person has difficulty seeing nearby objects because the lens focuses light behind the retina.
To solve the given problems:
Problem 1:
For a nearsighted person, the image of an object at infinity is formed 2 cm behind their eye's lens. However, the problem states that the image falls 0.5 cm short of their retina. We need to find the focal length (f) of a corrective lens that makes the image appear perfectly 2.5 cm behind the lens.
The distance from the lens to the retina is 2.5 cm. The distance from the lens to the image is 2 cm, but we want it to be 2.5 cm behind the lens, so we add 0.5 cm. Therefore, the distance from the lens to the object is 2.5 + 2 = 4.5 cm.
Using the lens equation, 1/f = 1/do + 1/di, where f is the focal length, do is the distance from the lens to the object, and di is the distance from the lens to the image, we can rearrange and substitute the values:
1/f = 1/4.5 - 1/2.5
f = -6.43 cm
Hence, the focal length (f) of the corrective lens should be -6.43 cm.
Problem 2:
In this problem, we have a similar scenario as the previous one, but for a farsighted person. The uncorrected image forms 0.5 cm behind their retina, and we need to find the focal length (f) of a corrective lens that makes the image form perfectly on the retina, 2.5 cm behind the lens.
For a farsighted person, the uncorrected image forms behind the retina. We want the image to form on the retina. Therefore, the distance from the lens to the image is 2.5 cm, and the distance from the lens to the retina is 2.5 cm - 0.5 cm = 2 cm.
Using the lens equation, 1/f = 1/do + 1/di, where f is the focal length, do is the distance from the lens to the object, and di is the distance from the lens to the image, we can rearrange and substitute the values:
1/f = 1/oo - 1/2
f = 8 cm
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The minimum resultant of two forces of 20N and 5N is:
a) 10N
b) 5N
c) 20N
d) 25N
Answers
Answer:
if it's combined forces then it would be 25N if it was an unbalanced force then it would be 15N
you throw a small rock straight up from the edge of a highway bridge that crosses a river. the rock passes you on its way down, 6.00 s after it was thrown. what is the speed of the rock just before it reaches the water 23.0 m below the point where the rock left your hand? ignore air resistance. express your answer with the appropriate units.
Answers
The required speed of the rock just before it reaches the water 23.0 m below the point where the rock left your hand is calculated to be 3.82 m/s.
The measurement of distance is the separation between two things or points. Typically, it is expressed in measures like meters, kilometers, miles, and feet. Distance can be used to gauge a journey's duration, a room's size, or the separation between two places. It can also be used to gauge an object's velocity, a mountain's elevation, or a lake's depth. Finding the shortest path between two places in daily life involves using distance, a key idea in both mathematics and science.
The time taken by the rock is given as 6 s.
The distance the rock below the point where the rock left your hand is 23 m.
The equation of speed, distance and time is known as,
⇒ 23/6 = 3.82 m/s
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The car has a mass of 22,000Kg. Calculate the force needed to stop the car.
Answers
Answer:
Momentum of car = 1200 kg * 10 m/s = 12000 kgm/s Momentum = Force * time 12000 kgm/s = Force * 20s Force = 600 N
Explanation:
The 6 kg block is then released and accelerates to the right, toward the 5 kg block. The surface is rough and the coefficient of friction between each block and the surface is 0.3 . The two blocks collide, stick together, and move to the right. Remember that the spring is not attached to the 6 kg block. Find the speed of the 6 kg block just before it collides with the 5 kg
Answers
Assuming a 6 kg block is coupled to a spring with a 350 N/m spring constant, and that there is 0.5 m between the two blocks.
Solution:Use the formula
U=1/2kx2
U=1/23500.52
U=43.75 J
Utilizing the law of conservation of energy, KE = U - f.d, where f is the frictional force acting on
1/2 mv2 = 43.75 - mgd
1/2 ×6×v²= 43.75-0.3×6×9.8×0.5\s
v= √11.643
The spring constant is k, what is it?The "spring constant," denoted by the letter "k," is a figure that effectively indicates how "stiff" a spring is. A significant value of k indicates that more power is needed to extend it a given distance than would be necessary to stretch a less stiff spring the same distance.
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It is a grphic of a car trip taken by Karen and her mother. The starting position (0,0) is their home. How far from the home did karen and her mother travel during the first hour of the trip?
Answers
Answer:
40 miles
Explanation:
Differentiate between the resolving power and magnifiying power of a lens. What is meant by the term "parfocal"?
Answers
Resolving power refers to the ability of a lens to distinguish between two closely spaced objects. It is determined by the wavelength of light and the numerical aperture of the lens.
Magnifying power, on the other hand, refers to the ability of a lens to enlarge the size of an object. It is determined by the focal length of the lens.
The term "parfocal" refers to a type of lens system where multiple lenses have the same focal point when the focus is adjusted. This means that when switching between different lenses, the focus remains the same, making it easier for the user to switch between lenses without losing focus.
Differentiating between the resolving power and magnifying power of a lens involves understanding their respective functions. Resolving power refers to the ability of a lens to distinguish between two closely spaced objects, or in other words, the clarity with which the lens can produce an image. Magnifying power, on the other hand, refers to the degree to which a lens can enlarge the image of an object.
The term "parfocal" is used to describe a set of lenses that, when interchanged on a microscope or other optical instrument, maintain their focus on the same object. This means that when you switch from one parfocal lens to another, only minimal adjustments to the focus are needed, allowing for a seamless transition between lenses with different magnifying powers.
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Resolving Power: It is the ability of a lens to separate or distinguish between closely spaced objects, reflecting the detail that can be seen with the lens.
The magnifying powerMagnifying Power: It denotes how much larger an object appears through a lens compared to its actual size. High magnification doesn't necessarily mean better image quality.
Parfocal: This term refers to lenses that remain in focus even when the magnification or focal length changes. It enables swift adjustments in magnification without needing constant refocusing.
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The turbine fan blade of a turbojet engine is 1.8 m in diameter and rotates at 300 r/s. How fast is the tip of a blade moving?
Linear and rotational velocity
When a body moves linearly along the straight line or one axis only, then the body is said to have linear velocity. On the other hand, when an object rotates about a fixed point, we call it rotational velocity.
Answers
The tip of the turbine fan blade is moving at approximately 540 meters per second.
What is the velocity of the turbine blade tip?The tip of the turbine fan blade in a turbojet engine is moving at a considerable speed. To determine its velocity, we need to consider both the linear and rotational aspects of its motion.
First, let's calculate the linear velocity. The diameter of the turbine fan blade is given as 1.8 meters, which means the radius is half of that, or 0.9 meters. The linear velocity can be determined by multiplying the radius by the rotational velocity.
In this case, the blade rotates at 300 revolutions per second, so the linear velocity is 0.9 meters (radius) multiplied by 300 revolutions per second, resulting in 270 meters per second.
Next, to find the velocity of the blade tip, we need to consider the circumference of the circle traced by the blade tip during each revolution.
The circumference is given by 2π times the radius, which in this case is 2π multiplied by 0.9 meters, equal to approximately 5.65 meters. Multiplying this value by the rotational velocity of 300 revolutions per second gives us a tip velocity of approximately 1695 meters per second.
Therefore, the tip of the turbine fan blade in a turbojet engine is moving at approximately 540 meters per second, considering both its linear and rotational velocities.
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Which will have the greater acceleration rolling down an incline— a bowling ball or a volleyball?
Answers
Answer:
Bowling ball
Explanation:
The bowling ball's mass will make it roll down the incline faster than the lighter volleyball.
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The use of fire-resistive materials when constructing a building is an example of: risk transfer risk control risk avoidance risk retention QUESTION 4 Which of the following statements is correct. 1. One of the pre-loss objectives of risk managers is to meet any legal requirements the company may face. II. One of the post-loss objectives of risk managers is to maximize his own wealth. I only II only Both I and II Neither I nor II
Answers
The correct statement is "I only." One of the pre-loss objectives of risk managers is to meet any legal requirements the company may face.
The use of fire-resistive materials when constructing a building is an example of risk control. This is because risk control involves taking proactive steps to reduce the likelihood or severity of loss when an incident occurs. Fire-resistive materials are designed to withstand fire, and they are meant to slow down or contain the spread of fire in a building, thus reducing the risk of loss or damage.
In risk management, risk control is one of the four basic methods used to handle or mitigate risks. The other methods include risk transfer, risk avoidance, and risk retention. Risk transfer involves shifting the risk of loss to another party, such as through insurance or contract agreements. Risk avoidance involves eliminating the activity that could lead to loss or harm, while risk retention involves accepting the risk and dealing with any losses that may occur. As for the second question, the correct statement is "I only."
One of the pre-loss objectives of risk managers is to identify, assess, and evaluate potential risks that could negatively affect an organization. They also work to develop strategies to manage these risks and to ensure that the company is meeting any legal or regulatory requirements. On the other hand, one of the post-loss objectives of risk managers is to minimize the impact of losses that occur. They work to evaluate the effectiveness of the company's risk management strategies and to ensure that the company recovers from the loss as quickly as possible. Maximizing the risk manager's wealth is not a post-loss objective of risk managers.
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Which statement describes S waves?
They move side to side.
They arrive before P waves.
They travel through liquids.
They occur at Earth's surface.
Answers
S waves, also known as secondary waves, are a type of seismic wave that travels through the Earth's interior during an earthquake. Unlike P waves, which cause particles to vibrate back and forth in the direction of wave propagation, S waves cause particles to move perpendicular to the direction of wave propagation, or side to side.
The statement "They arrive before P waves" is incorrect. P waves, or primary waves, are the first waves to arrive at a seismic station during an earthquake, followed by S waves.
The statement "They travel through liquids" is incorrect as well. S waves cannot travel through liquids, unlike P waves, which can travel through both solids and liquids.
Finally, the statement "They occur at Earth's surface" is incorrect. S waves travel through the Earth's interior and do not occur at the Earth's surface.
A displacement-time graph of Rohan, Mira and Sunil is given in the diagram.
Who is travelling the fastest?
Are all the three ever at the same point on the road?
How far does Rohan travel when Sunil passes to Mira?
How far has Sunil travelled when Rohan passes him?
Answers
The person who is traveling the fastest is Mira (part a). They are not always in the same position (part b). Rohan has moved 2 meters when Sunil passes Mira (part c), Sunil has moved 26 meters until Rohan passes him (part d).
Who is traveling the fastest?To identify who is traveling faster of the three we must look at the graph. The line that marks the greatest distance in the shortest time will be the person with the greatest speed. In this case, Mira travels 46 meters in 6 seconds.
Are all the three ever at the same point on the road?No, all three are not at the same point at any time.
How far does Rohan travel when Sunil passes to Mira?To identify how far away Rohan was when Sunil passed Mira, we must take into account at what point Sunil passes Mira. This occurs in the second 6.2. So we must check at that time where Rohan was with respect to his initial point, that is, 2 meters.
How far has Sunil traveled when Rohan passes him?In this case, we must identify when Rohan passes Sunil and compare the distance that he has traveled from his starting point, that is, 26 meters.
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What is the type of radioactive decay represented by the equation above? A. Gamma B. Fusion C. Alpha D. Fission 40. Alberta uses clean coal technology. This means that the coal has a lower i content than coal in other parts of Canada, which results in reduced ii The statement above is completed correctly by the information in row olla sdf to ridW Row i A. sulfur greenhouse gas emissions acid deposition sulfur carbon greenhouse gas emissions acid deposition carbon B. C. D. 29. Which of the following graphs depicts the relationship between gravitational field strength and the mass of the International Space Station orbiting Earth? A. Field Strength (N/kg) C. Field Strength (N/kg) Mass (kg) Mass (kg) B. Field Strength (N/kg) D. Field Strength (N/kg) Mass (kg) CADLC 30. Which of the following sequences of colours represents the changing temperatu from the surface to the atmosphere of the sun? a A. Red, orange, yellow, blue B. Yellow, red, orange, blue C. Orange, yellow, blue, red D. Blue, yellow, orange, red 1. When a star undergoes a blue shift, the star is A. moving away from an observer B. moving towards an observer C. moving parallel to an observer D. stationary Mass (kg)
Answers
The sun is Yellow, red, orange, and blue. Therefore option B is correct.
The star is moving toward an observer. Therefore option B is correct.
39. The type of radioactive decay represented by the equation provided Gamma. Therefore option A is correct.
40. The statement is completed correctly by the information which states that the coal in Alberta has a lower carbon content than coal in other parts of Canada, resulting in reduced greenhouse gas emissions.
29. graph B depicts the relationship between gravitational field strength and the mass of the International Space Station orbiting Earth.
30. The correct sequence of colors representing the changing temperature from the surface to the atmosphere of the sun is Yellow, red, orange, and blue. Therefore option B is correct.
1. When a star undergoes a blue shift, it indicates that the star is moving toward an observer. Therefore option B is correct.
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i need help solving this,
Answers
Answer:
8n
Explanation:
If we could see our own galaxy from 2 million light-years away, it would appear _________.
Answers
Answer:
It would appear as a flattened disk with a central bulge and spiral arms, spanning a few degrees across the sky.
Explanation:
I hope this helps! Have a great day!
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