A Beer's Law Plot of sample A gives a slope equal to 1.2 M-1cm-1. Calculate molar concentration of this sample at a wavelength of 420 nm and an absorbance reading of 0.23 in a 1 cm cuvette.

Answer:

D

Explanation:

i learned this in elementary

Answer:

Explanation:

Alkali metals   ------ outermost orbit containing one electron

ns²np¹

Alkaline metals -------- outermost orbit containing two electron

ns²np²

halogens --------------- outermost orbit containing seven electron

ns²np⁵

noble gas --------------- outermost orbit containing eight electron

ns²np⁶.

Answer:

a) 2Ba + O2 → 2BaO

b) 2HCl + Mg → MgCl2 + H2

c) 2HCl + CuO → CuCl2 + H2O

d) Fe + O2 → Fe2O3

Explanation:

Okay so for

a), you must add 2 at the front of Ba and BaO bcuz you're gonna need your equation balanced.

like as you can see, O has 2 so yeahh, you've got to balance it nicely.

b) you must add 2 in front of HCl bcuz the Cl and H after the reaction happened has 2 in them, were talking about balancing so XD

c) and yes again, you're gonna have to add 2 in front of HCl bcuz of the same reason as b).

d) D is definitely a special case bcuz, Fe3+ with O2, so well if you do the cross multiplication technique you'll automatically get Fe2O3. Yas that's it.

English is not my first language so it's hella tuff to explain it to you from in much more detailed perspective T-T Sorry (´∩｡• ᵕ •｡∩`)

The equations represent an acid-base reaction is Ca ( OH )₂ + 2HBr ⇒ CaBr₂ + 2H₂O . Therefore, option D is correct.

The acid-base reaction (neutralization reaction) A salt and water are created when an acid and a base interact and neutralize one another. neutralization. a reaction between an acid and a base that results in a solution that isn't as basic or acidic as the initial solutions.

Salts and water are always present in most acid-base interactions. For instance, sodium hydroxide (NaOH) and hydrochloric acid (HCl) react to produce sodium chloride (NaCl) salt and water (H2O).

A neutralizing reaction occurs when an acid and a base interact. This reaction yields a salt and water as byproducts.

Thus, option D is correct.

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Answer: NO2

Explanation:

Assume 100 grams of a substance so that %=mass in grams

1.) Convert both into moles of each substance

30.45 g N * (1 mol N/ 14.01 g N) = 2.173 mol of N

69.55 g O * (1 mol O/ 16.00 g O) =4.347 mol of O

2.) divide both by the smallest number of moles, in this case 2.173, to find subscripts of each element.

2.173/ 2.173= 1

4.347/ 2.173= 2

Therefore the empirical formula is NO2

The best way to measure the pH of a natural solution while out in a forest is to use a portable pH meter or pH test strips specifically designed for field use. These instruments provide accurate and reliable pH measurements and are convenient for outdoor applications.

1. Prepare the necessary equipment: Before heading out to the forest, gather the required tools. You will need a portable pH meter or pH test strips, as well as the necessary reagents or calibration solutions if using a pH meter.

2. Collect the sample: Locate the natural solution you want to measure the pH of, such as a stream, pond, or soil. Use a clean container to collect a representative sample of the solution.

3. Calibrate the pH meter (if applicable): If you are using a portable pH meter, it is essential to calibrate it before taking measurements. Follow the manufacturer's instructions to calibrate the meter using the provided calibration solutions.

4. Conduct the measurement: For pH meters, immerse the electrode into the collected sample. Allow some time for the reading to stabilize, and then record the pH value indicated on the meter's display.

5. Using pH test strips: If you are using pH test strips, dip the strip into the collected sample for the recommended amount of time. Remove the strip and compare the color change with the provided color chart. Determine the corresponding pH value from the chart.

6. Repeat for accuracy: To ensure reliability, repeat the measurement process at least once and compare the results. This step helps confirm the accuracy of your measurements.

7. Record and analyze the data: Note down the pH values obtained and any relevant observations. Analyze the data as needed for your research or monitoring purposes.

By following these steps and using the appropriate equipment, you can effectively measure the pH of a natural solution while in a forest setting.

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Since most reactions take place in solutions, it's critical to comprehend how the substance's concentration is expressed in a solution. The number of chemicals in a solution can be stated in a variety of ways. The grams of acetic acid is 611.90 g.

The number of moles of dissolved solute per liter of solution is the definition of molarity, a unit of concentration. Molarity is defined as the number of millimoles per milliliter of the solution by dividing the number of moles and the volume by 1000.

The equation which is used to calculate the molarity of two different solutions is:

M₁V₁ = M₂V₂

M₁ = M₂V₂ / V₁

0.300 × 18.53 / 10.00 = 0.55 M

Number of moles = Molarity × volume

n = 0.55 × 18.53 = 10.19

Mass = n × Molar mass = 10.19 × 60.05 = 611.90 g

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We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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Answer:

Water is heated as it travels through flat, glazed panels known as solar collectors, which are normally situated on the roof of the building. The heated water is then stored in an insulated storage tank.

Answer:

Explanation:

i) in keeping industrial machine cool

ii) in textile inustries for dying clothes

Answer:

12

Explanation:

The statements correct about the speed of gas particles have been A and B.

The movement of the gas particles has been influenced by the factors such as temperature and molar mass.

The speed of the gas has been inversely proportional to the molar mass. The molecules with higher molar mass will have lesser speed.

The statements that have been based on the speed of gas molecules are:

Thus statement A is correct.

Thus statement B is correct.

Thus statement C is incorrect.

Thus statement D is incorrect.

The statements correct about the speed of gas particles have been A and B.

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Answer:

The Ranking from

Hardest to softest is as follows :

0.80 wt% C with fine pearlite.

0.80 wt% C with spheroidite

0.25 wt% C with coarse pearlite

0.25 wt% C with spheroidite

Explanation:

To find - Rank the following iron-carbon alloys and associated microstructures from the hardest to the softest. Justify this ranking.

Solution -

Ranking is as follows :

(d) 0.80 wt% C with fine pearlite.

(b) 0.80 wt% C with spheroidite

(a) 0.25 wt% C with coarse pearlite

(c) 0 25 wt% C with spheroidite

Justification -

For some wt% C,

Fine pearlite is stronger than spheroidite

and

Coarse pearlite is stronger than spheroidite.

Now,

Due to carbon content,

0.80 wt% C with spheroidite is stronger than 0.25 wt% C with coarse pearlite.

So,

The Ranking from

Hardest to softest is as follows :

0.80 wt% C with fine pearlite.

0.80 wt% C with spheroidite

0.25 wt% C with coarse pearlite

0.25 wt% C with spheroidite

Answer:

2219.945

Explanation:

861.62/101.323 = 8.5

261.17 x 8.5 = 2219.945

At 40°C, the maximum amount of KNO₃ that can dissolve in 200 g of water is 130 g, but since only 110 g of KCl was added, all the KCl will dissolve, and 71.5 g of KNO₃ will dissolve.

To determine how much KNO₃ will dissolve, we need to compare the amount of KCl that was added to the maximum amount of KNO₃ that can dissolve at the same temperature.

First, we can find the maximum amount of KNO₃ that can dissolve in 200 g of water at 40°C, which is given as 65 g/100 g of water

Maximum amount of KNO₃ that can dissolve

= 65 g/100 g x 200 g

= 130 g

This means that at most, 130 g of KNO₃ can dissolve in 200 g of water at 40°C.

Next, we need to compare the amount of KCl added to the maximum amount of KNO₃ that can dissolve.

The amount of KCl added is 110 g, which is less than the maximum amount of KNO₃ that can dissolve (130 g). Therefore, all of the KCl will dissolve and some of the KNO₃ will dissolve.

To find the amount of KNO₃ that will dissolve, we need to calculate how much KNO₃ would be in 110 g of the solvent (water) if it were saturated with KNO₃

Amount of KNO₃ in 110 g of water

= 65 g/100 g x 110 g

= 71.5 g

This means that 71.5 g of KNO₃ will dissolve in 110 g of water at 40°C.

Therefore, the amount of KNO₃ that will dissolve in the 200 g of water containing 110 g of KCl is 71.5 g.

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Answer:

V = 1.79 L

Explanation:

Given data:

Volume of gas = ?

Number of moles of gas = 0.080 mol

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1 atm × V = 0.080 mol × 0.0821 atm.L/ mol.K  × 273.15 K

V = 1.79  atm.L / 1 atm

V = 1.79 L

Answer:

a. Shift left.

b. Shift left.

c. Shift left.

d. Shift right.

e. No change,

Explanation:

Let's remember Le Chatelier's Principle: Le Chatelier's principle states that if a dynamic equilibrium is disturbed by changing conditions, the position of equilibrium shifts to counteract the change to re-establish an equilibrium.

Let's write the reaction:

Now, let's analyze each statement:

a. We can apply pressure because all species in the reaction are in the gas phase. Remember that increasing the pressure on a gas reaction shifts the position of equilibrium towards the side with fewer moles of gas molecules. You can see in the reaction that on the left side we have 3 moles in total, but on the right side, we have 4 moles in total, so the equilibrium goes to the left. Shift left.

b. If we reduce the concentration of a substance in a reaction, in this case, O2 as the reactant, we will not increase the concentration of the products, so the equilibrium goes to the left. Shift left.

c. If we add NO, we will increase the concentration of N2O and O2, so in this case, the equilibrium goes to the left. Shift left.

d. This situation is similar to the last, but, we are on the other side. Increasing the concentration of N2O will increase the concentration of NO, so the equilibrium goes to the right. Shift right.

e. Remember that adding a catalyst makes absolutely no difference to the position of equilibrium, and Le Châtelier's principle does not apply. Based on this logic, there's no change.

N5+ + 2e →N³

here Nitrogen gains electron so, its reduction half-reaction

20²- → 0₂

here oxygen loss electron so, its oxidation half-reaction

20² → 20₂ + 4e¯​

here oxygen loss electron so, its oxidation half-reaction

2N5+ + 4e¯ → 2N³

here nitrogen gains electron so, its reduction half-reaction

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Answer: there are 127.5g of N2 in 4.55 moles of this molecule

Explanation:

The question requires us to calculate the mass that corresponds to 4.55 moles of nitrogen (N2).

To solve this problem, we can use the molar mass of N2, which correlates the mass of the molecule with one mol of it.

The atomic mass of nitrogen is 14.01 u. Thus, the molar mass of nitrogen gas (N2) is:

molar mass N2 = 2 * 14.01 = 28.02 g/mol

Now, we know that there are 28.02g of N2 in 1 mol of this gas, thus we can write:

1 mol N2 ------------------- 28.02g N2

4.55 mol N2 -------------- x

Solving for x, we'll have:

Therefore, there are 127.5g of N2 in 4.55 moles of this molecule.

Answer:

They are more spread out.

Explanation:

The atoms and molecules in gases are much more spread out than in solids or liquids. They vibrate and move freely at high speeds. A gas will fill any container, but if the container is not sealed, the gas will escape. Gas can be compressed much more easily than a liquid or solid.

Answer:

Explanation:

Explanation:

Gas – In a gas, particles are in continual straight-line motion. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other. In most cases, there are essentially no attractive forces between particles

To solve this type of question we must know the expression for rate law for first order kinetics. Therefore, the rate constant at 273 K is 8.11 x 10⁻⁷s⁻¹.

There are two kinds of rate law in chemical kinetics one is differential rate law and other is integrated rate law.

ln(k₁/k₂ )=-Ea /R(1/T₁-1/T₂)

Ea=102 kJ/mol

k₁=1.35 × 10⁻⁴ s⁻¹

T₁=306 K

k₂=?

T₂= 273 K

R=8.314J/kmol

substituting all the given values in the above equation, we get

ln(1.35 × 10⁻⁴ /k₂ )=-1.35 × 10⁻⁴ /8.314(1/306-1/273)

K\(_2\)=8.11 x 10⁻⁷s⁻¹

Therefore, the rate constant at 273 K is 8.11 x 10⁻⁷s⁻¹.

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The aldol condensation is an organic addition reaction for carbonyl compounds. propanal  undergo aldol addition with other propanal molecule producing the alpha-beta unsaturated aldehyde.

Aldol condensation is an organic reaction of carbonyl compounds taking place in presence of a base to produce beta-hydroxy carbonyl compound. Aldehydes and ketones undergo this type of reaction.

The mechanism of aldol reaction of propanal with 2,2 dimethyl propanal is given here. In the first step, the the base abstract the proton from the aldehyde.

The O- attack the carbonyl carbon of another aldehyde and form a bet-hydroxy aldehyde. This further undergo dehydration forming the alpha-beta unsaturated aldehyde.

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When sodium metal and hydrochloric acid combine, salt and hydrogen gas are produced. As a result, sodium metal and hydrochloric acid will be your reactants since these are the things that undergo transformation to produce salt and hydrogen gas.

In a chemical reaction, one or more substances—also known as reactants—are changed into one or more additional substances—also known as products. Chemical components or chemical compounds make up substances.

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Answer:

Ion know

Explanation:

Answer:

A.    

They have no charge and are located inside the nucleus.

Explanation: It is true that neutrons have no charge, but they do have mass. The neutron does not exist outside the atomic nucleus.

0.9 moles of water can be made when 137.6 grams of hno3 are consumed.

The mole, symbol mol, is the unit of amount of substance in the International System of Units. The quantity amount of substance is a measure of how many elementary entities of a given substance are in an object or sample. The mole is defined as containing exactly 6.02214076×10²³ elementary entities.

1 mole of HNO3 means 63g HNO3 and we have, 8 moles HNO3

To calculate moles of water can be made when 137.6 grams of hno3 are consumed,

112.6g HNO3 x 1 mole HNO3 x  4 moles H2O    =  0.9 moles H2O

0.9 moles of water can be made when 137.6 grams of hno3 are consumed.

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Answer:

\(t=1.34\times 10^{-3}\ mm\)

Explanation:

Given that,

Area of sheet of Aluminium foil is 1 m²

Mass of the sheet = 3.636 g

The density of Aluminium, \(d=2.699\ g/cm^3\)

We need to find the thickness of the sheet in millimeters.

The density of an object is given in terms of its mass and volume as follows :

\(d=\dfrac{m}{V}\)

V = volume, V = A×t, t = thickness of the sheet

So,

\(d=\dfrac{m}{A\times t}\\\\t=\dfrac{m}{Ad}\\\\t=\dfrac{3.636\ g}{10000\ cm^2\times 2.699\ g/cm^3}\\\\t=0.000134\ cm\)

Since, 1 cm = 10 mm

So,

t = 0.00134 mm

or

\(t=1.34\times 10^{-3}\ mm\)

Answer:

Your answer is B, Electrochemistry!

Explanation:

This is the part of chemistry that studies the chemical process in which electrons flow. This flow is called electricity. Electricity is generated by the flow of electrons, from one element to another element. This reaction is called oxidation reduction.

Answer: B

Explanation:

WE CAN SEE ATOMS!?!?! I swear I'm getting dumber everyday

but I think is like a.... a penny?

Answer:\(\rho=7.87g/mL\)

Explanation:

Hello,

In this case, we are analyzing a problem in which the Archimedes principle is considered, thus, as the volume of the metal rod is determined by the difference between the mass of the water and the mass of the water and the rod:

\(V_{rod}=15.00mL-10.00mL=5.00mL\)

In such a way, the density turns out:

\(\rho =\frac{m_{rod}}{V_{rod}}=\frac{39.35g}{5.00mL} \\ \\\rho=7.87g/mL\)

Regards.

Answer: -2

EXPLANATION

Valence refers to the number of electrons that an atom must borrow or lend to complete its outermost shell. An atom of oxygen wants to add two more electrons to complete its outer shell of eight electrons. Since doing so would result in the oxygen atom becoming negatively charged by accepting two more electrons, oxygen is said to have a valence -2  

                                                           -2

this is the answer