A guitar string has a fundamental frequency f. The tension in the string is increased by 1.70%. Ignoring the very small stretch of the string. How does the fundamental frequency change?

Answers

Answer 1

The characteristics of the speed of the waves in strings and the resonance allows to find the change in the fundamental frequency when changing the tension is:

 The change in fundamental frequency is: f = 1.08 f₀

The speed of the chord wave is given by the relationship between the tension and the density of the medium.

          \(v= \sqrt{\frac{T}{\mu } }\)  

Where v is the velocity of the wave, T the tension of the string and μ the density

In a rope held at the ends, a process of standing waves occurs, two at the point where it is attached we have a node and a anti-node in the center.

             2L = n λ

Where L is the length of the chord and call the wavelength

Wave speeds are related to wavelength and frequency.

        v = λ f

We substitute.

            \(\sqrt{\frac{T}{\mu } } = \frac{2L}{n} \ \ f\)  

For the fundamental frequency n = 1

            f₀ = \(f_o = \sqrt{\frac{T}{\mu } } \ \ \frac{1}{2L}\)  

They indicate that the tension increases 1.70%

           T = T₀ + 0.17 T₀

           T = 1.17 T₀

We substitute.

         \(f = \sqrt{1.17 } \ \sqrt{\frac{T_o}{\mu } } \ \ \frac{1}{2L}\)

         f = ra1.17 f₀

         f = 1.08 f₀

In conclusion, using the characteristics of the velocity of the waves in strings and the resonance we can find the change in the fundamental frequency when changing the tension is:

 The change in fundamental frequency is: f = 1.08 f₀

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Related Questions

find the direction of the dune of these two vectors

find the direction of the dune of these two vectors

Answers

Given:

Vector A = 63.5 m at 90 degrees

Vector B = 101 m at 57.0 degrees

Let's find the direction of the sum of these two vectors.

To find the direction, let's first find the x- and y-components of the vectors.

• Vector A:

\(\begin{gathered} A_x=65.3cos90=0\text{ m} \\ A_y=63.5sin90=63.5\text{ m} \end{gathered}\)

• Vector B:

\(\begin{gathered} B_x=101cos57.0=55\text{ m} \\ B_y=101sin57=84.7\text{ m} \end{gathered}\)

For the sum of components, we have:

x = Ax + Bx = 0 + 55 = 55 m

y = Ay + By = 63.5 + 84.7 = 148.2 m

Now, to find the direction of the sum, we have:

\(\theta=tan^{-1}(\frac{y}{x})\)

Plug in the values and solve for θ.

We have:

\(\begin{gathered} \theta=tan^{-1}(\frac{148.2}{55}) \\ \\ \theta=69.6^o \end{gathered}\)

Therefore, the direction of the sum of the vectors is 69.6 degrees.

ANSWER:

69.6 degrees.

Question 22 (1 point) Please select the shapes of galaxies. Irregular Spherical Catical Conical Spiral Elliptical​

Answers

The universe has four different types of galaxies: elliptical, spiral, barred spiral, and irregular. Although there are other sorts of galaxies besides these, which are the four primary categories, they are all categorized according to their shapes.

What governs the structure of galaxies?

A galaxy's shape is a result of a combination of the gravitational pull of the gas clouds' internal gravity and the spinning gas cloud's centrifugal force. Because of the spinning gas cloud's centrifugal force, all galaxies were born with an elliptical form.

The galaxy has a spiral shape, why?

Due to the fact that galaxies rotate around a central axis and due to a phenomenon known as "density waves," astronomers think that galaxies have spiral arms. Galactic density waves are comparable to ocean waves. In a pond, the water doesn't actually move; instead, wave energy moves and changes the water as it passes.

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Help me as pleasessss help with 1,2 and 3

Help me as pleasessss help with 1,2 and 3

Answers

1.) Flammability
2.) Physical Properties
3.) Flammability, Reactivity, Ability to Rust

What is hydrogens outer most energy level

Answers

Answer:

Students should realize that each atom in a group has the same number of electrons in its outermost energy level. For instance, hydrogen, lithium, sodium, and potassium all have 1 electron on their outer energy level. Let students know that these electrons in the outermost energy level are called valence electrons.

An airplane at 70 m/s in the direction 133 degrees counterclockwise from east. What are the east and north components of the plane's velocity?

Answers

Answer:

See below

Explanation:

East is   70 cos 133 = -47.7 m/s   East

North is  70 sin 133 = 51.2 m/s   North

Vitalpando Winery wants to raise $30 million from the sale of preferred stock. if the winery wants to sell one million shares of preferred stock, what annual dividend will it have to promise if inverstor demand a return of
a. 11% ?
b. 15%?
c. 8% ?
d. 10%?
e. 6% ?
f. 3% ?

Answers

Vitalpando Winery will need to promise an annual dividend of $330,000 if investors demand a return of 11% on their preferred stock. The dividend amounts for the other required return rates are as follows: $450,000 for 15%, $240,000 for 8%, $300,000 for 10%, $180,000 for 6%, and $90,000 for 3%.

To determine the annual dividend required to satisfy the investors' demands for different return rates, we need to multiply the number of shares by the desired return rate. In this case, the winery wants to sell one million shares of preferred stock.

For option (a), where the desired return rate is 11%, the calculation would be: $30,000,000 (total funds required) multiplied by 0.11 (11% expressed as a decimal) divided by 1,000,000 (number of shares). This results in an annual dividend of $330,000.

Similarly, for the other return rates, the calculations are as follows:

(b) $30,000,000 x 0.15 / 1,000,000 = $450,000

(c) $30,000,000 x 0.08 / 1,000,000 = $240,000

(d) $30,000,000 x 0.10 / 1,000,000 = $300,000

(e) $30,000,000 x 0.06 / 1,000,000 = $180,000

(f) $30,000,000 x 0.03 / 1,000,000 = $90,000

Therefore, the annual dividends required to satisfy the investors' demands for the different return rates are as stated above.

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17. A volleyball weighs about 300 grams.
Calculate the potential energy of a volleyball
that is in the air at a height of 15 m. (g = 9.8
m/s-). Round your answer to two decimals
and show the correct units of measure. Be
sure to convert units if necessary.

Answers

Answer:

PE = 44.1 J

Explanation:

Ok, to have the specific data, the first thing we must do is convert from grams to kilograms. Since mass must always be in kilograms (kg)

We have:

1 kilograms = 1000 grams.

We convert it using a rule of 3, replacing, simplifying units and solving:

\(\boxed{\bold{x=\frac{gr*1\ kg}{1000\ gr}=\frac{300\ gr*1\ kg}{1000\ gr}=\frac{300\ kg}{1000}=\boxed{\bold{0.3\ kg}}}}\)

==================================================================

Earth's gravity is known to be 9.8 m/s², so we have:

Data:

m = 0.3 kgg = 9.8 m/s²h = 15 mPE = ?

Use formula of potencial energy:

\(\boxed{\bold{PE=m*g*h}}\)

Replace and solve:

\(\boxed{\bold{PE=0.3\ kg*9.8\frac{m}{s^{2}}*15\ m}}\)\(\boxed{\boxed{\bold{PE=44.1\ J}}}\)

Since the decimal number, that is, the number after the comma is less than 5, it cannot be rounded, then we have this result.

The potential energy of the volleyball is 44.1 Joules.

Greetings.

A 1500 kg car is rolling at 2.0 m/s. You would like to stop the car by firing a 10 kg blob of sticky clay at it. what is the momentum of the car?
Is this an elastic or inelastic collision? Discuss. Is momentum conserved in the collision? Discuss. How fast should you fire the clay?

Answers

The momentum of the car is 3000 kg·m/s. The collision between the car and the clay blob is an inelastic collision, and momentum is conserved.

To stop the car, the clay blob should be fired with a velocity of -300 m/s. The momentum of an object is defined as the product of its mass and velocity. In this case, the car has a mass of 1500 kg and a velocity of 2.0 m/s. By multiplying these values, we find that the momentum of the car is 3000 kg·m/s. When the clay blob is fired at the car, the collision is considered an inelastic collision. In an inelastic collision, objects stick together or deform upon impact, resulting in the loss of kinetic energy. In this scenario, the clay blob sticks to the car, causing a change in the car's motion and resulting in a loss of kinetic energy. Momentum conservation states that the total momentum of a system remains constant if no external forces are acting on it.

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What is permeability?
a. pore spaces in a body of earth material that are not interconnected
b. pore spaces that are interconnected to allow the movement of air or water
c. it is a term that is synonymous with
d. the water table the ability of water to move upwards against the pull of gravity
Question 3 0.34 pts
What is the capillary fringe?
a. The capillary fringe is what supplies water to a well.
b. material above the water table that is moistened by the rise of capillary water against gravity
c. The capillary fringe is what provides water to streams when they are dry.
d. a zone under Earth's surface where air (and sometimes a mixture of air and water) fills in the openings between soil particles and rock material

Answers

What is permeability? b. pore spaces that are interconnected to allow the movement of air or water. Permeability is a measure of the ability of a material to allow the flow of fluids through it.

It is a measure of the interconnectedness of the pore spaces in a material. Materials with high permeability allow fluids to flow through them more easily than materials with low permeability.

What is the capillary fringe? b. material above the water table that is moistened by the rise of capillary water against gravity. The capillary fringe is the zone of soil or rock that is saturated with water due to capillary action.

Capillary action is the ability of water to move upwards against gravity through the narrow spaces between soil particles. The capillary fringe is typically a few centimeters thick, but it can be thicker in some soils.

Permeability is a measure of the ability of a material to allow the flow of fluids through it.

The capillary fringe is the zone of soil or rock that is saturated with water due to capillary action.

Permeability is important in a variety of applications, including groundwater recharge, well design, and the construction of dams and levees. The capillary fringe is important for plant growth, as it provides water to plants that are not located directly above the water table.

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a rollercoaster car is moving 19.8 m/s on flat ground when it’s hits the brakes. it decelerates at -3.77 m/s^2 over the next 45.8 m. how much time does it take?

Answers

Answer:

3.44 s

Explanation:

Given:

Δx = 45.8 m

v₀ = 19.8 m/s

a = -3.77 m/s²

Find: t

Δx = v₀ t + ½ at²

45.8 = 19.8 t + ½ (-3.77) t²

45.8 = 19.8 t − 1.885 t²

1.885 t² − 19.8 t + 45.8 = 0

t = [ -b ± √(b² − 4ac) ] / 2a

t = [ 19.8 ± √((-19.8)² − 4 (1.885) (45.8)) ] / 2(1.885)

t = [ 19.8 ± √(392.04 − 345.332) ] / 3.77

t = 3.44 or 7.06

The first time, 3.44 seconds, is correct.

The second time is the time it would take the car to return to 45.8 m if it continued decelerating after stopping.

A car accelerates at a rate of 3.0
m/s2 after stopping at a red light. If
the mass of the car is 3000 kg, what
force does its engine exert?

Answers

Force = mass x acceleration = 3000 x 3.0 = 9000 kg*m/s

The force of the car's engine exerts is 6000 N.

To find the force, the given values are,

acceleration, a = 3 m/s².

mass = 3000 kg

What is Newton's second law?Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body.         According to Newton's second law of motion, the acceleration of a body is directly proportional to the force acting on the body and inversely proportional to its mass. The formula for the Newton's second law is

Acceleration, a = Force F/ Mass m

From which we get the formula

Force F = Mass m × Acceleration a

Where, mass is kg and acceleration is m/s².

The unit of force is kgm/s² or N.

where kg is kilogram-meter per second square or Newton.

Substituting the Equation in:

F = ma

  = 3000kg x 2m/s²

  = 6000kgm/s²

F = 6000 N.

So, the Force of the car engine exerted is 6000 N.

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A brick with a mass of 1 kg is lifted to the top of a 4 m high roof. It slips off the roof and falls to the ground. Calculate the gravitational potential energy of the brick at the top of the roof and on the ground once it has fallen.

Answers

The magnitude of potential energy at the top will be 39.2 J and it will be zero on ground because kinetic energy is maximum.

Gravitational Potential Energy

Gravitational potential energy of an object is the product of its mass and the height attained under the influence of acceleration due to gravity.

Given that a brick with a mass of 1 kg is lifted to the top of a 4 m high roof. It slips off the roof and falls to the ground.

The parameters involved are

m = 1 kgh = 4 mg = 9.8 m/s²

The gravitational potential energy of the brick at the top of the roof will be;

GPE = mgh

GPE = 1 × 9.8 × 4

GPE = 39.2 J

The gravitational potential energy of the brick on the ground will be zero because all the potential energy of the brick must have been converted to kinetic energy once it has fallen.

Therefore, the gravitational potential energy of the brick at the top of the roof will be 39.2 J and on the ground will be zero.

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in an experiment searching for the photoelectric effect, an incident beam of green light did not eject any electrons from a metal. in order to eject electrons, the experimenter should

Answers

Increase the frequency of the incident light. The photoelectric effect occurs when light of a sufficient frequency strikes a metal and frees electrons from the metal's surface. The energy of the incident photons must be greater than the energy required to remove the electrons, known as the work function. Thus, increasing the frequency of the incident light will result in higher energy photons, increasing the likelihood of electron ejection in the photoelectric effect.

The kinetic energy of the photoelectrons that are released will grow as the light amplitude increases, according to the wave model of light, yet the measured current will increase as the frequency increases. In contrast to expectations, studies revealed that raising the light's frequency and amplitude raised the current and the photoelectrons' kinetic energy, respectively.

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A plane is flying with an airspeed of 190 miles per hour and heading 150°. The wind currents are running at 30 miles per hour at 170° clockwise from due north. Use vectors to find the true course and ground speed of the plane. (Round your answers to the nearest ten for the speed and to the nearest whole number for the angle.)

Answers

Answer:

\(Vg=200mile/hr\)

\(\theta=153 \textdegree\)

Explanation:

From the question we are told that:

Plane airspeed \(v_p=190mil/h\)

Plane direction \(\angle=150 \textdegree\)

Wind current speed \(V_w=30mil/h\)

Wind direction \(\angle=150 \textdegree\)

Generally the vector form of the forces is mathematically given by

For plane

\(\angle Q_p=90-150 \textdegree\)

\(V_p=170(cos60 \textdegree ,sin60 \textdegree)\)

\(V_p=(85,-147.224)\)

For wind

\(\angle Q_w=90-170 \textdegree\)

\(V_w=30(cos-80 \textdegree ,sin-80 \textdegree)\)

\(V_w=(5.2,-29.54)\)

Generally the equation for resultant force is mathematically given by

\(v_r=V_a+V_w\)

\(v_r=(85,-147.224)+(5.2,-29.54)\)

\(v_r=(90.21,-176.76)\)

\(v_r=198.45\angle -63\)

Therefore ground speed

\(V_g=198.5miles/hr\)

\(Vg=200mile/hr\)

Direction

\(\theta=(90+63)=153 \textdegree\)

\(\theta=153 \textdegree\)

1.

If a force of 40N is applied for 0.2 sec

to change the momentum of a

volleyball, what is the impulse?

Answers

Answer:

J = 8 kg-s

Explanation:

Given that,

Force, F = 40 N

Time, t = 0.2 s

We need to find the impulse. We know that,

Impulse, J = F×t

So,

J = 40 × 0.2

J = 8 kg-s

So, the impulse is 8 kg-s.

i need help with this lab. i have to answer the lab questions 4-10. i will upload the graphs u need to use. someone please answer these questions. i will upload the pictures in different questions because it won’t let me upload 3…

i need help with this lab. i have to answer the lab questions 4-10. i will upload the graphs u need to

Answers

The speed of an object is the rate of change of its position, and the object's velocity includes its speed as well as its direction of motion. The rate of change of the object's velocity gives the acceleration.

Explain Speed,Velocity and Acceleration?When an object's reference frame is chosen, its motion can be precisely characterized. The pace at which an object's position changes while it is moving is referred to as speed. The object's speed indicates how quickly or slowly it is going. But which way is the item traveling? The velocity of an object includes information about its direction of motion. The rate of change of an object's velocity, or the change in velocity per unit of time, is known as its acceleration.

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The smallest bird is the Cuban bee hummingbird, which has a mass of only 1.7 g. If this bird did 8.8 10 –4J of work by exerting an upward force of 3.4 10 –4 N, how far did it fly?

Answers

Answer:

The distance the bird flew is approximately 2.59 meters

Explanation:

We list out the parameters in the question, and the required measurement as follows;

The mass of the Cuban bee hummingbird, m = 1.7 g = 0.0017 kg

The amount of work the bird does, W = 8.8 × 10⁻⁴ J

The amount of upward force the bird exerts, F = 3.4 × 10⁻⁴ N

Let 'd' represent the distance flown by the bird

(The downward force, \(F_g\) = The weight of the bird, W

W = The mass of the bird, m × The acceleration due to gravity, g

The acceleration due to gravity, g ≈ 9.81 × 10 m/s²

∴ \(F_g\) ≈ 0.0017 kg × 9.81 m/s² = 0.016677 N > F)

Given that the weight of the bird is larger than 'F', we assume that the force exerted by the bird is the net force, \(F_{NET}\) = F

Therefore;

Work done, W = Net Force, \(F_{NET}\) × Distance, d

∴ W = \(F_{NET}\) × d

d = W/\(F_{NET}\) = 8.8 × 10⁻⁴ J/(3.4 × 10⁻⁴ N) = 2.58823529 meters

The distance the bird flew, d ≈ 2.59 m.

A ship leaves port and travels 50 miles at a standard position of 45⁰. The ship

then travels for 90 miles in a standard position angle of 80⁰. At that point the ship

drops anchor. A speedboat travelling 30 miles per hour moves towards the ship in a

straight line. At what time will it get there? ​

Answers

Answer:

   t = 4.468 h

Explanation:

For this exercise let's start by calculating the distance where the boat is

the first trip is 50 miles at 45 °, then 90 miles at 80 °,

to find the total distance let's find the distance of each displacement

             cos 45 = x₁ / 50

             sin 45 = y₁ / 50

             x₁ = 50 cos 45 = 35.35 miles

             y₁ = 50 cos 45 = 35.35 miles

             

             cos 80 = x₂ / 90

             sin 80 = y₂ / 90

             x₂ = 90 cos 80 = 15.63 miles

             y₂ = 90 sin 80 = 88.63 miles

let's find the total displacement in each axis

            x_total = x₁ + x₂

            x_total = 35.35 + 15.63

            x_total = 50.98 miles

         

            y_total = y₁ + y₂

            y_total = 35.35 + 88.63

            y_total = 123.98 miles

Let's use the Pythagorean theorem to find the modulus of the displacement

            R = √ (x_total² + y_total²)

            R = √ (50.98² + 123.98²)

            R = 134.05 miles

The boat goes at a constant speed,

           v = R / t

             

           t = R / v

let's calculate

           t = 134.05 / 30

            t = 4.468 h

Define the types of friction and give FOUR examples of each
Static Friction
Rolling Friction
Sliding Friction
Fluid Friction

Answers

Static Friction is the force that keeps an object at rest
example: pushing against a heavy box but it isnt moving due to the weight of the box and gravity pulling it down

Rolling friction is a resistive force that slows down something thats rolling such as a ball or a wheel
example: a rolling soccer being slowed down from grass

Sliding Friction is the friction created from two object sliding against eachother, just like kinetic friction. It is intended to make the object stop
example: A sled sliding down a hill against snow

Fluid Friction is the force that resist motion in fluid or something moving around a fluid.
example: water pushing against a swimmer when swimming through it

What will happen to people involved in handling Gamma rays if they are not providedwith lead coated apron and equipment without safety measures❤

Answers

Answer:

When gamma rays pass through the human body, they ionize the tissue.  gamma ray ionization can affect healthy cells. When high levels of gamma rays bombard a body, a resulting dangerous ionization of tissue can cause skin cancer.

Explanation:

Yea this question is difficult for me ive been trying to answer this for 40 mins

Yea this question is difficult for me ive been trying to answer this for 40 mins

Answers

Answer:

it is difficult

my best answer would be a. 6

hope its right!!

Answer:  A) 6

===========================================

Explanation:

The half-life formula is

y = A*(1/2)^(x/H)

where A is the starting amount, H is the half-life, x is the time value and y is the amount after x units of time have passed.

I'll express the x and H values in terms of millions of years. So for example, when we say H = 500, then that really refers to 500 million years.

----------

In this case, we know that,

A = 192H = 500y = 3

Let's use those values to solve for x. We'll need logs to cut the exponents down from the trees.

y = A*(1/2)^(x/H)

3 = 192*(1/2)^(x/500)

3/192 = (0.5)^(x/500)

0.015625 = (0.5)^(x/500)

log(0.015625) = log( (0.5)^(x/500) )

log(0.015625) = (x/500)*log(0.5)

(x/500)*log(0.5) = log(0.015625)

x = 500*log(0.015625)/log(0.5)

x = 3,000

Keep in mind that x is in millions of years. So saying x = 3,000 means 3,000 million years. This translates to 3,000*10^6 = 3,000,000,000 = 3 billion years.

It will take about 3 billion years for the 192 atoms to decay to only 3 atoms.

The amount of half-lives this occurs is x/H = (3,000)/500 = 6

So the time span of 3 billion years is the same as 6 half-lives when each half-life is 500 million years long.

When heating a liquid on the stovetop, the heated liquid becomes less dense and rises and the denser cooler liquid sinks to the bottom. What type of thermal energy transfer is occurring?.

Answers

Answer:

Natural convection

Explanation:

Natural convection occurs when fluids are heated. When the fluid molecules are heated, the fluid becomes larger and lighter. The heated molecules take up more space and rise to the top, while the cooler molecules sink to the bottom. These cooler molecules then become heated.

FILL IN THE BLANKS here on earth, the pull of gravity on a mass of 1 kg is ......... newtons​

Answers

Answer:

9.8 Newton

Explanation:

At average gravity on earth (conventionally, g=9.80665m/s2),

a kilogram mass exerts a force of about 9.8 newton

I hope this answer helps you

In which medium does light travel faster: one with a critical angle of 27.0° or one with a critical angle of 32.0°? Explain. (For both cases, air is the second medium.)

Answers

Answer:

Among those two medium, light would travel faster in the one with a reflection angle of \(32^{\circ}\) (when light enters from the air.)

Explanation:

Let \(v_{1}\) denote the speed of light in the first medium. Let \(v_{\text{air}}\) denote the speed of light in the air. Assume that the light entered the boundary at an angle of \(\theta_{1}\) to the normal and exited with an angle of \(\theta_{\text{air}}\). By Snell's Law, the sine of \(\theta_{1}\!\) and \(\theta_{\text{air}}\!\) would be proportional to the speed of light in the corresponding medium. In other words:

\(\displaystyle \frac{v_{1}}{v_{\text{air}}} = \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})}\).

When light enters a boundary at the critical angle \(\theta_{c}\), total internal reflection would happen. It would appear as if the angle of refraction is now \(90^{\circ}\). (in this case, \(\theta_{\text{air}} = 90^{\circ}\).)

Substitute this value into the Snell's Law equation:

\(\begin{aligned}\frac{v_{1}}{v_{\text{air}}} &= \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})} \\ &= \frac{\sin(\theta_{c})}{\sin(90^{\circ})} \\ &= \sin(\theta_{c})\end{aligned}\).

Rearrange to obtain an expression for the speed of light in the first medium:

\(v_{1} = v_{\text{air}} \cdot \sin(\theta_{1})\).

The speed of light in a medium (with the speed of light slower than that in the air) would be proportional to the critical angle at the boundary between this medium and the air.

For \(0 < \theta < 90^{\circ}\), \(\sin(\theta)\) is monotonically increasing with respect to \(\theta\). In other words, for \(\!\theta\) in that range, the value of \(\sin(\theta)\!\) increases as the value of \(\theta\!\) increases.

Therefore, compared to the medium in this question with \(\theta_{c} = 27^{\circ}\), the medium with the larger critical angle \(\theta_{c} = 32^{\circ}\) would have a larger \(\sin(\theta_{c})\). such that light would travel faster in that medium.

A rock falls off a cliff and hits the ground after three seconds. The rock's velocity is 29.4 m/s when it hits the ground. What is its acceleration of the rock in the downward direction?

Answers

Answer:

formula for acceleration= (final velocity - starting velocity)/ time elapsed

if the starting velocity was 0 m/s

if the final velocity is 29.4 m/s

time elapsed is 3 seconds

then a =(29.4-0)/3

=9.8 m/s^2

Answer 9.8 m/s^2

Explanation: sorry for the late answer

What is the evidence that star formation began when the universe was only a few hundred million years old

Answers

Answer: Globular clusters with stars more than 13 billion years old contain heavy elements.


How many times faster are plates moving at
7.3 cm/year than those moving at 1.3 cm/year?

Answers

Plates moving at 7.3 cm/year are approximately 5.615 times faster than those moving at 1.3 cm/year.

The speed at which plates move is determined by the relative motion between tectonic plates along their boundaries. To compare the speeds of plates moving at different rates, we can calculate the ratio between their velocities.Let's consider plates moving at 7.3 cm/year and 1.3 cm/year. To find the factor by which the faster plates are moving compared to the slower plates, we divide their velocities:

7.3 cm/year / 1.3 cm/year = 5.615

In other words, for every unit of time, the faster plates cover approximately 5.615 times the distance covered by the slower plates. This difference in speed can have significant implications for geological processes such as the accumulation of strain along plate boundaries, the occurrence of earthquakes, and the formation of mountain ranges. It highlights the dynamic nature of tectonic plate movements and their influence on Earth's geology and surface features.

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Mars has a mass of 642,000,000,000,000,000,000,000 kg. How would scientists express this number in scientific notation? A. 0.64224 kg B. 0.642 x 1024 kg C. 0.642 × 1021 kg D. 6.42 x 1023 kg​

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Answer:

I think it's B because if you put it in decimal form that would be it I THINK (anxiety)

Someone answer? Please

Someone answer? Please

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I don’t know ask your parents

A vector has initial point at (3, –5) and terminal point at (–2, 3). what are the characteristics of this vector? the magnitude is startroot 13 endroot, and the direction angle is about 58°. the magnitude is startroot 13 endroot, and the direction angle is about 122°. the magnitude is startroot 89 endroot, and the direction angle is about 58°. the magnitude is startroot 89 endroot, and the direction angle is about 122°.

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The magnitude of this vector is 9.43 and the direction angle of the vector is 58°.

The initial point and the terminal point of the vectors are (3 - 5) and (-2, 3) respectively.

The characteristics of the vector mainly includes the magnitude and the direction of the angle of the vector.

The magnitude of this vector will be given by,

M = √((-2-3)²+(3+5)²)

M = √(25+64)

M = √89

M = 9.43

The direction angle of this vector with the x-axis will be given by,

Tan A = (8/-5)

Tan A = -1.6

A = 58°.

The direction angle of this vector is 58 degree.

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Answer: D. The magnitude is StartRoot 89 EndRoot, and the direction angle is about 122°.

Explanation:

A vector has initial point at (3, 5) and terminal point at (2, 3). what are the characteristics of this
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