A title for your performance, including the act, scene, and line numbers from the play that you will perform a full script of what you will say during your performance, including the lines from a midsummer night's dream and your own commentary. in your commentary, you will explain to your audience how specific details in the scene create humor and a message, and why that humor and message is particularly relevant to an audience of twenty-first-century middle-school students.

Answers

Answer 1

The Title of my performance is: "A Midsummer Night's Dream:

There is Act 3, Scene 2, Lines 1-100 and titled: Love and Confusion" The Performance Script is attached.

What is the summary of a Midsummer Night's Dream:

In Act 3, Scene 2 of "A Midsummer Night's Dream," Shakespeare blends humor and a message about love and confusion. Characters include Puck and four lovers: Demetrius, Hermia, Helena, and Lysander.

Humor comes from the love triangle's chaos between Demetrius, Hermia, and Helena, worsened by Puck's interference. Puck's love potion causes Demetrius to love Helena instead of Hermia. Lysander also falls in love with Helena due to the potion. Humor from exaggerated love expressions and misunderstandings among characters.

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A Title For Your Performance, Including The Act, Scene, And Line Numbers From The Play That You Will

Related Questions

6. Kaylee borrows $700 from her dad to buy a new phone.
She has to pay him back in 24 months with a 2% simple
interest rate. How much inter
interest rate. How much interest will she have to pay?

Answers

Kaylee will have to pay $28 in interest.

What is simple interest?

The interest on a loan or principal sum can be easily calculated using simple interest. Simple interest is a notion that is employed across a wide range of industries, including banking, finance, automobiles, and more.

The interest Kaylee will have to pay is calculated as follows:

Interest = Principal x Rate x Time

where Principal is the amount borrowed, Rate is the interest rate as a decimal, and Time is the time period in years. Since Kaylee has to pay back the loan in 24 months, or 2 years, we can plug in the given values to get:

Interest = 700 x 0.02 x 2 = $28

Therefore, Kaylee will have to pay $28 in interest.

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tori is getting ready to run a marathon. she kept track of the lengths of her last few training runs. training runs (mi.) 11 8 15 16 8 20 16 12 6 13 7 which box plot represents the data?

Answers

The box plot would show the distribution of Tori's training runs and provide insights into the Central tendency and variability of the data.

A box plot, also known as a box-and-whisker plot, is a visual representation of the distribution of a dataset. It shows the median, quartiles, and range of the data. The median is the middle value of the dataset, the first quartile is the value that separates the lowest 25% of the data from the rest, and the third quartile is the value that separates the lowest 75% of the data from the rest. The range is the distance between the minimum and maximum values of the data.

To create a box plot for Tori's training runs, you would first order the data from smallest to largest: 6, 7, 8, 8, 11, 12, 13, 15, 16, 16, 20. Then, you would find the median (the middle value), which is 12.5. Next, you would find the first quartile (the value that separates the lowest 25% of the data from the rest), which is 8, and the third quartile (the value that separates the lowest 75% of the data from the rest), which is 16. Finally, you would calculate the range (the distance between the minimum and maximum values), which is 14 (20 - 6).

To draw the box plot, you would draw a rectangle with the bottom edge at the first quartile and the top edge at the third quartile. Inside the rectangle, draw a line at the median. Then, draw whiskers (lines) from the edges of the rectangle to the minimum and maximum values of the data (6 and 20). Any outliers (values that are more than 1.5 times the interquartile range away from the nearest quartile) can be plotted as individual points outside of the whiskers.

Without a visual representation of the data, it is difficult to say which box plot represents the data. However, the box plot would show the distribution of Tori's training runs and provide insights into the central tendency and variability of the data.

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tori is getting ready to run a marathon. she kept track of the lengths of her last few training runs.

Peter, Bridget and Caroline share some sweets in the ratio 4:3:1. Peter gets 20 sweets. How many sweets are there altogether?

Answers

In that the sweets are shared 20:15:5 (multiply all the numbers by five)
This means there are 20 + 15 + 5 = 40 sweets

ryan and betty both have 5 children in their family. their ages are ryan: 17, 12, 8, 4, 2 betty: 17, 16, 14, 11, 10 which group of children's ages have the greatest dispersion?

Answers

Betty's children have greater age dispersion than Ryan's children. Their ages range from 10 to 17, while Ryan's children range from 2 to 17.

Betty's children have the greatest dispersion. Dispersion refers to the extent to which the values in a set of data are spread out. The difference between the youngest and oldest child in Betty's family is 7 years, while the difference in Ryan's family is 15 years. The greater difference indicates a higher level of dispersion, meaning Betty's children have a greater range of ages and are spread out over a larger range of values than Ryan's children.

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If 18 gallons of gasoline cost $23.31 how much would 12 gallons cost

Answers

Answer:

15.60

Step-by-step explanation:

23.31/18=1.30 (for one gallon)

1.30*12=15.60 (for twelve gallons)

Answer:

$15.54

Step-by-step explanation:

Divide $23.31 by 18 to find the cost of 1 gallon, then multiply this by 12.

$23.31 ÷ 18 = $1.295 , then

12 gallons costs = 12 × $1.295 = $15.54

In the ACME rubber ball factory, a stream of rubber balls, each of mass m, comes out of a horizontal tube at a rate of R per second. These balls fall a distance of h into a bucket of mass M suspended by a rope from the ceiling. If the balls bounce out of the bucket back to their original height when leaving the tube, what is the (average) tension T in the massless rope holding the bucket

Answers

Therefore, the average force exerted on the bucket per unit time is given by the change in momentum divided by the time interval: Δp / (1/R) = RΔp.

The average tension T in the massless rope holding the bucket is equal to the total force exerted on the bucket due to the falling rubber balls. This force is equal to the change in momentum of the balls per unit time. When a rubber ball falls into the bucket, it experiences a change in momentum due to the gravitational force acting on it.

The change in momentum is given by the product of the mass of the ball (m) and the change in velocity (v), which is equal to the velocity of the ball when it leaves the tube. Since the balls bounce back to their original height, the change in velocity is twice the initial velocity, as the ball reverses its direction. The time interval between successive ball impacts is 1/R.

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Find the discriminant of the following quadratic equation then state the number of rational, irrational, and imaginary solutions.

Equation: −6x2−6=−7x−9

Discriminant: Answer

Solutions:

Answers

Answer:

-6x² - 6 = -7x - 9-6x² + 7x - 6 + 9 = 0-6x² + 7x + 3 = 06x² - 7x - 3 = 0

Discriminant:

D = (-7)² - 4*6*(-3) = 49 + 72 = 121

Since D > 0, there are 2 real solutions:

x = (- (-7) ±√121 )/12x = (7 ± 11)/12x = 1.5, x = -1/3

What is the following quotient?6-3(^3√6)/3/9
O 2(3√3)-3√/18
O 2(³√/3)-3(³/2)
O 3(3/3)-3√/18
O 3(³√/3)-3(3√/2)

What is the following quotient?6-3(^36)/3/9 O 2(33)-3/18O 2(/3)-3(/2)O 3(3/3)-3/18O 3(/3)-3(3/2)

Answers

Applying properties of exponents, the quotient is given as follows:

$2\sqrt[3]{3} - \sqrt[3]{18}$

What is the quotient?

The expression is given by:

$\frac{6 - 3\sqrt[3]{6}}{\sqrt[3]{9}}$

The 3 can be inserted into the cube root, as follows:

$\frac{6 - 3\sqrt[3]{6}}{\sqrt[3]{9}} = \frac{6 - \sqrt[3]{6 \times 3³}}{\sqrt[3]{9}}$

Applying the subtraction, we have that the expression is:

$\frac{6}{\sqrt[3]{9}} - \frac{\sqrt[3]{162}}{\sqrt[3]{9}} = \frac{6}{\sqrt[3]{9}} - \sqrt[3]{\frac{162}{9}} = \frac{6}{\sqrt[3]{9}} - \sqrt[3]{18}$

The denominator can be simplified as follows:

$\sqrt[3]{9} = \sqrt[3]{3^2} = 3^{\frac{2}{3}}$

Then:

$\frac{6}{\sqrt[3]{9}} = \frac{2 \times 3}{3^{\frac{2}{3}}} = 2 \times 3^{1 - \frac{2}{3}} = 2 \times 3^{\frac{1}{3}} = 2\sqrt[3]{3}$

Hence the quotient is given by:

$2\sqrt[3]{3} - \sqrt[3]{18}$

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A time traveler can take 3 books with him, and he has 57 books to choose from. How many different ways can the books be selected?

Answers

The time traveler can choose 3 books with him, but he can only take 57.

So in this case the order doesn't matter, therefore, we are going to use a combination:

Use the combination formula:

$C\text{ =}\frac{n!}{r!(n-r)!}$

When n is the total of books and r the sample.

n = 57 and n =3

Replace these values on the formula:

$C=\frac{57!}{3!(57-3)!}=\frac{57!}{3!54!}=29260$

Hence, there are 29260 ways that the books can be selected.

Simplify the following expression:

6(3x) − 2y + 3z + 12(4x) − 9y

Answers

Answer:

9x+48x-2y-9y +3z

57x -11y +3z

calculate the taylor polynomials 2 and 3 centered at =0 for the function ()=16tan().

Answers

Taylor polynomials of degree 2 and 3 centered at x = 0 for the function f(x) = 16tan(x) are:

P2(x) = 16x + 8x^2

P3(x) = 16x + 8x^2

To find the Taylor polynomials centered at x = 0 for the function f(x) = 16tan(x), we can use the Taylor series expansion for the tangent function and truncate it to the desired degree.

The Taylor series expansion for tangent function is:

tan(x) = x + (1/3)x^3 + (2/15)x^5 + (17/315)x^7 + ...

Using this expansion, we can find the Taylor polynomials of degree 2 and 3 centered at x = 0:

Degree 2 Taylor polynomial:

P2(x) = f(0) + f'(0)(x - 0) + (1/2!)f''(0)(x - 0)^2

= 16tan(0) + 16sec^2(0)(x - 0) + (1/2!)16sec^2(0)(x - 0)^2

= 0 + 16x + 8x^2

Degree 3 Taylor polynomial:

P3(x) = P2(x) + (1/3!)f'''(0)(x - 0)^3

= 0 + 16x + 8x^2 + (1/3!)(48sec^2(0)tan(0))(x - 0)^3

= 16x + 8x^2

Therefore, the Taylor polynomials of degree 2 and 3 centered at x = 0 for the function f(x) = 16tan(x) are:

P2(x) = 16x + 8x^2

P3(x) = 16x + 8x^2

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1.
Each exterior angle of a regular polygon is 30°.
Work out the number of sides of the polygon.
(2 marks)

Answers

Answer:

Dodecagon (12 sides)

Step-by-step explanation:

PLS GIVE BRAINLIEST

Use the lessons we practice in class for Caesar, St. Cyr, Pigpen, and Rail Fence ciphers to answer the following prompts.

Decipher the following statement, using a St. Cyr slide. All you know about the length of the slide is that it is a prime number (i.e., 2, 3, 5, 7, 11, 13, 17, 19, 23).

ETEWPESPRCLASTYPIPCNTDPESCPPFYGZETYR

Answers

The deciphered message is: "XOZXBXPPIUDXOQHRDCQGHXHPPAGHNRAXTXL".

To decipher the given statement using a St. Cyr slide, we need to determine the correct length of the slide. Since we know that the length of the slide is a prime number, we can try different prime numbers as the length and see which one produces a meaningful decryption.

Let's try the prime numbers from 2 to 23 and see which one gives us a readable message.

Using a St. Cyr slide with a length of 2: