All of the following are empirical formulas except A) Na2SO4 B) C6H5Cl C) Sn3(PO4)4 D) N2O4

The answer is-  142.27 food calories are in the taco.

Heat capacity-The amount of energy needed to increase the temperature of a substance by one degree Celsius.

How heat released or gained is related to heat capacity?

\(q = m* C*\)Δ\(T\)

Where m is the mass of substance.

C is the heat capacity

and Δ\(T\) is the change in temperature.

\(Heat\ = (22.8 ^{0}\ C) * (31.2 kJ/ ^{0}\ C) = 711.36\ kJ\)

1 kJ = 0.2 food calories

Thus, the food calories in the taco are-

\(Food\ Calories\ in\ taco = (711.36\ kJ) * (0.2 Food\ calories/ kJ) = 142.27\ calories\)

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The statement is FALSE. Non-ferrous metals can be hardened by heat treatment, although the mechanisms and processes involved may differ from ferrous metals.

Heat treatment techniques such as precipitation hardening can be used to increase the strength of non-ferrous metals. Non-ferrous metals are metals or alloys that do not include iron (or iron allotropes, such as ferrite, etc.) in significant quantities. Non-ferrous metals are employed because they have desired qualities like reduced weight (for example, aluminium), greater conductivity (for example, copper), non-magnetic characteristics, or corrosion resistance (for example, zinc), even though they are often more expensive than ferrous metals. In the iron and steel sectors, several non-ferrous materials are also employed. Bauxite, for instance, is used as a flux in blast furnaces, whereas wolframite, pyrolusite, and chromite are utilised to create ferrous alloys.

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Answer:

11460

Explanation:

Answer:

Carbon 16

Explanation:

Isotope of nitrogen

Cleaning the surface of the magnesium ribbon will remove the oxide layer from the surface and thus it will allow the ribbon to burn effectively to get the desired result.

Magnesium is a mineral needed for the development of human bone structure. This mineral substance is also very important in the body's metabolism. Besides, what does magnesium do?

Serves to help overcome constipation and dyspeptic symptoms. Magnesium also has a vital role for pregnant women to maintain a healthy womb. In addition, magnesium is useful for preventing back pain and cramps, as well as preventing heart attacks.

Magnesium is also useful for preventing diabetes and regulating sugar levels to stay normal. Other benefits include maintaining the normal function of nerves and muscles, helping to boost the immune system, while maintaining a normal heart rate.

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The alkene that would give only a ketone with three carbons as a product of oxidative cleavage is propene.

Oxidative cleavage of alkenes involves the breaking of the double bond and the addition of oxygen to form two carbonyl groups. The product formed depends on the position of the double bond and the number of carbon atoms on either side of it.

When propene undergoes oxidative cleavage, it forms a ketone with three carbons, namely acetone, as the only product. This is because propene has a double bond between the second and third carbon atoms, and upon cleavage, it forms two carbonyl groups, one on each end of the double bond, resulting in acetone with three carbons.

In contrast, alkenes with four or more carbon atoms will form a mixture of ketones and aldehydes upon oxidative cleavage.

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The percentage yield is equal to 200.6%.

The balanced equation for the given chemical reaction is :

2C2H + 5O2 → 4CO2 + 2H2O

Let's find the limiting reagent:

Mass of C2H = 120 g

Mass of O2 = 288 g

Molar mass of C2H = 26 g/mol

Molar mass of O2 = 32 g/mol

The number of moles of C2H is equal to:

120 g × 1 mol/26 g = 4.62 mol

The number of moles of O2 is equal to:

288 g × 1 mol/32 g = 9 mol

According to the stoichiometry of the balanced equation, 2 moles of C2H react with 5 moles of O2, so:

If 4.62 moles of C2H is used, then the required amount of O2 would be:

5/2 × 4.62 mol = 11.6 mol

We only have 9 mol of O2 which means it is the limiting reagent.

C2H is the excess reagent.

Let's find the mass of water produced:

According to the stoichiometry of the balanced equation,2 moles of H2O is produced per 2 moles of C2H2 moles of H2O is produced per 5 moles of O2If 9 mol of O2 is used, the number of moles of water produced would be:

2/5 × 9 mol = 3.6 mol

The mass of water produced is equal to:

3.6 mol × 18 g/mol = 64.8 g

Therefore, 64.8 g of water can be produced.

The amount of excess reagent is equal to:

4.62 mol - 2/2 × 9 mol = 4.62 - 9

= -4.38 mol

C2H is the excess reagent and it is not possible to have negative amount of a substance.

So, we assume that there is no excess reagent.

If 130 grams of water is produced, then the percentage yield is equal to:

Percent yield = actual yield/theoretical yield × 100

Theoretical yield is equal to 64.8 g

Actual yield is equal to 130 g

Percent yield = 130/64.8 × 100

= 200.6%

Therefore, the percentage yield is equal to 200.6%.

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Answer:

40.0 mL. (4 marks)...

Explanation:

Answer:

15.27895 x 10⁶kg of chlorine radical is added to the atmosphere in a year due to 100 million MVACs                                                                                              

Explanation:

Chlorofluorocarbons (CF₂Cl₂) from refrigerants produce chlorine radicals according to the following equation

         CF₂Cl₂ → CF2Cl  + Cl ⁻ .........(1)

From equation 1, one mole of CF₂Cl₂ produces one mole of Chlorine radical

From the question,

The emission rate of CF₂Cl₂ is 59.5mg/hour/MVAC

In one day the emission rate would be 59.5 x 24hours

                                                                  = 1428mg/day

In one year, the emission rate would be 1428mg/day x 365days

                                                                 =  521220mg/year

                                                                   = 521.220g/year/MVAC

Therefore the emission rate for 100 million MVAC using CF₂CL₂ in a year is

                                                                    = 52122 x 10⁶g/year/MVAC

                                                                    = 52122 x 10³kg/year/MVAC

The molar mass of CF₂CL₂                       = 120.913g/mol

No of moles  of CF₂CL₂                              = mass/ molar mass

                                                                     = 52122 x 10⁶g / 120.913g/mol

                                                                      = 431 x 10⁶ moles of CF₂Cl₂

From equation 1,  since one mole of CF₂Cl₂ produces one mole of Chlorine radical, it implies that

431 x 10⁶ moles of CF₂Cl₂ would produce 431 x 10⁶ moles of chlorine radical,

Therefore, to find the mass of chlorine radical produced, we use the formula

No of moles of chlorine radical  = mass/ molar mass

431 x10⁶ moles = mass of chlorine radical /molar mass of chlorine radical

431 x 10⁶ moles = mass/ 35.45g/mol

mass of chlorine =  431 x 10⁶ moles x 35.45 g/mol

                            =    15278.95 x 10⁶ g

In Kg, the mass    =   15,278.95 x 10³kg of cholrine radical

                             =   15.27895 x 10⁶ Kg of chlorine radical

Answer:

Degree Celsius

In the asthenosphere, density and temperature are the primary contributors to convection currents.

What exactly is the Earth's asthenosphere?

The weaker, denser layer below the lithospheric mantle is known as the asthenosphere. It is between 62 miles and 410 kilometers (100 miles) below the surface of the Earth. Because of the asthenosphere's extreme heat and pressure, rocks begin to weaken and partially melt, turning semi-molten.

What is the short definition of the asthenosphere?

Located under the lithosphere, the asthenosphere is a region of the Earth's mantle that is thought to be significantly hotter and more fluid than the lithosphere. Between 100 km (60 miles) and 700 km (450 miles) below the surface of the Earth is the asthenosphere.

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Answer:

compounds are substance which can be formed by chemically combining two or more elements.

mixtures are substance that are formed by physically mixing two or more substances

An atom of 10B contains 5 protons, 5 neutrons, and 5 electrons since atoms are electrically neutral, the number of protons is equal to the number of electrons.

Boron-10 is an isotope of boron, which means it has the same number of protons but a different number of neutrons compared to the most common isotope of boron, which is boron-11.

The atomic number of boron is 5, so it always has 5 protons.

The atomic mass of boron-10 is 10, which means it has 5 neutrons (10 - 5 = 5).

Since atoms are electrically neutral, the number of protons (positive charge) is equal to the number of electrons (negative charge).

Therefore, a boron-10 atom also contains 5 electrons.

In summary, an atom of 10B contains 5 protons, 5 neutrons, and 5 electrons.

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Answer: Acetaldehyde (IUPAC systematic name ethanal) is an organic chemical compound with the formula CH3CHO

Explanation:

According to the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature. Therefore, 1.63 mol of argon gas will occupy a volume of 41.0 L under the same conditions of temperature and pressure.

Since the temperature and pressure are the same in both cases, we can set up a proportion:
(PV)/n = (PV)/n
Substituting the values given in the question, we get:
(P x 64.3)/2.70 = (P x V)/1.63
Simplifying this equation, we get:
V = (2.70 x 64.3 x 1.63) / (1.63 x 2.70)
V = 41.0 L
To find the volume occupied by 1.63 mol of argon under the same temperature and pressure conditions, we can use the concept of molar proportionality.
Given:
Initial moles of argon (n1) = 2.70 mol
Initial volume (V1) = 64.3 L
Final moles of argon (n2) = 1.63 mol
Final volume (V2) = ?
Since the temperature and pressure conditions are the same for both situations, we can use the following proportion:
n1 / V1 = n2 / V2
Now, we'll solve for V2:
V2 = (n2 * V1) / n1
Plug in the given values:
V2 = (1.63 mol * 64.3 L) / 2.70 mol
V2 ≈ 39.0 L
So, under the same conditions of temperature and pressure, 1.63 mol of argon gas will occupy a volume of approximately 39.0 L.

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Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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To produce 2.00 L of CO2 at STP using the given reaction, you would need to use approximately 3.77 grams of sodium bicarbonate.

To produce 2.00 L of CO2 at STP using the given reaction, you would need to calculate the mass of sodium bicarbonate required. The balanced equation for the reaction is:

2 NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g)

The molar ratio between sodium bicarbonate (NaHCO3) and carbon dioxide (CO2) is 2:1. The molar mass of sodium bicarbonate is 84.0066 g/mol.

Using the equation:
mass = volume x molar mass / molar ratio

Substituting the given values, we have:
mass = 2.00 L x (22.4 L/mol) x (84.0066 g/mol) / 1 = 3.77 g

Therefore, you should use approximately 3.77 grams of sodium bicarbonate to produce 2.00 L of CO2 at STP.

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Answer:

valence electrons

Answer:

ALPHA

Explanation:

Answerfirst one

Explanation:

We can use the formula:

M1V1 = M2V2

where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

In this case, we know:

M1 = 12.0 M

V1 = ?

M2 = 0.100 M

V2 = 500.0 mL = 0.500 L (since 1 mL = 0.001 L)

We can rearrange the formula to solve for V1:

V1 = (M2V2) / M1

Substituting the values we know, we get:

V1 = (0.100 M)(0.500 L) / 12.0 M

V1 = 0.00417 L = 4.17 mL

Therefore, we need to measure 4.17 mL of 12.0 M hydrochloric aqueous solution and add it to 500.0 mL of water to prepare 500.0 mL of a 0.100 M diluted solution.

The addition of ice at the end of the heating process is important because it increases the solubility of the aspirin product.

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The formula for the limiting reagent is Fe, and the maximum amount of iron(II) oxide that can be produced is 0.135 moles.

To determine the limiting reagent and the maximum amount of iron(II) oxide that can be produced, we need to compare the moles of each reactant and their stoichiometric ratios in the balanced equation.

The balanced equation for the reaction is:

4Fe(s) + 3O₂(g) → 2Fe₂O₃(s)

From the balanced equation, we can see that the stoichiometric ratio between iron and oxygen is 4:3. This means that 4 moles of iron react with 3 moles of oxygen to produce 2 moles of iron(II) oxide.

Moles of iron(II) oxide = min (0.270 moles of Fe, (0.579 moles of O₂) × (2 moles of Fe₂O₃ / 3 moles of O₂))

To determine the limiting reagent, we compare the moles of iron and oxygen and choose the reactant that produces the lesser moles of iron(II) oxide. In this case, we have:

Moles of iron(II) oxide produced from 0.270 moles of Fe = 0.270 moles × (2 moles of Fe₂O₃ / 4 moles of Fe) = 0.135 moles

Moles of iron(II) oxide produced from 0.579 moles of O₂ = 0.579 moles × (2 moles of Fe₂O₃ / 3 moles of O₂) = 0.386 moles

Since 0.135 moles of iron(II) oxide is less than 0.386 moles, the limiting reagent is iron.

Therefore, the formula for the limiting reagent is Fe, and the maximum amount of iron(II) oxide that can be produced is 0.135 moles.

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When choosing a substance for use in a cooling system, we want a substance that can absorb a large amount of heat without undergoing a significant temperature change. This is where the specific heat capacity of a substance comes into play.

The specific heat capacity of a substance is defined as the amount of heat required to raise the temperature of one unit of mass of the substance by one degree Celsius (or Kelvin). A substance with a high specific heat capacity requires more heat to raise its temperature by a certain amount than a substance with a low specific heat capacity. Therefore, a substance with a high specific heat capacity would be best for use in a cooling system.

Out of the options given, a liquid with a high specific heat would be the best choice for use in a cooling system. Liquids have a higher specific heat than gases, which makes them better at absorbing and storing heat. Additionally, liquids have a higher thermal conductivity than solids, which means they can more efficiently transfer heat from one location to another.

Moreover, among the liquids, water is a commonly used coolant due to its high specific heat capacity, which means it can absorb a large amount of heat without undergoing a significant temperature change. Additionally, water has a high boiling point, which makes it effective at absorbing heat from high-temperature sources without boiling and evaporating.

In summary, a liquid with a high specific heat, such as water, would be the best choice for use in a cooling system due to its ability to absorb and store heat efficiently.

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Among the given options, the element that has the lowest ionization energy is beryllium. Thus, the correct option for this question is C.

Ionization energy may be defined as the amount of energy that is significantly required in order to eliminate an electron from an isolated atom or molecule. It is the minimum energy required to remove the most loosely bound electron of an isolated gaseous atom, positive ion, or molecule.

The group of elements that have the lowest ionization energy is known as alkali metals or alkali earth metals. This is because of the shielding effect that the ionization energy decreases from top to bottom within a group. Beryllium is a member of group 2 which has the lowest ionization energy. While Fluorine is said to have the highest ionization energy.

Therefore, the element that has the lowest ionization energy is beryllium. Thus, the correct option for this question is C.

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Answer:

33.4814814815

Explanation:

90.4/2.70

Answer:

html

Explanation:

im in web tech