An airplane has a mass of 2.5×10^6 kg , and the air flows past the lower surface of the wings at 80 m/s .
If the wings have a surface area of 1600 m2 , how fast must the air flow over the upper surface of the wing if the plane is to stay in the air?

The elastic potential energy stored is 0.9375 J.

The elastic potential energy stored in a spring can be calculated using the following formula:

Elastic potential energy = 0.5 × k × x²

where:

k is the spring constant

x is the distance the spring is compressed or stretched

In this case, the spring constant is given as 12.5 N/mm and the compression is 0.15 mm. Plugging these values into the formula, we get the following:

Elastic potential energy = 0.5 × 12.5 N/mm × (0.15 mm)²

= 0.9375 J

Therefore, the elastic potential energy stored is 0.9375 J.

The elastic potential energy stored in the abductin pad is used to open the shell when the muscles relax. The muscles close the shell by contracting, which compresses the pad. When the muscles relax, the pad expands, pushing the shell open. The energy to do this comes from the elastic potential energy that was stored in the pad when it was compressed.

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Answer:

\(a=0.8\ m/s^2\)

Explanation:

Given that,

Mass of a toy, m = 0.62 kg

Horizontal force, F = 16.3 N

Force on the opposite direction, F' = 15.8 N

We need to find the acceleration of the toy.

Here, two forces are acting in opposite direction, the net force will be the difference of forces.

Net force = 16.3 N-15.8 N

=0.5 N

The formula for net force is given by :

F = ma

a is the acceleration of the toy

\(a=\dfrac{F}{m}\\\\a=\dfrac{0.5\ N}{0.62\ kg}\\\\a=0.8\ m/s^2\)

So, the acceleration of the toy is \(0.8\ m/s^2\).

In physics, tension is described as the pulling force transmitted axially by the means of a string, a cable, chain, or similar object, or by each end of a rod, truss member, or similar three-dimensional object.

According to the question, the formula we use in this method is F = ma as we have to find the acceleration.

Therefore, the formula for the acceleration is

\(a= \frac{F}{m}\)

\(a= \frac{0.5}{0.62}\)

Hence, after the calculation, the acceleration is 0.8m/s.

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The total pressure acting on the submarine is equal to 2967.19 mmHg.

To find pressure at a depth of 30 m under the sea surface by using the formula:

P = ρgh

P = pressure,

ρ = density of the liquid

g = acceleration due to gravity

h = depth

According to question

density of seawater = 1g/cm³, which is equivalent to 1000 kg/m³

1g/cm³ = 1000 kg/m³, and

h is equal to  30 m,

We can find the pressure on the submarine by using:

Pressure = ρgh

Pressure = 1000 kg/m³ × 9.81 m/s² × 30 m

Pressure = 294300 Pa

To calculate the total pressure to act upon the submarine, add the atmospheric pressure to the pressure due to the seawater.

According to question atmospheric pressure is 760mmHg, which is equal to 101325 Pa (1mmHg = 133.322 Pa), the total pressure on the submarine can be obtained as:

Total pressure is equal to atmospheric pressure + pressure due to seawater

P = 101325 Pa + 294300 Pa

P = 395625 Pa

To change this pressure into units of mmHg, use the information that 1 Pa = 0.0075 mmHg

Total P in mmHg = 395625 Pa × 0.0075 mmHg/Pa

So, total pressure in mmHg is 2967.19 mmHg.

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Answer:

B. 4 times

Explanation:

Fg'=G(2m1)(2m2)/d²

Fg'=4Gm1m2/r²

A wave that remains in a constant position is referred to as a stationary wave or a standing wave.

It is formed by the superposition of two waves with the same frequency and amplitude traveling in opposite directions. Unlike a traveling wave that moves through space, a standing wave appears to be stationary because the wave peaks and troughs oscillate in place.

The formation of a standing wave occurs when a wave reflects back upon itself, interacting constructively and destructively with the incoming wave. This phenomenon is characterized by the presence of nodes and antinodes. Nodes are points along the wave where the amplitude is always zero, resulting from destructive interference between the two waves. Antinodes, on the other hand, are points of maximum displacement, created by constructive interference..

Standing waves have significant implications in various fields of study. In physics and engineering, they are essential in the analysis of acoustics, optics, and electromagnetic fields. They find applications in musical instruments, where standing waves inside the instrument's resonating body create distinct harmonics and produce specific musical tones.

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Christophe is trying to shape the light in order to get the desired result in his photograph. He is looking to identify where the light sources are and how their intensity, direction, and quality will affect the image. He might adjust the Kelvin temperature or sharpen the edges of the subject, or even use a light modifier to fade the backdrop.

Light is a powerful tool in photography that can be used to create stunning images. By understanding how to shape light, photographers can capture the perfect shot and bring their vision to life. This essay will explore the various ways light can be manipulated to produce the desired results in photography, from adjusting the Kelvin temperature to fading the backdrop and more.

To begin, it is important to recognize the various light sources that can be used to shape the image. Natural light is one of the most common sources of light used in photography, and it can be manipulated in a variety of ways. Photographers can adjust the Kelvin temperature to create the desired mood, or they can use a light modifier to soften the light, creating a more natural look. Additionally, by understanding the direction of the light and where it falls on the subject, photographers can create a more dynamic and interesting image.

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The 1 Mohm resistor using source transformations to first simplify the circuit shown is 51 MW.

What is the formula for calculating power dissipated?

To determine the power dissipated in the 1 Mohm we need to do the:

Step 1: Apply source transformation to simplify the circuit.

The circuit diagram is as follows:

Figure: Circuit diagram of the given circuitWe have a current source in the circuit which is in parallel with a resistor, so we can use the current source transformation to change the circuit in the following way:

Step 2: Simplify the circuit by calculating the equivalent resistance.

The circuit diagram after applying the source transformation is as follows:Figure: Circuit diagram after applying the source transformationWe can simplify the circuit by calculating the equivalent resistance between the terminals AB as follows:

R=1 + (3 x 2)/(3+2)=7/5=1.4 ohm

Step 3: Determine the power dissipated in the 1 Mohm resistor. The simplified circuit diagram is as follows:

Figure: Simplified circuit diagramThe current flowing through the resistor

R is:I=V/R=10/1.4=7.14 A

The power dissipated in the resistor R is:

P=I²R=7.14² x 1x10⁶=51x10⁶ W or 51 MW (approx)

Therefore, the power dissipated in the 1 Mohm resistor using source transformations to first simplify the circuit shown is 51 MW.

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The vector of the bucket is a force of 47.4 pounds acting at an angle of 39 degrees with the horizontal.

To find the vector of the bucket, we need to first calculate the net force acting on it. This can be done by resolving the given forces into their horizontal and vertical components and then adding them up.

1. Resolving Jill's force:

Jill pulled at an angle of 30 degrees with a force of 20 pounds. We can resolve this into its horizontal and vertical components as follows:

Horizontal component = 20 cos(30)

= 17.32 pounds

Vertical component = 20 sin(30)

= 10 pounds

2. Resolving Jack's force:

Jack pulled at an angle of 45 degrees with a force of 28 pounds.

We can resolve this into its horizontal and vertical components as follows:

Horizontal component = 28 cos(45)

= 19.8 pounds

Vertical component = 28 sin(45)

= 19.8 pounds

3. Adding up the components:

To find the net horizontal and vertical components, we can add up the horizontal and vertical components of the two forces as follows:

Net horizontal component = 17.32 + 19.8

= 37.12 pounds

Net vertical component = 10 + 19.8

= 29.8 pounds

4. Finding the vector:

Now that we have the net horizontal and vertical components, we can use the Pythagorean theorem to find the magnitude of the vector as follows:

Magnitude = sqrt((37.12)^2 + (29.8)^2)

= 47.4 pounds

Finally, we need to find the direction of the vector. We can use trigonometry to find this as follows:

Tanθ = Net vertical component / Net horizontal component = 29.8 / 37.12θ

= tan^-1(29.8 / 37.12)

= 39 degrees (approx.)

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Answer:

6m/s

Explanation:

Centripetal force is expressed according to the formula;

F = mv²/r

m is the mass of the body

v s the speed of the cart

r is the radius

Given

M = 2kg

r = 3m

Force F = 24N

Substitute into the formula and get v

24 = 2v²/3

24×3 = 2v²

72 = 2v²

v² = 72/2

v² = 36

v =√36

v = 6m/s

Hence the speed of the cart is 6m/s

The magnitude of the net force acting on the driver is 843,600 N. To calculate the force acting on the driver, we used the equation F = ma, where F is the net force, m is the mass of the driver, and a is the average deceleration.

We can use the equation for average acceleration, which relates the change in velocity to the time taken and the acceleration:

a = Δv/Δt

where Δv is the change in velocity, Δt is the time taken, and a is the average acceleration.

In this case, the driver goes from a speed of 18.0 m/s to rest in a distance of 5.00 cm, which we can convert to 0.0500 m. We can assume that the deceleration is constant over this distance, so we can use the equation of motion:

v² = u² + 2as

where v is the final velocity (zero in this case), u is the initial velocity (18.0 m/s), a is the acceleration, and s is the distance.

Solving for a, we get:

a = (v² - u²)/(2s)

= (-18.0²)/(2x0.0500)

= -12,960 m/s²

The negative sign indicates that the acceleration is in the opposite direction to the initial velocity, as expected for deceleration.

Now we can use Newton's second law, which relates force, mass, and acceleration:

F = ma

where F is the net force, m is the mass (65.0 kg), and a is the average acceleration that we just calculated:

F = (65.0 kg)(-12,960 m/s²)

= -843,600 N

The negative sign indicates that the force is in the opposite direction to the initial motion, which is also expected for deceleration. Therefore, the magnitude of the net force acting on the driver is 843,600 N.

When the driver encounters something solid like the steering wheel, the force of the impact is distributed over a small area of the driver's body, causing a large deceleration in a short amount of time. This is why the driver comes to rest in just a few centimeters, causing a large force to be exerted on their body.

To calculate the force acting on the driver, we used the equation F = ma, where F is the net force, m is the mass of the driver, and a is the average deceleration. The negative sign in the answer indicates that the force is in the opposite direction to the initial motion, as expected for deceleration.

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Finding a suitable material for the filament of an incandescent light bulb was one of Thomas Edison's biggest obstacles.

The source of light in an incandescent light bulb is the filament, which is a wire-like structure. It is often constructed of tungsten or another material with a high melting point and good thermal shock resistance. When an electric current is sent through the filament, which is commonly twisted into a coil or loop shape, the filament heats up and starts to generate light.

Thermal radiation causes the filament to produce light. This is the result of the filament's temperature-related electromagnetic radiation output. The filament starts to emit infrared radiation and visible light as it warms up.

The filament's temperature and the kind of material it is constructed of affect the hue of the light it emits.

A glass bulb that has been evacuated or a bulb that has been filled with an inert gas, such as argon or nitrogen, surrounds the filament in an incandescent light bulb. By doing this, you can avoid the filament from burning out or breaking, which would make the lightbulb unusable.

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Answer:

Vectors have both magnitude and direction

Explanation:

Vectors show how strong the force in because the bigger the arrow, the stronger the force.  Also, it obviously shows direction because its an arrow.

Vectors have magnitude and direction while scalars have only magnitude. Vectors are shown using an arrow above the symbol of the quantity and are often printed in bold face.

In Physics, we generally recognize two categories of quantities; vector quantities and scalar quantities.

Vector quantities have both magnitude and direction. It is normal to print vectors in bold face, with an arrow written above the symbol of the quantity. The arrow points in the direction of the vector.

The following are true regarding vectors;

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Answer:

Some object have less gravitational pull than other objects.

Explanation:

The energy connected to the disorderly, random motion of molecules is known as internal energy. It refers to the intangible microscopic energy at the atomic and molecular scales, which is distinct in scale from the macroscopic organized energy associated with moving objects.

In thermodynamics, internal energy is a property or state function that characterizes a substance's energy in the absence of capillary effects and the impacts of external magnetic, electric, and other fields.

The sum of the kinetic and chemical potential energies of all the particles in the system is the internal energy. Particles accelerate and pick up kinetic energy when energy is applied to increase the temperature.

Examples of internal energy include a substance's temperature and condition. For instance, the internal energy of water is influenced by its temperature as well as whether it is in the solid, liquid, or gas state. Due to its condition, liquid water has greater internal energy than solid copper at the same temperature.

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The outside diameter or side dimension of the vibrating element must be at least 19 mm but not greater than 38 mm is true. A vibration sensor is a system that is used to identify the condition of machinery and prevent it from being harmed. It keeps track of vibrations in the machinery and sends an alert if it exceeds a set threshold.

A sensor that detects vibrations in the environment or within a physical structure is known as a vibration sensor. Vibration sensors are commonly utilized in the maintenance of rotating equipment like pumps, motors, and other machinery to predict failure before it happens.

Based on the vibration being observed, these sensors may detect a range of defects, from unbalance and misalignment to bearing wear and looseness.

The outside diameter or side dimension of the vibrating element must be at least 19 mm but not greater than 38 mm. Hence, the given statement is true. This size range is important for the sensor to be able to pick up on the machinery's small vibrations and changes.

Anything smaller than 19 mm will not detect vibrations with the same precision, and anything larger than 38 mm will be more difficult to install in tight locations.

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Answer:

a) the building of irrigation systems

Explanation:

Although b and c would also allow for farmers to grow more crops, I believe that the building of irrigation systems had the most impact. Irrigation systems allowed for farmers to have larger fields without having to spend a large amount of time watering the entire field.

Answer: I think it is a

Explanation:

Answer:

Explanation:

It's not equal and opposite. You're thinking of Newton's 3rd Law. This is not that. This is gravitational attraction between 2 objects. We can figure out mathematically the pull that the earth has on a single person, by using the equation for gravitational force and the universal gravitational constant, G:

\(F_g=\frac{Gm_1m_2}{r^2}\) where G is the universal gravitational constant, m1 is the mass of one person, m2 is the mass of the earth, and r-squared is the addition of the radius of the earth plus the radius of you in relation to the surface of the earth.

Let's say a person weighs 150 pounds; in Newtons this is 667 N (rounded from 667.233); his mass then, in terms of the metric system (using 9.8 for gravity), is 68.2 kg. Let's also say that this person is 6 feet tall. 6 feet is the same as 1.83 m (rounded to 3 sig fig's) and the radius from that person's center to the surface of the earth would be about half that height at r = .915 meters. Filling in the formula:

\(F_g=\frac{(6.67*10^{-11})(68.2)(5.98*10^{24})}{(6.38*10^6)^2}\) it turns out that the person's radius adds nothing significantly to the radius of the earth, so it doesn't even count mathematically. It's way too small compared to the earth's radius (which is the denominator of that equation). We find that

\(F_g=668N\) That's the pull that the earth has on that person which, not coincidentally, is the weight in pounds we said that the person was. Isn't physics amazing!?

Because the refractive indexes of the immersion oil and the glass microscope slide are the same; the oil prevents the refraction of the incoming light rays.

An invisible space is present between the slide and the lens that contains air.

When the light rays fall on the slide and lens they might get refracted due to air present between them.

If the rays get refracted then the diameter of the objective lens will expand further.

So in order to prevent the refraction of light, it is very important to lubricate the surface of the lens because glass and oil have same refractive index and without oil the light rays refract from their original path.

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Allele frequencies are unaffected by assortative mating, but genotype frequencies .

Individuals with similar phenotypes and genotypes mate with others more frequently than is anticipated under a random mating pattern in assortative mating, which is a mating pattern and a type of sexual selection.

A population's genotype frequency is calculated by dividing the number of people having a particular genotype by the overall population size. The genotype frequency in population genetics is the frequency or ratio (i.e., 0 f 1) among genotypes inside a population.

The term "allele frequency" describes the prevalence of an allele in a population. It is calculated by calculating the number of times the allele occurs in the population and dividing by the sum of all the gene copies.

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The spring constant is:

                                             \(\Large\displaystyle\text{$\begin{aligned}k &= 612.5\ \dfrac{\text{N}}{\text{m}}\end{aligned}$}\)

To calculate the spring constant we must remember the law for it, the Hooke's Law:

                                            \(\Large\displaystyle\text{$\begin{aligned}\vec{F} = -k\Delta \vec{x} \end{aligned}$}\)

Where k is the spring constant [N/m].

So if the mass is suspended it means that its weight is equal to the elastic force (values), then we can write:

                                           \(\Large\displaystyle\text{$\begin{aligned}\vec{W} = k\Delta \vec{x} \end{aligned}$}\)

Therefore:

                                          \(\Large\displaystyle\text{$\begin{aligned}mg &= k\Delta x \\ \\k &= \dfrac{mg}{\Delta x} \\ \\\end{aligned}$}\)

Now we just have to put the values and calculate:

                                              \(\Large\displaystyle\text{$\begin{aligned}k &= \dfrac{mg}{\Delta x} \\ \\k &= \dfrac{5\cdot 9.8}{0.08} \\ \\k &= 612.5\ \dfrac{\text{N}}{\text{m}}\end{aligned}$}\)

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Answer:

Work, W = F * d, and

Work = change in kinetic energy, so W=deltaKE.

Hence,

deltaKE=F * d

(1/2)*m*v^2 =F * d

d=[(1/2)*m*v^2]/F

d=[(1/2)*0.6*20^2]/5

d=24 m.

Explanation:

Work = change in kinetic energy, so W=deltaKE.

The impulse delivered by the wall when the ball hits is 10m kgm/s.

To find the impulse delivered by the wall, we need to first find the change in momentum of the ball during the collision with the wall. Since momentum is a vector quantity, we need to break it down into its x and y components.

The initial momentum of the ball:

\(p_i = m \times v_i\)

where m is the mass of the ball, and v_i is the initial velocity of the ball.

\(p_{i_x} = m \times v_i \times cos(60^\circ)\)

\(p_{i_y} = m \times v_i \times sin(60^\circ)\)

Substituting the given values, we get:

\(p_{i_x} = m \times 10 \ m/s \times cos(60^\circ) = 5m \ kg m/s\)

\(p_{i_y} = m \times 10 \ m/s \times sin(60^\circ) = 8.66m \ kg m/s\)

The final velocity of the ball is at an angle of 60 degrees above the negative x-direction. This means that the angle between the final velocity and the initial velocity is 120 degrees. We can use the law of reflection to determine the final x and y components of the velocity:

\(p_{f_x} = -p_{i_x}\)

\(p_{f_y} = p_{i_y}\)

So, the change in momentum of the ball is:

\(\Delta p_x = p_{f_x} - p_{i_x} = -2p_{i_x} = -10m \ kg m/s\)

\(\Delta p_y = p_{f_y} - p_{i_y} = 0\)

The impulse delivered by the wall is equal to the change in momentum of the ball:

\(J = \Delta p = \sqrt{(\Delta p_x^2 + \Delta p_y^2)} = 10m \ kg m/s\)

Therefore, the impulse delivered by the wall is 10 times the mass of the ball, in kg m/s.

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The range of electronegativity for polar nonpolar and ionic bonding will be    between 1.5 and 2.1

Electronegativity is a chemical property that describes the tendency of an atom or a functional group to attract electrons toward itself.

The range of electronegativity for polar nonpolar and ionic bonding . So,  the difference in electronegativity is somewhere between 1.5 and 2.1, between a polar covalent bond and an ionic bond.

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The range of electronegativity for polar nonpolar and ionic bonding is less than 0.4 and greater that 0.4, respectively.

In general there are two major categories of bonds, which are polar molecules and nonpolar molecules.

In the field of chemistry, polarity can be described as the distribution of electric charge around atoms, chemical groups, or molecules.

There is no hard and fast rule but in general, a bond is considered as non polar if the difference in electronegativities is less than about 0.4, and it will be called a polar bond molecule if the difference is greater than 0.4.

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The voltage in the secondary coil for a step up transformer is 1.58 x 10³ Volts.

The potential difference between two ends of a metallic conductor is called the voltage.

The primary coil has Np = 250 turns and the secondary coil has Ns = 475 turns. If the input effective voltage is 83.0 V,

Turn ratio = Ns/Np = Vs/Vp

Substituting the values, we get the value of Vs

Vs =(475/250) x 83V

Vs = 1.58 x 10³ Volts

Thus, the voltage in the secondary coil is 1.58 x 10³ Volts

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Tension must a rope withstand is 2.182kN

Tension is described stress transmitted axially by a cord, rope, chain, or similar object, or through the ends of a rod, truss, or similar three-dimensional object. Stresses can also be described as pairs of acting and reaction forces acting at each end of the element. Tension may be the opposite of compression. At the atomic level, a restoring force can create what is called stress when atoms or molecules are pulled apart and gain potential energy while the restoring force is still present. An end of a cord or rod under such tension can pull on the object to which it is attached to return the cord or rod to its relaxed length.

Solution:

Assuming only tension and gravity act on the car,

T+mg=ma

T=m(g+a)

=3074*(9.81 - 9.1) N

=2.182 kN which is the tension the rope must withstand.

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Answer:

A. adjust the seat so you can reach all controls

------------------------------------------------------

This is so you can reach the gas petal, break petal, steering wheel, (and other things) easier so you won't have to lean forward and it makes it easier for when you're driving. Especially if you need to quickly press your breaks, you'll be able to do this a lot faster if you're closer to them than if you had to reach in order to do so.

I hope this helped, im not the best at explaining things lol

At low pressure, a gas behaves more like an ideal gas. At low or high pressure, the gas acts as an ideal gas. Here option B is the correct answer.

The behavior of a gas can be described by its equation of state, which relates the pressure, volume, and temperature of the gas. An ideal gas is a theoretical gas that obeys the ideal gas law, which is a simple equation of state that assumes that the gas particles have zero volume and no intermolecular forces. In reality, no gas perfectly follows this law, but some gases behave more like an ideal gas than others.

At low pressures, the particles of a gas are relatively far apart, and their interactions with each other are weak. Therefore, gas will behave more like an ideal gas at low pressure because its particles are more likely to obey the assumptions of the ideal gas law. The volume of the particles becomes negligible compared to the volume of the container, and the intermolecular forces between the particles are negligible, allowing them to move freely without any interaction.

On the other hand, at high pressures, the particles of a gas are packed more closely together, and their interactions with each other become stronger. This leads to deviations from the ideal gas law, and the gas is less likely to behave like an ideal gas. As a result, a gas will not behave like an ideal gas at high pressure.

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Complete question:

Does a gas behave more like an ideal gas at low pressure or high pressure?

A - the ideal gas behavior of a gas is independent of the pressure.

B - a gas will behave more like an ideal gas at low pressure.

C - a gas will behave more like an ideal gas at high pressure.

Answer:

atoms and molecules

Explanation:

as opposed to being continuous or just including particles). On the following page, the idea is stated as one of four concepts in Dalton's theory: “All matter is composed of tiny, indivisible particles called atoms”

Answer: atoms

Matter is made of atoms, the basic building blocks. Atoms are made of protons, neutrons and electrons. The answer is atoms.

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The m dot = 1A1v1 = (821 kg/m3)(0.618 m2)(2.117 m/s) 1077 kg/s is the flow rate of the oil.

fluid moving through a horizontal pipe P1 + ½ρv12 = P2 + ½ρv22. The pressure will depend on the fluid's speed if it is flowing frictionlessly through a horizontal pipe with a variable cross-sectional area as a liquid (or a gas that is not being compressed).

The fluid's velocity and cross-sectional area before and after the pipe's constriction can be compared using the continuity concept.

ρ1A1v1 = ρ2A2v

Moreover, we may link the fluid's pressure and velocity before and after the constriction using Bernoulli's equation:

P1 + 1/2ρ1v1² = P2 + 1/2ρ2v2²

v2 = (ρ1/ρ2) × (A1/A2) × v1

P1 + 1/2ρ1v1² = P2 + 1/2ρ1(A1/A2)²(v1)²

Solving for v1, we get:

v1 = sqrt(2(P1 - P2)/ρ1(1 - (A1/A2)²))

v1 = sqrt(2(7980 - 5985)/(821)(1 - (0.618/0.223)^2)) = 2.117 m/s.

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