9. What is the process of nuclear fusion? *
(10 Points)
O A. The process of carrying light
B. The process of two atoms fusing
O C. The process of gravity and inertia keeping the universe together
O D. The process of fusing two stars
Answer:
the process of carrying light
HELP DUE TOMMOROW! FAILING CLASS!!! When it would be appropriate to use Radiocarbon dating, Rubidium-Strontium dating, Uranium-Lead dating, and Potassium-Argon dating. Include if the types of dating are used for organic or inorganic things and the time range they are useful for.
Answer:
Uhm if you're failing the class why are you still using brainly to get answers... Where's your momma boy?
Explanation:
It izzz what it izzz
what happens to your body if carbon dioxide is not removed
Explanation:
can damage the tissues and organs and further impair oxygenation of blood
The combustion of glucose, C6 H12 O6 (s), produces carbon dioxide, CO2 (g), and water, H2 O(g), according to the equation below. Upper C subscript 6 upper H subscript 12 upper O subscript 6 (s) plus 6 upper O subscript 2 (g) right arrow 6 upper C upper O subscript 2 (g) plus 6 upper H subscript 2 upper O (l). The enthalpy of the reaction is â€"2,840 kJ. What is the heat of combustion, per mole, of glucose? â€"2,840 kJ/mol â€"473. 3 kJ/mol 473. 3 kJ/mol 2,840 kJ/mol.
The heat of combustion, per mole, of glucose is -2,840 kJ/mol.
The proper equation for the combustion of glucose is shown as follows;
C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(g)
The heat of combustion is the heat released when the substance is burnt under standard conditions.
From the question, the enthalpy of combustion of glucose is -2,840 kJ. Let us recall that the equation shows the heat required to burn 1 mole of glucose. Hence, the heat of combustion, per mole, of glucose is -2,840 kJ/mol.
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Answer:
A
Explanation:
EDGE 2022
product of molar concentration of ion raised to the power of number of ions produced per compound in saturated solution is called as
The product of molar concentration of ion present in chemical reactants raised to the power of number of ions produced per chemical compound in a saturated solution is called: solubility product.
What is solubility product?Solubility product can be defined as a product of the molar concentration of ion present in two or more chemical reactants raised to the power of number of ions produced per chemical compound in a saturated solution.
The formula for solubility product.Mathematically, the solubility product is given by this formula:
\(K_{sp} = [A^+]^x[B^{-}]^y\)
Where:
k is the rate constant.A is the molar concentration of ion.B is the molar concentration of ion.x and y are the number of ions.In Chemistry, the solubility product is typically used as an equilibrium constant for the dissolution of a chemical compound in a saturated solution.
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1. -
Averigua la molaridad de una disolución que contiene 58,8 gramos de yoduro de calcio (CaI2) , por litro
The molarity of the solution comes out to be 0.200 M, which is calculated in the below section.
The number of moles of calcium iodide can be calculated as follows-
n = m / M ......(1)
Molar mass (M) of Calcium iodide = 293.887 g/mol
Mass (m) = 58.8 grams
Substitute the known values in equation (1) as follows-
n = 58.8 grams / 293.887 g/mol
= 0.200 moles
Now, the molarity can be calculated using the below formula-
Molarity = no. of moles / Volume
= 0.200 moles / 1 L
= 0.200 M
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Complete question-
Find the molarity of a solution that contains 58.8 grams of calcium iodide (CaI2), per liter.
CALCULATE THE VOLUME OF 16 g OF OXYGEN GAS AT S.T.P?
Answer:
To calculate the volume we must first find the number of moles
Number of moles (n ) = mass / Molar mass (M)
Since oxygen is diatomic
M of oxygen = 16 × 2 = 32g/mol
n = 16 / 32 = 0.5mol
Next we use the formula
V = n × V(dm³)
where V is the volume
V(dm³) is the volume of 1 mole of a substance at s.t.p which is
22.4dm³
Volume of oxygen gas at s.t.p is
0.5 × 22.4dm³
= 11.20dm³
Hope this helps you
Calculate the concentration of a solution made by diluting 83.083.0 mL of 5.45.4 M HBrHBr to a final volume of 750.0750.0 mL.
To calculate the concentration of a solution made by diluting 83.0 mL of 5.4 M HBr to a final volume of 750.0 mL, we will use the formula: C1V1 = C2V2. Here, C1 = 5.4 M, V1 = 83.0 mL, V2 = 750.0 mL, and we need to find C2.
When a concentrated solution is diluted, the number of moles of the solute remains constant, as per the law of conservation of mass. This means that the number of moles of the solute present in the concentrated solution is equal to the number of moles of the solute present in the diluted solution. Hence, we can equate the initial and final number of moles of the solute. The initial number of moles of HBr present in the concentrated solution can be calculated using the formula:Initial moles of HBr = Molarity × Initial volume (in liters) = 5.4 M × 0.0830 L = 0.4482 molThe final number of moles of HBr present in the diluted solution can be calculated using the formula:Final moles of HBr = Molarity × Final volume (in liters) = C2 × 0.750 LWe know that the initial and final number of moles of HBr are equal. Hence: Initial moles of HBr = Final moles of HBr⇒ 0.4482 mol = C2 × 0.750 L⇒ C2 = 0.4482 mol / 0.750 L⇒ C2 = 0.60 M
Therefore, the concentration of the solution made by diluting 83.0 mL of 5.4 M HBr to a final volume of 750.0 mL is 0.60 M.
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please help me quick
Different rock and mineral ,soil profile
Drag and drop each of the three molecular sizes to the location each would occur during the process of column chromatography.
The correct positions of the different molecular sizes within the column chromatography are as follows: Small molecules: Start, Intermediate molecules: Middle, and Large molecules: End
Chromatography is based on the principle where molecules in mixture applied onto the surface or into the solid, and fluid stationary phase (stable phase) is separating from each other while moving with the aid of a mobile phase.
During the process of column chromatography, the different molecular sizes will settle at different positions. The small molecules are going to travel through the column at a much slower pace than the larger molecules. The three molecular sizes involved in the process of column chromatography are the following:
i) Small molecules
ii) Intermediate molecules
iii) Large molecules
Now, we have to place these molecules in their respective positions. The following is a drag and drop table which shows the positions of each molecule within the chromatography process:
Molecule size Position
Small molecule Start
Intermediate molecule Middle
Large molecule End
Therefore, the correct positions of the different molecular sizes within the column chromatography are as follows:
Small molecules: Start Intermediate molecules: Middle Large molecules: End
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A chemist wishes to convert iron into iron(II) bromide using this reaction: Fe (s) + 2 HBr (aq) → FeBr2 (aq) + H2(g) She mixes small pieces of iron with 0.2 M aqueous HBr at room temperature and discovers that the reaction proceeds slowly. List two ways she could speed up the reaction.
Increasing the surface area of iron and raising the temperature are effective ways to enhance the reaction rate and speed up the conversion of iron into iron(II) bromide.
There are two ways the chemist could speed up the reaction between iron and HBr:
1. Increasing the surface area of iron: Breaking the iron into smaller pieces or using iron filings instead of large chunks increases the exposed surface area of iron. This allows more iron atoms to come into contact with HBr, enhancing the rate of reaction.
2. Increasing the temperature: Raising the temperature increases the kinetic energy of the particles, leading to more frequent and energetic collisions. This can accelerate the reaction rate. By heating the reaction mixture, the chemist can provide the necessary energy for the reaction to occur more quickly.
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What is the condensed structural formula for the product of the hydrogenation of 2-butene using a platinum catalyst?.
The condensed structural formula for the product of the hydrogenation of 2-butene using a platinum catalyst CH3 – CH2 – CH2 – CH3
What is hydrogenation of alkene ?
Molecular hydrogen (H2) and another substance or element undergo a chemical reaction known as hydrogenation, typically in the presence of a catalyst such as nickel, palladium, or platinum. The method is frequently used to saturate or decrease organic molecules.
In order to give shortenings a hard firmness and plasticity, hydrogenation is the process of saturating certain double bonds and converting others to trans configuration. This enables the formation of solid and semi-solid fats.
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what volume, in milliliters, of a 0.156 m ba(oh)2 solution is needed to completely react 40.3 ml of a 0.170 m hcl solution.
21.97 mL (volume) of a 0.156 M Ba(OH)2 solution is needed to completely react with 40.3 mL of a 0.170 M HCl solution.
To find the volume of a 0.156 M Ba(OH)2 solution needed to completely react with 40.3 mL of a 0.170 M HCl solution, we need to use the stoichiometry of the reaction and the concept of molarity.
The balanced chemical equation for the reaction between Ba(OH)2 and HCl is:
Ba(OH)2 + 2HCl → BaCl2 + 2H2O
From the balanced equation, we can see that 1 mole of Ba(OH)2 reacts with 2 moles of HCl.
Now, let's use the given information to find the volume of the Ba(OH)2 solution required:
1. Calculate the moles of HCl:
moles of HCl = (volume of HCl) × (molarity of HCl) = (40.3 mL) × (0.170 M) = 6.851 moles HCl
2. Determine the moles of Ba(OH)2 needed:
moles of Ba(OH)2 = (moles of HCl) / 2 = 6.851 moles / 2 = 3.4255 moles Ba(OH)2
3. Calculate the volume of the Ba(OH)2 solution:
volume of Ba(OH)2 = (moles of Ba(OH)2) / (molarity of Ba(OH)2) = (3.4255 moles) / (0.156 M) = 21.97 mL
So, 21.97 mL of a 0.156 M Ba(OH)2 solution is needed to completely react with 40.3 mL of a 0.170 M HCl solution.
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we need 22.01 mL of a 0.156 M Ba(OH)₂ solution to completely react with 40.3 mL of a 0.170 M HCl solution.
To solve this problem, we can use the balanced chemical equation for the reaction between Ba(OH₂) and HCl:
Ba(OH)₂ + 2 HCl → 2 H₂O + BaCl₂
From the equation, we can see that one mole of Ba(OH)₂ reacts with two moles of HCl. Therefore, we need to calculate the number of moles of HCl in 40.3 mL of a 0.170 M solution:
moles of HCl = (0.170 mol/L) x (40.3 mL / 1000 mL/mL) = 0.006861 mol
Since two moles of HCl react with one mole of Ba(OH)₂, we need half as many moles of Ba(OH)₂:
moles of Ba(OH)₂= 0.006861 mol / 2 = 0.003431 mol
Finally, we can use the molarity and the number of moles to calculate the volume of Ba(OH)₂ solution needed:
0.156 mol/L = 0.003431 mol / V mL
V mL = 0.003431 mol / 0.156 mol/L = 22.01 mL
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A line-angle structure of terephthalic acid shows a ring with six vertices and alternating single and double bonds.
a. True
b. False
A line-angle structure of terephthalic acid does not show a ring with six vertices and alternating single and double bonds. The given statement is false
Terephthalic acid, with the chemical formula C₈H₆O₄, is a compound that consists of a benzene ring with two carboxylic acid groups (-COOH) attached to it. It does not have alternating single and double bonds in the ring structure. The correct representation of terephthalic acid would show a benzene ring with two -COOH groups attached to it.
Hence, the given statement a line-angle structure of terephthalic acid shows a ring with six vertices and alternating single and double bonds is false.
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Please help with this
1. Double-Replacement reactions
2. Decomposition
3. Combustion
4. Syntesis
5. Single replacement
Further explanationGiven
Chemical equations
Required
Type of reaction
Solution
1. 2AgNO₃ + MgCl₂ ⇒ 2AgCl + Mg(NO₃)₂
Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant
2. 2KBr⇒2K +Br₂
Decomposition
Single compound breaks down in to 2 or more products
3. C₃H₈ + 5O₂ ⇒ 4H₂O + 3CO₂
Combustion
Hydrocarbon and Oxygen reaction and form water and carbon dioxide
4. NaO + H₂O ⇒ NaOH
Syntesis
2 or more reactants combine to form a single product
5. Zn + CuCl₂ ⇒ZnCl₂ + Cu
Single replacement
One element replaces another element from a compound
(a) 2, 8, 8, 2
(b) 2, 8, 8
(c) 2, 8, 8, 4
(d) 2, 8, 8, 6
Answer:
Its C) 2,8,8,4
Explanation:
The kinetic engery of molecules increase as you go from solid liquid gas true or false
When the name of ions end with ide, is it true that they are all negative ions
Which of the following gives the balanced equation for this reaction?
Answer:
\(B\)Explanation:
Here, we want to check if the equation of the reaction is balanced or not
Now, for a balanced equation of reaction, the number of atoms of the individual elements on both sides of the equation is equal
Now, let us check the atoms:
We have 1 Sr on both sides
We have 1 SO4 on both sides
We have 1 Mg on both sides
We have 2 OH on both sides
From what we can see, the equation of the reaction is balanced
Thus, the correct answer choice is B
you have one mole of each of these atoms: carbon-12, oxygen-16, and uranium-235. Which substance has more atoms
One mole of each element contains Avogadro's number of atoms, which is 6.022 x 10^23 atoms. Therefore, all three substances have the same number of atoms, which is 6.022 x 10^23 atoms.
Perform the following operation
and express the answer in
scientific notation.
9.2x10^7 ÷ 3.7x10^9
Answer:
coefficient green : 2.4865
exponent (yellow) : 16
Explanation:
Given the following equation: H2(g)+F2(g)=2HF(g)
How many grams of HF gas are produced as 5 mol of fluorine react?
Answer:
200grams
Explanation:
The balanced chemical equation for this reaction is given as follows:
H2(g)+F2(g) → 2HF(g)
This equation shows that it takes 1 mol of both hydrogen gas (H2) and fluorine gas (F2) to produce 2 moles of hydrogen fluoride (HF)
Hence, 5 moles of fluorine gas (F2) will produce 5 × 2 = 10 moles of HF.
In order to convert the mole value of HF to gram value, we use the following formula;
Mole = mass/molar mass
Molar mass of HF = 1 + 19 = 20g/mol
mass = mole × molar mass
mass = 10 × 20
mass = 200grams of HF.
Conservation of matter means that:
55
Matter is never created nor destroyed.
Matter is always created and destroyed.
Matter always turns into energy
Matter is flexible, it can be created destroyed, or turned into energy
Answer:
Matter is never created or destroyed
To what temperature must a given Mass of nitrogen at 0°c heated so that both it volume and pressure will be double.
1/4 temperature must give Mass of nitrogen at 0°c heated so that both it volume and pressure will be double.
To double both the volume and pressure of a given mass of nitrogen at 0°C, we can utilize the combined gas law, which relates the initial and final states of a gas. The combined gas law is expressed as:
(P1 * V1) / T1 = (P2 * V2) / T2
Where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.
Since we want to double both the volume and pressure, we can set P2 = 2P1 and V2 = 2V1. Plugging these values into the combined gas law equation, we get:
(2P1 * 2V1) / T1 = P1 * V1 / T2
Simplifying the equation, we find:
4P1V1 = P1V1 / T2
Cancelling out the common terms, we have:
4 = 1 / T2
Rearranging the equation, we find:
T2 = 1 / 4
Therefore, to double both the volume and pressure of the given mass of nitrogen at 0°C, it must be heated to a temperature of 1/4 or 0.25 times its initial temperature.
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How does a scientific theory compare to a scientific law?
Answer:
Explanation:
Scientific theory is an in-depth explanation of the observed phenomenon. A law is a statement about an observed phenomenon or a unifying concept.
Determine the molecular formula of a compound with an empirical formula of NH2 and a molar mass of 32.06 g/mol.
The molecular formula of the compound is N2H4
What is the molecular formula?A molecular formula is a concise way of expressing the composition of a molecule, representing the number and type of atoms present in it. It shows the type of elements present in a molecule and the ratio of atoms of each element. The molecular formula is represented as symbols of the constituent elements with subscripts to indicate the number of each type of atom.
No we know that;
[14 + 2(1)]n = 32
n = 32/16
n = 2
The molecular formula of the compound is N2H4
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If 4.50 mol of ethane, C2H6, undergo combustion according to the unbalanced equation C2H6+ O2 CO2 + H20, how many moles of each product are formed?
Taking into account the reaction stoichiometry, 9 moles of CO₂ and 13.5 grams of H₂O are formed if 4.50 mol of ethane undergo combustion.
Reaction stoichiometryIn first place, the balanced reaction is:
2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
C₂H₆: 2 molesO₂: 7 molesCO₂: 4 gramsH₂O: 6 molesMoles of each product formedThe following rule of three can be applied:
if by reaction stoichiometry 2 moles of C₂H₆ form 4 moles of CO₂, 4.50 moles of C₂H₆ form how many moles of CO₂?moles of CO₂= (4.50 moles of C₂H₆×4 moles of CO₂)÷ 2 moles of C₂H₆
moles of CO₂= 9 moles
if by reaction stoichiometry 2 moles of C₂H₆ form 6 moles of H₂O, 4.50 moles of C₂H₆ form how many moles of H₂O?moles of H₂O= (4.50 moles of C₂H₆×6 moles of H₂O)÷ 2 moles of C₂H₆
moles of H₂O= 13.5 moles
Finally, 9 moles of CO₂ and 13.5 grams of H₂O are formed.
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What term do we use to describe how bright a star “seems” to us here on Earth?
absolute magnitude
apparent magnitud
Answer:
Apparent magnitude
Explanation:
By definition, Apparent magnitude which is usually denoted by "m" is the measure of the brightness of a star or even other astronomical objects that are observed from Earth. Meanwhile the absolute magnitude is defined as the intrinsic luminosity emitted by a star or other astronomical objects.
Thus, apparent magnitude is correct.
How do we use the scientific method and lab reports to conduct investigations and communicate our results?
Answer:
Make an observation.
Ask a question.
Form a hypothesis, or testable explanation.
Make a prediction based on the hypothesis.
Test the prediction.
Iterate: use the results to make new hypotheses or predictions.
Explanation: the order of the steps and self explanatory from there
which chair conformation is the most stable conformation of cis-1,3-dimethylcyclohexane?
The more stable conformation of cis-1,3-dimethyl cyclohexane is acquired when in which two methyl groups are at equatorial positions.
The cis conformation is obtained when two locations have axial existing within it. This axial can be up or down substitution or maybe equatorial substitution. The Trans conformation contrasts with the cis type.
Basically, the stable chair conformation exists usually when the bulky groups are present at equatorial positions within the molecule. It should be noted that there must be minimum electron cloud distortion.
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