An electroscope is a device with a metal knob, a metal stem, and freely hanging metal leaves used to detect charges. The diagram below shows a positively charged leaf electroscope.
As a positively charged glass rod is brought near the knob of the electroscope, the separation of the leaves will
remain the same
increase

Answer:

a. During each second the object travels 4.9 m

The distance, s, the object traveled each second is s = (u × 1 + 4.9) meters

b. The average speed at time t = 4s is 39.2 m/s

the average speed at t = 4 second  is 78.4 m/s

c. The instantaneous speed at time t = 3 s is 29.4 m/s

The instantaneous speed at time t = 3 s is 44.145 m/s

d. The average acceleration at time t = 1 s is 9.8 m/s² is correct

e. The average acceleration at time t = 3 s is 29.4 m/s²

The average acceleration at time t = 3 s is 9.81 m/s²

Explanation:

a. During each second the object travels 4.9 m

The distance, s, the object traveled each second is s = (u × 1 + 4.9) meters

b. The average speed at time t = 4 s is 39.2 m/s

The speed is given by the following equation;

v = u + g·t

Where;

u = The initial velocity =  m/s

g = The acceleration due to gravity

t = The time

At the third second, the speed is given as follows;

t = 3 s

v = 0 × 3 + 1/2×9.81×3² = 44.145 m/s

At the fourth second, the speed is given as follows;

t = 4 s

v = 0 × 4 + 1/2×9.8×4² = 78.4 m/s

Therefore, the average speed at t = 4 second  is 78.4 m/s

Similarly

The distance covered at t = 4 = 1/2×9.8×4² = 78.4

The time = 1 s

Average speed = Distance/Time = 78.4/1 = 78.4 m/s

c. The instantaneous speed at time t = 3 s is 29.4 m/s

The instantaneous speed is given by the following equation;

v = u + g·t

At the third second, the speed is given as follows;

t = 3 s

v = 0 × 3 + 1/2×9.81×3² = 44.145 m/s

The instantaneous speed at time t = 3 s is 44.145 m/s

d. The average acceleration at time t = 1 s is 9.8 m/s²

The acceleration of the object in free fall is constant and equal to 9.8 m/s²

e. The average acceleration at time t = 3 s is 29.4 m/s²

Neglecting air resistance, an object in free fall has a constant negative acceleration of 9.81 m/s²

Therefore, the average acceleration at time t = 3 s is 9.81 m/s²

The angular speed of a point 0.075 m from the center of the disk is approximately 33.33 rad/s.

Angular speed is a measure of how quickly an object rotates around a fixed axis. It is represented by the symbol ω (omega) and is typically measured in radians per second (rad/s). The angular speed of an object can be calculated using the formula:

ω = v / r

We can use the formula for centripetal acceleration to find the angular speed. The centripetal acceleration (a) is related to the radius (r) and angular speed (ω) by the equation:

a = r * ω^2

Given:

Radius of the rotating disk, r = 0.15 m

Centripetal acceleration at the rim, a = 5.0 m/s^2

We need to find the angular speed (ω) at a point 0.075 m from the center of the disk.

To solve for ω, we rearrange the equation:

ω^2 = a / r

Substituting the given values:

ω^2 = 5.0 m/s^2 / 0.15 m

ω^2 ≈ 33.33 rad^2/s^2

Taking the square root of both sides:

ω ≈ √(33.33 rad^2/s^2)

ω ≈ 5.77 rad/s

Therefore, the angular speed of a point 0.075 m from the center of the disk is approximately 5.77 rad/s.

The angular speed of a point 0.075 m from the center of the rotating disk is approximately 5.77 rad/s.

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The relative velocity of the athlete relative to the ground is 5.2 m/s

The given parameters;

constant velocity of the athlete, V = 5.2 m/s

let the velocity of the ground = Vg = 0

The relative velocity concept helps us to determine the velocity of a moving object relative to a stationary observer.

The athlete is the moving object in this question while the ground is stationary.

The relative velocity of the athlete relative to the ground is calculated as follows;

\(V/V_g = V - V_g = 5.2 - 0 = 5.2 \ m/s\)

Thus, the relative velocity of the athlete relative to the ground is 5.2 m/s

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Answer:

a = (Vf - Vi) / t = (10.9 - 27.7) / 2.37 = -16.8 / 2.37 = -7.09 m/s/s

negative means slowing down

Explanation:

Answer:

F = 294.3 [N]

Explanation:

To solve this problem we must use Newton's second law which tells us that force is equal to the product of mass by acceleration. It is this particular case the acceleration is due to the gravitational acceleration since the body is in free fall.

Therefore we have:

F = m*g

where:

F  = force [N]

m = mass = 30 [kg]

g = gravity acceleration = 9.81 [m/s^2]

F = 30*9.81

F = 294.3 [N]

The induced emf in the loop as a function of time is ε(t) = a * B_a * e^(-a*t) * A.

The magnetic flux through the loop as a function of time is given by Φ = B(t) * A, where B(t) is the magnetic field and A is the area of the loop.
In this case, the magnetic field is given by B(t) = B_a * e^(-a*t), where B_a is the initial magnetic field magnitude and a is a constant.
Therefore, the magnetic flux through the loop as a function of time is Φ(t) = B_a * e^(-a*t) * A.
To find the induced electromotive force (emf) in the loop as a function of time, we use Faraday's law of electromagnetic induction, which states that the emf induced in a loop is equal to the rate of change of magnetic flux through the loop. The induced emf (ε) in the loop is given by ε = -dΦ/dt, where dΦ/dt represents the derivative of magnetic flux with respect to time.
Taking the derivative of Φ(t), we get ε(t) = -d/dt (B_a * e^(-at) * A) = a * B_a * e^(-at) * A.

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The final induced electromotive force (emf) in the loop is represented by the equation -aBₐeᵃt·A. This equation combines factors such as magnetic field strength (B), loop area (A), and exponential decay (eᵃt) to determine the emf.

The induced emf in the loop can be calculated using the formula:

emf = -d(Φ)/dt,

where emf represents the induced electromotive force, Φ is the magnetic flux through the loop, and dt is the change in time.

In this case, the magnetic field B is given as B = Bₐeᵃt, where Bₐ is a constant and a represents a constant rate of change with respect to time.

The magnetic flux Φ through the loop can be determined by integrating the magnetic field over the enclosed area S:

Φ = ∫B·dA,

where dA represents an infinitesimal area element.

To calculate the induced emf, we differentiate the magnetic flux Φ with respect to time:

d(Φ)/dt = d/dt ∫B·dA.

Since the magnetic field B is constant over the enclosed area S, it can be taken out of the integral:

d(Φ)/dt = ∫d(B·dA)/dt.

Applying the differentiation inside the integral:

d(Φ)/dt = ∫(dB/dt)·dA.

As the magnetic field B = Bₐeᵃt, differentiating with respect to time yields:

dB/dt = aBₐeᵃt.

Substituting this expression into the equation for d(Φ)/dt:

d(Φ)/dt = ∫aBₐeᵃt·dA.

Since the magnetic field B is perpendicular to the plane, the integral simplifies to:

d(Φ)/dt = aBₐeᵃt·A,

where A represents the area of the loop.

Finally, we obtain the induced emf:

emf = -d(Φ)/dt = -aBₐeᵃt·A.

In conclusion, the induced emf in the loop is given by -aBₐeᵃt·A.

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The magnitude of the coulombic force of attraction between a central charge of \(-2 * 10^-^5 C\) and the surrounding numbered charges can be determined by analyzing the electric field.

To determine the magnitude of the coulombic force of attraction, we need to analyze the electric field created by the central charge and its interaction with the surrounding numbered charges. The electric field is a vector quantity that describes the influence a charge exerts on other charges in its vicinity.

The magnitude of the coulombic force of attraction can be determined using Coulomb's law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

First, calculate the electric field at the position of each numbered charge. The electric field at a given point is the force experienced by a positive test charge placed at that point. Once the electric field at each numbered charge is determined, multiply the magnitude of the electric field by the charge of the central charge and the charge of the numbered charge. This will give the magnitude of the force between the central charge and the numbered charge.

By following these steps for each numbered charge and summing up the forces, you can determine the magnitude of the coulombic force of attraction between the central charge and the surrounding numbered charges. Remember to consider the signs of the charges (+ or -) when calculating the force, as opposite charges attract each other while like charges repel.

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Answer:

C

Explanation:

That is where the most heat and light is showing on this diagram.

The sun on this HR diagram is placed at region A. The correct option is A.

The Hertzsprung-Russell (HR) diagram is a plot of stars that shows their luminosity (or brightness) versus their temperature or spectral type. The HR diagram is divided into several main parts:

Main sequence: This is the prominent diagonal band that extends from the upper left (hot, bright stars) to the lower right (cool, dim stars). The main sequence represents stars that are fusing hydrogen in their cores and is where most stars, including the Sun, spend the majority of their lives.

Giants and supergiants: These are stars that are much larger and more luminous than main-sequence stars, and are found above and to the right of the main sequence. Giants and supergiants are typically older stars that have exhausted the hydrogen fuel in their cores and are in the later stages of their evolution.

White dwarfs: These are the small, dense remnants of stars that have exhausted their nuclear fuel and have shed their outer layers. White dwarfs are found at the lower left of the HR diagram and are the final stage of evolution for stars like the Sun.

Instability strip: This is a narrow region of the HR diagram that includes some of the most variable stars, such as Cepheid variables and RR Lyrae variables. These stars pulsate in size and brightness over a regular period of time, making them useful for measuring distances to other galaxies.

By studying the position of stars on the HR diagram, astronomers can learn about their size, age, temperature, and luminosity, and use this information to develop models of stellar evolution and the history of the universe.

In this question,

The Sun is a main-sequence star, meaning it is in the phase of its life cycle where it is fusing hydrogen in its core to form helium.

On an HR diagram, the Sun falls near the center of the main sequence, which is a diagonal band that extends from the upper left (hot, bright stars) to the lower right (cool, dim stars). The temperature of the Sun is about 5,500°C, which places it in the spectral class G2V.

Therefore, The sun resides in the region of A.

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Answer:

you know the answer i answered it before on a question 0-0

Explanation:

Answer: 1960 kPa

Explanation:

The pressure exerted on a body at a certain depth in a fluid can be calculated using the equation:

Pressure = Density x Gravity x Depth

Where Density is the density of the fluid, Gravity is the acceleration due to gravity and Depth is the distance below the surface of the fluid.

In this case, the density of the fresh water is 1000 kg/m³, the depth of the body is 200m and the acceleration due to gravity is 9.8 m/s².

So the pressure exerted on the body can be calculated as:

Pressure = 1000 kg/m³ x 9.8 m/s² x 200m

Pressure = 1960000 N/m²

Pressure = 1960 kPa

Therefore, the pressure exerted on the body with a mass of 75 kg at 200m below the surface of fresh water with a density of 1000 kg/m³ is 1960 kPa.

Answer:

It would be option B.

Explanation:

Option B. is the right answer because as the mass of the canon increases the kinetic energy will increase as well, but the will decrease due to its greater mass.

If the mass of the cannonball increases, and all other initial conditions stay the same,  the velocity decreases, and the kinetic energy increases.

The kinetic energy of an object is the energy possessed by the object due to its motion.

\(K.E = \frac{1}{2} mv^2\)

where;

When the mass increases, the kinetic energy will increase.

\(v^2 = \frac{2K.E }{m}\\\\v=\sqrt{\frac{2K.E }{m}}\)

when the mass increases, the velocity of the cannonball will decrease.

Thus, we can conclude that if the mass of the cannonball increases, and all other initial conditions stay the same,  the velocity decreases, and the kinetic energy increases.

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Given that the velocity at any time t is

Also, the time interval is from t = 0 to t = 8 seconds

The position at time t = 0 s is s(0) = 1 m towards right of zero.

The initial time is t = 0 s, so the initial velocity will be

The final time is t = 8 s, so the final velocity will be

The average velocity will be

Thus, the average velocity is 14 m/s.

Part II:

The instantaneous velocity at time t =5 s will be

The instantaneous speed is the magnitude of instantaneous velocity.

Thus, the instantaneous speed will be 2 m/s.

Part III:

The particle will move towards the right when v(t) > 0

The time intervals will be

Thus, time intervals are t > 3 and t > 6 when the particle is moving towards the right.

Part IV :

The particle will move faster if the acceleration, a(t) > 0

The particle will slow down if the acceleration, a(t) < 0

So, first, we need to find the acceleration, it can be calculated as

For the particle moving faster,

For particle slowing down,

The total distance can be calculated as

Here, the negative symbol indicates it is towards the left from zero.

The third quartile is 183.72 minutes. So, the answer is 183.72 minutes.

Given: The typical college freshman spends an average of =150 minutes per day, with a standard deviation of =50 minutes, on social media and the third quartile is 0.75.

Therefore, we can determine the answer as follows:

We know that the third quartile, denoted by Q3, is the value such that 75% of the data lies below it. So, z-score corresponding to the third quartile is given by:

z = invNorm(0.75)

Where, invNorm is the inverse Normal distribution function.

By definition, the inverse Normal distribution gives the z-score given the area under the Normal distribution curve. Here, we need to find the area corresponding to the upper tail of 0.25 (since 75% of the data lies below the third quartile). This can be calculated as follows:

Area to the left of Q3 = 1 - Area to the right of Q3= 1 - 0.25 = 0.75

Therefore, the z-score corresponding to this area is given by:

z = invNorm(0.75) = 0.6745

Now, the value of the third quartile can be obtained by using the z-score formula as follows:

z = (X - μ) / σ

where, X = value of the third quartile, μ = population mean = 150 (given), σ = population standard deviation = 50 (given)

Substituting the values, we get:

0.6745 = (X - 150) / 50

Solving for X, we get: X = 150 + 0.6745 * 50X = 183.72

Therefore, the third quartile is 183.72 minutes. So, the answer is 183.72 minutes.

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The results of the calculation are as follows;

The term kinematics has to do with the study of motion without looking at the cause of motion which is force.

Now let us try to solve the problems;

v = u + at

v = final velocity

u = initial velocity

a = acceleration

t = time

v = 6.5 + (2.4 * 8)

v = 25.7 m/s

b) Given the formula

h = ut + 1/2gt^2

h = height

g = acceleration due to gravity

Thus;

h = 1/2gt^2 (because u = 0 m/s when the object is dropped from a height)

h = 0.5 * 9.8 * (3.2)^2

h = 50.2 m

c) v = u + gt

v = gt

v = 9.8 * 3.2

v = 31.4 m/s

d) v^2 = u^2 - 2gh

Now v = 0 m/s at the maximum height

Thus;

u^2 = 2gh

u = √2gh

u = √2 * 9.8 * 17

u = 18.2 m/s

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If the resistance remains constant and the voltage doubles, the power will increase by a factor of 4 (option E)

The following data were obtained from the question:

P = V² / R

Resistance is constant, we have

V₁² / P₁ = V₂² / P₂

V² / P = (2V)² / P₂

V² / P = 4V² / P₂

Cross multiply

V² × P₂ = P × 4V²

Divide both side by V²

P₂ = P × 4V² / V²

P₂ = P × 4

From the above, we can conclude that the power will increase by a factor of 4 (option E)

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A cougar with a mass of 80 kg is standing at the edge of a cliff, then the cougar's potential energy, if the cliff is 70 m high, would be 54880 Joules.

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.

As given in the problem a cougar with a mass of 80 kg is standing at the edge of a cliff, and if the cliff is 70 meters high then we have to find the potential energy,

The potential energy of the cougar = 80×9.8×70

                                                           =54880 Joules

Thus, the potential energy of the cougar would be 54880 Joules.

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(i) Impulse given to the body is 18 Ns.

(ii) Final speed of the body 10 m/s.

The result is obtained by using Impulse-Momentum Theorem.

The Impulse-Momentum Theorem states that impulse of an object equals to the change of the momentum. It can be expressed as

I = mΔv

Where

The impulse quantity is also calculated by multiplying force and time.

I = FΔt

Where

A body of mass 2 kg initially moving with a velocity of 1 m/s is acted upon by a horizontal force of 6 N for 3 second.

Find (i) Impulse given to the body (ii) Final speed of the body!

We have

Using the formula above, the impulse given to the body will be

I = FΔt

I = 6 × 3

I = 18 Ns

The final speed is

I = mΔv

18 = 2(v₂ - 1)

9 = v₂ - 1

v₂ = 9 + 1

v₂ = 10 m/s

Hence, the impulse and final speed of the body is 18 Ns and 10 m/s, respectively.

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Answer:

i) Hooke's Law works for some materials

ii) Hooke's Law only applies up to a certain force

iii) The force at which Hooke's Law stops working for springs is lower than for most materials

Explanation:

Hooke's Law of elasticity states that the deformation of an elastic material is proportional to the applied for small deformations

The law is applicable to elastic materials whose values of deformation or extension as well as the applied load or stress are expressible by a single real number

Hooke's Law is applicable when the force and the extension of the elastic material are proportional, at larger force, the elastic material is observed to expand more than as expected based on Hooke's Law

The nature of springs is such that its elastic limit is reached by a much lower force than for most materials. Therefore, Hooke's law stops working for springs at a lower force than for most materials.

Answer:

The tissues in a multicellular organism requires a circulatory system in other to deliver oxygen and food to the tissues while also removing carbon dioxide and metabolic wastes due the complexity of these activities

Explanation:

Multicellular organisms are organisms that are made of more than one cell. the more cells an organism has the more complex certain activities might be for the organism hence the tissues in a multicellular organism requires a circulatory system in other to deliver oxygen and food to the tissues while also removing carbon dioxide and metabolic wastes

Answer:

b

Explanation:

To pull the tanker 0.630 km total work to be done is  1.871 × 10⁹ Joule.

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

Resultant force acting on the tugboat = √2 × 2.10 × 10⁶ N.

To pull the tanker 0.630 km, that is, 630 m, work done = force × displacement

= √2 × 2.10 × 10⁶ N × 630 m

= 1871004543.01 Joule.

= 1.871 × 10⁹ Joule.

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Answer:

Its d 3.74 x 10-8N

Explanation:

Answer: 3.74 x 10-8 N

Explanation:

Following Greek customs of direct democracy and majority rule when passing legislation, the Mayflower Compact of 1620 served as the Massachusetts colony's constitution. The House of Burgesses had an impact on the founding fathers' decision to create a representative form of government where members gathered to discuss topics, adopt laws, and pass taxes.

To help organise and rule the populace, they all passed laws.

Because the Mayflower Compact was the first document to establish self-government in the New World, it was significant. Up until Plymouth Colony joined Massachusetts Bay Colony in 1691, it was still in operation.

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(A magnetic compass does not point to the geographic north pole. A magnetic compass points to the earth's magnetic poles, which are not the same as earth's geographic poles. Furthermore, the magnetic pole near earth's geographic north pole is actually the south magnetic pole. When it comes to magnets, opposites attract.)

Answer:

A. 50 Hz

B. 2 m/s

Explanation:

We'll begin by converting 20 ms to s. This can be obtained as follow:

1000 ms = 1 s

Therefore,

20 ms = 20 ms × 1 s / 1000 ms

20 ms = 0.02 s

Next, we shall convert the value of the wavelength (i.e 4cm) to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

4 cm = 4 cm × 1 m / 100 cm

4 cm = 0.04 m

A. Determination of the frequency.

Period (T) = 0.02 s

Frequency (f) =?

f = 1 / T

f = 1 / 0.02

f = 50 Hz

Therefore, the frequency of the wave is 50 Hz

B. Determination of the velocity.

Wavelength (λ) = 0.04 m

Frequency (f) = 50 Hz

Velocity (v) =?

v = λf

V = 0.04 × 50

v = 2 m/s

Therefore, the velocity of the wave is 2 m/s

If you increased the amount of force applied on your chosen Item, rate of increase of  its velocity with time will increase.

An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.

The definition of force in physics is: the push or pull on a mass-containing item changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

So, if you increased the amount of force applied on your chosen Item, its acceleration will be increased and rate of increase of velocity with time will increase.

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Answer:

the first on the left goes with the 3rd on the right

second left last right

3rd goes with 1st

4th goes with 5th

5th goes with 4th

and last but not least 6th goes with the second

Explanation:

The design that has the metal bar would increase the chances of an elastic collision and lead to an increase of the velocity of the car after collision.

We know that an elastic collision is one in which there is a conservation of the kinetic energy of the momentum. Recall that the colliding particles would have to constitute a closed system such that there is no loss in the momentum of the objects that are colliding.

We have two designs of the bumpers of the cars. We know that the balloon  design would have more tendency to have this car stick to the other car and create an inelastic Collison.

However, with the metal bar design, there is less tendency that the cars would stick together after collision and we would have an elastic collision. The effect of this is that velocity of the car 2 may increase after the collision.

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Explanation:

There is a force of 3N acting towards the left and 2 forces of 4N each acting towards the right.

Net force = (4N) + (4N) - (3N) = 5N towards the right.

P.S. We subtract the 3N force because the forces are in opposite directions.

Therbligs are basic physical elements of motion used in methods time measurement exercises to analyze and measure work processes. They represent the smallest unit of time and the full range of motions required to complete a job.

Therbligs were introduced by Frank B. Gilbreth, an industrial engineer, as a means to analyze and improve work processes. They are used in methods time measurement exercises to break down a task or job into its fundamental motions. Each therblig represents a specific basic physical element of motion, such as grasp, position, release, search, transport, and so on. These elements can be combined in different sequences to represent the full range of motions required to complete a job. Therbligs are used to measure the time required to perform each individual motion, and by summing up the times for all therbligs involved, the total time to complete a job can be determined. By analyzing the therbligs involved in a task, engineers can identify inefficiencies, eliminate unnecessary motions, and streamline work processes to increase productivity and reduce fatigue or strain on workers.

Therefore, therbligs serve as a standardized method for measuring and evaluating work processes, allowing for improvements in efficiency and productivity. They represent both the smallest unit of time used in methods time measurement exercises (individual motions) and the largest unit of time (the full range of motions required to complete a job).

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