approximately how much volume is picked up by the loop if the solution is 0.8 x 10-1 μg/μl and a loopful of solution contains 0.8 μg of pglo plasmid?

To calculate the pump head, we can use the Bernoulli's equation:

Substituting the given values, we get:pump_head = (40+14.7)/(62.432.2) - (5+14.7)/(62.432.2) = 85.4 ftTo calculate the brake horsepower required by the pump, we can use the following equation:BHP = (Q x pump_head x ρ x g) / (3,960 x pump_efficiency)Where Q is the flow rate in gpm, pump_head is the pump head in feet, ρ is the density of water in lb/ft³, g is the acceleration due to gravity in ft/s², and pump_efficiency is the pump efficiency as a decimal.Substituting the given values, we get:BHP = (800 x 85.4 x 62.4 x 32.2) / (3,960 x 0.7) = 204.8 hpTo calculate the suction head, we need to determine the absolute total head at the suction side of the pump. Assuming that the suction pipe is straight and horizontal, and using the given values, we can calculate the suction head as:h_suction = z + (p_suction - p_vapor)/(where p_vapor is the vapor pressure of water at the operating temperature, which can be obtained from steam tables. For water at 80°F, the vapor pressure is approximately 0.75 psi.

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A minimum set of requirements for plumbing installations in a municipality, city, county, or state is a plumbing code.

A plumbing code is a set of minimum standards and regulations that dictate the design, installation, and maintenance of plumbing systems. The code is typically enforced by local or state authorities and serves to protect public health and safety by ensuring that plumbing systems are safe, functional, and sanitary. Plumbing codes cover a wide range of requirements, including the size and type of pipes and fittings, fixture installation and location, drainage and venting, water supply, and backflow prevention. Plumbing codes are updated periodically to reflect advances in technology, changes in building materials, and new safety and environmental concerns. Compliance with the plumbing code is mandatory, and failure to meet the code requirements can result in fines, penalties, or legal action.

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The answer is A. Sensors

The number of threads in 16 inches of the rod is 176 threads

Given that:

1 threaded rod= 11 threads per inch

Therefore, to find the number of threads in 16 inches of the rod,

We would have to multiply and this is given below:

16 * 11= 176 threads

This answer is gotten because a threaded rod has 11 threads per inch and when there are 16 inches of rod, to find the number of inches, you would have to multiply the values together.

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Answer:

The answer is below

Explanation:

The mining auxiliary operations in underground mining involve various activities that are important for a successful mining operation particularly in the areas of productive operating conditions.

The activities involved in the auxiliary operations in underground mining include the following: ventilation, haulage, drainage, power supply, lighting, delivery of compressed air, water, supplies to the working sections, and communications.

Based on the information provided by these technicians, both of them are correct.

According to heating, ventilation, and air conditioning (HVAC), heat in an air-conditioning system generally flows from the hotter object to the colder object.

As the refrigerant evaporates in a small radiator-type unit (evaporator), it absorbs heat as it changes phase from liquid to gas. Also, as the heat is being absorbed by the refrigerant, the small radiator-type unit (evaporator) becomes cold.

In conclusion, we can logically deduce that both of them are correct.

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The load Py at which the aluminum beam begins to yield can be calculated using the yield strength of approximately 280 MPa (40,000 psi).

When a material reaches its yield strength, it means that it has reached the point where it starts to deform permanently under load. In this case, the yield strength of the aluminum is given as 280 MPa. To calculate the load Py at which the beam begins to yield, we need to consider the cross-sectional area of the beam.

Assuming the beam has a uniform cross-section, we can use the formula:

Py = Yield strength × Cross-sectional area

To calculate the cross-sectional area, we need to know the dimensions of the beam, such as its width and height. Once we have the cross-sectional area, we can substitute it into the formula to find the load Py.

It's important to note that this calculation assumes the load is applied uniformly across the entire cross-section of the beam. In real-world scenarios, the distribution of the load and other factors might affect the actual yield point.

the mechanical properties of different materials and how they affect structural calculations by exploring textbooks or engineering references that cover topics such as material science and structural analysis.

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This is correct. Model-level environment settings take precedence over model-process environment settings.

What is environment?
All living as well as non-living things that occur naturally, or in this case, without the use of artificial means, are included in the natural environment as well as natural world. The phrase is most frequently used in reference to Earth or certain regions of it. The interaction of all living things, the climate, the weather, and the natural resources that have an impact on human survival as well as economic activity are all included in this environment. The built environment stands in contrast to a natural environment. Humans have significantly changed the natural environment into a more streamlined human environment in built environments, such as urban settings and the conversion of agricultural land.

Therefore, if a model-level environment setting is applied to the model, it will override any model-process environment settings that may be applied to the individual processes.

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Answer:

oa

Explanation:

Answer:

safety factor

Explanation:

i got it correct on the test

To verify an adequate AC power supply to a wireless network, the following actions are typically involved:
1. Inspect the power source
2. Check the power cables
3. Verify the voltage
4. Monitor power stability
5. Test the wireless equipment
By completing these actions, you can ensure an adequate AC power supply is provided to your wireless network.

To verify an adequate AC power supply to a wireless network, there are several actions involved:

1. Check the voltage and current rating of the power supply: Make sure that the voltage and current rating of the power supply match the requirements of the wireless network. This information can usually be found in the network device's documentation.

2. Test the power supply: Use a multimeter to test the voltage and current output of the power supply. If the readings are not within the acceptable range, the power supply may need to be replaced.

3. Check the power cable and connectors: Ensure that the power cable and connectors are in good condition and securely connected. Loose or damaged connections can cause power supply issues.

4. Verify power redundancy: If the wireless network has redundant power supplies, ensure that both supplies are operational and distributing power evenly.

5. Monitor power supply performance: Continuously monitor the power supply performance to ensure that it is providing the necessary power to the wireless network. This can be done using network management software or by physically checking the power supply.

By following these actions, you can verify that your wireless network has an adequate AC power supply and prevent potential power-related issues.

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__________________________________________________________

Hello! In this question, we are trying to find the maximum value of shear flow in the web of the wing spar. Note that we are trying to find this with a section that is 1 meter away from the free end of the beam.
__________________________________________________________

Explanation:

In this problem, we know that:

This information should be kept in mind and can help us solve our problem.

__________________________________________________________

Solve:

Let us begin to solve the problem.

Since we're analyzing the moment in one section, in this case, we can note this as "section 1", we can use this formula to determine the moment in this section:

\(M_{1}=\frac{wl^2}2}\)
Whereas:

Plug in the values into the equation and solve:

\(M_{1}=\frac{15*1^2}2}=7.5\text{kN-m}\)
Now, let us find the moment of inertia of the beam in our 1st section. We'll use the formula:

\(I_{xx}=\frac{BD^3}{12} +2Ah^2\)

Whereas:

Plug in the values into the equation and solve:

\(I_{xx}=\frac{2(300)^3}{12} +2(500)(150)^2=2.7\times10^7\:\text{mm}^4\)
Now knowing our moment and inertia, we can solve our direct distress in the z direction of our flanges using the following formula:

\(\sigma_{z,U} = -\sigma_{z,L}=\frac{M_{1}}{I_{xx}}y\)
We know:

Plug the values into the equation and solve. (Note that unit conversion was done for M1):

\(\sigma_{z,U} = -\sigma_{z,L}=\frac{7.5\text{kN-m}*(\frac{1000 N}{1kN})(\frac{1000mm}{1m} )}{2.7\times10^7}(150mm)=-41.7\:\text{N/mm}^2\)
Since we now know what our direct distress is, we can find the bending moment resultant with the formula:

\(P_{z,U}=\sigma_{z,U}\times A\)

We know:

Plug in the values to our equation and solve:

\(P_{z,U}=-41.7\:\text{N/mm}^2\times 500\:mm^2=-20850\:N\)
Now knowing our bending moment resultant, we can now find our flange load of the web section. Note that our flange load is uniformly distributed. We will use the formula:

\(P_{U}=\sqrt{P_{z,U}^2+P_{y,U}^2}}\)
We know that:

Plug in the values into the equation and solve:
\(P_{U}=\sqrt{(-20850)^2+0^2}}=20850\:N\)
Please note that the answer we calculated above is our tension (T).

Let's now calculate our bending moment resultant using:

\(P_{y,L}=P_{z,L}\times\frac{\delta{y}^2}{\delta_{z}}\)

We know:

Plug in the values and solve. To make things go faster, I included the unit conversion for our denominator value:

\(P_{y,L}=-20850\:N\times\frac{100\:mm}{(1\:m\times\frac{1000\:mm}{1\:m} )}=-2085\:kN=2085\:kN\)
Please note that the above calculation would be our compression value.

Let's calculate our shear force in the web in our 1st section using a known relationship:

\(S_{y}=-W\times\delta_{z}+P_{y,L}\)
We know:

Plug in our known values and solve:

\(S_{y}=-15\times(1\:m\times\frac{1000\:mm}{1\:m} )+2085=-12915\:N\)

In order to figure out what our shear flow is (note that our shear flow is represented as q), we will use the relationship:

\(q=\frac{S_y}{I_{xx}} [\int_{0}^{s}2(150-s)ds+500\times(\frac{300}{2} )]\)

We know:

Plugging in the values, we will get:

\(q=\frac{12915}{2.7\times10^7\:mm} [\int_{0}^{s}2(150-s)ds+500\times(\frac{300}{2} )]\)

Simplify the equation:

\(q=4.78\times10^{-4} [\int_{0}^{s}(300-s)ds+75000]\)
Integrate the equation:

\(q=4.78\times10^{-4} [\int_{0}^{s}(300-s)ds+75000]\\\\q=4.78\times10^{-4} ((300s-\frac{2s^2}{2} +[0])+75000)\\\\q=4.78\times10^{-4} ((300s-s^2 )+75000)\)

We now have our equation for the shear flow. We know that the max value of shear flow will happen when s equals 150 mm, so let's plug in the value 150 mm into "s" in our "q" equation and solve:

\(q=4.78\times10^{-4} ((300(150)-150^2 )+75000)=\boxed{46.8\:N/mm}\)

__________________________________________________________

Answer:

The max value of shear flow in the web in the 1st section of the beam is:

\(q=\boxed{46.8\:N/mm}\)

__________________________________________________________

Answer:

Used to recall the direction a standard screw

(a) The temperature of the exiting mixture is 300.8 8C.

(b) The rate of entropy production is 0.767 kW/K.

(c) The rate of exergy destruction is 177.5 kW.

Air at 50 8C, 1 atm and a volumetric flow rate of 60 m3/min mixes with helium entering as a separate stream at 120 8C, 1 atm and a volumetric flow rate of 25 m3/min. A single mixed stream exits at 1 atm. Ignoring kinetic and potential energy effects, determine for the control volume.

(a) the temperature of the exiting mixture, in 8C. (b) the rate of entropy production, in kW/K. (c) the rate of exergy destruction, in kW, for T0 5 295 K.The given problem can be solved by the application of the energy and mass balance equations as well as the second law of thermodynamics.

The rate of mass flow (m) of air (ṁ_air) and helium (ṁ_he) can be calculated using the given volumetric flow rate and the density of air and helium.The mass flow rate of air (mṁ_air) = Volumetric flow rate of air (V_air) × Density of air (ρ_air) = 60 m3/min × 1.2 kg/m3= 72 kg/min

The mass flow rate of helium (mṁ_He) = Volumetric flow rate of helium (V_He) × Density of helium (ρ_He) = 25 m3/min × 0.166 kg/m3 = 4.15 kg/min.The mass flow rate of the mixture is the sum of the mass flow rates of the air and helium.

Therefore, the mass flow rate of the mixture (mṁ_mixture) = mṁ_air + mṁ_He = 72 + 4.15 = 76.15 kg/min(a) Calculation of the temperature of the exiting mixture:By applying the energy balance equation for steady-state processes, the energy input equals the energy output. That is,Q_in = Q_outor, mṁ_air Cpa T1 + mṁ_He Cp_He T2 = mṁ_mixture Cp T3

where, Cpa and Cp_He are the specific heat capacities of air and helium at constant pressure respectively.Cp is the specific heat capacity of the mixture at constant pressure.T1 and T2 are the temperatures of air and helium before mixing.T3 is the temperature of the mixture after mixing.

Substituting the given values into the above equation and solving for T3, we get;72 × 1.005 × (508 − T3) + 4.15 × 5.193 × (1208 − T3) = 76.15 × 1.128 × (T3 − 298)T3 = 573.8 K = 300.8 8C

Therefore, the temperature of the exiting mixture is 300.8 8C.

(b) Calculation of the rate of entropy production:The rate of entropy production can be calculated using the second law of thermodynamics. The entropy generation (S_gen) is given by the equation:S_gen = ṁ_mixture × s_mixture − ṁ_air × s_air − ṁ_He × s_He

where, s_air and s_He are the specific entropies of air and helium respectively.s_mixture is the specific entropy of the mixture.Taking the reference temperature (T0) to be 295 K, the rate of entropy production can be calculated as:

S_gen = ṁ_mixture × [s_mixture − s_0(T0)] − ṁ_air × [s_air − s_0(T0)] − ṁ_He × [s_He − s_0(T0)]where, s_0(T0) is the entropy at reference temperature (T0).

s_mixture = 1.128 × ln [(0.21 × P_1)/(0.21 × P_1 + 0.79 × P_2)] + 0.881 × ln [(0.79 × P_2)/(0.21 × P_1 + 0.79 × P_2)] = 1.128 × ln [(0.21 × 1)/(0.21 × 1 + 0.79 × 1)] + 0.881 × ln [(0.79 × 1)/(0.21 × 1 + 0.79 × 1)] = 0.375 kJ/kg.K

where, P_1 and P_2 are the partial pressures of air and helium respectively at the exit temperature.Taking the specific entropies of air and helium from steam tables, we get;

s_air = 72 × 1.005 × [ln T3/T0] − 72 × R_air × [ln P1/P0] = 72 × 1.005 × [ln(573.8/295)] − 72 × 0.287 × [ln 1/1] = 349.1 J/kg.ks_He = 4.15 × 5.193 × [ln T3/T0] − 4.15 × R_He × [ln P2/P0] = 4.15 × 5.193 × [ln(573.8/295)] − 4.15 × 2.076 × [ln 1/1] = 602.1 J/kg.k

Where, R_air and R_He are the specific gas constants of air and helium respectively.The rate of entropy production (S_gen) = 76.15 × [0.375 − 0.365] − 72 × [0.349 − 0.300] − 4.15 × [0.602 − 0.176] = 0.767 kW/K

Therefore, the rate of entropy production is 0.767 kW/K.

(c) Calculation of the rate of energy destruction:

The rate of energy destruction is calculated using the equation:Energy destruction rate = S_gen × (T − T0)where, T is the temperature at which the entropy is generated.Substituting the given values, the rate of energy destruction is;Energy destruction rate = 0.767 kW/K × (573.8 K − 295 K) = 177.5 kW

Therefore, the rate of energy destruction is 177.5 kW.

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If your truck has a  starter button , you must first turn the engine key to the ‘on’ position before engaging it.

An ignition switch, starter switch, or start switch is a switch in a motor vehicle's control system that activates the vehicle's primary electrical systems, including "accessories."

The ignition switch is a critical component of an automobile. It starts and stops the car's engine, as well as the electrical in-car devices. It also powers the starting motor of the automobile. The ignition switch not only turns on and off the engine, but it also powers the lights and radio.

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Full Question:

If your truck has a(n) _____, you must first turn the engine key to the 'on' position before engaging it. *

10 points

A. starter button

B. engine brake

C. clutch button

D. cruise control

True. It is illegal to drive a vehicle when the tire tread is less than 1/16 inch deep.

The tire tread depth plays a crucial role in maintaining traction and stability on the road. When the tread depth is less than 1/16 inch, it can compromise the grip of tire on the road, especially during wet or snowy conditions, and increase the risk of accidents. Most jurisdictions have regulations in place to enforce a minimum tire tread depth for the safety of all road users. Therefore, it is important to periodically check and replace your tires when the tread depth reaches the legal minimum to ensure safe driving.

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To calculate the car's gas mileage in mpg, we need to first convert the 60 liters of gasoline to gallons. One gallon is approximately equal to 3.785 liters, so 60 liters is equal to 15.85 gallons (60 ÷ 3.785 = 15.85).

Next, we can use the formula for gas mileage: mileage = distance traveled ÷ amount of gasoline used. In this case, the distance traveled is 560km, and the amount of gasoline used is 15.85 gallons.
So, gas mileage = 560km ÷ 15.85 gallons = 35.3km/gallon

To convert this to mpg, we need to use a conversion factor of 0.6214 (1 kilometer is approximately equal to 0.6214 miles).
So, gas mileage = 35.3km/gallon × 0.6214 = 21.93mpg, which is closest to 22mpg.
Therefore, the answer is o 22mpg.

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Answer:

-6sin(6x+2)cos²(3x+1)dx.

Explanation:

\(dy=4*cos^3(3x+1)*3*(-sin(3x+1))dx=-6sin(6x+2)cos^2(3x+1)dx.\)

The given statement of the stack is true.

What is stack?

A stack is an abstract data type which serves as a collection of elements, with two major operations: Push, which adds an element to the collection, as well as Pop, which removes the most recently added piece that has not yet been removed. A peek operation can also return the value of the most recently added element without altering the stack. The term "stack" refers to a collection of physical goods placed on top of one another, such as a stack of dishes.

Dear student, As we all know, in stack, we use top, which is a stack index.

In push operation top++ (post increment)

In pop operation --top ( pre decrement)

So, by referring to the aforementioned, we can now answer your question.

We want to get to the bottom element, which we can do by utilising the index value.

So, time complexity will be O(1).

Hence option is true.

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Answer:

Coiled tubing is often used to carry out operations similar to wire lining.

Answer:

building?

Explanation:

Answer:

a rock is made up of two or more minerals but a mineral is a natural substance with chemical and physical properties

The smallest acceptable size of the next state register in bits depends on the number of distinct states that need to be represented. It can be determined by finding the minimum number of bits required to uniquely represent all possible states.


To determine the smallest acceptable size of the next state register, we need to consider the number of distinct states the system can have. If the system has N distinct states, the next state register should have enough bits to represent all these states uniquely.
The number of bits required to represent N states can be calculated using the formula: log2(N). This formula represents the base-2 logarithm of N, which gives the minimum number of bits required. It is important to round up the result to the nearest whole number to ensure that all states can be represented.
For example, if a system has 8 distinct states, we would calculate log2(8) = 3, indicating that at least 3 bits are required to represent all the states uniquely. Therefore, the smallest acceptable size of the next state register in this case would be 3 bits.
In general, the size of the next state register should be chosen to accommodate the maximum number of distinct states the system can have, ensuring that all states can be represented without ambiguity.

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Answer:

a) The current in the heating element when it is connected to 120 V is 9.229 amperes, b) The power received by the heatng element connected to 120 V is 1107.522 watts.

Explanation:

a) The resistance as a function of voltage and power can be obtained from this expression, derived from the Ohm's Law:

\(\dot W = \frac{V^{2}}{R}\)

Where:

\(V\) - Source voltage, measured in volts.

\(R\) - Heating element resistance, measured in ohms.

Now, resistance is clear and determined afterwards:

\(R = \frac{V^{2}}{\dot W}\)

If \(V = 240\,V\) and \(\dot W = 4,430\,W\), then:

\(R = \frac{(240\,V)^{2}}{4.430\,W}\)

\(R = 13.002\,\Omega\)

Now, let consider that heating element is conected to a 120-V source. The power generated by this element is:

\(\dot W = \frac{V^{2}}{R}\)

\(\dot W = \frac{(120\,V)^{2}}{13.002\,\Omega}\)

\(\dot W = 1107.522\,W\)

Besides, power as a function of current and resistance is given by this:

\(\dot W = i^{2}\cdot R\)

Where \(i\) is the current required by the heating element, measured in amperes, and which is cleared herein:

\(i = \sqrt{\frac{\dot W}{R} }\)

If \(\dot W = 1107.522\,W\) and \(R = 13.002\,\Omega\), then:

\(i = \sqrt{\frac{1107.522\,W}{13.002\,\Omega} }\)

\(i \approx 9.229\,A\)

The current in the heating element when it is connected to 120 V is 9.229 amperes.

b) The power received by the heatng element connected to 120 V is 1107.522 watts. (see point a) for further details)

False. The claim regarding the cofactor matrix and eigenvalues is not directly related to Markov chains and determinants.

The assertion itself is erroneous as well. The cofactor matrix is not always the same as the sum of the eigenvalue and the identity matrix when the eigenvalue of a matrix is 0. The matrix of determinants of the (n-1) x (n-1) matrices produced by deleting one row and one column from A, multiplied by (-1)(i+j), where I and j are the row and column indices of the element being removed, is known as the cofactor matrix for a matrix A. The answers to the equation det(A - I) = 0, where is an eigenvalue and I is the identity matrix, are the eigenvalues of a matrix A. These ideas, which are closely related to matrix algebra and linear algebra, are thoroughly researched in mathematics and fields that are related to it.

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False. Markov chain and determinant are not directly related to the statement that if 0 is an eigenvalue, then the cofactor matrix is equal to the product of eigenvalues.

In linear algebra, if 0 is an eigenvalue of a matrix, then the determinant of that matrix is 0. However, the cofactor matrix is not necessarily equal to the product of the eigenvalues. The cofactor matrix is a matrix that is used to calculate the inverse of a matrix, and it is related to the adjugate matrix, which is the transpose of the matrix of cofactors.

The product of the eigenvalues is equal to the determinant of the matrix, but this does not necessarily mean that the cofactor matrix is equal to the product of the eigenvalues.

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Answer:

Explanation:

Find the temperature at exit of compressor

\(T_2=300 \times 8^{\frac{1.667-1}{1.667} }\\=689.3k\)

Find the work done by the compressor

\(\frac{W}{m} =c_p(T_2-T_1)\\\\=5.19(689.3-300)\\=2020.4kJ/kg\)

Find the actual workdone by the compressor

\(\frac{W}{m} =n_c(\frac{W}{m} )\\\\=1 \times 2020.4kJ/kg\)

Find the temperature at exit of the turbine

\(T_4=\frac{1800}{8^{\frac{1.667-1}{1.667} }} \\\\=787.3k\)

Find the actual workdone by the turbine

\(1 \times 5.19 (1800-783.3)\\=5276.6kJ/kg\)

Find the temperature of the regeneration

\(\epsilon = \frac{T_5-T_2}{T_4-T_2} \\\\0.75=\frac{T_5-689.3}{783.3-689.3} \\\\T_5=759.8k\)

Find the heat supplied

\(Q_i_n=c_p(T_3-T_5)\\\\=5.19(1800-759.8)\\\\=5388.2kJ/kg\)

Find the thermal efficiency

\(n_t_h=\frac{W_t-W_c}{Q_i_n} \\\\=\frac{5276.6-2020.4}{5388.2} \\\\n_t_h=60.4\)

60.4%

Find the mass flow rate

\(m=\frac{W_net}{P} \\\\\frac{60 \times 10^3}{5276.6-2020.4} \\\\=18.42\)

Find the actual workdone by the compressor

\(\frac{W_c}{m} =\frac{(\frac{W}{m} )}{n_c} \\\\=\frac{2020.4}{0.8} \\\\=2525.5kg\)

Find the actual workdone by the turbine

\(\frac{W_t}{m} =n_t(\frac{W}{m} )\\\\=0.8 \times5.19(1800-783.3)\\\\=4221.2kJ/kg\)

Find the temperature of the compressor exit

\(\frac{W_t}{m} =c_p(T_2_a-T_1)\\2525.5=5.18(T_2_a-300)\\T_2_a=787.5k\)

Find the temperature at the turbine exit

\(4221.2=5.18(1800-T_4_a)\\\\T_4_a=985k\)

Find the temperature of regeneration

\(\epsilon =\frac{T_5-T_2}{T_4-T_2}\\\\0.75=\frac{T_5-787.5}{985-787.5}\\\\T_5=935.5k\)

Answer:

a) 60.4%;  18.42 kg/s

b) 37.8% ;    35.4 kg/s

Explanation:

a) at an isentropic efficiency of 100%.

Let's first find the exit temperature of the compressor T2, using the formula:

\((r_p) ^k^-^1^/^k = \frac{T_2}{T_1}\)

Solving for T2, we have:

\( T_2 = 300 * (8)^1^.^6^6^7^-^1^/^1^.^6^6^7 = 689.3 K \)

Let's now find the work dine by the compressor.

\( \frac{W_c}{m} = c_p(T_2 - T_1) \)

\( \frac{W_c}{m} = 5.19(689.3 - 300) = 2020.4 KJ/kg\)

The actual work done by the compressor =

\( W_c = 1 * 2020.4 = 2020.4 KJ/kg \)

Let's find the temperature at the exit of the turbine, T4

\((r_p) ^k^-^1^/^k = \frac{T_3}{T_4}\)

Solving for T4, we have:

\(T_4 = \frac{1800}{(8)^1^.^6^6^7^-^1^/^1^.^6^6^7} = 783.3 K\)

Let's find the work done by the turbine.

\(\frac{W_t}{m} = c_p(T_3 - T_4)\)

\(\frac{W_t}{m} = 5.19(1800 - 783.3) = 5276.6 KJ/kg\)

The actual work done by the turbine:

= 1 * 5276.6 = 5276.6 KJ/kg

Let's find the regeneration temperature, using the formula:

\( e = \frac{T_r - T_2}{T_4 - T_2}\)

Substituting figures, we have:

\( 0.75 = \frac{T_r - 689.3}{783.3 - 689.3} \)

\( T_r = [0.75(783.3 - 689.3)] + 689.3 = 759.8 \)

Let's calculate the heat supplied.

\(Q = c_p(T_3 - T_r)\)

\( Q = 5.19(1800 - 759.8) \)

Q = 5388.2 kJ/kg

For thermal efficiency, we have:

\( n = \frac{W_t - W_c}{Q} \)

Substituting figures, we have:

\( n = \frac{5276.6 - 2020.4}{5388.2} = 0.604 \)

0.604 * 100 = 60.4%

For mass flow rate:

Let's use the formula:

\( m = \frac{W_n_e_t}{P} \)

Wnet = 60MW = 60*1000

\( m = \frac{60*10^3}{5276.6 - 2020.4} = 18.42 \)

b) at an isentropic efficiency of 80%.

Let's now find the work done by the compressor.

\( \frac{W_c}{m} = c_p(T_2 - T_1) \)

\( \frac{W_c}{m} = 5.19(689.3 - 300) = 2020.4 KJ/kg\)

The actual work done by the compressor =

\( W_c = \frac{2020.4}{0.8}= 2525.5 KJ/kg \)

Let's find the work done by the turbine.

\( \frac{W_t}{m} = c_p(T_3 - T_4) \)

\( \frac{W_t}{m} = 5.19(1800 - 787.5) = 5276.6 KJ/kg\)

The actual work done by the turbine:

= 0.8 * 5276.6 = 4221.2 KJ/kg

Let's find the exit temperature of the compressor T2, using the formula:

\(\frac{W_c}{m} = c_p(T_2 - T_1) \)

\( 2525.5 = 5.19(T_2 - 300) \)

Solving for T2, we have:

\( T_2 = \frac{2525.5 + 300}{5.19} = 787.5 \)

Let's find the temperature at the exit of the turbine, T4

\( \frac{W_t}{m} = c_p(T_3 - T_4) \)

\( 4221.2 = 5.19(1800 - T_4) \)

Solving for T4 we have:

\( T_4 = 958 K\)

Let's find the regeneration temperature, using the formula:

\( e = \frac{T_r - T_2}{T_4 - T_2}\)

Substituting figures, we have:

\( 0.75 = \frac{T_r - 787.5}{985 - 787.5} \)

\( T_r = [0.75(958 - 787.5)] + 787.5 = 935.5 K \)

Let's calculate the heat supplied.

\(Q = c_p(T_3 - T_r)\)

\( Q = 5.19(1800 - 935.5) \)

Q =  4486.2 kJ/kg

For thermal efficiency, we have:

\( n = \frac{W_t - W_c}{Q} \)

Substituting figures, we have:

\( n = \frac{4221.2 - 2525.2}{4486.2} = 0.378 \)

0.378 * 100 = 37.8%

For mass flow rate:

Let's use the formula:

\( m = \frac{W_n_e_t}{P} \)

Wnet = 60MW = 60*1000

\( m = \frac{60*10^3}{4221.2 - 2525.2} = 35.4 kg/s \)