at highway speeds, a particular automobile is capable of an acceleration of 1.6 m/s2. at this rate, how long does it take to accelerate from 80 km/h to 110 km/h?

Answer:

6.71 m/s magnitude

Explanation:

d = 1/2 a t^2

1.48 = 1/2 (9.81)(t^2 )    t = .549 s

Vertical velocity is given by

vf = at

      = 9.81 ( .549) = 5.39 m/s   VERTICAL velocity

Crazy cat went  horizontally 2.2 m in .549 s  =  4 m/s   horizontal velocity

Total velocity magnitude =  sqrt (4^2 + 5.39^2) = 6.71 m/s

The statement that is true if matter undergoes both chemical and nuclear reaction is that atoms are rearranged (option A).

A chemical reaction is a process, typically involving the breaking or making of interatomic bonds, in which one or more atoms or substances are changed into others.

Also, a nuclear reaction is a process such as the fission of an atomic nucleus, or the fusion of one or more atomic nuclei and/or subatomic particles in which the number of protons and/or neutrons in a nucleus changes.

In a nuclear reaction, the products may contain a different element or a different isotope of the same element.

This suggests that are atoms are rearranged in both chemical and nuclear reactions.

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The mass of all the hydrogen in this star is approximately 4.0661 times the mass of the Sun.

The mass of all the hydrogen in this star can be calculated by multiplying the mass of the star (5.9M sun) by the fraction of the star's mass accounted for by hydrogen gas (68.9%).

The mass of hydrogen in a star is significant as it determines the star's energy production through nuclear fusion. Hydrogen fusion reactions occur in the star's core, releasing immense amounts of energy in the form of light and heat. This energy sustains the star's luminosity and enables it to radiate heat and light into space. Additionally, hydrogen is the primary fuel source for stars, and its abundance directly influences the star's lifespan, size, and overall evolution.

To calculate the mass of hydrogen, we can use the following formula:

Mass of hydrogen = Mass of the star * Fraction of mass accounted for by hydrogen gas

Substituting the given values:

Mass of hydrogen = 5.9M sun * 0.689 = 4.0661M sun

Therefore, the mass of all the hydrogen in this star is approximately 4.0661 times the mass of the Sun.

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To find the distance from the base of the hill where Josh ends up, we need to analyze the motion of the sled on the hill and the horizontal patch of snow separately.

Motion on the hill:

The sled slides down the frictionless hill, and we can analyze this motion using principles of conservation of energy.

The change in gravitational potential energy is equal to the change in kinetic energy:

mgh = (1/2)\(mv^2\)

where m is the mass of the sled, g is the acceleration due to gravity, h is the height of the hill, and v is the velocity of the sled at the bottom.

The mass (m) cancels out, and we can solve for v:

v = √(2gh)

Given:

Height of the hill (h) = 3.5 m

Acceleration due to gravity (g) ≈ 9.8 \(m/s^2\)

Substituting the values:

v = √(2 * 9.8\(m/s^2\) * 3.5 m)

Calculating the value:

v ≈ 10.97 m/s

Motion on the horizontal patch of snow:

The sled slides across the horizontal patch of snow with a coefficient of kinetic friction (μ) of 0.6. The friction force (f_friction) can be calculated using:

f_friction = μ * N

where N is the normal force acting on the sled. The normal force is equal to the sled's weight (mg).

The friction force causes a deceleration (a) in the sled's motion. We can calculate this using Newton's second law:

f_friction = ma

Substituting the expression for the friction force:

μ * N = ma

Since N = mg:

μmg = ma

The mass (m) cancels out, and we can solve for a:

a = μg

Given:

Coefficient of kinetic friction (μ) = 0.6

Acceleration due to gravity (g) ≈ 9.8 \(m/s^2\)

Substituting the values:

a = 0.6 * 9.8 \(m/s^2\)

Calculating the value:

a ≈ 5.88 \(m/s^2\)

Now, we can use the kinematic equation to find the distance (d) covered by the sled on the horizontal patch of snow:

d = (\(v^2\)) / (2a)

Substituting the values:

d = (10.97 \(m/s)^2\) / (2 * 5.88 m/s^2)

Calculating the value:

d ≈ 10.34 m

Therefore, Josh ends up approximately 10.34 meters from the base of the hill on the horizontal patch of snow.

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Light is radiant energy in the form of a wave of electromagnetic energy.

Light is a form of electromagnetic radiation that is visible to the human eye. It is made up of a stream of energy particles, called photons, that travel in a wave-like pattern. It has various properties, including intensity, color, and direction, which can be used to explain its behavior. It can be described as having both a particle-like nature and a wave-like nature. The particle-like nature of light is exhibited in the way it travels in packets of energy, known as photons. The wave-like nature of light is demonstrated by the way it can be bent, diffracted, and refracted.
The intensity of light is determined by the amount of energy that a photon has. The color of light is determined by the wavelength of the light, with different colors having different wavelengths. Direction is also an important property of light, as it determines how light will be bent when it passes through an obstacle or is reflected off of a surface.
Light plays a critical role in the lives of humans and other organisms. It is used in vision, to help organisms understand the world around them. Light also has numerous applications in science and technology, such as in communications, photography, and solar energy.
In conclusion, light is a form of electromagnetic radiation composed of photons that travel in a wave-like pattern. It has various properties, including intensity, color, and direction, that are used to explain its behavior. Light is important for vision and has various uses in science and technology.

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Answer:

\(\huge\boxed{\sf I = 50,000\ Ns}\)

Explanation:

Force = F = 100,000 N

Time = t = 0.5 s

Impulse = I = ?

I = F × t

I = 100,000 × 0.5

I = 50,000 Ns

\(\rule[225]{225}{2}\)

Answer:

Answer is: 162 g of beryllium.

Chemical reaction: Be + 2H₂O → Be(OH)₂ + H₂.

m(H₂) = 36,0 g.

m(Be) = ?

n(H₂) = m(H₂) ÷ M(H₂)

n(H₂) = 36,0 g ÷ 2 g/mol = 18 mol.

from reaction: n(Be) : n(H₂) = 1 : 1.

n(Be) = n(H₂) = 18 mol.

m(Be) = n(Be) · M(Be).

n(Be) = 18 mol · 9 g/mol = 162 g.

Answer:

Answer is: 162 g of beryllium.

Chemical reaction: Be + 2H₂O → Be(OH)₂ + H₂.

m(H₂) = 36,0 g.

m(Be) = ?

n(H₂) = m(H₂) ÷ M(H₂)

n(H₂) = 36,0 g ÷ 2 g/mol = 18 mol.

from reaction: n(Be) : n(H₂) = 1 : 1.

n(Be) = n(H₂) = 18 mol.

m(Be) = n(Be) · M(Be).

n(Be) = 18 mol · 9 g/mol = 162 g.

Answer:

decreases 1/4 of the original value

If the distance between two charged particles is doubled, the force between them changes by a factor of 1/4.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Force between two charge particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

If the distance between two charged particles is doubled, the force between them changes by a factor of 1/4.

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As n is not an integer, so there will be no constructive interference between the speakers, if speaker A is moved by minimum distance.

Interference is a phenomenon in which two waves combine by adding  displacement together at every single point in space and time and to form a resultant wave of greater, lower, or same amplitude.

Wavelength of a 500 Hz sound wave is the speed of sound (about 343 m/s) divided by the frequency of the sound, which is 343/500 m = 0.686 m. Therefore, minimum distance you can move speaker A to achieve constructive interference along x-axis is 0.686/2 m = 0.343 m.

Given, distance between the speakers is 6m. Constructive interference will occur when path difference between two waves is equal to integer multiple of the wavelength. To achieve constructive interference, distance between the speakers + the distance moved by speaker A should be equal to n*wavelength where n is integer.

So, 6 + 0.343 = n* 0.686

n = (6+0.343)/0.686 = 8.8

As n is not an integer, so there will be no constructive interference between the speakers, if speaker A is moved by minimum distance.

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Answer:

Newton passed sunlight through a glass prism to separate the colors into a rainbow spectrum. He then passed sunlight through a second glass prism and combined the two rainbows. The combination produced white light. His simple experiment proved conclusively that white light is a mixture of colors.

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The period of the pendulum on the surface of Mars, where g = 3.71m/s², would be the same as the period on Earth, 1.70s.  The pendulum on the surface of Mars has a period of roughly 3.31 seconds, according to our calculation of this expression.

A basic pendulum's period is determined by the equation T = 2(L/g), where T is the period, L is the pendulum's length, and g is the acceleration brought on by gravity.

L = (T/(2))2g can be solved for on Earth with a period of 1.70s by rearranging the equation.

Using the same equation and the Mars surface gravity, g = 3.71m/s2, we can now get the period on Mars' surface: T\(_{mars}\) = 2(L/g\(_{mars}\)).

The equation T\(_{mars}\) = 2(((T/(2))2g)/(g\(_{mars}\))) is obtained by substituting the expression for L and the surface gravity of Mars.

T\(_{mars}\) = T(g/g_Mars), to simplify the formula.

T\(_{mars}\) = 1.70s(9.81m/s2 / 3.71m/s) is the result of plugging in the data. The pendulum on the surface of Mars has a period of roughly 3.31 seconds, according to our calculation of this expression.

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If tangential speed is 29.7 km/s, the orbital radius of Earth is approximately 1.49 x 10¹¹ meters.

The motion of Earth around the Sun can be described as circular motion, where the gravitational force of the Sun acts as the centripetal force. In this scenario, we are given the tangential speed of Earth and the centripetal acceleration acting on Earth, and we need to determine the orbital radius of Earth.

The formula for centripetal acceleration is:

a = v²/r

Where a is the centripetal acceleration, v is the tangential velocity, and r is the orbital radius.

We are given that the tangential speed of Earth is 29.7 km/s, which is equivalent to 29,700 m/s. We are also given that the centripetal acceleration acting on Earth is 5.9 x 10⁻³ m/s².

Plugging in the values, we get:

5.9 x 10⁻³ m/s² = (29,700 m/s)² / r

Solving for r, we get:

r = (29,700 m/s)² / (5.9 x 10⁻³ m/s²)

r = 1.49 x 10¹¹ meters

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Suppose a particle is undergoing circular motion in the xy plane, with the center of the circle at the origin.

The particle is moving at a constant speed, and is traveling counterclockwise around the circle. When the particle is moving to the left, the direction of the acceleration vector is towards Right (in the positive x-direction).

When a particle moves in a circular path, its velocity changes with time as it moves from one point to another. Because of this velocity change, the particle experiences acceleration. The direction of the acceleration vector points towards the center of the circle.

It is always perpendicular to the velocity vector of the particle at a given instant. The magnitude of the acceleration vector is given by the formula a = v²/r, where v is the speed of the particle and r is the radius of the circle. So, when the particle is moving to the left, its velocity vector will be directed towards the left.

The acceleration vector will be directed towards the center of the circle, which is towards the right. Therefore, the direction of the acceleration vector is towards Right (in the positive x-direction).

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The calculated spring constant is approximately (9.0 s^2 / 4π^2) kg.

The period of vibration of an object attached to a spring is related to the mass of the object and the spring constant. The formula to calculate the period (T) of an oscillating mass-spring system is:

T = 2π√(m/k)

Where:

T = period of vibration

m = mass of the object

k = spring constant

In this case, the period (T) is given as 3.0 seconds, and the mass (m) is 1.0 kg. We can rearrange the formula to solve for the spring constant (k):

T = 2π√(m/k)

(3.0 s) = 2π√(1.0 kg/k)

Now, we can isolate k:

(3.0 s) / (2π) = √(1.0 kg/k)

(3.0 s) / (2π) = √(k/1.0 kg)

Square both sides:

(3.0 s / 2π)^2 = k / 1.0 kg

Simplifying:

(9.0 s^2 / 4π^2) = k / 1.0 kg

Multiplying both sides by 1.0 kg:

k = (9.0 s^2 / 4π^2) kg

Therefore, the calculated spring constant is approximately (9.0 s^2 / 4π^2) kg.

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Answer:

(1) body composition, (2) flexibility, (3) muscular strength, (4) muscular endurance, and (5) cardiorespiratory endurance. 

Here is a screenshot of the answer:

(The second sentence is incorrect because the triangle should be a right triangle, not an isosceles one. The fifth sentence is incorrect because we use M cos g to calculate the horizontal component.)

Answer:

You may be saving someone from a rock slide, where the rocks will fall at any time, before they fall they have potential energy.

Explanation:

It is important to note that both nitric acid and hydrochloric acid are strong acids that can dissolve many metals.

However, there are some metals that are resistant to these acids and do not dissolve. One of these metals is chromium (Cr). Chromium is a hard, shiny metal that is commonly used in the production of stainless steel and other alloys. It is resistant to many corrosive substances, including nitric acid and hydrochloric acid. Therefore, if you were to place a piece of chromium metal in either of these acids, it would not dissolve.

Finally, cadmium (Cd) and zinc (Zn) are two metals that are generally considered to be more reactive than chromium and potassium. However, they are still somewhat resistant to nitric acid and hydrochloric acid. While these acids can dissolve cadmium and zinc, it may take longer for the metals to dissolve compared to other metals. Therefore, if you were to place a piece of cadmium or zinc metal in nitric acid or hydrochloric acid, it may eventually dissolve, but it would take more time than it would for some other metals.

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(a) The spacing Y of the maxima of the screen for light is  5 x 10^-7 m. (b) Yes, we would expect to observe the interference of light. (c) The slits should be placed a distance of 500 nm apart to observe the maxima separated by 1 mm.

(a) The spacing Y of the maxima on the screen can be calculated using the formula for the interference of light from two slits:

=> Y

= L x λ / d

here L is distance from the slits to the screen,

λ is wavelength of the light,

d is distance between the slits.

Putting the values, we have:

=> Y

= 1 m x 500 nm / 1 cm

= 500 nm/cm

= 5 x 10^-7 m

(b) Yes, we would expect to observe the interference of light on the screen for this situation. This is because when light passes through two narrow slits, it creates an interference pattern on the screen that is a result of the constructive and destructive interference of the light waves. This pattern is characterized by bright and dark bands, with the bright bands representing areas of constructive interference and the dark bands representing areas of destructive interference.

(c) To calculate the distance the slits should be placed to observe the maxima separated by 1 mm, we need to rearrange the formula for Y and solve for d:

=> d

= L x λ / Y

= 1 m x 500 nm / 1 mm

= 500 x 10^-9 m

So, the slits should be placed a distance of 500 nm apart to observe the maxima separated by 1 mm.

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Answer: 1. 12 MPH 2. 36m 3. 8 Hz

Explanation:

Answer:

1. 12 MPH 2. 36m 3. 8 Hz

Explanation:

For #1, I multiplied 6 by 2, For #2 I multiplied 6 by 6 and for #3 it's 8 x 2

Light will reflect at the same angle off a smooth surface as when it first touches it. The direction of reflected light beams for a flat surface is the same. Specular reflection is what is happening here.

When light reflects off of a surface, it happens. Light will reflect at the same angle it was incident upon if the surface is glossy and smooth.

A smooth polished surface is what is referred to as a reflection when a light ray strikes it and bounces back. Surface reflection occurs when a light beam hits it and then leaves it.

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Answer: The part of color that's reflected is the red that bounces off the paper.

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Answer:

It creates bad air so that’s like air pollution I guess

Explanation:

Answer:

2.5 seconds.

Explanation:

Time equals speed divided by acceleration. gravitational acceleration is equal to 9.8 \(\frac{m}{s^{2} }\). You know that the speed is equal to 24.5 m/s, so plug those values into the equation.

24.5 / 9.8 = 2.5 seconds.

Hope this helps!

Answer:  2.5 s

Time=speed/acceleration

Gravitational Acceleration=9.8 m/s^2

Speed=24.5 m/s

Time=24.5/9.8=2.5 s

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and sorry it took so long i was trying to catch up with my missing assignments  

Answer:

\(\boxed {\boxed {\sf 3 \ meters}}\)

Explanation:

Work is the product of force and distance.

\(W=F*d\)

We know the force to lift the rock was 50 Newtons. The work was 150 Joules.

\(W= 150 \ N*m \\F= 50 \ N\)

Substitute the values into the formula.

\(150 \ N*m= 50 \ N * d\)

We want to solve for distance, so we must isolate the variable. Divide both sides of the equation by 50 Newtons.

\(\frac{150 \ N*m}{50 \ N }=\frac{50 \ N * d}{50 \ N }\)

The Newtons will cancel out.

\(\frac{150 \ m }{50} =d \\3 \ m =d\)

The rock was lifted 3 meters.

To calculate the electric field of a point charge, we can use Gauss's Law, which is one of Maxwell's equations.

Specifically, we can use the integral form of Gauss's Law, which states that the electric flux through a closed surface is proportional to the charge enclosed within the surface. By assuming symmetry of the charge distribution, we can choose a Gaussian surface that is also symmetric, such as a sphere or a cylinder. This allows us to simplify the integral and solve for the electric field at any point outside the charge distribution. So, in summary, we can use Gauss's Law, along with a symmetry argument, to calculate the electric field of a point charge.

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Answer:d

Explanation:

I took the quiz and I got that question right :)

Answer:

Cold Front. A side view of a cold front (A, top) and how it is represented on a weather map (B, bottom).

Warm Front. ...

Stationary Front. ...

Occluded Front.

Answer:

Front 3 is an occluded front. A cold air mass moves toward warmer air. The colder, heavier air pushes the warm air upward until it’s wedged between two cold air masses. Clouds can form from the lifting of the warm air.

Explanation:PLATO

Answer:

The sharp ended nail was very easy to panitrate through the wall

Explanation:

This is due to pressure