When limestone (which is principally CaCO3)


is heated, carbon dioxide and quicklime


(Cao) are produced by the reaction


CaCO3(s) 4CaO(s) + CO2(g).


If 12. 5 g of CO2 was produced from the ther-


mal decomposition of 40. 79 g of CaCO3, what


is the percentage yield of the reaction?


Answer in units of %.

Answers

Answer 1

To calculate the percentage yield of the reaction, we need to compare the actual yield (the amount of CO2 produced in the given experiment) to the theoretical yield (the amount of CO2 that should be produced according to stoichiometry).

Given:

Mass of CaCO3 = 40.79 g

Mass of CO2 produced = 12.5 g

1. Determine the moles of CaCO3:

Moles of CaCO3 = Mass / Molar mass

Molar mass of CaCO3 = 40.08 g/mol (atomic mass of calcium) + 12.01 g/mol (atomic mass of carbon) + (3 * 16.00 g/mol) (atomic mass of three oxygen atoms)

Molar mass of CaCO3 = 100.09 g/mol

Moles of CaCO3 = 40.79 g / 100.09 g/mol

2. Calculate the moles of CO2 produced:

From the balanced equation, we can see that the stoichiometric ratio between CaCO3 and CO2 is 1:1.

Therefore, the moles of CO2 produced will be the same as the moles of CaCO3.

Moles of CO2 produced = Moles of CaCO3

3. Calculate the theoretical yield of CO2:

Theoretical yield = Moles of CO2 produced × Molar mass of CO2

Molar mass of CO2 = 12.01 g/mol (atomic mass of carbon) + (2 * 16.00 g/mol) (atomic mass of two oxygen atoms)

Molar mass of CO2 = 44.01 g/mol

Theoretical yield = Moles of CO2 produced × 44.01 g/mol

4. Calculate the percentage yield:

Percentage yield = (Actual yield / Theoretical yield) × 100

Percentage yield = (12.5 g / (Moles of CO2 produced × 44.01 g/mol)) × 100

             = (12.5 g / (Moles of CaCO3 × 44.01 g/mol)) × 100

             = (12.5 g / (40.79 g / 100.09 g/mol × 44.01 g/mol)) × 100

Now, we can calculate the value of the expression and find the percentage yield:

Percentage yield = (12.5 g / (40.79 g / 100.09 g/mol × 44.01 g/mol)) × 100

Calculating the expression:

Percentage yield = 80.2%

Therefore, the percentage yield of the reaction is approximately 80.2%.

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Related Questions

a 250 gram sample of water at the boiling point had 35.0 kj of heat added. how many grams of water were vaporized? heat of vaporization for water is 40.6 kj/mole.

Answers

The required mass of water vaporized is 15.5 grams, from a 250 gram sample of water at the boiling point had 35.0 kj

Given: Mass of water (m) = 250 gHeat added (q) = 35.0 kJHeat of vaporization (ΔHvap) = 40.6 kJ/mole

To find:Mass of water vaporized (x) Formula:q = ΔHvap × nx = (q / ΔHvap) × nMass = moles × molar mass

We know that molar mass of water (H2O) = 18 g/molMoles of water vaporized (n) = (35.0 kJ / 40.6 kJ/mol) = 0.861 mol

Therefore,Mass of water vaporized (x) = 0.861 mol × 18 g/mol= 15.5  

Detailed Solution: According to the given statement,250g of water was taken at its boiling point and 35.0 kJ of heat was added to it, we need to find how many grams of water were vaporized. To solve this question, first, we need to know the heat of vaporization for water, which is 40.6 kJ/mole. It means to vaporize 1 mole of water, 40.6 kJ of heat is required.

Mass of water (m) = 250 g Heat added (q) = 35.0 kJHeat of vaporization (ΔHvap) = 40.6 kJ/molen = q / ΔHvapn = (35.0 kJ / 40.6 kJ/mol) = 0.861 molMoles of water vaporized (n) = 0.861 mol

Therefore, Mass of water vaporized (x) = 0.861 mol × 18 g/mol= 15.5 g Hence, the required mass of water vaporized is 15.5 grams.

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Please select the word from the list that best fits the definition

Tracks the location, movement, and amount of precipitation in storms
Please select the word from the list that best fits the definition
A. radar
B. satellite

Answers

Answer:

satellite

Explanation:

found it on the internet

The correct answer is Radar

If the Earth is at a perpendicular angle or right angle to the sun we will be experiencing...??
plz hurry!!

Answers

Answer:

angle

Explanation:

let us see the sun moves an a angle

If 7.0 mol sample of a gas has a volume of 12.2 L, what would the volume be if the amount of gas was increased to 16.8 mol

Answers

Answer:

\(V_{2} = 29.28\,L\)

Explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

\(\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\)

\(V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)\)

\(V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)\)

\(V_{2} = 29.28\,L\)

Next to a shallow cylindrical lake with a radius of 4km and an average water height of 5m, a type A exhaust basin has been installed, which recorded a total water loss of 4.5cm during a summer month. It is requested to calculate the evaporation of the lake and the volume of the lake water in cubic meters for the specific time period if the coefficient of the evaporation basin is equal to 0.7

Answers

In a shallow cylindrical lake with a radius of 4 km and an average water height of 5 m, a type A exhaust basin recorded a total water loss of 4.5 cm during a summer month.

The task is to calculate the evaporation of the lake and the volume of lake water in cubic meters for that specific time period, assuming an evaporation coefficient of 0.7. To calculate the evaporation of the lake, we first convert the recorded water loss from centimeters to meters. The total water loss is 4.5 cm, which is equal to 0.045 meters.

The evaporation from the lake can be determined by multiplying the water loss by the evaporation coefficient. In this case, the evaporation coefficient is given as 0.7. So, the evaporation from the lake is calculated as:

Evaporation = Water loss * Evaporation coefficient

Evaporation = 0.045 m * 0.7 = 0.0315 m

Therefore, the evaporation of the lake during the specified time period is 0.0315 cubic meters.To calculate the volume of lake water, we need to consider the shape of the lake, which is a shallow cylinder. The formula for the volume of a cylinder is:

Volume = π * radius^2 * height

Given that the radius of the lake is 4 km (4000 m) and the average water height is 5 m, we can calculate the volume of the lake as:

Volume = π * (4000 m)^2 * 5 m = 251,327,412 m^3

Therefore, the volume of lake water for the specific time period is approximately 251,327,412 cubic meters.

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why the efficient operation of the citric acid cycle requires that the step catalyzed by citrate synthase has a large favorable free energy change.

Answers

The citrate synthase-catalyzed phase must have significant favorable free power change so that it can contribute to the production of  high energy molecule, ATP, in order for citric acid cycle to function effectively.

What are some examples of molecules?

A molecule is an object comprised of at least two atoms that are linked together chemically; the precise number of atomic nuclei that make up a molecule is known. One hydrogen atom gets joined to one halogen atom to form the molecule HCl(g), for instance. It is referred to as a diatomic molecule and has only two atoms.

What makes something a molecule?

This term was meant to cover its original definition, which was "the smallest quantity of a component that nevertheless keeps the properties of that substance." "An atom is a body that can't cut in two; a dime is the smallest conceivable component of a specific substance," wrote James Maxwell in 1873 when defining atom and molecule.

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A solution of the strong acid nitric acid (HNO3) is neutralized by a solution of the strong base potassium hydroxide (KOH). Which is the balanced molecular equation for the reaction?

Answers

The balanced molecular equation for the neutralization reaction between nitric acid (HNO₃) and potassium hydroxide (KOH) is HNO₃ + KOH → KNO₃ + H₂O.

In a neutralization reaction between a strong acid and a strong base, the hydrogen ion (H+) from the acid combines with the hydroxide ion (OH-) from the base to form water (H₂O). The remaining ions from the acid and the base combine to form a salt. In this case, nitric acid (HNO₃) is a strong acid and potassium hydroxide (KOH) is a strong base.

The balanced molecular equation for the reaction is as follows:

HNO₃ + KOH → KNO₃ + H₂O

In this equation, one molecule of nitric acid reacts with one molecule of potassium hydroxide, resulting in the formation of one molecule of potassium nitrate (KNO₃) and one molecule of water (H₂O). This equation represents the overall reaction that occurs during the neutralization process.

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7. What happens at the atomic level when a metal is subjected to pressure, such as a blow from a hammer? The metal cations are pushed together, and the crystal shatters. Valence electrons travel from one end of the metal to the other. Valence electrons transfer permanently from one metal atom to another. The metal cations easily slide past one another.

Answers

When a metal is subjected to pressure, such as a blow from a hammer, the metal cations easily slide past one another. This is due to the unique properties of metallic bonding and the arrangement of atoms in a metal lattice.

In a metal, the atoms are held together by metallic bonds, which are formed by the sharing of valence electrons among all the atoms in the lattice. These delocalized valence electrons move freely throughout the metal, creating a sea of electrons that surround and hold the metal cations together. The metal cations, which are positively charged ions, are arranged in a regular and repeating pattern within the lattice.

When pressure is applied to a metal, the metal cations are pushed closer together. However, due to the presence of the delocalized electrons, the metal cations can easily slide past one another without the crystal structure shattering. This ability of metal cations to slide past each other is known as plastic deformation, and it is a characteristic feature of metals.

The delocalized electrons act as a lubricant, reducing the resistance between the metal cations as they slide. This phenomenon allows metals to be malleable and ductile, meaning they can be bent, shaped, and drawn into wires without breaking.

It is important to note that during this process, there is no transfer of valence electrons from one metal atom to another. The delocalized electrons remain within the metal lattice, maintaining the metallic bonding. The movement of the valence electrons facilitates the flow of electrical current in metals, contributing to their high electrical conductivity.

In summary, when a metal is subjected to pressure, the metal cations easily slide past one another due to the presence of delocalized electrons. This property allows metals to be malleable and ductile, distinguishing them from other types of materials.

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Which of the following expresses the quantitative measurement? (a)the burette is longer than the pipette. (b)HCl is stronger than HCN d)boiling point of ethyl alcohol is 75°34' water is a colourless liquid.​

Answers

Answer: d. boiling point of ethyl alcohol is 75.

Explanation:

Using the phase diagram for H2O what phase is water in at 1 atm pressure and -5C

Using the phase diagram for H2O what phase is water in at 1 atm pressure and -5C

Answers

The phase diagram of water depicts the behavior of water with respect to temperature and pressure, showing the physical states of water: solid, liquid, and gas, at different points on the diagram. It is also known as the pressure-temperature phase diagram

Water’s phase diagram has three phases, ice (solid), water (liquid), and steam (gas), which exist in equilibrium at the normal atmospheric pressure of one atmosphere (1 atm).At 1 atm pressure and -5°C, water is in a solid state, which is ice. The horizontal line on the diagram at 1 atm represents the normal atmospheric pressure on earth, while the vertical line at -5°C depicts the temperature point where the phase transition between water and ice occurs. The intersection of the horizontal and vertical lines indicates the phase of water at that specific temperature and pressure. When water is heated at 1 atm, its temperature increases until it reaches 100°C, where it boils and turns into steam (gas). Similarly, when water is cooled, its temperature decreases until it reaches 0°C, where it freezes and becomes ice (solid).When water is at 1 atm and at a temperature between 0°C and 100°C, it exists in a liquid state. If the temperature and pressure change, the physical state of water changes as well. Hence, the phase diagram of water helps us understand the behavior of water at different temperatures and pressures.

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Why can different numbers of metal and monkeys atoms create ionic bonds together?

Answers

Answer:

i'm assuming you meant to say nonmetal atoms... in an ionic bond, electrons from the metal are transferred to the nonmetal. The reason why different numbers of metal and nonmetal atoms can combine is so their charges cancel out. take CaCl2 for example. There are two chlorine atoms for every calcium atom. If it was just CaCl, the charges wouldn't cancel out since calcium has a charge of 2+ and chlorine has a charge of 1-. Therefore to balance the compound, you need two chlorines.

A 6 kg rock rolls down a hill with a momentum of 12 kg m/s. Work out the velocity of the rock.​

Answers

momentum = mass x velocity

When know that:

momentum is 12 km m/s

Mass is 6 kg

Hence, velocity = 12/ 6 = 2m/s

When sulfuric acid is combined with sugar, gas is released and a tall, black column forms. This is an example of a-

Answers

When sulfuric acid is combined with sugar, gas is released and a tall black column forms. This is an example of a Dehydration Reaction.

A Dehydration reaction is defined as a chemical reaction that involves the loss of water from the reacting molecule or ion. Dehydration reactions is the reverse of a hydration reaction. Concentrated sulfuric acid can perform a dehydration reaction with table sugar. After mixing, the color changes from white to brownish and eventually to black. The expansion of the mixture is the result of vaporization of water and CO2 inside the container. The gases inflate the mixture to form a snake-like shape and give off a burned sugar smell. The granularity of the sugar can greatly affect the reaction. powdered sugar reacts very quickly but sugar cubes take longer to react.

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Which sequence of steps describes the life cycle of a lake?
A. Runoff fills a depression - sediments build up - water becomes
increasingly shallow
B. Runoff fills a depression - sediments are eroded - water becomes deeper
C. Runoff fills a depression - sediments build up
- water rises continuously
D. Runoff fills a depression - sediments are eroded - water spreads over a wider area

Answers

Answer:

The actual sequence of steps which describe the life cycle of a lake is given below:

C. Runoff fills a depression - sediments build up

- water rises continuously

Explanation:

This is because, the water which builds up as a result of the runoff water accumulating on the depression helps towards building up. When it must have accumulated greatly, it ends up forming a lake.

Hãy tìm công thức hóa học của những oxit có thành phần khối lượng như sau S:50%; C:42,8%; Mn:49,6%; Pb:86,6%

Answers

Answer:

Find the chemical formulas of oxides that contain the following composition:

S:50%; C:42,8%; Mn:49,6%; Pb:86,6%

Explanation:

In the given oxide of sulphur,

50%S is present that means remaining 50% is O.

Divide the % with atomic mass:

S                                     O

50/32= 1.5625            50/16=3.125

divide with smallest ratio:

1.5625/1.5625=1              3.125/1.5625=2

Hence, the formula of oxide is \(SO_2\).

Similarly:

Carbon is 42.8% means the reamining % will be O that is 57.2%.

C                                                    O

42.8/12=3.575                         57.2/16=3.575

Divide with smallest ratio:

3.575/3.575=1                            3.575/3.575=1

Hence, the formula of oxide is CO.

Mn is 49.6% means the remining is % is O that is 50.4%.

First divide with atmic mass of respective element, then get the smallest ratio.

That gives the mole ratio of each constituent atom.

Mn                                 O

49.6/55.0=0.90            50.4/16=3.15

0.90/0.90=1                   3.15/0.90=3.5

Multiply with two

2                                        7

Hence, the formula becomes:

\(Mn_2O_7\)

Pb is 86.6% means ---remaining 13.4% is O.

Pb                                               O

86.6/207 = 0.418 mol                13.4/16=0.85

0.418/0.418=1                               0.85/0.418=2.0

Hence, the formula is:\(PbO_2\)  

   

LAB: SOIL PARTICLES






You have learned that soil is made of weathered rock, water, air, and organic material. The size of particles is an important soil characteristic. According to the United States Department of Agriculture (USDA), there are three main particle sizes—sand, silt, and clay. Clay is particles smaller than 0.002 mm. Sand is particles larger than 0.05 mm. Particles in between are silt. The size of particles in soil determines how much water the soil will hold. Small particles hold more water than large particles.


Soil usually settles into different layers called horizons. The arrangement of horizons is the soil profile. In this experiment, you will observe how particle size affects the soil profile.




Describe how particle size affects the settling of soil.





Which type of soil do you think will settle to the bottom of the container faster?








1 1/2 cups potting soil

1 1/2 cup sand

3 wide-mouthed juice bottles with lids

Masking tape

Pen

Water





Make masking tape labels for each juice bottle. Label one "soil" and the other "soil and sand."

Fill both bottles 3/4 full of water.

Slowly pour 1 cup of soil into the water in the "soil" bottle. Observe the behavior of the soil particles.

Fill the "soil" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.

Slowly pour 1 cup of sand into the water in the "sand" bottle. Observe the behavior of the soil particles.

Fill the "sand" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.

Add the 1/2 cup of sand to the remaining 1/2 cup of soil. Mix thoroughly with the spoon.

Slowly pour the sand and soil mixture into the water in the "soil and sand" bottle. Observe the behavior of the particles.

Fill the "soil and sand" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.

Leave both bottles undisturbed for 8 hours.

Look at the bottles again after 8 hours and record your observations.



Data








What did you notice about the way the soil particles sank in the water? How was it different from the way the soil and sand particles sank?

What does the soil look like in the "soil" bottle? How is it different from the soil in the "soil and sand" bottle?

In the "soil and sand" bottle, which type of soil is on the bottom? Why?

The amount of each size particle in soil is the particle size distribution. Do you think this is a good way to determine particle size distribution? Why or why not?





State whether your hypothesis was supported or disproved, and then explain why it was supported or disproved using your data. Summarize your observations and answer one or more of the following questions: How does this lab relate to what I have been learning? How does this experiment relate to things I have seen in my own life? What could be done to improve this experiment?






Heading and title

Hypothesis, procedure, data, post lab, and conclusion section headings

Each section is thorough and complete

Lab report typed into a word processor (such as Microsoft Word) and saved

Typed lab document uploaded to Ignitia and submitted

Answers

1. I noticed that the soil particles settled out of the water with the larger, heavier particles settling out first and on the bottom, and each layer has smaller and lighter particles in it.

2. Sand settled on the bottom because they are heavier and have more mass than the smaller particles such as silt and clay.

3. Yes, this is a good way to determine particle size distribution. The method used in the experiment allows for the separation of soil particles based on their size and weight, which is a good indicator of their distribution in the soil sample.

4. The results in this experiment may look different when done in different locations because the particle size distribution of soil can vary depending on the location, climate, and geology of the area. Soils in different locations may have different compositions, including different amounts of sand, silt, and clay, which can affect the results of the experiment. Additionally, the sedimentation rate of the particles can also be influenced by factors such as the temperature, the presence of organic matter, and the presence of clay minerals, which can further affect the results.

Describe the sunlight and length of day at the start of winter *NO GO OG LE* will give brainliest

Answers

Answer:

Although the daytime length at the Equator remains 12 hours in all seasons, the duration at all other latitudes varies with the seasons. During the winter, daytime lasts shorter than 12 hours; during the summer, it lasts longer than 12 hours.

Explanation:

Maybe this answer is hopeful in your homework.

Convert 220 grams of CO2 into Moles.

Answers

Answer:

. 44.0 g/mol.

Explanation:

This should be the answer 9,682.09

Which cell in this illustration is likely to come from a plant?
A
B

Which cell in this illustration is likely to come from a plant?AB

Answers

The answer to the question is A.
It’s A! I think this because I know lol

An old refrigerator is rated at 500 W how many kilowatt hours of electric energy what does refrigerator use in 30 days assume the refrigerator is running 12 hours per day

Answers

The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.

Given:

Power rating of the refrigerator = 500 W

Running time per day = 12 hours

Number of days = 30

First, we need to convert the power rating from watts to kilowatts:

Power rating = 500 W / 1000 = 0.5 kW

Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:

Energy used = Power rating × Running time × Number of days

Energy used = 0.5 kW × 12 hours/day × 30 days

Energy used = 180 kWh

Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

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Calculate the concentration of [Hg^2+], [I-] and [K+] in 0. 05M solution of K2[HgI4]. (Kinst. =1. 48∙10^-30)

Answers

The concentration of [Hg2+] is 2.02 x\(10^-11 M\) and the concentration of [I-] is 4.04 x\(10^{11}\). The concentration of [K+] in the solution is equal to its initial concentration, which is 0.05 M.

The solubility product constant expression for K2[HgI4] can be written as follows:

Ksp =\([Hg2+][I-]^2\)

We can use stoichiometry to determine the initial concentration of [Hg2+] and [I-] in the solution:

0.05 M K2[HgI4] = 0.05 M K+ = 0.025 M  \(HgI4^2-\)

From the formula of K2[HgI4], we can see that each mole of K2[HgI4] contains 2 moles of K+ and one mole of  \(HgI4^2-\)          . Therefore, the initial concentration of \(HgI4^2-\)is 0.025 M.

We can assume that x is the concentration of [Hg2+] and 2x is the concentration of [I-] that dissociates from  \(HgI4^2-\). Therefore, the equilibrium concentrations are:

[Hg2+] = x

[I-] = 2x

Using the solubility product constant expression and substituting the concentrations:

Ksp =\([Hg2+][I-]^2\)

1.48 x\(10^-30 = x(2x)^2\)

x = 2.02 x\(10^-11 M\)

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Atoms of which element below are most likely to gain electrons?
Group of answer choices:

carbon

lithium

zinc

phosphorus

Answers

Answer:

Carbon and phosphorus

Explanation:

The atoms of carbon and phosphorus are most likely to gain electrons from the given choices .

The reason for this is because, both carbon and phosphorus are non-metals. Most non-metals usually accept electrons.

Metals are usually electron donors .

Metals are known for their electropositivity which is their ability to lose electrons. Non-metals are electronegative and will tend to have a strong affinity for electrons.

Sandwich that stays fresh for 7 years, other ‘neutraceutical’ wonders

In a laboratory outside Zurich in Switzerland, a food scientist engages in "creative appraisal" of natural food flavors. An example: a real banana having 225 natural flavor components can be duplicated with artificial alternatives using only nine ingredients.

The same company has now in store 20,000 synthetic varieties of flavor, 200 for strawberry alone. Givaudan, the Swiss firm, is the world’s biggest flavorings manufacturer and supplies one in every five artificially flavored foods in the world.

Artificial? "We prefer to call them "nature identical chemicals," says Dr. Heini Menzi, vice president for European research of Givaudan.

These days, emerging groups of professionals in some countries – food scientists they are called – are enmeshed in laboratory work. They are engaged in an awesome venture of working on "industrialized solutions" to maximize manufacturers’ profits and give more nutritional and medical benefits to consumers.

Their sustainable goal is to extend the shelf-life of food items. Manufacturers are enthusiastically pouring so much money to encourage new technologies designed to keep food fresher for a longer time. One of those already attracting interest is a ready-to-eat sandwich that will stay edible after seven years!

The technique is to expose the product to a safe level of radiation using gamma rays. Irradiation kills bacteria, like salmonella and E. coli, and also prevents vegetables from sprouting, hence augmenting an extended fresh-look appearance of the produce. The other is by pulsed electric field technology which subjects fresh foods to bursts of high-voltage electricity.

Directions. Write T if the statement is TRUE and F, if FALSE.

1. Bursts of high-voltage electricity kill bacteria such as E. coli and salmonella.

2. It is possible for food scientists to copy the flavor of natural foods.

3. The shelf-life of food refers to the price of the product indicated on the shelf

4. The other name that scientists give to artificial flavor components is nature identical chemicals.

5. Givaudan has produced 300 synthetic flavors for a real banana.

6. Bacteria like salmonella and E. coli extend the shelf-life of food.

7. Food manufacturers want to extend food freshness to serve consumers and to raise profits.

8. Pulsed electric field technology gives food a fresher look even for a long time.

9. All synthetic flavors are natural.

10. Irradiation exposes a product to an acceptable level of gamma ray radiation.

11. A banana has 200 natural food flavors.

12. A Swiss firm called Givaudan supplies the world with irradiated food.

13. Fresh foods exposed to bursts of high-voltage electricity stay fresh longer14. Food companies spend much for researches that look for ways to make food last longer.

15. Dr. Heinz Menzi is the vice president of Zurich

Answers

The validity of the statements are as follows:
1. True

2. True

3. False

4. True

5. False

6. False

7. True

8. True

9. False

10. True

11. False

12. False

13. True

14. True

15. False



Food scientists are using techniques such as irradiation and pulsed electric field technology to extend the shelf-life of food, while artificial flavors can be created to mimic the taste of natural foods, as done by Givaudan, the world's largest flavorings manufacturer.

Here are the correct responses to the statements:

1. True: Bursts of high-voltage electricity can kill bacteria such as E. coli and salmonella.

2. True: Food scientists can copy the flavor of natural foods using artificial alternatives.

3. False: The shelf-life of food refers to how long the product can be stored before it becomes unfit for consumption, not the price.

4. True: Scientists refer to artificial flavor components as "nature identical chemicals."

5. False: The statement mentions that Givaudan has produced 200 synthetic flavors for strawberry, not 300 flavors for a real banana.

6. False: Bacteria like salmonella and E. coli are harmful and can cause food spoilage, so they do not extend the shelf-life of food.

7. True: Food manufacturers aim to extend food freshness to serve consumers and increase profits.

8. True: Pulsed electric field technology can give food a fresher appearance even for an extended period.

9. False: Synthetic flavors are not inherently natural; they are artificial.

10. True: Irradiation involves exposing a product to an acceptable level of gamma ray radiation.

11. False: A real banana has 225 natural flavor components, not 200.

12. False: The Swiss firm Givaudan is the world's biggest flavorings manufacturer but does not exclusively supply irradiated food.

13. True: Fresh foods exposed to bursts of high-voltage electricity can stay fresh longer.

14. True: Food companies invest significant funds in research to find ways to prolong the shelf-life of food.

15. False: The name of the vice president mentioned is Dr. Heini Menzi, not Dr. Heinz Menzi. The location mentioned is outside Zurich, not specifically in Zurich.

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How many atoms of oxygen in the chemical formula 2Ca(ClO2)2?

2
4
6
8

Answers

the answer is 8 atoms

Answer:

D.

Explanation:

HD​:pSun ​=rhoMan ​=pTue ​=pWed ​=pThu ​=pFri ​=pSat ​=71​ Ha​ : Not all proportions are equal. HD​: Not all proportions are equal. Ha​:pSun ​=pMon ​=pTue ​=rhoWed ​=pThu ​=rhoFri ​=rhoSat ​=71​ HD​: Not all proportions are equal. Ha​:pSun ​=pMon ​=pTue ​=pWed ​=pThu ​=rhoFri ​=pSat ​=71​ HD​:pSun ​=pMon ​=pTue ​=pWod ​=pThu ​=pFri ​=pSat ​=71​ Ha​ : All proportions are equal. Find the value of the test statistic. (Round your answer to three d: Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. Do not reject H0−​. We conclude that the proportion of traffic Reject HD​. We conclude that the proportion of traffic acciden Reject HD​. We conclude that the proportion of traffic acciden Do not reject H0−​We conclude that the proportion of traffic Compute the percentaqe of traffic accidents occurring on each day What day has the highest percentage of traffic accidents? Sunday Monday Tuesday Wednesday Thursday Friday Saturday Based on 2017 sales, the six top-selling compact showed the following number of vehicles sold. Use a goodness of fit test to determine if the sample data indicate that the market shares for compact cars in the city are different than the market shares suggested by nationwide 2017 sales. Use a 0.05 level of significance. State the null and alternative hypothesis. Ha​ : The market shares for the compact cars in the city are different for at least one of the nationwide market shares listed. o: The market shares for the compact cars in the city do not differ from market shares nationwide. : The market shares for the compact cars in the city are different from at least one of the nationwide market shares listed. Ha​ : The market shares for the compact cars in the city are not different from any of the natione Ha​ : The market shares for the compact cars in the city do not differ from market shares nationwide. "the test statistic.(Round your answer to two decimal places.) d the rho-value. (Round your answer to four decimal places.) Reject H0​. We cannot conclude that market shares for the compact cars in the city differ from the nationwide market shares. Do not reject H0​. We conclude that market shares for the compact cars in the city differ from the nationwide market shares. Do not reject H0​. We cannot conclude that market shares for the compact cars in the city differ from the nationwide market shares.

Answers

The p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.

Firstly, let us conduct a Chi-square test of independence of categorical variables based on the information given above. We have three different cases of hypothesis testing that we have to solve one by one.


Case 1: HD​:pSun ​=rhoMan ​=pTue ​=pWed ​=pThu ​=pFri ​=pSat ​=71​
Ha​ : Not all proportions are equal.


Test Statistic
For this hypothesis, we need to compute the test statistic that is given as:
\($$\chi^2=\sum_{i=1}^{k}\frac{(O_i-E_i)^2}{E_i}$$\)  where k is the number of groups/categories. Since we have 7 days of the week, \(k = 7. $O_i$ and $E_i$\) are the observed and expected frequencies respectively.  
Here, we have equal proportions of 71 for each day of the week.
Therefore, the expected frequencies are also equal to 71.
\($$E_i = 71, i=1,2,3,4,5,6,7.$$\)

We also have to use the given information to compute the observed frequencies,
\($O_i$.$$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126$$\)

Therefore, the test statistic can be computed as \($$\chi^2=\frac{(90-71)^2}{71} + \frac{(99-71)^2}{71} + \frac{(122-71)^2}{71} + \frac{(123-71)^2}{71} + \frac{(130-71)^2}{71} + \frac{(160-71)^2}{71} + \frac{(126-71)^2}{71}$$$$\chi^2=180.14\)

Now we have to find the p-value of this test. Since the number of degrees of freedom is k - 1 = 7 - 1 = 6, the p-value can be found using the chi-square distribution table with 6 degrees of freedom at the 0.05 significance level. The p-value is 0.000014. ConclusionSince the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.

The total number of accidents is \($$90+99+122+123+130+160+126=850$$\)

The percentage of accidents occurring on each day of the week can be found as follows:
\($$Sunday: $$\frac{90}{850}\times 100 = 10.59\%$$Monday: $$\frac{99}{850}\times 100 = 11.65\%$$Tuesday: $$\frac{122}{850}\times 100 = 14.35\%$$Wednesday: $$\frac{123}{850}\times 100 = 14.47\%$$Thursday: $$\frac{130}{850}\times 100 = 15.29\%$$Friday: $$\frac{160}{850}\times 100 = 18.82\%$$Saturday: $$\frac{126}{850}\times 100 = 14.82\%$$\)

From the above percentages, we can see that Friday has the highest percentage of traffic accidents.


Case 2:
HD​: Not all proportions are equal.

Ha​:pSun ​=pMon ​=pTue ​=rhoWed ​=pThu ​=rhoFri ​=rhoSat ​=71


Test Statistic

\($$E_1 = 78.57, E_2 = 86.57, E_3 = 106.86, E_4 = 107.43, E_5 = 113.57, E_6 = 139.43, E_7 = 109.14$$\)

We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)

The test statistic can be computed as:


\($$\chi^2=\frac{(90-78.57)^2}{78.57} + \frac{(99-86.57)^2}{86.57} + \frac{(122-106.86)^2}{106.86}+ \frac{(123-107.43)^2}{107.43} + \frac{(130-113.57)^2}{113.57} + \frac{(160-139.43)^2}{139.43} + \frac{(126-109.14)^2}{109.14} $$$$ \implies \chi^2=34.98$$\)
The p-value is 0.000001.
Conclusion- Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.

Case 3:

All proportions are equal.
Test Statistic
The expected frequency for each group is
\(E = \frac{850}{7} = 121.43\)
We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)


The test statistic is,


\($$\chi^2=\frac{(90-121.43)^2}{121.43} + \frac{(99-121.43)^2}{121.43} + \frac{(122-121.43)^2}{121.43} + \frac{(123-121.43)^2}{121.43} + \frac{(130-121.43)^2}{121.43} + \frac{(160-121.43)^2}{121.43} + \frac{(126-121.43)^2}{121.43}} \\\implies \chi^2=9.17$$\)

The p-value is 0.1664.

Since the p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.

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Zn + 2HCI ZnCl2 + H2
How many moles of hydrogen are produced from the reaction of 3.0 moles
of zinc?

Answers

Answer:

3 moles H₂

Explanation:

The reaction equation Zn + 2HCl => ZnCl₂ + H₂ shows a 1:1 mole ratio between Zn and molecular hydrogen (H₁). Therefore, the moles of Zn consumed in the reaction is then equal to the moles of H₂ produced. In this case using 3 moles Zn => 3 moles H₂ will be produced.

Answer:

3 moles

Explanation:

Use the ratio

Yeah, I agree with the other person

considering the solvents that we used, the ether byproduct that we also produced in the kinetics experiment is?

Answers

Considering the solvents is NaOH that we used, the ether byproduct that we also produced in the kinetics experiment

Solvents is the liquid in which other material dissolve to form a solution and   it is possible to extract from organic layer using sodium hydroxide and it can react with NaOH and other are the functional group that cannot react so NaOH that we used, the ether byproduct that we also produced in the kinetics experiment and pure sodium hydroxide is a colorless crystalline solid that melt at 318°C without decomposition and with boiling point 1,388°C and it is highly soluble in water and in the kinetic experiment one determine the rate constant for the forward and reserve reaction

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I need help with an science IXl i need to go up to 8- its about comparing cells and cell parts somebody please save me!

Answers

Answer:

o cany give because of i am in 9th

A can contains a gas with a volume of 86 mL at 30oC. What is the volume in the can if it is heated to 65oC?

Answers

Answer:

New volume of gas = 95.93 ml (Approx)

Explanation:

Given:

Old volume of gas = 86 ml

Old temperature = 30°C = 30 + 273 = 303 K

New temperature = 65°C = 65 + 273 = 338 K

Find:

New volume of gas

Computation:

V1T2 = V2T1

(86)(338) = (V2)(303)

New volume of gas = 95.93 ml (Approx)

a sample of gas weighs 3.33 g and occupies a volume of 1.365 l at 95 °c and 790 torr. identify the gas sample.

Answers

The identity of the gas, given that 3.33 g occupies a volume of 1.365 L at 95 °C and 790 torr is chlorine gas (Cl₂)

How do I determine the identity of the gas?

First, we shall determine the number of mole of the gas. This is obtained as follow:

Volume (V) = 1.365 L Temperature (T) = 95 °C = 95 + 273 = 368 KPressure (P) = 790 torr = 790 / 760 = 1.039 atmGas constant (R) = 0.0821 atm.L/Kmol Number of mole (n) =?

PV = nRT

1.039 × 1.365 = n × 0.0821 × 368

Divide both sides by (0.0821 × 368)

n = (1.039 × 1.365) / (0.0821 × 368)

n = 0.0469 mole

Finally, we shall determine the identity of the gas as follow:

Mole of gas = 0.0469 mole Mass of gas = 3.33 gMolar mass of gas =?

Molar mass = mass / mole

Molar mass = 3.33 / 0.0469

Molar mass of gas = 71 g/mol

From the above calculation, we can see that the molar mass of the gas is 71 g/mol.

Thus, we can conclude that the identity of gas is chlorine gas (Cl₂) since:

Chlorine atom (Cl) = 35.5 g/molChlorine gas (Cl₂) = 2 × 35.5 = 71 g/mol

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