Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.​

Given:

A ball bouncing eventually comes to stop.

To find:

What kind of a system is this?

Explanation:

An open system is a system where the free exchange of matter and energy with the surroundings takes place.

A closed system is where only the energy of the system is shared with the surrounding. In these kinds of systems, the exchange of matter does not take place.

An isolated system is where neither matter nor energy is exchanged between the system and the surrounding.

When a ball is bouncing, it gradually loses its kinetic energy to the surroundings and eventually comes to stop. But the mass of the ball remains the same. Thus this is a closed system.

Final answer:

The given system is a closed system.

Therefore the correct answer is option B.

A 65-year-old man's energy intake should focus on meals c.) with a lower caloric density and increased nutrient density

Calorie density represents a metric that is employed to determine how many calories are contained in a given amount of food. For a 65-year-old male, meals with a lower calorie density and a higher nutritional density would be ideal. People's metabolisms tend to slow down as they become older, so they need fewer calories.

To preserve their health, they still require enough nourishment, though. By choosing foods that are high in nutrients yet low in calories, such as fruits, vegetables, whole grains, lean proteins, and healthy fats, one may meet nutritional needs while limiting calorie intake. Adding more fibre to your diet can also help ya person to lose weight and maintain good digestive health.

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Answer:

2991.47 [cm^2]

Explanation:

To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:

\(3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2} }{1^{2}in^{2} } \\2991.47[cm^{2}]\)

Answer:

0.531m

Explanation:

Soln

Mass = 3.2kg

Kinetic energy = 8 J

Mechanical energy = 25 J

Recall,

Mechanical energy = K.E + P.E

But P.E = mass × g × h

where g = acceleration due to gravity = 10ms² and h = height.

Mechanical energy = K.E + mass × g × h

25 = 8 + 3.2×10×h

25 - 8 = 32×h

17 = 32×h

divide both sides by 32

17/32 = h

h = 0.531 metres.

The force that your bottom is pushing against the chair is called the "action force."

The action force is equal and opposite to the "reaction force" that the chair is pushing back against your bottom. This is known as Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction.

So, when you are sitting in a chair, your bottom is pushing against the chair with a certain amount of force, and the chair is pushing back against your bottom with the same amount of force. This is why you are able to sit in the chair without falling through it.

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The most recent view of the atom is the quantum mechanical model of the atom.

We know that the atom is smallest part of the substances that can take part ion a chemical reaction.

An atomic model is a theoretical construct that explains the properties and behavior of atoms, the basic building blocks of matter. The most widely accepted atomic model is the quantum mechanical model, which describes atoms as consisting of a nucleus of protons and neutrons, surrounded by a cloud of electrons.

The electrons occupy energy levels or orbitals, and their behavior is described by the principles of quantum mechanics. The earliest atomic model was proposed by John Dalton in the early 19th century, which was a classical mechanical model.

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Given that,

The mass of marble A, m₁=0.08 kg

The mass of marble B, m₂=0.05 kg

The initial velocity of marble A, u₁=0.5 m/s

As the marble B was at rest, the initial velocity of marble B is u₂=0 m/s

The final velocity of marble A, v₁=-0.1 m/s

Let the final velocity of marble B be v₂.

According to the law of conservation of momentum, the total momentum before the collision is equal to the total after the collision.

Therefore

On rearranging the above equation,

On substituting the known values in the above equation,

Therefore the

Answer:

See below

Explanation:

Use conservation of momentum (rather than Kinetic Energy ) for collision problems:

Momentum A  = mv = .08 * .5 = .04  km m/s

Momentum B = mv  = 0

    Total Momentum = .04 + 0 = .04  kg m/s

After collision the sum must be the same

A = mv = .08 ( -.1 ) = - .008 kg m/s

B = m vb   = .05 vb

    .04   =  - .008   +  .05 vb

      vb =  + .96 m/s      in the same direction as original A direction

Although both Harry and Sue cycle at the same speed, the tires on Sue's bike will have a greater rotational speed due to their smaller diameter.

The rotational speed of a tire is determined by the number of rotations it completes in a given time. It is directly related to the distance traveled by a point on the tire's circumference.

Since Harry and Sue cycle at the same speed, their linear speeds (or the speeds at which they move forward) are equal. However, the tires on Harry's bike have a larger diameter than those on Sue's bike.

The rotational speed of a tire is inversely proportional to its diameter. A larger diameter tire covers more distance with each rotation compared to a smaller diameter tire.

Therefore, the tires on Sue's bike will have a greater rotational speed. This means that for every rotation of Sue's smaller diameter tires, a point on the circumference will cover a shorter distance compared to Harry's larger diameter tires.

Consequently, Sue's tires will rotate more times in the same amount of time compared to Harry's tires.

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Answer: Gases

Explanation: Gases don't have a certain direction, so they go in all directions.

Answer:

its black

Explanation:

because thats the color it is

Answer:

Constants: 1 atm = 760 mm Hg = 760 torr = 1.01325 bar = 101.325 kPa R = 8.314 J·mol-1K-1= 0.08206 L·atm·mol-1K-11 Calorie = 1 kcal = 4.184 kJ Data:Properties of liquid water: b.p. (at 1 atm) = 100.00°CCH2O(l)= 4.184 J·g-1·K-1ΔHovap= 40.7 kJ·mol-1dH2O(l)(at 25°C) = 1.00 g·mL-1 KfH2O= 1.86 °C·kg·mol-1KbH2O= 0.52 °C·kg·mol-1Po(298 K)= 23.8 mm Hg Properties of ice: m.p. (at 1 atm) = 0.00°CCH2O(s) = 2.06 J·g-1·K-1 dH2O(s)= 0.917 g·mL-1 ΔHofus= 6.02 kJ·mol-1Formulae: ΔGo= ΔHo-TΔSo ΔG = ΔGo+ RT lnQΔGo= -RT lnKeqC = k P (or, S = k P) P = χPoΔT = KmπV = nRT [A]t= -k t + [A]oln[A]t= -k t + ln[A]o1/[A]t= k t + 1/[A]o

I am not sure If that helps im sorry I'm only in middle school :P.

The total work done by the man is approximately 3809.32 Joules.

To calculate the work done by the man in pushing the crate up the ramp, we need to consider both the work done on the crate and the work done on the man's body.

The work done is given by the formula:

Work = Force * Distance * cos(θ)

Where:

- Force is the parallel component of the force applied (in the direction of motion).

- Distance is the displacement along the direction of the force.

- θ is the angle between the force vector and the displacement vector.

Let's calculate the work done on the crate first:

Force on the crate = 500 N

Distance = 4.00 m

theta = 20.0°

Work on the crate = Force on the crate * Distance * cos(θ)

Work on the crate = 500 N * 4.00 m * cos(20.0°)

Work on the crate ≈ 3809.32 J

Now let's calculate the work done on the man's body:

Since the man is moving at a constant speed, the net work done on his body is zero. This is because the work done by his body against gravity (lifting himself up) is equal in magnitude and opposite in direction to the work done on his body by gravity. Therefore, the work done on the man's body is zero.

Total work done = Work on the crate + Work on the man's body

Total work done = 3809.32 J + 0 J

Total work done ≈ 3809.32 J

Therefore, the total work done by the man is approximately 3809.32 Joules.

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Complete Question:

Calculate the work done by an 85.0-kg man who pushes a crate 4.00 m up along a ramp that makes and angle of 20.0° with the horizontal. He exerts a force of 500 N on the crate parallel to the ramp and moves at a constant speed. Be certain to include the work he does on the crate and on his body to get up the ramp.

Answer:

When an object is in contact with another object, it creates friction.

The force on a charge Q moving with velocity v is given by the Lorentz force law, whose equation is F =QvBsinθ.

The Lorentz force equation relates the force experienced by a charged particle when it is moving in a magnetic field. The force is proportional to the charge on the particle, the strength of the magnetic field, and the velocity of the particle.

The direction of the force is perpendicular to both the velocity and the magnetic field direction and follows the right-hand rule.

The equation is given by:

F = QvBsinθ

Where F is the force on the charge. Q is the charge on the particle, v is the velocity of the particle, and B is the magnetic field strength.θ is the angle between the velocity vector and the magnetic field vector.

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Answer:

Pressure, temperature and humidity all affect air density. And you can think of air density as the mass of air molecules in a given volume.

Explanation:

Answer:

Capricorn what is yours

Answer:

leo

Explanation:

Answer:

it'll stay the same unless there's rain

Answer:

item/object; more

Explanation:

A variable is defined as an object or item that can have more than one single value.

A variable is defined as a quantity that can have more than one single value.

In the context of mathematics and science, a variable is a symbol or quantity that can change or vary. It represents an unknown or changing value that can take on different values in different situations or scenarios. Variables are used to describe relationships, equations, and patterns in various fields such as mathematics, physics, economics, and more.

Variables are an essential concept in scientific research and experimentation. They allow scientists to investigate how changes in one factor can affect another factor. In an experiment, variables are typically categorized into two main types: independent variables and dependent variables. The independent variable is the one that the researcher manipulates or controls to observe its effect on the dependent variable, which is the outcome being measured.

For example, in a study investigating the effects of different amounts of fertilizer on plant growth, the amount of fertilizer would be the independent variable, as it is being controlled by the researcher. The plant growth would be the dependent variable, as it depends on the different amounts of fertilizer applied.

Overall, variables are fundamental components of scientific inquiry, data analysis, and problem-solving, enabling researchers and scientists to understand and describe the relationships and patterns within various phenomena.

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Answer:

Product of masses and square of the distance them.

Explanation:

The gravitational force between two objects is given by :

\(F=\dfrac{km_1m_2}{r^2}\)

The two characteristics that determine the strength of the gravitational force between two objects are :

1. The product of masses of two objects

2. The distance between the charges

Answer:

B. radio waves

Explanation:

Trust me It's correct

This question deals with working with chemicals in the lab. And many chemicals are of course dangerous to touch and dangerous to inhale.You should never smell taste or touch chemicals in the lab. .That could be very dangerous.

You never want to taste and you do not want to touch chemicals with your bare hands. That's why we have a variety of different tools that allow you to transfer chemicals without ever touching them with your hand.

To ensure safety, it is always advised to wear closed-toe shoes and no open-toe shoes as there are chances of spillage of chemicals on the skin. Such chemicals can be hazardous, and so always, one should wear closed-toe shoes in the chemistry lab.

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The total number of free electrons in the intrinsic Si bar (shown below) at 100°C is 1.536 × 10¹¹ electrons.

The formula for calculating the number of free electrons in an intrinsic Si bar at a temperature of 100°C is given as follows:  

n_{i}=1.5×10^{10}e^{-\frac{E_g}{2kT}}

Where,

Eₑₒ = 1.12 eV,

k = 8.62 × 10⁻⁵ eV/K, and

T = 100°C + 273 = 373 K.

The intrinsic concentration is given by nᵢ.

We now use this formula to determine the number of free electrons in the intrinsic Si bar.

n_{i}=1.5×10^{10}e^{-\frac{E_g}{2kT}}

\qquad =1.5×10^{10}e^{-\frac{1.12}{2×8.62×10^{-5}×373}}}

On solving this equation we get,  

\qquad = 9.6 × 10^{15} cm^{−3}

The volume of the intrinsic Si bar is given by the product of its dimensions, which are (4 cm x 2 cm x 2 cm)Volume = (4 cm) × (2 cm) × (2 cm) = 16 cm³

As a result, the overall number of free electrons in the intrinsic Si bar is:

Number = n_{i} × Volume

Substituting the known values, we get,

Number = 9.6 × 10^{15} × 16 × 10^{-6}

Number = 1.536 × 10^{11} \ electrons

Therefore, the total number of free electrons in the intrinsic Si bar (shown below) at 100°C is 1.536 × 10¹¹ electrons.

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If the gas particles suddenly stopped moving, the pressure of the gas would drop to zero.

Pressure is caused by the collisions of gas particles with the walls of a container. When gas particles are moving, they collide with the walls of the container and exert a force on them, creating pressure. If the gas particles suddenly stopped moving, they would no longer collide with the walls of the container and the pressure would drop to zero.

However, it is important to note that in reality, it is impossible for gas particles to suddenly stop moving. This is because gas particles are always in motion due to their kinetic energy. If the gas particles were to stop moving, they would need to lose all of their kinetic energy, which is not possible according to the laws of thermodynamics.

Answer:

21.76J

Explanation:

F=ma

where:

m=mass

a=acceleration

Kamaria's mother should pull her with a force of  21.76 Newton if she (Kamaria) wants her acceleration to be 0.80 m/s².

In order to accelerate a body of mass 'm kg' with an acceleration of 'a m/s²', a force of magnitude equal to the product of mass and required acceleration is required. Mathematically -

F = m x a

Given is a girl learning how to ice skate. She wants to move with an acceleration of 0.80 m/s² and her mass is 27.2 kg.

From the definition of force, we can write -

F = m x a

F = 27.2 x 0.8

F = 21.76 Newton

Therefore, Kamaria's mother should pull her with a force of  21.76 Newton if she (Kamaria) wants her acceleration to be 0.80 m/s²

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(a) Push down harder on the pedals of a bicycle when first starting out than when moving at constant speed it is because of the 1st and 2nd law of motion.

(b) Need to pedal at all when cycling at constant speed because bicycle slows down and comes to rest due to the frictional force.

Unless acted on by an unbalanced force, an object at rest remains at rest, while an object in motion continues in motion at constant speed and in a straight path. The acceleration of an item is determined by its mass and the amount of force applied.

Use Newton's First and Second Law of Motion:

(a) The bicycle is at rest initially, in order to accelerate from rest, the net force must be greater than zero. When moving at constant speed net force equal to zero. Now when first starting to move it is necessary to overcome the static friction which is larger than kinetic friction.

(b) The net force acting on the object moving with constant speed is zero. So on bicycle also the net force is zero with constant speed. The bicycle slows down and comes to rest due to the frictional force. So at constant speed bicycle needs to be paddled when cycling.

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Action-reaction pairs are forces that operate on separate objects in opposing directions and at identical magnitudes. Never do they affect the same thing. We learn that forces are interactions from Newton's third law.

When two bodies contact, they exert an equal and opposite force on one another in accordance with Newton's third rule of motion. Action-reaction forces are made up of these forces.

Think about how a baseball bat and a ball interact, for instance. The bat forces the ball to the right while the baseball forces the bat to the left. The action-reaction force pair is made up of these two forces acting on two separate objects together.

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Formula for momentum:

\(p=mv\)

momentum(measured in kg*m/s) = mass(measured in kg) * velocity(measured in m/s)

__________________________________________________________

Given:

\(m=3kg\)

\(v=3m/s\)

\(p=?\)

__________________________________________________________

Finding momentum:

\(p=mv\)

\(p=3\times3\)

__________________________________________________________

Answer:

\(\fbox{p = 9 kg*m/s}\)

The angular velocity depends on the length of the orbit and the orbital

speed of the telescope.

Response:

First question:

Second question:

Third question:

The distance of the James Webb telescope from the Sun = 1.5 million kilometers from Earth on the side facing away from the Sun

The orbital velocity of the telescope = The Earth's orbital velocity

First question:

\(Angular \ velocity = \mathbf{\dfrac{Angle \ turned}{Time \ taken}}\)

The orbital velocity of the Earth = 29.8 km/s

The distance between the Earth and the Sun = 148.27 million km

The radius of the orbit of the telescope = 148.27 + 1.5 = 149.77

Radius of the orbit, r = 149.77 million kilometer from the Sun

The length of the orbit of the James Webb telescope = 2 × π × r

Which gives;

r = 2 × π × 149.77 million kilometers ≈ 941.03 million kilometers

Therefore;

\(Angular \ velocity = \dfrac{29.8}{941.03}\times 2 \times \pi \approx 0.199\)

Second question:

Centrifugal force force, \(F_{\omega}\) = m·ω²·r

Which gives;

\(F_{\omega} = m \cdot \dfrac{28,500^2 \, m^2/s^2}{149.77 \times 10^9 \, m} \approx 0.0054233 \cdot m\)

\(Gravitational \ force, F_G = \mathbf{G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}}\)

Universal gravitational constant, G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Mass of the Sun = 1.989 × 10³⁰ kg

Which gives;

\(F_G = 6.67408 \times 10^{-11} \times \dfrac{1.989 \times 10^{30} \times m}{149.77 \times 10^9} \approx 0.00592 \cdot m\)

Which gives;

\(F_{\omega}\) < \(F_G\), therefore, the James Webb telescope has to accelerate away from the Sun

F = \(\mathbf{F_{\omega}}\) - \(\mathbf{F_G}\)

The amount by which the telescope accelerates away is approximately 0.00592·m - 0.0054233·m ≈ 0.0005·m (away from the Sun)

Third part:

Other forces include;

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